What is the theoretical amount of sodium citrate (Na3C6H5O7) produced if you react 85.0g of citric acid (H3C6H5O7) in excess amount sodium hydroxide? If you actually produced 97.3 g of sodium citrate what is the percent yield?

Answer:

i think the answer is C , atom mass increases with temperature

Answer:

The egg will gain mass.

Explanation:

Eggs soaked in distilled water will gain mass and appear dramatically swollen.

Answer:

Gain mass

Explanation:

Carbonated water will create a reaction inside the egg making the fluid inside the egg becoming more solid thus gaining mass

Hope this helps!

Answer:

Arginine is the most basic among them because it contains guanidine side group, −(CH2)4NHC(=NH)NH2, which is basic. Lysine has two amine groups, which makes it overall basic because of the second isolated amine group (−(CH2)4NH2). Histidine, on the other hand, contains imidazole group, which is also basic.

Explanation:

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Answer:

0.133681 (cubic foot)

Explanation:

Answer:

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)

why are electric switches and boards are made up of plastic

Because plastic is a poor conductor of electricity.

Plastics do not conduct enough heat and electricity. Therefore, it is used in the manufacture of plug switches, plug boards, etc.

Answer:

+65 degress ?

Explanation:

I feel like there is more to this question

There are 6.44 × 10²³ molecules in 24.0 L of oxygen gas at standard temperature and pressure.

HOW TO CALCULATE NUMBER OF MOLECULES:

To calculate the number of molecules in a substance, we need the number of moles. The number of moles can be calculated using ideal gas law equation as follows:

PV = nRT

Where;

According to this question, oxygen gas is at standard temperature (273K) and pressure (1 atm)

1 × 24 = n × 0.0821 × 273

24 = 22.4n

n = 24 ÷ 22.4

n = 1.07moles

To calculate the number of molecules, we multiply the no. of moles by Avogadro's number (6.02 × 10²³)

no. of molecules = 1.07 × 6.02 × 10²³

no. of molecules = 6.44 × 10²³

Therefore, there are 6.44 × 10²³ molecules in 24.0 L of oxygen gas at standard temperature and pressure.

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Answer:

Place the object in the graduated cylinder, and record the resulting water volume as "b." Subtract the volume of the water alone from the volume of the water plus the object. For instance, if "b" was 50 milliliters and "a" was 25 milliliters, the volume of the irregularly shaped object would be 25 milliliters.

Heat flows from our body to iron

1 mL = 0.815 g

11.2 mL = X

X = 11.2 × 0.815

= 9.128 g

mole = 9.128/58

= 0.157 mole

1 mole = 6.02 × 10^23 atoms

0.157 mol = x

X = 0.157/1 × 6.02 × 10^23

= 9.451 × 10^22 atoms of C

please to recheck answers to ensure they are correct

I really hope this helps

Answer:

0.5131M

Explanation:

NaOH(aq) + HCl(aq) — NaCl(aq) + H20(l)

Mole ratio of acid to base 1:1

(Ca × Va)/ (Cb × Vb) = Na/Nb

(0.175 × 73.3)/ (Cb × 25)= 1/1

12.8275= 25 × Cb

Cb= 12.8275/25

= 0.5131M

Answer:

A.

The answer is A :)

the second options

the number of protons and electrons found in that element

Answer:

Liquid sugar is the sugar you consume in liquid form from beverages like sugar sweetened soda. The sugar in beverages is often highly concentrated and easy to consume in large amounts without feeling full. Some examples of these drinks are fairly obvious, such as sodas and fruit punch.

Answer:

A. candle wax cooling on the table

Explanation:

Candle wax cooling on a table is an example of freezing because the atoms in the candle wax start to slow down as the wax cools. This is considered "freezing" because the slower an atom is vibrating then the colder it is and of course the faster an atom is vibrating then the hotter it is! :)

Answer:

A solution contains 0.100 mol of NaCl dissolved in 8.60 mol of water.

