Definition of main energy level

Answers

Answer 1

Answer:

the orbital in which the electron is located relative to the atom's nucleus.

Explanation:

Answer 2

Answer:

the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.


Related Questions

What does the diagram show about X and Y?
A They have the same mass and the same volume but different weights.
B They have the same mass and the same weight but different volumes.
C They have the same mass, the same volume and the same weight.
D They have the same weight and the same volume but different masses.

Answers

Answer: answer is c rest of explanation is in the comments

If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?​

Answers

Answer:

96.5 mL

Explanation:

*
as the mass of an object increases, the force of attraction...

Answers

Answer:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Answer:

thanks

Explanation:

for answer byebye

NEED HELP ASAP PLEASE
The drop time can be calculated as follows t = sqrt((2y)/g) where y is the vertical height of the table and g is the acceleration due to gravity (9.80 m/)How did the calculated drop time compare to the average of your measured drop times? Find the percent error using the following equation measured drop time - calculated drop time % 100 calculated drop time What factors might cause the differences?

Answers

did you end up getting the answer- im struggling

Answer:

I would think human error could cause differences like not pressing the stop watch on time.

Explanation:

What is the velocity of a dropped object after it has fallen for 3.0 s?

Answers

Answer:

30 m/s.

Explanation:


A heating curve is a graph that shows the temperature change of a substance as
thermal energy is introduced.
True
False

Answers

Answer:

This statement is true, a heating curve is a graph that shows the temperature change of a substance as thermal energy is introduced.

A heating curve is a graph that represents the temperature change of a substance as thermal energy is introduced.

What is the heating curve?

The heating curve can be described as the relationship between the heating supply temperature and the outside air temperature of the system. The heating curve gives what temperature the boiler is to heat the water at an outdoor temperature.

Heating curves indicate how the temperature changes as a substance are heated up. Cooling curves are generally the opposite of the heating curve. They indicate how the temperature changes as a substance are cooled down. Similar to heating curves, cooling curves have horizontal parts where the state transforms from gas to liquid/ from liquid to solid.

The heating curve represents the material in phases of solid, liquid, and gas. As this graph is a plot of T v/s q, the slope is 1/mC. As the heating continues, the solid substance melts. During this time the temperature remains constant. The length of the line can be described as the amount of heat required to melt the solid.

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Given an unknown metal using C= {Q/(M T)} with energy added of 8,000. J, in which the temperature goes from 24.0 C to 28.0 C at a mass of 46.0 g, find its specific heat capacity?​

Answers

Answer:

47.48 J/g/K or 4.74 × 10⁴J/Kg/K

Explanation:

C(specific heat capacity)= Q(quantity of heat)/M(mass) × ∆T(change in temperature, Kelvin)

Q= 8000J

M= 46g or 46 ×10^-3Kg

T1= 24°C = 297K

T2 = 28°C = 301K

∆T = 301-297

= 4K

C= 8000/46 × 4

= 47.48 J/g/K or 4.74 × 10⁴J/Kg/K

In a 200.0-m relay race (each leg of the race is 50.0 m long), one swimmer has a 0.450 second lead
and is swimming at a constant speed of 3.90 m/s towards the opposite end of the pool. What minimum
speed must the second swimmer have in order to catch up with the first swimmer by the end of the
pool?

Answers

The minimum  speed that the second swimmer must have in order to catch up with the first swimmer by the end of the  pool is; 4.04 m/s

We are given the following facts;

Both swimmers swim the same distance of 50 m for a leg of the relay race.Swimmer 1 swims at constant speed of 3.9 m/s. Swimmer 1 has a 0.450 second head start.

Formula for time taken is;

time = distance/speed

Time taken by swimmer 1 for one leg;

t₁ = 50/3.9

t₁ = 12.82 s

Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;

t₂ = 12.82 -0.45

t₂ = 12.37 s

Thus, speed of swimmer 2;

v = 50/12.37

v = 4.04 m/s

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define one kilogram mass ​

Answers

Answer:

kg - one thousand grams; the basic unit of mass adopted under the Systeme International d'Unites; "a kilogram is approximately 2.2 pounds"

Explanation:

what are the electrical signals generated by neurons called?

