while in horizontal flight at a speed of 20 m/s, a baseball of mass 0.11 kg is struck by a bat. after leaving the bat, the baseball has a speed of 29 m/s in a direction opposite to its original direction. the magnitude of the impulse given the ball is

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Answer 1

The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity. The baseball received an impulse with a magnitude of -5.39 kg*m/s.

The baseball's change in momentum is equal to the impulse applied to it. An object's momentum is determined by multiplying its mass by its velocity.

The baseball's initial momentum is equal to 0.11 kg times 20 m/s, or 2.2 kg/s.

The baseball's ultimate velocity is calculated as (0.11 kilogramme) * (-29 m/s) = -3.19 kgm/s.

The difference between the baseball's final and starting velocities, or its change in momentum, is equal to 5.39 kg*m/s (final momentum - beginning velocities = -3.19 kgm/s - 2.2 kgm/s).

As a result, the baseball received an impulse with a magnitude of -5.39 kg*m/s.

Due to the ultimate velocity being in the opposite direction of the original vector, the impulse is negative.

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Related Questions

A source produced 15 waves in 3 seconds , The distance between a crust is 15cm . Find frequency and wavelength​

Answers

Frequency and wavelength​ is 100m/s.

Exactly how is frequency calculated?

Pictures for Calculate the frequency and wavelength. The formula for frequency expressed in terms of time is given as follows: f = 1/T, where T is the duration of a cycle expressed in seconds and f is the frequency expressed in hertz. The frequency formula is stated as f = / where denotes the wave speed and the wavelength of the wave.

Explanation:

In 3 seconds, the source is generating 15 waves.

In a second, there are 15/3 waves, or 5 waves, produced.

Thus, the frequency is 5 Hz.

assuming that the wave length /2 = 10 cm

so that =20 cm

speed = frequency *wavelength v=5*20

v=100m/s.

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while a car travels around a circular track at a constant speed, its group of answer choices velocity is zero. none of the above acceleration is zero. inertia is zero.

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Answer: None of the options.

What is energy ?

-- energy, in physics, the capacity for doing work. It may exist in capacities, kinetic, thermal, electrical, chemical, nuclear, or other various forms.

-- There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another

When we talk about uniform circular motion (constant speed) we yet have a changing velocity and therefore, acceleration.

How is this possible?

-- Well, velocity is a vector, and as a vector it has magnitude (the speed) and direction.

--  So, while an object performs a uniform circular motion, althought its speed is not changing, its direction does change.

-- And, since acceleration  is the variation of velocity  in time  , certainly there is acceleration here.

On the other hand, Inertia  is mathematically expressed as:

This means that for a system with a given axis of rotation and a given total mass , the greater the distance from the axis  to the object that performs the circular motion, the greater the inertia.

This also means that inertia depends directly on the mass of the system and the radius of the circular motion, therefore, as long as these elements exist, in a circular motion the inertia will always be different from zero.

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You are riding a bike with a bag in the front basket. A friend
on the sidewalk watches you ride by, heading south.
Which statement best describes how the bag's motion is
relative to the frame of reference - you and your friend?

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Bag's motion is ,a straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).

Describe a speed example?In a specific direction, accelerate. A 50 mph Eastbound automobile is an illustration. the relationship between an object's motion's distance and time is demonstrated. An object's speed is depicted by the line.An object's velocity is altered by a net force; the acceleration increases with the magnitude of the net force. For an item to accelerate by the same amount as an object that is less massive, more net forces are needed.A straight line with a constant slope (positive slope) and positive value represents a positive, steady velocity (upwards sloping).        

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one can tell a raw egg from a boiled one by spinning it on a table. a boiled egg spins for a longer time. explain using fluid mechanics concept.

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A boiled egg rotates for longer time.

While a raw egg contains liquid, a hardboiled egg behaves like a stiff body. The fluid inside the egg flows about as the raw egg is spun, changing its center of gravity or balancing point. Due to centrifugal force, when rotated, the liquid is pushed out from the center. Since raw eggs have more moment of inertia than boiled eggs do, they spin with less angular acceleration because their mass is dispersed farther from the axis in raw eggs than it is in boiled eggs. So, boiling eggs will spin more quickly than raw ones.

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The reason behind the fluids mechanics concept is the moment of inertia.

