this picture shows part of an organ system in a human body what is the main function of the organs shown

Answers

Answer 1

The kidney and bladder are part of the organ system depicted, and its job is to extract water and salts from the blood.

The kidney is in charge of filtering blood as well as eliminating extra salt, water, and waste from the body. Prior to being expelled from the body, the bladder holds urine produced by the kidneys. By filtering waste and extra water from the blood and excreting them as urine, they are essential to preserving the body's internal ecology. An essential job of the urinary system, which is made up of the kidneys, bladder, and related tissues, is to remove water and salts from the body.

Therefore, the correct option is C.

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Your question is incomplete, most probably the complete question is:

The picture shows an organ system in the human body.

Kidney and Bladder

What is a function of the organ system shown?

This Picture Shows Part Of An Organ System In A Human Body What Is The Main Function Of The Organs Shown

Related Questions

What force helps draw materials into a capillary?

Answers

The force that helps draw materials into a capillary is capillary action. This is a result of the intermolecular forces between the liquid and the walls of the capillary, which causes the liquid to be drawn up into the narrow tube.

The adhesive forces between the liquid and the capillary wall overcome the cohesive forces within the liquid, allowing it to rise up the capillary. This is how liquids like water can travel through small tubes or narrow spaces, even against the force of gravity. The force that helps draw materials into a capillary is called capillary action. Capillary action is the ability of a liquid to flow through narrow spaces, such as capillary tubes, due to the forces of adhesion, cohesion, and surface tension. This force allows materials to be drawn into the capillary without the need for external assistance.

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In Graves' disease, the immune system makes antibodies that stimulate TSH receptors on the thyroid gland. What effect does this have on Krista's thyroid?

Answers

Krista's thyroid is that it causes the thyroid gland to become overactive, producing excessive amounts of thyroid hormones.



The antibodies mimic the action of TSH (thyroid-stimulating hormone) by binding to TSH receptors.

This binding results in the thyroid gland increasing hormone production, leading to hyperthyroidism.



Hence, the effect of Graves' disease on Krista's thyroid is that it stimulates TSH receptors, causing the thyroid gland to produce excessive thyroid hormones, leading to hyperthyroidism.

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What is the colorless, jelly-like substance found inside cells?
A) water
B) cell membraneâ
C) carbohydrates
D) protoplasm

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The colorless, jelly-like substance found inside cells is called protoplasm. So the correct option is D. Protoplasm

Protoplasm is a thick, colorless, and jelly-like substance that fills the interior of cells. It is composed of a complex mixture of organic and inorganic molecules, including water, proteins, carbohydrates, lipids, nucleic acids, and various ions. Protoplasm is essential for the survival and function of cells, as it provides the medium for the biochemical reactions that occur within the cell. It also serves as a support structure for the organelles within the cell, such as the mitochondria, ribosomes, and endoplasmic reticulum. The composition and structure of protoplasm can vary depending on the type of cell and its function. Understanding the properties and function of protoplasm is essential to understanding the overall function and behavior of cells.

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which of the following is one of the seven basic characteristics used to classify living things? group of answer choices multicellularity vs unicellularity possession or absence of blue pigment in feathers or skin presence or absence of vacuoles in the cell cytoplasm presence or absence of bacteria within the structures of the body presence or absence of green pigment within the organism.

Answers

The characteristic used to classify living things among the options given is "multicellularity vs unicellularity."

Multicellularity vs unicellularity is one of the seven basic characteristics used to classify living things. This characteristic refers to whether an organism is composed of one single cell (unicellular) or many cells (multicellular).

Unicellular organisms are those that are made up of only one cell, and examples include bacteria and yeast. In contrast, multicellular organisms are made up of many cells, and examples include animals, plants, and fungi.

The distinction between unicellular and multicellular organisms is important because it affects their overall structure, function, and behavior. Multicellular organisms have specialized cells that are organized into tissues, organs, and organ systems, allowing them to carry out more complex functions and behaviors than unicellular organisms.

Overall, multicellularity vs unicellularity is an important characteristic used to classify living things and understand their biological complexity.

