A ray is a half-infinite line. The pairs of non-overlapping angles that share a ray to make a right angle are ∠FGE and ∠FGH.
Since, We know that;
A half-infinite line (also known as a half-line) with one of the two points and is commonly used to represent a ray. It is assumed to be infinite.
A straight line has an angle of measurement of 180°. And a 90° angle is made when two lines are perpendicular to each other.
As we can see the line EGH is a straight line, and FG is another line that is perpendicular to line EH,
Therefore, it will form two angles measuring 90°. These angles will be ∠FGE and ∠FGH.
Hence, the pairs of non-overlapping angles that share a ray to make a right angle are ∠FGE and ∠FGH.
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A pool measuring 10 meters by 20 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the pool and the path combined is 1200 square meters, what is the width of the path?
Answer:
The area of the pool is 10*20 = 200 square meters. Let's assume the width of the path is x. Then the dimensions of the entire region would be (10+2x) by (20+2x). The area of the entire region would be (10+2x)*(20+2x) = 400 + 60x + 4x^2. We know that the area of the pool and the path combined is 1200 square meters. So we can set up the equation as follows:
200 + 1200 = 400 + 60x + 4x^2
Simplifying the equation, we get:
4x^2 + 60x - 1000 = 0
Dividing both sides by 4, we get:
x^2 + 15x - 250 = 0
Factoring the equation, we get:
(x + 25)(x - 10) = 0
x = 10 or x = -25
Since the width of the path can't be negative, the width of the path is 10 meters.
Step-by-step explanation:
Mark Brainliest!!
Look at the transformation from the green triangle to the blue triangle
Draw and label the "Line of Reflection."
Describe the transformation from green triangle to blue triangle in words
The reflection from green triangle to blue triangle is a reflection over the x-axis
What is reflection over x-axis?Reflecting a two-dimensional shape over the x-axis is a geometric transformation that represents an image flipping or mirroring itself across the fixed x-axis.
This axis appears as the horizontal marker in a Cartesian coordinate system, providing the reference line to then split the plane into its top and bottom elements.
When which this action is fullfilled, all the y-coordinates of each point within the figure will be reversed while the x-coordinate remains unchanged;
The image of the reflection is attached and the reflection line labeled
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4. Find maximum/minimum / Inflection points for the function y = 5 sin x + 3x Show all work including your tests for max/min. (0 < x < 2phi )
The points of inflection are (0, 3π), (π, 4π), and (2π, 9π).
To find the maximum/minimum and inflection points of the function y = 5 sin x + 3x, we need to take the first and second derivatives of the function with respect to x, and then find the critical points and points of inflection by setting these derivatives equal to zero.
First derivative:
y' = 5 cos x + 3
Setting y' = 0 to find critical points:
5 cos x + 3 = 0
cos x = -3/5
Using a calculator or reference table, we can find the two values of x between 0 and 2π that satisfy this equation: x ≈ 2.300 and x ≈ 3.840.
Second derivative:
y'' = -5 sin x
At x = 2.300, y'' < 0, so we have a local maximum.
At x = 3.840, y'' > 0, so we have a local
To check whether these are global maxima/minima, we need to examine the behavior of the function near the endpoints of the interval 0 < x < 2π.
When x = 0, y = 0 + 0 = 0.
When x = 2π, y = 5 sin (2π) + 6π = 6π, since sin(2π) = 0.
So the function is increasing on the interval [0, 2.300], reaches a local maximum at x = 2.300, is decreasing on the interval [2.300, 3.840], reaches a local minimum at x = 3.840, and then is increasing on the interval [3.840, 2π]. Therefore, the maximum value of the function occurs at x = 2π, where y = 6π, and the minimum value of the function occurs at x = 3.840, where y ≈ 1.221.
To find the points of inflection, we set y'' = 0:
-5 sin x = 0
This equation is satisfied when x = 0, π, and 2π. We can use the second derivative test to determine whether these are points of inflection or not.
At x = 0, y'' = 0, so we need to examine the behavior of the function near x = 0.
When x is close to 0 from the right, y is positive and increasing, so we have a point of inflection at x = 0.
At x = π, y'' = 0, so we need to examine the behavior of the function near x = π.
