The trend in the molar solubility of in different concentrations seen in the graph above appears to be best explained by the statement (a) "increasing concentrations of allow less to dissolve before the solution
The amount of a material present in a mixture or solution is referred to as its concentration. Different units, such as molarity (moles of solute per litre of solution), molality (moles of solute per kilogramme of solvent), or mass percentage, can be used to quantify them (mass of solute as a percentage of total mass). Concentrations play a key role in chemistry for predicting reaction behaviour and figuring out how much of a material to add to a solution. Concentrations are crucial in figuring out how various chemicals affect living things and the environment in sectors like environmental science and medicine.
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the enthalpy of the overall reaction represented above can be determined by adding the enthalpies of reactions 1 and 2. which of the following could be reaction 2 ?
Most probably the reaction 2 could be A: "( 2NO(g)+O2(g)→2NO2(g) )".
Reaction 2 is the second step of the overall reaction, which is the formation of NO2 from NO and O2. The overall reaction is (2O3(g)+2NO(g)→2NO2(g) + 2O2(g) ).
From the given options, the best match for reaction 2 is (NO(g) + O2(g) → 2NO2(g) ) because it is a balanced equation that forms 2 moles of NO2 from 1 mole of O2 and 1 m0le of NO. This is consistent with the balanced equation of the overall reaction, which forms 2 moles of NO2.
Option A: 2NO(g) + O2(g) → 2NO2(g) forms 2 moles of NO2 but it consumes 2 moles of NO which is not consistent with the overall reaction.
Option B: 5NO(g) + O2(g) → 3NO2(g) forms 3 moles of NO2 but it consumes 5 moles of NO, again this is not consistent with the overall reaction.
Option C: NO(g)+O2(g)→2NO2(g), it is a balanced equation that forms 2 moles of NO2 from 1 mole of O2 and 1 m0le of NO.
Therefore, based on the information provided, the correct option for reaction 2 is C: NO(g) + O2(g) → 2NO2(g)
"
Complete question
Reachtion 1 = (2O2(g)→3O2(g) ).
Reachtion 2 = ?
Overall recation = (2O3(g)+2NO(g)→2NO2(g) + 2O2(g) ).
the enthalpy of the overall reaction represented above can be determined by adding the enthalpies of reactions 1 and 2. which of the following could be reaction 2 ?
A: 2NO(g)+O2(g)→2NO2(g)
B: 5NO(g)+O2(g)→3NO2(g)
C: NO(g)+O2(g)→2NO2(g)
D: None
"
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would you expect the following compound to have a dipole moment? if the molecule has a dipole moment, specify its direction. select the single best answer.
The compound to have a dipole moment, the correct statement about the dipole moment is 4) The molecule has no dipole moment.
The molecule is CF₄, carbon tetrafluoride. The bond between the C - F is the polar covalent bond because of the greater electronegativity difference between the C and the F atoms. Even though it has no dipole moment because of the geometry that is tetrahedral geometry. The all the C - F bonds are arrange in such a manner that the dipole moment will cancel out each other.
Thus, the CF₄ molecule has no dipole moment. The molecule is the non - polar molecule.
This question is in complete , the complete question is :
Would you expect the following compound to have a dipole moment? if the molecule has a dipole moment, specify its direction. select the single best answer. CF₄
1) The dipole moment is oriented from the fluorine atom towards the carbon atom.
2) The dipole moment is oriented from the carbon atom towards the fluorine atom.
3) The orientation cannot be determined.
4) The molecule has no dipole moment.
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x consists of a flexible container with eight particles of a gas as shown. what happens to the pressure of the system when x is converted to the representations in (a), (b), and (c)?
When a gas is heated in a flexible container with constant pressure, the statement "The gas particles travel quicker" is accurate.
option (C)
The container's walls are struck more forcefully by the gas particles inside the container.
(a) Gas molecules lack a fixed form and a fixed volume. They grow till they fill their container. Gas molecules move readily both inside and outside of the container because they are fluid. Unless compressed, gas molecules are not very dense.
(b) Gas molecules mix and disperse as they diffuse and effuse (travel through small holes).
(c) The container's walls are struck more forcefully by the gas particles inside the container. The gas container's capacity expands as a result of the impact.