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correct form of question

which of the following is one of the seven basic characteristics used to classify living things? group of answer choices

multicellularity vs unicellularity

possession or absence of blue pigment in feathers or skin

presence or absence of vacuoles in the cell cytoplasm

presence or absence of bacteria within the structures of the body

presence or absence of green pigment within the organism.

the atp synthase in this cell is engineered to have 15 c subunits in the c-ring. otherwise, the synthase has the composition of other mammalian synthases. determine the total number of atps can be formed from the h being pumped back through the synthase? (2 pts)

Answers

The total number of ATPs that can be formed from H⁺ being pumped back through the engineered ATP synthase with 15 c subunits in the c-ring is approximately 5.625 ATPs.

To determine the total number of ATPs that can be formed from H⁺ being pumped back through the ATP synthase with 15 c subunits in the c-ring, we need to consider the following steps:

1. Understand that ATP synthase is a protein complex that produces ATP from ADP and inorganic phosphate (Pi) using the energy provided by the proton motive force (H⁺ gradient).


2. In mammalian ATP synthase, the c-ring typically has 8 c subunits. This means 8 H⁺ ions are required to rotate the c-ring 360 degrees for one complete rotation.


3. However, in this engineered ATP synthase, the c-ring has 15 c subunits. So, 15 H⁺ ions are required for one complete rotation of the c-ring.


4. One complete rotation of the c-ring generates 3 ATP molecules in mammalian ATP synthase.


5. To determine the total number of ATPs generated in this engineered ATP synthase, we need to compare the number of H⁺ ions required for both the engineered and the typical mammalian ATP synthase: 15 H⁺ ions (engineered) / 8 H⁺ ions (typical) = 1.875.


6. Multiply the ratio (1.875) by the number of ATPs generated per rotation in mammalian ATP synthase (3 ATPs): 1.875 * 3 = 5.625 ATPs.

Therefore, the total number of ATPs that can be formed from H⁺ are approximately 5.625 ATPs.

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The _____ nervous system carries impulses or messages to the central nervous system.
A) autonomic
B) peripheral
D) primary
D) precipitate

Answers

The peripheral nervous system carries impulses or messages to the central nervous system. So, the correct answer is B) peripheral.

It consists of two major divisions: the somatic nervous system and the autonomic nervous system. The somatic nervous system is responsible for voluntary activities such as movement, while the autonomic nervous system is responsible for involuntary activities such as maintaining blood pressure and digestion. The PNS is composed of a network of nerves and ganglia (clusters of nerve cell bodies) that connect the CNS to the rest of the body. It is made up of afferent nerves, which send signals from the body to the CNS, and efferent nerves, which send signals from the CNS to the body.

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Based on their shape, bones that have a length about equal to their width are classified as _____ bones.

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Based on their shape, bones that have a length about equal to their width are classified as short bones.


Long bones are classified as bones that have a length about equal to their width. This type of bone is found in the arms, legs, fingers, and toes of the human body.

They consist of a long cylindrical shaft called the diaphysis, which is hollow and filled with bone marrow, and two bulbous ends called the epiphyses, which are covered with articular cartilage to allow for smooth movement at joints. Long bones are important for support, movement, and the production of blood cells in the bone marrow.

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When food is swallowed, the tongue pushes down the ______ to close the glottis and direct food into the esophagus behind it.

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When food is swallowed, the tongue pushes down the epiglottis to close the glottis and direct food into the esophagus behind it.

When we swallow, a complex series of muscular contractions and movements occur in the mouth and throat to move the food or liquid from the mouth to the stomach. The tongue plays a crucial role in this process by pushing the food or liquid to the back of the mouth and initiating the swallowing reflex.

As the food or liquid moves towards the back of the mouth, the epiglottis moves to cover the opening of the trachea, preventing any food or liquid from entering the lungs. The epiglottis acts like a trapdoor that covers the entrance to the trachea, directing the swallowed material to the esophagus instead.

The esophagus is a muscular tube that connects the mouth to the stomach. It contracts rhythmically to move the food or liquid down to the stomach, using a wave-like motion called peristalsis. Once the food or liquid reaches the stomach, it is mixed with stomach acid and enzymes to begin the process of digestion.

