Flaming the loop between each streak when performing the streak plate method is vital for sterility, proper dilution of bacterial concentration, and maintaining a clean working environment, ultimately leading to accurate and reliable results.
When performing the streak plate method, flaming the loop between each streak is crucial for several reasons. First, it helps ensure the sterility of the loop, which is important to prevent the contamination of the sample or the agar plate. This step eliminates any remaining microorganisms from the previous streak, allowing for a more accurate analysis of the target microorganism.
Second, flaming the loop helps in obtaining isolated colonies by diluting the bacterial concentration on the loop. As you progress through the streaking pattern, you want to pick up fewer and fewer bacteria with each streak. By heating the loop until it's red-hot, you effectively kill off a portion of the bacteria present on the loop, promoting a proper dilution pattern and, ultimately, isolated colonies on the agar plate.
Finally, maintaining a sterile working environment is essential in microbiological studies, as it prevents cross-contamination between samples and ensures the validity of the experimental results. Flaming the loop between each streak contributes to this sterile environment, maintaining the integrity of your work.
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Specimens are visible on a phase contrast microscope because they refract the light that illuminates them.
Yes, specimens are visible on a phase contrast microscope because they refract the light that illuminates them.
Phase contrast microscopy is a technique used to enhance the contrast of transparent and colorless specimens that are difficult to visualize using brightfield microscopy. This is achieved by altering the phase of light that passes through the specimen, which results in the refraction of light waves.
Refraction causes the light waves to bend as they pass through the specimen, and this bending creates an interference pattern that can be visualized using a specialized objective lens. The interference pattern is then interpreted as an image of the specimen.
In summary, phase contrast microscopy relies on the refraction of light by specimens to visualize them. This technique is particularly useful for studying live cells and other transparent biological specimens.
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Media containing some ingredients of unknown chemical composition are called __________ media.
A. undefined
B. complex
C. defined
D. synthetic
The correct answer is A. Undefined media. Undefined media are commonly used in microbiology and contain some ingredients of unknown chemical composition.
These ingredients may be extracts from natural sources such as plants or animal tissues, which cannot be fully characterized in terms of their chemical composition. However, the overall composition of the media can still be adjusted to support the growth of specific microorganisms. In contrast, defined media contain known amounts and types of individual chemical components. Complex media are similar to undefined media but contain known ingredients of complex chemical composition, such as yeast extract or peptone. Synthetic media are completely chemically defined and contain only known chemical components. The choice of media depends on the specific microorganism being studied and the objectives of the experiment.
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3.2 What other information should you gather at the survey site in addition to your interrupted belt transect?
Hi! When conducting an interrupted belt transect survey, it's important to gather additional information to ensure accurate and comprehensive data collection. Along with the transect data, you should also gather information on:
1. Environmental conditions: Record the temperature, humidity, wind speed, and precipitation at the survey site to understand how these factors may influence the species or habitat being studied.2. Site description: Note the topography, soil type, and water sources, as these can impact the distribution and abundance of organisms in the area.3. Vegetation structure: Document the different plant layers, canopy cover, and plant species present to provide context for the observed distribution of organisms.4. Human impact: Observe and record any signs of human activity or disturbance (e.g., litter, construction, or footpaths) that may affect the habitat or species.5. Time and date: Record the date and time of the survey to account for any seasonal or diurnal variations in the species' activity.By gathering this additional information, you will have a more robust data set to better understand the relationships between the species and their environment in your interrupted belt transect survey.
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What is the most serious form and occurs especially in immunocompromised people, especially HIV patients?
The most serious form of infection that occurs especially in immunocompromised people, including HIV patients, is opportunistic infections. These infections take advantage of a weakened immune system and can lead to severe complications or even death.
The most serious form of HIV is acquired immunodeficiency syndrome (AIDS). AIDS is a condition caused by the human immunodeficiency virus (HIV), which attacks the immune system and weakens the body's ability to fight infections and certain cancers.AIDS is considered to be the most severe stage of HIV infection. It is diagnosed when a person with HIV has a CD4 T-cell count of less than 200 cells/mm³ or develops certain opportunistic infections or cancers associated with HIV.People with HIV who have advanced disease or poorly controlled HIV are more likely to develop AIDS. Additionally, individuals who are immunocompromised due to other medical conditions or treatments may also be at increased risk for developing AIDS or other serious infections associated with HIV.
