If an EMT has 5g of Dextrose and if the volume of the water is 121 mL, what is the concentration of the solution the EMT can make in molarity?

Answers

Answer 1

The concentration of the dextrose solution that the EMT can make is 0.2295 M.

How to calculate the molarity of the solution ?

We need to know the number of moles of dextrose in the solution and the total volume of the solution.

First, we need to convert the mass of dextrose from grams to moles using its molar mass. The molar mass of dextrose (C6H12O6) is 180.16 g/mol. Therefore:

Number of moles of dextrose = 5 g / 180.16 g/mol = 0.02777 mol

Next, we need to calculate the total volume of the solution in liters. We can convert the given volume of 121 mL to liters by dividing by 1000:

Total volume of solution = 121 mL / 1000 = 0.121 L

Finally, we can calculate the molarity of the solution using the formula:

Molarity (M) = moles of solute / liters of solution

Molarity = 0.02777 mol / 0.121 L = 0.2295 M

Therefore, the concentration of the dextrose solution that the EMT can make is 0.2295 M.

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Related Questions

Hello what are the answers to these?

Answers

The kinetic energy is the energy of an object in motion.

What is kinetic energy?

Kinetic energy is a form of energy that an object possesses due to its motion. It is defined as the energy that an object has as a result of its mass and velocity.

We know that;

KE = 1/2mv^2

PE = mgh

1) KE = 0.5 * 2300 * (32)^2

= 1177600 J

2) PE = 31 * 2.2 * 9.8

= 52.6 J

3) PE = mgh

h = PE/mg

h = 65000/525 * 9.8

h = 12.6 m

4) KE = 1/2mv2

m = 2KE/v^2

m = 2 * 370/(6.5)^2

m = 17.5 Kg

5) KE = 0.5 * 75000 * (11500)^2

KE = 4.96 * 10^12 J

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Give the systematic name for each of the following organic molecules and enter it in the space provided. Be sure to include appropriate punctuation.

Answers

A complex molecule known as an organic is composed primarily of carbon atoms joined to other elements and/or other carbon atoms.

What is organic molecules?

Although the distinction between "organic" and "inorganic" is disputed, many authors in the field of chemistry believe that any chemical compound that contains carbon-hydrogen or carbon-carbon bonds is considered to be an organic compound. Methane is an example of an organic compound, but opinions on whether carbon halides without hydrogen (such as carbon tetrachloride,  are organic or inorganic vary from author to author.

Millions of organic substances have been identified as a result of carbon's capacity to catenate (form strands with other carbon atoms).

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is sodium carbonate aqueous

Answers

Answer: Yes

Explanation:

Because Sodium carbonate is a salt of a strong base and weak acid.

how many grams of sodium would you comsume if you ate 85 g or.this fiod

Answers

350 mg of sodium would be ingested if you consumed 85 g of the food. This is less than the 2,300 mg (or one teaspoon of table salt) daily limit that is advised.

What is sodium?

The body needs sodium, a mineral, to maintain the proper balance of body fluids. It is an explosively reactive alkali group metallic element that is soft, light, and silvery-white. It reacts with water. Table salt and a number of processed foods both contain sodium. Table salt is created when sodium and chlorine are combined. Nonetheless, the body can get harmed by excess sodium.

The amount of sodium in various foods, and even within the same food category, varies greatly.

But, you can ascertain the salt content per serving, which is often represented in milligrams, by looking at the nutrition facts label or ingredient list of the meal (mg). So, using a proportion, you can determine how much salt is in 85 g of the food:

(x mg sodium) / (serving size in g) = (sodium per serving in mg) / (85 g)

The amount of sodium in 85 g of the food, expressed in milligrams, can be found by solving for x. You may divide this by 1000 to get grams.

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What does mass measure?
A. The space that a substance takes up.
B. The amount of energy in a substance
C. The phase of matter of a substance
D. The amount of matter (particles) in a substance

Answers

D is the correct answer

BASED ON THE REDOX TITRATION EXPERIMENT, CAN SOMEONE HELP WITH THESE QUESTIONS?

Answers

The pH of the medium used for titration has an impact on the titrant used in redox titration, potassium permanganate (KMnO4). The oxidizing action of KMnO4 is greater in acidic than in basic media.

Why should an acidic medium be used for oxalate and permanganate titration?

