What is the average amount of time an American spends consuming media in a week?
A. 10 hours
B. 18 hours
C. 22 hours
D. 28 hours
Please collect the best answer from the choices provided
HURRY!!

Answers

Answer 1

Answer: D. 28 hours

Explanation: on edge 2020 :))

Answer 2

The average amount of time an American spends consuming media in a week is 28 hour.

What is Media?

Media is the plural form of medium, which (broadly speaking) describes any channel of communication. This can include anything from printed paper to digital data, and encompasses art, news, educational content and numerous other forms of information.

The average amount of time an American spends consuming media in a week is 28 hour.

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Related Questions

In the human circulatory system, arteries carry blood away from the heart to different parts of the body. Veins carry blood from different parts of the body back to the heart. A scientist claims that the greater the amount of exercise a person performs, the greater the amount of oxygen (O2) the body uses. He records the oxygen concentration in the blood of people while they are riding an exercise bike. The graphs show the results of this investigation.



a. Identify at least two systems within the human body that work together during exercise.

b. Explain how the evidence from the data in the graphs supports or does not support the scientist’s claim.

Answers

Answer:

There are many different systems involved in when we exercise, the three main ones are the Respiratory system which is involved in breathing the circulatory system which is about circulation of blood around the body and finally the muscular system and finally the Muscular system which is about how we move.

Explanation:

If the data consistently do not support the hypothesis, then CLEARLY, the hypothesis is NOT a reasonable explanation of what you are investigating. The hypothesis is rejected, and we search for a new interpretation, an new hypothesis that supports the experimental data

Respiratory and circulatory systems are the two systems within the human body that work together during exercise.

How does the respiratory and circulatory systems work together during exercise?

The respiratory system:

allows the exchange of gases intake of oxygen and exhalation of carbon-dioxide.oxygenation of blood at the lungs.

The circulatory system:

transports deoxygenated blood to the lungs for oxygenation.delivers oxygenated blood to the appropriate tissue.Hence, during exercise more oxygen is used by the body.The claim by scientist is true?

During exercise:

breathing rate increases from about 15 times per minute to roughly 40–60 times per minute.heart rate also rises, providing more oxygen to reach your muscles and allowing them to continue moving.

To learn more about respiratory system, circulatory system, blood, exercise, and oxygen here,

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How does changing the initial mass of the copper affect how much heat energy it has?

Answers

Answer:

Increasing the temperature of the copper made the final temperature increase and decreasing the temperature of the copper made the final temperature decrease. ... How does changing the initial mass of the copper affect how much heat energy it has? The more copper, the more heat energy.

Explanation:

Decreasing the temperature of the copper made the final temperature decrease. But the mass remains constant.

What is heat energy?

Heat is energy that is transmitted from one body to another as a result of a temperature differential. When two bodies of different temperatures come into contact,

Thermal expansion is the tendency of matter to alter its form, area, volume, and density in response to a change in temperature.

Thermal expansion is caused by heating. The mass remains constant. The loudness rises. As a result, the density drops.

To learn more about heat energy refer to the  link;

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A train is travelling at 15 m/s. It accelerates at 3 m/s² for 20 seconds. How far does the train travel in this time?

Answers

The distance traveled by the train is 900 m.

The given parameters:

Initial velocity of the train, u = 15 m/sAcceleration of the train, a = 3 m/s²Time of motion, t = 20 s

What is distance?Distance is a scalar quantity that shows the total path covered by an object.

The distance traveled by the train is calculated as follows;

[tex]s = ut + \frac{1}{2} at^2\\\\s = (15 \times 20) + (0.5 \times 3 \times 20^2)\\\\s = 900 \ m[/tex]

Thus, the distance traveled by the train is 900 m.

