What is the height of the brick?

Answer: 0.3K IS THE DIFFERENCE

Step-by-step explanation:

HOPE IT HELPS =D

Answer:

3k

Step-by-step explanation:

1. Combine multiplied terms into a single fraction

2. Multiply all terms by the same value to eliminate fraction denominators

3. Cancel multiplied terms that are in the denominator

4. Multiply the numbers

The areas of the given triangle and rectangle are 60 cm² and 120 cm² respectively.

What are a triangle and rectangle?

A triangle is a three-sided polygon which has 3 angles formed when two sides join to form a vertex.

A rectangle is a four-sided polygon whose opposite sides have the same lengths and all sides are perpendicular to each other.

The given triangle is a right-angled triangle.

The area of a right-angled triangle is 1/2*b*h

where,

    b= base of the triangle

   h = height of the triangle

From the figure, b = 10 cm and h = 12 cm

     Area of triangle = 1/2*10*12 = 60 cm²

The given rectangles have a length of 12 cm and a breadth of 10cm.

The area of the rectangle is given by the product of breadth and length.

Area of rectangle = 12 * 10 = 120 cm²

Therefore the areas of the given triangle and rectangle are 60 cm² and 120 cm² respectively.

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An equation to represent the relationship is y=15x.

What is linear equation ?

Linear equation can be defined as the equation in which highest degree is one.

Given ,

The table represents a proportional relationship.

So we have to write an equation to represent the relationship

Given,

Time that is

x = {5,8,12 }

Distance that is

y = {75,120,180}

so here from the given table,

75 = 15*5

120 = 8*15

180 = 12*15

hence , it is in the form of y = 15x.

Therefore, An equation to represent the relationship is y=15x.

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Answer:

Step-by-step explanation:I  D   K

a) Does not give an equivalent ratio

b) Does not give an equivalent ratio

c) Does not give  an equivalent ratio

d) Gives an equivalent ratio

An equivalent ratio is a ratio that is equal in value to a given ratio, but may have a different form. Two ratios are equivalent if they have the same relationship between the terms, even if the numbers are different.

In this case, we have the ratio 8/20. The process of addition or subtraction can not be able to give us the equivalent ratio that we are looking for but the multiplication  would do that. Recall that the original fraction is 8/20 so;

a) 10/22 = 5/11

b) 6/18 = 3/9

c) 4/10 = 2/5

d) 16/40 = 8/20

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The probability of obtaining heads on fourth trial is 1/2

In a random experiment of tossing a penny, let H be the event of obtaining head and T be the event of obtaining tail

As it is a fair penny, the probability of obtaining head=1/2

The outcomes of the trials are independent when a coin is tossed multiple times.

Probability of getting three heads ,

P(3H)=P(H∩H∩H)

=P(H)xP(H)xP(H)

=1/2x1/2x1/2

=1/8

We will use conditional probability to find the probability of obtaining head in the fourth trial, given that three heads are already obtained in three trials

P(H|3H)=P(H∩3H)/P(3H)=(1/8x1/2)/(1/8)=1/2

Thus, the required probability is 1/2

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Answer:

a. 1750; b. 900; c. sean 50%, Adrian = 850/3500= 24.3%, James =25.7%

Step-by-step explanation:

Sean got half = 3500/2 =1750

Adrian = 850

James = 3500-1750-850 =900

In the given situation the given values can be correctly modeled by a (B) linear function.

What is a linear function?
A linear function has a straight line as its graph. A linear function has the form shown below. a + bx = y = f (x).

A linear function consists of one independent variable and one dependent variable.

The independent and dependent variables are X and Y, respectively.

In mathematics, the terms "linear function" refers to two distinct but connected concepts: In calculus and related subjects, a polynomial function of degree zero or one with a graph that is a straight line is referred to as a linear function.

Therefore, in the given situation the given values can be correctly modeled by a (B) linear function.

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Answer:

Step-by-step explanation: Hello! You know that there are 3 students who scored 55, 4 students who scored 60, 8 students who scored 65, 4 students who scored 70, 4 students who scored 75, 1 student who scored 80, 9 students who scored 85, and 5 students who scored 90.  To find the mean of a set of values, here is the formula:

a + b + c + d + e . . .

--------------------------

           2

Each variable should represent the score of a single student, so write each score for each individual student.

(55 + 55 + 55 + 60 + 60 + 60 + 60 + 65 + 65 + 65 + 65 + 65 + 65 + 65 + 65 + 70 + 70 + 70 + 70 + 75 + 75 + 75 + 75 + 80 + 85 + 85 + 85 + 85 + 85 + 85 + 85 + 85 + 85 + 90 + 90 + 90 + 90 + 90)/2

You could divide all of this by 2 or you could multiply the values and then add them:

((55 x 3) + (60 x 4) + (65 x 8) + (70 x 4) + (75 x 4) + 80 + (85 x 9) + (90 x 4))/2

Either way works, but the second way is probably faster.

--------------------------------------------------------------------------------------------------

How to find the answer:

55 x 3 = 165
60 x 4 = 240
65 x 8 = 520
70 x 4 = 280
80 = 80
85 x 9 = 765
90 x 4 = 360

Substitute this into the equation

(165 + 240 + 520 + 280 + 80 + 765 + 360)/2

(405 + 800 + 845 + 360)/2

(1205 + 1205)/2

2410/2

= 1205

The answer is 1205

Answer:

y = -4/3x + 4

Step-by-step explanation:

4x+3y=12

3y = -4x + 12

y = -4/3x + 4

For the 5 GB and x GB over use of the data plan per month the total cost paid by Penelope is $160 and $(35 + 25x ).

Let 'x' represents the extra GB used by Penelope in his smart phone data plan.

Cost to used fixed 9 GB of data in a month is equal to $35

Extra charge per GB over the included amount for fixed 9 GB is $25

Equation represents the data plan relation is:

35 + 25x

When Penelope used 5 GB extra over the 9 GB data plan then ,

x = 5GB

Amount to be paid for extra 5 GB is

= 35 + 25( 5 )

= 35 + 125

= $ 160

Amount to be paid for extra 'x' GB is $(35 + 25x).

Therefore, the total cost for extra use of data plan per month is:

a. For 5 GB it is $160.

b. For x GB it is $(35 + 25x).

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The word description "3 to the power of a + 4" should be written as 3^{a + 4}.

In Mathematics, an exponent is sometimes referred to as power and it can be defined as a mathematical operation that is used in conjunction with an algebraic expression to raise a quantity to the power of another and it is generally written as;

bⁿ

Where:

the variables b and n represent numerical values or an algebraic expression.

By applying the property of exponents based on the law of indices for powers, we have the following:

Expression = 3^{a + 4}.

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Complete Question:

What is 3 to the power of a+4?

The area of the triangle is 59.6[tex]m^2[/tex]

Now, According to the question:

The area of a triangle is defined as the total region that is enclosed by the three sides of any particular triangle. Basically, it is equal to half of the base times height, i.e. A = 1/2 × b × h.

In the question, Area unit is not mentioned.

But i take the unit in meter.

Now, We have the given data is:

In triangle HPK:

K = 8 m

P = 14.9 m

To find the area of triangle.

We know that :

Area of Triangle is  = 1/2 × b × h.

A  = 1/2 × 8 × 14.9

A = 59.6 [tex]m^2[/tex]

Hence, The area of the triangle is 59.6

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This is consistent with the solutions for the equation x2 - 6x + 5 = 0 being x = 1 and x = 5.

An equation is a mathematical statement that expresses the equality of two expressions. It consists of one or more terms, each of which contains one or more variables. The terms are separated by an equal sign (=) and are usually written in a standard form known as an algebraic equation. Equations can be used to model and solve problems in a wide variety of fields, from physics and chemistry to economics and finance.

The graph of the quadratic equation is a parabola that opens upward and intersects the x-axis at two points. The x-intercepts occur when the equation is equal to zero, so the x-intercepts for the equation x2 - 6x + 5 = 0 are the solutions for x. These solutions are x = 1 and x = 5.

The graph of the quadratic equation also shows that the two solutions of the equation, x = 1 and x = 5, are the x-intercepts of the parabola. This means that when x equals 1 or 5, the equation is equal to zero, so the x-intercepts are the solutions of the equation. This is consistent with the solutions for the equation x2 - 6x + 5 = 0 being x = 1 and x = 5.

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The problem deals with the concept of simple random sampling and stratified random sampling techniques. Here, use these techniques to identify the correct statement for the given study.

a sampling technique that guarantees each population member or object has the same chance of being selected for the sample.

Stratified random sample: A stratified random sample is created by first separating the population's components into distinct, non-overlapping groups, or strata, and then randomly choosing a sample from each stratum in turn. A stratified SRS is a unique type of stratified sampling that chooses units from each stratum using SRS.

To forecast appraised value from different variables, such as size, age, number of bathrooms, etc., the real estate appraiser may utilize basic random or stratified random samples.

A real estate appraiser must get a random sample of single-family homes in the basic random sample approach in order to analyze or anticipate the necessary qualities.

He must create a basic random sample from each of the ten neighborhood districts that are specified as stratums in the stratified random sample method. He can research or extrapolate the necessary qualities from the sample that was generated. The population in this investigation is limited and recognizable. This makes it enumerative.

An appropriate approach is to create a stratified random sample by selecting a simple random sample from each of the 10 district neighborhoods or to construct a random sample of all single-family residences in the city.

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Answer: The domain of a function is the set of all input values (x-values) for which the function produces a valid output. In the case of the function f(x) = -x + 15, the function will take any real number as input and produce a corresponding output.

Therefore, the domain of the function f(x) = -x + 15 is all real numbers. This can be represented as (-∞, ∞) or simply as "all x".

Option O is correct: x are all real numbers

Option O x ≤ 30, O x > -2, O x >0 are incorrect

Step-by-step explanation:

The average rate of change of demand when the number of items demanded increases from 2 thousand units to 4 thousand units is 401.13 and if it increase from 1 thousand units to 5 thousand units is 201.13

What is Algebraic expression ?

Algebraic expression can be defined as the combination of variables and constants.

Given,

The expression, p(x) = 0.2 x^2 + 1.13x+5.2

where x is given in units of a thousand .

The average rate of change of demand when the number of items demanded increases from 2 thousand units to 4 thousand units.

p(x) = 0.2x^2 + 1.13x+5.2

p(2000 ) = 0.2 (2000*2000) + 1.13 (2000) + 5.2

= 800000 + 2260 + 5.2

= 802265.2

p(4000 ) = 0.2 (4000*4000 ) + 1.13 (4000) + 5.2

= 1600000 + 4520 + 5.2

= 1604525.2

p(2000) - p (4000) / 2000-4000  = 802265.2 - 1604525.2 /  -2000

= -8,02,260 / -2000

= 401.13

p (1000) = 0.2 (1000*1000) + 1.13 (1000) + 5.2

= 200000 + 1130 + 5.2

= 201135.2

p (5000 ) = 0.2 (5000*5000) + 1.13(5000) + 5.2

= 1000000 + 5650 + 5.2

= 1005655.2

p (1000) - p (5000) / 1000 - 5000  = 201135.2 - 1005655.2  / -4000

= 804520 / 4000

= 201.13

Hence, The average rate of change of demand when the number of items demanded increases from 2 thousand units to 4 thousand units is 401.13 and if it increase from 1 thousand units to 5 thousand units is 201.13.

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Ty works 22 hours in weekdays and 14 hours in weekends to earn at least $600 by working a total of 36 hours in a week.

In the question, we have to find how many hours he need work on the weekends.

Let he work x hours on weekdays.

Let he work y hours on weekends.

He works total 36 hours. So the required question is:

x + y = 36..................(1)

Ty earns $14 an hour working on weekdays. If he works x hours, then he earns total 14x.

Ty earns $21 an hour working on weekends. If he works y hours, then he earns total 21x.

He earns total $600.

So the required equation is:

14x + 21y = 600..................(2)

Multiply equation 1 by 21 and subtract by equation 2

21x + 21y - (14x + 21y) = 756 - 600

Simplify

7x = 156

Divide by 7 on both side, we get

x = 22.29

x = 22

Now put the value of x in equation 1, we get

22 + y = 36

Subtract 22 on both side, we get

y = 14

Hence, he works 22 hours in weekdays and 14 hours in weekends.

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True. Testing other points in addition to the vertices is necessary

True. When trying to optimize (find the max or min) of a function, it is not enough to test only the vertices. The function may have a maximum or minimum value at a point that is not a vertex, such as an inflection point, or a point on the edge of the domain.

Thus, testing other points in addition to the vertices is necessary in order to ensure that the maximum or minimum value of the function has been found.

Linear programming is a powerful tool that can be used to model and solve a wide range of real-world problems in fields such as finance, manufacturing, transportation, and resource allocation.

For example, it can help to determine the optimal number of products to produce, the best way to use resources (e.g. labor, materials) and the best scheduling to minimize costs and maximize profits.

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There are 22 purple notebooks in the bin.

There are 37 pink socks in the bin.

In order to determine the number of purple notebooks that are in the bin, we would develop an expression to multiply the total number of notebooks (T) by the percentage of the number of purple notebooks placed in the note bin as follows;

Total number of purple notebooks (P) = 25/100 × 88

Total number of purple notebooks (P) = 0.25 × 88

Total number of purple notebooks (P) = 22 notebooks.

Total number of socks (S) = 50/100 × 74

Total number of socks (s) = 0.50 × 74

Total number of socks (s) = 37 socks.

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The angular speed is 8 rad/s and the angular position of point A  will be 8m/s².

The angular speed of the wheel at t=2s can be calculated using the equation ω=αt, where ω is the angular speed, α is the angular acceleration and t is the time. Substituting the given values, we get ω = 4 (2) = 8 rad/s.

The angular position of point A at t=2s can be calculated using the equation

θ = ωt + (1/2)αt².

Substituting the given values, we get

θ = 8 (2) + (1/2) (4) (2²) = 24 rad.

The total acceleration of point A at t=2s can be calculated using the equation a = rα, where a is the total acceleration, r is the radius of the wheel and α is the angular acceleration. Substituting the given values, we get a = 2 (4) = 8 m/s²

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Answer:  X= - 2

Step-by-step explanation:

The rate of change over 1 ≤ x ≤ 3 is -5.76 and  rate of change over 4 ≤ x ≤ 7 is -2.665.

A relation is a function if it has only One y-value for each x-value.

The general form of an exponential function is:

f(x) = 40(0.8)ˣ

where 40 is the initial value and 0.8 is the decay factor.

To get the average rate of change over an interval, compute the slope of the line that connects the endpoints of the interval (it's called the secant line). For an interval running from x₁ to x₂, the slope formula for a straight line is:

slope = (f(x₂)-f(x₁)) / (x₂-x₁)

where f(x₁) and f(x₂) are the values of your function at x₁ and x₂.

So for the interval 4 ≤ x ≤ 7

slope = average rate of change = (f(7)-f(4)) / (7-4)

=8.388-16.384/3

=-2.665

For the interval  1 ≤ x ≤ 3

Average rate of change =f(3)-f(1)/2

=20.48-32/2

=-5.76

Hence, the Rate of change over 1 ≤ x ≤ 3 is -5.76 and  rate of change over 4 ≤ x ≤ 7 is -2.665.

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Answer:

5

Step-by-step explanation:

1.5+5x

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax n is nax n−1

5x1−1

Subtract 1 from 1.

5x 0

For any term t except 0, t 0 =1.

5×1

For any term t, t×1=t and 1t=t.

5

This is how i would solve it :))

The property descibed by the statement "whatever is done on one side of the equation must also be done on the other side of the equation” is (d) Property of Equality

From the question, we have the following parameters that can be used in our computation:

“whatever is done on one side of the equation must also be done on the other side of the equation”

This means that if x is added to the first side, it must be done on the other side

The property described above is (d)

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As per the combination method,

(a) at least one of each letter is 36

(b) at least two of each letter is 15

(c) at least one A, two Bs, and three Cs is 15

(d)  any number of each letter is 120

(e)  at least one A and at least two Bs is 36

In math the term combination method is known as  the number of possible combinations that can be obtained by taking a sample of items from a larger set.

Here we have given that the value of n is 10 and the value of r is 3.

Then the resulting values are calculated as,

Here for the letters with at least one of each letter then the length is 10 with a 3 elements to choose from the given set.

Here we know that 3 of the 10 slots will be taken up by A,B, and C. With 7 remaining, any letter could take up those spots it will be calculated as,

=> (7+3-1 choose 3-1)

=> (9 choose 2).

=> 36

Where as the other one is with at least two of each letter

Then here we have the letter with two of each letter 6 letters will take up 10 slots no matter what is calculated as,

=> 10-6 = 4

Now then we have 3 to choose from so (4 + 3 - 1 choose 3-1).

=> (6 choose 2)

=> 15

And the another option is to have at least one A, two Bs, and three Cs

=> 1A + 2B + 3C will take up 6 spots.

=> (4+ 3-1 choose 3-1)

=>  (6 choose 2).

=> 15

Where as the count is any number of each letter

=> 10 choose 3.

=> 120

Finally if we take at least one A and at least two Bs

Then at least 1 A and two Bs taking up a total of 3 slots is calculated as,

=> 10 - 3 = 7.

=>  (7 + 3 - 1 choose 3 - 1)

=> (9 choose 2) = 36

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The slope of the line is 1/2 and the y-intercept is 4. Then the correct option is D.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

If you have a different linear equation such as y = (1/2) x + 4. Then the slope and y-intercept of the line are given as,

m = 1/2

y = 4

The slope of the line is 1/2 and the y-intercept is 4. Then the correct option is D.

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All the correct expressions are,

Slope of BC = - 2/5

Slope of CD = 5/2

Slope of DE = - 3/5

Slope of EB = 3

Length of BC = √ 29

Length of CD = √ 29

Length of DE = √34

Length of EB = √40

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

We have to given that;

Coordinate of B = (- 9, 1)

Coordinate of C = (- 4, - 1)

Coordinate of D = (- 2, 4)

Coordinate of E = (- 7, 7)

Now, We know that;

The slope of line passing through the points (x₁ , y₁) and (x₂, y₂) is,

⇒ m = (y₂ - y₁) / (x₂ - x₁)

Thus, Slope of BC is,

⇒ m = (- 1 - 1) / (- 4 - (-9))

⇒ m = - 2/5

Slope of CD is,

⇒ m = (4 - (-1)) / (- 2 - (-4))

⇒ m = 5/2

Slope of DE is,

⇒ m = (7 - 4) / (- 7 - (-2))

⇒ m = 3/- 5

⇒ m = - 3/5

Slope of EB is,

⇒ m = (1 - 7) / (- 9 - (-7))

⇒ m = - 6/-2

⇒ m = 3

Length of CD is,

⇒ CD = √ (- 2 - (-4))² + (4 - (- 1))²

         = √4 + 25

        = √ 29

Length of BC is,

⇒ BC = √ (- 4 - (-9))² + (- 1 - 1)²

         = √25 + 4

        = √ 29

Length of DE is,

⇒ DE = √ (- 2 - (-7))² + (4 - 7)²

         = √25 + 9

        = √ 34

Length of EB is,

⇒ EB = √ (- 7 - (-9))² + (7 - 1)²

         = √4 + 36

        = √ 40

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If 6x/(x²-3x) is subtracted from the sum of 3/(5x-15) and (x+3)/(x-3) , then the result is (12 - 5x)/(x - 3) .

The sum of the algebraic expressions 3/(5x-15) and (x+3)/(x-3)  are written as ; ⇒ 3/(5x-15) + (x+3)/(x-3) ;

taking 5 common from the denominator of the first term ,

we get ;

⇒ 3/5(x-3) + (x+3)/(x-3) ;

taking LCM as 5(x-3) and simplifying further ,

we have ;

⇒ 3/5(x-3) + (x+3)/(x-3) ;

⇒ [3 + 5(x+3)]/5(x-3)  ;

⇒ (5x + 18)/5(x-3)  .......equation(1)

Now 6x/(x²-3x) is subtracted from the equation(1)

⇒ (5x + 18)/5(x-3) - 6x/(x²-3x)  ;

⇒ (5x + 18)/5(x-3) - 6x/x(x-3)  ;

⇒ (5x + 18)/5(x-3) - 6/(x-3)  ;

taking LCM as as 5(x-3) and simplifying further ,

we have ;

⇒ (5x + 18 - 30)/5(x-3)  ;

⇒ (5x -12)/5(x-3)  ;

Therefore , the  final result is (5x -12)/5(x-3) .

The given question is incomplete , the complete question is

If 6x/(x²-3x) is subtracted from the sum of 3/(5x-15) and (x+3)/(x-3) .  What is the result ?

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We can conclude that (1-sinx)(1+cscx)=cscx-sinx is a true equation.

An equation is a mathematical expression containing symbols, constants, and/or numbers that combine to create an equation that states the equality of two mathematical expressions. Equations are used to describe relationships between different quantities and can be used to model real-world phenomena. Equations can also be used to solve problems and make predictions about a system.

To verify that this equation is true, we can use algebraic manipulation. First, we need to expand the left side of the equation. We can do this by multiplying (1-sinx) by (1+cscx). This gives us the equation (1-sinx)(1+cscx) = 1+cscx-sinx-sinxcscx.
Next, we need to simplify the right side of the equation. We can do this by combining the two terms with a minus sign. This gives us cscx-sinx.
Finally, we can compare the two equations. We see that both equations are equal, so the original equation is true.
Therefore, we can conclude that (1-sinx)(1+cscx)=cscx-sinx is a true equation.

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