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7.3 As well as GFP, the plasmid DNA encoded a gene to give the bacteria antibiotic resistance. Why did the second agar plate contain the antibiotic?
The second agar plate contained the antibiotic because it served as a selection mechanism for the bacteria that successfully took up the plasmid DNA.
The plasmid DNA encoded both the GFP (green fluorescent protein) gene and an antibiotic resistance gene. When the bacteria were exposed to the antibiotic, only those that had successfully incorporated the plasmid would survive, as they had acquired the antibiotic resistance gene.
This selection process is crucial in identifying and isolating the bacteria containing the desired plasmid. The surviving bacteria on the second agar plate will not only be resistant to the antibiotic but also express the GFP gene, making it easier to study the gene's effects and applications in the bacteria.
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which statement is correct about a bottleneck event? (1 point)responsesa bottleneck event increases the population of a species permanently. a bottleneck event increases the population of a species permanently. a bottleneck event increases the gene pool of a population. a bottleneck event increases the gene pool of a population. a bottleneck event decreases the gene pool of a population. a bottleneck event decreases the gene pool of a population. a bottleneck event decreases the population of a species permanently.
A bottleneck event drastically reduces the gene pool of the population. The correct option is C.
A population bottleneck is an event that drastically reduces the size of the population. Due to this event, there is a decrease in the gene pool of the population because many alleles, or gene variants, that were present in the original population are lost. Because of this event, the remaining population has a very low chance of genetic diversity.
The bottleneck event may be caused by various events, such as an environmental disaster, or the hunting of a species to the point of extinction.
Therefore, the ideal option is option C.
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How does ATP typically transfer energy from exergonic to endergonic reactions in the cell?
CC 8.3
ATP typically transfers energy from exergonic to endergonic reactions in the cell through hydrolysis.
ATP, or adenosine triphosphate, is a molecule that stores energy in its phosphate bonds. When ATP undergoes hydrolysis, one of the phosphate groups is cleaved off, releasing energy and forming ADP (adenosine diphosphate) and an inorganic phosphate molecule. This energy can be used to drive endergonic reactions, which require energy input to occur. In this way, ATP acts as a kind of energy currency in the cell, allowing for the transfer of energy between different metabolic pathways.
Overall, ATP serves as a crucial source of energy for many cellular processes, and its ability to transfer energy from exergonic to endergonic reactions through hydrolysis is a key mechanism by which cells are able to carry out their many functions.
Adenosine triphosphate (ATP) is a molecule that plays a central role in cellular energy metabolism. One of the key ways in which ATP is able to transfer energy from exergonic to endergonic reactions is through hydrolysis.
ATP is composed of three phosphate groups, a ribose sugar molecule, and an adenine base. The energy stored in ATP is contained within the high-energy phosphate bonds between the phosphate groups. When these bonds are broken through hydrolysis, energy is released, and the molecule is converted to adenosine diphosphate (ADP) and an inorganic phosphate molecule. This energy can be used to drive endergonic reactions, which require energy input to occur.
One example of how ATP is used to transfer energy in the cell is during muscle contraction. Muscles are able to contract due to the interaction between actin and myosin filaments. This interaction requires energy, which is supplied by ATP. When ATP is hydrolyzed, energy is released, allowing the myosin head to bind to the actin filament and initiate the contraction process. The ADP and inorganic phosphate that are formed during this process are then regenerated back into ATP through a process called cellular respiration.
Another example of how ATP is used to transfer energy in the cell is during photosynthesis. During photosynthesis, energy from sunlight is captured and converted into chemical energy in the form of ATP. This energy is then used to drive endergonic reactions that convert carbon dioxide and water into glucose and oxygen.
ATP is a crucial molecule in cellular energy metabolism, and its ability to transfer energy from exergonic to endergonic reactions through hydrolysis is a key mechanism by which cells are able to carry out their many functions. Through a variety of metabolic pathways, ATP is able to provide energy for processes ranging from muscle contraction to photosynthesis.
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Explain why bodies of water have a moderating effect on climate.
