What is the speed of a
rocket that travels
8,000m in 13 seconds?

Answers

Answer 1

Answer:

speed of rocket=615.38m/s

Explanation:


Related Questions

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 53.9 m/s2 . The acceleration period lasts for time 6.00 s until the fuel is exhausted. After that, the rocket is in free fall.

Find the maximum height ymax reached by the rocket. Ignore air resistance and assume a constant free-fall acceleration equal to 9.80 m/s2 .

Answers

Answer:

maximum height reach by rockect =970.2metre

Explanation:

Ashley is flying a plane that has to reach a gradient of 360m/km in order to take off and not crash. Her goal is to travel from sea level to an elevation of 1000m at a distance of 2.8km. Calculate the gradient of Ashley’s flight and determine if she will crash!

Answers

Answer:

She is likely to crash because her flight gradient is lesser than the flight gradient required gradient to avoid crashing

Explanation:

The given parameters are;

The required gradient of the plane Ashley is flying needs to reach in order to take off and not crash = 360 m/km

The initial elevation of the plane Ashley is flying = Sea level = 0 m

The goal Ashley intends to make = Elevation of 1000 m at 2.8 km. distance

∴ Ashley's goal = Traveling from sea level to 1000 m at 2.8 km horizontal distance

We have;

The gradient  = Rate of change of elevation/(Horizontal distance)

Therefore;

The gradient of Ashley's flight = (1000 - 0)/(2.8 - 0) = 357.143 m/km

The gradient of Ashley's flight ≈ 357.143 m/km which is lesser than the required 360 m/km in order to take off and not crash, therefore, she will crash.

Jen had an average speed of 2.5 m/s when hopping on one foot. If she hopped for 5.0 seconds, for what distance was she hopping?

Answers

Explanation:

distance

speed =_________

time

distance = speed × time

= 2.5 × 5.0

distance = 12.5 m

If Newton's third law was true, then why does a table move when I push it? If the table exerted the same amount of force to me, why does it move?​

Answers

The reason is the table has less mass than you. The forces are equal and opposite but masses are not. The acceleration of the table is greater because its mass is smaller.

PLZ HELP ME

1. A stone is thrown horizontally from a cliff 30m high with an initial speed of 20m/s. How far from the cliff does the stone strike the ground?


2. A ball rolls off the edge of a table 1.44m above the floor and strikes the floor at a point 2m horizontally from the edge of the table.

A) What is the time the ball was in the air?


B) What is the initial velocity of the ball?



3. A golfer hits a ball and gives it an initial velocity of 40 m/s, at an angle of 30º above the horizontal.

A) How long does the ball stay in the air?


B) How far horizontally (the range) does the ball travel before hitting the ground?

Answers

Answer:

1. The stone will strike the ground 49.46 m from the base of the cliff

2. A) Approximately 0.542 seconds

B)  Approximately 3.69 m/s

3. A) The time the ball spends in the air is approximately 4.0775 s

B) The horizontal range is approximately  141.25 m.

Explanation:

1. The time it takes the stone to land is given by the equation, t = √(h/(1/2 × g)

∴ t = √(30/(1/2 × 9.81)) ≈ 2.473 seconds

The horizontal distance covered by the stone in that time = 20 × 2.473 ≈ 49.46 m

The stone will strike the ground 49.46 m from the base of the cliff

2. A) The time the ball spends in the air = t = √(h/(1/2 × g)

∴ t = √(1.44/(1/2 × 9.81)) ≈ 0.542 seconds

B) The initial horizontal velocity, u = Horizontal distance/(Time) = 2/0.542 ≈ 3.69 m/s

The initial horizontal velocity ≈ 3.69 m/s

3. A) The time the ball spends in the air is given by the following equation;

t = 2 × u × sin(θ)/g = 2 × 40 × sin(30)/9.81 ≈ 4.0775 s

t ≈ 4.0775 s

B) The horizontal range, R, of the  ball is given by the equation for the range of a projectile as follows;

[tex]Range, R = \dfrac{u^2 \times sin (2 \cdot \theta) }{g}[/tex]

Substituting the known values, gives;

[tex]Range, R = \dfrac{40^2 \times sin (2 \times 30^{\circ}) }{9.81} \approx 141.25 \ m[/tex]

The horizontal range ≈ 141.25 m.

What are greenhouse gases? Can you name any?

Answers

greenhouse gasses in the upper atmosphere trap heat from the Earth and reflect it back down rather than allow it to escape. This makes Earth progressively warmer.

1. In your own words explain what happens at a subduction zone. 2. In your own words explain what happens at a mid-ocean ridge. 3. At a subduction zone what causes magma to rise?

