Answer:
Its angular velocity is
π
30
radians per second (about 0.105 radians/s.
Explanation:
Explanation:
Think of it like this:
There are
2
π
radians in one complete rotation, and that takes the second hand 60 seconds to complete.
So, the rate of rotation (the angular velocity) is
2
π
/60 = pi/30 radians per second# which is about 0.105 radians per second.
To solve the problem we will first calculate the time taken by the second arm to travel 1 rad.
Time taken by the second arm to travel 1 rad
We know that the arm of the second travels 2π radians in 60 seconds. therefore, the time is taken to travel 1 rad by the second arm,
[tex]1\rm\ rad = \dfrac{60}{2\pi}[/tex]
Time taken by the second arm to travel 3.57 radTime taken by the second arm to travel 3.57 rad
[tex]=3.57\times \dfrac{60}{2\pi}\\\\= 34.09\rm\ sec[/tex]
Hence, the time taken by the second arm to travel 3.57 rad is 34.09 sec.
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refers to a fear of being trapped in a crowded, public place.
Answer:
Agrophobia
Explanation:
an anxiety disorder in which someone feals anxious and scared in a public place
what is the speed of a boy moving around a circular park of radius 6m if he goes around the park in 20s
Answer:
1.884 meters per second
Explanation:
s = d/t
d = C = 2πr = 2π(6) = 37.68 m
t = 20 s
s = (37.68 m)/(20 s)
s = 1.884 m/s
The speed of the boy is 1.88 m/s while he is moving around a circular park of radius 6m and taking time 20 seconds.
What is speed?Speed can be defined as a measurement of how quickly the distance an object traveled changes with time. Speed is a scalar quantity as it has magnitude but no direction as a unit of measurement.
An object that moves quickly and with high speed, traveling a lot of ground in a lesser time.
Given, the radius of the circular park, r = 6m,
The time taken to cover one round of the park, t = 20 s
The total distance traveled by the boy is equal to the circumference of the circular park, so
Circumference of park, C = d = 2πr = 2× 3.14 × 6 =37.68 m
The speed of the boy, S = d/t
S = 37.68 /20
S = 1.88 m/s
Therefore, the speed of the boy is equal to 1.88 m/s.
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1. A 10 kg rocket blast off the ground with an applied force of 150 N, calculate the net force
of your rocket
The net force on the rocket at the given applied force is 52 N.
The given parameters:
Mass of the rocket, m = 10 kgApplied force, F = 150 NThe net force on the rocket is calculated by applying Newton's second law of motion as follows;
F(net) = F(up) - F(down)
F(net) = 150 - mg
F(net) = 150 - (10 x 9.8)
F(net) = 150 - 98
F(net) = 52 N
Thus, the net force on the rocket at the given applied force is 52 N.
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You hang a light in front of your house using an
elaborate system to keep the 12-kg object in static
equilibrium (Figure 1). What are the magnitudes of the
forces that the ropes must exert on the knot connecting
the three ropes if 02 = 639 and 03 = 45° ?
The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N F₂ = 89.21 N F₃ = 57.28 NGiven data :
Mass ( M ) = 12 kg
∅₂ = 63°
∅₃ = 45°
Determine the magnitudes of the forces exerted by the ropes on the connecting knota) Force exerted by the first rope = weight of rope
∴ F₁ = mg
= 12 * 9.81 ≈ 118 kg
b) Force exerted by the second rope
applying equilibrium condition of force in the vertical direction
F₂ sin∅₂ + F₃ sin∅₃ - mg = 0 ---- ( 1 )
where: F₃ = ( F₂ cos∅₂ / cos∅₃ ) --- ( 2 ) applying equilibrium condition of force in the horizontal direction
Back to equation ( 1 )
F₂ = [ ( mg / cos∅₂ ) / tan∅₂ + tan∅₃ ]
= [ ( 118 / cos 63° ) / ( tan 63° + tan 45° ) ]
= 89.21 N
C ) Force exerted by the third rope
Applying equation ( 2 )
F₃ = ( F₂ cos∅₂ / cos∅₃ )
= ( 89.21 * cos 63 / cos 45 )
= 57.28 N
Hence we can conclude that The magnitudes of the forces that the ropes must exert on the knot connecting are :
F₁ = 118 N, F₂ = 89.21 N, F₃ = 57.28 N
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Physical Science A 2021-2022
Why does increasing the number of trials increase confidence in the results of the experiment?
Answer:
Increasing the number of trials reduces the impact of any one imprecise measurement. … To increase the number of attempts, you can find an average result for the experiment, as well as find and discrepancies as human error if you perform an experiment several times.
Explanation:
hope it helps :)
Answer:
It is because the increase in the number of trials reduces the impact of any one imprecise measurement. Using an average value for data points provides a better representation of the true value.
Which combination of three concurrent forces acting on a body could not produce equilibrium?
1
1 N, 3N, EN
2
2 N, 2N, 2N
.
3.
3 N, 4N, EN
4.