The tough boiled egg spins for a good deal longer (and quicker) than the uncooked egg. This is due to the fact the inner is stable, so the whole element is one stable mass. The uncooked egg has liquid at the inner, which isn't connected to the shell. The liquid inner it a good deal tougher to spin, and it slows the egg down a good deal quicker. When circled the liquid is driven far from the centre because of centrifugal force. Therefore mass in uncooked egg is sent further from the axis as compared to boiled egg, so moment of inertia for uncooked egg is extra so uncooked egg spin with much less angular acceleration. Therefore, boiled egg will spin quicker than uncooked egg.

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if a vehicle is of length 4.7 m on the average, what is the average spacing between vehicles at the above traffic density?

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Average vehicle spacing at higher traffic density is 35.4 m for a vehicle with a length of 4.7 m.

Let's assume that Traffic flows at 96 km/h as per international data.

We need to find average vehicle spacing.

It indicates that a 96 km stretch of traffic gets cleared in one hour. In addition, 2400 cars may be supported in one lane for an hour. It implies that at least 96km must be taken up by 2400 automobiles. Congestion results from more vehicles moving at the same speed but occupying a smaller space as the number of automobiles increases.

Here, the key to the issue is that you must just consider length. 96 kilometres equal 96,000 metres at this time. If 2400 automobiles take up this much space [just lengthwise], 1 car will take up 96000/2400 m. it is 40 metres. Therefore, each automobile may use up 40m. But the automobile is 4.2 metres long.

It can thus also have a free space of 40 - 4.6 = 35.4 m.

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a mass is attached to a vertical spring and set into vibration. the highest point of the motion is point a and the lowest point of the motion is point b. at what position or positions in its motion is the object's potential energy at a maximum? (consider the potential energy of the mass-earth-spring system.)

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Peak A, which is the motion's highest point, and point B, which is its lowest point, are where the object's potential energy is greatest.

Point A, the greatest point of the motion, has the largest potential energy for the item. The mass is now at its maximal potential energy and the spring is fully expanded. The potential energy drops as the mass descends toward point B because the spring contracts and the mass loses potential energy. The potential energy is at its lowest when the mass reaches point B since the spring is entirely compressed and the mass is at its lowest point. The mass subsequently goes back up to point A, and the process is repeated, increasing the potential energy.

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oak is 0.8 as dense are water and therefore floats in water. what weight of water will be displaced by a 50 kg floating oak beam?

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613.25 N is the weight of water will be displaced by a 50 kg floating oak beam, if oak is 0.8 times dense of water.

Density of water, = 1000 kg/m³

Density of oak, = 0.8 × 1000 = 800 kg/m³

Floating of an object is possible if the upward force exerted by the water is equal to the weight of the object. And this upward force is equal to the weight of water displaced by the floating object.

Volume of the water displaced by the 50 kg oak, V = 50/800 = 0.0625 m³

Mass of the displaced water = 0.0625 × 1000 = 62.5 kg

Weight of the displaced water = 62.5 × 9.81 = 613.13 N.

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Two Small Spheres Spaced 20.0 Cm Apart Have Equal Charge. &Nbsp; How Many Excess Electrons Must Be Present On Each Sphere If The Magnitude Of The Force Of Repulsion Between Them Is 4.57 X 10-21 N? &Nbsp; Number Of Electrons = ?This problem has been solved!You'll get a detailed solution from a subject matter expert that helps you learn core concepts.See AnswerTwo small spheres spaced 20.0 cm apart have equal charge.How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57 x 10-21 N?Number of Electrons = ?

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The number of excess electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.

How to calculate the number of excess electrons?

The number of extra electrons in each sphere can be calculated using Coulomb's law. Coulomb's law states that the repulsive force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

F = k * (q1 * q2) / d^2

where F is the repulsive force, q1 and q2 are the charges on the two spheres, d is the distance between the spheres, and k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2).

Since the repulsive force is 4.57 x 10-21 N and the distance between the spheres is 20 cm = 0.2 m, we can rearrange the equations to find the charge on each sphere.

q1 = sqrt(F * d^2 / k)

q1 = square root (4.57 x 10-21 N * (0.2 m)^2 / (8.99 x 10^9 Nm^2/C^2)) = 1.24 x 10^-19 C

So the number of extra electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.