In summary, the tongue and epiglottis work together to ensure that food and liquid are directed safely to the esophagus and stomach, while preventing any material from entering the trachea and lungs. This process is essential for efficient digestion and respiration, and any disruption in this process can lead to choking and other serious health problems.

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Describe how matter changes forms and moves between organisms. a. Describe how a heterotroph obtains organic matter. (2 points) b . Describe where and how the organic matter formed. (4 points) c . Describe two ways the organic matter changes after it enters the heterotroph . ( 4 point)

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Matter changes forms through physical and chemical processes while it moves between organisms through ecological processes. (a) A heterotroph obtains organic matter by feeding on other organisms. (b) Organic matter is formed in the chloroplasts of plant cells through the process of photosynthesis. (c) Two ways the organic matter changes after it enters a heterotroph include metabolism and storage.

Matter changes forms as a result of physical and chemical processes. Matter can flow between species through ecological processes like photosynthesis, consumption, as well as decomposition.

(a) Photosynthetic organisms, like plants, harness solar energy to transform carbon dioxide and water into organic matter. Heterotrophs, such as animals, consume this organic matter, and when they pass away or leave behind waste, decomposers convert this organic material into more easily utilizable inorganic molecules.

For example, animals such as tigers and humans feed on other animals, whereas, fungi decompose dead organisms or waste products to obtain organic matter.

(b) The organic matter is synthesized within the chloroplasts of plant cells   via photosynthesis. Plants utilize the light energy from the Sun to synthesize organic matter (glucose) and oxygen from carbon dioxide and water.

(c) The organic matter obtained by heterotrophs can go through a variety of transformations. First, it is broken down into simpler chemicals by metabolic processes such as digestion. Second, it can be used to generate energy for the growth and other biological processes of heterotrophs.

The heterotroph can store the extra organic matter for later use, in the fat cells present in their body.

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Which of the following are plausible responses to the objection that cloned people would not be unique individuals, and thus be deprived of human dignity and worth?
a. Clones will be able to avoid mistakes made by their older "twins."
b. Identical twins are more like each other than a clone would be to the one cloned.
c. Clones would be different from everyone but their progenitors, and therefore would have dignity and worth except when compared to their progenitors.
d. Clones and the individual cloned will have the same personality, but will be able to use it in different ways.

Answers

The following are plausible responses to the objection that cloned people would not be unique individuals, and thus be deprived of human dignity and worth is a. Clones will be able to avoid mistakes made by their older "twins."

In response to the objection that cloned people  frstly, identical twins are more like each other than a clone would be to the one cloned (option b). This is because clones share only genetic similarities, whereas identical twins share the same environment and upbringing as well.  Secondly, clones would be different from everyone but their progenitors, and therefore would have dignity and worth except when compared to their progenitors (option c). This implies that clones would still have their own individuality and uniqueness, as they would only share genetic information with their progenitors and not their experiences or environment.

Lastly, clones and the individual cloned will have the same personality, but will be able to use it in different ways (option d). While they may share genetic traits, the development of personality is influenced by a combination of genetics, environment, and life experiences. Therefore, the clone and the individual cloned would still have unique identities and abilities to contribute to society. The following are plausible responses to the objection that cloned people would not be unique individuals, and thus be deprived of human dignity and worth is a. Clones will be able to avoid mistakes made by their older "twins."

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How does the parasympathetic division act at rest?

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The parasympathetic division of the autonomic nervous system is responsible for regulating bodily functions during periods of rest and relaxation.

When the body is at rest, the parasympathetic nervous system helps to conserve energy and promote restoration by slowing down the heart rate, decreasing blood pressure, and stimulating digestion. The parasympathetic division acts to maintain a state of calm and relaxation in the body during periods of rest. This division promotes rest and digest activities such as the release of digestive enzymes, stimulation of urination, and reduction of pupil size.

Overall, the parasympathetic division is essential for maintaining balance in the body and promoting a healthy state of relaxation.

