Answer:
delta
Explanation:i just got it right
Which of the following statements is true?
Type 2 diabetes is usually caused by genetics.
Regular exercise is one way to prevent Type 2 diabetes.
Congenital heart disease is caused by an unhealthy lifestyle.
The most common warning sign for cancer is chest pain
Answer:
yes that is true the answer is regular exercise
Explanation:
I did a question like this before and also type 1 diabetes is an injection
The true statement is that regular exercise is one way to prevent Type 2 diabetes. Thus, the correct option is B.
What is the significance of exercise?The significance of exercise is determined by the fact that it significantly enhances your brain health, regulates weight, reduces the threat of disease, strengthens bones and muscles, and improves your ability to do everyday activities.
According to the context of this question, type 2 diabetes is not usually caused by genetics as it is also caused by uncontrollable intake of sugar. Congenital heart disease is caused by the disruption of the normal development of the heart. The most common warning sign for cancer is swelling or lumps, fatigue, weight loss, etc.
Therefore, the true statement is that regular exercise is one way to prevent Type 2 diabetes. Thus, the correct option is B.
To learn more about Type 2 diabetes, refer to the link:
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Part D
Which two kinds of energy are associated with flames?
Answer:
Thermal energy and electrical energy
Explanation:
Answer:
Hello!!! Princess Sakura here ^^
Explanation:
The two kinds of energy are thermal and electrical.
2. Which of the following is a true statement.
Sound travels faster than light.
Sound travels slower than light
Answer:
Sound travels slower than light
Explanation:
Sound travels at around 1/3 km per second, while light travels around 300,000 km per second.
Also, this is the reason you see the lightning before you hear the thunder.
I hope this helped.
Answer:
Sound travels slower than light
Explanation:
Bc light is faster than sound
which produces wave particles that move and displace one another
Answer:
a guitar?
Explanation:
A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed
Complete Question
A sled of mass m is coasting at a constant velocity on the ice covered surface of a lake. Three birds, with a combined mass 0.5m, gently land at the same time on the sled. The sled and birds continue sliding along the original direction of motion. How does the kinetic energy of the sled and birds compare with the initial kinetic energy of the sled before the birds landed?
a) The final kinetic energy is one half of the initial kinetic energy.
b) The final kinetic energy is one third of the initial kinetic energy.
c) The final kinetic energy is one quarter of the initial kinetic energy.
d) The final kinetic energy is one ninth of the initial kinetic energy.
e) The final kinetic energy is equal to the initial kinetic energy
Answer:
The correct option is b
Explanation:
From the question we are told that
The mass of the sled is m
The mass of the three birds is [tex]m_b = 0.5 m[/tex]
Generally from the law of momentum conservation,
The initial momentum of the boat = final momentum of the boat
Hence
[tex]m * v = (m_b+ m) * v_2[/tex]
=> [tex]m v = (0.5m+ m) * v_2[/tex]
=> [tex]m v = 1.5m* v_2[/tex]
Here v is the velocity of the boat before the birds landed and [tex]v_2[/tex] is the velocity after the birds landed
So
[tex]v_2 = \frac{2}{3} v[/tex]
Generally the initial velocity of the boat before the birds landed is mathematically represented as
[tex]K_i = \frac{1}{2} * m * v ^2[/tex]
Generally the final velocity of the boat when the birds have landed is mathematically represented as
[tex]K_f = \frac{1}{2} * (m_b + m ) * v_2^2[/tex]
=> [tex]K_f = \frac{1}{2} * (0.5m + m ) * (\frac{2}{3} v)^2[/tex]
=> [tex]K_f = \frac{1}{2} * 1.5m * (\frac{2}{3} v)^2[/tex]
=> [tex]K_f = \frac{1}{2} * 1.5m * \frac{4}{9} v^2[/tex]
=> [tex]K_f = \frac{1}{2}m v^2 * \frac{1}{3}[/tex]
Comparing this equation with that of the initial kinetic energy
=> [tex]K_f = \frac{1}{3} K_i[/tex]
The kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.
What is kinetic energy?When an object is in motion, then the energy possessed by the object at the state of motion is known as its kinetic energy.
Given data -
The combined mass of three birds is, M = 0.5m.
