When you empty the trash on your computer what happens?

C I believe cause that’s what my teacher always told us to do

Answer:

a tablet because it's controlled by the touch of a finger.

Answer:

collabirations

Explanation

Wikis are designed for collabirations, which is allowing people to contribute more than just posting a response.

Hope this helps solve it

The process of sending and receiving messages with words defines: A. Verbal communication.

Communication can be defined as a process which involves the transfer of a message from an individual (sender) to another (receiver or recipient), through the use of words, semiotics, symbols and signs, that are mutually understood by both the sender and the receiver.

In English language, there are different types of communication and these include:

Visual communicationNon-verbal communicationWritten communicationListening communicationVerbal communication

Verbal communication is also referred to as oral communication and it refers to the process of sending and receiving messages from one individual to another through the use of words.

Read more: https://brainly.com/question/14810228

Answer:

its a

Explanation:

yw

The answer is cyclin subunit

Answer:

Accessibility offline

Explanation:

Answer:

C

Explanation:

what types of loop will be used.

Answer:

the author makes an emotional connection between you and the character

Explanation:

short version:you feel the characters emotion

The answer is 570 hope it helps

Answer: drawright(30)

Explanation:

Answer:

C option

Explanation:

Because in testing phase the game has been developed and test for errors in game.

Computer memory I hope it works

Answer:

I personally think its a hard drive or something like that,im not a computer expert to be honest

Answer:

Virusus

Explanation:

-

Hope that helps

Answer:

if 40>= item >=49

Explanation:

The function is an illustration of loops.

Loop instructions are used to repeat operations

The function in Python, where comments are used to explain each line is as follows:

#This defines the function

def exclamation(myStr):

   #This iterates through the string

   for i in range(len(myStr)):

       #This checks if the current character of the string is "i"

       if myStr[i] == "i":

           #If yes, this converts the string to a list

           s = list(myStr)

           #This replaces i with !

           s[i] = '!'

           #This gets the updated string

           myStr = "".join(s)

   #This returns the new string

   return myStr

       

Read more about similar programs at:

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Just go into settings, type in startup apps, and it will take you to an area where you can select certain apps to start or not start when you reset / shut down / turn off your computer and turn it back on again.

Answer:

1

Explanation:

Binary search is a useful approach for reducing a list of items. It divides the section of the list that might contain the item in half repeatedly until there is only one viable position left. Thus, option D is correct.

What using a binary search?

Recursive and iterative methods. The main distinction between the two approaches is that the recursive approach utilizes O(logN) space complexity, whereas the iterative approach uses O (1).

On sorted arrays, binary search operates.The binary search process begins by comparing a middle-of-the-array member to the desired value.

Therefore, It is necessary to locate element 59 in a 10-digit array. The index of the elements ranges from 0 to 9. The array's centre is now calculated. To do this, divide the index's leftmost and rightmost values by two.

Learn more about binary search here:

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#SPJ2

Answer:

1 Start

2 Read the value of radius r of Circle

3. Give Pi = 3.14

4 Calculate area of Circle = Pi x r x r

5. Calculate Circumference of circle

( You can use either C= 2 X Pi X r Or Area (A) = Pi X r X r Circumference (C) = 2 X Pi X r A/r = Pi X r A/r = C/2 So C = 2 x ( A/r ) 5. Print area and Circumference

6. End.

Answer: Worst fit

Explanation:

Answer: Routing protocols

Explanation:

When you first purchase a notebook, make sure you have a RECOVERY CD. It enables the restoration of the notebook computer.

A recovery disc is a disc that enables to restore the computer to the same condition when it was bought.

Moreover, a recovery drive refers to a separate partition in the notebook that must contain the required files to restore the device if the system becomes unstable.

A recovery disc can be considered as a drive used to keep a backup of the files (e.g., images) and other types of restoration data.

Learn more about recovery disc here:

https://brainly.com/question/14217813

Answer: to avoid late fees and interest

Explanation:

[tex]\blue{<><><><><><><><><><><><><}[/tex]

[tex]\green{<><><><><><><><><><><><><}[/tex]

Answer:

False

Explanation:

Because, aligment the tex are aligned in the centre of the page.