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Venous circulation is considered to terminate in the

Answers

Answer:

In both Atria

PLEASEEEE SOMEONE HELPPPPP ASAP

Answers

Answer:

row 1: CGT TC

row 2: AAT GC

row 3: CTA TG

row 4: GCC TA

Regarding replication of an enveloped animal virus, match the stage of replication with its definition uncoating assembly adsorption penetration Synthesis release Match each of the options above to the tems below 4 virus attaches to its host cell by binding cell surface receptors virus is engulfed in a vesicle or endosome and transported internally vesicle membrane and viral envelope fuse, releasing capsid into the host cytoplasm 4 under control of viral genes, the host celf synthesizes all the components needed to assemble new viral particles viral nucleic acid encased in capsid, viral proteins inserted in host cell membrane viruses bud off from the host cell membrane

Answers

the stages of replication of an enveloped animal virus, matched with their respective definitions:

1. Adsorption: This is the stage where the virus attaches to its host cell by binding to cell surface receptors.

2. Penetration: During this stage, the virus is engulfed in a vesicle or endosome and transported internally.

3. Uncoating: Here, the vesicle membrane and viral envelope fuse, releasing the capsid into the host cytoplasm.

4. Synthesis: Under the control of viral genes, the host cell synthesizes all the components needed to assemble new viral particles.

5. Assembly: The viral nucleic acid is encased in the capsid, and viral proteins are inserted into the host cell membrane to assemble new viral particles.

6. Release: Finally, the new viruses bud off from the host cell membrane to begin the infection of other cells.

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Where on the body is thin skin (with four epidermal layers) found?

Answers

Thin skin with four epidermal layers is primarily found on the body's surface, including areas such as the forearms, upper chest, back, and lower legs.

This type of skin is characterized by a thinner epidermal layer, which contains fewer layers of cells compared to thick skin. Thin skin is also hair-bearing and contains sweat glands, while thick skin is hairless and lacks sweat glands. The thinner epidermal layer in thin skin allows for greater sensitivity to touch, heat, and cold, making it ideal for tactile sensations. It is also more susceptible to damage from the environment, such as sun exposure and friction. Understanding the differences between thin and thick skin is important for dermatologists and other medical professionals in diagnosing and treating various skin conditions, such as psoriasis and eczema. By understanding where thin skin is found on the body, medical professionals can more effectively diagnose and treat conditions that affect this type of skin.

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The largest bone of the arm, extending from the elbow to the shoulder, is the:
A) clavicle
B) ulna
C) humerus
D) radius

Answers

The largest bone of the arm, extending from the elbow to the shoulder, is the humerus.

The humerus is a long bone that connects the shoulder to the elbow joint and is responsible for most of the movement of the arm. It is located between the scapula (shoulder blade) and the radius and ulna bones of the forearm. The humerus has several important features that allow for its function in the arm. The proximal end of the bone forms the shoulder joint with the scapula, while the distal end forms the elbow joint with the radius and ulna bones. The upper part of the humerus is rounded, forming the head of the humerus, which fits into the socket of the scapula to allow for shoulder movement.

The humerus also has several muscle attachments, including the deltoid, biceps, and triceps muscles, which allow for movement of the arm at the shoulder and elbow joints. The humerus is also responsible for transmitting the weight of the arm to the bones of the forearm, allowing for support and stability during activities such as lifting or pushing. Overall, the humerus is a crucial bone for arm function, connecting the shoulder to the elbow and providing support and movement for the upper limb.

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If a paramecium swims from a hypotonic to an isotonic envioronment, will its contractile vacuole become more or less active? Why?
CC 7.3

Answers

If a paramecium swims from a hypotonic to an isotonic environment, its contractile vacuole will become less active. This is because in a hypotonic environment, water moves into the paramecium causing it to swell and potentially burst. The contractile vacuole functions to remove excess water from the paramecium to maintain its shape and prevent it from bursting.

However, in an isotonic environment, there is no net movement of water into or out of the paramecium, so the contractile vacuole does not need to work as hard to remove excess water. Therefore, the paramecium will require less active transport to maintain its osmotic balance in an isotonic environment compared to a hypotonic environment.

Paramecium is a type of ciliates that can live in hypotonic fresh water. It is a single-celled eukaryotic organism with eight flagella that enable it to move. The paramecium can survive in freshwater, containing less salt and minerals than salt water.

