At Henry's yearly physical, he measured 5 feet 8 inches tall. If there are 2.54 centimeters in 1 inch, what is Henry's height in centimeters?

Answers

Answer 1

Answer:

172.72 centimeters

Step-by-step explanation:

1. 5 ft. = 60 in.

2. 60 in. + 8 in. = 68 in.

3. 68 x 2.54 = 172.72

4. add unit of measurement to your answer

Answer 2

Henry's height in centimeters is 172.72 cm

What is unitary method ?

"A process of finding the value of a single unit, and based on this value we can find the required value. "

For given question,

Henry measured 5 feet 8 inches tall.

There are 2.54 centimeters in 1 inch.

that is, 1 inch = 2.54 cm

First we convert Henry's height in inches.

We know that 1 feet =  12 inches

⇒ 5 feet = 60 inches

so, Henry's height in inches would be,

5 feet 8 inches

= (60 + 8) inches

= 68 inches

From given, 1 inch = 2.54 cm

⇒ 68 inches = 172.72 cm

Therefore, Henry's height in centimeters is 172.72 cm

Learn more about the unitary method here:

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Related Questions

multiply the complex number by this complex conjugate.
16. 8+i
17. 3 - 2i
18. -7- 5i

Answers

8xi=16 to explain your answer

What formula is used to
determine the expected value for a variable?

Answers

The basic expected value formula is the probability of an event multiplied by the amount of times the event happens: (P(x) * n).

Question 3 of 6 (1 point) Attempt 33 of Unlimited View question in a popup

2.4 Section Exercise 6

In a study of 550 meals served at 75 campus cafeterias, 77 had less than 10 grams of fat but not less than 350 calories; 81 had

less than 350 calories but not less than 10 grams of fat; 186 had over 350 calories and over 10 grams of fat.

Part: 0/2

E

Part 1 of 2

(a) What percentage of meals had less than 10 grams of fat? Round your answer to the nearest tenth of a percent.

of the meals studied, 1% of them had less than 10 grams of fat.

Answers

Answer:

10%

Step-by-step explanation:

(a) What percentage of meals had less than 10 grams of fat?

(b) Round your answer to the nearest tenth of a percent.

To find the percentage of meals with less than 10 grams of fat, count the number of meals with less than 10 grams of fat and divide by the total number of meals; multiply this figure by a hundred.

(A) Total number of meals = 550

Number of meals having less than 10 grams of fat = 77

Percentage of meals having less than 10 grams of fat = 77/550 × 100

= 0.14 × 100 = 14%

(B) Rounding the answer to the nearest tenth of a percent means approximating it to the nearest multiple of 10 that is not more than 100 (where 100 here represents a full cent or 'percent').

The multiples of 10 that are close to 14 are 10 and 20. The closest being 10, your answer becomes 10%

What is the midpoint of the segments with endpoints (3,7) and (9,15)

Answers

The midpoint is (6, 11)

I have attached the equation so it’s easier to understand.

To find the midpoint we do
(x^1+x^2 /2 , y^1+y^2 /2)

3, 7 is x^1, y^1
And
9, 15 is x^2, y^2

(3+9 /2 , 7+15 /2)

Add the x and y =

(12/2 , 22/2)

Now we divide both by 2 =

(6, 11)

Answer:

(6,11)

I can confirm that this question is right.

12/2      22/2

(6   ,        11)

Polynomial A: 4z + 724 - 7y+7
Polynomial B: 2.c + 12y - 12z - 7
What will be the coefficients for x, y, and z in the resulting sum?
Select all that apply.
-8
-5
-5
2
5
9
Asse
16
Sect
GO BACK
SUBMIT AND CONTINUE
284691-1307

Answers

Answer:

-8z +724 + 5y +2c

Step-by-step explanation:

Combine like terms

The product of which expression contains four decimal places?

Answers

Answer:

D.) 14.2*0.784

Step-by-step explanation:when you calculate it, there is 4 numbers behind the decimal point.