Answer:
Water heats and cools more slowly than landmasses. Therefore, the coastal regions will stay cooler in summer and warmer in winter, thus creating a more moderate climate with a narrower temperature range.
What makes water a good moderator of climate?
The high heat capacity of water also explains why the temperatures of land near a body of water are more moderate. The high heat capacity of water keeps its temperature within a relatively narrow range, causing nearby coastal areas to also have a narrow daily and seasonal temperature range.
What affect do oceans have on moderating temperatures?
Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off. The world's ocean is crucial to heating the planet. While land areas and the atmosphere absorb some sunlight, the majority of the sun's radiation is absorbed by the ocean.
Hope this helps :)
Pls brainliest...
Answer:
Bodies of water have a moderating effect on climate because they have a higher heat capacity than land. This means that they can absorb and release more heat energy without changing their temperature significantly. As a result, bodies of water tend to warm up and cool down more slowly than land, and they can transfer heat to or from the surrounding air. This makes the climate near large bodies of water more stable and less prone to extreme temperature fluctuations. For example, coastal areas typically have milder winters and cooler summers than inland areas at the same latitude3. Bodies of water also influence precipitation patterns, wind currents, and humidity levels, which affect the climate of nearby regions4.
Explanation:
When a skeletal muscle fiber contracts, the
a. zones of overlap get larger
b. width of the A band increases
c. H bands and I bands get larger
d. Z lines move further apart
e. All of the answers are correct
The answer is e. All of the answers are correct. When a skeletal muscle fiber contracts, the width of the A band increases as the myosin thick filaments shift towards the center of the sarcomere.
When a skeletal muscle fiber contracts, all of these changes occur: the zones of overlap between the thin and thick filaments get larger, the width of the A band increases, the H bands and I bands get smaller, and the Z lines move closer together. At the same time, the H bands and I bands get larger as the myosin thin filaments move further apart. Additionally, the zones of overlap between the thick and thin filaments get larger and the Z lines move further apart. All of these changes result in a shortening of the muscle fiber.
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When making a decision in the presence of uncertainty, decision makers should only be interested in the average, or expected, outcome. True False
When making a decision in the presence of uncertainty, it is FALSE that decision-makers should only be interested in the average, or expected, outcome.
How to make decisions in the presence of uncertainty?
When making a decision in the presence of uncertainty, decision-makers should consider not only the expected outcome but also the range of possible outcomes and their likelihoods. This is because uncertainty means that there is a range of possible outcomes and their likelihoods are uncertain, so simply focusing on the average outcome may not provide a complete picture of the potential risks and rewards of the decision.
While the average outcome can provide useful information, it is also important to consider other factors such as risk, potential worst-case scenarios, and the range of possible outcomes to make a well-informed decision.
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3¿Un cable de 20 cm de largo es colocado de forma perpendicular a la dirección de un campo magnético de 0. 7 T de intensidad y cuando pasa una corriente desconocida por él, sufre una fuerza de 2. 5 N. Calcula el valor de la corriente que pasa por dicho cable?
The value of the current flowing through that wire which is 20 cm long is given by the 17.85 A.
A stream of charged particles, such as electrons or ions, travelling through an electrical conductor or a vacuum is known as an electric current. The net rate of electric charge flowing through a surface or into a control container is how it is calculated.Charge carriers, which can be any of a number of particle kinds depending on the conductor, are the moving particles. Electrons flowing over a wire are frequently used as charge carriers in electric circuits. They can be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons are the charge carriers in plasma, an ionised gas.
The passage of electric charge across a surface at a rate of one coulomb per second is measured by the SI unit of electric current, known as the ampere, or amp. A standard SI base unit is the ampere (symbol: A). The ammeter is a tool used to measure electric current.
The formula for Magnetic field is:
F =l( i × B )
where
F is forcei is currentl is lengthB is intensityTherefore,
F =l( i × B )
2.5 = 0.2(i x 0.7)
i = 2.5/(0.14)
i = 17.85 A.
Therefore, value of the current flowing through that wire is 17.85 A.
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Complete question:
A 20 cm long wire is placed perpendicular to the direction of a magnetic field of 0.7 T intensity and when an unknown current passes through it, it experiences a force of 2.5 N. Calculate the value of the current flowing through that wire?
