Help please I've been stuck on this for so long.​

q₃ is approximately -7.58 nC. The direction of the net force on 'q₃' is the negative '-' direction. For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

q₃ is approximately -7.58 nC

The direction of the net force on 'q₃' is the negative '-' direction

For the net force on 'q₃' to be zero, 'q₃' can be placed at x = -0.079 m or x = -1.881 m

1) The force, 'F', between two charged spheres is given as follows;

F = K*q1*q2/r2

By substituting the given values, we have;

F NET = 14117n C *K /320

K = 9 × 10⁹ N·m²·C⁻²

q₃ ≈ -7.58 nC

= -7.58 nC

2) Given that the negative charge, 'q₁' (-4.10 nC), is located at x = 0.250 m, which is on the positive, '+' side of the origin, it will repel the negatively charged 'q₃', to the '-' direction. q₃ will also be attracted to the '-' direction by the positively charged 'q₂' which is at -0.320 m on the negative side of the origin

The net force's direction on q₃ will be in the '-' direction

3) For zero net force, we have;

= K* 2.20 n C /R 1 (2)

The distance between the given point charges, r = 0.250 - (-0.320)) = 0.57 m

Let 'r1' represent the distance between 'q1' and 'q3', therefore, the distance between 'q2' and 'q3' is 0.57 - r1

From which we have;

(r₁)²×4.10 = 2.20 × (0.57 - r₁)²

From the above equation, we have;

95,000·r₁²+ 125,400·r₁-35739 = 0

Solving, using a graphing calculator we get;

r₁ ≈ 0.241 or r₁ ≈ -1.561

Where, 'r₁', is measured from 'q₂', therefore, we have;

r₁ = 0.241 + (-0.320) ≈ -0.079 or r₁ = -1.561 + (-0.320) ≈ -1.881

Therefore, the charge 'q₃' can be placed at x = -0.079 or x = -1.881 for the ne force on it to be zero

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You are given a set of black coordinate axes  with '(velocity) v (m/s)' on the vertical axis  and 't (s)' on the horizontal axis.

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You will get a set of black coordinate axes with "(velocity) v (m/s)" on the vertical axis and "t (s)" on the horizontal axis.

What is speed?

Speed ​​is the direction in which a body or object is moving. Speed ​​is primarily a scalar quantity. Speed is essentially a vector quantity. The rate of change of distance and the rate of change of displacement are called velocity. Speed corresponds to the specification of speed and direction of movement (e.g. 60 km/h to the north). Velocity is commonly defined as a vector value of velocity and direction of motion. Simply put, speed is how fast something is moving in one direction.

The speed of a car driving north on a freeway and the speed of a rocket launched into space can be measured by velocity.

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The magnitude of the force F on the 1.0 nC charge in the figure is the positive charge and force F is 8 x 10^9 N (8 Giga Newtons).

The force F on the 1.0 nC charge in the figure can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the inversely proportional to the square of the distance between the charges and a product of the charges. The magnitude of the force can be calculated using the following formula:

|F| = k x |q1| x |q2| / r^2

where k is the Coulomb constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges (in Coulombs), and r is the distance between the charges (in meters).

In this case, q1 = 1.0 nC = 1.0 x 10^-9 C and q2 = -1.0 nC = -1.0 x 10^-9 C (since the charges are opposite and the force is attractive) and r = 0.1 m.

So, the magnitude of the force F can be calculated as:

|F| = k x |q1| x |q2| / r^2 = (9 x 10^9 Nm^2/C^2) x (1.0 x 10^-9 C) x (-1.0 x 10^-9 C) / (0.1 m)^2 = 8 x 10^9 N

The magnitude of the force F is 8 x 10^9 N (8 Giga Newtons)

It's important to note that the direction of the force is from the positive charge.

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The conservation of charge states that charge cannot be created or destroyed, but can be transferred between objects.

How does the conservation of charge affect the behavior of electric circuits?

The conservation of charge states that charge cannot be created or destroyed, it can only be transferred from one object to another. This principle affects the behavior of electric circuits by ensuring that the total charge in a closed circuit remains constant. This means that the charge flowing into a circuit must equal the charge flowing out of the circuit. If there is an imbalance, the circuit will not function properly.

