What question did use of a telescope by hubble answer A) Is earth the center of the universe B) Is the sun the center of the universe C) How do the planets move in the solar system D) Are there more galaxies beyond the milky way

Answers

Answer 1

Answer: C

Explanation:

Answer 2

The characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helps to answer is:

           D) Are there more galaxies beyond the milky way

Telescopes are instruments that can perceive very small amounts of light and have very large magnifications, in general to be able to see objects increasingly weak in intensity, telescopes become larger and the observation times of the object increase.

When we increase the observation times, the problem is that atmospheric movement changes the observation conditions and makes it difficult to obtain good images. One way to solve the problem was with telescopes in near space, the environmental disturbance is eliminated.

When the Hubble telescope was placed in space, there were already many answers but they continue to wonder what the limit of the universe is, this telescope allowed us to observe a body much farther away than ground-based telescopes, which is why it answered the question how many and to where there are galaxies out of the milky way.

Let's review the statements given to see the correct ones;

A) False. Copernicus clarified that the Sun is the center of the solar system

B) False. The center of the universe is not known, but the sun is a star in one of the arms of the milky way that is not the center of the universe either.

C) False. It has been known for a century what the movement of the planets in the solar system

D) True. The telescope in space allowed us to expand the limit of vision of the universe and respond to where there are galaxies outside the Milky Way.

In conclusion with the characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helped to answer is:

      D) Are there more galaxies beyond the milky way

Learn more here:  brainly.com/question/16319804

What Question Did Use Of A Telescope By Hubble Answer A) Is Earth The Center Of The Universe B) Is The

Related Questions

Someone help me please it’s urgent

Answers

Explain what we need to do ?

1. A person weighs 155 lbs and is walking 3.1 miles per hour. How much kinetic energy does the person have? (Keep in mind, 1 kg is 2.2 lb, and 1 m/s is 2.24 mi/h.)2. What is the kinetic energy of a 5 g bullet travelling 400 m/s?
3. Is it possible to have a negative KE? Why or why not?

Answers

Answer:

Explanation:

Kinetic energy is expressed as;

KE =1/2 mv²

M is the mass

v is the velocity of the object

1) Given

Mass = 155lb

Velocity = 3.1mi/hr

Since 1kg = 2.2lb

x = 155lb

x= 155/2.2

x = 70.45kg

Also

1m/s = 2.24mi/hr

y = 3.1mi/hr

y = 3.1/2.24

y = 1.384m/s

KE = 1/2(70.45)(1.384)²

KE = 0.9577×70.45

KE = 67.47Joules

2) M = 5g =0.005kg

V = 400m/s

KE = 1/2(0.005)400²

KE = 80000×0.005

KE = 400Joules

3} Since a body decelerates (negative acceleration) this mean that the velocity of a body can be a negative value showing that it is possible for a moving body to possess negative kinetic energy.

A projectile rolls off a cliff with a velocity of 40 m/s. The cliff is 60 meters high.
1. Calculate the time the projectile takes to hit the ground
2. Calculate the distance the projectile travelled on the X-axis horizontally before hitting the ground
3. Calculate the impact velocity of the projectile on the Y-axis
4. Calculate the Resultant velocity V r
5. Calculate the angle at which the projectile hits the ground
6. Calculate Sine Θ
7. Calculate Tan Θ
8. A final Resultant Velocity Statement

Answers

Answer:

1) t = 3.45 s, 2)  x = 138 m, 3) v_{y} = -33.81 m /s, 4) v = 52.37 m / s ,

5) θ = -40.2º

Explanation:

This is a projectile exercise, as they indicate that the projectile rolls down the cliff, it goes with a horizontal speed when leaving the cliff, therefore the speed is v₀ₓ = 40 m / s.

