Answer:
MATTER
ARE
OF
THREE
TYPES
SOLID
LIQUID
GAS
The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?
Answer:
momentum= 145999324.8(kg(m/s))
Explanation:
formula for momentum: p=mv
where p= momentum, m=mass, and v=velocity.
p=2000lbs(100mi/hr)
The standard unit for mass is kg
2000lbs=907.2kg
standard unit for velocity is meters/sec
100mi=160934meters.
907.2kg(160934m/s)=145999324.8
a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with
Answer:
papi sus
Explanation:
can someone explain it please?
Answer:
The answer is 9.4 m/s
Explanation:
Because you add 5.0 + 4.5= 9.4
Given that the mass of a liquid is 0.01kg and the volume of the liquid is 0.05m^3 . Calculate the density of the liquid
A) 2kg/m^3
B)0.2kg/m^3
C) 5kg/m^3
D) 0.5kg/m^3
Answer:
B.
Explanation:
Density = mass / volume
= 0.01/0.05
= 0.2 kg/m^3.
Which form can solutions come in?
liquid
gas
solid
all of the above
Answer:
liquid
Explanation:
leave a thanks if helped !
what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.
Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.
S = I(fsd) / V(fsd).
S = 4.0 / 25
S = 0.16 mA/Ω
Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)
(S(new)) = 50 mA / V(fsd)
(S(new)) = 50 / 0.16
(S(new)) = 312.5 Ω
Add External Resistor:
Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter
(R(internal) = 25 Ω:
R(ext) = R(new) - R(internal)
R(ext) = 312.5 Ω - 25 Ω
R(ext) = 287.5 Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.
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who made the first game
A William Shakespeare
B Horace Alexander
C Doris Twitchell Allen
D William higginbotham
Physical data is often used in the court system. In fact, police officers use radar to determine your speed when you are driving and admit that record in court if you are ever given a ticket. In one such instance, the police officer submitted data that goes against the claim of the driver, who is contesting his ticket in court. The police officer (who was stationary when he made the measure) claims that the driver was speeding at 44.7 m/s, but the driver claims he was only going 26.8 m/s (according to his speedometer). The speed limit was 60 mph. The driver argues that the radar gun must have been set incorrectly to record relative velocity. Is it possible that they are both telling the truth?
The driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
The given parameters:
Speed of the driver observed by the stationary police officer, Vo = 44.7 m/sSpeed of the driver, V = 26.8 m/s.Speed limit = 60 mphThe speed limit of the driver in meter per second is calculated as follows;
[tex]= 60 \ \times \frac{miles}{hour} \times \frac{1609.34 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s}\\\\= 26.82 \ m/s[/tex]
From the speed limit, it is obvious that the driver's speed is within the limit. Thus, we can conclude that the driver is telling the truth, the radar gun must have been set incorrectly to record relative velocity.
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If a spaceship travels at an average speed of 6x10^10 kilometers per year, how many years will it take the spaceship to travel 3x10^30 kilometers? Show work or explain your logic for full credit. a) 5x10^2 b) 5x10^19 c) 5x10^20 d) 5x10^21
First, you need to find out the speed of 6x10^10. Then find out the value of 3x10^30 after you do that, Make this visual,
3x10^30. 5x10 to the 19 power
_______.
6x10^10
The answer is c
If the spaceship travels a distance of 6 × 10¹⁰ kilometers with an average speed the time taken to travel 3 × 10³⁰ kilometers is 5 × 10¹⁹ years. Thus, option a is correct.
What is speed?Speed is a physical quantity associated with a moving body. It is the measure of distance travelled per unit time . Thus, mathematically it is the ratio of distance to the time.
If we have the time and speed known we can find the distance travelled and vice versa. As the speed increases, the distance covered per unit time will be higher.
Here the spaceship travels 6 × 10¹⁰ kilometers . Thus the time taken to travel 3 × 10³⁰ kilometers can be calculated as follows:
1 year - 6 × 10¹⁰ km
? - 3 × 10³⁰ km
Cross multiply them we get, 3 × 10³⁰ km/ 6 × 10¹⁰ km = 5 × 10¹⁹ years.Hence, option a is correct.
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The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Which law was used to determine the relationship between the volume and the number of moles in this equation? Boyle’s law Charles’s law Avogadro’s law Gay-Lussac’s law.
The relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
Avogadro's law:
It states that at constant temperature and pressure, gases with same volume has the same number of molecules.
For an ideal gas with with constant temperature and pressure, the volume of the gas is directly proportional to the amount or number of molecules.
Charle's law states that at constant pressure, volume (V) and temperature (T) are directly proportional.Boyle's law states that at constant temperature, the volume of gas is inversely proportional to the gas pressure.Gay-Lussac's law states that pressure (P) and absolute temperature (T) of the gas are directly proportional.Therefore, the relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
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Answer:
Avogadro's law
Explanation:
plssss helppppppppppp i need it
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
Kepler’s laws of planetary motion describe each of the three laws
Kepler's laws laid the foundation for the early study of astronomy.
