What does pressure measure

Answers

Answer 1

Answer:

Pressure measurement is the analysis of an applied force by a fluid (liquid or gas) on a surface. Pressure is typically measured in units of force per unit of surface area.

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Answer 2

Answer:

THIS IS YOUR ANSWER I HOPE IT IS HELPFUL PLZ MARKS ME BRANILY
What Does Pressure Measure

Related Questions

Give the ratio that balances out the following equation: ___Cr + ___Pb(NO3)4 ---> ___ Cr(NO3)3 + ____ Pb

Answers

the doge has the answer

Pb(NO3)4

Inquiry Extension Consider a reaction that occurs between solid potassium and chlorine gas. If you start with an initial mass of 15.20 g K, and an initial mass of 2.830 g Cl2, calculate which reactant is limiting. Explain how to determine how much more of the limiting reactant would be needed to completely consume the excess reactant. Verify your explanation with an example

Answers

The 3.13 g of K would be needed to completely react with the remaining [tex]Cl_2[/tex].

To determine which reactant is limiting, we need to calculate the amount of product that can be formed from each reactant and compare them. The reactant that produces less product is the limiting reactant, since the reaction cannot proceed further once it is consumed.

The balanced chemical equation for the reaction between solid potassium and chlorine gas is:

2 K(s) + [tex]Cl_2[/tex](g) -> 2 KCl(s)

From the equation, we can see that 2 moles of K react with 1 mole of [tex]Cl_2[/tex] to form 2 moles of KCl.

First, we need to convert the masses of K and [tex]Cl_2[/tex] into moles:

moles of K = 15.20 g / 39.10 g/mol = 0.388 mol

moles of [tex]Cl_2[/tex] = 2.830 g / 70.90 g/mol = 0.040 mol

Now, we can use the mole ratio from the balanced equation to calculate the theoretical yield of KCl from each reactant:

Theoretical yield of KCl from K: 0.388 mol K x (2 mol KCl / 2 mol K) = 0.388 mol KCl

Theoretical yield of KCl from [tex]Cl_2[/tex]: 0.040 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) = 0.080 mol KCl

We can see that the theoretical yield of KCl from K is 0.388 mol, while the theoretical yield of KCl from [tex]Cl_2[/tex] is 0.080 mol. Therefore, the limiting reactant is [tex]Cl_2[/tex], since it produces less product.

To determine how much more of the limiting reactant would be needed to completely consume the excess reactant, we can use the stoichiometry of the balanced equation.

We know that 1 mole of [tex]Cl_2[/tex] reacts with 2 moles of K to produce 2 moles of KCl. Therefore, the amount of additional K needed to react with the remaining [tex]Cl_2[/tex] can be calculated as follows:

moles of K needed = 0.040 mol [tex]Cl_2[/tex] x (2 mol K / 1 mol [tex]Cl_2[/tex])

                                = 0.080 mol K

This means that 0.080 moles of K would be needed to completely consume the remaining [tex]Cl_2[/tex]. We can convert this to a mass by multiplying by the molar mass of K:

mass of K needed = 0.080 mol K x 39.10 g/mol

                              = 3.13 g K

Therefore, The 3.13 g of K would be needed to completely react with the remaining.

Example verification:

Suppose we had an additional 0.50 g of [tex]Cl_2[/tex] in the reaction. Would all of the K be consumed, or would there still be excess K?

Moles of additional [tex]Cl_2[/tex] = mass of [tex]Cl_2[/tex] / molar mass of [tex]Cl_2[/tex]

Moles of additional [tex]Cl_2[/tex] = 0.50 g / 70.90 g/mol

Moles of additional [tex]Cl_2[/tex] = 0.0070 mol

The theoretical yield of KCl that can be formed from the additional [tex]Cl_2[/tex] is:

0.0070 mol [tex]Cl_2[/tex] x (2 mol KCl / 1 mol [tex]Cl_2[/tex]) x (74.55 g KCl / 1 mol KCl) = 1.04 g KCl

Therefore, the total amount of KCl that can be formed from all of the [tex]Cl_2[/tex] is:

5.95 g + 1.04 g = 6.99 g

The amount of K that would be needed to completely consume all of the [tex]Cl_2[/tex].