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Which of the following is an example of epithelial to mesenchymal transition? SELECT ALL CORRECT ANSWERS
A. epiboly in zebrafish
B. PMCs ingressing in sea urchin
C. endoderm and mesoderm cells ingressing through the primitive streak in chick
D. the invagination of the archenteron in sea urchin

Answers

An example of epithelial to mesenchymal transition are PMCs ingressing in sea urchin and endoderm and mesoderm cells ingressing through the primitive streak in chick. So the correct answer is B and C.


Epithelial to mesenchymal transition (EMT) is a process by which epithelial cells undergo a transformation into mesenchymal cells, which are more migratory and invasive in nature. This process plays a crucial role in embryonic development, tissue repair, and cancer metastasis.

In option B, PMCs (Primary Mesenchyme Cells) ingressing in sea urchin undergo EMT as they transform from epithelial cells at the surface of the embryo into mesenchymal cells that migrate inward and contribute to the formation of the mesodermal structures.

In option C, endoderm and mesoderm cells ingressing through the primitive streak in chick also undergo EMT as they transition from an epithelial layer to a more mesenchymal phenotype, allowing them to migrate and differentiate into various tissue types during embryonic development.

Option A, epiboly in zebrafish, involves the movement of epithelial cells but does not necessarily involve EMT as it primarily occurs through intercalation and stretching rather than a transformation of cell types.

Option D, the invagination of the archenteron in sea urchin, does not involve EMT as it primarily involves changes in cell shape and movement rather than a transition from epithelial to mesenchymal cells.

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Which of the following is the most likely reason for the observed differences in the frequency of the G allele between 1965 and 1972?(A) Emigration of white moths from the population(B) Chance(C) Selection against gray phenotypes (D) Speciation(E) Mutation

Answers

The most likely reason for the observed differences in the frequency of the G allele between 1965 and 1972 is the selection against gray phenotypes.

The G allele provides a genetic advantage to the white moth population, as it allows them to blend in with their surroundings and avoid predation. Therefore, natural selection would favor the increase in the frequency of the G allele over time. This is supported by the fact that the frequency of the G allele increased from 1% in 1965 to 99% in 1972, which is a significant change over a relatively short period of time.

Emigration of white moths from the population is unlikely to have caused the observed differences in the frequency of the G allele, as this would have led to a decrease in the frequency of the G allele in the remaining population. Chance is also an unlikely explanation, as the significant increase in the frequency of the G allele over time suggests that there is a selective advantage to this allele. Speciation and mutation are also unlikely explanations, as they refer to much larger evolutionary processes that would not occur over such a short period of time.

In summary, selection against gray phenotypes is the most likely reason for the observed differences in the frequency of the G allele between 1965 and 1972 in the white moth population.

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which of the below animals is the least related to the others, evolutionarily? group of answer choices lobster parasitic nematode worm snail beetle centipede

Answers

The parasitic nematode worm is the least related to the other animals in the list, as it belongs to a different phylum and has a distinct body plan and evolutionary history.

Out of the given options, the parasitic nematode worm is the least related to the others evolutionarily. This is because nematodes are a completely different phylum (Nematoda) from the rest of the animals in the list, which all belong to the phylum Arthropoda. Nematodes are unsegmented, cylindrical worms with a tough cuticle, while arthropods have segmented bodies, jointed limbs, and exoskeletons.

Additionally, nematodes have a different body plan and developmental pathway compared to arthropods, and they are more closely related to other worm-like animals such as flatworms and roundworms. The remaining animals in the list are all arthropods, which means they share a more recent common ancestor and have more similarities in their evolutionary history.

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How can the social factors of sustainability be used to reduce the likelihood of a
sixth mass extinction driven by human activity?
REMEMBER that the social factors are ECONOMICS, POLITICAL SCIENCE, and
ETHICS.

Answers

The likelihood of a sixth mass extinction brought on by human activities by utilizing the social sustainability aspects of economics, political science, and ethics, can promote a more sustainable relationship between mankind and nature and stop future loss of biodiversity.

Economics, political science, and ethics, three social aspects of sustainability, can be extremely important in lowering the probability of a sixth mass extinction brought on by human activities. These are a few applications for these factors:

Economics: Economic systems have the power to encourage ecologically friendly behaviours while discouraging unsustainable ones. Economic strategies that can be implemented by both governments and corporations include carbon pricing, renewable energy subsidies, and taxes on resource extraction and pollution. Economic rewards can motivate people and organizations to engage in sustainable practices, such as lowering greenhouse gas emissions, conserving resources, and preserving biodiversity.

