x^2+12x-20/3x-5 = x^2+8x+12/2x+3
[tex] \frac{ {x}^{2} + 12x - 20}{3x - 5} = \frac{ {x}^{2} + 8x + 12}{2x + 3} [/tex]
Solution give;;;
Answers
Answer:
In attachment I have answered this problem.
![X^2+12x-20/3x-5 = X^2+8x+12/2x+3[tex] \frac{ {x}^{2} + 12x - 20}{3x - 5} = \frac{ {x}^{2} + 8x + 12}{2x](https://brainimage.s3.us-east-005.backblazeb2.com/answers/attachments/QIg6PJFut6p5lWD1RpwDe8l0Uq2ZDxXY.jpeg)
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
Para conocer cual es la fuerza que necesita el cuerpo para aumentar su velocidad de 5 m/s a 12 m/s en 8 m
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Answer:
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Answers
Answer:
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step:
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Step:
20% = 20/100
of = ×
20/100 × $1575.00
Answer : $315
How many solutions does this equation have
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Answer:
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Answers
Answer:
Step-by-step explanation:
put C=13,700 and find m
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\[m \approx 30000\]
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Answers
Answer:
Step-by-step explanation:
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