Learn more about distance here: https://brainly.com/question/23848540

Answer:

900m

Explanation:

Use the equation: acceleration (a) = change in velocity (v – u) / time taken (t)

Rearrange to solve for the final velocity (v):

v = u + at

Substitute in values and solve:

v = 15 m/s + 3 m/s2 × 20 s = 75 m/s

Rearrange the equation for uniform acceleration (v2 – u2 = 2as) to solve for distance (s):

s = (v2 – u2) / 2a

s = ((75 m/s)2 – (15 m/s)2) / (2 × 3 m/s2)

s = (5,625 m2/s2 – 225 m2/s2) / 6 m/s2

s = 5400 m2/s2 / 6 m/s2

s = 900 m

hey pls help with this HDJSJDH im rlly bad at this kinda stuff :,) i'll mark the correct answer brainliest

Answers

I am pretty sure it’s A
The cue exerts force onto the white ball which pushes the blue ball into the direction of the hole.

Answer:

A. Cue, White Ball, Blue Ball

Explanation:

Visualize in which order things are being hit

A tourist wishes to catch a train in 1.2 hours, which is 115 km away. If she spends the first half-hour going 90km/h, how fast will she need to go to get to station on time?

Answers

Answer:

100km/hr

Explanation:

From the problem statement we know that distance of the trip is 115km

Expected time for the trip = 1.2hrs

→ If she spends the first half-hour going 90km/hr,

    Here  time  = 0.5hr

              speed  = 90km/hr

 The distance covered;

    Distance covered   =  Speed x time

    Distance covered  = 90 x 0.5  = 45km

→The remaining distance will be:

        Total distance - distance covered

              115km  - 45km  = 70km

→ The remaining time;

      1.2hr - 0.5hr  = 0.7hr

 Speed  = [tex]\frac{distance}{time}[/tex]  

  Insert the parameters and solve;

  Speed  = [tex]\frac{70}{0.7}[/tex]   = 100km/hr

For the remaining lap, the tourist must travel at a rate of 100km/hr to catch up.

Write one example situation of Newton's Third Law involving mass that are the same.

Answers

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

HELP PLEASE

A load is a device that changes electrical energy into other forms of energy. Which load converts electrical energy into thermal energy by passing an electric current through a high-resistance material?



A.
Hand-powered generator

B.
Toaster

C.
Fan

D.
Electrical drill

Answers

Answer:

A toaster because you plug it up for electric energy and heat to toast it

plzzzz help me and I will mark u the brainiest

Answers

A.) 3,800
* Add 1800+2000 because they are both going forward, and you are look for the total amount of forward force. Hope this helped good luck!!!

The diagram below shows the velocities of two runners.
11 m/s west
Runner 1
5 m/s east
Runner 2
From the frame of reference of runner 1, what is the velocity of runner 2?
O A. 5 m/s east
O B. 6 m/s east
C. 16 m/s west
O D. 16 m/s east

Answers

Answer : 16 m/s east

Explanation: Trust the process!!

From the frame of reference of runner 1, the velocity of runner 2 will be D) 16 m/s east

What is relative velocity ?

The relative velocity is defined as the velocity of an object with respect to another observer

When two bodies are moving in opposite directions , relative velocity get added and if bodies are moving in same direction , relative velocity will get subtracted .

From the frame of reference of runner 1, the velocity of runner 2 will be

v (relative) = v1 + v1

v1 = velocity of runner 1  = 11m/s west

v2 = velocity of runner 2 = 5m/s

v = 11 + 5 = 16 m/s

correct answer will be O D. 16 m/s east as runner 2 is running in east direction

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Write an equation of the line in slope-intercept form.
Please explain.

Answers

Answer:

 y =  [tex]-\frac{1}{4}[/tex]x + 3

Explanation:

The equation of a straight line is given as:

              y  =  mx + c

y and x are the coordinates

m is the slope

c is the y -intercept

 The y-intercept = 3;

Slope  = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

x₁ = 0

x₂ = 4

y₁ = 3

y₂ = 2

 Slope = [tex]\frac{2-3}{4 -0 }[/tex]  = [tex]-\frac{1}{4}[/tex]

 

       y = mx + c

       y =  [tex]-\frac{1}{4}[/tex]x + 3

Explica la relación entre momento de torsión y aceleración angular mencionando tres ejemplos Una varilla uniforme delgada mide 1.5 m de longitud y tiene una masa de 6kg si la varilla se hace girar en un centro y se queda en rotación con una velocidad angular de 16 rad/seg calcular la cantidad de movimiento