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Two tiny conducting spheres are identical any carry charges of `-20.0 mu C` and `+50.0 muC`. They are separated by a distance of 2.50 cm. The spheres are brought into contact and then separated to a distance of 2.50 cm. Determine the magnitude of the force that each sphere now experiences, and state whether the force is attractive or repulsive.
A. 1.30 x 10^(2) N, attractive
B. 3.24 x 10^(3) N, attractive
C. 3.24 x 10^(3) N, repulsive
D. 1.44 x 10^(4) N, repulsive

Answers

The magnitude of the force that each sphere before contact and after contact are 1.438 × 10¹⁶ N and 3.5 × 10¹⁴ N respectively.

"Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them." It runs on the same track as the two charges, which are thought of as point charges.

Q₁ = -20 C

Q₂ = +50 C

Distance d = 2.5 cm equals 0.025 metres

F = (k Q₁ Q₂)/d² = (8.99 × 10⁹ × 20×50) /(0.025)² = 1.438×10¹⁶ N

Given that, the charges have opposing signs, the force is alluring.

The charge on each sphere after contact,

Q = Q₁ + Q₂/2 = -20+ 50/2 = -20 + 25 = 5 C

Magnitude of force = k Q²/d² = (8.99× 10⁹ × 5²)/(0.025)² = 224.75× 10⁹/(0.000625) = 359600× 10⁹ = 3.5 × 10¹⁴ N

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A substance has a triple point at a temperature of 17 ∘C and a pressure of 3. 2 atmospheres. In what states can the substance exist on the surface of Earth at sea level (open to the atmosphere)?

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Due to changes in temperature and pressure, the substance can exist either as a solid or a gas.

Given The triple point temperature is, (T) = 17 ∘C

The pressure of substance at triple point (P) = 3.2atm

The triple point is the temperature at which a certain substance can exist in all three of its major forms (solid, liquid and gas). Generally speaking, there are three stages of states that can be used to classify the states of matter. At sea level, we will experience conditions with a pressure of 1 atm and a temperature of 25∘C. At the sea level surface of the Earth, the triple point temperature is exceeded and the pressure decreases. The material can therefore exist in both the solid and gas phases. As a result, we can draw the conclusion that the substance can exist in both a solid and a gaseous state due to temperature and pressure variations.

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consider the energy consumed by a 300 w light bulb in an hour. how many flights of stairs would you have to climb to equal the work of the lightbulb?

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The number of flights of stairs you would have to climb to equal the work of the lightbulb in this time is approximately 589 stairs.

Given that,

Mass = 88 kg

Height of stairs = 2.1 meters.

Power = 300 Watt

Time = 1 hour

To calculate how many flights of stairs you would need to travel to accomplish the same amount of work as the lightbulb in this period of time:

First, we would figure out how much effort is required to ascend a set of steps that is 2.1 metres high.

Work done, mathematically, is given as,

W = m g h = 88 × 10 × 2.1 = 1848 J

Energy is given by, E = power × time

E = 300 × 3600 = 1080000 J

We can now determine how many flights of stairs you would need to climb to accomplish the same amount of work as the lightbulb in this period:

Flights = Energy/work done = 1080000/1848 = 588.41 ≈ 589 stairs

The given question is incomplete. The complete question is 'Assume your mass if 88 kg and the acceleration of gravity is 10 m/s². How much work do you do against gravity when you climb a flight of stairs that is 2.1 meters high?'

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how many decibels are emitted from a jet plane with a sounf intensity of 8.5*10^2 watts per square meter

Answers

The jet plane emits 149 914 decibels at 8.2 .

What is the jet plane?

 The Principal Differences. The key difference between a jet and an airplane is that to be a jet, a plane has to have a jet engine. Essentially, every jet is an airplane but not every airplane is a jet. A jet engine could either be a turbojet or turbofan, while a non-jet engine is usually a turboprop.A jet aircraft (or simply jet) is an aircraft (nearly always a fixed-wing aircraft) propelled by jet engines.While the typical VLJ and light jet carry a maximum of six passengers, a mid-size business jet offers comfortable seating for up to 10 passengers.A Jet aircraft flies much faster at higher altitudes, as high as 33,000–49,000 ft, than a propeller-powered aircraft. The Jet engine consists of an engine with a rotary air compressor powered by a turbine, with the leftover power providing thrust via a propelling nozzle.