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A common asteroid is in the first photograph. Haley's Comet is in the second photograph. What can be inferred about comets and asteroids? Answer A Both have orbits around the Earth that are ellipses B Both are miniature planets because they orbit the Sun C Both could be planetary fragments from the beginnings of solar system formation D Both are made of rock, ice, and solar dust from the beginning of the solar system

Answers

Answer:

D Both are made of rock ,ice and solar dust from the beginning of the solar system

Answer:

The answer is D

Explanation:

Calculate the volume of solvent present in a 55.5%
by volume of 10.5 mL alcohol solution.

Answers

Answer:

I dont know

Explanation:

good luck

Robert Hooke observed a slice of cork under a microscope. He saw what looked like “pores” or “cells” in it. Hooke can assume that the cork is most likely - Answer F A man made material G A type of living organism H A type of mineral J A petroleum based product

Answers

The cork oak tree from which cork is extracted is native to southwest europe and northwest africa. Cork is extracted from cork oak trees without harming the tree. So cork is a type of mineral. The correct option is C.

What is a cork cell?

The dead cells without having intercellular spaces are defined as the cork cells. They appear at the periphery of roots and stems when they grow older and increase in girth. They also have a chemical called suberin in their walls.

It is the suberin which makes them impervious to gases and water. The outer protective coat of a tree is called the cork. It is one of the components of bark of the tree. The tissues of bark become old and the secondary mersitem replaces them.

Cork is made up of multiple thick layers and it protects the tree from bacterial or fungal infection.

Thus the correct option is C.

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What does the cell theory state? Answer F All organisms are composed of a nucleus G All prokaryotes are composed of multiple cells H All prokaryotes are single celled organisms J All organisms are composed of cells

Answers

Answer:

(J) All organisms are composed of cells

write half-reactions that show how H2O2 can act as either an oxidizing agent or a reducing agent, and describe where each of these situations occurred in your testing.

Answers

Answer:

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

Explanation:

When

H2O2 acts as an oxidizing agent

H2O2 + 2e- 2H+--->   2H2O

Reducing agent

H2O2 --> O2 + 2e + 2H+

H2O2 reduces itself to H2O and also oxidizes to O2 simultaneously thereby acting both as an oxidizing and reducing agent .

The equivalence point of a titration corresponds to which of the following?
O the point where equal volumes of acid and base have been used
O Equivalence point is another term for end point
All of the listed options are true
Equivalence point is defined as the point where the pH indicator changes color
O the point where the acid and base have been added in proper stoichiometric amounts

Answers

Answer:

E: the point where the acid and base have been added in proper stoichiometric amounts

Explanation:

Equivalence point in titration is simply the point where the amounts of acid and base used just sufficiently reacts chemically to cause neutralization whereas the endpoint is the point where the indicator of the titration changes colour.

The Equivalence point occurs before the endpoint.

Thus, option E is correct.

Cu+k.HNO3 --> Cu(No3)2+..........+...........

Answers

Answer:

Cu + HNO3 → Cu(NO3)2 + H2O + NO2

Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 (balanced equation)

What is the relative humidity of the air when the dry-bulb temperature is 4°C and the dewpoint is -4°C?
1.
42%
2.
46%
3
51%
4
56%

Answers

Answer:56%

Explanation:

In the dewpoint chart when you line it up it ends up at 56%

The relative humidity of the air when the dry temperature is about 4 degrees and the dew point is about -4 degrees C is 56%. Hence option  4 is correct.

What is dewpoint?

The dew point is the temperature at which the air needs to be colled at a ta constant pressure in order to have an RH of 100%. The dew point is minus four degrees and the RH of the air is 4 degrees.

For the forces to initiate the air must get cooler and a constant addition of water pressure should be there. Thus substrating the temperature of the wet bulb, putting the thermometer on the dry bulb, and making use of the RH chart tells us that RH is 56%

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In calorimetry, energy is measured through heat transfer from one substance to
another. Which of the following is NOT a method of heat transfer?