Political science: Political systems have the power to influence environmental laws and policies that are essential for averting a global extinction. Legislators can pass and implement measures to save threatened and endangered species, control deforestation.

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Discuss; what is the difference between hypertrophy and atrophy and give an example of how each might occur.

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Hypertrophy is an increase in cell size or tissue mass, while atrophy is a decrease. An example of hypertrophy is muscle growth from exercise, and atrophy is muscle wasting from disuse.

Hypertrophy and atrophy are two opposite processes that affect cells, tissues, and organs. Hypertrophy refers to an increase in cell size or tissue mass due to increased workload or stimulation, such as muscle growth from exercise or heart enlargement from hypertension. Atrophy, on the other hand, is a decrease in cell size or tissue mass that occurs due to reduced workload or stimulation, such as muscle wasting from disuse or nerve damage leading to muscle loss. Both processes can have significant impacts on an individual's overall health and functioning, and understanding the differences between them can help guide appropriate interventions to prevent or treat them.

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An open system in which the growth rate is maintained by adding a nutrient (present in limiting quantities) at the same rate as that medium containing micro-organisms is removed is called
A.manostat
B. chemostat
C. turbidostat
D. culturostat

Answers

The open system described in the question is called a chemostat. In a chemostat, the growth rate of microorganisms is controlled by adding nutrients at the same rate as they are consumed, thus maintaining a constant nutrient concentration in the system.

This is done by continuously removing a portion of the culture and replacing it with fresh medium containing the limiting nutrient. The chemostat is commonly used in microbiology research to study microbial growth dynamics and to maintain cultures of microorganisms in a controlled environment.

An open system is a system that has external interactions. Such interactions can take the form of information, energy, or material transfers into or out of the system boundary, depending on the discipline which defines the concept.

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differences in an organisms traits such as lactose intolerance are determined by differences in?

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Differences in an organism's traits such as lactose intolerance are determined by differences in lactase enzyme.

What is lactose intolerance?

Lactose intolerance is usually caused by a lack of lactase, an enzyme in the body. Abdominal cramps, bloating, and diarrhea are common symptoms.

The treatment centers on avoiding dairy products, using lactose-free goods, or taking lactase supplements.

Lactase deficit occurs when your body does not manufacture enough lactase.

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if there are 20 centromeres in a cell at anaphase, how many chromosomes are there in each daughter cell following cytokinesis?
a. 20
b. 10
c. 30
d. 40

Answers

Answer:

10 chromosomes

Explanation:

At anaphase, there are 20 centromeres, indicating 20 chromosomes.

Following cytokinesis, the chromosomes are equally distributed between the two daughter cells, resulting in each daughter cell having 20 chromosomes.

During anaphase, the sister chromatids of each chromosome are pulled apart and move toward opposite poles of the cell. This separation is facilitated by the spindle fibers that attach to the chromosomes via the centromeres.

The number of centromeres and chromosomes present in a cell at anaphase is the same as that in the previous stage of mitosis, which is metaphase.

Therefore, if it is given that at anaphase, there are 20 centromeres, then there are 20 chromosomes present in the cell. After the chromosomes are separated, cytokinesis occurs, resulting in the formation of two daughter cells, each containing 20 chromosomes.

It is important to note that the number of chromosomes and centromeres in a cell may vary depending on the organism, tissue type, and stage of the cell cycle.

For instance, human somatic cells typically contain 46 chromosomes or 23 pairs, while sex cells or gametes contain only 23 chromosomes. Additionally, some cells, such as those in cancerous tissues, may have an abnormal number of chromosomes due to mutations or chromosomal abnormalities.

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dna profiling has proven to be a huge asset to solving many forensic investigations. list four high-profile instances in which dna profiling was used in a forensic investigation

Answers


The 4 cases demonstrate the immense power and potential of DNA profiling in forensic investigations.

DNA profiling has indeed played a crucial role in solving numerous forensic investigations. Here are four high-profile instances where DNA profiling was used:

1. The O.J. Simpson trial (1995) - DNA profiling played a significant part in the case, with evidence such as bloodstains and gloves found at the crime scene. The defense raised concerns about contamination, but the DNA evidence was a major focus of the trial.