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20N , 5m
2. If the crate does not move, does Ignacio perform any work? Does he use any
power? Explain.
th
probl
Study the illustration above, and then answer the following questions on a separate
sheet of paper.
1. Ignacio is trying to move this crate. What are the two equations you can use to
calculate the power Ignacio must use to move the crate?
3. What else do you need to know to find the power Ignacio uses when he moves
the crate?
4. Ignacio moves the crate in 10 s. How much power, in watts, does he use?
5. Carolina moves the crate in 5 s. How much power, in joules per second, does
she use?
6. Felix moves the crate twice as far as Ignacio and Carolina in 5 s. How much
power, in watts, does he use?

Answers

The quantity of internal and mechanical energy that things contain fluctuates as a result of work.

How can you tell if someone is working on something or not?Example of a Work, An item must be subjected to a force and move in the direction of the force in order for work to be done on it.The quantity of internal and mechanical energy that things contain fluctuates as a result of work. Energy is contributed to a system or an item when work is done on it. A system or item transfers part of its energy to something else when it does work. When a ball is thrown, a hand exerts force while an arm swings forward.

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can you receive a shock severe enough to prevent you from releasing the wire from an ordinary outlet with dry hands?

Answers

It is possible to receive a severe electrical shock from an ordinary outlet that would prevent a person from releasing the wire with dry hands, but it is not likely.

What are the factors to judge the severity of an electrical shock?

The severity of an electrical shock depends on several factors, including the amount of current flowing through the body, the duration of the shock, and the path the current takes through the body. In most cases, a person would be able to release the wire from an outlet even if they received a shock. However, it is important to note that any electrical shock can be dangerous and should be avoided.

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while playing ulimate frisbee you run north for 10 m, then eas for 30 m, adn finally 34 m in a direction 37 degrees south of east. what is your total displacememnt (magnitude and direction) during this run?

Answers

The total displacement is 48m in a direction 30° south of east.

What is total displacement?

Total displacement is the vector sum of all individual displacements that an object has undergone during a certain period of time.

To calculate this, we first need to calculate the displacement when running north for 10m. That would be 10m in a direction of 0° (due north).
Next, when running east for 30m, the displacement would be 30m in a direction of 90° (due east).
Finally, when running in a direction 37° south of east for 34m, the displacement would be 34m in a direction of 37° south of east.
Now to calculate the total displacement, we need to add the vector components of each of these three displacement vectors together.
The x component of the total displacement is 10m + 30m + (34m * cos(37°)) = 48m.
The y component of the total displacement is 0m + 0m + (34m * sin(37°)) = 31m.
Using the Pythagorean theorem, we can calculate the magnitude of the displacement vector to be sqrt(48^2 + 31^2) = 59.48m.
To calculate the direction of the displacement vector, we can use the inverse tangent function, arctan(31/48) = 30.14°.
Therefore, the total displacement is 48m in a direction 30° south of east.

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A 0. 6 kg basketball is thrown straight up at a velocity of 4 m/s. What is the initial kinetic energy of the basketball?

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The initial kinetic energy of the basketball is 8 J.

What do you mean by Kinetic Energy?

Kinetic energy is the energy an object possesses due to its motion. Kinetic energy is proportional to the square of an object's velocity and is expressed as KE = 0.5 * m * v^2, where m is the mass of the object and v is its velocity. Kinetic energy is a scalar quantity, meaning it only has magnitude and not direction. When an object slows down or comes to rest, its kinetic energy is converted into other forms of energy, such as heat or potential energy. Kinetic energy is a crucial concept in the fields of mechanics, thermodynamics, and other branches of physics.

The initial kinetic energy of the basketball can be found using the formula:

KE = 1/2 * m * v^2, where m is the mass of the object and v is its velocity.

For the 0.6 kg basketball with a velocity of 4 m/s, the initial kinetic energy is:

KE = 1/2 * 0.6 kg * (4 m/s)^2

KE = 8 J

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To determine the density of a piece of glass, a forensic technician places the glass in a liquid with a density of 2. 1 g/mL. The glass sinks. What should the technician do now?


a. Record that the density is greater than 2. 1 g/mL and stop the analysis.


b. Add a liquid with a density less than 2. 1 g/mL until the glass begins to float.


c. Add a liquid with a density greater than 2. 1 g/mL until the glass begins to float.


d. Record that the density is less than 2. 1 g/mL and stop the analysis

Answers

The technician can either note that the density is more than 2.1 g/mL and halt the analysis, or he can add more liquid until the glass starts to float.

