what is the mass per running metre of a copper bar with a uniform cross-section in the form of a triangle as shown in the figure? the density of copper is 8 850 kg/m³.​

Answer:

$5.50(2/3)π(6.5^3) = $3,163.45

$5.50(2/3)(3.14)(6.5^3) = $3,161.85

$3,161.85 is the correct answer.

Answer:

Step-by-step explanation:The system of equations represented by the given points is:1x + 0y = 1   (equation 1)

1x + 6y = 1   (equation 2)

8x + 26y = 1  (equation 3)

8x - 22y = 1  (equation 4)

We can use the first equation to solve for x in terms of y:1x + 0y = 1

1x = 1

x = 1

Then we can substitute x=1 into equations 2-4 to obtain three equations in terms of y:1(1) + 6y = 1    =>   6y = 0   =>   y = 0

8(1) + 26y = 1   =>   26y = -7/8   =>   y = -7/208

8(1) - 22y = 1   =>   -22y = -7/8 - 7   =>   y = 15/44

Therefore, the solution to the system is x = 1 and y = -7/208 or y = 0 or y = 15/44.

However, we are given that x = -2, which contradicts our solution of x = 1. Therefore, there is no solution to the system with the given values.

Answer:

(3, 0)

Step-by-step explanation:

It might be first helpful to think about the function [tex]|x-3|[/tex], we will call this [tex]g(x)[/tex]. So, [tex]g(x)=|x-3|[/tex].

The modulus (absolute value) function reflects any points on a graph that go below the x-axis up into the positive x region.

We know that the graph of [tex]y=x-3[/tex], will cross the x-axis at (3,0). We can work this out by setting y to 0 and rearranging for x. At the x-axis, y = 0.

Therefore, when the modulus comes in, a vertex will be created at (3,0).

But that is the vertex of [tex]g(x)[/tex].

Using basic algebra we can derive from previous working that [tex]f(x)=2g(x)[/tex].

Graphically, the multiplier of 2 on the outside of [tex]g(x)[/tex] stretches the graph in y-axis, and does so by the scale factor of 2.

With our vertex (3,0), the y value is 0. And if you multiply 0 and 2 together, 0 is produced. The x value will remain unchanged as a result of this transformation.

Therefore, the vertex of [tex]f(x)[/tex] is (3,0).

Answer:

43.96 = 2πr

r = 21.98/π

A = π(21.98/π)^2 = 483.1204/π = 153.78 square meters

A = 483.1204/3.14 = 153.86 square meters

The statement that could be true for h is h(2) = 16.

Option A is the correct answer.

We have,

The function h has a domain of -3 ≤ x ≤ 11 and a range of 1 ≤ h(x) ≤ 25, and we know that h(8) = 19 and h(-2) = 2.

To determine which statement could be true for h, we can use the given domain and range, along with the two known function values, to narrow down the possible values of h(x) for different values of x.

h(2) = 16

We do not have enough information to determine whether this statement could be true or not.

It is possible that h(2) = 16, but it is also possible that h(2) could be a different value within the range of 1 ≤ h(x) ≤ 25.

h(8) = 21

This statement cannot be true, as we already know that h(8) = 19.

h(13) = 18

This statement cannot be true, as 13 is outside the given domain of -3 ≤ x ≤ 11.

h(-3) = -1

This statement cannot be true, as -1 is outside the given range of 1 ≤ h(x) ≤ 25.

Therefore,

The statement that could be true for h is h(2) = 16.

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The range, difference of maximum and minimum values, is larger for Class C with a range of 10 compared to Class D with a range of 3. The data provided is not sufficient to calculate the IQR (Interquartile Range) for either class.

To begin, let's understand what the terms 'range' and 'IQR' (Interquartile Range) refer to in statistics. The range is simply the difference between the largest and smallest data values. The IQR is the range of the middle 50% of the values when ordered from lowest to highest.

For Class D, the lowest absence number is 0 and the highest is 3, thus the range is 3-0 = 3. For Class C, the lowest absence number is 0 and the highest is 10, so the range is 10-0 = 10. Thus, the range for the distribution of absences is larger for Class C.

Calculating IQR requires determining the 1st Quartile (Q1) and 3rd Quartile (Q3) values and subtracting Q1 from Q3. The data given doesn't include enough information to directly calculate these values and hence, it is impossible to definitively say which class has a larger IQR based on the provided information.

