A car traveling 60 miles west (-) stops and then travels another 20 miles
west (-). The car then loops around and travels back to the east (+) a total
of 10 miles. What is the displacement of the car?*
Answer:
128
Explanation:
One clomiter is 1.06 multipled by 80
A gas is compressed to 75cm3 to a volume of 30cm3. Its temperature remains the same The pressure of the gas after it has been compressed is 110 Pa. What was the pressure before it was compressed?
Given parameters:
Initial volume = 75cm³
New volume = 30cm³
New pressure = 110Pa
Unknown:
Initial pressure = ?
Solution:
Condition: temperature is constant
We simply apply Boyle's law to this problem:
" the volume of a fixed mass(mole) of a gas varies inversely as the pressure changes if the temperature is constant".
Mathematically;
P₁ V₁ = P₂ V₂
where P and V are pressure and volume values
1 and 2 are the initial and final states.
Input the parameters and solve for P₁;
P₁ x 75 = 110 x 30
P₁ = 44Pa
The initial pressure is 44Pa
III.
Solve:
1. An elephant puts a force of 30000N on its four feet, which have a total area of
750cm. What is the pressure exerted by the elephant on the
ground?
please explain T-T
The solar system revolves around the center of the Milky Way.
True or false
Answer:
yes
Explanation:
Answer: True
Im sure of it i took the test
Explanation:
This waterbottle has a mass of .5 kg. If the net force acting on the bottle is five and to the right what is the bottles acceleration (hint: use formula a=f/m
Answer:
a = 10/s^2
Explanation:
Answer:
a=10 m/s *2 right
Explanation:
The net force (0.5 kg) divided by the mass (5 N) = 10
The force moved the object to the right.
So you Would put this in the equation a=___ m/s *2 _____
And you would get a=10m/s*2 right
HOPE YOU LEARNED SOMETHING SO WHEN WE GO BACK TO SCHOOL YOU WILL KNOW WHAT YOU ARE TALKING ABOUT ! : )
whu is it important to mave regular supervision of weights and measurements in the market
Answer:
Hope the answer helped you. if yes pls follow me
Explanation:
the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.
Answer:
the fundamental answer is without regular supervision of definition of weights and measures,commerce exchange will be impossible and there would be no market whatsoever for anything.
Explanation:
"who"
To determine the height of a bridge above the water, a person drops a stone and measures the time it takes for it to hit the water. If the time is 2.3 s, what is the height of the bridge? Neglect air resistance.
a. 32 m
b. 52 m
c. 26 m
d. 14 m
e. 10 m
A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
A stone is dropped from a bridge and it experiences a uniformly accelerated rectilinear motion. It takes 2.3 s for the stone to reach the water.
We can calculate the height of the bridge, which is equal to the displacement of the stone, using the following kinematic equation.
[tex]s = ut + \frac{1}{2} a t^{2} = (0m/s)(2.3 s) + \frac{1}{2} (9.8m/s^{2} ) (2.3s)^{2} = 26 m[/tex]
where,
s: displacementu: initial speed (0 m/s)t: timea: acceleration due to gravity (9.8 m/s²)A stone dropped from a 26 m bridge, takes 2.3 s to reach the water.
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A 5000 kg truck and a 1000 kg car are traveling at constant speeds when they collide. What is true about the forces and accelerations on each?
Force is the physical action that can give acceleration to a body upon which it is applied
The true statements about the forces and accelerations of each when they collide are;
The force acting on the truck is equals the reactive force of the car The acceleration of the car is five times the acceleration of the truckThe reasons why the above statements are true are given as follows:
Known:
Mass of the truck, m₁ = 5,000 kg
Mass of the car, m₂ = 1,000 kg
Velocity of the truck = [tex]v_t[/tex]
Velocity of the car = [tex]v_c[/tex]
According to Newton's third law of motion, action and reaction are equal and opposite
The force applied by the truck, F = The reactive force by the carForce, F = Mass, m × Acceleration, a
Let a₁ represent the acceleration of the truck and let a₂ represent the acceleration of the car, we have;
F = 5,000 × a₁ = 1,000 × a₂
[tex]a_2 = \dfrac{5,000 \ kg}{1,000 \ kg} \times a_1 = 5 \cdot a_1[/tex]
Therefore;
The acceleration (rate of change of velocity) of the car, a₂ due to the collision is five times the acceleration of the truck due to the collisionLearn more about the about force and acceleration here:
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where is the image located when an objectis placed 30cm from a convex lens with a focal length of 10cm?