When x is close to π from the left, y is negative and decreasing, so we have a point of inflection at x = π.
At x = 2π, y'' = 0, so we need to examine the behavior of the function near x = 2π.
When x is close to 2π from the right, y is positive and increasing, so we have a point of inflection at x = 2π.
Therefore, the points of inflection are (0, 3π), (π, 4π), and (2π, 9π).
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I NEED HELP ASAP
BRAINIEST WILL GET 10 POINTS!!!
PLEASE ITS DUE IN MINUTS
Answer:
1) 4 pounds / $5.48 = .73 pounds / dollar
2) 5 pounds / $4.85 = 1.03 pounds / dollar
3) $3.51 / 3 pounds = $1.17 / pound
4) $9.12 / 6 pounds = $1.52 / pound
There are 60 seats on a train. 35% of the seats are empty. How many empty seats are there on the train?
Answer:
21
Step-by-step explanation:
35% of 60=60% of 35
10% of 35=3.5
3.5*6=21
At a construction site, the brace used to retain a wall is 9.6 m in length. The distance from the wall to the lower end of the brace (on the ground) is 5.3 m. Calculate the angle at which the brace meets the wall.
The angle at which the brace meets the wall is approximately 56.51 degrees.
To calculate the angle at which the brace meets the wall at a construction site, we can use the right triangle trigonometry. Here, the brace is the hypotenuse of a right-angled triangle, with the distance from the wall to the lower end of the brace being one of the legs. We will use these terms: construction, brace, and angle in our explanation.
Step 1: Identify the given measurements
- Length of the brace (hypotenuse) = 9.6 m
- Distance from the wall to the lower end of the brace (adjacent leg) = 5.3 m
Step 2: Use the cosine function to find the angle
cos(angle) = adjacent leg / hypotenuse
cos(angle) = 5.3 m / 9.6 m
Step 3: Calculate the angle using the inverse cosine function
angle = cos^(-1)(5.3 m / 9.6 m)
Step 4: Find the angle using a calculator
angle ≈ cos^(-1)(0.5521) ≈ 56.51°
So, at the construction site, the angle at which the brace meets the wall is approximately 56.51 degrees.
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11. Solve the following inequality Express your answer in interval notation. 2x - 75 5x + 2
The answer for the following inequality expressed in interval notation is (-77/3, infinity)
To solve the inequality 2x - 75 < 5x + 2,
we need to isolate the variable x on one side of the inequality sign.
Starting with 2x - 75 < 5x + 2:
Subtracting 2x from both sides:
-75 < 3x + 2
Subtracting 2 from both sides:
-77 < 3x
Dividing both sides by 3 (and flipping the inequality sign because we are dividing by a negative number):
x > -77/3
So the solution to the inequality is x > -77/3.
Expressing this in interval notation, we have:
(-77/3, infinity)
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Helppp (Fill in all the blanks)
The answers are explained in the solution.
Given is a circle F,
The central angle = ∠GFH
The semicircle = arc GJI
The major arc = arc GJH
Since, the measure of semicircle is 180°, therefore,
The semicircle = arc GJI = 180°
We know that the measure of arc intercepted by the central angle is equal to the measure of the central angle.
Therefore, ∠GFH = 125°
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A particular fruit's weights are normally distributed, with a mean of 753 grams and a standard deviation of 9 prams if you pick 3 fruits at random, then of the time, their mean weight will be greater than how many grams? Give your answer to the nearest grami.
If you pick 3 fruits at random, the mean weight will be greater than 757 grams approximately 1.26% of the time.
To solve this problem, we need to use the properties of the normal distribution. We know that the weights of the fruit are normally distributed with a mean of 753 grams and a standard deviation of 9 grams.
The mean of the sample of 3 fruits will also be normally distributed with a mean of 753 grams and a standard deviation of 3 grams (since we are dividing by the square root of the sample size).
To find the probability that the mean weight of the sample of 3 fruits will be greater than a certain amount, we need to convert this amount to a z-score using the formula:
z = (x - μ) / (σ / √n)
where x is the amount we are interested in, μ is the mean, σ is the standard deviation, and n is the sample size (in this case, 3).