Answers

Answer:

electrons

Explanation:

because it electrons

How much work is done when mass of 3kg(weighing 30N)is lifted vertically through 6m?

Answers

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].


El. A horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. How much work is done by the 40 - N force?

E2. A woman does 160 J of work to move a table 4 m across the floor. What is the magnitude of the force that the woman applied to the table if this force is applied in the horizontal direction?

E3. A force of 60 N used to push a chair across a room does 300 J of work. How far does the chair move in this process?

E4. A rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. A frictional force of 120 N opposes this motion.

a. What is the work done by the force applied by the rope?

b. What is the work done by the frictional force?

c. What is the total work done on the crate?​

Answers

The same formula of work can be applied to all the questions. The answers are:

E1. 100J

E2. 40N

E3. 5m

E4. a.) 360 J           b.) 240 J               c.) 120 J

El. If a horizontally directed force of 40 N is used to pull a box a distance of 2.5 m across a tabletop. The formula to get the much work that will be done by the 40 - N force will be

Work done = force x distance

Work done = 40 x 2.5

Work done = 100 J

E2. If a woman does 160 J of work to move a table 4 m across the floor. We will use the same formula to calculate the magnitude of the force that the woman applied to the table assuming the force is applied in the horizontal direction.

Work done = force x distance

160 = 4F

F = 160/4

Force F = 40 N

E3. Given that a force of 60 N used to push a chair across a room does 300 J of work. Same formula to get how far the chair move in this process.

Work done = force x distance

300 = 60 x distance

distance = 300/60

Distance = 5 m

Therefore, the chair moved 5m away.

E4. Given that a rope applies a horizontal force of 180 N to pull a crate a distance of 2 m across the floor. And a frictional force of 120 N opposes this motion.

a. The work done by the force applied by the rope can  be found by

W = F x S

W = 180 x 2

W = 360 J

b. What is the work done by the frictional force?

W = [tex]F_{r}[/tex] x s

W = 120 x 2

W = 240 J

c. What is the total work done on the crate?

W = (F - [tex]F_{r}[/tex]) x distance

Where  [tex]F_{r}[/tex]  = frictional force

Substitute all the parameters

W = (180 - 120) x 2

W = 60 x 2

W = 120 J

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Which type of border shows the division between Sonora and Chihuahua?

National border
State border
Physical boundary
Natural boundary

Answers

The answer is the national border

You're driving your pickup truck around a curve with a radius of 22 m. A box in the back of the truck is pressed up against the wall of the truck. How fast must you drive so that the force of the wall on the box equals the weight of the box?

Answers

Answer:

Explanation:

Centrifugal force Fc = m x v2 / r

Weight  = mg

As required by the question

Fc = W

v2 /r = g

given radius r = 22 m

v2 /22 = 9.8

Solve for v

required speed v = √(22 * 9.8)

= 14.35 m/s

v=15 m/s

this may help you

The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.

What is centrifugal force?

The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.

The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:

[tex]{\displaystyle F=m\omega ^{2}r}[/tex]

Given, the radius of the curve, r = 22m

The acceleration, a = v²/r

The weight of the box, W = mg

We know that, F = ma

mg = m(v²/r)

v = √gr

[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]

v = 14.68 m/s

Therefore, you should drive at a speed of 14.68 m/s

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Here's a question from ~ [ AIEEE 2002 ]

The minimum velocity ( in m/s ) with which a car driver must traverse a flat curve of radius 150 m and Coefficient of friction 0.6 to avoid skidding is ~

[ I'm looking for Proper Information, and please don't get it from any Website ]

Thanks for Answering !​

Answers

r=150mcoefficient of friction=[tex]\mu[/tex]=0.6

As car is avoid skidding

[tex]\\ \sf\hookrightarrow \dfrac{mv^2}{r}=\mu mg[/tex]