[tex]\pink{<><><><><><><><><><><><><}[/tex]

[tex]\red{<><><><><><><><><><><><><}[/tex]

False
:)))))))))))))))))

Answer:

Include multiple people in the "To" section. picture attached below.

Answer:

Ok so im not completely sure about this but i think its

Systems Software

Explanation:

because word processor is for typing documents and stuff

spreadsheet is for like tracking you money your daily money or something

or some kind of graph for stuff like that (i think)

applications software well your keyboard isn't a application unless its the on screen keyboard

so the only one left is system software

hope it helped :)))) (●'◡'●)

Answer:

speed(0)

penup()

setposition(-200,-200)

pendown()

def draw_square_row():

color_value = 0

for i in range (10):

if color_value %2 == 0:

begin_fill()

color("red")

for i in range (4):

forward(40)

left(90)

forward(40)

color_value = color_value + 1

end_fill()

elif color_value %2 == 1:

begin_fill()

color("black")

for i in range (4):

forward(40)

left(90)

forward(40)

color_value = color_value + 1

end_fill()

def draw_square_row_2():

color_value = 1

for i in range (10):

if color_value %2 == 0:

begin_fill()

color("red")

for i in range (4):

forward(40)

left(90)

forward(40)

color_value = color_value + 1

end_fill()

elif color_value %2 == 1:

begin_fill()

color("black")

for i in range (4):

forward(40)

left(90)

forward(40)

color_value = color_value + 1

end_fill()

def move_up_a_row():

left(90)

forward(40)

right(90)

backward(400)

for i in range (5):

draw_square_row()

move_up_a_row()

draw_square_row_2()

move_up_a_row()

Explanation:

tell me if you get it right

hi there!

Answer:

I agree with this statement as wireless networks are better than wired ones especially for a huge structures like a school. in a big you will have to use kilometers of cables to set up a network, whereas you can set up the same network using a few access points and much less cables of course.

hope this helps.

//Note: This program was compiled using turboc compiler. If you are using gcc or any other compiler, then you have to modify the code slightly
#include
#include
int main()
{
int field[110][110]; //FIELD SIZE
int N, i, j;
char dir[50]; //TO REPRESENT THE DIRECTIONS OF 50 COWS
int cow[50][1][2]; //TO STORE THE X,Y COORDINATES OF 50 COWS
int infinity[50]; //TO IDENTIFY, HOW MANY COWS VALUES WILL BE INFINITY AND VICE VERSA
int count[50]; //TO COUNT AMOUNT OF GRASS EATEN BY EVERY COW
int cont = 1; //FLAG VARIABLE, INITIALLY KEEP IT 1.

//CLEAR THE SCREEN
clrscr();

//MARK ALL FIELD POSITIONS AS 1, INDICATING THERE IS GRASS TO EAT
for (i=0; i<110; i++)
for (j=0; j<110; j++)
field[i][j]=1;

//FOR ALL COWS SET INFINITY AS 1 AND COUNT AS 0. I.E WE ASSUME THAT
//EVERY COW WILL EAT INFINITE GRASS AND INITIALLY IT HAS NOT EATEN ANYTHING
//SO COUNT IS SET AS 0
for (i=0 ; i<50 ; i++){
infinity[i] = 1;
count[i] = 0;
}

//READ N, I.E NO. OF COWS
scanf("%d", &N);

//FOR EACH COW, READ THE DIRECTION AND X, Y COORDINATES
for( i=0 ; i fflush(stdin);
scanf("%c%d%d", &dir[i], &cow[i][0][0], &cow[i][0][1]);
}