The conservation of charge also helps to explain the behavior of electric charges in different types of circuits, such as series and parallel circuits.

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The magnitude of the average northward velocity is 27 m/s, while the magnitude of the average southbound velocity is 17 m/s. The total journey average speed is 20.25 m/s to the north.

We must determine the weighted average of the northward and southern velocities in order to get the average speed for the whole journey. We may apply the following formula since the automobile drives north for 3/4 of the time and south for 1/4 of the time:

average speed is (3/4) * (27 m/s) + (1/4) * (-17 m/s)

Since the southbound velocity is moving in the opposite direction of the northward velocity, it is given a negative sign.

Calculating the average velocity results in:

Average speed is equal to (3/4) times 27 m/s plus (1/4) times -17 m/s, or 20.25 m/s.

The total journey average speed is 20.25 m/s to the north.

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Energy must be taken in as heat from the high-temperature reservoir is 1200 J.

The science of thermodynamics examines how heat, work, temperature, and energy are related. The flow of energy from one location to another and from one form to another is broadly what thermodynamics is concerned with.

The efficiency of a heat engine is the ratio of the useful work done by the engine to the total heat energy taken in from the hot reservoir. In this case, the efficiency is 35%. Therefore, the useful work done by the engine is 35% of the total heat energy taken in from the hot reservoir.

If the heat engine does 420 J of useful work, we can use the efficiency formula to find the total heat energy taken in from the hot reservoir:

Total heat energy = (Useful work) / (Efficiency) = 420 J / 0.35 = 1200 J

So, in order for this heat engine to do 420 J of useful work, it must take in 1200 J of energy as heat from the high-temperature reservoir.

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Radiant energy is also called responses thermal energy (b)  light energy is correct option.

Radiant energy in physics refers to the energy of electromagnetic and gravitational radiation. Radiant energy is particularly studied via radiometry. Its SI unit for energy is the joule (J). Other than radiometry, electromagnetic energy is denoted by the letters E or W. The phrase is specifically used when electromagnetic radiation is released into the environment by a source. For the human eye, this radiation might be visible or invisible.

Energy included in electromagnetic waves is known as radiant energy. These consist of microwaves, infrared, radio waves, ultraviolet light, and visible light. The random molecular movements of substances store thermal energy, often known as heat energy.

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Because potential energy increases with separation distance, Jamal should move the toy car with the greatest separation distance.

The term potential energy is defined as stored energy that depends upon the relative position of various parts of a system. Potential energy is energy that cannot be transfer to kinetic energy. It has the capacity to do work but is not presently doing so.

Because magnetic force is inversely proportional to the separating distance between the cars, the magnetic force acting on the vehicles will decrease as he moves the cars away from each other.

Thus, potential energy increases with separation distance, Jamal should move the toy car with the greatest separation distance.

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Answer: Therefore, the rock that has a mass of 10 kg and a gravitational energy of 2400 J must be at a height of 24 meters.

Explanation:

How high above the ground is a 10 kg boulder that has 2400 J of gravitational potential energy?

Data:

m = 10 kg

Epg = 1200 J

h = ?

g = 10 m/s²

The formula for gravitational potential energy is:

Where

We must calculate the height, for which we clear the formula, then

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{Ep_g}{m*g} } \end{gathered}$}}[/tex]

We substitute data in the formula and solve:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ J}{10 \ kg*10\frac{m}{s^2} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ J}{100 \ kg*\frac{m}{s^2} } } \end{gathered}$}}[/tex]

Before continuing to answer, we must work with the units of Joules, so

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ N*m}{100 \ kg*\frac{m}{s^2} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \not{kg}*\not{\frac{m}{s^2}} *m}{100 \not{kg}*\not{\frac{m}{s^2}} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ m}{100} } \end{gathered}$}}[/tex]

[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h\cong24 \ m } \end{gathered}$}}}[/tex]

Therefore, the rock that has a mass of 10 kg and a gravitational energy of 2400 J must be at a height of 24 meters.

The Law of Conservation of Energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.