Let m be the mass of the sled. Then applying the conservation of linear momentum as,
The initial momentum of the boat = final momentum of the boat
mv = (M + m)v'
v is the velocity of the boat before the birds landed and v' is the velocity after the birds landed.
mv = (0.5m + m)v'
mv = 1.5mv'
v = 3/2 v'
or
v' =2/3v
The initial kinetic energy of the boat before the birds landed is mathematically represented as
[tex]K_{1}= \dfrac{1}{2}mv^{2}[/tex]
And the final kinetic energy of the boat when the birds have landed is mathematically represented as,
[tex]K_{2}=\dfrac{1}{2}(M+m)v'^{2}\\\\K_{2}=\dfrac{1}{2}(1.5m) \times 4/9v^{2}\\\\K_{2}=\dfrac{1}{3} \times \dfrac{1}{2}mv^{2}\\\\K_{2}=\dfrac{1}{3} \times K_{1}[/tex]
Thus, we can conclude that the kinetic energy of the sled and birds is one-third the initial kinetic energy of the sled before the birds landed.
Learn more about kinetic energy here:
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Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance
Answer:
It is directly proportional to the source charge.
Explanation:
I found it pretty sure it's right hit me up on my insta
desiignerjoe173
2.What is the weight of an object that has a mass of 5 kg?
Answer:
5 kg
or 11 lbs
Explanation:
If an object has zero acceleration, does it have to have zero velocity?
Answer:
Yes, the velocity would also be zero.
Explanation:
Acceleration is the change in velocity over time, therefore, there has to be a change in velocity for something to accelerate. which means without acceleration, the object has no velocity.
How far from the home did Karen and her mother travel during the first hour of the trip?
Answer:
none cuz she was too bus yelling at the cashier at the gas station
Planets A and B have the same size, but planet A is half the mass of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the planets
are the same size.
B. You would weigh less on planet A because it has less mass than
planet B.
C. You would weigh the same on both planets because your mass
would be the same on both.
D. You would weigh more on planet A because it has less mass than
planet B.
Answer:
B
Explanation:
The more mass an object has, the more gravity it has.
The statement which correctly explains the weight you would experience on each planet is: B. You would weigh less on planet A because it has less mass than planet B.
Weight can be defined as the force acting on a body or an object as a result of gravity.
Mathematically, the weight of an object is given by the formula;
[tex]Weight = mg[/tex]
Where;
m is the mass of the object.g is the acceleration due to gravity.Hence, we can deduce that the weight and gravity acting on an object is highly dependent on the mass of an object.
Therefore, the higher the mass in a planet, the higher the gravity existing there.
Read more: https://brainly.com/question/18320053
Determine the acceleration that an unbalanced force of 28 N gives to a 6.8 kg mass.
Answer:
4.12 m/s^2
Explanation:
unbalanced force means the presence of resultant force (net force)
[tex]net \: force \: = mass \times accleration[/tex]
f = 28N
m = 6.8kg
a = ?
? = 28/6.8
= 4.1176...
approximately = 4.12 m/s^2
A shell is fired from a mortar over level terrain. The firing speed is 59 m/s and the mortar is aimed 70° above the horizontal. Find the range of the shell.
Answer:
228.23m
Explanation:
Vy=59sin70=55.44m/s
x=V0t+1/2at^2
0=55.44t-4.9t^2
t=11.31s
Vx=59cos70=20.18m/s
Range=20.18*11.31=228.23m
Predict the energy transformation that occurs when Carson sands a piece of wood with sandpaper.
A. chemical energy to heat energy
B. heat energy to mechanical energy
C. mechanical energy to heat energy
D. mechanical energy to chemical energy
Answer:
C. Mechanical to heat i,m pretty sure
Explanation:
I took the test
Answer:
C or D
Explanation:
not really sure
A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
[tex]v(x) = v * cos(x)[/tex]
We can write:
since the horizontal part of velocity remains constant:
[tex]v(x1) = v(x2)[/tex]
[tex]cos(50) = cos(x)[/tex]
[tex]50 = x[/tex]
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
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The correct response is given when the angle is asked a question.
1. Suppose you have a metal bar. Its mass is 57.9g and its volume is 3cm'. What is its
density?
¡Hellow!
How we know, for calculate density, we can use the formule:
[tex]\boxed{\textbf{p = m / v} }[/tex]
Where:
[tex]\sqrt{[/tex] p = Density = ?
[tex]\sqrt{[/tex] m = Mass = 57,9 g
[tex]\sqrt{[/tex] v = Volume = 3 cm³
Let's replace according we information:
p = 57,9 g / 3 cm³
p = 19,3 g/cm³
The density of the metal bar is 19,3 g/cm³.