1) Let's calculate the time that Taardaen reaches the bottom, we place the reference system at the bottom of the cliff

      y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²

When leaving the cliff the speed is horizontal  v_{oy}= 0 and at the bottom of the cliff y = 0

      0 = y₀ - ½ g t2

      t = √ 2y₀ / g

      t = √ (2 60 / 9.8)

      t = 3.45 s

2) The horizontal distance traveled

     x = v₀ₓ t

     x = 40 3.45

     x = 138 m

3) The vertical velocity at the point of impact

     v_{y} = I go - g t

     v_{y} = 0 - 9.8 3.45

     v_{y} = -33.81 m /s

the negative sign indicates that the speed is down

4) the resulting velocity at this point

   v = √ (vₓ² + v_{y}²)

   v = √ (40² + 33.8²)

   v = 52.37 m / s

5) angle of impact

    tan θ = v_{y} / vx

    θ = tan⁻¹ v_{y} / vx

    θ = tan⁻¹ (-33.81 / 40)

    θ = -40.2º

6) sin (-40.2) = -0.6455

7) tan (-40.2) = -0.845

8) when the projectile falls down the cliff, the horizontal speed remains constant and the vertical speed increases, therefore the resulting speed has a direction given by the angle that is measured clockwise from the x axis

Impact extinction 65 million years ago over 50% of all species became extinct, ending the reign of dinosaurs and opening the way for mammals to become the dominant land vertebrates. A theory for this extinction, with considerable supporting evidence, is that a 10-km-wide 1.8×1015kg asteroid traveling at speed 11 km/s crashed into Earth.

A) Determine the change in velocity of Earth due to the impact. Mass of Earth is 5.98×1024kg.

B) Determine the average force that Earth exerted on the asteroid while stopping it. Assume that stopping distance is 0.60 km (depth of the crater created)

C) Determine the internal energy produced by the collision (a bar chart for the process might help). By comparison, the atomic bombs dropped on Japan during World War II were each equivalent to 15,000 tons of TNT (1 ton of TNT releases 4.2×109J of energy).

Answers

Answer:

for a)

Explanation:

(1.8 x 10^15)(11 x 10^3 m/s)  = (5.98 x 10^24 + 1.8 x 10^15)vf

vf= (1.8 x 10^15)(11 x 10^3 m/s) / (5.98 x 10^24 + 1.8 x 10^15)

= 3.3×10−6  m/s

An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the velocity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries

Answers

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]   (1)  

Where:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]

[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]

[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

When water changes from a gas in the atmosphere to a liquid droplet in a cloud, this is known as

Group of answer choices

transpiration

condensation

evaporation

precipitation

Answers

Answer:

Condensation

Explanation:

Answer:When water changes from a gas in the atmosphere to a liquid droplet in a cloud, this is known as

Group of answer choices

transpiration

condensation

evaporation

precipitation,←, that one is right

Explanation: so ur answer is precipitation

A baseball is thrown horizontally with a velocity of 44 m/s. It travels a horizontal distance of 18
m to the plate before it is caught. How long does the ball stay in the air?

A.0.41 sec
B.41 sec
C.4.1 sec
D.4 sec

Answers

Answer:

a 0.41

plug number into equation

A horizontal baseball pitch is launched at 44 m/s. The ball will stay for 4.1 sec (approx) in the air. Hence, option C is correct.

What is Velocity?

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

Its SI unit is represented as m/s, and it is a vector quantity, it means that it has both magnitude and direction.

According to the question, the given values are :

Initial Velocity, u = 44 m/s,

Distance travelled, s = 18 m and,

Final velocity, v = 0.

Use equation of motion :

v = u + at

0 = 44 + (-9.8)t

t = 44 / 9.8

t = 4.3 (approx)

Hence, the time for which the ball stay in the air is 4.1 sec (approx).