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Log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm is  2 + log₁₆(b)

We can use the product rule of logarithms, which states that the logarithm of a product is equal to the sum of the logarithms of the factors.

Therefore, we can write

log₁₆(256b) = log₁₆(256) + log₁₆(b)

We can simplify log₁₆(256) as follows:

log₁₆(256) = log₁₆(16^2) = 2

Therefore, we have:

log₁₆(256b) = log₁₆(256) + log₁₆(b)

= 2 + log₁₆(b)

So, we have rewritten log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm.

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Evaluating the given function, we can see that the intensity at 35 cm is 0.816

The intensity at a distance d in centimeters is given by the function:

I = 100*d⁻²

Here we want to find the intensity at 35 centimeters from the source, then we need to evaluate the function above at d = 35, doing that we will get:

I = 100*35⁻²

I = 100/(35²)

I = 0.816

The intensity at 35 centimeters from the source is 0.816.

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Anna will make  $1602.71 in all over 10 weeks.

Here, the first week salary of Anna = $116

i.e., the initial salary a =  $116

She was guaranteed a raise of 7% each week.

so, her salary in the next week would be,

116 + 7% of 116

7 percent of 116 is:

116 × 7/100 = 8.12

so, her salary will be $124.12

So, the equation for the salary after 'm' weeks would be,

[tex]n = 116\times (1 + 0.07)^{m - 1}\\\\n = 116\times (1 .07)^{m - 1}[/tex]

Using this equation , the salary in the second week m = 2 would be,

n = 124.12

Salary in the third week m = 3 would be,

n = 116 × [tex](1.07)^{3-1}[/tex]

n = 132.81

Salary in the fourth week m = 4 would be,

n = 116 × [tex](1.07)^{4-1}[/tex]

n = 142.11

Salary in the fifth week m = 5 would be,

n = 116 × [tex](1.07)^{5-1}[/tex]

n = 152.05

Salary in the sixth week m = 6 would be,

n = 116 × (1.07)⁶⁻¹

n = 162.7

Salary in the seventh week m = 7 would be,

n = 116 × (1.07)⁷⁻¹

n = 174.08

Salary in the eighth week m = 8 would be,

n = 116 × (1.07)⁸⁻¹

n = 186.27

Salary in the nineth week m = 9 would be,

n = 116 × (1.07)⁹⁻¹

n = 199.31

And the salary after the tenth week m = 10 would be,

n = 116 × (1.07)¹⁰⁻¹

n = 213.26

The total money after 10 weeks would be,

T = 116 + 124.12 + 132.81+ 142.11 + 152.05 + 162.7 + 174.08 + 186.27 + 199.31 + 213.26

T = $1602.71

This is the required amount.

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The height will be  61.8 ft

Find the volume of prism

Volume = Base Area × Height

since height = 10 feet

5,119.5 ft³ / 10 ft

= 511.95 ft²

formula for the area of a regular polygon is:

Area = (Perimeter × Apothem) / 2

ide length of the pentagon as 's' and the apothem as 'a'

511.95 ft² = (5s × a) / 2

angle at the center of the pentagon is 360° / 5 = 72°

72 / 2 = 36  degrees

tan(36°) = (s/2) / 17.25

solve for the value of s

s = 2 × 17.25 × tan(36°)

= 12.36 ft

5 s =

5 x 12.36 ft

=  61.8 ft

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The solution to the system of equations is:

x = 3, y = 2, z = 2

To solve for x, y, and z, we can use the elimination method or substitution method. Here, we will use the elimination method.

First, we will eliminate y from the equations by multiplying the first equation by 3 and the second equation by 1, and then adding them:

(3) (2x – y + 3z = 10)

6x – 3y + 9z = 30

(1) (x + 3y – 2z = 5)

x + 3y – 2z = 5

Adding the two equations gives:

7x + 7z = 35

Simplifying, we get

x + z = 5 (Equation 1)

Next, we will eliminate y again by multiplying the second equation by 2 and the third equation by 3, and then adding them:

(2) (x + 3y – 2z = 5)

2x + 6y – 4z = 10

(3) (3x – 2y + 4z = 12)

9x – 6y + 12z = 36

Adding the two equations gives:

11x + 8z = 46

Substituting x + z = 5 from Equation 1 into the above equation, we get:

11(x + z) + 8z = 46

11x + 19z = 46

Solving for z, we get:

z = 2

Substituting z = 2 into x + z = 5 from Equation 1, we get:

x + 2 = 5

x = 3

Finally, substituting x = 3 and z = 2 into any of the original equations, we can solve for y:

2x – y + 3z = 10

2(3) – y + 3(2) = 10

6 – y + 6 = 10

y = 2

Therefore, the solution to the system of equations is:

x = 3

y = 2

z = 2

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The greatest of the given integers is 64.