Answers

Answer:

1. The subduction zone serves as the meeting point for two tectonic plates.

2. At the Mid- Ocean ridge, decompression melting occurs.

3 What causes the magma to rise is the increase in pressure caused by collection of gases by the magma.

Explanation:

Subduction zone is define as a zone where tectonic plates ( an oceanic plate slides beneath a continental plate) meets and contributes to the rise of magma to the surface in geological sciences.

At the Mid - Oceanic ridge, decompression melting occurs. As mantle ascends beneath the mid-ocean ridge, less and less rock lies above it, so large pressure changes occur, which leads to melting. The melt is less dense than the solid, and rises to the surface to form the oceanic crust.

At the subduction zone the magma that is formed is usually made up of silica rich lava. Thick silica rich magma does not release the gasses very easily so they build up inside the magma chamber. As the gasses collect in the chamber, the pressure rises. It is possible for the pressure to rise so much that the chamber cannot contain the magma and it erupts explosively.

A satellite was in two separate crashes. In both crashes, the satellite had the same mass. Engineers want to know about the speed and direction of the satellite after the crashes. Why would the crash affect the motion of the satellite, and which crash caused a greater change in motion for the satellite?

Answers

Answer & Explanation:

Crashing into the asteroid would cause the satellite to slow down, stop, or reverse direction, because it is a force in the opposite direction to the satellite's motion. Whichever crash was a stronger force would cause it to change motion more. It takes a stronger force to change the velocity of a more massive object.

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the
material.

Answers

I would say 5.6 to the 4 and I’ll I did was add it to both side

We have that for the Question "Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the material." it can be said that

From the question we are told

Light travels in a transparent material at 2.5 x 10 m/s. Find the index of refraction of the  material.

Generally the equation for the  index of refraction  is mathematically given as

[tex]n=\frac{C}{v}\\\\Therefore\\\\n=\frac{3*10^8}{2.5 * 10 }\\\\n=12000000\\\\[/tex]

Therefore

The  index of refraction  of the material is

n=12000000

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find acceleration of block and tension in strings if m1 =8kg m2= 4kg and take g=10m/s²​

Answers

[tex]\large\bold{\underline{\underline{Given:-}}}[/tex]

[tex]\sf{m_1}[/tex] = 8kg

[tex]\sf{m_2}[/tex] = 4kg

g = 10m/s²

[tex]\large\bold{\underline{\underline{To \: Find:-}}}[/tex]

→Acceleration of block

→Tension in strings

[tex]\large\bold{\underline{\underline{Solution:-}}}[/tex]

Let, the two equation will be ,

[tex]\leadsto[/tex] 8g - T = 8a ..... Equation no (1)

[tex]\leadsto[/tex] T - 4g = 4a ..... Equation no (2)

Putting the value of equation no (1) and (2) we get,

[tex]\implies[/tex] 4g = 12a

[tex]\implies[/tex] 4 × 10 = 12a

[tex]\implies[/tex] 40 = 12a

[tex]\implies[/tex] a = [tex]\sf\dfrac{\cancel{40}}{\cancel{12}}[/tex]

[tex]\dashrightarrow[/tex] a = [tex]\dfrac{10}{3}[/tex]

Again, we have to putting the value of a in the equation no (2) we get,

[tex]\implies[/tex] T - 4g = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 4 × 10 = 4 × [tex]\dfrac{10}{3}[/tex]

[tex]\implies[/tex] T - 40 = [tex]\dfrac{40}{3}[/tex]

[tex]\implies[/tex] T = [tex]\dfrac{40}{3}[/tex] + 40

[tex]\implies[/tex] T = [tex]\dfrac{40 + 120}{3}[/tex]

[tex]\dashrightarrow[/tex] T = [tex]\dfrac{160}{3}[/tex] N

[tex]\therefore[/tex] Acceleration of block = [tex]\dfrac{10}{3}[/tex] m/s².

And, Tension in strings = [tex]\dfrac{160}{3}[/tex] N

40 points and brainliest plz helppp luv yah thxx
A car moving at 10 m/s slows to a stop. It moves 25 meters forward while braking.
1. What is its braking acceleration?
Explain how you found your answer.