To get more information about velocity :

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#SPJ2

Which statement correctly describes the diferences between positive and negative acceleration
O Positive acceleration describes a change in speed, negative acceleration desxibes no change in speed,
Positive acceleration describes no change in speed, negative acceleration desibes a change in speed,
Positive acceleration describes an increase in speed, negative sexeleration desnibes a decrease in speed
O Positive acceleration describes a decrease in speed, negative sideration describes an increase in sarees

Answers

Answer:The answer is this Positive acceleration describes an increase in speed, negative sexeleration desnibes a decrease in speed

Explanation:

b. Interpret Data Solution A has a pH of 1.6.
Solution B has a pH of 4. Which solution
has a greater concentration of hydrogen
ions? Explain.

Answers

Answer:

Solution A has a pH of 6 and solution B has a pH of 8. Which of the following is true regarding the concentration of hydrogen ions in each solution? A) A has 100 times greater H+ concentration than B. B) B has 100 times greater H+ concentration than A. C) A has 7/9 of the H+ concentration of B. D) A has 9/7 of the H+ concentration of B. E) none of these

Explanation:

Hey im super sorry if i get this wrong :)

how can voltage be produced by magnetism and motion?​

Answers

Answer:

Electromagnetic Induction by a Moving Magnet

Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.

Explanation:

A child sits on a merry-go-round, 1.5 meters from the center. The merry-go-round is turning at a constant rate, and the child is observed to have a radial acceleration of 2.3 m/s2. How long does it take for the merry-go-round to make one revolution

Answers

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

The merry-go round will take 5.07 s to complete one complete revolution.

Given data:

The distance of child from the center is, r = 1.5 m.

The magnitude of radial acceleration is, [tex]a = 2.3 \;\rm m/s^{2}[/tex].

Since, the child is on merry-go round, which is undergoing a rotational motion. And radial acceleration means that it is under the acceleration, whose value is given as,

[tex]a=\dfrac{v^{2}}{r}\\\\v=\sqrt{a \times r}[/tex]

Here, v is the linear velocity.

Solving as,

[tex]v=\sqrt{2.3 \times 1.5} \\\\v=1.857 \;\rm m/s[/tex]

Now, we to obtain the time taken by merry-go round to complete one revolution. Then the expression for the time taken to complete one revolution is,

[tex]T=\dfrac{2 \pi r}{v}\\\\T=\dfrac{2 \pi \times 1.5}{1.857}\\\\T = 5.07 \;\rm s[/tex]

Thus, we can conclude that the merry-go round will take 5.07 s to complete one revolution.

Learn more about the centripetal acceleration here:

https://brainly.com/question/14465119

Is a compound considered a pure substance?

Answers

Answer:

It depends on which compound you use carbon dioxide can be while helium will not but if you where to sum it up it would be use because simply most compounds are considered pure substance.

Explanation:

When living things use chemical reactions to break down food, some of the energy is transformed into
OA. sound.
OB. heat.
OC. light
OD.waste
waste.

Answers

The answer is (D) Waste.

Answer:

OB. Heat

Explanation:

I hope this helped :)

A horizontal force of 100 N is applied to move a 50-kg cart (initially at rest) across a 10 m level surface. What is the final kinetic energy of the cart?

Answers

The net force on the cart is 100 N in the direction of its motion, so by Newton's second law we can find the acceleration a applied to it:

100 N = (50 kg) a

a = (100 N) / (50 kg)

a = 2 m/s²

The cart starts at rest and travels a distance of 10 m, so that its final velocity v satisfies

v ² - 0² = 2 (2 m/s²) (10 m)

v ²= 40 m²/s²

and so the cart ends up with kinetic energy

KE = 1/2 m v ² = 1/2 (50 kg) (40 m²/s²) = 1000 J

Which of these is a base?


HNO3


vinegar


ammonia


HCl

Answers

The correct answer is Ammonia

what energy transfer will a stretched rubber band have when let go

Answers

Answer:

when the rubber band is realeased the potential energy is quickly converted to kinetic energy this is equal to one mass of the the rubber band multiplied by its velocity( in meters per second)

Two hockey players are about to collide on the ice. One player has a mass of
66 kg and is traveling at 1.5 m/s north. The other has a mass of 75 kg and is
traveling at 1.2 m/s south. The system consists of the two tlockey players.
According to the law of conservation of momentum, what is the total
momentum of the system after they collide? Assume the collision is an
elastic collision.
A. 189 kg-m/s south
O B. 9 kg-m/s north
C. 189 kg.m/s north
D. 9 kg m/s south

Answers

Answer:

Option B: 9 kg.m/s North

Explanation:

We are told;

One player has a mass of

66 kg and is traveling at 1.5 m/s north.