The gas container's capacity expands as a result of the impact. Gas molecule characteristics
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The complete question follows
x consists of a flexible container with eight particles of a gas as shown. what happens to the pressure of the system when x is converted to the representations in (a), (b), and (c)?
(a) pressure increased
(b) pressure decreased
(c) pressure is constant
In which of the following intermolecular interactions will polar molecules, such as water, commonly participate? (Mark all that apply A. Hydrogen bonding with non-polar molecules B. Hydrogen bonding with polar molecules C. Van der Waal interaction with polar molecules D. Electrostatic interaction with lonic compounds
B. Hydrogen bonding with polar molecules is the inter molecular interactions will water participate commonly with polar molecules.
Why does water pull polar molecules toward it?Polarity causes the water molecules to attract each other. Water is polar despite possessing a zero net charge because of the structure of its molecules. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are attracted to other polar molecules and to one another as a result.
What polar molecules are drawn to water?The polarity of water enables hydrogen bonds to form whenever adjacent water molecules are drawn to each other by their opposing charges. Other polar molecules and ions, such as many biomolecules including sugars, nucleic acids, and certain amino acids, are also attracted to or attracted by water.
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From the formula for calcium acetate,Ca(C2H3O2)2, calculatethe mass of carbon that can be obtained from 65.3 g of thecompound.
The mass of carbon that can be obtained from 65.3 g of the compound is 19.83 grams of carbon,
First, you should calculate the % of carbon in calcium acetate
% of carbon - (12.01 x 4)/(40.08+12.01 x 4+ 1.008 x 6+16x 4)
% of carbon-48.04/158.168 x 100%
% of carbon 30.37% In 65.3 g of compound,
there are 65.3 x 30.37% -19.83 grams of carbon.
What do you mean by compound?
A object created by joining several different elements or parts. Particularly: a separate substance created by the chemical fusion of two or more substances in a certain weight-to-volume ratio. a fresh antibiotic substance.
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define each of the following as atomic element, molecular element, ionic compound, or molecular compound. h2s [ select ] xe [ select ] br2 [ select ] cacl2 [ select ] i2 [ select ] al2s3 [ select ] pb [ select ] no2
Xe and Pb are atomic elements. I₂ and Br₂ are molecular elements. CaCl₂ and Al₂S₃ are ionic compounds and NO₂ and H₂S are molecular compounds.
Atomic elements are the elements which cannot be broken down further and combine together to form molecules. Among the substances given to us, Xenon (Xe) and Lead (Pb) can be categorised as atomic elements. Molecular elements are formed when the same elements combine with each other. I₂ and Br₂ are molecular elements.
Ionic compounds are consist of ions bound together. CaCl₂ and Al₂S₃ are ionic compounds. Molecular compounds are formed up of two or more elements and NO₂ and H₂S are molecular compounds.
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which of the following has the correct curved arrows placement to show resonance for the given allylic carbocation>
An allylic lone pair is the appropriate positioning for the curved arrows to indicate resonance for the specified allylic carbocation.
What is a carbocation and how does one create one?The carbocation is indeed an organic molecule that develops when two valence electrons, which are typically shared by two atoms of carbon, are lost from such a carbonyl group that already possesses four bonds. As a result, a carbon atom with three rather than four bonds and a positive charge is created.
What distinguishes a carbocation?All carbon atoms in carbocations, also referred to as carbonium ions, are positively charged. A ion is indeed a positive charge, and the "carbo" part of the term refers to an atom of carbon.
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What is the correct reading of the volume in the pictured buret? Make sure to report your reading with the appropriate significant figures. Select one: a. 39.9 mL b. 39.5 mL c. 40.0 mL d. 39.950 mL e. 39.95 mL f. 40.05 mL
The correct reading of the volume in the pictured burette is e) 39.95 mL. The picture is attached below.
The purpose of the burette reading is to show that how much the solution has been dispensed, not the how much the burette contains. As compared to the volumetric glassware, the zero scale on the burette is written on the top. The Measurement scale on the burette is at the 1.0 intervals.
The intervals can be calculated as :
Intervals = (larger value - small value) / 2
Intervals = 1
The reading will be 39.95 mL.
Thus, according to the picture of the burette, the reading of the burette is the 39.95 mL.
