Samantha has 4 1/2 gallons of lemonade for her daughter’s birthday party. Each gallon of lemonade contains 1.5 grams of fat. How many grams of fat are contained in all the lemonade Samantha has for the party?

Answer:

The jar contains 156 grams of zinc

Step-by-step explanation:

Ratios

Let's call

Z=gr of zinc

C=gr of copper

We know the ratio between them in a certain chemical is:

[tex]\displaystyle \frac{Z}{C}=\frac{4}{17}[/tex]

The jar of the chemical contains C=663 gr of copper. Calculate the grams of zinc by solving the above relation for Z:

Multiplying by C:

[tex]\displaystyle Z=\frac{4}{17}\cdot C[/tex]

Substituting the value of C:

[tex]\displaystyle Z=\frac{4}{17}\cdot 663[/tex]

Z=156 gr

The jar contains 156 grams of zinc

Answer:

[tex]\frac{3}{5}[/tex] or 0.6

Step-by-step explanation:

This problem requires the slop formula which is [tex]\frac{y2-y1}{x2-x1}[/tex]

You start with the first point which is (-1,1). This will be x1 and y1.

The next point is (4,4). This will be x2 and y2.

You plug these values into your equation which gives you [tex]\frac{4-1}{4-(-1)}[/tex]

To solve, you evaluate, [tex]\frac{4-1}{4-(-1)}[/tex]  = [tex]\frac{3}{5}[/tex] or 0.6

Answer:

a

[tex]N = 7.0 *10^{44} \ Ways [/tex]

b

[tex]U  = 2.85 *10^{26}\  ways [/tex]

Step-by-step explanation:

From the question we are told that

   The number of students are  n =  100

    The number of dormitories  is  k =  3

    The capacity of the first dormitory is  A =  25

     The capacity of the second dormitory is  B =  35

      The capacity of the third dormitory is  c =  40

Generally the number of way to fill the dormitory up is mathematically represented as

      [tex]N  =  \frac{n!}{A! B!C!}[/tex]

=>   [tex]N  =  \frac{100!}{25! 35! 40!}[/tex]

Here ! stands for factorial, so we will be making use of the factorial functionality in our calculators to  evaluated the above equation

=>   [tex]N  =  \frac{100!}{25! 35! 40!}[/tex]

[tex]N = \frac{9.332622* 10^{157}}{[1.551121* 10^{25}]* [1.0333148* 10^{40}] * [8.1591528*10^{47}]}[/tex]

[tex]N = 7.0 *10^{44} \ Ways [/tex]

From the question we are told that there are 50 men and  50  women and

     A is  all-men's dorm and  B is all-women's dorm while C is co-ed

So

When A is filled , the number of men that will be remaining to fill dorm C is  50-25 = 25

While when B is filled the number of women that will be remaining to fill dorm C is   50-35 = 15

Generally the number of ways there to fill the dormitories is equivalent to the number of ways of selecting the 25 men and 35 women to fill dormitory A and B plus one more way which is filling dorm C with the remaining students this is  mathematically represented as  

       [tex]U  =  ^{50}C_{35} * ^{50}C_{25}  +  1[/tex]

Here C stands for combination hence we will be making use of the combination functionality in our calculators

     [tex]U  = 2.250829575* ^{12}  * 1.264106064 * 10^{14} +  1[/tex]

=>    [tex]U  = 2.85 *10^{26}\  ways [/tex]

Answer:

(x/2,(y/2)

Step-by-step explanation:

(16/2,24/2)

(8,12)

Answer:

The additional wells for maximum amount of oil per day is 3 wells.

Step-by-step explanation:

Given;

initial number of wells, n = 6

total production, T = 1800

average production per well, = 1800/6 = 300 barrels per day

Let the additional well = y

total number of wells after optimization = 6 + y

new production per well = 300 - 25y

new total production = (6+y)(300-25y)

t = 1800 - 150y + 300y - 25y²

t = 1800 + 150y - 25y²

dt / dy = 150 -50y

for maximum value, dt/dy = 0

150 - 50y = 0

50y = 150

y = 150 / 50

y = 3

Therefore, the additional wells for maximum amount of oil per day is 3 wells.

33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

Given that an oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day, and for each additional well that is drilled, the average production per well decreases by 25 barrels per day, to determine how many additional wells should be drilled to to obtain the maximum amount of oil per day, the following calculation must be performed:

Therefore, 33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.