In this case, we want to find the z-score for a mean weight of 757 grams:
[tex]z = \frac{(757 - 753)}{\frac{9}{\sqrt{3}} }} =1.26[/tex]
We can use a standard normal distribution table or calculator to find that the probability of getting a z-score greater than 1.26 is approximately 0.0985, or 9.85%. However, since we are interested in the probability that the mean weight will be greater than 757 grams (not just greater than the mean), we need to add half of the probability of getting exactly 757 grams (which is the mode of the distribution) to this value.
Since the normal distribution is symmetrical, the probability of getting exactly 757 grams is the same as the probability of getting exactly 749 grams (which is the mean minus one standard deviation). Using the same formula as before, we can find the z-score for a weight of 749 grams:
z = \frac{(749 - 753)}{\frac{9}{\sqrt{3}} }} =-1.26[/tex]
The probability of getting a z-score less than -1.26 is also approximately 0.0985, so the probability of getting exactly 757 grams is approximately 0.197. Half of this value is 0.0985, which we add to the probability of getting a z-score greater than 1.26 to get the final answer:
0.0985 + 0.0985 = 0.197
So the probability of getting a mean weight greater than 757 grams is approximately 0.0985 + 0.197 = 0.2965, or 29.65%.
To convert this probability to weight, we can use a standard normal distribution table or calculator to find the z-score corresponding to a probability of 29.65%. This is approximately 0.56. Using the same formula as before, we can solve for x:
\frac{(x - 753)}{\frac{9}{\sqrt{3}} }} =0.56[/tex]
x ≈ 757.23
So if you pick 3 fruits at random, their mean weight will be greater than 757 grams approximately 1.26% of the time.
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Henry predicted whether he got answers right or wrong in his 50 question exam.
He identified the 31 questions he thought he got right.
It turns out that Henry got 6 questions wrong that he thought he got correct and he only got 12 of the questions wrong he had predicted.
What is the percentage accuracy he had with predicting his scores?
You started your day out with $120 in your bank account. You paid your electricity bill that was $67. Then, you went out with friends and spent $44 on your night out. On your way home, you stopped and purchased gas for $35. How much do you have to deposit into your bank account to not receive an overdraft fee?
You need to deposit at least $74 into your bank account to avoid an overdraft fee.
We have,
Start with the initial balance = $120
Subtract the first expense, the electricity bill = $120 - $67 = $53
Subtract the second expense, the night out with friends = $53 - $44 = $9
Subtract the third expense, the gas purchase = $9 - $35 = -$26
Now,
Since the remaining balance is negative, you would receive an overdraft fee if you left it at this amount.
To avoid the overdraft fee, you need to deposit enough money to bring your account balance back to $0 or higher.
To do this, you need to add the absolute value of the negative balance to your desired minimum balance, which in this case is:
$0 = |-26| + $0 = $26
Therefore,
You need to deposit at least $74 into your bank account to avoid an overdraft fee.
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Consider the equation y=2x²+4x+26.
Part A. Find the value of the discriminant. Show your work.
Part B. Based on the value of the discriminant found in part A, how many real roots does y=2x³+4x+26 have?
Part C. Use the quadratic formula to find the values of x when y-o. Show each step.
Answer:
A. 4^2 - 4(2)(26) = 16 - 208 = -192
B. This equation has no real roots.
C. (-4 + √-192)/(2×2) = (-4 + 8i√3)/4
= -1 + (2√3)i
1. A train 600 m long is running at the speed of 40 km/hr. Find the time taken by it to pass a man standing near the railway line. Not yet answered A 54 B. 10 sec C. 15 sec D. 10.5
The time taken by the train to pass the man is 54 seconds
To find the time taken by the train to pass a man standing near the railway line, we need to convert the train's speed to meters per second and then use the formula time = distance/speed.
1. Convert the speed of the train from km/hr to m/s: 40 km/hr * (1000 m/km) / (3600 s/hr) = 40000/3600 = 40/3.6 = 10/0.9 = 100/9 m/s.
2. Now, use the formula: time = distance/speed. The distance is the length of the train (600 m) and the speed is 100/9 m/s.
time = 600 m / (100/9 m/s) = 600 * 9 / 100 = 54 seconds.