Given that, the sum of four consecutive integers is 250. We need to find what is the greatest of these integers.

Let the consecutive integers be = x, x+1, x+2, x+3

Therefore,

x + x+1 + x+2 + x+3 = 250

4x + 6 = 250

2x + 3 = 125

2x = 122

x = 61

Therefore, the greatest integer = 61 + 3 = 64

Hence, the greatest of the given integers is 64.

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The value of the expression when x = 4 is 12.

The value of the expression when x = -8 is 6.

We have,

To evaluate the expression 10 + x/2 for a given value of the variable x, we simply substitute the value of x into the expression and simplify.

For example:

If x = 4:

10 + x/2 = 10 + 4/2

= 10 + 2

= 12

So when x = 4, the value of the expression is 12.

If x = -8:

10 + x/2 = 10 + (-8)/2

= 10 - 4

= 6

So when x = -8, the value of the expression is 6.

Thus,

The value of the expression when x = 4 is 12.

The value of the expression when x = -8 is 6.

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Answer:

B) 0.08 and 0.1

The answer was 0.09, which is between 0.08 and 0.1

The area of the shaded region for the normal distribution is approximately 0.6985.

We have,
To find the area of the shaded region under the standard normal distribution curve between z = -0.87 and z = 1.24, we can use a standard normal distribution table or a calculator with a standard normal distribution function.

Using a standard normal distribution table, we look up the area to the left of z = -0.87 and the area to the left of z = 1.24 and then subtract the smaller area from the larger area to find the area between z = -0.87 and z = 1.24.

The table value for z = -0.87 is 0.1949, and the table value for z = 1.24 is 0.8934.

The area between z = -0.87 and z = 1.24 is:

= 0.8934 - 0.1949

= 0.6985

So the area of the shaded region is approximately 0.6985.

Thus,

The area of the shaded region for the normal distribution is approximately 0.6985.

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An equation for the height of the rocket after t seconds is h(t) = -16t² + 352t.

The time it takes for the rocket to reach a height of 0 is 22 seconds.

The time it takes to reach the top of its trajectory is 11 seconds.

The maximum height is 1,936 feet.

The time it takes to reach a height of 968 feet is 18.8 or 3.2 seconds.

Based on the information provided, we can logically deduce that the height (h) in feet, of this rocket above the​ ground is related to time by the following quadratic function:

h(t) = -16t² + Vit

When the initial velocity is 352 feet per seconds, the height function becomes;

h(t) = -16t² + 352t

Generally speaking, the height of this rocket would be equal to zero (0) when it hits the ground. Therefore, we would equate the height function to zero (0) as follows:

0 = -16t² + 352t

352t = 16t²

Time, t = 352/16

Time, t = 22 seconds.

Next, we would determine the maximum height of this rocket by taking the first derivate in order to determine the time (t) it takes;

h(t) = -16t² + 352t

h'(t) = -32t + 352

352 = 32t

t = 352/32 = 11 seconds.

h(11) = -16(11)² + 352(11)

h(11) = 1,936 feet.

At a height of 968 feet, the time is given by;

968 = -16t² + 352t

16t² - 352t + 968 = 0

t² - 22t + 60.5 = 0

Time, t = 18.8 or 3.2 seconds.

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Answer:

660,430 gallons AKA 2499.9995045071 kilograms

you would proably round it to 2500 kilograms

Step-by-step explanation:

looked it up, had the same measurements as you gave

Answer:The algebraic steps you have taken are incorrect, leading to an invalid conclusion. Let's go through each step and see where the mistake is made:

X = 1 (given)

X+X = 1+X (adding X to both sides)

2X = 1+X (combining like terms)

2X = X+1 (rearranging terms)

2X-2 = X+1-2 (subtracting 2 from both sides)

2X-2 = X-1 (simplifying)

2(x-1)/(x-1) = (x-1)/(x-1) (dividing both sides by x-1, note that x cannot be 1 as it would result in division by 0)

2 = 1 (canceling out the (x-1)/(x-1) on both sides)

The error lies in dividing both sides by (x-1) in step 7. Although (x-1) appears on both sides of the equation, it is not equal to zero as x cannot be 1 due to division by zero. Dividing by (x-1) effectively cancels it out, leading to the incorrect result of 2=1.