Kepler was one of the earliest astronomers that contributed immensely to the study of the planets. The Kepler's laws of planetary motion are as follows;
The planets each travel along an ellipse with the sun at one focus.The line joining the sun and the planets sweeps out equal areas in equal time intervals.The square of the period of the revolution of the planets equals the cube of the planet's mean distance from the sun.Learn more about Kepler's laws; https://brainly.com/question/1017661
how to find velocity of center of mass before and after the collision
Hey there! I'll try to provide you with my best answer.
Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
bow long does it take earth to rotate once on its axis
Answer:
23 hours, 56 minutes
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]
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Answer:
6.983 km/hr
Explanation:
The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr
Mejor yo por favor
The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to the cup or surroundings. What is the final temperature of the mixture? answer in celsius
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function of its horizontal position x.
Part A
Find the net work done on the box as it moves from x = 0 m to x = 8.0 m. .
Part B
Apply concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m. Assume the box started from rest.
From the graph, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
From the question, these are the given parameters;
Mass M = 5.5 KgPosition X = 0 to X = 8mPart A
The net work done will be the area under the graph.
From position X = 2m to X = 8m gives us the shape of a trapezium.
A = 1/2( a + b )h
A = 1/2( 2 + 6 ) x 8
A = 8 x 4
A = 32 Nm
From X = 0 to X = 2 gives us the shape of a triangle.
A = 1/2bh
A = 1/2 x 2 x (-4)
A = -4 x 1
A = -4 Nm
Net Work done = 32 - 4
Net work done = 28 Nm
Part B
Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m
Net Work done = 1/2m[tex]V^{2}[/tex]
Substitute all the necessary parameters
28 = 1/2 x 5.5 x [tex]V^{2}[/tex]
5.5[tex]V^{2}[/tex] = 56
[tex]V^{2}[/tex] = 56/5.5
[tex]V^{2}[/tex] = 10.18
V = [tex]\sqrt{10.1818}[/tex]
V = 3.19 m/s
Therefore, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
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plssssss look at the picture i need it right hurry pls
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
Which image shows an example of the electromagnetic force in action?
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
Depth perception is also known as ___________ vision.
Answer:
depth from optical expansion
Explanation:
Help it multiple-choice 16 and 17 only
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.
anything that has mass and occupies space is called
Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
how to prove the first linear motion
Answer:
Then solve for v as a function of t. This is the first equation of motion . It's written like a polynomial — a constant term (v0) followed by a first order term (at). Since the highest order is 1, it's more correct to call it a linear function.
Explanation:
What is number 10 for this?
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
can someone explain it with steps?
A car was moving on a road at a constant speed of 15 m/s when suddenly the car driver saw some animal on the road at a distance of 21 m from the car, so he applied the brakes after a response time of 0.4 s and stopped before hitting the animal by 1 m. What was the deceleration of the car?
a-7.5 m/s^2
b-5.2 m/s^2
c-8.0 m/s^2
d-5.6 m/s^2
Answer:
Option C is the correct answer
Explanation:
Distance travelled by car during reaction time
[tex]=15\times0.4\\\\=6m[/tex]
The car stopped before hitting the animal by [tex]1 m[/tex]
Distance travelled during deceleration is [tex]21-6-1=14m[/tex]
Hence by [tex]v^2=u^2+2as[/tex]
We have
[tex]0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2[/tex]
Option C is the correct answer
Distance traveled during reaction time
15(0.4)=6mTotal distance
21-6-1=14m[tex]\\ \sf\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \sf\longmapsto -(15)^2=2(14)a[/tex]
[tex]\\ \sf\longmapsto -225=28a[/tex]
[tex]\\ \sf\longmapsto a=-8.0m/s^2[/tex]
Describe your acceleration if you ride your bike up a hill,then ride down the other side.
Answer:
first negative and then positve
A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.
The position on the meter mark where Ari catches up with Amanda is 19.3 m.
The given parameters:
Range of the number line, = 0 to 30Position of the closed circles, = 6 and 25The ratio between the initial position and final position of Ari = 7:3The distance between 6 m mark and 25 m mark is calculated as follows;
[tex]d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m[/tex]
The distance traveled by Ari before catching up with Amanda is calculated as follows;
total ratio = 7 + 3 = 10
[tex]distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m[/tex]
The position of Ari from the 6 m mark is calculated as follows;
[tex]position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m[/tex]
Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.
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Answer:
The above answer is correct! The answer is 19.3 meters :)
Explanation:
adding a ss for proof!
hope this helps :D
what are two variables that are always in every experiment?
the independent variable and the dependent variable.