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Enter your answer in the provided box. Ammonium hydrogen sulfide decomposes according to the following reaction, for which Kp = 0.11 at 250°C: NH4HS(s) ⇌ H2S(g) + NH3(g) If 59.4 g of NH4HS(s) is placed in a sealed 5.0−L container, what is the partial pressure of NH3(g) at equilibrium? PNH3 = __________atm
The partial pressure of NH3(g) at equilibrium is 0.122 atm.
To calculate the partial pressure of NH3(g) at equilibrium, we can use the equilibrium constant expression (Kp = [H2S][NH3]/[NH4HS]). We know that Kp = 0.11 at 250°C and that the initial amount of NH4HS is 59.4 g. Since we also know the volume of the container is 5.0 L, we can use the ideal gas law (PV = nRT) to convert the number of moles of NH4HS to pressure.
First, we need to convert the mass of NH4HS to moles:
n = m/M = (59.4 g) / (51.11 g/mol) = 1.162 moles
Next, we can use the ideal gas law to find the pressure of NH4HS at the start of the reaction:
P = (nRT) / V = (1.162 mol)(0.0821 atm·L/mol·K)(523 K) / (5.0 L) = 9.98 atm
At equilibrium, the sum of the partial pressures of H2S and NH3 must equal 9.98 atm. Therefore, we can use the equilibrium constant expression to find the partial pressure of NH3:
Kp = [H2S][NH3]/[NH4HS] = 0.11
[NH4HS] = [H2S][NH3] / Kp = (P_H2S)(P_NH3) / 0.11
We know that P_NH4HS = 9.98 atm, so we can solve for P_NH3:
P_NH3 = [NH4HS] * Kp / [H2S] = 9.98 atm * 0.11 / P_H2S
Since we know that the sum of the partial pressures of H2S and NH3 must equal 9.98 atm, we can substitute that in for P_H2S:
P_NH3 = 9.98 atm * 0.11 / (9.98 atm - P_NH3)
Solving for P_NH3, we get P_NH3 = 0.122 atm
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T/F rf values should be kept in the range of 0.2 to 0.8 for the most effective separation when more than one compound is present in the sample.
The statement is true that rf values should be kept in the range of 0.2 to 0.8
Polar compoundsPolar will have higher Rf values than nonpolar compounds under the same developing conditions. Rf values should be kept in the range of 0.2 to 0.8 for the most effective separation when more than one compound is present in the sample. The less polar the solvent, the higher the Rf value.The fastest moving spot has the highest Rf value. polar (fastest moving), and the spot with the lowest polargo through the given link below to know more about rf values:-
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what is the formula of manganese which contains 50.48% oxygen? Ar (Mn) = 64.94
(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.
What is the empirical equation for a manganese oxide with a 49.5 manganese content?(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.The chemical having the formula MnO2 is known as manganese dioxide.By elemental manganese oxidation, When oxygen in the environment interacts with elemental manganese, MnO2 is the result. In nature, manganese is typically found as manganese dioxide since elemental manganese cannot exist due to this reaction.(Hint: Oxide is the result of combining Mn and O.) Mn (Mass of the element, in g) (assuming 100 g of compound) elements in moles The smallest moles or moles of an element Multiplier mathematical model O 1. 49.5 2. _50,5 3.To learn more about manganese dioxide refer to:
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A gas sample at a certain temperature has an initial volume of 5.345 L. What is the initial temperature of the sample if the volume and the temperature are changed to 4.345 L and 898.0 K, respectively? Assume that the pressure and the amount of the gas remain constant.
Answer:
1104 K
Explanation:
We can use Charles' Law: [tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]
Plugging in the numbers gives us the initial temperature to be 1104 K
Caroline knows the amount of a compound in moles.To find the number of molecules in the given sample of her compound, which of these values must also be used in her calculation? a. mass of the sample in grams b. Avogadro's numberc. Omolecular mass of the compound d. atomic mass of each element in the compound
Caroline knows the amount of a compound in moles.To find the number of molecules in the given sample of her compound, b. Avogadro's number also must be used in her calculation.