Answer:
15 cm
Explanation:
using the thin lens formula for convex lens
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}\\ \\where f = focal length \\ p = object distance \\ q = image distance\\[/tex]
so,
[tex]\frac{1}{q} = \frac{1}{f} - \frac{1}{p} \\\\\frac{1}{q} = \frac{1}{10} - \frac{1}{30} \\\frac{1}{q} = \frac{2}{30}\\\frac{1}{q} = \frac{1}{15cm}[/tex]
so,
q = 15 cm
When your blood pressure is low, choose a choice below that explains what occurs.
A. The nervous system signals smooth muscles in the blood vessels to relax to decrease blood pressure.
B. The nervous signals smooth muscles in the blood vessels to relax to increase blood pressure.
C. The nervous system signals smooth muscles to contract to decrease blood pressure.
D. The nervous system signals smooth muscles in the blood vessels to contract to increase blood pressure
Answer:
The correct option is;
D. The nervous system signals smooth muscles in the blood vessels to contract to increase blood pressure
Explanation:
The contraction or relaxation of the vascular smooth muscles lead to the blood vessel volume change and blood pressure change such that the blood is redirected to regions of the body that requires instantaneous increased oxygen intake. As such the nervous system signals the blood vessel's vascular smooth muscle to contract, through vasoconstriction so as to raise the blood pressure, when the blood pressure is low.
During a spacewalks an astronaut lets go of a tool, causing it to float away and bounce off the side of the space shuttle. The astronaut saw
the the tool hit the shuttle but did not hear it hit the shuttle. Why would the astronaut be able to see the tool hit the shuttle but not hear it
hit the shuttle?
FISH
Answer:
In space noone can hear you scream.....
Explanation:
There is no sound in space. Sound, like light or heat, is a wave. However, one major distinction is that, unlike light or heat (radiation), sound needs a medium to travel. Sounds require the presence of molecules or particles to travel from one region to another.
PLEASE HELP ME FAST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Basketball has a mass of 0.1kg
m = 0.1 kg
The basket ball is moving at constant speed, this shows that it is not accelerating. So, acceleration is zero
a = 0m/s²
The constant speed is 6m/s
v = 6m/s
So, force to keep it moving with this constant speed can be calculated using Newton second law of motion
F = ma
F = m × 0
F = 0N
So, since the basket ball is moving at constant speed, then, the force need to keep the ball moving is 0N.
The drawing shows a 26.1-kg crate that is initially at rest. Note that the view is one looking down on the top of the crate. Two forces, and , are applied to the crate, and it begins to move. The coefficient of kinetic friction between the crate and the floor is k = 0.347. Determine the (a) magnitude and (b) direction (relative to the x axis) of the acceleration of the crate.
Answer:
(a). The magnitude of the acceleration of the crate is 1.44 m/s².
(b). The direction of the crate is 34.60°.