Learn more in https://brainly.com/question/13581736

Answer:

y+5 = -0.7 (x-1)

Step-by-step explanation:

m = (change in y) / (change in x) = (2-(-5)) / (-9-1) = 7 / (-10) = -0.7

Answer:

Question 1: 20,160 cookies

Question 2: 37,600 letters

Question 3: 252,396 squares on each tablecloth

Question 4: 138,762 points

Question 5: 4,652,352 shrimp

Step-by-step explanation:

Question 1: Multiply 315 and 64 to get amount of cookies

Question 2: Multiply 940 and 40 to get the number of letters

Question 3: Multiply 36 and 7,011

Question 4: Multiply 26 and 5,337 to get the number of points

Question 5: Multiply 96 and 48,462 to get the number of shrimp the chef prepared.

:)

Answer:

2c^2

Step-by-step explanation:

c3-c1=c2

d2-d2=0

8/4=2

Answer:

$8.85

Step-by-step explanation:

Step-by-step explanation: well if you take 23.60 and divide it by 8 you would get 2.95 times that by three and you would get 8.85 and there's your answer.

Answer:

7.35    

because my kid got the question wrong              

Answer:

5 packages

Step-by-step explanation:

One package of blackberries cost $3

Let x represent the number of packages that will cost $15

1 = $3

x= $15

3x= 15

Divide both sides by the coefficient of x which is 3

3x= 15/3

x= 5

Hence 5 packages of blackberries will cost $15

Answer:

freeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

trump 20202020202020020202020

Answer:

0.45576

Step-by-step explanation:

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Standard Deviation = √variance

Mean = 50

= √9

= 3

z = 51 - 50/3

= 0.11111

Probability value from Z-Table:

P(x<51) = 0.54424

P(x>51) = 1 - P(x<51)

= 1 - 0.54424

= 0.45576

The probability that the dealer will sell 51 or more cars is 0.45576

Answer:

Sophia is not correct

Step-by-step explanation:

The given situation represent the problem of a ratio and it is predicted to do the simplify the ratio by determining the smallest possible values

Here it can be presented 60:36 as a fraction i.e. [tex]\frac{60}{36}[/tex]

Now the fraction should be fall by dividing both the numerator and denominator by a common factor i.e. 6

Now after dividing it, the fraction would be [tex]\frac{10}{6}[/tex]

Now it can be further reduced by a common factor i.e. 2

So now the fraction is [tex]\frac{5}{2}[/tex]

Thus, the ratio is 5:2

Hence, she is not correct

Answer:

a- just took the test

Step-by-step explanation:

Answer:

-0.21428571428

Answer:

9 1/66

Step-by-step explanation:

9 x 1 is 9 so its that but to add more proof the problem is 9 1/6, 1 1/11 multiply 6 and 11 it is 66 so the answer is 9 1/66

Answer:

80

Step-by-step explanation:

use the formula of arithmetic progression

Answer:

-24

Step-by-step explanation:

If you are struggling with this here's a tip!

-18+-6 is what you are trying to solve

The 6 is negative, so get rid of the plus sign -18-6

2 negative numbers are just added like positive numbers

So add 18 and 6, you should get 24

Don't forget about the negative!

-24

Answer:

the answer is A) X=m/n-p

Step-by-step explanation:

m/x=n-p

n-p=m/X

(n-p)×x=m

X=m/n-p

Answer:

I am going with B.1,3,9,27

Step-by-step explanation:

A,C and D the patterns are from addition ie. A +8, C+3 and D +1 but B it's ×3

Answer: 10.2272727273

Step-by-step explanation:

Answer:

Each class = 225 glue sticks

22 classes = 225*25  

                   = 5625 glue sticks

Answer:sorry this probably is t the most helpful but the closest i could get was 399 lbs. it’s is st$497.7 for one and $$497.8.

Step-by-step explanation:

Answer:

4,000 -x3

Step-by-step explanation:

x times 3 is equal to the decrease so therefore you take the decrease away form 4/oo

Answer:

3y-x=4,000

Step-by-step explanation:

Answer:

The correct answer is -3

Step-by-step explanation:

attached is a number line to show diagrammatically how to count five units from the chosen point to point 2 on a number line.