The density of a material is an indicator of how heavy it is in relation to its size. An object will float when submerged in water if its density is lower than that of the water, while sinking if its density is higher. A differentiating characteristic that is unrelated to a substance's volume is its density. By suspending a glass sample in a liquid solution, one can calculate the density of an unknown glass sample. The density of the liquid is then determined, either directly or by comparison with a glass sample.

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will wants to allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv. which window treatments will achieve this result?

Answers

Blinds window treatments will allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv.

Even additional light will enter through the open window, further illuminating the space. You should think about some strategic lighting solutions for dark spaces in addition to trying to increase any available natural light.

East and west-facing windows frequently receive excessive sunlight, exposing these rooms to the sun at its hottest part of the day. The warmth in the room rises due to the sun's glare through these windows, which might make it difficult to read or watch television.

According to Lowe's, temporary heat-control window film should be used to cover windows that face south and west in order to reduce glare from the sun. This film is specifically created to prevent UV sun rays while yet allowing allowing some daylight to enter.

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what is the minimum hose diameter of an ideal vacuum cleaner that could lift a 11 kg dog off the floor?

Answers

4 cm hose diameter required of an ideal vacuum cleaner that could lift a 11 kg dog off the floor.

How to measuring a Hoses Diameter?

The internal diameter of your hose is the measurement across its width. There are two simple methods for measuring this.

Take a ruler to your hose and measure across the interior if you want it to be the same size as what you now have. Alternately, place a paper tube inside the aperture and measure across it.

You might try see if the spray attachment's existing type of fitting would accept that size. It never hurts to double-check, but most fitting like a 1 quick-connect coupler are universal.

What are Different Diameter Sizes Of Garden Hoses?

The 5/8 diameter is the most prevalent size. It is a generally suitable size for your yard. The flow is also stronger. Using attachments like a hose nozzle, you want to manage that flow. In particular, if you have to lay it down while watering, you don't want to flood your yard. Additionally, it's perfect for filling up the kiddie pool or keeping an eye on your car. It is an excellent all-purpose hose.

Additionally, you'll discover that many hoses with diameters of 3/4 and 1/2 inches, which are slightly smaller than the 5/8 size, will also function well and are great for baskets and container plants. It enables a lovely trickle of water without endangering your sensitive plants.

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if half of the weight of a flatbed truck is supported by its two drive wheels, what is the maximum acceleration (in m/s2) it can achieve on wet concrete where the coefficient of kinetic friction is 0.5 and the coefficient of static friction is 0.7.

Answers

The maximum acceleration that the flatbed truck can achive on wet concrete is 5[tex]m/s^{2}[/tex]

The maximum acceleration a truck can achieve on wet concrete is determined by the coefficient of friction between the two drive wheels and the surface.

Taking into account the coefficients of static and kinetic friction between the drive wheels and a wet concrete surface—0.7 and 0.5, respectively—the maximum acceleration of a truck with half its weight supported by its two drive wheels can be calculated using Newton's Second Law of Motion.

According to Newton's Second Law, F = ma, where F is force, m is mass and a is acceleration.

Since the truck has half its weight supported by its two drive wheels, we know that F = 0.5 mg (where m is mass and g is gravitational acceleration). Thus, when solving for a (acceleration), we have:

a = F/m

 = 0.5mg/m

 = 0.5g

 = 4.9 [tex]m/s^{2}[/tex] ≈ 5 [tex]m/s^{2}[/tex]

This means that on wet concrete with coefficients of static friction and kinetic friction at 0.7 and 0.5 respectively, the maximum acceleration a truck with half its weight supported by its two driving wheels can achieve is 5 [tex]m/s^{2}[/tex].

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What simple machine did you find the most useful in everyday life? Explain why. ​

Answers

Simple machines are advantageous because they lessen labor requirements or enable people to undertake things that would otherwise be beyond their capacity.

What six simple machines can you recall?