¿Good luck?
2 physical properties for manganese
Greg paid $3.60 for a package of 8 nails at the home store. John paid $3.18 for a package of 6 nails at the hardware store. How much more did John pay per nail than Greg?
(PLS HELP ( . *)^( . *)
Answer:
8 cents extra.
Explanation:
First find out how much one nail is for each of them. So, divide.
3.60 divided by 8 is 0.45.
3.18 divided by 6 is 0.53.
Subtract 0.45 from 0.53 and voila you have 0.08.
Answer:
5
Explanation:
76789967
how does the size of the solar system compare to the Milky Way galaxy?
1. the solar system is larger
2. the solar system is the same size
3. the solar system is much smaller
4. the solar system is about one half the size
Answer:
either 3 or 4 most likely 3
Explanation:
To describe a position in more than one
dimension, you must use more than one______
Answer:
To describe a position in more than one dimension you must use more than one reference point. The reference point is a basis for evaluation, assessment or comparison; a criterion.
Explanation:
Hope this answer help :D
Answer:
reference point
Explanation:
A car is moving with a constant speed of 70.0 mi/h (31.2 m/s). If its wheels have a radius of 24.1 cm, what is their angular speed
Answer:
129.46rad/s
Explanation:
Given
Linear speed v = 31.2m/s
Radius of wheel = 24.1cm = 0.241m
The formula for calculating the angular speed in terms of linear speed is expressed as;
v = wr
w is the angular velocity
r is the radius
v is the linear velocity
From the formula:
w = v/r
Substitute
w = 31.2/0.241
w = 129.46rad/s
Hence the angular speed is 129.46rad/s
An airplane is flying at a velocity of 79 m/s eastward relative to the air. Due to a high-pressure region to the north, the velocity of the air relative to the ground is 18 m/s southward. Find the ground speed of the airplane.
how does 'g' at a point vary with the distance from the centre of earth?
Answer:
No gravity
Explanation:
because their is not gravity on earth and also close to the sun but not as close as mecury
A man with mass 60 kg rides a Ferris wheel that has a radius of 20 m. The man is sitting on a scale. If the man's translational (linear) speed during the ride is a constant 5 m/s, what would the scale read at top of the ride
Answer:
75NExplanation:
in this problem we are expected to solve for the force, and this force, is the centripetal force exerted on the man/
we know that the expression for the centripetal force is given as
F=mv^2/r
given data
mass, m=60kg
radius, r= 20m
velocity, v= 5m/s
Substituting into the expression we have
F=60*5^2/20
F=60*25/20
F=1500/20
F=75N
The reading at the top of the ride will be 75N
Which of the following would be useful to show the growth rate of plants at varying temperatures?
bar graph
circle graph
line graph
frequency table
Answer:
line graph
Explanation:
Ik im late but i hope this helps lol
Does time of flight depend on initial speed?
Why is friction like applied force but different from gravity?
Answer:
Friction is when a force is applied or done by weight dragging onto something.
Explanation:
Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.
How can you predict the number of swings an 80 cm pendulum will make in 15 seconds?
three charges are located at 100m intervals along a horizontal line: a charge of -3.0C on the left, 2.0C in the middle, and 1.0C on the right. What is the resultant force on the 1.0C charge due to the other two
We know, force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Here, k in a constant.
[tex]Net \ Force = F_1+F_2\\\\Net \ Force = k(\dfrac{Qq_1}{r_1^2}+\dfrac{Qq_2}{r_2^2})\\\\Net \ Force = k( \dfrac{-3}{50}+\dfrac{2}{50})\\\\Net \ Force = 9\times 10^9\times \dfrac{-1}{50}\ N\\\\Net\ Force = -1.8\times 10^8\ N[/tex]
Hence, this is the required solution.
I will give you branilest!
A 1500 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing?
Explain.
Hellow!
First, lets recabe information:
m (mass) = 1500 kg
a (aceleration) = 3 m/s²
F (Force) = ?
For calculate Force, if we have mass and aceleration, we can applicate the second law of Newton:
"Force is proportional to the product of the mass plus aceleration."
In a equation, this is like:
F = m * a
Let's replace according we information, and let's resolve:
F = 1500 kg * 3 m/s²
F = 4500 N
Result:
The force applicated is of 4500 Newtons.
Gud Luck!
define density with a suitable formula
Answer:
ratio between m/v
or d= m/v
m= mass
v= volume