4N, 4N, 5N
All the three concurrent forces acting on a body will not produce equilibrium.
The given parameters:
1. 1 N, 3 N and 5 N
2. 2N, 2N and 2 N
3. 3N, 4N and 5 N
4. 4N, 4N and 5 N
Concurrent forces lie on the same plane and their line of action pass through a common point.
A body under concurrent forces is in equilibrium if the resultant of the forces on the body is zero.
[tex]\Sigma F = 0\\\\F_1 + F_2 + F_3 = 0\\\\F_1 + F_ 2 = - F_3[/tex]
where;
[tex]F_3[/tex] is the equilibrant force
First set of concurrent forces;
[tex]1 \ N \ + \ 3\ N = 4 \ N\\\\F_ 3 = 5 \ N\\\\5 \ N > 4 \ N[/tex]
Second set of concurrent forces;
[tex]2 \ N \ + \ 2 \ N = 4 \ N\\\\F_ 3 = 2 \ N\\\\4 \ N > 2 \ N[/tex]
Third set of concurrent forces;
[tex]3 \ N \ + \ 4 \ N = 7 \ N\\\\F_ 3 = 5 \ N\\\\7 \ N > 5 \ N[/tex]
Fourth set of concurrent forces;
[tex]4 \ N \ + \ 4 \ N = 8 \ N\\\\F_ 3 = 5 \ N\\\\8 \ N > 5 \ N[/tex]
Thus, we can conclude that all the three concurrent forces acting on a body will not produce equilibrium.
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That’s easy please tell me!
A body with a uniform acceleration travels distances of 24m and 64m during the first two equal consecutive intervals of time, each of duration 4s. Determine the initial velocity and acceleration of the moving body.
Answer:
Explanation:
Average velocity in the 24 m interval is 24 / 4 = 6 m/s
Average velocity in the 64 m interval is 64 / 4 = 16 m/s
There is a 4 second interval between the two points where average velocity equals actual velocity
a = Δv/t = (vf - vi) / t = (16 - 6) / 4 = 2.5 m/s²
s = v₀t + ½at²
24 = v₀(4) + ½(2.5)4²
4v₀ = 24 - 20
v₀ = 1 m/s
Not asked for but the velocity at the end of the first segment and beginning of the second segment is 11 m/s and final velocity is 21 m/s
how is the atomic mass determined?
Answer:
Atomic mass is defined as the number of protons and neutrons in an atom, where each proton and neutron has a mass of approximately 1 amu (1.0073 and 1.0087, respectively). The electrons within an atom are so miniscule compared to protons and neutrons that their mass is negligible.
Explanation:
Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
A first order reaction is 25% completed in 1h minutes. Calculate the time required for its 50% completion.
when a student comned his dry hair for a long time, his hair began to stand up. Which of these has MOST LIKELY happened
His hair got charged due to continuous friction causing them to get attracted to other objects and thus standing up.
Answer:The comb and hair have become charged with opposite charges.
Explanation:When a comb is run through your hair charges pass between your hair and the comb, so the comb becomes charged either positively or negatively, and the hair oppositely charged. When the comb is brought close to paper an opposite charge is induced in the paper, and the opposite charges attract.
help me i have little time left i will give brainliest
Answer:
Explanation:
Conservation of momentum
Initial momentum is zero
3.0(6.0) + 7.0v = 0
v = -18/7 = - 2.57142857...
|v| = 2.6 m/s
How large is the tension in a rope that is being used to accelerate a 100 kg box upward at 2m/s2?
[tex]\\ \sf\Rrightarrow T=F[/tex]
[tex]\\ \sf\Rrightarrow T=ma[/tex]
[tex]\\ \sf\Rrightarrow T=100(2)[/tex]
[tex]\\ \sf\Rrightarrow T=200N[/tex]
A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a third ball with a mass of 0.2 kg. If the system is closed, what is the velocity of the third ball?
4 m/s
36 m/s
30 m/s
1.44 m/s
1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.
Answer:
Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.
[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]
20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]
20 = u + 4² - 0²
20 = u + 16
u = 4 m/s
A 2.98-kg object oscillates on a spring with an amplitude of 8.05 cm. Its maximum acceleration is 3.55 m/s2. Calculate the total energy.
Answer:
a = ω^2 A formula for max acceleration (ignoring sign)
V = ω A formula for max velocity
V^2 = ω^2 A^2 = a A from first equation
E = 1/2 M V^2 = 1/2 * 2.98 * 3.55 * .0805 = .426 J
(kg * m/sec^2 * m = kg m^2 / sec^2 = Joule
A 2N and an 6N force pull on an object to the right and a 4N force pulls on the object to the left. If the object has a mass of 0.25 kg what is its acceleration?
Answer:
[tex]16m/s^{2}[/tex]
Explanation:
Please ask if you have more questions!
Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in
Answer:
There ya go
Explanation:
The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.Learn more about "Oscillation" here:
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I need help with this question!