Thus, velocity is positive since it's acting in the positive direction upwards.

Thus;

m1 = 66 kg

v1 = 1.5 m/s

Also, The other has a mass of 75 kg and is traveling at 1.2 m/s south.

Since it's traveling south, it means that velocity is negative. Thus;

m2 = 75 kg

v2 = -1.2 m/s

From conservation of mass, total momentum is;

m_total = m1•v1 + m2•v2

m_total = (66 × 1.5) + (75 × -1.2)

m_total = 99 - 90

m_total = 9 kg.m/s

This is positive and thus it will be in the direction of the north.

Answer:

9 kg-m/s north

Explanation:

A jogger runs 4 km in 0.4 hr, then 8 km in 0.8 hr. What is the average speed of the jogger?

Answers

The jogger would have ran about 10 km/h.

PLZ HELP help me help help

Answers

Answer:

matter

Explanation:

Hope I helped :)

At what condition does a body becomes weightless at the equator?

Answers

Answer:

The decrease is due to the bulge at the equator (putting more distance between the rest of the planet and the surface

Explanation:

Dr. Metallica wants to change the property of an alloy? How could she do this? SELECT ALL THAT APPLY.
A. She could heat the alloy enough that it is malleable.
B. She could change the metal(s) used in the alloy.
C. She could change the nonmetal(s) used in the alloy.
D. She could change the percentages of the elements used in the alloy.

Answers

Answer:

METALLICA = HOT BAND

Explanation:

The answer is a, you're welcome babes

Answer: A B D

Explanation:

A toaster is rated at 600W, when connected to a120-V source. What current does the toaster carry, and what is its resistance?

Answers

Explanation:

Given parameters:

Power of the toaster  = 600W

Voltage  = 120V

Unknown:

Current = ?

Resistance = ?

Solution:

The power in the circuit is related to resistance and current using the expression below;

       P = IV  

       P = [tex]\frac{V^{2} }{R}[/tex]

P is the power

I is the current

V is the voltage

R is the resistance

    To find the current;

        I = [tex]\frac{P}{V}[/tex]   = [tex]\frac{600}{120}[/tex]  = 5A

     Now, resistance;

       V²   = PR

       R = [tex]\frac{V^{2} }{P}[/tex]   = [tex]\frac{120^{2} }{600}[/tex]  = 24ohms

Current, I=5A

Resistance, R=24 ohms

Firstly, let's write the given values:

Power, P=600W

Voltage, V=120V

To find:

Current, I=?

Resistance, R=?

Lets understand ohm's Law:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Formula for Ohm's law:

[tex]V=I.R[/tex]

The relation between power, current and resistance can be represented as:[tex]P=I.V[/tex]

Or

[tex]P=\frac{V^2}{R}[/tex]

To find current:

[tex]I=\frac{P}{V}[/tex]

So on substituting given values,

[tex]I=\frac{600}{120} =5A[/tex]

To find resistance:

[tex]R=\frac{V^2}{P}[/tex]

So on substituting given values,

[tex]R=\frac{14400}{600} =24 \text{ohms}[/tex]

Learn more:

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Rita wants to make some toast for breakfast, which she knows involves a chemical change to the bread.
She puts a slice of bread in the toaster, but, after 10 minutes, she notices that the sides of the bread are
black. What caused this chemical change to go too far?
A. an increase in temperature
B. a decrease in temperature
C. the size of the bread
D. the type of bread

Answers

Answer:

A

Explanation:

The toaster was too high so its the increase in eat

A 2,000 kg car travels with a tangential
velocity of 12 m/s around a circular
track with a radius of 30 meters. What
is the car's rate of centripetal
acceleration?