Every Sunday, Tamika sells pieces of homemade fudge at a local carnival. Each piece of fudge weighs 34 pound. Next Sunday, Tamika plans on

bringing 712 pounds of homemade fudge to sell.

How many pieces of fudge will Tamika be able to sell at the carnival next Sunday?

Answers

Answer:

The answer is c. 5 5/8.

Step-by-step explanation:

Its c because your supposed to multiply them. When you multiply them you get 5 5/8. Hope this helped,have a great day!

Find the unknown angle measures.

Answers

Answer:

x = 9°

y = 119°

Step-by-step explanation:

Given,

y° = 61°+58° { the exterior angle formed by producing the side of triangle is equal to two non-adjacent angle}

or, y° = 119°

therefore, y° = 119°

Now,

52°+y°+x° = 180°{the sum of angle if triangle is 180°}

or, 52°+119°+x°= 180°

or, 171°+x° = 180°

or, x° = 180°-171°

or, x° = 9°

therefore, x° = 9°

To make a shade of paint called jasper green, mix 4 quarts of green paint with cups of black paint. How much green paint should be mixed with 4 cups of black paint to make jasper green?

Answers

Answer:

8 quarts

Step-by-step explanation:

no explanation needed this should be correct.

Brainliest will be given to the correct answer!


The formula for the area of a trapezoid is A = 1/2h (b1 + b2), where h is the height of the trapezoid, and b1 and b2 are the lengths of the bases.

Part A: Solve the formula for h. What is the height of a trapezoid that has an area of 91 cm2 and bases of 12 cm and 16 cm?

Part B: What method would you use to solve the formula for b1? What is the formula when solved for b1?

Part C: What is the length of the other base if one base of a trapezoid is 30 cm, the height of the trapezoid is 8.6 cm, and the area is 215 cm2?

Part D: If both bases of a trapezoid have the same length, can you find their lengths given the area and height of the trapezoid? Explain.

Answers

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].  [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex]

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. [tex]b = \frac{A}{h}[/tex]

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

[tex]A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})[/tex] (Eq. 1)

Where:

[tex]h[/tex] - Height of the trapezoid, measured in centimeters.

[tex]b_{1}[/tex], [tex]b_{2}[/tex] - Lengths fo the bases, measured in centimeters.

[tex]A[/tex] - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}][/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]h = \frac{2\cdot A}{b_{1}+b_{2}}[/tex] Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that [tex]A = 91\,cm^{2}[/tex], [tex]b_{1} = 16\,cm[/tex] and [tex]b_{2} = 12\,cm[/tex], then height of the trapezoid is:

[tex]h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}[/tex]

[tex]h = 6.5\,cm[/tex]

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for [tex]b_{1}[/tex]:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})[/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]2\cdot A \cdot h^{-1} = b_{1}+b_{2}[/tex] Existence of multiplicative inverse/Modulative property

5) [tex]\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}[/tex] Definition of division/Compatibility with addition/Commutative and associative properties

6) [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex] Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ([tex]A= 215\,cm^{2}[/tex], [tex]h = 8.6\,cm[/tex] and [tex]b_{2} = 30\,cm[/tex])

[tex]b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm[/tex]

[tex]b_{1} = 20\,cm[/tex]

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. Now we present the procedure to clear [tex]b[/tex] below:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]b_{1} = b_{2}[/tex] Given.

3) [tex]A = \frac{1}{2}\cdot h \cdot (2\cdot b)[/tex] 2) in 1)

4) [tex]A = 2^{-1}\cdot h\cdot (2\cdot b)[/tex] Definition of division.

5) [tex]A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b[/tex] Commutative and associative properties/Compatibility with multiplication.

6) [tex]b = A \cdot h^{-1}[/tex] Existence of multiplicative inverse/Modulative property.

7) [tex]b = \frac{A}{h}[/tex] Definition of division/Result.

Tickets for a drumline competition cost $5 at the gate and $3 in advance. One hundred more tickets were sold in advance than at the gate. The total revenue from ticket sales was $1990. How many tickets were sold in advance?