Cancel m

[tex]\\ \sf\hookrightarrow \dfrac{v^2}{r}=\mu g[/tex]

[tex]\\ \sf\hookrightarrow v^2=\mu rg[/tex]

[tex]\\ \sf\hookrightarrow v^2=0.6(10)(150)[/tex]

[tex]\\ \sf\hookrightarrow v^2=60(150)[/tex]

[tex]\\ \sf\hookrightarrow v^2=900[/tex]

[tex]\\ \sf\hookrightarrow v=30ms^{-1}[/tex]

Done

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

The given parameters:

Radius of the curve, r = 150 mCoefficient of friction, μ = 0.6

The minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is calculated as follows;

[tex]\frac{mv^2}{r} = \mu mg\\\\v^2 = \frac{\mu mgr}{m} \\\\v^2 = \mu gr\\\\v = \sqrt{\mu gr} \\\\v = \sqrt{0.6 \times 9.8 \times 150} \\\\v = 29.7 \ m/s[/tex]

Thus, the minimum velocity of the with which the car driver must traverse the flat curve to avoid skidding is 29.7 m/s.

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A roller coaster goes from 2.00 m/s [forward] to 10.0 m/s [forward) in 4.50 s. What is its acceleration?

Answers

The answer would be 1.77778:

We must use the kinematic equation v = v0 + at, then fill in the elements given and solve which equals 1.77778

Maria drove 100 miles in 2 hrs. what was marias speed?​

Answers

50 miles per hour was Maria’s speed

given the formula p=mv what are the units of p

Answers

Answer:

They are kg * m/s.

The unit of the momentum p would be kg × m/s..

What is momentum?

Momentum is defined as the ability or tendency of an object to continue moving.

Also momentum is the product of mass and velocity. It can be shown as follows;

p = m × v

where,    

p = momentum

m = mass

v = velocity

Thus, we can conclude that the formula p = mv show the relationship between momentum, mass, and velocity.

Now the unit of the momentum p would be;

p = m × v

p = kg × m/s

Hence, the unit of the momentum p would be kg × m/s.

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Ciara is swinging a 0.015 kg ball tied to a string around her head in a flat, horizontal circle. The radius of the circle is 0.50 m. It takes the ball 0.70 seconds to complete one full circle. Calculate the tension in the string and its direction that provides the centripetal force acting on the ball to keep it in the circular path. (3 points)

0.60 N, along the line tangent to the circle
0.015 N, along the line tangent to the circle
0.60 N, toward the center of the circle
0.015 N, toward the center of the circle

Answers

Answer:

0.60N along the line tangent to the circle

Answer:

A is the answer

Explanation:

Just got finished with the quiz! Hope this helps <3

A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

Answers

The final speed of the combined masses is 0.21 m/s

Applying the law of conservation of momentum:

Total momentum before collision = Total momentum after collision.

⇒ Formula:

MU+mu = V(M+m).................. Equation 1

⇒ Where:

M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.

From the question,

⇒ Given:

M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)

⇒ Substitute these values into equation 1

0.24(0.6)+0.26(-0.20) = V(0.24+0.2)

⇒ Solve for V

0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/s

Hence the final speed of the combined masses is 0.21 m/s

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Heat always moves from hot to cold through the processes of?

Answers

Answer: The processes are conduction, convection and radiation.

Explanation: Unless people interfere, thermal energy — or heat — naturally flows in one direction only: from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection and radiation. Sometimes more than one may occur at the same time.

A cannonball explodes in mid-air, fragmenting into several pieces. How does the total
momentum of the pieces after the explosion compare to the total momentum of the
cannonball just before the explosion?
I. They are the same
II. The momentum of the fragments is less than the momentum of the cannonball
III. The momentum of the fragments is more than the momentum of the cannonball

Answers

Hi there!

I. They are the same.

Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.

how many asteroids do scientists believe exist in the solar system?