Therefore, the time taken by the train to pass the man is 54 seconds (Option A).
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An artist recreated a famous painting using a 4:1 scale. The dimensions of the scaled painting are 8 inches by 10 inches. What are the dimensions of the actual painting?
40 inches by 50 inches
32 inches by 40 inches
12 inches by 14 inches
2 inches by 2.5 inches
Answer:
To find the dimensions of the actual painting, we need to use the scale factor of 4:1. This means that the actual dimensions of the painting are four times larger than the scaled dimensions.
Let's start with the width of the actual painting:
8 inches (scaled width) × 4 = 32 inches (actual width)
Now, let's find the height of the actual painting:
10 inches (scaled height) × 4 = 40 inches (actual height)
Therefore, the dimensions of the actual painting are 32 inches by 40 inches.
Using the following data, determine if the normal distribution gives a reasonable approximation: 71 42 77 84 46 93 94 63 82 88 57 32 79 67 68 83 60 65 58 70 Calculate the mean and standard deviation for these data using the appropriate equations. Compare these values to those you would get from the distribution line that you draw through the data by eye.
Hi, I'm glad to help you with this question. To determine if the normal distribution gives a reasonable approximation using the given data, we need to calculate the mean and standard deviation. Here are the steps:
1. Calculate the mean (average): Add all the data points together and divide by the number of data points.
(71+42+77+84+46+93+94+63+82+88+57+32+79+67+68+83+60+65+58+70) / 20 = 1380 / 20 = 69
Mean = 69
2. Calculate the standard deviation: First, find the difference between each data point and the mean, square the differences, and then find the average of those squared differences. Finally, take the square root of that average.
a. Differences from the mean: (-2, 27, 8, 15, -23, 24, 25, -6, 13, 19, -12, -37, 10, -2, -1, 14, -9, -4, -11, 1)
b. Squared differences: (4, 729, 64, 225, 529, 576, 625, 36, 169, 361, 144, 1369, 100, 4, 1, 196, 81, 16, 121, 1)
c. Average of squared differences: (4520) / 20 = 226
d. Square root of the average: √226 ≈ 15.03
Standard Deviation ≈ 15.03
Now that we have the mean (69) and the standard deviation (15.03), you can compare these values to the distribution line that you draw through the data by eye. If the distribution line follows a bell-shaped curve with the mean at the center and the data points spread around it following the standard deviation, then the normal distribution provides a reasonable approximation for this data set.
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Find the exact value of the expressions (a) sec
sin−1 12
13
and (b) tan
sin−1 12
13
On solving this trigonometry, we find that (a) sec(sin⁻¹ [tex]\frac{12}{13}[/tex]) = [tex]\frac{13}{5}[/tex] and (b) tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) = [tex]\frac{12}{5}[/tex]
(a) To find the exact value of sec(sin⁻¹ [tex]\frac{12}{13}[/tex]), we can use the fact that sec(x) = [tex]\frac{1}{cos}[/tex](x). Let's draw a right triangle with opposite side 12 and hypotenuse 13. Using the Pythagorean theorem, we can find the adjacent side:
a² + b² = c²
a² + 12² = 13²
a² = 169 - 144
a = √25
a = 5
So our triangle has sides of length 5, 12, and 13. Now we can find cos(sin⁻¹ [tex]\frac{12}{13}[/tex]) by looking at the adjacent/hypotenuse ratio in this triangle:
cos(sin⁻¹ [tex]\frac{12}{13}[/tex]) = [tex]\frac{5}{13}[/tex]
Therefore, sec(sin⁻¹(12/13)) = 1/cos(sin⁻¹ [tex]\frac{12}{13}[/tex])
= 1/[tex]\frac{5}{13}[/tex]
= [tex]\frac{13}{5}[/tex].
So the exact value of sec(sin⁻¹ [tex]\frac{12}{13}[/tex]) is [tex]\frac{13}{5}[/tex].
(b) To find the exact value of tan(sin⁻¹ [tex]\frac{12}{13}[/tex]), we can use the fact that tan(x) = sin(x)/cos(x). Let's use the same right triangle as before.