Permanganate titrations must be performed in a strong acid solution. Because nitric acid and hydrochloric acid might participate in conflicting oxidation-reduction reactions, lowering the accuracy of the titration, sulfuric acid is typically employed for this purpose.

Why does titration use only KMnO4?

MnO4-4 is a greenish-brown substance that turns deep purple when combined with acid, which alters its color from the acid solution.

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who discovered Einsteinium

Answers

Answer: History. Einsteinium was discovered in the debris of the first thermonuclear explosion which took place on a Pacific atoll, on 1 November 1952. Fall-out material, gathered from a neighboring atoll, was sent to Berkeley, California, for analysis.

; Discovered by, Albert Ghiorso and colleagues; Origin of the name, Einsteinium is named after the renowned physicist Albert Einstein.

Answer:

Albert Ghiorso

Explanation:

Albert Ghiorso discovered Einsteinium in 1952 in the debris of the first thermonuclear explosion.

Steel is made by heating iron ore with carbon. Iron ore is a reddish-brown rock that contains iron oxide. Steel is dark gray in color and is composed mostly of iron with only a small amount of carbon. Steel is stronger than iron and resists rusting unlike iron. Sometimes small amounts of other metals, such as chromium, molybdenum, or nickel, are added to steel, which makes it even harder, stronger, or more rust-resistant than iron.

a. Based on the information provided, explain why steel is considered a synthetic material.

Input Field 1 of 3

Answers

Answer:

Notify me if there is a prob!

Explanation:

You might think of iron as a hard, strong metal tough enough to support bridges and buildings, but that's not pure iron. What we have there is alloys of iron (iron combined with carbon and other elements), which we'll explain in more detail in a moment. Pure iron is a different matter altogether. Consider its physical properties (how it behaves by itself) and its chemical properties (how it combines and reacts with other elements and compounds).

Physical properties

Pure iron is a silvery-white metal that's easy to work and shape and it's just soft enough to cut through (with quite a bit of difficulty) using a knife. You can hammer iron into sheets and draw it into wires. Like most metals, iron conducts electricity and heat very well and it's very easy to magnetize.

Chemical properties

The reason we so rarely see pure iron is that it combines readily with oxygen (from the air). Indeed, iron's major drawback as a construction material is that it reacts with moist air (in a process called corrosion) to form the flaky, reddish-brown oxide we call rust. Iron reacts in lots of other ways too—with elements ranging from carbon, sulfur, and silicon to halogens such as chlorine.

Two elements, and , combine to form two binary compounds. In the first compound, 23.3 g of combines with 3.00 g of . In the second compound, 7.00 g of combines with 4.50 g of . Show that these data are in accord with the law of multiple proportions. If the formula of the second compound is , what is the formula of the first compound?

Compound I:

Answers

Answer:

To show that the data are in accord with the law of multiple proportions, we need to determine the ratios of the masses of to in each compound and see if they are in small whole number ratios.

For the first compound:

Mass of : 23.3 g

Mass of : 3.00 g

Ratio of masses: 23.3 g / 3.00 g = 7.77

For the second compound:

Mass of : 7.00 g

Mass of : 4.50 g

Ratio of masses: 7.00 g / 4.50 g = 1.56

These ratios are not in small whole number ratios, which indicates that the formula for the first compound cannot be determined by simple inspection. However, the fact that the ratios are different is in accord with the law of multiple proportions, which states that when two elements form more than one compound, the masses of one element that combine with a fixed mass of the other element are in small whole number ratios.

Let's assume that the formula for the second compound is . This means that the ratio of to in the compound is 2:1. From the data provided, we know that there are 4.50 g of in the compound, which means there must be twice as much in the compound. Therefore, there are 9.00 g of in the compound.

To determine the formula of the first compound, we can subtract the mass of from the total mass of the compound:

Mass of : 23.3 g

Mass of : 3.00 g

Total mass: 26.3 g

Mass of : 26.3 g - 3.00 g = 23.3 g

So the ratio of to in the first compound is:

Mass of : 23.3 g

Mass of : 3.00 g

Ratio of masses: 23.3 g / 3.00 g = 7.77

We can divide this ratio by the ratio of to in the second compound to get the ratio of the two compounds:

Ratio of first compound: 7.77

Ratio of second compound: 2.00

The ratio of the two compounds is not a small whole number ratio, which suggests that the formula for the first compound is more complex than a simple binary compound. Therefore, we cannot determine the formula of the first compound from the data provided.