Answers

I think you forgot to add a picture?

Answer:

Refraction

Explanation:

Which of the following would be considered an Exothermic Reaction?*
Ice Melting
Burning wood
Boiling water
Baking a cake

Answers

Answer:

Burning wood

Explanation:

the fire releases heat into the air from the burning wood

A student pours 10.0 g of salt into a container of water and observes the amount of time it takes for the salt to dissolve. She then repeats the process using the same amounts of salt and water but this time she slowly stirs the mixture while it is dissolving. The student performs the experiment one more time but this time she stirs the mixture rapidly.

Answers

Answer:

It will go faster each time because she is stirring therefore the water can get to the salt faster than it just sitting at the top

Explanation:

When 12.00 moles of potassium chlorate decomposes, how many dm3 of oxygen are produced at 325K and 188 kPa?
2KClO3 →2KCl + 3O2
show work pls

Answers

Answer:

258.71 dm³

Explanation:

We'll begin by calculating the number of mole of O₂ produced by the decomposition of 12 moles of KClO₃. This can be obtained as follow:

The balanced equation for the reaction is given below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 moles of KClO₃ decomposed to produce 3 moles of O₂.

Therefore, 12 moles of KClO₃ will decompose to produce = (12 × 3)/2 = 18 moles of O₂.

Finally, we shall determine the volume of the O₂. This can be obtained as follow:

Temperature (T) = 325 K

Pressure (P) = 188 KPa

Number of mole (n) = 18 moles

Gas constant (R) = 8.314 KPa.dm³/Kmol

Volume (V) =?

PV = nRT

188 × V = 18 × 8.314 × 325

188 × V = 48636.9

Divide both side by 188

V = 48636.9 / 188

V = 258.71 dm³

Thus, 258.71 dm³ of oxygen were obtained from the reaction.

0.850 moles of N2 originally at 85°C is cooled such that it now occupies 17.55L at 1.25 atm. What is the final temperature of the gas?

Answers

you know at condition 2
P = 1.25atm
V = 17.55L
T = ?
R = 0.08206 Latm/molK
n = 0.850 mol

so you can use
PV = nRT
to solve for T

T = PV / (nR)
T = (1.25atm) x (17.55L) / (0.850mol x 0.08206 Latm/molK)
T = 314.5K = 41.1°C

The final temperature of the gas is 269.9 K, or -3.25 °C, which was calculated with the help of ideal gas equation.

What is the ideal gas equation?

The ideal gas equation gives the relation between pressure, volume and temperature.

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

To find the initial volume of the gas. We can use the fact that the number of moles of gas does not change during the cooling process:

n = 0.850 moles

We can also use the ideal gas law to find the initial volume of the gas:

PV = nRT

V = nRT/P

where R = 0.08206 L atm/K mol is the gas constant.

Convert the initial temperature from Celsius to Kelvin:

T1 = 85 °C + 273.15 = 358.15 K

Substitute the given values into the equation:

V₁ = (0.850 mol)(0.08206 L atm/K mol)(358.15 K)/(1 atm) = 24.03 L

Now we can use the combined gas law to find the final temperature:

(P₁V₁/T₁) = (P₂V₂/T₂)

Substitute the given values into the equation:

(1.25 atm)(24.03 L)/(358.15 K) = (P₂) (17.55 L)/(T2)

Solve for T₂:

T₂ = (P₂)(17.55 L)(358.15 K)/(1.25 atm)(24.03 L)

T₂ = 269.9 K

Therefore, the final temperature of the gas is 269.9 K, or -3.25 °C.

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when rolling a number cube 500 times, how many times you expect to get a 3?

Answers

Answer:

[tex]\frac{250}{3}[/tex]

Explanation:

you can expect to get a 3 (theoretically) 1 time every 6 times you roll. A 1/6 chance.

Here's the equation:

[tex]\frac{1}{6} =\frac{x}{500}[/tex]

cross multiply (i think that's what it is called)

500=6x

divide by 6 on both sides:

x=[tex]\frac{250}{3}[/tex] or approx 83 times.