As the object falls to the ground, its potential energy is converted into kinetic energy. The potential energy is determined by the object's mass and its height above the ground. As the object falls, its height decreases and its potential energy decreases, but this decrease in potential energy is compensated by an increase in kinetic energy. The kinetic energy is determined by the object's mass and its velocity. As the object's height decreases and its velocity increases, its kinetic energy increases.

As the object falls, the total amount of energy remains constant. The initial potential energy of 10 J is equal to the final kinetic energy of the object. This is an example of the Law of Conservation of Energy in action. The object's potential energy is transformed into kinetic energy, but the total amount of energy remains the same.

Fetch: A region of an ocean or lake's surface where wind blows in a direction that is basically continuous, producing waves.

An energetic disturbance called a wave moves from one place to another. The only thing that changes when a wave moves is energy, not matter. The substance in which a wave passes is known as the medium. Until it lands in the same place, that medium frequently swings back and forth.

But amplitude, wavelength, energy, and speed are characteristics that all waves share. How much a wave's medium moves is described by its amplitude. Wavelength and frequency both refer to the size and frequency of waves. A wave's speed is its rate of movement.

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Answer:

The rotation of the earth on its tilted axis is the reason behind the difference in the length of the day and night time in different parts of the earth throughout the year. The annual motion of the Earth is called revolution. Since the path of the Earth is elliptical, the interval between the Earth and the Sun keeps shifting.

Explanation:

The distance traveled by object is 120 m in given time 10 seconds.

If other information is known, a set of four equations called the kinematic equations can be used to predict unknown information about an object's motion.

The equations can be applied to any motion that can be classified as either a constant velocity motion (with an acceleration of 0 m/s/s) or a constant acceleration motion. They are never permitted to be used over any time frame in which the acceleration is changing.

Four variables are present in each of the kinematic equations. The fquations offer a useful method of predicting details about an object's motion.

The kinematic equation for distance is,

[tex]\boxed{\mathrm{ d = (v +v_0) \dfrac{t}{2} }}[/tex]

Where,

[tex]\mathrm{V_0}[/tex] - initial speed = 8 m/s

V - final speed = 16 m/s

t - time = 10 s

Put the values in formula,

[tex]{\mathbf{ {d = (16+9) \dfrac{10}{2} }}[/tex]

[tex]\mathbf{d=120m}[/tex]

Thus, The distance traveled by object is 120 m in given time 10 seconds.

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The 1.55 g particle must have a positive charge that is equivalent to 635 N/C times (1.55 g / 9.8 m/s2) = 11.9 C. To maintain equilibrium against gravity.

for a)

a particle's charge must be opposite in sign and magnitude to the electric force acting on it.

mg = qe

1.55 X 10 ⁻³ X 9.81 = q X 635

q = - 0.023 X 10⁻³ C

it willl be negative

We get at q = F / E = 15.09 N / 635 N/C = 0.0237 C after solving for the charge.

This indicates that the particle's charge must be positive and equal to 0.0237 Coulombs in order for it to balance against gravity in the 635 N/C-magnitude downward electric field.

qe = mg

1.6 X 10 ⁻¹⁹ E = 1.67 X 10 ⁻²⁷ X 9.81

E = 1.02 X 10⁻⁷N/C

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The height of the apartment is 127.5 m.

The height of the apartment is calculated by applying the following equation.

first equation for your throw; h = ¹/₂g(t +3.4)²

second equation for your friend's throw; h = vt  +  ¹/₂gt²

h = vt  +  ¹/₂gt²

h = 66.64t  +  ¹/₂gt²

now equate the two equations;

¹/₂g(t+3.4)² = 66.64t  +  ¹/₂gt²

¹/₂(9.8)(t² + 6.8t + 11.56) = 66.64t  +  ¹/₂(9.8)t²

4.9(t² + 6.8t + 11.56) = 66.64t  +  4.9t²

4.9t² + 33.32t + 56.64 = 66.64t  +  4.9t²

33.32t = 56.64

t = 1.7 seconds

The height of the apartment is calculated as;

h = ¹/₂g(t +3.4)²

h = ¹/₂(9.8)(1.7 +3.4)²

h = 127.5 m

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With the help of slip rings, an AC generator connects the rotating armature to its external circuit.