Explanation:
Given that,
Mass of crate = 26.1 kg
Coefficient of kinetic friction = 0.347
We need to calculate the resultant force
Using figure
[tex]F'=\sqrt{(F_{x}+F_{z})^2+F_{y}^2}[/tex]
Put the value into the formula
[tex]F'=\sqrt{(88\cos{55}+54)^2+(88\sin 54)^2}[/tex]
[tex]F'=126.4\ N[/tex]
(a). We need to calculate the acceleration of the crate
Using formula of sum of force
[tex]\sum{F}=F'-\mu N[/tex]
[tex]ma_{total}=F'-\mu mg[/tex]
[tex]a_{total}=\dfrac{F'}{m}-\mu g[/tex]
Put the value into thr formula
[tex]a_{total}=\dfrac{126.4}{26.1}-0.347\times9.8[/tex]
[tex]a_{total}=1.44\ m/s^2[/tex]
(b). We need to calculate the direction
Using formula of the direction
[tex]\theta=\tan^{-1}(\dfrac{F_{y}}{F_{x}+F_{z}})[/tex]
Put the value into the formula
[tex]\theta=\tan^{-1}(\dfrac{88\sin55}{88\cos55+54})[/tex]
[tex]\theta=34.60^{\circ}[/tex]
Hence, (a). The magnitude of the acceleration of the crate is 1.44 m/s².
The direction of the crate is 34.60°.
HELP ASAP! Will make BRAINLEST
Which two options are reasons that electromagnetic waves can be used effectively in communication devices?
A. The speed at which they carry information can be varied.
B. They require no wires to carry information
C. Any type of electromagnetic wave can be used for communication.
D. They can travel through either air or other types of matter.
Answer:
B and D
Explanation:
Did the quiz
Electromagnetic waves require no wires to carry information and can travel through either air or other types of matter. Therefore, options (B) and (D) are correct.
What are electromagnetic waves?Electromagnetic radiations are produced when an electric field comes in contact with the magnetic field. Electromagnetic waves are the composition of oscillating electric as well as magnetic fields.
Infrared radiation is used in security cameras and used for night vision. UV rays are useful to detect forged banknotes as the real banknotes don’t turn fluorescent under UV light.
Electromagnetic radiation can travel energy in a vacuum or air. Electromagnetic waves play a vital role in today's communication technology. Electromagnetic waves are specially used in RADARS to detect aircraft in the earth's atmosphere.
Radio waves, microwaves, infrared (IR), and visible light can be used for communication. Radio waves are used to transmit information on television and radio programs. Microwaves are used to transmit satellites, mobile phones, and television.
Learn more about the electromagnetic wave, here:
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1. There is a group of kids playing tee ball in front of your house. If the bat is 5kg traveling with a velocity
of 8m/s, with what velocity will the 1.5 kg ball travel after it is hit by the bat?
Answer: tug vi
Explanation:
Because
A soccer player runs 80 yards down the field and then 30 yards back toward her
original starting point. This takes 55 seconds total. What is the average velocity of
the soccer player?
0.50 yd/s
0.91 yd/s
1.10 yd/s
2.00 yd/s
A stone has a mass of 2kg and volume of 0.00025m3, what is the density of the stone?
Answer:
density = [tex]\frac{mass}{volume}[/tex]
so,
d = 2/0.00025
d = 8000 kg/m3
What is the momentum of a 950 kg car moving at 10.0 m/s?
9.5 kgm/s
95 kgm/s
9500 kgm/s
95000 kgm/s
Answer:
The answer is 9500 kgm/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocityFrom the question
mass = 950 kg
velocity = 10.0 m/s
We have
momentum = 950 × 10
We have the final answer as
9500 kgm/sHope this helps you
What forces cause acceleration?
Answer:
friction, should be correct i think!
A water-balloon launcher with a mass of 2.0 kg is suspended on a wire. It
fires a 0.75 kg balloon to the west at a velocity of 14.0 m/s. What is the
resulting velocity of the launcher if the net force on the launcher is equal to
the reaction force?
A. 5.3 m/s east
B. 6.6 m/s west
C. 7.4 m/s east
D. 37.3 m/s east
Answer:
5.3
Explanation:
Answer:
5.3 m/s east
Explanation:
A boy is going down a slide. As he reaches the bottom, friction causes him to slow down and stop. Which one of Newton's laws is this?
2nd law
3rd law
1st law
4th law
The given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.
Given data:
A boy slides down and friction causes him to slow down and stop.