Answers

Answer:

The number of tickets sold at the gate is [tex] G = 211.25[/tex]

The number of tickets sold in advance is  [tex]  A = 311.25 [/tex]

Step-by-step explanation:

From the question we are told that

 The cost of a tickets at the gate is [tex]a =  \$ 5[/tex]  

  The cost of a ticket in advance is  [tex]b =  \$ 3[/tex]

Let the number of ticket sold in the gate be G

Let the number of ticket sold in advance  be   A

From the question we are told that

  One hundred more tickets were sold in advance than at the gate and this can be mathematically represented as

       [tex]G  +  100 =  A[/tex]

From the question we are told that

  The total revenue from ticket sales was $1990  and this can be mathematically represented as

    [tex]5 G  +  3A  =  1990[/tex]

substituting for  A in the equation above

    [tex]5 G  +  3[G  +  100]=  1990[/tex]    

    [tex]5 G  +  3G  +  300=  1990[/tex]    

    [tex] 8G  +  300=  1990[/tex]  

    [tex] 8G  =  1690[/tex]

=>  [tex] G = 211.25[/tex]

Substituting this for G in the above equation

     [tex]5 [211.25]  +  3A  =  1990[/tex]

=>    [tex]  3A  =  1990 - 1056.25[/tex]

=>    [tex]  A = 311.25 [/tex]

What is the value of x?

20
35
60
70

Answers

Answer:

20°

Step-by-step explanation:

Step 1:

x + 40° = 3x       Vertical ∠'s

Step 2:

40° = 2x      Subtract x on both sides

Step 3:

x = 40° ÷ 2     Divide

Answer:

x = 20°

Hope This Helps :)

There were 75 sheep and 60 cows. What is the ratio of the number of cows to the number of sheep at mcneely’s farm

4/9
5/9
4/5
5/4

Answers

Answer:

4/5

Step-by-step explanation:

Find the surface area of the cube shown below 2.3

Answers

Answer:

2 2/3 or 8/3

Step-by-step explanation:

Formula for each side = 2/3 x 2/3

2/3 x 2/3 = 4/9

6 sides

4/9 x 6 or 4/9 + 4/9 + 4/9 + 4/9 + 4/9 + 4/9

=2 2/3 or 8/3

Answer:

2 2/3

Is the answer

function rule y=3x-3

Answers

Answer:

-15, -9, -3, 3

Step-by-step explanation:

First One:

y =3(-4)-3 is -15

Second:

y= 3(-2)-3 is -9

Third:

y= 3(0)-3 is -3

Last One:

y= 3(2)-3 is 3

Rectangle A’B’C’D’ is the image of rectangle ABCD after which of the following rotations?

Answers

Answer:

You're right!

Step-by-step explanation:

Answer:

Were you right?

Step-by-step explanation:

The body temperatures of a group of healthy adults have a​ bell-shaped distribution with a mean of 98.18 F and a standard deviation of 0.65 F. Using the empirical​ rule, find each approximate percentage below.

a.

What is the approximate percentage of healthy adults with body temperatures within 3 standard deviation of the​ mean, or between 96.23 F and100.3 ​F?

Answers

Answer:

99.7%

Step-by-step explanation:

Empirical rule formula states that:

• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

From the question, we have mean of 98.18 F and a standard deviation of 0.65 F

The approximate percentage of healthy adults with body temperatures between 96.23 F and100.13 ​F is

μ - 3σ

= 98.18 - 3(0.65)

= 98.18 - 1.95

= 96.23 F

μ + 3σ.