2. How much time does it take to slow to a stop?
Explain how you found your answer.

Answers

Answer:

hey want you to separate the energy’s and put them in the categories they go in like why are They different what is chemically different about them? Etc.why do they act differently.. do they act the same in some ways? Think about that

Explanation:

400 N of load can be overcome by an effort of 50 N by using a lever. Calculate the mechanical advantage of the lever.

Answers

Answer:

load (l)=400N

Effort(E)=50N

mechanical advantage (MA)= load ÷Effort

(ma)=400÷50

(ma)=8

Explanation:

I copy pasted from the answer from the same question. Remember to first check if ur question is there


Which of the following best describes applying a force over a period of time?
power
energy
Impulse

Answers

impulse
it’s the only one that makes sense energy is just light and power almost the same thing

Scientists have invented the equipment to harness the power of lighting for energy use. True or false

Answers

I think it’s false .
Let me know if it’s incorrect .

A man is pulling on a rope with a force of 72 N
directed at an angle of 36◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.

Answers

Answer:

57,6N

Explanation:

To find the component  of a force on the x-axis we can simply do:

F * cos(36) = 72N * 0.8 = 57,6N

You push against a wall and the wall pushes back on you.
O Newton's 1st Law of Motion
O Newton's 2nd Law of Motion
Newton's 3rd Law of Motion

Answers

Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

A dumptruck filled with sand moves 1.8 km/h when it begins to accelerate uniformly at a constant rate. After traveling 4.0  102 m, the truck's speed is 24.0 km/h. What is the magnitude of the truck's acceleration?

Answers

The acceleration of the truck is obtained from the calculation done as  0.055 m/s^2.

What is the magnitude of the truck's acceleration?

We know that the acceleration is defined as the rate of the change of the velocity of the object with time and we can be able to obtain the acceleration by the use of the equations of kinematics as usual.

Initial velocity =  1.8 km/h  or 0.5 m/s

Final velocity = 24.0 km/h or 6.67 m/s

Distance covered = 4.0 * 10^2 m

Then;

v^2 = u^2 + 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance covered

a = v^2 - u^2/2s

a = (6.67)^2 - (0.5)^2/2 *  4.0 * 10^2

a = 44.4 - 0.25/800

a = 0.055 m/s^2

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If you are in a car at a stop sign and then the driver
presses on the gas pedal really hard, which way is the car
accelerating?

Answers

Answer:

it wont be because the hand brake would be on

The car is accelerating forward.

You are making s'mores with a friend. When you heat the marshmallow over the fire, what happens to the volume of the air bubbles inside the marshmallows? *

Answers

Answer:

Heat was trapped within the marshmallow.

Explanation:

Increasing temperatures make air contained within the marshmallow extend to fill up more room, causing the versatile sugar combination to spread. Eventually, if there is so much tension? It's small explosion. But take the marshmallow out from the heat, and it's going to deflate even if the extended gelatin does not really recover quickly.

Answer:

Heat gets trapped within the marshmallow.

Explanation:

Rickey Henderson, baseball's record holder for stolen bases, approaches third base. He dives head first, hitting the ground at 6.75 m/s and reaching the base with a speed of 5.91 m/s, accelerating at -5.11 m/s 2 . Determine the distance Rickey slides across the ground before touching the base. How much time is he sliding for before touching the base?

Answers

Answer:

The distance is 1.04 m and time is 0.16 seconds.

Explanation:

Initial speed, u = 6.75 m/s

Final speed, v = 5.91 m/s

Acceleration, a = -5.11 m/s²

We need to find the distance Rickey slides across the ground before touching the base and the time he sliding for before touching the base.

Let d is the distance. It can be calculated using third equation of motion as follows :

[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(5.91)^2-(6.75)^2}{2\times (-5.11)}\\\\d=1.04\ m[/tex]

Let t is the time he slides for before touching the base. Using first equation of motion as follows :

[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{5.91-6.75}{-5.11}\\\\t=0.16\ s[/tex]

So, the distance is 1.04 m and time is 0.16 seconds.

the person is not able to see the far lying object clearly. which type of lens will the doctor prescribe him give reason?

Answers

Answer:

correction of farsightedness uses a converging lenses that compensates for the under convergence by the eye. the converging lens produces an image farther from the eye than the object so that farsighted can see it clearly.

What is the height of a 50 kg person that has a potential energy of 4900J?

245,000m

98 m

10 m

Answers

Answer:

10 m

Explanation:

PE = mgh

m = 50kg

g= 9.8 m/s^2

h=?

so,

4900= 50×9.8× h

50h = 4900/9.8

50h = 500

h = 10 m

A fire is burning in a fireplace. Where is the radiation?

A. You touch warm bricks next to the fireplace
B. You can feel the heat from across the room
C. Heat is rising up from the chimney

Answers

I think it’s A.
........