Answer:

the formula of the first compound is A2.08B0.78, which we can simplify to A2B.

Explanation:

To determine if these data are in accord with the law of multiple proportions, we need to compare the ratios of the masses of one element to the fixed mass of the other element in each compound:

For the first compound:

mass ratio of A:B = 23.3 g / 3.00 g = 7.77

For the second compound:

mass ratio of A:B = 7.00 g / 4.50 g = 1.56

If the ratios of the masses of one element to the fixed mass of the other element are simple whole number ratios, then the data are in accordance with the law of multiple proportions. We can see that the ratios calculated above are not simple whole numbers, so the law of multiple proportions does not appear to be satisfied.

To determine the formula of the first compound, we can assume that the formula is AxBy, where x and y are the subscripts that we need to determine. We can set up a system of equations based on the mass ratios:

23.3 g of A combines with 3.00 g of B:

(23.3 g A) / (x mol A) = (3.00 g B) / (y mol B)

7.77 mol A / mol B = (23.3 g A) / (3.00 g B)

7.77 (y/x) = 23.3 / 3.00

y/x = 3/7.77

7.77 g of A combines with 1.00 g of B:

(7.77 g A) / (x mol A) = (1.00 g B) / (y mol B)

1.56 mol A / mol B = (7.77 g A) / (1.00 g B)

1.56 (y/x) = 7.77 / 1.00

y/x = 5/2

Now we have two equations for y/x that we can solve simultaneously:

y/x = 3/7.77

y/x = 5/2

Setting these two expressions equal to each other, we get:

3/7.77 = 5/2x

x = 2.08

Now that we know x, we can use one of the equations for y/x to solve for y:

y/x = 3/7.77

y/2.08 = 3/7.77

y = 0.78

Therefore, the formula of the first compound is A2.08B0.78, which we can simplify to A2B.

Conclusions
5. Based on your trials, did you find that condensation took more or less time to form in a warmer temperature?

6. A cold front is the zone where a cold air mass is replacing a warmer air mass. What do you predict will
happen to the weather at a cold front? Make sure to explain why you think that!
Type your answer here:

Answers

Condensation happens more quickly when water vapour is made colder. The rate of condensation increases as the amount of water vapour in the air increases.

Is condensation causing an increase or decrease in temperature?

When condensation takes place, the latent heat of condensation that is provided to the air is released by the water vapour that is already there. The temperature of the air rises as a result of the heat being absorbed.

Does a warmer environment result in greater condensation?

Condensation happens at higher temperatures in humid environments. Despite relatively low humidity, condensation happens when it's cold outside. Condensation forms on windows and doors due to the temperature differential between the environment, whether interior or exterior, and the glass.

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You have atoms of two elements: lithium (Li) and fluorine (F).

Which of the two atoms would you expect to have a greater mass? Why?
Which atom would you expect to have a larger atomic radius? Why?

Answers

"Fluorine (F) would have a greater mass than lithium (Li) because it has more protons, neutrons, and electrons than lithium. Specifically, the atomic mass of fluorine is approximately 19 atomic mass units (amu), while the atomic mass of lithium is approximately 7 amu.

On the other hand, lithium would have a larger atomic radius than fluorine. This is because atomic radius tends to increase down a group (column) of the periodic table and decrease across a period (row). Lithium is located in Group 1 (the alkali metals) of the periodic table, while fluorine is located in Group 17 (the halogens). Elements in Group 1 have relatively large atomic radii due to their low effective nuclear charges and the shielding effect of their inner electrons.

In contrast, elements in Group 17 have relatively small atomic radii due to their high effective nuclear charges and the lack of shielding from their inner electrons. Therefore, since lithium is located in a group that has larger atomic radii, it would have a larger atomic radius than fluorine, which is located in a group with smaller atomic radii." (ChatGPT, 2023)

5.0 Mol Al reacts with 6.0 mol O2 to form Al2O3.
How many moles of Al2O3 form when 6.0 mol O2 are used up?

Answers

Answer: The answer is 4

Explanation:

How many moles of copper 2 sulphate are present in the 100cm3 solution

Answers

We have 0.34 L of the remedy. A type of concentration known as % mass/volume shows how much solute is present in 100 mL of solution.

What is an example of mass to volume?