Hope this helps! Lmk if u have more questions <3

Convert 7.8 moles of carbon tetrafluoride into grams.

Answers

Answer:

686.43363984 is the answer when 7.8 moles is converted.

Calculate how many grams of methane (CH4) are in a sealed 800. mL flask at room temperature (22 °C) and 780. mm of pressure. Show work pls.

Answers

"0.0340" mol of CH₄ are in sealed flask.

Methane (CH₄)

Methane would also be a greenhouse gas, therefore its existence tends to affect humanity's surface temp as well as weather patterns framework; it is released into the atmosphere from such a wide assortment of life forms as well as biogenic.

According to the question,

Volume, V = 800 mL or, 0.800 L

Temperature, T = 22°C or, 295

Pressure, P = [tex]\frac{780}{760}[/tex] = 1.03 atm

As we know the relation,

The gram of moles will be will be:

→ n = [tex]\frac{PV}{RT}[/tex]

By substituting the values, we get

     = [tex]\frac{1.03\times 0.800}{0.08206\times 295}[/tex]

     = [tex]\frac{0.824}{242.077}[/tex]

     = 0.0340

Thus the response above is correct.

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What is the volume of a balloon if it contains 3.2 moles of helium at a temperature of 20. °C and standard pressure?

Answers

Answer:

1.14 mol

Explanation:

The concept ideal gas law can be used here to determine the volume of the balloon. The volume of the balloon is 76.97 L.

What is ideal gas law?

The combination of Boyle's law, Charles's law and Avogadro's law leads to an equation which gives the combined effect of change of temperature and pressure on the volume of a gas.

According to Boyle's law, V ∝ 1/P

According to Charles's law, V ∝ T

According to Avogadro's law, V ∝ n

On combining all these equations, the ideal gas equation is given as:

PV = nRT

P - Pressure

V - Volume

n - Number of moles

R - Universal Gas constant

T - Temperature

Here the standard pressure is 1 atm

20°C = 20 + 273 = 293 K

V = nRT / P

3.2 × 0.0821 × 293 / 1

= 76.97 L

Thus the volume of balloon is 76.97 L.

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Explain the term orbital.​

Answers

Answer: a mathematical expression describing the probability of finding an electron at various locations; usually represented by the region of space around the nucleus where there is a high probability of finding an electron

Explanation:

Which organic compound listed below does not have a carbonyl group ?

A. Aldehyde
B. Ketone
C. Ethers
D. Protein
E. Ester
F. Amides

Answers

I believe the answer is F

PLEASE HELP I HAVE 19 MINUTES LEFT I WILL MARK BRAINLIEST
How much more acidic is a pH of 4 as compared to a pH of 6.5?

Answers

Answer:

316.227766

Explanation:

Answer 3.16 hope it helps

What are the missing coefficients for C3H8 + o2 = Co2 +H2O

Answers

Answer: C3H8 + 5O2 = 3Co2 +4H2O

Explanation: Equations must be balanced

You must have the same amount of C

H and O on both sides of the equation

A balloon is inflated to a volume of 8.0 L on a day when the atmospheric pressure is 1.013 bar . The next day, a storm front arrives, and the atmospheric pressure drops to 0.968 bar . Assuming the temperature remains constant, what is the new volume of the balloon, in liters

Answers

Answer:

[tex]V_2=8.4L[/tex]

Explanation:

Hello there!

In this case, according to the definition of the Boyle's law, which describes de pressure-volume behavior as an inversely proportional relationship, it is possible for us to write:

[tex]P_1V_1=P_2V_2[/tex]

Thus, since we are given the initial pressure and temperature, and the final pressure, we are able to calculate the final volume as shown below:

[tex]baV_2=\frac{P_1V_1}{P_2}\\\\V_2=\frac{8.0L*1.013bar}{ 0.968bar}\\\\V_2=8.4L[/tex]

Regards!