The airplane, wedge, screw, lever, pulley, and wheel-and-axle are the six most typical simple machines. They are made to change the direction or strength of the force (remember that work is equal to force times distance), which makes the task easier to complete.

Which basic machines are the most popular ones?

Simple machines including the axle, wheel and axle, pulleys, inclined plane, screw, wedge, and lever are frequently utilized. Although simple machines may increase or decrease the forces which can be applied on them, they have no effect on the overall amount of work required to complete the activity.

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a cubical gaussian surface surrounds two charges q1 6.8 10 12 c and q2 2.0 10 12 c as the drawing shows what is the electric flux passing through the surface how do i get the answer as 0.54 n m 2 c a see answer

Answers

For the given statement the Electric flux through the surface is 0.54 N m 2 /C.

Note: we are considering the distance between two charges to be 0.1 m

Electric flux in electromagnetism is a measurement of the electric field passing through a certain surface. The SI unit for the scalar quantity known as electric flux is newton-meters squared per coulomb (N m 2 /C). N · m 2 /C )

The electric flux passing through a surface can be calculated using the equation:

Φ = E * A = (k * q1 + k * q2) / r^2 * A

k = Coulomb's constant = 8.99 x 10^9 N * m^2 / C^2

r = distance between the charges = 0.1 m

A = surface area = 0.1 m * 0.1 m = 0.01 m^2

Now if we calculate:

Φ = (k * q1 + k * q2) / r^2 * A =  [(0.01 m^2)]* [(8.99 x 10^9 N * m^2 / C^2) *( 6.8 x 10^-12 C)] + [(8.99 x 10^9 N * m^2 / C^2) * (2 x 10^-12 C)] / (0.1 m)^2 = 0.54 N * m^2 / C.

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A pipe discharges storm water into a creek. Water flows horizontally out of the pipe at 1.9 m/s, and the end of the pipe is 3.1 m above the creek.

How far out from the end of the pipe is the point where the stream of water meets the creek?

Answers

The  distance from the end of the pipe is the point where the stream of water meets the creek is 1.52 m.

What is the time taken for the water to flow?

The time taken for the water to fall from the given height is calculated as follows;

t = √ ( 2h / g )

where;

g is acceleration due to gravityh is the height of fall

t =  √ ( 2 x 3.1 / 9.8 )

t = 0.8 s

The horizontal distance travelled by the stream of water is calculated as;

x = vt

x = 1.9 m/s  x 0.8 s

x = 1.52 m

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a certain voltage source provides a constant 6v. the circuit connected to the source draws an exponentially decaying current from the source given by ma, for , where 749ma and 67ms. assuming that for , at what point in time has the source provided 46mj of energy? express your answer in units of ms (milli-seconds).

Answers

At a certain time, by performing the given steps of calculation with appropriate values one can find the point of time at 46mj energy.

To find the point in time at which the source has provided 46mJ of energy, we need to integrate the current over time and set it equal to 46mJ.

The current as a function of time is given by:

i(t) = 749mA * e^(-t/67ms)

The energy provided by the source is given by the integral of the current with respect to time.

E = ∫i(t) dt

To solve the integral, we can use the power rule of integration:

∫e^(ax) dx = e^(ax) / a + C

By substituting the values in the above equation we can get the time at which the source provided 46mJ of energy.

E = ∫(749mA * e^(-t/67ms)) dt

E = 749mA * (e^(-t/67ms) / (-1/67ms)) + C

E = 749mA * (-67ms * e^(-t/67ms)) + C

Solving for t we get t = 67ms * ln(46mJ/(749mA * 67ms))

Therefore, at t = 67ms * ln(46mJ/(749mA * 67ms)) the source has provided 46mJ of energy.

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orbitwheels are a cross between a skateboard and pair of inline skates. riders insert each foot in a large wheel that rotates sideways. orbitwheels differ from a skateboard in that they are self-propelled by the rider's wave-like motion so the need to push off the ground every few feet to get moving is eliminated. the product has been popular among some kids, especially athletic teen boys. athletic teen boys could be described as the

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The sporty teen males here represent a subset of the overall market for skates, which is distinct from the tangential market. Target market is the appropriate response.

What is Target Market ?