In the given problem, when boy was sliding down, then he was in the state of motion, such that the when the he reaches at the bottom of hill, the friction plays the role of external agent to stop its motion.
This shows that the first law of motion is clearly followed which says that, "If an object is in motion, then it will be in motion until and unless any external force is applied on it". This is also known as law of inertia.
Thus, we can conclude that the given condition satisfies the Newton's First Law of motion. Hence, option (C) is correct.
Learn more about the Newton's first law of motion here:
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Write a short story where the main character needs protection from two different EM radiations
19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m
19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m19. Calculate the work done when a 30 N force pushes a rock 10 m. a) 3J b) 0.33 J c) 40 J d) 300 J
20. How far did a rock move if a force of 200 N moved it doing 100 J of work? a) 2 m b) 0.5 m c) 20,000 m d) 300 m
21. An explosion of gas from a Hawaiian volcano blows a rock into the sky. the rock has 2000J of kinetic energy. What was its mass if the rock had a velocity of 20m/s. a) 200Kg b) 20,000Kg c) 10Kg d) 200Kg
22. How much potential energy does a 2 kg book have if it is 2 meters from the ground? a) 39.2J b) 12 J c) 19.6 J d) 98 J
23. 45J of work were done on the object that moved 5M. How much force was applied to the object? a) 8N b) 9N c) 225N d) ON
24. If you do 40 joules of work lifting a 10N box, how high is the shelf you move it to. a) 400m b) 50m c) 40m d) 4m
25. A force of 100 newtons was necessary to lift a rock. A total of 150 joules of work was done. How far was the rock lifted? a) 1.5 m b) 15 m c) 0.15 m d) 150 m
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The stage of respiration that releases most of the energy in glucose occurs in the ______.
What are three ways less gravity changes the human body
What is the pH of 0.001 M HNO3?
Answer:
i think its 2.0
Explanation:
hopefully i am right ...
Who is Josh Gibson write a short paragraph 3-5 sentences
Answer:
Hope this helps
Explanation:
Josh Gibson, (born December 21, 1911, Buena Vista, Georgia, U.S.—died January 20, 1947, Pittsburgh, Pennsylvania), American professional baseball catcher who was one of the most prodigious home run hitters in the game’s history. Known as “the black Babe Ruth,” Gibson is considered to be the greatest player who never played in the major leagues, there being an unwritten rule (enforced until the year of his death) against hiring black ballplayers
how does a meteor transfer energy?
Answer:
Hope this answered your question!~ (Sorry if you get it wrong or I got it wrong-)
Explanation:
When an impact event happens, the enormous kinetic energy of the asteroid or meteorite – a massive body travelling at high speed – is partly transferred to the Earth but largely converted into heat and sound, creating pressure waves travelling radially outwards from its centre, similar to that of an atom bomb.
~The Confuzzeled homan
how far will a 600 kg boat travel in 12 s if there is a constant 900 N force on it and it starts from rest?
Answer:
Distance, S = 108 meters.
Explanation:
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is;
[tex] F = ma[/tex] ............equation 1
Where;
F represents force measured in Newton. m represents the mass of an object measured in kilograms. a represents acceleration measured in meters per seconds square.Given the following data;
Since the boat is starting from rest, initial velocity, u = 0
Mass, m = 600kg
Time, t = 12s
Force, F = 900N
Substituting into equation 1, we have;
[tex] 900 = 600*a[/tex]
[tex]a = \frac{900}{600}[/tex]
Acceleration, a = 1.5 m/s²
T
To solve for distance, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation, we have;
[tex] S = 0(12) + \frac {1}{2}*1.5* 12^{2}[/tex]
[tex] S = 0 + 0.75* 144[/tex]
Distance, S = 108m
Therefore, the distance covered by the boat is 108 meters.
1300 J of work are done when a rock is pushed 40 m. How much force was used?
Explanation:
Work=ForcexDisplacement
Force= Work/Displacement
= 1300/40
= 32.5 N