Answer:
Explanation:
Conservation of momentum
In the x direction
2(15) + 2(-10) = 2(-5) + 2(vBfx)
vBfx = 10 m/s
In the y direction
2(30) + 2(5) = 2(20) + 2(vBfy)
vBfy = 15 m/s
vBf = 10i + 15j
KEi = ½(2)(15² + 30²) + ½(2)(-10² + 5²) = 1250 J
KEf = ½(2)(-5² + 20²) + ½(2)(10² + 15²) = 750 J
KEf - KEi = 750 - 1250 = -500 J
Would it be possible to predict the speeds that a coaster will reach before it’s ever placed on the track?
Yes, it's possible to predict the speeds that a coaster will reach before it’s
ever placed on the track.
This is usually calculated with the potential energy which is
Potential energy = m g h
where m is mass, g is acceleration due to gravity and h is height.
The given formula above is used in predicting the speeds that a coaster will
reach before it’s ever placed on the track.
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i need help with the problem below
Answer:
Explanation:
a) F = ma
a = F/m
a = 9(800) / 1 x 10⁹ = 7.2 x 10⁻⁶ m/s
b) t = v/a
t = 200 / 7.2 x 10⁻⁶
t = 2.8 x 10⁷ s about 10½ months
c) v² = u² + 2as
s = (v² - u²) / 2a
s = (200² - 0²) / (2( 7.2 x 10⁻⁶))
s = 2.8 x 10⁹ m nearly 7 times around the earth
And all this assumes NO FRICTION.
13. In which of the following climates does chemical weathering generally occur most
rapidly?
A. Canda
B. Greenland
C. Brazil
D. Algeria
Which phrase describes the energy transformation that happens in a
generator?
A. Electrical energy into chemical energy
ООО
B. Electrical energy into mechanical energy
C. Chemical energy into electrical energy
O
D. Mechanical energy into electrical energy
SI
Answer:
Mechanical energy into electrical energy
Explanation:
Answer:
ExplanMechanical energy into electrical energy
SIation:
If 90J of energy are available for every 30C of charge, what is the potential difference?
Enter your answer as a number
V
Answer:
3 v
Explanation:
Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Potential energy is the amount of energy possessed by a body due to its position relative to another object.
a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight
Potential energy = 6324 Joules
b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
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Water pumps use electrical energy to create mechanical energy needed to move water.
A 1875 W water pump is plugged into a 110 V electrical outlet.
Answer:
n/a
Explanation:
this question is not feasible
A 70 kg man is running up the stairs which is 3m high in 2s.(a)How much work is done by the man?(b)What is the power exerted by the man? (Use g = 10ms 2)
Explanation:
m = 70 kg
s = 3m
t =2s
g = 10 m/s²
(a)How much work is done by the man?
W = Fs
= mg X s
= 70 x 3 x 10
= 210 x 10
= 2100 Joule
(b)What is the power exerted by the man?
P = W/t
= 2100/2
P = 1050 Watt
Ginny is snowboarding down a ski slope. Her total mass (including the snowboard) is 68.5 kg. When she reaches the bottom of the slope, she is moving at 6.55 m/s. The coefficient of friction between the snowboard and the ground is 0.088 . How fast will Ginny be moving 2 seconds after reaching the bottom of the slope?
1) 5.71 m/s
2)5.91 m/s
3)4.82 m/s
4)4.08 m/s
Answer:
Explanation:
Assuming the run out at the bottom of the slope is horizontal
μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at
v = u + μgt
v = 6.55 - 0.088(9.81)(2)
v = 4.82 m/s
After reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
What is Friction?Friction is the force which opposes the relative motion of solid surfaces, fluid layers, and material elements that are sliding against each other. There are many types of friction like
Dry frictionFluid frictionLubricated friction Skin friction Internal frictionFriction can be expressed as
Ff = μFN
where, Ff is the force of friction (N)
μ is the coefficient of friction.
FN is the normal force
As per the above equation, it is actually the normal force, not the weight, which is responsible for friction.
For given information,
Assuming the bottom of the slope is horizontal
So, μ = Ff/N = Ff/mg
Ff = μmg
a = Ff/m = μmg/m = μg
v = u + at (u- initial speed, v= final speed, a= acceleration and t= time)
v = u + μgt (g= acceleration due to gravity)
u = 6.55 - 0.088(9.81)(2)
u = 4.82 m/s
Thus, after reaching the bottom of the slope, it will take a speed of 4.8m/s to reach. So, the correct option is (C).
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Which of the following is NOT a function of the lens in the eye?
It can perform minor adjustments for distance.
It flattens when light rays from distant objects are to be focused.
It is a light receptor that generates nerve signals that are sent to the brain.
It maintains its spherical shape to view nearby objects.
Answer:
it is a light receptor that generates nerve signals that are sent to the brain
Explanation:
the lens are like the glasses, this means that is used to see things better. You just put them in your eye and that's all it's not connected to the brain
Answer:
c
Explanation: