What is the horizontal asymptote of j(x)=14x^3+45/2x^3+x+9

Answer:

a - 48

Step-by-step explanation:

12 cups are divided into 1/4 cup bags.

Converting 12 into a fraction, you get:

12/1 divided by 1/4.

When we divide fractions, we flip the second fraction and change the operation to multiplication.

12/1 * 4/1.

Since 12/1 and 4/1 are now just whole numbers, (12 and 4), we can multiply them together.

12 * 4 = 48.

Answer:

  96°

Step-by-step explanation:

We assume you intend ...

  ΔLMN ~ ΔQRS

Then corresponding angles have the same measure:

  ∠M = ∠R = 26°

  ∠L = ∠Q = 58°

  ∠N = ∠S = 180° -26° -58° = 96° . . . . sum of a triangle's angles is 180°

The measure of angle S is 96°.

Answer:

hope this answer is right 71/45

Step-by-step explanation:

please, this is so easy !

so, please, burn this into your brain forever : the sum of all angles in a triangle is always (really, always) 180°.

so,

180 = 25 + 100 + A

A = 55°

ΔABC has: ∠CAB + ∠ABC + ∠ACB = 180°

so:  ∠CAB = 180° - ∠ABC - ∠ACB = 180° - 100° - 25° = 55°

ANSWER: ∠CAB = 55°

ok done. Thank to me :>

The correct comparison as shown in the figures are:

From the given diagram, we are to fill in the blank spaces with a < or > symbol.

21) The measure of the angles is a function of the measure of the sides.

Since the angle facing the side QR is less than that of QS, hence QR < QS

22) Similarly for this figure, the angle facing the side AB is greater than that of CD, hence AB >  CD

23) Also, for this figure, the side facing the angle m<FJG is greater than the side facing the angle m<HJG, hence m<FJG > m<HJG

24) Also, for this figure, the side facing the angle m<QSP is greater than the side facing the angle m<QSR, hence m<QSP > m<QSR

Learn more on angles here: https://brainly.com/question/16281260

Answer:

y=2/1+7

Step-by-step explanation:

Answer:

Step-by-step explanation:

The domain: { - 25, - 3, 20, 21, 23 }

The range: { - 21, - 14, 4, 8, 13 }

Answer:

110

Step-by-step explanation:

there is a angle of 70 in the other side is there is a total of 180 and subtract 70 you get 110

Answer:

110

Step-by-step explanation:

Answer:

Yes, this is a function

Step-by-step explanation:

You know this because it passes the vertical line test.

I hope this helps!

Answer:

Function

Step-by-step explanation:

Answer:

ok first we round them both

386230 is rounded to 386k

59250 is rounded to 59 k

386+59=445

445,000

Hope This Helps!!!

Answer:

-14x+2(7x)=0

-14×+14×=0

0=0

Answer:

The answer is B

Step-by-step explanation

It's a system ranking people in a hierarchy

Answer:

Step-by-step explanation:

(h, k) = (4, 8)

(y - k) = a(x - h)²

(y - 8) = a(x - 4)²

     y  = a(x - 4)² + 8

plug in one of the x intercepts (or any other known point on the curve)

    0 = a(2 - 4)² + 8

    0 = a(4) + 8

     a = -2

     y  = -2(x - 4)² + 8 fourth option.

Answer:

y= -(x-4)^2+8

Step-by-step explanation:

negative graph since the turning point is +ve 4..thus the equation will be (x-4)^2 the y axis is 8 units up therefore the above equation is the answer

Answer:

32

Step-by-step explanation:

x(48 - 2x) = 32

Hope it helps.

Answer:

(-∞, -1]

Step-by-step explanation:

−x−6≥−5

-x≥1

x≤-1

−2x−5>4

-2x>9

x<-9/2

So x < -9/2 V x ≤ -1

Answer:

(−∞,∞)

Step-by-step explanation:

5x - 4 ≤ - 3

5x ≤ 1

x ≤ [tex]\frac{1}{5}[/tex]

4x + 6 > 0

4x > - 6

x > - [tex]\frac{3}{2}[/tex]

Answer:

y=2x-8

Step-by-step explanation:

y-y1=m(x-x1)

y-4=2(x-6)

y=2x-12+4

y=2x-8

The percentage of students in the 6th grade class that have received dragon  tickets is 84%.

Given the following data:

To determine the percentage of students in the 6th grade class that have received dragon  tickets:

A percentage is used to describe or represent a portion of a given population or total number of something.

Mathematically, the percentage for the given number of students is:

[tex]D = \frac{Students}{Total\;students} \times 100\\\\D = \frac{252}{300} \times 100\\\\D=0.84\times 100[/tex]

D = 84%

Read more on percentage here: https://brainly.com/question/14432715

the bbc lenth is 19 which i like in my mouth an deven my throayt

Answer:

a)12

b)4

c)6

d)10

e)36

f)84

g)45

h)4

Answer:

its the 2nd and the 6th one

Step-by-step explanation:

Answer:

14r

Step-by-step explanation:

since there are 14 members and each sold r tickets r x 14 which is 14r

Answer:

A≈117.81 square inches

Step-by-step explanation:

just plug it in formula.

Answer:

117.8 inches

Step-by-step explanation:

Answer:

13cm

Step-by-step explanation:

substitute values we have into the formula:

1664 = 16 x w x 8

rearrange:

1664/16×8 = w

which equals 13

Answer:

13

Step-by-step explanation: just took the test :)

Answer:

anything but 2

Step-by-step explanation:

f(-1/2)

If you plug in 2, you'd get -1. But if you plug in other values, it won't be equal to -1.

Answer:

5/12

Have a good day!

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]

Answer: The darkness is the correct answer

Step-by-step explanation:

As you know that if the darkness becomes bigger you are unable to see it. Hope you like the answer do let me know in the about your thoughts.