Volume is the amount of space a thing occupies, whereas mass is the amount of stuff it contains. Example: Basketball and bowling balls have roughly the same volume, but the bowling ball has a lot more mass. Make sure you understand the distinction between mass and weight before utilising measurement words.

In this instance, there are 100 mL of solution and 25 g of CuSO4.

We can use the rule of three to determine the solution:

100 mL of solution holds 25 g of solute.

Our 85 g may fit in (85.100) /25, or 340 mL.

Volume is converted from mL to L.

1L / 1000mL = 0.34 L 340ml

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air is a mixture and its composition keeps on changing from one place to another . justify your answer with the help of any two examples

Answers

Air is a mixture of gases, primarily nitrogen (78%) and oxygen (21%), with small amounts of other gases such as argon, carbon dioxide, neon, helium, and methane, as well as water vapor and various pollutants.

The composition of air can vary from one place to another based on a variety of factors, including altitude, temperature, humidity, and sources of pollution. Here are two examples of how the composition of air can change:

Altitude: The higher you go in the atmosphere, the less dense the air becomes. As a result, the percentage of oxygen and other gases in the air decreases. At the top of Mount Everest, for example, the air is only about one-third as dense as it is at sea level, and contains less oxygen and more nitrogen.
Pollution: The air in urban areas can contain higher levels of pollutants such as carbon monoxide, nitrogen oxides, and particulate matter due to human activities like transportation, industry, and agriculture. This can have negative impacts on human health and the environment. In contrast, the air in rural areas may have lower levels of pollutants but higher levels of natural allergens like pollen and mold spores.
Therefore, it is clear that the composition of air varies from one place to another and can be affected by a variety of factors, resulting in different mixtures of gases and pollutants.

Air is a mixture of various gases, including nitrogen, oxygen, carbon dioxide, and water vapor, among others. The composition of air varies depending on the location and the time of the day, making it a heterogeneous mixture.


For instance, the air composition in urban areas may be different from that in rural areas due to the presence of pollutants.

Another example of the changing composition of air is the difference in air pressure and temperature between the earth's surface and the upper atmosphere. As altitude increases, air pressure decreases, and the concentration of gases such as oxygen and carbon dioxide decreases. Therefore, the composition of air changes with altitude.


In conclusion, air is a mixture, and its composition changes from one place to another and with altitude. Understanding the variations in air composition is essential for the management of air quality and environmental protection.


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Find the volume of 1.50 mol of an ideal gas at 26.0°C and a pressure of 419 kPa. Use the ideal gas law and
R=0.0821 atm x L/mol x K.

Answers

The volume of a 1.50 moles of an ideal gas at 26.0°C and a pressure of 419 kPa is 8.91L.

How to calculate volume?

The volume of an ideal gas can be calculated using the following ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)v = volume (L)n = no of molesT = temperature (K)R = gas law constant

According to this question, 1.50 moles of an ideal gas at 26.0°C and a pressure of 419 kPa. The volume can be calculated as follows:

4.135 × V = 1.5 × 0.0821 × 299

4.135V = 36.82185

V = 8.91L

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How many atoms of oxygen are in 30.5 grams of Fe2O3​?

Answers

Answer: Atoms of oxygen in 30.5 grams of Fe2O3 = 7.65 x 10^22 atoms

Explanation: To determine the number of atoms of oxygen in 30.5 grams of Fe2O3, we first need to calculate the number of moles of Fe2O3, and then use the mole ratio between Fe2O3 and O atoms to calculate the number of O atoms.

The molecular weight of Fe2O3 can be calculated by adding the atomic weights of two Fe atoms and three O atoms:

Molecular weight of Fe2O3 = (2 x atomic weight of Fe) + (3 x atomic weight of O)

= (2 x 55.85 g/mol) + (3 x 16.00 g/mol)

= 159.69 g/mol

So, 30.5 g of Fe2O3 is equal to:

Number of moles = Mass / Molecular weight

= 30.5 g / 159.69 g/mol

= 0.191 moles

The mole ratio between Fe2O3 and O atoms is 3:2. This means that for every 3 moles of Fe2O3, there are 2 moles of O atoms. Therefore, the number of moles of O atoms in 0.191 moles of Fe2O3 is:

Number of moles of O atoms = 2/3 x 0.191 moles

= 0.127 moles

Finally, we can use Avogadro's number to convert the number of moles of O atoms into the actual number of O atoms:

Number of O atoms = Number of moles x Avogadro's number

= 0.127 moles x 6.022 x 10^23 atoms/mol

= 7.65 x 10^22 atoms

Therefore, there are 7.65 x 10^22 atoms of oxygen in 30.5 grams of Fe2O3.