A stunt man launches a car from the edge of a cliff horizontally. If he is launching off a
30-meter high cliff and must hit a mark 268-meters down range, with what speed
must he leave the cliff?

Answers

Answer:

All i got to say is that he is dead dead

Explanation:

A student is given an investigation of the human body. The student is to predict how new cells are created. According to cell theory, which prediction is correct?

A.Cells grow and develop, but are never replaced.

B. New cells are created from pre-existing cells in the human body.

C. New cells are created but quickly die during cell growth.

D. Humans are born with all the cells they will ever need.

Answers

Answer:

B. New cells are created from pre-existing cells in the human body.

Explanation:

According to the cell theory, the correct assumption from the student's investigation is that "new cells are created from pre-existing cells in the human body".

One of the postulates of the cell theory is that all cells originated from pre-existing cells. Also, a cell is the fundamental unit of life.

So, the student is correct to say that new cells are created from pre-existing cells in the human body.

When the energy of a wave increases, what happens to the amplitude?

Answers

Answer:

The energy transported by a wave is directly proportional to the square of the amplitude. So whatever change occurs in the amplitude, the square of that effect impacts the energy. This means that a doubling of the amplitude results in a quadrupling of the energy.

Explanation:

When the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

What is the amplitude of a wave?

The amplitude of a wave may be defined as the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

It is the principle of physics that when the amplitude of the wave is higher, the energy also gets higher. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude. The higher the frequency, the more energy, and the higher the amplitude, the more energy.

Therefore, when the energy of a wave increases, the amplitude also increases. This is because the amplitude of the wave is directly proportional to the energy of a wave.

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to calculatw the power produced by a force, the size of the force must be known. What else needs to be known to calculate the power

Answers

-- The distance the force moved through

-- How long the force lasted

The other thing we need to calculate the power is the "Velocity".

A quantity of labor or work done to be accomplished within a particular period of timeframe is determined as power. It is denoted by "P".According to the given query, we are talking about the relation between Power and Force. Along with simple instances where such an item is moved at continuous speed by a constant force.

The relation can be shown as:

→ [tex]P= Fv[/tex]

where,

P = PowerF = Forcev = Velocity

Thus the above is the right response.

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A 30 kg object has a frictional force of 60 N. It's coefficient of friction must be...?
A) 0.2
B) 2
C) .002
D) 20

Answers

mass = 30kg

frictional force = coefficient of friction * (mass * g)

g = 9.8 m/s^2

So:

60N = x * 294 N

x = 60 N / 294 N = 0,2

Tyler drives 50km north. Tyler then drives back 30km south. What distance did he cover? What was his displacement?

Answers

Answer:

80 km is distance and 30km north is displacement

Explanation:

distance= 50+30=80km

displacement= 50-20=30

his displacement is 30km north

When Tyler drives 50 km north and then drives back 30 km south, we have:

1. The distance that he covers is 80 km.

2. Tylor's displacement is 20 km.  

1. The distance is a scalar that is given by the sum of the kilometers traveled by Tyler as follows:

[tex] d = d_{1} + d_{2} = 50 km + 30 km = 80 km [/tex]

Hence, the distance traveled by Tyler was 80 km.

2. The displacement is a vector that depends on the direction of travel. Takin the north direction as positive we have:

[tex] x = x_{1} + x_{2} = 50 km + (-30 km) = 20 km [/tex]

Therefore, Tyler's displacement is 20 km.

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In which situation is the net force on the object equal to zero?


A.) a bicycle moving at a constant speed on a straight, level road

B.) an automobile braking to a stop

C.) a satellite moving at a constant speed around Earth in a circular orbit

D.) a pitched baseball being hit by a bat

Answers

Answer:

A.) a bicycle moving at a constant speed on a straight, level road.

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

In Physics, when the net force acting on a body or an object is equal to zero (0); the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In this scenario, the situation in which the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

The net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

The given problem is based on the Newton's second law to define net force. The net force on any object is an external effort by which the object change its speed with respect to time or tends to change the state of its motion. The mathematical expression for the net force is,

F = ma

Here, F is the net force, m is the mass of object and a is the acceleration of object.

When the net force acting on a body or an object is equal to zero , then the body or object is said to be in a state of equilibrium because it is not accelerating. This ultimately implies that, an object whose net force is equal to zero is either moving with a constant speed or the object is static i.e not moving at all.

In the given problem the net force on the object is equal to zero would be a bicycle moving at a constant speed on a straight, level road because it is at equilibrium and as such its resultant force is equal to zero.

Thus, we conclude that the net force on the object (bicycle) is zero due to its constant speed on a straight levelled road. Hence, option (A) is correct.

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