The _____ nerve affects the muscles of the chin, lower lip, and external ear.â
âA) posterior auricular
B) âmandibular
âC) maxillary
âD) ophthalmic
The correct answer to the question is B) mandibular nerve. The mandibular nerve is one of the three branches of the trigeminal nerve, the largest of the 12 mandibular nerve.
The mandibular nerve is responsible for innervating the muscles of the chin, lower lip, and external ear. It is also responsible for providing sensation to the jaw, lower lip, cheek, and part of the ear. The mandibular nerve also plays an important role in chewing and biting, as it supplies motor fibers to the muscles of mastication. Additionally, the mandibular nerve provides sensory innervation to the anterior two-thirds of the tongue, including taste sensation. Damage to the mandibular nerve can result in numbness or tingling in the affected areas, as well as difficulty chewing and speaking. Overall, the mandibular nerve plays a crucial role in the functioning of the face and jaw.
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using the data calculate the growht rate in cells/ml x hour of the bacterial population between 2 and 4
The growth rate in cells/ml x hour of the bacterial population between 2 and 4 is 1.1985 cells/ml x hour.
To calculate the growth rate in cells/ml x hour of the bacterial population between 2 and 4, you will need to use the formula:
Growth rate = (ln N2 - ln N1) / (t2 - t1)
Where N2 is the final cell count at time 4, N1 is the initial cell count at time 2, t2 is the end time (4 hours), and t1 is the start time (2 hours).
Let's say that the initial cell count at 2 hours was 100 cells/ml, and the final cell count at 4 hours was 400 cells/ml. Plugging in these values into the formula, we get:
Growth rate = (ln 400 - ln 100) / (4 - 2)
Growth rate = (2.397 - 0) / 2
Growth rate = 1.1985 cells/ml x hour
Therefore, the growth rate in cells/ml x hour of the bacterial population between 2 and 4 is 1.1985 cells/ml x hour.
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QUESTION 5:
What causes the vesicles inside a neuron to fuse with the plasma membrane?
a. an action potential in the neuron
b. acetylcholine being broken down by acetylcholinesterase
c. an action potential in the muscle fiber
d. acetylcholine binding to acetylcholine receptors
The correct answer to this question is (a) an action potential in the neuron. Vesicles are small sacs within a neuron that contain neurotransmitters, which are chemical messengers used for communication between neurons.
When an action potential is generated in a neuron, it travels down the axon and reaches the axon terminal, where it causes the release of neurotransmitters from the vesicles. This is achieved through a process called exocytosis, where the vesicles fuse with the plasma membrane of the neuron, releasing their contents into the synaptic cleft, which is the space between the neurons. The neurotransmitters then bind to specific receptors on the postsynaptic neuron, leading to the generation of a new action potential and the continuation of the communication between the neurons. So, the fusion of the vesicles with the plasma membrane is a crucial step in the transmission of nerve impulses in the nervous system, and it is triggered by the arrival of an action potential in the neuron.
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in chickens, the dominant allele cr produces the creeper phenotype (having extremely short legs). however, the creeper allele is lethal in the homozygous condition. the homozygous recessive genotype results in a normal individual. if two creepers are mated, what will be the phenotypic ratio among the living offspring? 1 normal : 1 creeper 3 creepers : 1 normal 3 normal : 1 creeper 2 creepers : 1 normal 2 normal : 1 creeper
If two creepers are mated, the phenotypic ratio among the living offspring will be 2 normal : 1 creeper. This is because both creepers are homozygous dominant for the cr allele, so all of their offspring will inherit one copy of the cr allele.
However, as the creeper allele is lethal in the homozygous condition, any offspring that inherit two copies of the cr allele will not survive. Therefore, the only surviving offspring will be those that inherit one copy of the cr allele and one copy of the normal allele from their parents. These offspring will have the creeper phenotype, but will not be homozygous for the lethal creeper allele, allowing them to survive. The ratio of normal to creeper offspring will be 2:1 because there is a 1 in 4 chance of each offspring inheriting two copies of the normal allele, which will result in a normal phenotype. The other 3 in 4 chance will result in offspring with one copy of the normal allele and one copy of the cr allele, giving them the creeper phenotype. Therefore, the phenotypic ratio among the living offspring of two creepers will be 2 normal : 1 creeper.