Which of the following is NOT a way that natural resources are obtained?

Multiple choice question.
cross out

A)
extracted from Earth

cross out

B)
farmed from the land

cross out

C)
sourced from the ocean

cross out

D)
made in a factory

Answers

Answer:

d . made in a factory

Explanation:

Sulfur dioxide (SO2) is an unwelcome result
of burning soft coal in power plants. Some
of the SO2 ends up as sulfuric acid in acid
precipitation. The net reaction is
2 SO2(g) + O2(g) + 2 H2O(ℓ) −→ 2 H2SO4(ℓ)
What mass in grams of SO2 is needed to
react with 1804 g of O2?
Answer in units of g.

Answers

A portion of the SO2 undergoes acid precipitation and becomes sulfuric acid. In this instance, 903.34 grams of SO2 and 1804 grams of O2 must react.

How can you figure out how much SO2 you need in grams of mass?

O2's molecular mass is equal to twice its atomic weight in grams per mole, or 32 g/mol.

O2 mass divided by its molecular mass yields the number of moles of oxygen: 1804 g divided by 32 g/mol, or 56.375 mol.

Amount of SO2 molecules equals 1/2 x Number of O2 molecules, or 28.1875 mol

Amount of moles of SO2 x their molecular mass equals 28.1875 mol x 32.06 g/mol, or 903.34 g, for the mass of SO2.

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Acid precipitation transforms some of the SO₂ into sulfuric acid. 903.34 grams of SO₂ and 1804 grams of O₂ must react in this case.

How can you figure out how much SO₂ you need in grams of mass?

O₂'s molecular mass is equal to twice its atomic weight in grams per mole, or 32 g/mol.

O₂ mass divided by its molecular mass yields the number of moles of oxygen: 1804 g divided by 32 g/mol, or 56.375 mol.

Amount of SO₂ molecules equals 1/2 x Number of O₂ molecules, or 28.1875 mol

Amount of moles of SO₂ x their molecular mass equals 28.1875 mol x 32.06 g/mol, or 903.34 g, for the mass of SO₂.

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What is the process of making an object by adding new layers onto one another?

Answers

In chemical, deposition is the process of building an object by putting fresh layers on top of one another.

What is deposition?

Deposition includes the direct transformation of a vapor into a solid without first going through the liquid phase. A layer of substance is added to the surface of a substrate during deposition; the substrate might be solid or liquid.

This method is employed in many different contexts, including the creation of protective coatings, optical coatings, and thin films for electrical devices. A number of methods, such as atomic layer deposition, physical vapor deposition, and chemical vapor deposition (CVD), can be used to deposit material (ALD).

What is Vaporizing?

A phase change from the liquid phase to the vapor phase is called vaporization (or vaporization) of an element or molecule. Both evaporation and boiling result in sublimation. Boiling is a bulk phenomenon, whereas evaporation is a surface phenomenon.

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A 3.1-mol sample of KCIO3 was decomposed according to the equation
2KCIO3(s)→ 2KC1(s) + 302(g)
How many moles of O₂ are formed assuming 100% yield?
a) 2.1 mol
b) 3.1 mol
c) 2.6 mol
Od) 4.7 mol
e) 1.6 mol

Answers

Answer:

It's (d) 4.65 ≃ 4.7

Explanation:

By understanding that a mole  is the unit of amount of substance that equals Avogadro's number ([tex]N_a[/tex] = 6.022*10^23)

we make a ratio of moles as below:

2KClO3 --> 2KCl + 3O2
2        :        2     :    3
3.1      :        ?      :    ?

part value = 3.1 / 2 = 1.55

number of moles of O2 yielded from this reaction = 1.55 * 3 = 4.65 moles


Enter your answer in the provided box.
Using the balanced equation for fermentation answer the following questions.
C6H12O6(aq)-> 2 C2H6O(aq) + 2 CO2(g)

How many grams of glucose are needed to form 2.0 mol of ethanol?

Answers

Answer:

Looking at the balanced equation for fermentation:

C6H12O6(aq) -> 2 C2H6O(aq) + 2 CO2(g)

We can see that 1 mol of glucose (C6H12O6) produces 2 mol of ethanol (C2H6O).