About Avogadro's numberAvogadro's constant or “Avogadro's number” (symbol: L, NA) is the number of constituent particles (usually atoms or molecules) found in the amount of substance in one mole. Therefore, Avogadro's number is a proportional factor relating the molar mass of a substance to the mass of the sample. This value is equal to 6.022 140 857 (62) × 1023 mol−1.
Previous definitions of chemical quantities involved Avogadro's number, a historical term closely related to Avogadro's constant but defined differently: it was originally defined by Jean Baptiste Perrin as the number of atoms in one mole of hydrogen. It was later redefined as the number of atoms in 12 grams of the carbon-12 isotope and then generalized to relate the number of substances to their molecular weight.
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Deduce the structure of a compound of molecular formula C4H9Br which exhibits the following 1H NMR spectrum.
The structure C₄H₉Br that is 2-bromo-2-methylpropane , exhibits the ¹H NMR is as follows :
CH₃
|
CH₃ - CH - CH₃
|
Br
In the 2-bromo-2-methylpropnae molecule, all the 9 protons has the same chemical environment and there no splitting of the ¹H NMR resonance. All the protons are chemically equivalent, and they will have the same resonance frequency in the NMR.
In the molecule , 9 protons of the 2-bromo-2-methylpropane, as all the hydrogen atoms are having the same chemical environment. In the the Chemical shift (a) of the 1.80 ppm on the ¹H NMR spectrum for the 2-bromo-2-methylpropane is present.
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Given the following balanced equation, determine the rate of reaction with respect to [O2]: 2O3 (g).....yields.....3O2 (g)
a. Rate = -2deltaO2 over delta t
b. Rate = -2/3delta O2 over delta t
c. Rate = +1/3delta O2 over delta t
d. Rate = +3delta O2 over delta t
e. it is not possible to determine without more information
The balanced equation is :
2O₃(g) -----> 3O₂(g)
The rate of the reaction with [O₂] :The correct option c) Rate = + (1/3) Δ[O₂] /Δt
The balanced chemical equation is as follows :
2O₃(g) -----> 3O₂(g)
The rate of the reaction is the speed of the reaction at which the product is formed from the reaction in the chemical reactions. The rate for the chemical reaction is expressed by the decrease in the concentration of the reactants or the increase in the concentration of the products:
The rate of reaction with respect to the [O₂] is expressed as :
The rate = + (1/3) Δ[O₂] /Δt
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An energy _____ is the change of energy from one form to another. An energy _____ is the movement of energy from one object to another.
Urgent, will mark Brainliest.
An energy conversion is the change of energy from one form to another. An energy transfer is the movement of energy from one object to another.
What is energy conversion?Energy is a property of matter that gives us the ability to move or do work. The process of converting energy from one form to another is called energy transformation or energy conversion.
Energy is transformed in someplace every minute of every day. Thermal, electrical, nuclear, electromagnetic, mechanical, chemical, and sound energy are just a few of the many distinct sources of energy.
Energy transfer is the act of moving energy from one location to another.
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in which of the following compounds is the mass ratio of chromium to oxygen closest to 1.62 to 1.00? responses cro3 cro 3 cro2 cro 2 cro cro cr2o cr 2 o cr2o3
The compounds is the mass ratio of the chromium to the oxygen closest to 1.62 to 1.00 is CrO₃.
The Atomic mass of Cr = 52 g /mol
The Atomic mass of O = 16 g/mol
The mass ratio of the chromium to the oxygen is given below as :
1) CrO₃ = 52 / 16 × 3 = 1.08
2) CrO₂ = 52 / 16 ×2 = 1.63
3) CrO = 52 / 16 = 3.25
4) Cr₂O = 52 × 2 / 16 = 6.5
5) Cr₂O₃ = 52 × 2 / 16 × 3 = 2.1
Thus the compound correct mass ratio of chromium to oxygen closest to 1.62 to 1.00 is CrO₃.
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Determine the empirical formula of each of the following compounds from the percent composition: a. 7.8% carbon and 92.2% chlorine b. 10.0% C c. 0.80% H, 89.1% Cl
The empirical formula of a compound with 7.8% carbon and 92.2% chlorine is CCl₄ and that of a compound with 10.0% C, 0.80% H and 89.1% Cl is CHCl₃.
In order to determine the empirical formula of the compounds, we have to divide the percentage by mass of each of the elements by their relative atomic masses and then divide them through the lowest ratio.