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A technical term for fat is:
A) cartilage
B) epithelial tissue
C) tendons
D) adipose tissue
Adipose tissue :) I hope that helps and all please awnser one of my questions!
Why do present horses have much weaker teeth than horses of the past?
The present-day horses have weaker teeth compared to horses of the past due to factors such as dietary changes, domestication, and breeding practices.
Breeding practices refer to the deliberate selection and breeding of certain organisms to produce offspring with desirable traits. This can be done through various methods such as natural selection, artificial selection, hybridization, and genetic engineering. Breeding practices are widely used in agriculture, livestock production, and pet breeding to enhance specific traits such as disease resistance, growth rate, meat quality, or appearance. However, these practices have also raised ethical concerns regarding animal welfare and genetic diversity. Therefore, responsible breeding practices should consider the welfare of the organisms involved, the impact on the environment, and the preservation of genetic diversity.
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which of the following is most likely to cause the greatest disruption to an ecosystem?emptying an aquarium containing non-native species into a local waterway
Emptying an aquarium containing non-native species into a local waterway is likely to cause the greatest disruption to an ecosystem. This is because non-native species may not have natural predators or competitors in the local ecosystem, which can lead to uncontrolled growth and overpopulation.
This can result in the displacement or even extinction of native species, as well as changes in the balance of the food chain. Non-native species may also introduce new diseases, parasites, or toxins that can harm native species and the overall health of the ecosystem. Once introduced, it can be difficult or even impossible to remove non-native species from an ecosystem, making prevention the most effective strategy.
Therefore, it is important to be mindful of the potential impact of our actions on the environment and to take steps to prevent the introduction of non-native species into local ecosystems and further creating a disruption.
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Peptidoglycan is an important component of the cell walls of which microbes?
a) Some bacteria and all archaea
b) All archaea and bacteria
c) All archaea and some bacteria
d) All archaea
e) Most bacteria
Answer in a paragraph format with at LEAST 7 sentences. Make sure to be clear with your definition of terminologies. Provide specific evidence or examples. Sentence structure, grammar, and spelling count. In your responses, be sure to highlight the “interactions/connections/associations” of the concepts.
Based on the two figures, what is the factor that differentiates primary and secondary succession?
Explain using Figure 1 how it moved from bare rock to a forest.
Explain using the figures, why it took 150+ years for Figure 2 to reach a climax community and why it took longer for Figure two (2) to reach the climax stage.
The presence of soil is the main element that distinguishes primary from secondary succession. On surfaces without soil, such bare rock, sand, or ash, primary succession takes place. On the other hand, secondary succession takes place on surfaces that already contain a covering of soil.
The fundamental succession process is shown in Figure 1. It starts off as rock, which lichens and mosses swiftly colonise. Acids produced by these organisms dissolve the rock and create a thin layer of dirt. Following that, grasses, bushes, and finally trees take over this layer of soil.
Figure 2 illustrates how this colonisation and soil formation process takes roughly 150 years. Figure 2 depicts the peak community as a mature forest, which consists of a wide range of trees and other plants. Due to the fact that trees and other plants require time to develop and get established in their surroundings, this peak stage only occurs after more than 150 years of succession.
The climax community is also more stable than the earlier stages of succession, which is why it takes longer for Figure 2 to reach the climax stage.
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A G protein is active when __________.
SHOW HINT
a) it is bound by its ligand and transported to the nucleus
b) GDP replaces GTP
c) it is phosphorylated by protein kinase
d) Ca2+ binds to a G-protein-linked receptor
e) GTP is bound to it
A G protein is active when GTP (guanosine triphosphate) is bound to it.
a aprocess that is facilitated by GTPase-activating proteins (GAPs).
A G protein is active when GTP (guanosine triphosphate) is bound to it. When a ligand binds to a G protein-coupled receptor on the cell surface, it activates the associated G protein by causing it to exchange its bound GDP (guanosine diphosphate) for GTP.
This activates the G protein and enables it to interact with downstream effector molecules, leading to a cellular response. Once activated, the G protein remains in its active state until the GTP is hydrolyzed to GDP, a aprocess that is facilitated by GTPase-activating proteins (GAPs).