So, to form 2.0 mol of ethanol, we would need:

2.0 mol ethanol x (1 mol glucose / 2 mol ethanol) = 1.0 mol glucose

Therefore, we would need 1.0 mol of glucose to form 2.0 mol of ethanol.

To convert from moles of glucose to grams, we can use the molar mass of glucose, which is approximately 180.16 g/mol.

Mass of glucose needed = 1.0 mol x 180.16 g/mol = 180.16 g

Therefore, we would need 180.16 grams of glucose to form 2.0 mol of ethanol.

Which is one use for infrared waves?

A)To provide heat for pets or livestock
B)To power nuclear weapons
C)To operate a machine that cooks food quickly
D)To light desk lamps

Answers

A contraption that swiftly prepares food is run by infrared rays. Microwaves employ infrared rays to heat meals by warming any water that may be present.

What are some uses for infrared and microwave technology?

Numerous food production processes, including drying, boiling, heating, peeling, polyphenol recovery, freeze-drying, antioxidant recovery, microbiological inhibition, sterilizing grains, baking bread, roasting food, making juices, and cooking food, all use infrared technology.

What are some uses and applications for infrared waves?

Infrared radiation has the ability to ease or release muscle tension and encourage local blood circulation in the body. Infrared radiation has been used in conventional and modern medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.

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What does the name or formula of a compound tell us about its structure and properties

Answers

Answer:

The name or formula of a compound provides important information about its structure and properties.

The name of a compound often reflects the type of elements it contains and how they are bonded together. For example, a compound containing only two elements may have a name that ends in "-ide", while a compound containing a metal and a non-metal may have a name that indicates the oxidation state of the metal. The formula of a compound also gives us information about the relative number of atoms of each element present in the compound.

The structure of a compound can be deduced from its formula, and can provide insight into its properties. For example, the shape of a molecule can influence its polarity, boiling point, and reactivity. The presence of certain functional groups in an organic compound can give it specific chemical properties and reactivity.

Overall, the name and formula of a compound provide important clues about its properties and behavior, and are an essential part of understanding and working with chemical compounds.

Explanation:

reduction of: 3-methylpentan-2-one

Spell out the full name of the compound.

Answers

The full name of the compound after reduction of 3-methylpentan-2-one would be 3-methylpentan-2-ol.

Use the following equation to answer the next question
P₂O5 + 3 H₂O → 2H3PO4
8. If you started the reaction with 55 g.of P₂O5 and 16 g. of H₂O, the H₂Qwould be your
limiting reactant.
How many grams of excess reactant would you have? *The molar mass of P₂O5 is 141.88
g/mol.

Answers

The limiting reactant would be  H₂O.

The mass of the excess reactant would be 13.05 grams

Stoichiometric problem

Number of moles of P₂O5 = mass / molar mass

Number of moles of P₂O5 = 55 g / 141.88 g/mol

Number of moles of P₂O5 = 0.388 moles

Number of moles of H₂O = mass / molar mass

Number of moles of H₂O = 16 g / 18.02 g/mol

Number of moles of H₂O = 0.888 moles

Using the balanced chemical equation, we see that 1 mole of P₂O5 reacts with 3 moles of H₂O to produce 2 moles of H3PO4. Therefore, to react with all the P₂O5, we would need:

0.388 moles of P₂O5 × (3 moles of H₂O / 1 mole of P₂O5) = 1.164 moles of H₂O

Since we only have 0.888 moles of H₂O, it is the limiting reactant.

To determine the amount of excess P₂O5, we need to find how many moles of H₂O would be needed to react with all the P₂O5:

0.888 moles of H₂O × (1 mole of P₂O5 / 3 moles of H₂O) = 0.296 moles of P₂O5

The amount of excess P₂O5 is the initial moles of P₂O5 minus the moles of P₂O5 required to react with all the H₂O:

0.388 moles of P₂O5 - 0.296 moles of P₂O5 = 0.092 moles of excess P₂O5

Mass = 0.092 x 141.88 = 13.05 grams

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100.0 g of sample A has 77.6 g Xe
and 22.4 g F.
What is the percent by mass of Xe
in sample A?

Answers

The percent by mass of Xe in sample A is calculated as 77.6%.

What is the percent by mass?

To calculate the mass percent of an element in compound, we divide the mass of element in 1 mole of compound by the molar mass of compound and multiply the result by 100.