Answers

a= v²/R
a = 12²/30 =4.8 m/s²

The car's rate of centripetal acceleration in the circular path is 4.8 m/s².

The given parameters;

mass of the car, m = 2,000 kgvelocity of the car, v = 12 m/sradius of the circular path, r = 30 m

The centripetal acceleration of the car is calculated as follows;

[tex]a_c = \frac{v^2}{r}[/tex]

where;

v is the tangential speed of the carr is the radius of the circular path

Substitute the given parameters and solve for the centripetal acceleration;

[tex]a_c = \frac{12^2}{30} \\\\a_c = 4.8 \ m/s^2[/tex]

Thus, the car's rate of centripetal acceleration is 4.8 m/s².

Learn more here:https://brainly.com/question/11700262

A 300 g object attached to a horizontal spring moves in simple harmonic motion with a period of 0.340 s. The total mechanical energy of the spring–object system is 3.00 J.
(a) What is the spring constant (in N/m)?
(b) What is the amplitude (in m) of the motion?
(c) What is the percentage change in amplitude of motion if the total energy of the system is increased to 5.00 J?

Answers

Answer:

Explanation:

angular velocity ω = 2π / T where T is time period of rotation .

= 2 x 3.14 / .34 = 18.47 rad /s

Total mechanical energy = 1/2 m ω²Α² where A is amplitude .

spring constant = k

[tex]\omega=\sqrt{\frac{k}{m} }[/tex]  

m is mass

[tex]\omega^2=\frac{k}{m} }[/tex]

18.47² = k / .3

k = 102.34 N /m

b )

energy = 1/2 m ω²Α²

3 = .5 x 18.47² x A²

A² = .01759

A = .1326

13.26 cm .

c )

If energy becomes 5 J

5 = .5 x 18.47² x A²

A² = .0293

A = .1711

= 17.11 cm

percent increase

= (17.11 - 13.26 )x100 / 13.26

= 29%

Please answer ASAP, and please don't joke around and actually do answer my question. I will give you brainliest if you answer it well:

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. If the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?
Remember to identify all your data, write the equation, and show your work.

Answers

Answer:

30 feet

Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

Having been kicked, a soccer ball rolls past a kid with a stopwatch. At the moment the ball passes the kid, it has an initial velocity of 4.0 m/s and the watch reads 10.0 s. If the watch reads 23.3 s when the ball stops rolling, what is its average acceleration?

Answers

The ball rolls to a rest from 4.0 m/s in a span of 23.3 s - 10.0 s = 13.3 s, so the average acceleration is

(0 - 4.0 m/s) / (13.3 s) ≈ -0.30 m/s²

The engine of a boat (m = 2280 kg) exerts an
1800 N force northward, while the current
pushes it 1050 N eastward.
What is the magnitude of the acceleration
of the boat?

Answers

Answer:

a = 0.9139 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

The forces are on two different axes, x & y axes (North and East). In this way, the Pythagorean theorem should be used to determine the total force.

Fx = 1800 [N]

Fy = 1050 [N]

[tex]F = \sqrt{(F_{x} )^{2} +(F_{y} )^{2} } \\F=\sqrt{(1800)^{2} +(1050)^{2} } \\F=2083[N][/tex]

Now using Newton's second law.

ΣF = m*a

where:

F = force = 2083.8 [N] (units of Newtons)

m = mass = 2280 [Kg]

a = acceleration [m/s²]

2083.8 = 2280*a

a = 0.9139 [m/s²]

11. How fast will a pebble be traveling 3 seconds after being dropped? (g = 9.8 m/s2)
A.-9.8 m/s
B.29.4 m/s
C.9.8 m/s2
D.29.4 m/s

Answers

B is the correct answer.

Which change of state is shown in the model?

-condensation
-deposition
-boiling
-freezing

Answers

Answer: what’s the model

Explanation:

it's B hope this help's

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