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match the following components involved with protein import into the er with the cellular location where they are normally found. - signal recognition particle - protein translocator - mrna - srp receptor - active site of signal peptidase 1. cytosol 2. er lumen 3. er membrane
By matching the components involved with protein import into the ER with their cellular locations, we get:
Signal recognition particle: 1. cytosol
Protein translocator: 3. ER membrane
mRNA: 1. cytosol
SRP receptor: 3. ER membrane
Active site of signal peptidase: 2. ER lumen
Several elements are crucial for protein import into the endoplasmic reticulum (ER). A cytosolic protein called the signal recognition particle (SRP) identifies and attaches to the signal peptide on the developing protein as it leaves the ribosome.
The SRP then directs the ribosome-nascent protein-SRP complex to the ER membrane's SRP receptor. The nascent protein is moved more easily over the ER membrane and into the ER lumen thanks to the protein translocator, which is also a component of the ER membrane. The ER lumen contains the signal peptidase active site, which cleaves off the signal peptide. The nascent protein's mRNA can be found in the cytosol as well.
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Why do older people have more difficulty controlling body temperature than do younger people?
Older people have more difficulty controlling body temperature than younger people due to a combination of factors. These factors include a decrease in metabolic rate, reduced muscle mass, decreased blood circulation, and a less efficient sweating mechanism. As people age, their bodies may not respond as quickly or effectively to changes in environmental temperature, which can make it more challenging for them to maintain a stable internal temperature.
As people get older, their bodies go through various changes, including a decrease in muscle mass and a decrease in the amount of water in their bodies. These changes can make it harder for older people to regulate their body temperature. Additionally, the body's natural ability to adjust to temperature changes can also decline with age. This means that older people may be more sensitive to changes in temperature and have a harder time adjusting to hot or cold environments. Overall, a combination of physiological changes and decreased adaptability can contribute to older people having more difficulty controlling their body temperature than younger people.
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what are the three types of bone conduction
compressional bone conduction mode, ossicular inertial bone conduction mode, and external canal bone conduction mode
Bone conduction is the transmission of sound through the bones of the skull to the inner ear. There are three types of bone conduction: compressional bone conduction mode, ossicular inertial bone conduction mode, and external canal bone conduction mode.
The compressional bone conduction mode occurs when sound waves directly stimulate the skull bones, causing them to vibrate and transmit sound to the inner ear. This mode is most effective at low frequencies. The ossicular inertial bone conduction mode occurs when the sound waves reach the middle ear and cause the ossicles (the tiny bones in the middle ear) to vibrate, which in turn causes the skull bones to vibrate and transmit sound to the inner ear. This mode is most effective at mid-range frequencies. The external canal bone conduction mode occurs when sound waves enter the ear canal and vibrate the external canal bone, which in turn vibrates the skull bones and transmits sound to the inner ear.
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In this activity, you will select a genetically based disease to research. Diseases have a variety of causes, including bacteria, viruses, and toxins. An important part of your research will be to identify that the disease relates (at least in part) to a person's genetics. In a genetically based disease (also called a genetic disorder), a mutation at one or more specific genes either causes the disease or puts someone at a higher risk for developing the disease.
-Here are some examples of genetic disorders you could choose:
--Sickle cell anemia, Type 1 diabetes, Breast cancer, Colon cancer, Cystic fibrosis, Huntington's disease, Alzheimer's disease, Alpha thalassemia, Beta thalassemia, Hemophilia, Marfan syndrome
--As you pick a disease to research, remember that you are looking for a disease caused by a gene or genes. Genetic disorders may be easily confused with chromosomal disorders. Chromosomal disorders involve a person either having an extra chromosome, as in Down syndrome, or missing an entire chromosome. Chromosomal disorders are not caused by mutations at one or more specific genes. So, you should not research one of these disorders for this activity.
--Mutations of some genes make a disease more likely. But a person with these genes may or may not develop a disease. You may choose one of these genetic disorders, but be sure you understand and explain that difference.