Then sin(sin⁻¹ [tex]\frac{12}{13}[/tex])= [tex]\frac{12}{13}[/tex] and cos [tex]\frac{12}{13}[/tex]) = [tex]\frac{5}{13}[/tex] , so
tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) = sin(sin⁻¹ [tex]\frac{12}{13}[/tex])/cos(sin⁻¹[tex]\frac{12}{13}[/tex])
= [tex]\frac{12}{13}[/tex] / [tex]\frac{5}{3}[/tex]
= [tex]\frac{12}{5}[/tex]
So the exact value of tan(sin⁻¹ [tex]\frac{12}{13}[/tex]) is [tex]\frac{12}{5}[/tex].
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2,8km a m:
27,55dm a m:
27,9hm a m:
275dam a m:
The conversions are :
a) 2.8 km = 2800 m.
b) 27.55 dm = 2.755 m.
c) 27.9 hm = 2790 m.
d) 275 dam = 2750 m.
What is the conversion about?By multiplying the value by 1000 will help us to change kilometers (km) to meters (m). In order to change decimeters into meters, it is necessary to divide the figure by 10.
To convert, Note that:
km = kilometers m = meters,d= decimetershm = hectometersdam =decameters
a) 2.8 km to m:
= 2.8 x 1000 m
= 2800 m
b) 27.55 dm to m:
= 27.55 ÷ 10 m
= 2.755 m
c) 27.9 hm to m:
= 27.9 x 100 m
= 2790 m
d) 275 dam to m:
= 275 x 10 m
= 2750 m
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Convert the following to meter
2,8km
27,55dm
27,9hm
275dam
You are going to cut a circle out of the triangle piece of wood below how much wood will be left over after you cut the circle if the base is six the height is five
Answer:
6.03
Step-by-step explanation:
In math terms, we can model the area left when cutting a circle out of a triangle as subtracting the area of a circle inscribed in a triangle.
There was only one side length of the triangle given (its base), so we can assume that it is an isosceles triangle with the given height.
To find the radius of the triangle, we can use the formula:
r = (A / s)
where r is the radius of the inscribed circle, A is the area of the triangle, and s is the semiperimeter (half-perimeter) of the triangle.
Finding the area of the triangle:
A = (1/2) * b * h
A = (1/2) * 6 * 5
A = 15
Finding the length of the congruent sides of the triangle:
[tex]a^2 + b^2 = c^2[/tex]
[tex]c^2 = 5^2 + 3^2[/tex]
[tex]c^2 = 34[/tex]
[tex]c \approx 5.83[/tex]
Finding the semiperimeter:
s = (side1 + side2 + side3) / 2
s = (5.83 + 5.83 + 6) / 2
s ≈ 8.83
Plugging these values into the radius formula:
r = A / s
r = 15 / 8.83
r ≈ 1.69
From here, we can get the area of the circle cutout:
A(circle) = πr²
A(circle) = π(1.69)²
A(circle) ≈ 8.97
Finally, we can get the leftover area by subtracting the area of the circle from the area of the triangle:
A = A(triangle) - A(circle)
A = 15 - 8.97
A = 6.03
Given the linear inequality graph, which two statements are true? A) Point (8, 3) is a solution. B) The graph represents y < − 1 3 x + 5. C) The graph represents y ≤ 3x + 5. D) All points in the blue area are solutions. E) All points above the broken line are solutions.
Given the linear inequality graph, which two statements are true include the following:
B) The graph represents y < −1/3(x) + 5.
D) All points in the blue area are solutions.
How to determine an equation of this line?In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):
y - y₁ = m(x - x₁)
Where:
x and y represent the data points.m represent the slope.First of all, we would determine the slope of this line;
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Slope (m) = (4 - 7)/(3 + 6)
Slope (m) = -3/9
Slope (m) = -1/3
At data point (3, 4) and a slope of -1/3, a linear equation for this line can be calculated by using the point-slope form as follows:
y - y₁ = m(x - x₁)
y - 4 = -1/3(x - 3)
y - 4 = x/3 + 1
y = x/3 + 5
y < x/3 + 5
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Missing information:
The question is incomplete and the complete question is shown in the attached picture.