Answers

Answer:

Astronomers think there are between 1.1 and 1.9 million asteroids in the solar system.

Explanation:

9- Under what circumstances would a vector have components that are equal in
magnitude?
a. if the vector is oriented at 45° from the axes.
b. if the vector is oriented at 90° from the axes.
c. if the vector is oriented at 0° from the X -axis.
d. if the vector is oriented at 0° from the y-axis.
itude of 30 units Vector B is perpendicular to vector A

Answers

Explanation:

c. if the vector is oriented at 0° from the X -axis.

Explain Body Mechanics.
PLUS BRAINLY! and 50 Points

Answers

Answer Body mechanics is a term used to describe the ways we move as we go about our daily lives. It includes how we hold our bodies when we sit, stand, lift, carry, bend, and sleep. ... Good body mechanics means using the body's strength to the best mechanical advantage to do a task efficiently and without injury.

Explanation:

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectile is modeled using the equation h(t) = â€""16t2 48t 190. Approximately when will the projectile hit the ground? 1. 5 seconds 3. 2 seconds 5. 3 seconds 6. 2 seconds.

Answers

The time for the projectile to hit the ground from the given position is 1.5 s.

The given parameters:

Initial velocity of the projectile, u = 48 ft/sHeight, h = 190 ftModel of the projectile path, h(t)  = –16t² + 48t + 190.

The time for the projectile to hit the ground is calculated as follows:

when the projectile hits the ground, the final velocity = 0

[tex]v_f = 0\\\\\frac{dh(t)}{dt} = v_f\\\\\frac{dh(t)}{dt} = -32t + 48\\\\-32t+48 = 0\\\\32t = 48\\\\t = \frac{48}{32} \\\\t = 1.5 \ s[/tex]

Thus, the time for the projectile to hit the ground from the given position is 1.5 s.

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Which best describes why a liquid needs a container when a solid does not?
O Solids fill their containers, and liquids have definite shapes.
Solids have definite shapes, and liquids fill their containers.
Solids particles will expand to fill their containers, and liquid particles will expand as well.
O Solids particles expand to fill their containers, and liquid particles do not.

Answers

Answer: Solids have definite shapes and liquids fill their containers.

Explanation: Liquids have got further apart molecules than solids, so the liquid molecules have a higher degree of locomotion than solid molecules, hence able to fill the container though without a definite volume, which is not the case for solid molecules.

the normal formula to find force is F = m*a. What kind of math do you need to do
to find the mass of an object?

- Divide: F / a
- Divide: a / F
- Multiply: F* a
- Subtract: F - a

Answers

[tex]\\ \sf\Rrightarrow F=ma[/tex]

Take a to leftAs it's multiplied on right side it will be divided on right side.

[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]

Or

[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]

how to read a micrometer on a clark cm-100 vickers hardness tester

Answers

Answer:

Explanation:

Equipment manufactured by LECO(8 Corporation, St. Joseph, Michigan is warranted free from defect in material

and workmanship for a period of six months from the date of purchase. Equipment not manufactured by LECO is

covered to the extent of warranty provided by the original manufacturer and this warranty does not cover any

equipment, new or used, purchased from anyone other than the LECO Corporation. All replacement parts shall

be covered under warranty for a period of thirt days from date of purchase. LECO MAKES NO OTHER

REPRESENTATION OR WARRANTY OF ANY OTHER KIND, EXPRESSED OR IMPLIED, WITH RESPECT TO

THE GOODS SOLD HEREUNDER, WHETHER AS TO MERCHANTABILITY, FITNESS FOR PURPOSE, OR

OTHERWISE.

Expendable items such as crucibles, combustion tubes, chemicals and items of like nature are not covered by

this warranty.