98.18 + 3(0.65)

= 98.18 + 1.95

= 100.13 F

Therefore, the approximate percentage of healthy adults with body temperatures between 96.23 F and 100.13 ​F which is within 3 standard deviations of the mean is 99.7%

Ralph chase plans to sell a piece of property for 170000 he wants the money to be paid off in two ways -a short-term note at 11% interest and a long term note at 9% interest. Find the amount of each note if the total annual interest paid is 171700

Answers

Answer:

There is something wrong with the question because you cannot earn more interest during a year than the principal if you earn only 9% or 11%. You would have to earn more than 100%, so I will do this calculation based on $17,170 (not $171,700) earned in interest per year.

let S = amount received from short term note, and L = amount received from long term note

0.11S + 0.09L = 17170

S + L = 170000

S = 170000 - L

0.11 (170000 - L) + 0.09L = 17170

18700 - 0.11L + 0.09L = 17170

1530 - 0.02L = 0

1530 = 0.02L

L = 1530 / 0.02 = $76,500

S = 170000 - 76500 = $93,500

Select the correct answer from the drop-down menu.

A company sells its products to distributors and boxes of 10 units each. it's profits can be modeled by this equation, where p is the profit after selling n boxes.

p = -n² + 300n + 100,000

Use this equation to complete the statement.

The company breaks even, meaning the profits are only $0, when it sells _____ boxes.

Options for Blank:

A: 200 or 500

B: 500

C: 150

D: 200​

Answers

Answer:

B. 500

Step-by-step explanation:

Given the profit made by a company modeled by the function

p = -n² + 300n + 100,000

The company breaks even when p = 0

To get the number of boxes sold when the company breaks even, we will substitute p = 0 into the equation.

0 = -n² + 300n + 100,000

multiply through by -1

0 = n² - 300n - 100,000

n² - 300n - 100,000 = 0

(n² - 500n) + (200n - 100,000) = 0

n(n-500)+200(n-500) = 0

(n+200)(n-500) = 0

n+200 = 0 and n-500 = 0

n = -200 and n = 500

Since n cannot be negative

Hence n = 500

This means that the company breaks even when it sells 500 boxes

A stick is broken into two pieces, at a uniformly random breakpoint. Find the CDF and average of the length of the longer piece.

Answers

Answer:

Step-by-step explanation:

See attachment

A lumber supplier sells 96-inch pieces of oak. Each piece must be within ¼ of an inch of 96 inches. Write and solve an inequality to show acceptable lengths.

Answers

Answer:

[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]

Step-by-step explanation:

Given that a lumber supplier sells 96 inch Pieces of oak which must be within 1/4 of an inch.

This situation can be represented by the following absolute value inequality:

[tex]|x \: - 96| \: \leqslant \: \frac{1}{4} [/tex].

The absolute value can be thought of as the size of something because length cannot be negative. The length must be no more than 1/4 away from 96.

To simplify this, pretend this is a standard equality, |x-96| = 1/4. 1/4 is the range of acceptable length, 96 is the median of the range, and x is the size of the wood.

First apply the rule |x| = y → x = [tex]\pm[/tex]y

|x-96| = 1/4

x - 96 = [tex]\pm[/tex]1/4

x = [tex]96 \pm 1/4[/tex]

(These are just the minimum, and maximum sizes)

Now with a less than or equal to, the solutions are now everything included between these two values.

Therefore:

[tex]96 - 1/4 \: \leqslant x [/tex] [tex]\leqslant \: 96 + 1/4 [/tex]

With less than inequalities, you must have the lower value on the left, and the higher value on the right.

If x represents the size of the pieces, then the acceptable lengths are represented by this following inequality:

[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]

This is interpreted as x (being the size of the oak) is greater than or equal to 95 3/4, and less than or equal to 96 1/4 in inches.

True or false: 8.9 x 10-7 = 0.000 008 9.

Answers

It is False 8.9x10-7 does not equal 0.00000089

What is the greatest whole number that rounds to 2, 100when rounded to the nearest​ hundred? The least whole​ number?