find the equation of P
The equation of circle P include the following: D. x² + (y - 3)² = 4
What is the equation of a circle?In Mathematics and Geometry, the standard form of the equation of a circle is represented by the following mathematical equation;
(x - h)² + (y - k)² = r²
Where:
h and k represents the coordinates at the center of a circle.r represents the radius of a circle.By critically observing the graph of this circle, we have the following parameters:
Radius, r = 2 units.Center, (h, k) = (0, 3).By substituting the given parameters into the equation of a circle formula, we have the following;
(x - h)² + (y - k)² = r²
(x - 0)² + (y - 3)² = 2²
x² + (y - 3)² = 4.
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Five students enter a school talent competition the scatter plot shows the number of hours each student has rehearsed and the score of the students Calculate the balance point of the data
The balance point of the data, given the number of hours rehearsed and the score would be (5, 50).
How to find the balance point ?The balance point on the graph is simply the average of the x vertices and the y vertices.
The average of the x vertices is:
= ( 1 + 3 + 4 + 8 + 9 ) / 5
= 25 / 5
= 5
The average of the y vertices is:
= ( 30 + 50 + 20 + 90 + 60 ) / 5
= 250 / 5
= 50
This then means that the balance point would be ( 5, 50 ).
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Solve each system by using elementary row operations on the equations or on the augmented matrix. Follow the systematic elimination procedure described in this section.
2x 1+4x 2=−4 5x1+7x 2=11
The solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].
To solve the system, we can use the method of elimination or Gaussian elimination.
We start by writing the system in augmented matrix form:
[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5 & 7 & 11\end{array}\right]$$[/tex]
We can eliminate the [tex]$\$ x_{-} 1 \$$[/tex] variable from the second equation by subtracting 5 times the first equation from the second:
[tex]$$\left[\begin{array}{cc|c}2 & 4 & -4 \\5-5(2) & 7-5(4) & 11-5(-4)\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}2 & 4 & -4 \\-3 & -13 & 31\end{array}\right]$$[/tex]
Next, we can eliminate the [tex]$\$ x_{-} 2 \$[/tex]$ variable from the first equation by subtracting twice the second equation from the first:
[tex]$$\left[\begin{array}{cc|c}2-2(-13) & 4-2(7) & -4-2(31) \\-3 & -13 & 31\end{array}\right] \Rightarrow\left[\begin{array}{cc|c}28 & -10 & -66 \\-3 & -13 & 31\end{array}\right]$$[/tex]
We can simplify this further by dividing the first row by 2 :
[tex]$$\left[\begin{array}{cc|c}14 & -5 & -33 \\-3 & -13 & 31\end{array}\right]$$[/tex]
Now we can solve for [tex]$\$ x_{-} 2 \$$[/tex] in terms of [tex]$\$ x_{-} 1 \$$[/tex] by multiplying the first equation by 13 and adding it to the second equation:
[tex]$$13(14) x_1-13(5) x_2-13(33)-3(-13) x_1-3(-13) x_2=13(31)-3(14) x_1$$[/tex]
Simplifying:
[tex]$$\begin{aligned}& 169 x_1-91 x_2-429+39 x_1+39 x_2=403 \\& 208 x_1=832 \\& x_1=4\end{aligned}$$[/tex]
Substituting back into the first equation, we get:
[tex]$$2(4)+4 x_2=-4 \Rightarrow x_2=-3$$[/tex]
Therefore, the solution to the system is [tex]$\$\left(x_{-} 1, x_{-} 2\right)=(4,-3) \$$[/tex].
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Plane A has just 1 ton of fuel left and has requested plane B to refuel it. Plane B has 21 tons of fuel. Fuel transfer happens at the rate of 1 ton per minute. Use this information as you work through the activity and find how long it will take to refuel plane A until both planes have the same amount of fuel. Let x be the time in minutes and y be the amount of fuel in tons. The equation y = x + 1 represents the quantity of fuel with respect to time in plane A, and y = -x + 21 represents the quantity of fuel with respect to time in plane B. For each equation, find two points that satisfy the equation
The time for which plane B will take to refuel plane A is equals to 10 minutes. The two points who satisfy the equation, y = x + 1, are (0, 1), (-1,0). The two points who satisfy the equation, y = -x + 21, are (0,21), (21,0).