Answers

Answer:

1) τ = I α    whereby the torque is provided by the angular acceleration

2)  L = 216 Kg m² / s

Explanation:

1) Let's start with Newton's second law

       F = m a

multiply by the arm or perpendicular distance

       F r = m a r

if the distance is not perpendicular a way of realizing the relations using the vector product

      τ = F r = F x r

the bold are vectors.  The angular and linear acceleration are related

       a = α r=

         

      τ = m (α r) r

      τ = (m r²) α

the inertia of the rotational motion is

        I = m r²

we substitute

       τ = I α

whereby the torque is provided by the angular acceleration.

As an example we have:

* a spinning disk

* a ball rotating in the air

* a pulley

2) The rotational momentum is

           L = I w

the moment of inertia of a rod that through its center

           I = m L²

we substitute

           L = m L² w

let's calculate

          L = 6 1.5 2 16

          L = 216 Kg m² / s

La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.

1) La relación entre el momento de torsión ([tex]M[/tex]), una variable cinética y relacionada con la aplicación de una fuerza externa cuya línea de proyección no cruza el centro de masa del objeto, y la aceleración angular ([tex]\alpha[/tex]), una variable cinemática, es la resistencia del cuerpo a rotar, la cual es función de su masa y su geometría, representada por la variable de momento de inercia.

A continuación, presentamos tres ejemplos del concepto:

Giro de una tuerca como consecuencia del giro de una llave inglesa por la acción de una mano y un brazo.Transmisión del movimiento a través de la transmisión de una bicicleta.Cierre de una compuerta mediante una transmisión rígida por engranes y un volante.

2) Asumamos que la varilla uniforme es de masa constante, con una rotación a velocidad angular constante y con un centro de rotación localizado en el centro geométrico de la varilla. La cantidad de movimiento es expresada mediante la siguiente ecuación:

[tex]L = I\cdot \omega[/tex] (1)

Donde:

[tex]L[/tex] - Cantidad de movimiento angular, en kilogramos-metro cuadrado por segundo.[tex]I[/tex] - Momento de inercia, en kilogramos-metro cuadrado.[tex]\omega[/tex] - Rapidez angular, en radianes por segundo.

El momento de inercia de una varilla uniforme con centro de rotación en el centro queda expresado por la siguiente fórmula:

[tex]I = \frac{1}{12}\cdot m\cdot L^{2}[/tex] (2)

Donde:

[tex]m[/tex] - Masa de la varilla, en kilogramos.[tex]L[/tex] - Longitud de la varilla, en metros.

Al aplicar (2) en (1), tenemos la expresión resultante:

[tex]L = \frac{1}{12} \cdot m\cdot L^{2}\cdot \omega[/tex] (3)

Si sabemos que [tex]m = 6\,kg[/tex], [tex]L = 1.5\,m[/tex] y [tex]\omega = 16\,\frac{rad}{s}[/tex], entonces la cantidad de movimiento angular es:

[tex]L = \frac{1}{12}\cdot (6\,kg)\cdot (1.5\,m)^{2}\cdot \left(16\,\frac{rad}{s} \right)[/tex]

[tex]L = 18\,\frac{kg\cdot m^{2}}{s}[/tex]

La cantidad de movimiento angular de la varilla uniforme es 18 kilogramos-metro cuadrado por segundo.

Invitamos cordialmente a ver este problema sobre cantidad de movimiento: https://brainly.com/question/17711894

A windshield hits a bug with force of 10 N.
What force does the bug hit the windshield?
Explain using Newton's third law.

Answers

The big hits the windshield with a force of 10N. Newton’s third law states that every action must have an equal and opposite reaction

hey guys, l need some help! what is the weight of potatoes of mass 75 kg on the surface of the earth? (g=9.8m/s square) ans=735N l need process

Answers

Answer:

735N

Explanation:

Weight is a measurement of force.

F = Force

m = mass

a = acceleration

F = m*a

F = 75kg*9.8m/s²

F = 735N


1.
A student pushes against a wall with 20 N of force and the wall does not move. In this situation, the
wall exerts -
A.

A.20 N of force in the same direction as the push.
B.20 N of force in the opposite direction of the push.
C.less than 20 N of force.
D.more than 20 N of force.

Answers

Answer:

B

Explanation:

This is a balanced force. In a balanced force, nothing happens.

The answer is B and he unlocks mastered ultra instinct

Dr. Aloysius found four homogeneous mixtures, but he thinks that only three are alloys. He tests each one and determines their elemental compositions. Which of the following is not a possible alloy?

A. carbon and boron
B. iron an nickel
C. aluminum and magnesium
D. iron, carbon, and nickel

Answers

Answer:

A. carbon and boron

Explanation:

Carbon and boron is not an alloy.

An allow forms between metals and metals using their huge electron could.

Carbon is a non-metal, boron is a also a non-metal

Two non-metals combining together does not make an alloy.

Iron, nickel, aluminum  are all metals.

Answer:

carbon and boron

Explanation:

carbon and boron

Plyometrics can help a person maintain cardiorespiratory fitness. Please select the best answer from the choices provided. T F

Answers

Answer: IT IS TRUE

Explanation:

Hope this helps

Plyometrics can help a person maintain cardiorespiratory fitness T

It is TRUE that plyometrics can help a person maintain cardiorespiratory fitness

Plyometrics

Plyometrics is a type of exercise training that works with the principle of using speed and force of different movements to build muscle power.

Plyometrics include different types of exercises such as pushups, throwing, running, jumping, and kicking.

Learn more about plypmetrics:

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HURRY PLEASE!!I’ll mark you as brainiest!! 15 points

compare the circuits and lightbulbs below. which would be brighter? a or b? explain why.

Answers

Answer:

I think A. would be brighter

Explanation:

Circuit A has only one bulb so it gets 100% of the electricity

Circuit B has two bulbs which means that they only get 50% of the electricity because it has to be split equally.

Hope it helps!

It’s A, I hope this help in some

what is the spring constant for a spring if pulling it back .0391m causes a force in the opposite direction of .922N?
-0.361N
.361N
-2.36N
2.36N

Answers

Answer: correct me if i'm wrong but is it 0.361N

Which Box in the diagram above, should this picture go into?
Box A
ООО
O Box B
O Box C



Plzz answerr idk

Answers

What diagram? There isn’t one

Circle the letter of each factor that determines whether a molecule
is polar or nonpolar.

a. the number of atoms in the molecule
b. the type of atoms in the molecule
c. the number of bonds in the molecule
d. the shape of the molecule

Answers

I believe the answer is C
Hope this helps you

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 3.04 m away from a waterfall 0.585 m in height, at what minimum speed must a salmon jumping at an angle of 41.7 ◦ leave the water to continue upstream? The acceleration due to gravity is 9.81 m/s 2 . Answer in units of m/s.

Answers

Answer:

V₀ = 5.47 m/s

Explanation:

The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:

R = V₀² Sin 2θ/g

where,

R = Range of Projectile = 3.04 m

θ = Launch Angle = 41.7°

V₀ = Minimum Launch Speed = ?

g = 9.81 m/s²

Therefore,

3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)

V₀² = 3.04 m/(0.10126 s²/m)

V₀ = √30.02 m²/s²

V₀ = 5.47 m/s

Explain how bar graphs can show comparisons between 2 topics.

Answers

Answer:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

Explanation:

A bar chart also known as a bar graph can be defined as the graphical representation of data (informations) by using vertical columns or rectangular bars. When a data set is observed, a bar chart can be used to graphically represent or record the total or overall amount of information contained therein. Generally, bar charts are used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

The bar graph has a x-axis and a y-axis used to represent the various categories of data collected.

In this scenario, the x-axis is used to denote the points earned by the teams while the y-axis is used to denote the seasons as seen in the image attached.

Hence, point scores by team (Team A, B and C) per seasons (2002, 2003, 2004 and 2005) can best be compared through the use of a bar chart (graph).

Answer:

Answer above is correct i only put this:

Explanation:

A bar chart is typically used for the comparison of informations obtained from a data collection by representing each value (information) with rectangular bars respectively.