--After you have chosen a disease to study, you will perform research using reliable internet or library sources. For this assignment, you should include at least one primary source along with your secondary sources. Primary sources are published by scientists to share the results of their investigations. They include descriptions of the methods used, data gathered, data analysis, and conclusions. Primary sources are often published in peer-reviewed science journals. They are written for other scientists, so they can be long and complex. However, they usually begin with an abstract that summarizes the information, which can be helpful to read. Secondary sources review or summarize primary sources. They are often written by experts, but they can help nonexperts understand the information presented in primary sources.
--For this topic, you might find reliable information in scientific journals, on government websites, or in university publications. Here are a few suggestions of places to look :
--National Human Genome Research Institute: https://www.genome.gov/
National Center for Biotechnology Information PubMed Central®: https://www.ncbi.nlm.nih.gov/pmc/
National Library of Medicine MedlinePlus®: https://medlineplus.gov/
There are also strategies you can use to achieve useful results in an internet search. For example, consider using the following search terms:
--[your chosen disease] + .org
scientific journals + [your chosen disease] + gene
Before you decide to use a source, consider whether it is likely to be credible and reliable. Think about these questions:
Who is the author? Is this person an expert in the subject or in communicating science topics?
What is the goal of the author?
Does the author have a possible bias?
Was the material written recently, or is the information it contains likely to be outdated?
Does the author include specific scientific evidence to support the claims?
Are the claims and reasoning presented clearly, without grammatical errors or information that you know to be inaccurate?
Does the author cite credible references?
In Part 1, you will start by finding websites with information you can use. The questions in Part 2 will help you take notes. In Part 3, you will create a brochure or pamphlet that summarizes the information you researched and can help educate a patient about the disease.
Part 1: Identifying Sources (5 points)
1. List at least five terms from the introduction that you can use as keywords in your search. (1 point)
2. Identify at least two websites or other sources you will use to start your research. If you end up using other websites or sources to answer the questions in Part 2, add them to this list. Cross out any websites that don't end up helping you complete the activity. (2 points)
3. Evaluate two of the sources you plan to use, including a primary source. Explain why each source seems credible and likely to contain accurate information. Evaluate the arguments they present. Do the arguments seem valid? Are they backed up by data? Identify possible sources of bias. (2 points)
Activity requires selecting a genetically based disease to research, finding credible sources, and creating a brochure summarizing the findings. Suggestions of diseases and sources are given. Primary and secondary sources should be used, and sources should be evaluated for credibility and bias.
The activity involves selecting a genetic disorder to research and finding reliable sources of information using at least one primary source. The instructions advise against selecting a chromosomal disorder, and note that some genetic disorders are caused by mutations that make the disease more likely but do not guarantee it. Reliable sources of information are suggested, and strategies for finding information on the internet are given.
The instructions also provide guidelines for evaluating sources, including assessing the author's expertise and possible bias, as well as checking for supporting evidence and accurate information. Finally, the activity requires creating a brochure or pamphlet summarizing the findings to educate a patient about the disease.
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36) Enzymes known as lyases participate in __________ reactions.
A) anabolic
B) catabolic
C) both anabolic and catabolic
D) neither anabolic nor catabolic
E) oxidation-reduction
Enzymes are proteins that catalyze biochemical reactions in living organisms. Lyases are a type of enzyme that participate in reactions that involve the addition or removal of groups to a molecule, without the involvement of water.
This means that lyases break down larger molecules into smaller ones or build up smaller molecules into larger ones.
Based on their function, lyases participate in both anabolic and catabolic reactions. Anabolic reactions involve building up larger molecules from smaller ones, while catabolic reactions involve breaking down larger molecules into smaller ones. Lyases help to facilitate both types of reactions by breaking down or creating chemical bonds between molecules. In addition to anabolic and catabolic reactions, enzymes also play a role in oxidation-reduction reactions, which involve the transfer of electrons from one molecule to another. However, lyases are not specifically involved in these types of reactions, so option E is not the correct answer to the question. Therefore, the correct answer to the question "Enzymes known as lyases participate in _________ reactions" is C) both anabolic and catabolic.
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__________________ produces only a small amount of energy. Most of glucose's energy (90%) remains locked in the chemical bonds of pyruvic acid at the end of glycolysis.
Glycolysis produces only a small amount of energy.