We have a fuel left in Plane A = 1 ton
fuel left in Plane B = 21 tons
Fuel transfer rate = 1 ton per minute
In order that for them to have the same amount of fuel, We add up the fuel left in Plane A and Plane B = 21 + 1 = 22 tons. This implies each plane will have fuel of 11 tons. Time that plane B will take to refuel plane A until both planes have the same amount of fuel is calculated by : Plane B will transfer 10 tons of fuel to A.
Plan A has a total of 11 tons. Since, the transfer rate = 1 ton per minute
=> 1 ton will transfer in 1 minute
So, 10 tons fuel will need 10 minutes. Hence, required time value is 10 minutes. Now, The equation for quantity of fuel with respect to time in plane A is, y = x + 1 --(1). If x = 0 => y = 1
and y = 0 => x = -1. So, (0, 1) and (-1,0).
The equation for quantity of fuel with respect to time in plane B is, y = -x + 21 --(2). For it, x = 0 => y = 21 and y= 0 => x = 21. Hence, two points that satisfy the equation(1) and equation(2) are (0, 1), (-1,0) and (0,21), (21,0) respectively.
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The chart below represents data collected from 10 eighth grade boys
showing their height in inches and their weight in pounds.
Height
(inches)
60 63 65 61 70 55 58 61 64 57
Weight
(pounds) 125 139 155 136 170 108 116 139 129 121
Which statement best describes the association between height and
weight of the ten boys?
A. The data shows a negative, linear association.
B. The data shows a positive, linear association.
C. The data shows a non-linear association.
D. The data shows no association.
B. The data shows a positive, linear association.
To determine the association between height and weight of the ten boys, we will first observe the data points provided. We can compare the increase or decrease in height with the corresponding increase or decrease in weight to identify a pattern.
Here's a list of height and weight pairs:
(60, 125), (63, 139), (65, 155), (61, 136), (70, 170), (55, 108), (58, 116), (61, 139), (64, 129), (57, 121)
Upon observing these pairs, we can see that as height increases, weight generally increases as well. For example, when height increases from 55 inches to 70 inches, weight increases from 108 pounds to 170 pounds. This pattern can also be seen in other data pairs.
This means that there is a direct relationship between the height and weight of the boys, where taller boys tend to weigh more, and shorter boys tend to weigh less.
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pls help me with Question B only
a. The nth term of the sequence is 11 - 3n.
b. The nth term of the sequence is 14- 5n.
How to find the nth term of a sequence?The sequence is an arithmetic progression. Therefore, the expression for the sequence can be represented as follows:
nth term = a + (n + 1)d
where
n = number of termsd = common differencea = first termTherefore,
a.
a = 8
d = 11 - 8 = - 3
Therefore,
nth term = 8 + (n - 1)-3
nth term = 8 - 3n + 3
nth term = 11 - 3n
b.
a = 19
d = 14 - 19 = -5
nth term = 19 + (n - 1)-5
nth term = 19 - 5n - 5
nth term = 14 - 5n
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Write a Variable equation for each sentence
Danika's new running route is 4 miles longer than
her old route.
Answer:
Let x be the length of Danika's old running route in miles.
Then, her new running route can be represented by x + 4, since it is 4 miles longer than her old route.
Step-by-step explanation:
Which of the following is NOT a factor of 4 x³ − 7x²+x+6?
-
Ox-1
OX-2
Ox+1
Ox+2
All of the expressions are not a factor of the polynomial function 4x³ − 7x²+x+6
Which is NOT a factor of the polynomial function?From the question, we have the following parameters that can be used in our computation:
The polynomial function 4x³ − 7x²+x+6
To check the expression that is not a factor, we set the expression to 0, solve for x and calculate the value of the polynomial at this x value
If the result is not zero (0), then it is not a factor of the polynomial
Using the above as a guide, we have the following:
x - 1 gives x = 1
So, we have
4(1)³ − 7(1)² + (1) + 6 = 4
x - 2 gives x = 2
So, we have
4(2)³ − 7(2)² + (2) + 6 = 12
x + 1 gives x = -1
So, we have
4(-1)³ − 7(-1)² + (-1) + 6 = -6
x + 2 gives x = -2
So, we have
4(-2)³ − 7(-2)² + (-2) + 6 = -56
None of the expressions give a solution of 0
Hence, all of the expressions are not a factor of the polynomial function
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eleanor robson regarding plimpton 322, she lists six criteria for interpreting ancient mathematical texts what are the 6 criteria
The 6 criteria are Internal consistency, Contextual consistency, Intelligibility, Mathematical plausibility, Historical plausibility and Replicability.