The goal of mass marketing is to use the same marketing mix to sell to as many people as possible. In light of this, a mass market is defined as having a sizable number of consumers and is handled as a homogenous aggregate, disregarding segmentation differences. Market aggregation also refers to mass marketing, which involves the sale of standardised commodities to a broad audience. However, the target market also contains a specific market segment or segments on which the product is focused, and the market mix was created to meet the needs of consumers in these categories. In this instance, the target market for the product, for whom the business should create the marketing mix, is sporty teen boys who enjoy using Orbit wheels.

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How do microorganisms work as decomposers in an ecosystem

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Answer:

they eat what is decomposing speeding up the decomposition

What is the net work required to slow down a 5,020kg car from 41.0m/s to 21.0m/s?
a. Wnet = 6.22 · 106J
b. Wnet = 5.02 · 104J
c. Wnet = -3.11· 106J
d. Wnet =-9.85 · 105J

Answers

The net work that has been done is obtained as  5.02 * 10^4J. Option B

What is the net work that is required?

We have to note that the work that is done is defined as the product of the force that has been applied and the acceleration of the object. In this case ,we can see that there is work that has been done as the velolcity of the object is changed.

Hence;

Work done = 1/2mΔv^2

m = mass of the object

v = velocity of the object

Thus;

Work done = 0.5 * 5020 * (21 - 41)^2

Work done =  5.02 * 10^4J

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a meter stick is supported at each end by a spring scale. a heavy mass is then hung on the meter stick so that the spring scale on the left hand side reads four times the value of the spring scale on the right hand side. if the mass of the meter stick is negligible compared to the hanging mass, how far from the right hand side is the large mass hanging?

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The mass is dangling 4/5 of the length of the metre stick away from the right side if the mass of the metre stick is insignificant in comparison to the hanging mass.

The turning force on an item is measured by torque, which is computed by dividing the force by the separation from the pivot point.

Let's designate the forces on the left and right spring scales as F1 and F2, respectively.

F1 = 4F2, as we are aware.

The left side's torque is F1 * L, while the right side's torque is F2 * L (L is the distance from the right side).

Accordingly, F1 * L = F2 * L 4 F2 * L = F2 * L, the total torque on the left side must match the total torque on the right side.

It is evident that L = 4L/5.

In other words, the mass is dangling 4/5 of the way down the metre stick from the right side.

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a proton is placed in an electric field of intensity 801 n/c. what are the magnitude of the acceleration of the proton due to this field? (e

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When a proton is placed in an electric field of intensity 801 n/c, then the  magnitude of the acceleration of the proton is 7.7 x 10^9 m/s^2.

What is electric field?

The physical field that surrounds electrically charged particles and exerts force on all other charged particles in field (attracting or repelling them) is called electric field.

As we know, a = F/m

where F is force acting and m is its mass.

It is known that, q = 1.6 x 10^-19 C

F = Eq = 801 N/C * 1.6 x 10^-19 C = 1.28 x 10^-17 N

Mass of a proton is approximately 1.67 x 10^-27 kg.

Therefore, acceleration of the proton can be calculated as:

a = F/m = (1.28 x 10^-17 N) / (1.67 x 10^-27 kg) = 7.7 x 10^9 m/s^2

So, the magnitude of acceleration of the proton is 7.7 x 10^9 m/s^2.

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a gardener mows a lawn with a push mower. the handle of the mower makes an angle of 32 degrees. if a 209 n force is applied along the handle of the 18 kg mower, what is the normal force exerted on the mower?

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The normal force exerted on the mower is 290.8 N. The result is obtained by using the concept of Newton's first law.

What is Newton's first law?

Newton's first law states that every object will remain at rest or keep constantly moving in a straight line unless an external force acts upon it.

The equation of Newton's first law can be expressed as

∑F = 0

A gardener mows a lawn with a push mower with

Angle, θ = 32 degreesForce, F = 209 NMass = 18 kg

Find the normal force exerted on the mower?

We use g = 9.8 m/s².

See the illustration picture of forces directions in the attachment!

The direction of normal force is up. Using the Newton's first law, we will add parallel forces.

∑F = 0

Fn - F sin θ - W = 0

Fn = F sin θ + W

Fn = 209 sin 32° + 18 × 10

Fn = 209 (0.53) + 180

Fn ≈ 290.8 N

Hence, the mower will exert the normal force of 290.8 N.

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