Carbon = 7.8%
7.8/12 = 0.65
Chlorine = 92.2%
92.2 / 35.5 = 2.59
Dividing by the lowest ratio,
Carbon = 0.65/0.65 = 1
Chlorine = 2.59/0.65 = 3.98 ≅ 4
So the empirical formula is CCl₄.
Hydrogen = 0.80%
0.80/1 = 0.80
Chlorine = 89.1%
89.1/35.5 = 2.50
Carbon = 10.0%
10/12 = 0.83
Dividing by the lowest ratio,
Hydrogen = 0.80/0.80 = 1
Carbon = 0.83/0.80 = 1.03 ≅ 1
Chlorine = 2.50/0.80 = 3.1 ≅ 3
So the empirical formula is CHCl₃
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a gas is compressed from a volume of 5.42 l to a volume of 2.75 l by an external pressure of 748 torr. which of the following correctly reflect the calculations required to determine the work done on/by the system (the gas)? select all that apply.
The one which correctly reflect the calculation required to find the work done is a) W = - P ΔV = 266 J
The initial volume = 5.42 L
The final volume = 2.75 L
The change in volume , ΔV = final volume - initial volume
= 2.75 - 5.42
The change in volume , ΔV = - 2.67 L
The work done is expressed as :
Work done, W = - P ΔV
where,
ΔV = - 2.67 L
P = 748 torr = 0.984 atm
W = - P ΔV
W = - ( 0.98 × - 2.67 ) × 101.3 J ( 1 atm ⋅L = 101.3 J )
W = 266 J
The work done is 266 J.
A gas is compressed from a volume of 5.42 l to a volume of 2.75 l by an external pressure of 748 torr. which of the following correctly reflect the calculations required to determine the work done on/by the system (the gas)? select all that apply.
a) W = - P ΔV = 266 J
b) W = + P ΔV = - 266 J
c) none of the above
d) both a and b
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write a balanced equation for the synthesis reaction that occurred in experiment 1. include physical states.
The equation NaCl + AgNO3 => AgCl + NaNO3 incorporates the physical states for the synthesis reaction that took place in experiment 1. Factors are denoted by symbols in chemical equations.
When two or more chemical equations combine in a synthesis reaction, the result is A + B AB. This form makes it easy to spot synthesis reactions because there are more reactants than products. When two or more reactants react, a larger compound is produced depending on the direction of the reaction and the physical characteristics of the reactants. In 1615, chemist Jean Beguin of France formulated the first chemical equation. Chemical processes are present everywhere, beginning with food metabolism.
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The density of air at ordinary atmospheric pressure and 25 ∘C is 1.19 g/L. What is the mass of the air in a room that measures 14.5×16.5×6.0 ft?
Answer:
40,827.34 g
Explanation:
First find the volume of the room and then multiply it by the density of air at ordinary atmospheric pressure and 25 ∘C.
In this case, the room has a length of 14.5 ft, a width of 16.5 ft, and a height of 6.0 ft.
volume = 14.5 ft x 16.5 ft x 6.0 ft = 1209.25 ft^3
To convert ft^3 to L, we can use the conversion factor 1ft^3 = 28.316846592 L
1209.25 ft^3 = 1209.25 * 28.316846592 = 34,416.99 L
Calculate the mass of the air in the room by multiplying the volume of the room by the density of air:
mass = 34,416.99 L x 1.19 g/L = 40,827.34 g
So, the mass of the air in the room is 40,827.34 g
A. The atomic number (Z) of an element is the number of protons in the nucleus of atoms of that element. Because the net charge on an atom is zero, the number of protons is equal to the number of electrons. Thus, the atomic number also gives the number of electrons in a neutral atom. The mass number (A) of an atom is the total number of nucleons (protons plus neutrons). Therefore, the number of neutrons in an atom can be found by subtraction:
Mass number – atomic number = number of neutrons
Atomic Number Mass Number Number of protons Number of neutrons Number of electrons Element Symbol
6 6
39 19
77 Xe
64 29
35 45
The Atomic Number, Mass Number, Number of protons, Number of neutrons, Number of electrons, Element, and Symbol is shown below:
Atomic Number = 6; Mass Number = 12; Number of protons = 6; Number of neutrons = 6; Number of electrons = 6; Element = Carbon, Symbol = CAtomic Number = 19; Mass Number = 39; Number of protons = 19; Number of neutrons = 20; Number of electrons = 19; Element = Potassium, Symbol = KAtomic Number = 54; Mass Number = 131; Number of protons = 54; Number of neutrons = 77; Number of electrons = 54; Element = Xenon, Symbol = XeAtomic Number = 29; Mass Number = 64; Number of protons = 29; Number of neutrons = 35; Number of electrons = 29; Element = Copper, Symbol = CuAtomic Number = 35; Mass Number = 80; Number of protons = 35; Number of neutrons = 45; Number of electrons = 35; Element = Bromine, Symbol = Br.What is the atomic number of an element?The atomic number of an element is the number of protons present in the nucleus of the atom of the element.