Step-by-step explanation:

The difference of p and z times the sum of p and z is p² - 2pz - z².

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations such as addition, subtraction, division and multiplication.

Hence, the difference of p and z times the sum of p and z can be represented as follows:

Therefore,

(p - z) × (p + z) = (p - z) (p + z)

(p - z) (p + z)  = p² - pz - pz - z²

p² - pz - pz - z² = p² - 2pz - z²

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Note that the difference in the radii of the two circular tracks is about 13.68 ft

recall that the circumference of a circle is denoted by the expression

C = 2πr

In this case, C = Circumference
and r   radius

Since we have two tracks

Let ra = radius of the purple track and

rb = radius of the yello track

So

265 = 2πra

170 = 2πrb

making ra and rb subject of the expression we have

ra = 256/(2π)  =40.7436654315 ≈ 40.74

rb = 170 / (2π) = 27.0563403256 ≈ 27.06

Hence, the difference is

40.74 - 27.06 = 13.68ft

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Full Question:

at a fair Daniel and Claire went on a ride that has two separate circular tracks. Daniel rode in a purple car that travels a total distance of 265 feet around the track . Ciara rode in a yellow car that travels a total distance of 170 feet around the track. They drew drew a sketch of the ride. What is the difference ofthe radii of the two circle tracks

10: HL

11: AAS

12: SSS

13: SSS

14: HL

15: AAS

16: AAS

17: HL

18: AAS

19: SAS

20 AAS

1: SAS

2: ASA

3: HL

4: HL

5: ASA

6: ASA

7: HL

8: SSS

9: HL

Answer: The brother is 16 and she is 19.

Step-by-step explanation:

35 - 3 = 32

32 / 2 = 16

16 + 3 = 19

Answer:

28 hours

Step-by-step explanation:

Let's use "B" to represent the number of hours Bianca practiced.

From the problem, we know that Filipe practiced 12 fewer hours than Bianca, which means:

Filipe's practice time = Bianca's practice time - 12

We are also told that Filipe practiced for 16 hours, so we can substitute that into the equation:

16 = B - 12

To solve for B, we can add 12 to both sides:

16 + 12 = B

So, Bianca practiced for a total of 28 hours.

The probability of the task taking between 48 and 49.9 minutes is 0.1357 or 13.57% (rounded to four decimal places).

To calculate this probability, we first need to find the total probability of the entire range between 43 and 57 minutes. This can be found by subtracting the lower bound from the upper bound and dividing by the total range:

P(43 < X < 57) = (57 - 43) / (57 - 43) = 1

Since the probability of the entire range is 1, we can find the probability of any sub-interval by dividing the length of the sub-interval by the length of the total range. Therefore, the probability of the task taking between 48 and 49.9 minutes is:

P(48 < X < 49.9) = (49.9 - 48) / (57 - 43) = 1.9 / 14 = 0.1357 or 13.57%

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Answer:

B. The candidate received at least 250 votes in half of the 6 towns.

This is because the median number of votes is the middle value when all the vote counts are put in order. This means that at least three towns gave the candidate more than 250 votes, and at least three towns gave the candidate fewer than 250 votes. So, the candidate received at least 250 votes in half of the 6 towns. The total number of votes the candidate received in the election cannot be determined from this information. Similarly, the number of votes received in individual towns cannot be determined.

The system of equations in the context of this problem is given as follows:

The solution is given as follows:

h = 35, c = 55.

The variables used for the system of equations are given as follows:

Considering the Monday's earnings, the equation is given as follows:

5h + 3c = 340.

Considering the Wednesday's earnings, the equation is given as follows:

2h + 6c = 400.

Hence the system is:

Simplifying the second equation by 2, we have that:

h + 3c = 200.

Subtracting the first equation by the second, we can obtain the value of h as follows:

4h = 140

h = 140/4

h = 35.

Hence the value of c is given as follows:

c = (200 - 35)/3

c = 55.

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The total height of the three jumps is A = 20.744 feet

Given data ,

1st high jump score: 7.016 feet

2nd high jump score: 5.42 feet

3rd high jump score: 8.308 feet

On adding the scores , we get

7.016 + 5.42 + 8.308 = 20.744 feet

On simplifying the equation , we get

A = 20.744 feet

Hence , Oliver jumped a total of 20.744 feet in the three high jumps

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