//REPEAT UNTIL CONT==1
while( cont==1 ){

//FOR EVERY COW CHECK ITS DIRECTION
for( i=0 ; i //IF THE COW IS FACING NORTH DIRECTION
if( dir[i] == 'N'){
//IF THE RESPECTIVE COW'S Y COORDINATE IS LESS THAN 109
if( cow[i][0][1] < 109 )
//IF THERE IS GRASS IN THE PARTICULAR LOCATION,
if( field[cow[i][0][0]][cow[i][0][1]] == 1 ){
//LET THE COW MOVES TO THE NEXT LOCATION, BY INCREMENTING THE VALUE ASSOCIATED WITHN Y-COORDINATE
cow[i][0][1]++;
//INCREMENT THE COUNT VALUE FOR THE RESPECTIVE COW
count[i]++;
}
else
//IF THERE IS NO GRASS IN THAT LOCATION, THEN MAKE THE INFINITY VALUE CORRESPONDING TO THIS COW AS 0
//COW STOPS
infinity[i] = 0;
}

//IF THE COW IS FACING EAST DIRECTION
if( dir[i] == 'E'){
//IF THE RESPECTIVE COW'S X COORDINATE POS IS LESS THAN 109
if( cow[i][0][0] < 109 )
//IF THERE IS GRASS IN THAT PARTICULAR LOCATION
if( field[cow[i][0][0]][cow[i][0][1]] == 1 ){
//LET THE COW MOVE ON TO THE NEXT LOCATION
cow[i][0][0]++;
//INCREMENT THE COUNT FOR THE RESPECTIVE COW
count[i]++;
}
else
//IF THERE IS NO GRASS THEN MAKE INFINTY AS 0 FOR THE PARTICULAR COW.
//THE COW STOPS
infinity[i] = 0;
}
}

/*IN THE PREVIOUS TWO LOOPS WE MADE THE COW TO MOVE TO THE NEXT LOCATION WITHOUT
EATING THE GRASS, BUT ACTUALLY THE COW SHOULD EAT THE GRASS AND MOVE. THE BELOW
LOOP ENSURES THAT. THIS TASK WAS SEPARTED, TO ALLLOW TO TWO COWS TO SHARE THE SAME
POSITION FOR EATING.*/
for( i=0 ; i //IF THE COW IS FACING NORTH
if( dir[i] == 'N'){
//IF CURRENT Y POSITION IS <= 109
if( cow[i][0][1] <= 109 )
//IF IN THE PREVIOUS Y POSITION, THERE IS GRASS
if( field[cow[i][0][0]][cow[i][0][1]-1] == 1 )
//REMOVE (EAT) THE GRASS
field[cow[i][0][0]][cow[i][0][1]-1]=0;
}
//IF THE COW IS FACING EAST
if( dir[i] == 'E'){
//IF CURRENT X POS IS <= 109
if( cow[i][0][0] <= 109 )
//IF IN THE PREVIOUS X POS, THERE IS GRASS
if( field[cow[i][0][0]][cow[i][0][1]] == 1 )
//REMOVE (EAT) THE GRASS
field[cow[i][0][0]-1][cow[i][0][1]]=0;
}
}

/*ASSUME THAT ALL THE COW STOPS EATING AS THERE IS NO GRASS IN THE CURRENT CELL
OR THE COW HAS REACHED THE LAST LOCATION*/
cont = 0;

//REPEAT FOR EVERY COW
for( i=0 ; i //IF THE COW IS FACING NORTH
if( dir[i] == 'N'){
//IF THE COW HAS NOT REACHED LAST Y LOC OR NOT STOPPED EATING
if( cow[i][0][1] < 109 && field[cow[i][0][0]][cow[i][0][1]] !=0 )
cont = 1; //MAKE COUNT AS 1, THE WHILE LOOP SHOULD REPEAT
}
//IF THE COW IS FACING EAST
if( dir[i] == 'E'){
//IF THE COW HAS NOT REACHED LAST X LOC OR NOT STOPPED EATING
if( cow[i][0][0] < 109 && field[cow[i][0][0]][cow[i][0][1]] !=0)
cont = 1; //MAKE COUNT AS 1
}
}
}

//DISPLAY THE OUTPUT
for( i=0 ; i {
//IF THE INFINITY VALUE OF THE RESPECTIVE COW IS 1, THEN DUSPLAY AS INFINITY
if( infinity[i] == 1 )
printf("\nInfinity");
else //ELSE DISPLAY THE RESPECTIVE COUNT VALUE
printf("\n%d", count[i]);
}

getch();
return 0;
}

Answer:

I believe the answer is C, im sorry if im wrong