The mass number is the sum of the protons and neutrons in the nucleus of the atom of the element.
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the linear order of amino acids (blank structure), with the varying properties of their side chains (or blank groups), determines what blank and blank structures will form to produce a protein. the resulting unique blank shapes of proteins are key to their specific and diverse functions.
The linear order of amino acids (primary structure), with the varying properties of their side chains (R groups), determines what secondary and tertiary structures will form to produce a protein. The resulting unique three-dimensional shapes of proteins are key to their specific and diverse functions.
Amino acids are the building blocks of proteins, and the order of their assembly is known as the primary structure.
Each amino acid has a side chain, or R group, that is composed of different atoms, giving each amino acid a unique property that affects the structure and function of the proteins they create.
Depending on the primary structure and the chemical characteristics of the side chains, proteins can assume a variety of secondary and tertiary structures. It is these unique three-dimensional shapes that enable proteins to carry out their specific and varied functions.
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The hottest temperature yet recorded in Phoenix, Arizona, was 122 O F on June 26, 1990. IVhat is that temperature in 0 C? In K?
The temperature in Celsius and kelvin is 50°C and 323.15 K.
The three most used temperature scales for usage in business, science, and daily life are Kelvin, Celsius, and Fahrenheit.
A scale in Kelvin is absolute. There are no degree symbols after its values, which begin at absolute zero.
Both Celsius and Fahrenheit are relative scales. The degree symbol is used to indicate Fahrenheit and Celsius temperatures.
Given the temperature is 122°F
Temperature in Celsius is -
⇒ C = (F - 32)/1.80
⇒ C = (122 - 32) / 1.80
⇒ C = 90 / 1.80
⇒ C = 50°C
Temperature in Kelvin is -
K = 5/9(F - 32) + 273.15
⇒ K = 5/9 (122 - 32) + 273.15
⇒ K = 323.15 K
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Given the density of Au is 19.3 g/cm^{ 3} , determine the mass of gold in an ingot with the dimensions of 10. in x 4.00 in x 3.00 in. Give your answer as a number with correct sig figs only.
The mass of the gold with the density of 19.3 g/cm³ with dimensions of 10.0 in x 4.00 in x 3.00 in is 38,011.48 grams.
How to calculate mass?The mass of a substance can be calculated from the density by using the following expression;
Density = mass ÷ volume
According to this question, the dimensions of gold is given as 10.0 in x 4.00 in x 3.00 in. The density of gold is 19.3 g/cm³.
Volume of gold = 10 × 4 × 3 = 120in³
120in³ is equivalent to 1966.45cm³
19.3g/cm³ = mass ÷ 1966.45cm³
mass = 19.3 × 1966.45
mass = 38,011.48 grams.
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The Northville School Board has proposed this budget for the upcoming school year:
20% for school staff’s salaries
50% for school maintenance and upkeep
10% to refurbish the gymnasium
5% to upgrade the computer lab hardware
10% for new instruments for the music department
5% for new sports equipment
After a brief discussion, the school board revised the budget as follows:
20% for school staff’s salaries
50% for school maintenance and upkeep
10% to refurbish the gymnasium
10% to upgrade the computer lab hardware
5% for new instruments for the music department
5% for new sports equipment
In this case, the opportunity cost for
was
.