Answers

Answer:

i am pretty sure it would be 8

Step-by-step explanation:

when it rounds to 2 but also rounds to 100, 8 would be the best bet.

suppose that the life distribution of an item has the hazard rate function of what is the probability that

Answers

Answer:

that what

Step-by-step explanation:

5
4. y = 1
D
1
1
1
I
B

Answers

Answer:

not sure what you need but I would be happy to help

A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out what price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit.
y=-10x^2+600x-3588
y=−10x
2
+600x−3588

Answers

Answer:

Step-by-step explanation:

The maximum profit will be found in the vertex of the parabola, which is what your equation is. You could do this by completing the square, but it is way easier to just solve for h and k using the following formulas:

[tex]h=\frac{-b}{2a}[/tex] for the x coordinate of the vertex, and

[tex]k=c-\frac{b^2}{4a}[/tex] for the y coordinate of the vertex.

x will be the selling price of each widget and y will be the profit. Usually, x is the number of the items sold, but I'm going off your info here for what the vertex means in the context of this problem.

Our variables for the quadratic are as follows:

a = -10

b = 600

c = -3588. Therefore,

[tex]h=\frac{-600}{2(-10)}=30[/tex] so the cost of each widget is $30. Now for the profit:

[tex]k=-3588-(\frac{(600)^2}{4(-10)})[/tex] This one is worth the simplification step by step:

[tex]k=-3588-(\frac{360000}{-40})[/tex] and

k = -3588 - (-9000) and

k = -3588 + 9000 so

k = 5412

That means that the profit made by selling the widgets at $30 apiece is $5412.

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

What is the maximum profit?

Maximum profit, or profit maximisation, is the process of finding the right price for your products or services to produce the best profit.

Here given that,

A company sells widgets. The amount of profit, [tex]y[/tex], made by the company, is related to the selling price of each widget, [tex]x[/tex], by the given equation.

As the maximum profit found in the vertex of the parabola,

Here, [tex]x[/tex] will be the selling price of each widget and [tex]y[/tex] will be the profit.

The number of items sold is [tex]x[/tex].

So, the quadratic equation is:-

[tex]a = -10b = 600c = -3588.[/tex]

Therefore, so the cost of each widget is $[tex]30[/tex].

For the profit:-

[tex]k = -3588 - (-9000) andk = -3588 + 9000 sok = 5412[/tex]

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

To know more about the maximum profit

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Graph the line y-3=-1/3(x+2)

Answers

Slope: 1/2

y-intercept(s): (0, 7/3)

x: 0, 7

y: 7/3, 0

Step-by-step explanation:

y=-3 -1/3(1+2)=2/3.3=1.3=3

y=3

solve for z 3=(z+1) write your answers as integers or as proper or improper fractions

Answers

Answer:

z=2

Step-by-step explanation:

Just solve

1 + z = 3 (minus 1 on both sides)

z = 2

Plug in

3=(2+1)

3 = 3

11. Mary just received her paycheck and would like to cash it. She does not have a checking account, where should she go to cash it? *

Answers

Answer:

Cash it at the issuing bank (this is the bank name that is pre-printed on the check)

Cash a check at a retailer that cashes checks (discount department store, grocery stores, etc.)

Cash the check at a check-cashing store.

Deposit at an ATM onto a pre-paid card account or checkless debit card account.

Step-by-step explanation:

Answer:

Amscot?

Step-by-step explanation:

From a circular sheet of paper with a radius 20 cm, four circles
of radius 5 cm each are cut out. What is the ratio of the uncut to
the cut portion?

Answers

Answer:

3 : 1

Step-by-step explanation:

The biggest circle has a radius of 20 cm

So that means, its area will be,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi * 20^{2}[/tex]

A = [tex]\pi * 400[/tex]

=> A = 400[tex]\pi[/tex]

We do not need to solve this because it is nit required

Then, one small circle has an area of,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi *5^{2}[/tex]

Area = [tex]\pi *25[/tex]

=> Area = 25[tex]\pi[/tex]

As there are 4 circles in, we get that the area covered by the small squares,

=> [tex]25\pi * 4[/tex]

=> [tex]100\pi[/tex]

So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)

=> 1/4

So, there is 1 cut region and the remaining is the uncut region,

As we need to find uncut to cut, the ratio will be,

=> remaining : 1

=> 3 : 1

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

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