2. The Golden State Killer (2018) - DNA profiling was used to identify and apprehend Joseph James DeAngelo, who was responsible for at least 13 murders, 50 rapes, and numerous burglaries in California from 1974 to 1986.

3. The Green River Killer (2001) - Gary Ridgway was linked to the murders of at least 49 women through DNA profiling. This evidence was crucial in his arrest and conviction.

4. The World Trade Center attacks (2001) - DNA profiling was employed to identify victims from the remains found at the site of the tragedy, helping bring closure to families of those lost in the attack.

These cases demonstrate the immense power and potential of DNA profiling in forensic investigations.

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Which of the following is part of the cell duplication machinery found in animals, but not in plants?a. cell plateb. centrosomec. microtubular organizing centerd. lysosomes

Answers

Answer:

cell plate centrosome microtubular organizing center

Explanation:

The correct answer is b. centrosome.

The centrosome is a microtubular organizing center that is involved in the organization of microtubules during cell division in animal cells, but is not present in plant cells.
Centrosomes play a crucial role in animal cell duplication by organizing the microtubular structures that separate the duplicated chromosomes during cell division. In contrast, plants have a different mechanism called the cell plate, which is responsible for cell division. While both animal and plant cells utilize microtubules during cell division, the centrosome is a unique component specific to animal cells.

The term that refers to the cell duplication machinery found in animals, but not in plants, is " b. centrosome."

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From the virtual lab experiment, did the length of UV exposure time affect the growth of microbes? Describe the correlation and explain why.

Answers

Duration of UV exposure increases, the growth of microbes decreases. As the exposure time increases, more DNA damage occurs, leading to a more significant reduction in microbial growth which is the correlation.

From the virtual lab experiment, there was a clear correlation between the length of UV exposure time and the growth of microbes. The longer the exposure time, the less the microbes grew. This is likely due to the fact that UV radiation damages DNA, which is essential for microbial growth and replication. Therefore, as the exposure time increases, the amount of DNA damage also increases, leading to a decrease in microbial growth.
From the virtual lab experiment, it was observed that the length of UV exposure time did affect the growth of microbes. The correlation between UV exposure time and microbial growth is an inverse relationship. This means that as the duration of UV exposure increases, the growth of microbes decreases.

The reason behind this correlation is that the UV light has the ability to damage the DNA of microbes, which ultimately inhibits their ability to reproduce and grow. As the exposure time increases, more DNA damage occurs, leading to a more significant reduction in microbial growth.

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My Response Based on the data in the figure, a student claimed that since 2007, the carrying capacity of wolves in Yellowstone National Park has been 100 wolves, and the maximum annual per capita growth rate of gray wolves is 0.6 wolves per wolf per year. Which of the following is closest to the calculated wolf population size in 2017 based on the student's claim? A 100 B 103 C 113 D 173

Answers

since the carrying capacity is the maximum number of individuals an environment can support, the population cannot exceed 100 wolves. So, the calculated wolf population size in 2017 based on the student's claim would be closest to which is 100 wolves.

The correct option is :- (A)


1. Determine the time period: 2017 - 2007 = 10 years
2. Calculate the population growth: 0.6 wolves per wolf per year * 10 years = 6 wolves per wolf
3. Multiply the growth rate by the carrying capacity: 6 wolves per wolf * 100 wolves = 600 wolves
4. Add the growth to the carrying capacity: 100 wolves + 600 wolves = 700 wolves

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when should heat fixation take place during the capsular stain

Answers

Heat fixation should take place after the slide has been flooded with the primary stain and rinsed with distilled water during the capsular stain. Heat fixation helps to fix the bacterial cells to the slide, allowing them to withstand subsequent washing and staining steps.

The heat also aids in the penetration of the primary stain into the capsule, improving the staining results. The slide should be briefly heated by passing it over a flame several times, making sure not to overheat or burn the slide. After heat fixation, the slide should be allowed to cool before continuing with the staining process. Overall, heat fixation is an essential step in the capsular stain and should be performed carefully to ensure accurate results.

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