The opportunity cost for the new instruments for the music department is the 10% to upgrade the computer lab hardware
What is the opportunity cost here?The revision of the budget is that the school board had to redistribute the budget allocation for upgrading the computer lab hardware from 5% to 10%. This means that the school board had to make a trade-off in terms of allocating more budget for upgrading the computer lab hardware and less for other areas such as new instruments for the music department or new sports equipment.
This trade-off is known as the opportunity cost, as the school board had to give up the potential benefits of allocating more budget to those areas in order to allocate more budget to upgrading the computer lab hardware.
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Calculate the number of grams of sulfuric acid in 1 gallon of battery acid if the solution has a density of 1.31 g/ml and is 38.7 % sulfuric acid by mass.
Answer:
4.956 g/gallon * 0.387 = 1.91 g of sulfuric acid in 1 gallon of battery acid.
Explanation:
To calculate the number of grams of sulfuric acid in 1 gallon of battery acid, we can use the density of the solution and the percentage of sulfuric acid by mass.
First, we need to convert the density from g/ml to g/gallon. Since 1 gallon is equal to 3.785 L, we can multiply the density of 1.31 g/ml by 3.785 to get 4.956 g/gallon.
Next, we can use the percentage of sulfuric acid by mass to find the mass of sulfuric acid in the solution. To do this, we can multiply the mass of the solution by the percentage of sulfuric acid by mass, which is 0.387.
which of the following would decrease the rate of a chemical reaction? adding more reactants stirring the reaction more vigorously squeezing the reactants into a smaller volume increasing the temperature raising the activation energy
Raising the activation energy would decrease the rate of a chemical reaction.
The rate of a chemical reaction refers to the speed at which the reactants are converted into products. There are several factors that can affect the rate of a chemical reaction, including the concentration of reactants, temperature, and the presence of catalysts or inhibitors.
Adding more reactants would generally increase the rate of a chemical reaction, as there would be more particles present to collide and react. Stirring the reaction more vigorously would also increase the rate of the reaction, as it would increase the chances of successful collisions between reactant particles. Squeezing the reactants into a smaller volume would also increase the rate of the reaction, as it would increase the concentration of reactants and the chances of successful collisions.
On the other hand, increasing the temperature would generally increase the rate of a chemical reaction, as it would increase the kinetic energy of the reactant particles and increase the chances of successful collisions.
However, raising the activation energy would decrease the rate of a chemical reaction, as it would require more energy for the reactant particles to overcome the activation energy barrier and undergo a successful reaction. Activation energy is the energy required to start a chemical reaction.
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How many atoms are in 30.1 L of Water vapor at STP?
First ⬆️. Second ⬆️
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you want to determine the heat of reaction when a sodium chloride solution is formed using a 10.0 g sample of nacl(s) and 50.0 ml of water in a coffee cup calorimeter. which of the following equations would you use? assume the specific heat of the solution is the same as the specific heat of water.
The heat of reaction when a sodium chloride solution is formed using a 10.0 g sample of NaCl(s) and 50.0 ml of water in a coffee cup calorimeter. The equation is :
E. q = ((60.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))
Given that :
The mass of the NaCl = 10 g
The volume of sample = 50 mL
The molar heat of the reaction for NaCl ( sodium chloride ) = + 3.9 kJ/mol
The equation for the heat is given as :
q = m c ΔT
Where,
q = heat energy
m = mass
c = specific heat capacity
ΔT = change in temperature
Therefore the equation is given as :
q = m c ΔT
q = ( 50 g + 10 g) (4.184 J/g °C) (T f - T i)
q / mol = q water / mol NaCl
q = ((60.0 g)(4.18 J/g K)(T f - T i)) / (10.0 g/(58.44 g/mol))
The given question is incomplete, the complete question is :
You want to determine the molar heat of solution of sodium chloride using a 10.0 g sample of NaCl(aq) and 50.0 mL of water in a coffee cup calorimeter. Which of the following equations would you use? Assume the specific heat of the solution is the same as the specific heat of water.
A. q = (50.0 g)(4.18 J/g K)(T i - T f)
B. q = ((10.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))
C. q = (60.0 g)(4.18 J/g K)(T f - T i)
D. q = (60.0 g)(4.18 J/g K)(T i - T f)
E. q = ((60.0 g)(4.18 J/g K)(T f - T i))/(10.0 g/(58.44 g/mol))
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