A slip ring is an electronic device that permits the transfer of electrical currents and energy from a still structure to a spinning one. Any electrical device that needs to rotate while sending energy or currents can employ a slip ring.

A device that generates electrical energy from mechanical energy is an AC generator. Mechanical energy is provided by steam turbines, gas turbines, and combustion engines as the AC generator's input source. Alternating electrical power in the form of current and voltage is the output.

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(1) The force exerted by the hammer claws on the nail is 67.54 N.

(2) The the force exerted by the surface on the point of contact with the hammer head is 124 N.

The force exerted by the hammer claws on the nail is calculated by applying the following formula.

Fy = W sinθ

where;

Fy = 124 N x  sin ( 33 )

Fy = 67.54 N

The the force exerted by the surface on the point of contact with the hammer head is calculated as follows;

Fn = W sin (90)

Fn = 124 N

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Explanation:

ρ = 997kg/m³

v = 375m³

ρ = m/v

m = ρv

m = 997×375

m = 373,875kg

The equation for the system's gravitational potential energy is U = − G * (m2 / R). and G * (m2 / R) is the amount of effort the gravitational force must do to move the particle from the sphere's surface to its centre.

(a) The formula U = - G * (Mm / r), where G is the gravitational constant, M is the mass of the sphere, and m is the mass of the particle, may be used to compute the gravitational potential energy of the system. Here, M = m U = - G * (m2 / R)

(b) The particle's initial potential energy when it is on the sphere's surface is Ui = - G * (m2 / R), and its final potential energy when it is in the sphere's centre is Uf = 0. Work completed equals Uf - Ui work completed equals 0 - (- G * (m2 / R)) work completed equals G * (m2 / R).

G * (m2 / R) represents the amount of effort the gravitational force must do to move a particle from the sphere's surface to its centre.

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Explanation:

"Outlier" data can shift a Normal Bell Curve ____.

A. to get a large peak

B. to flatten out

C. to the left or right

D. up at both ends

The velocity of an object can be calculated using the equation:

velocity = momentum / mass

Given the mass of the object is 3 kg and the forward momentum is 1050 kg-m/sec, we can substitute these values into the equation:

velocity = 1050 kg-m/sec / 3 kg

velocity = 350 m/sec

Therefore, the velocity of the object is 350 m/sec.

The velocity of an object is directly proportional to its momentum. As the velocity of an object increases, so does its momentum. This relationship is described by the equation p = m * v, where p is the momentum, m is the mass of the object and v is its velocity. This equation shows that the momentum of an object is directly proportional to the velocity of the object. This means that if the velocity of an object is doubled, its momentum will also double. Conversely, if the velocity of an object is halved, its momentum will also be halved. Also, If the direction of motion of an object changes it also changes the direction of momentum but the magnitude of momentum will remain the same.

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An object whose mass is 3 kg is fired from a cannon, giving it a forward momentum has a velocity of  350 m/sec.

The velocity of an object can be calculated using the equation:

                          velocity = momentum / mass

Given the mass of the object is 3 kg and the forward momentum is 1050 kg-m/sec, we can substitute these values into the equation:

                      velocity = 1050 kg-m/sec / 3 kg

                       velocity = 350 m/sec

Therefore, the velocity of the object is 350 m/sec.

The velocity of an object is directly proportional to its momentum. As the velocity of an object increases, so does its momentum. This relationship is described by the equation p = m * v, where p is the momentum, m is the mass of the object and v is its velocity. This equation shows that the momentum of an object is directly proportional to the velocity of the object. This means that if the velocity of an object is doubled, its momentum will also double.

Conversely, if the velocity of an object is halved, its momentum will also be halved. Also, If the direction of motion of an object changes it also changes the direction of momentum but the magnitude of momentum will remain the same.

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Answer:

870 m

Explanation:

d = Vit + 1/2at²

a = ΔV/Δt = (85 m/s - 60 m/s) / (12 s) = (25 m/s) / 12 s = 2.08 m/s²

d = (60 m/s)(12 s) + 1/2 (2.08 m/s²)(12 s)² = 870 m

Answer:

The automobile traveled 870 meters during the 12 second interval.