The percent by mass of Xe in sample A can be calculated using the following formula:

percent by mass of Xe = (mass of Xe / total mass of sample) x 100%

Given mass of Xe is 77.6 g and total mass of sample is 100.0 g.

Putting these values into the formula, we get:

percent by mass of Xe = (77.6 g / 100.0 g) x 100% = 77.6%

Hence, the percent by mass of Xe in sample A is 77.6%.

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Determine the mass of an 80 N dog.

Answers

Answer:

Answer. Mass of object is 8.16 kg (or 8 kg if g = 10 m/s²)

Explanation:

One way to calculate mass: Mass = volume × density. Weight is the measure of the gravitational force acting on a mass. The SI unit of mass is "kilogram". The SI unit of weight is Newton (N).

In a laboratory experiment you dissolved 1.02 g of an unknown, nonvolatile substance in a 25 mL of distilled water. Vapor pressure if purr water is 23.7 torr, and you measure the vapor pressure of the solution to be 22 torr. What is the molar mass of the solute?

Answers

Answer: We can use Raoult's Law to solve for the molar mass of the solute:

ΔP = P°_solvent x mole fraction of solute x vapor pressure of solute

Since the solute is nonvolatile, its vapor pressure is negligible and we can assume that it is equal to zero. Thus, we can simplify the equation to:

ΔP = P°_solvent x mole fraction of solute

Solving for the mole fraction of solute:

ΔP / P°_solvent = mole fraction of solute

Plugging in the values:

(23.7 torr - 22 torr) / 23.7 torr = mole fraction of solute

mole fraction of solute = 0.072

Now we can use the mole fraction of solute to calculate the moles of solute dissolved in the solution:

moles of solute = mole fraction of solute x moles of solvent

moles of solvent = (25 mL / 1000 mL) x (1 g/mL) / (18.015 g/mol) = 0.001385 mol

moles of solute = 0.072 x 0.001385 mol = 0.0001 mol

Finally, we can calculate the molar mass of the solute:

molar mass of solute = mass of solute / moles of solute

mass of solute = 1.02 g

molar mass of solute = 1.02 g / 0.0001 mol = 102 g/mol

Therefore, the molar mass of the solute is 102 g/mol.

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A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: 3+ 2 Cr³+ (aq) + 3Ca (s) → 2Cr (s) + 3 Ca²+ (aq) 3+ Suppose the cell is prepared with 4.01 M Cr³+ in one half-cell and 1.96 M Ca 2+ Calculate the cell voltage under these conditions. Round your answer to 3 significant digits. in the other.​

Answers

The cell voltage can be calculated using the Nernst equation:

Ecell = E°cell - (RT/nF)ln(Q)

where:
- E°cell is the standard cell potential
- R is the gas constant (8.314 J/K·mol)
- T is the temperature in Kelvin (25.0°C = 298.15 K)
- n is the number of electrons transferred in the balanced redox reaction (in this case, n = 6)
- F is the Faraday constant (96,485 C/mol)
- Q is the reaction quotient, which can be calculated as [Cr²⁺]^2[Ca²⁺]^3/[Cr³⁺]^2

First, let's calculate the standard cell potential, E°cell. We can do this using the standard reduction potentials for the half-reactions involved:

Cr³⁺(aq) + e⁻ → Cr²⁺(aq) E°red = -0.407 V
Ca²⁺(aq) + 2e⁻ → Ca(s) E°red = -2.870 V

The overall reaction is the sum of the two half-reactions, so we can add their standard reduction potentials to get the standard cell potential:

E°cell = E°red,cathode - E°red,anode
E°cell = 0.407 - (-2.870) = 3.277 V

Now we can plug in the values into the Nernst equation and solve for Ecell:

Ecell = 3.277 V - (8.314 J/K·mol)(298.15 K)/(6 mol)(96,485 C/mol)ln((1.96 M)^3/(4.01 M)^2)
Ecell = 3.277 V - 0.059 V
Ecell = 3.218 V

Therefore, the cell voltage under these conditions is 3.218 V (rounded to 3 significant digits).

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Calculate the number of grams of sulfur in 1.22 mol of sulfur.
Express your answer in grams to three significant figures.

Answers

Answer:

39.119 g

Explanation:

1 mole of S has 32.065 g

=> 1.22 x 32.065 = 39.1193 or 39.119 g

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