If a rock is found inside of another rock layer, then the rock inside must be younger than that layer surrounding it. Question 1 options: True False

Answers

Answer:

False.

Explanation:

The layer beneath the another rock will be older. The sequence will not matter in the layers of the rock. The layer inside will be older than the upper layer. This is called law of Superposition. Sedimentary rocks forms the youngest layer of the rocks.

what is the coefficent for hydrochloric acid

Answers

Answer:

HCI

Explanation:

I dont know what you mean by coefficient but that's the thing you would see in the periodic table

A man has a mass of 66 kg on Earth. What is his weight in Newtons?

Answers

Answer:

answer is 66 kilograms-force = 647.2389 newtons

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 646.8 \ Newtons }}[/tex]

Explanation:

Weight in Newtons can be found by multiplying the mass times the acceleration of gravity.

[tex]W=m*g[/tex]

The mass of the man is 66 kilograms on Earth.

Earth has an acceleration of gravity that is 9.8 meters per square second.

[tex]m= 66 \ kg \\g=9.8 \ m/s^2[/tex]

Substitute the values into the formula.

[tex]W=66 \ kg *9.8 \ m/s^2[/tex]

Multiply.  

[tex]W=646.8 \ kg*m/s^2[/tex]

1 kg * m/s² is equal to 1 Newton, therefore our answer of 646.8 kg *m/s² is also equal to 646.8 Newtons, or N.

[tex]W=646.8 \ N[/tex]

The man's weight in Newtons in 646.8 Newtons.

How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?

Answers

Answer:

The answer is 5 s

Explanation:

The time taken can be found by using the formula

[tex]t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{20}{4} \\ [/tex]

We have the final answer as

5 s

Hope this helps you

the answer to this question is 5s

Math Practice: Cart A loaded with blocks (600g) moving left at 0.7m/s hits stationary cart B (200g).
After the collision, both carts move left, Cart A at speed 0.27m/s.

What is the velocity of cart B after the collision? Show your work.

Answers

Answer:

The velocity of cart B after the collision is 1.29 m/s.

Explanation:

We can find the velocity of cart B by conservation of linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{A}v_{A_{i}} + m_{B}v_{B_{i}} = m_{A}v_{A_{f}} + m_{B}v_{B_{f}} [/tex]

Where:

[tex]m_{A}[/tex] is the mass of cart A = 600 g = 0.6 kg            

[tex]m_{B}[/tex] is the mass of cart B = 200 g = 0.2 kg

[tex]v_{A_{i}}[/tex] is the inital velocity of cart A = 0.7 m/s

[tex]v_{A_{f}}[/tex] is the final velocity of cart A = 0.27 m/s

[tex]v_{B_{i}}[/tex] is the initial velocity of cart B = 0

[tex]v_{B_{f}}[/tex] is the final velocity of cart B =?

Taking the left direction as the positive horizontal direction:

[tex] 0.6 kg*0.7 m/s + 0 = 0.6 kg*0.27 m/s + 0.2 kg*v_{B_{f}} [/tex]

[tex] v_{B_{f}} = 1.29 m/s [/tex]

                       

Therefore, the velocity of cart B after the collision is 1.29 m/s.

I hope it helps you!  

A high-speed train in Japan travels a distance of 300. kilometers in 3.60 x 103 seconds. What is the average speed of this train? (Turn the time into hours by using a unit conversion)​

Answers

Answer:

The average speed is 83.3 m/s

Explanation:

Unit 2 kinetic energy mastery test

Answers

Answer: kinetic energy is Energy of motion.

Explanation:

A car travels west for 200000 m in 12600 s what’s its velocity

Answers

Answer:

Velocity = 15.87m/s

Explanation:

Given the following data;

Distance, d = 200000m

Time, t = 12600secs

*To find the velocity*

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

[tex]Velocity = \frac{distance}{time}[/tex]

Substituting into the equation, we have;

[tex]V = \frac{200000}{12600}[/tex]

Velocity = 15.87m/s

Therefore, the velocity of the car is 15.87 meters per seconds due west.

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