Explanation:

We can use this kinematics equation to evaluate how far the automobile traveled.

[tex]\overline v=\frac{\Delta x}{\Delta t}[/tex]

Note

[tex]\overline v[/tex] is the average velocity

[tex]\Delta x[/tex] is the change in position (displacement)

[tex]\Delta t[/tex] is the change in time (time interval)

The formula for average velocity is

[tex]\overline v=\frac{V_f-V_o}{2}[/tex]

We are given

[tex]V_f=85\\V_o=60\\\Delta t=12[/tex]

First lets evaluate the average velocity.

[tex]\overline v=\frac{85-60}{2}[/tex]

[tex]\overline v=72.5[/tex]

Rearranging our kinematics equation to isolate [tex]\Delta x[/tex] we get

[tex]\Delta x=\overline v \Delta t[/tex]

Now lets evaluate [tex]\Delta x[/tex].

[tex]\Delta x=72.5*12\\\Delta x=870[/tex]

There are many different ways you can solve this; I could have used a different equation.

The water released from the reservoir and passes through turbines to produce electricity.

At the plant level, water flows through a pip also known as a penstock, and then spins the blades in a turbine, which, in turn, spins a generator that ultimately produces electricity.

Hydro turbines, it transform moving water's kinetic energy into mechanical energy, and this mechanical energy is converted into electricity using a hydropower generator. Hydropower turbines contain blades, which spin to produce electricity. Hydro turbines work on Faraday's principles.

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When a turbine's blades are turned by water, electricity is produced and sent to the power plant's users.

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The upward throw of a ball. The gravity acceleration is 9.8 m/s2, and its combination 1 speed is 10.8 m/s. So, 1.10 seconds pass between the ball's release and the moment it reaches its highest point.

Gravity's acceleration is constantly downward and constant, however the speed and direction of the acceleration vary. The speed of the ball is zero at its top portion in its trajectory, then it picks up speed again as it descends toward.

Because the acceleration caused by the gravitational force is operating constantly downward at the greatest point when a body was thrown vertically upwards, only that point's velocity is zero. As a result, the velocity is zero due to the acceleration.

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Answer:

I do not know this one sorry

The wavelength of x-rays that could be produced when the electrons strike a solid is given by Bragg's equation. Mathematically, it is represented as, n λ = 2 d sinθ.

The X-angle ray's of incidence, and angle of scattering, are the same when it strikes a crystal surface. Additionally, constructive interference will happen when the path difference, d, is equal to a whole number of wavelengths, n.

As we require wavelength, let us make it as the subject in the above equation. Then we have, λ = 2 d sinθ/n

where,

d is the distance between atoms' planes

θ is the angle of scattering

n is the path difference

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The required velocity of the ball when it hits the ground is calculated to be 7.75 m/s.

Mass of the ball = 2 kg

A ball is dropped from a height = 3 m

Velocity = ?

Initial potential energy of the ball Ep = m g h = (2)(10)(3) = 60 J

As the ball reaches the ground, its potential energy becomes zero as it is entirely converted into its kinetic energy Ek.

So, Ek = 60 J

The formula for Ek is said to be 1/2 m v².

Ek = 1/2 m v²

Making v as subject, we have,

v = √(2 Ek/m) = √(2×60/2) = 7.75 m/s

Thus, the velocity of the ball when it hits the ground is 7.75 m/s.

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Answer:  14,286 kg

Explanation:

Mass and velocity, have a positive correlation to momentum.

The formula to determine momentum is:

Momentum = Mass x Velocity

So, if we want to determine the mass of the object, the formula can be rearranged to look like this:

Momentum/Velocity = Mass

And can be solved by imputing the values given in the question:

Mass = (100 kg*m/s) ÷ (7 m/s)

Mass = 14,286 kg

The average angular acceleration of the figure skater during the time interval of 4.6 s is 0.99 rad/s².

For this question:

Then,

angular acceleration = Change in angular velocity / time

α = ω2 - ω1 / t

α = 7.7 - 3.2 / 4.6

α = 4.5/4.6

α = 0.99 rad/s²

Thus, the average angular acceleration of the figure skater during the time interval of 4.6 s is 0.99 rad/s².

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