The London forces designated as A are much weaker than the dipole- dipole interaction designated as B.

The intermolecular forces are interactions that exists between molecules of a substance in a particular state of matter. The nature of intermolecular forces in a substance greatly affect the properties of the substance.

We can see that A represents weak London forces while B represents dipole - dipole interactions. The London forces are very much weaker than the dipole - dipole interactions.

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Answer:

The setup above is used to collect hydrogen gas

Both filtration and distillation are useful ,methods to purify or separate components of a mixture. To collect soluble gas such as ammonia the best method is distillation. Thus setup 2 is better for collection of solute.

Distillation is the process of separation of compounds using  heat and condenser. The mixture is first boiled to the boiling point of solvent. When it is heated the solvent such as water passes from the beaker on which the mixture is taken.

The steam of the solvent is then cooled in the condenser tube and then liquid is collected to a second beaker. Therefore, the solute remains in the first beaker and can be collected.

Using filtration, we can only separate solution with insoluble solutes. Using filter paper the solid from the solution can be separated out.

First set up shows the filtration method  which is not applicable for collecting soluble gas like ammonia. Therefore, the second setup that is distillation is better to collect soluble gases.

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A chemical compound is a material made up of several types of molecules. Therefore, potassium Nitride is the name of the compound K[tex]_3[/tex]N.

A compound is indeed a substance that is composed of two or more separate chemical elements mixed in a defined ratio in chemistry. When the elements combine, they react and generate chemical connections that really are hard to break. These bonds occur as a result of atoms sharing or exchanging electrons.

A chemical compound is a material made up of several types of molecules (or molecular entities) that include atoms from much more than one chemical element and are bound together by chemical bonds. Potassium Nitride is the name of the compound K[tex]_3[/tex]N.

Therefore, potassium Nitride is the name of the compound K[tex]_3[/tex]N.

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Answer:

A. increase

Explanation:

the smaller the size of the ionic compounds, the more closer they get packed together. This means electrostatic attraction also increases, which means the ionic bonds gets stronger...therefore increases the melting point

This question is describing an spectrophotometry experiment in which the concentration of copper(II) ions has to be determined when 2.50 g of a copper-rich penny is reacted with 50.0 mL of nitric acid. In addition, the absorbance of a sample of the solution turned out to be 0.12 at 635 nm, so that the concentration was estimated as 12.8 g/L.

First of all, we must recall the Beer's law that can be written as follows:

[tex]A=ebC[/tex]

Whereas A is the absorbance of the sample, e the molar absorptivity, b the cuvette's path and C the concentration. However, this problem is not providing sufficient information to calculate the required concentration, however, similar absorbance experiments have graphed (absorbance vs concentration) calibration curves exhibiting trendlines as the one shown below:

[tex]y=0.009647x-0.003655[/tex]

Thus, since y stands for the absorbance and x for the concentration but in g/L not M (mol/L) for those experiments, we can set y equal to 0.12 so we solve for x as the concentration of the copper(II) ions in the sample:

[tex]y=0.009647x-0.003655\\\\x=\frac{0.12+0.003655}{0.009647}\\\\x=12.8g/L[/tex]

Nevertheless, it would be great if you come up with your own trendline, having clear the units for the absorbance vs concentration graph and thus double check your results because the data was not enough for the time being.

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Here is the atomic model in the picture.

Answer:

A. 4,6-dimethyloct-1,4,6-yne

B. deconic acid

C. 3-ethyl-4-methyl-7-bromocyclohexene

D. 2,2,3-trimethyl-4-butyl-heptane

E. 3-methylhexane

F. ethyl hexanoate

G. butanal

H. propyne

J. 2,4-dimethyl-pent-2-ene

Explanation:

sorry i didn't have time to do I

Answer:

The Sigma (σ) Bond

S-S Overlapping. In this kind of overlapping, one 's' orbital from each participating atom undergoes head-on overlapping along the internuclear axis. ...

S-P Overlapping. ...

P-P overlapping.