According to Eleanor Robson's interpretation of Plimpton 322, she lists six criteria for interpreting ancient mathematical texts. These six criteria are as follows:
1. Internal consistency: The mathematical text should be internally consistent and coherent in its logic.
2. Contextual consistency: The mathematical text should be consistent with the historical and cultural context in which it was written.
3. Intelligibility: The mathematical text should be understandable and intelligible to the intended audience.
4. Mathematical plausibility: The mathematical content of the text should be mathematically plausible and in line with known mathematical principles.
5. Historical plausibility: The mathematical text should be historically plausible and fit within the known historical context.
6. Replicability: The mathematical text should be replicable, meaning that other mathematicians should be able to reproduce the calculations and results presented in the text.
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Factor the expression, and use the factors to find the x-intercepts of the quadratic relationship it represents. Type the correct answer each box, starting with the intercept with the lower value The x- intercepts occur where x = and x =
The factors to the given expression are -1(x+3)(x-8)
The x-intercepts of the quadratic relationship are -3, 8. When we write an expression in its factors and multiplying those factors gives us the original expression, then this process is known as factorization.
How do we factorize the given expression?
We equate the given expression to f(x)
(-[tex]x^{2}[/tex] + 5x + 24) = f(x)
⇒ -1([tex]x^{2}[/tex] - 5x - 24) = f(x)
⇒ -1([tex]x^{2}[/tex] - (8-3)x - 24) = f(x)
⇒ -1([tex]x^{2}[/tex] + 3x - 8x -24) = f(x)
⇒ -1(x(x+3) -8(x+3)) = f(x)
⇒ -1(x+3)(x-8) = f(x)
∴The factor to the given expression is -1(x+3)(x-8)
How do we find the x-intercepts?
We equate f(x) = 0 to find the x-intercepts.
⇒ -1(x+3)(x-8) = 0
⇒ (x+3)(x-8) = 0
The roots of the above equation are x-intercepts.
Therefore, the x-intercepts occur where x = -3 and x = 8
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The complete question is "Factor the expression (-x^2 + 5x + 24.) and use the factors to find the x-intercepts of the quadratic relationship it represents.
Type the correct answer in each box, starting with the intercept with the lower value.
The x-intercepts occur where x =
and x = "
Which of the following is true regarding a regression model with multicollinearity, a high r2 value, and a low F-test significance level? a.The model is not a good prediction model. b.The high value of 2 is due to the multicollinearity. c.The interpretation of the coefficients is valuable. d.The significance level tests for the coefficients are not valid. e.The significance level for the F-test is not valid.
The correct answer is d. The significance level tests for the coefficients are not valid.
Multicollinearity is a statistical term that refers to the presence of high correlation among predictor variables in a regression model. This can cause issues in the model, such as unstable or unreliable coefficients, and can lead to incorrect conclusions about the relationships between the predictors and the response variable.
When multicollinearity is present, the R-squared value of the model can become inflated because the model is able to explain more of the variation in the response variable due to the high correlation among the predictor variables. This can give the impression that the model is a good predictor when in fact it may not be. Additionally, multicollinearity can cause the F-test significance level to be low, indicating that the model is a good fit, even though the individual coefficients may not be statistically significant.
Multicollinearity can cause inflated R-squared values and low F-test significance levels. However, it does not necessarily mean that the model is a poor predictor. The interpretation of coefficients may also be affected by multicollinearity.
However, the most significant issue with multicollinearity is that it can lead to unreliable significance tests for individual coefficients, making it difficult to determine which predictors are contributing significantly to the model.
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