LECO's sole obligation under this warranty shall be to repair or replace any part or parts which, to our

satisfaction, prove to be defective upon return prepaid to LECO Corporation, St. Joseph, Michigan. This

obligation does not include labor to install replacement parts, nor does it cover any failure due to accident, abuse,

neglect, or use in disregard of instructions furnished by LECO. In no event shall damages for defective goods

exceed the purchase price of the goods, and LECO SHALL NOT BE LIABLE FOR INCIDENTAL OR

CONSEQUENTIAL DAMAGES WHATSOEVER.

All claims in regard to the parts or equipment must be made within ten (10) days after Purchaser learns of the

facts upon which the claim is based. Authorization must be obtained from LECO prior to returning any other

parts. This warranty is voided by failure to comply with these notice requirements.

NOTICE

The warranty on LECO equipment remains valid only when genuine LECO replacernent parts are employed.

Since LECO has no control over the quality or purity of consumable products not manufactured by LECO, the

specifications for accuracy of results using LECO instruments are not guaranteed unless genuine LECO

consumables are employed in conjunction with LECO instruments. If purchaser defaults in making payment for

any parts or equipment, this warranty shall be void and shall not apply to such parts and equipment. No late

payment or cure of default in payment shall extend the warranty period provided herein.

LECO Corporation is not responsible for damage to any associated instruments, equipment or apparatus nor wil

LECO be held liable for loss of profit or other special damages resulting from abuse, neglect, or use in disregard

of instructions. The Buyer, their employees, agents and successors in interest assume all risks and liabilities for

the operation, use and/or misuse of the product(s) described herein and agree to indemnify, hold harmless and

defend the seller from any and all claims and actions arising from any cause whatsoever, including seller's

negligence for personal injury incurred in connection with the use of said product(s) and any and all damages

proximately resulting therefrom.

CAUTION

The instrument should be operated only by technically qualified individuals who have fully read and understand

these instructions. The instrument should be operated only in accordance with these instructions.

The operator should follow all ,of the warnings and cautions set forth in the manual and the operator should follow

and employ all applicable standard laboratory safety procedures.

LECO'" is a registered trademark of the LECO Corporatio

15. Find the density of a certain object that has the dimensions 2cm x 6cm x 7cm and a
mass of 42g.
16. What is the volume of a container of liquid that has a density of 120g/ml and a mass
of 17g.
17. If the mass of an object has a mass of 23g and a volume 123ml, what is its density.
“Express your answer in Kg/ml!"
18. What is the volume of a cubed object with a measure of 12cm on one of its sides, if
the mass of that same object is 45g and its density is 240g/cm3?
19. An object with a density of 3g/ml is placed into a body of water. Since the density of
water is 1g/ml, will this object sink or float.

Answers

This question is asking for five different questions about density, mass and volume which can be all summarized with the following definition of density as the degree of compactness of the objects taken into consideration:

[tex]\rho =\frac{m}{V}[/tex]

In such a way, we can proceed as follows:

15. the mass is given as 42 g and the volume can be found by multiplying the given dimensions:

[tex]V=2cm*6cm*7cm=84 cm^3[/tex]

And the density turns out to be:

[tex]\rho =\frac{42g}{84cm^3}=0.5 g/cm^3[/tex]

16. both mass and density are given as 17 g and 120 g/mL respectively, so that we have to solve for the volume as shown below:

[tex]V=\frac{m}{\rho} =\frac{17g}{120g/mL} =0.14 mL[/tex]

17. the mass is given as 23 g and the volume as 123 mL, so that the density is calculated as shown below:

[tex]\rho=\frac{23g}{123 mL} =0.19 g/mL[/tex]

Which can be converted to kg/mL as follows:

[tex]0.19\frac{g}{mL} *\frac{1kg}{1000g}=0.00019 kg/mL[/tex]

18. the mass is given as 45 g and the density as 240 g/cm³, so we can solve for the volume as follows:

[tex]V=\frac{m}{\rho} =\frac{45g}{240g/cm^3}=0.19 cm^3[/tex]

19. In this case, since the water has lower density than the object, we can infer that the latter is heavier than the former, this means that the object will sink according to the Archimedes principle.

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