Moving five units from -3 to 2 on a number line is given as follows:

-3 ⇒ -2 ⇒ -1 ⇒ 0 ⇒ 1 ⇒ 2

From the motion expression shown above, moving from -3 to 2 involves moving 5 units.

another way of determining the correct answer is to find the difference in interval between the two points as shown below:

Let the point be x

2 - x = 5 units

2 - 5 = x

∴ x = -3

Answer:

-3

Step-by-step explanation:

it was on quiz baby

Answer:

11/132 = 1/12

Step-by-step explanation:

just put the rise over the run and simplify

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

Find the table attached

a) Given

F(x) = 6/x-2

When x = -4

F(-4) = 6/-4-2

F(-4) = 6/-6

F(-4) = -1

F(x) = 6/x-2

When x = -3

F(-3) = 6/-3-2

F(-3) = 6/-5

F(-3) = -1.2

F(x) = 6/x-2

When x = -2

F(-2) = 6/-2-2

F(-2) = 6/-4

F(-2) = -1.5

F(x) = 6/x-2

When x = -1

F(-1) = 6/-1-2

F(-1) = 6/-3

F(-1) = -2.0

F(x) = 6/x-2

When x = 0

F(0) = 6/0-2

F(0) = 6/-2

F(0) = -3

F(x) = 6/x-2

When x = 1

F(1) = 6/1-2

F(1) = 6/-1

F(1) = -6

F(x) = 6/x-2

When x = 2

F(2) = 6/2-2

F(2) = 6/0

F(2) = infty

F(x) = 6/x-2

When x = 3

F(3) = 6/3-2

F(3) = 6/1

F(3) = 6

F(x) = 6/x-2

When x = 4

F(4) = 6/4-2

F(4) = 6/2

F(4) = 3

b) Given

r(x)=6x+12/x^-4

When x = -4

r(-4) = 6(-4)+12/(-4)^-4

r(-4) = -24+12/(1/256)

r(-4) = -12(256)

r(-4) = -3072

When x = -3

r(-3) = 6(-3)+12/(-3)^-4

r(-3) = -18+12/(1/81)

r(-3) = -6(81)

r(-3) = -486

When x = -2

r(-2) = 6(-2)+12/(-2)^-4

r(-2) = -12+12/(1/16)

r(-2) = -0(16)

r(-2) = 0

When x = -1

r(-1) = 6(-1)+12/(-1)^-4

r(-1) = -6+12/(1)

r(-1) = -6+12

r(-1) = 6

When x = 0

r(0) = 6(0)+12/(0)^-4

r(0) = 0+12/0

r(0) = 12/0

r(0) = infty

When x = 1

r(1) = 6(1)+12/(1)^-4

r(1) = 6+12/1

r(1) = 18(1)

r(1) = 18

When x = 2

r(2) = 6(2)+12/(2)^-4

r(2) = 12+12/1/16

r(2) = 24(16)

r(2) = 384

When x = 3

r(3) = 6(3)+12/(3)^-4

r(3) = 18+12/1/81

r(3) = 30(81)

r(3) = 2430

When x = 4

r(4) = 6(4)+12/(4)^-4

r(4) = 24+12/1/256

r(4) = 36(256)

r(4) = 9216

We want to construct tables of values for the two given functions.

The tables are:

a)

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b)

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

A table will be something like:

[tex]\left[\begin{array}{ccc}x&y\\-4&\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\\4&\end{array}\right][/tex]

Where the values of x go from -4 to 4.

To complete the tables, we just need to evaluate the functions in each one of the x-values at the left, and the outcome will be placed at the right.

a) f(x) = 6/x - 2

Now we just need to evaluate the function in all the given points:

f(-4) = 6/(-4) - 2 =  -3/2 - 4/2 = -7/2

f(-3) = 6/-3 - 2 = -4

f(-2) = 6/-2 - 2 = -5

f(-1) = 6/-1 - 2 = -8

f(0) is undefined, as we can't divide by zero, here we can write NaN (Not a number).

f(1) = 6/1 - 2 = 4

f(2) = 6/2 - 2 = 1

f(3) = 6/3 - 2 = 0

f(4) = 6/4 - 2 = -1/2

Now we put all of these in the correspondent place of the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]

b) We do the same thing, here we have:

r(x) = 6*x + 12/x^-4 = 6*x + 12*x^4

Now we evaluate this in the given values:

r(-4) = 6*(-4) + 12*(-4)^4 = 3,048

r(3) = 6*(-3) + 12*(-3)^4 = 954

r(-2) = 6*(-2) + 12*(-2)^4 = 180

r(-1) = 6*(-1) + 12*(-1)^4 = 6

r(0) = 6*0 + 120^4 = 0

r(1) = 6*1 + 12*1^4 = 18

r(2) = 6*2 + 12*2^4 = 204

r(3) = 6*3 + 12*3^4 = 990

r(4) = 6*4 + 12*4^4 = 3,096

Now we place these values in the correspondent place on the table:

[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]

These are our two tables.

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