Glycolysis is the first step in cellular respiration, during which glucose is broken down into two molecules of pyruvic acid. Although glycolysis produces some energy in the form of ATP (adenosine triphosphate), most of the energy (90%) remains stored within the chemical bonds of pyruvic acid. This means that only a small portion of the energy from glucose is released during glycolysis, and the majority is still contained in the pyruvic acid molecules.
In summary, glycolysis produces a limited amount of energy, as 90% of glucose's energy remains locked in the chemical bonds of pyruvic acid at the end of this process. Further steps in cellular respiration, such as the Krebs cycle and electron transport chain, are necessary to release the remaining energy stored in pyruvic acid.
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in haploid yeast with this dbm mutation, what is the length of the restriction fragment detected by the probe following noti digestion?
In order to determine the length of the restriction fragment detected by the probe following NotI digestion in haploid yeast with the dbm mutation, you would need to follow these steps:Identify the specific dbm mutation, Locate the NotI recognition sites, Calculate the restriction fragment length, Probe hybridization
1. Identify the specific dbm mutation: This involves knowing the exact location and nature of the mutation in the yeast genome. This information is essential in order to analyze the restriction fragment resulting from NotI digestion.
2. Locate the NotI recognition sites: NotI is a restriction enzyme that cleaves DNA at specific recognition sites. You will need to find the positions of these sites flanking the region of interest (where the dbm mutation is located) in the yeast genome.
3. Calculate the restriction fragment length: Once you have the positions of the NotI recognition sites, subtract the position of the first site from the position of the second site to determine the length of the restriction fragment containing the dbm mutation.
4. Probe hybridization: The probe will specifically bind to the complementary sequence of the dbm mutation within the restriction fragment. The detection of this hybridization event will confirm the presence and length of the fragment containing the mutation.
In summary, to find the length of the restriction fragment detected by the probe following NotI digestion in haploid yeast with the dbm mutation, you need to identify the mutation, locate the NotI recognition sites, calculate the fragment length, and confirm with probe hybridization. However, without specific information about the yeast genome and the dbm mutation, it's not possible to provide a numerical length for the restriction fragment.
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he human growth hormone, produced by the pituitary gland, is secreted during sleep in higher concentrations than when awake. (True or False)
True, the human growth hormone (HGH), produced by the pituitary gland, is secreted during sleep in higher concentrations than when awake.
This hormone plays a crucial role in growth, cell reproduction, and cell regeneration. Studies have shown that there is an increase in HGH levels during sleep, and specifically during the deeper stages of sleep. This is because the body is able to conserve energy while sleeping, allowing it to focus on the production of HGH. During sleep, the pituitary gland is able to secrete up to seven times the amount of HGH it would during a normal waking state. HGH plays a key role in the body’s growth and development. It helps to regulate and stimulate the production of other hormones and is important for healthy bones, muscles, and tissue.
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two noti restriction enzymes cleave dna on opposite sides of the dbm gene in a species of yeast. a molecular probe for dbm detects a dna restriction fragment of 8.5 kb in organisms that are wild type at dbm. in a strain of yeast, a ty1 transposable genetic element mutates dbm. ty1 is 5.6 kb in length.
The two NotI restriction enzymes cleave DNA on opposite sides of the dbm gene in a species of yeast.
A molecular probe specific for dbm detects a DNA restriction fragment of 8.5 kb in organisms that are wild type at dbm.
However, in a strain of yeast where a ty1 transposable genetic element has mutated dbm, the size of the restriction fragment detected by the probe will be different. This is because the ty1 element is 5.6 kb in length, and its insertion disrupts the sequence of the dbm gene, resulting in a smaller restriction fragment. Therefore, the molecular probe would detect a restriction fragment of a smaller size in the mutated strain compared to the wild type strain.
It appears that your question involves two NotI restriction enzymes, the DBM gene, a molecular probe, and a Ty1 transposable element. Based on the provided information, the wild-type DBM gene is found within an 8.5 kb DNA restriction fragment. However, in a mutated yeast strain, the Ty1 element, which is 5.6 kb in length, has caused a mutation in the DBM gene. This mutation could potentially alter the size of the DNA restriction fragment detected by the molecular probe due to the insertion of the Ty1 element.
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