A student weighs 0.347 g of KHP on a laboratory balance. The KHP was titrated with NaOH and the concentration of the NaOH determined to be 0.110 M. For the second titration, the student correctly diluted 6 M HCl from the reagent shelf using a graduated cylinder to obtain approximately 0.6 M HCl. This solution was titrated with the original NaOH solution. The student calculated the concentration of NaOH from the experiment to be 0.099 M. In which experiment should the student be more confident of the concentration of the NaOH solution

Answers

Answer:

Following are the solution to the given question:

Explanation:

Each method through KHP is somewhat more precise since we have weighed that requisite quantity, we exactly know the KHP intensity appropriately. Its initial 6 M HCl concentration was never considered mandatory. They have probably prepared 6 M HCl solution although long ago and could have changed its concentration over even a period.

given mass of nitrogen is 0.12 dm^3 at 60°C and 1.01*10^5 Nm^2. Find its pressure at the same temperature if its volume is changed to 0.24 dm^3​

Answers

50500Nm^2 or 5.05Nm^2

Explanation:

so bring out the parameters

p1= 0.12dm3, T1= 60c , because temperature is in kelvin add 273= 333k, v1= 0.12dm3 , T2= to the same value because the temperature didn't change = 333k, v2= 0.24dm3,P2= ?

general gas equation p1v1 over T1 = P2V2 over T2, when you input everything or make p2 the subject of the formula first you'll get the answer, pressure can have an s.i unit of mmhg but I'm using the same si unit as the question given and always check your units in the question to convert. please if this question has options please check, I don't want you to fail so verify from others if I made a mistake

A balloon is filled with 3.50 L of water at 24.0°C. What is the volume of the water at 307 K?

Answers

Answer:

what is the volume of the water at 307 k?

explain why hydrogen chloride does not conduct electricity, but a solution of hydrogen chloride and water conduct electricity

Answers

The answer is… Ions are highly charged species that can readily conduct an electrical current. But hydrogen chloride the gas does not exist as ions since there is no solvent medium for them to dissolve into. Hope this helps!

0.41g of neon is held in a 200. mL container at 11 °C. Calculate the pressure in atm.

Answers

Answer:

2.39 atm

Explanation:

We'll begin by calculating the number of mole in 0.41 g of neon (Ne). This can be obtained as follow:

Mass of Ne = 0.41 g

Molar mass of Ne = 20 g/mol

Mole of Ne =.?

Mole = mass / molar mass

Mole of Ne = 0.41 / 20

Mole of Ne = 0.0205 mole

Next we shall convert 200 mL to L.

1000 mL = 1 L

Therefore,

200 mL = 200 mL × 1 L / 1000 mL

200 mL = 0.2 L

Next, we shall convert 11 °C to Kelvin temperature.

T(K) = T(°C) + 273

T(°C) = 11 °C

T(K) = 11 + 273

T (K) = 284 K

Finally, we shall determine the pressure. This can be obtained as follow:

Mole of Ne (n) = 0.0205 mole

Volume (V) = 0.2 L

Temperature (T) = 284 K

Gas constant (R) = 0.0821 atm.L/Kmol

Pressure (P) =?

PV = nRT

P × 0.2 = 0.0205 × 0.0821 × 284

P × 0.2 = 0.4779862

Divide both side by 0.2

P = 0.4779862 / 0.2

P = 2.49 atm

Therefore, the pressure of the gas is 2.39 atm

Question 6 (4 points)
(08.02 MC)
What is the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water? (4 points)
а
26.596
D
20.946
с
18.296
d
16.796

Answers

Answer:

20.9%

Explanation:

I took the test i hope this helps:)

The percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%. This is calculated using the definition (formula) of percentage by mass of a solution.

What is meant by percentage by mass?

The mass percent of a solution is defined as the ratio of the mass of solute that is present in a solution, relative to the mass of the solution, as a whole.

The formula for percentage by mass is given as

percentage by mass = (mass of the solute/ total mass of the compound solution) × 100

Calculating percentage by mass for the given solution:

The mass of the solute ( the chemical which is going to be dissolved) HCl

= 27.0 grams

The mass of the solvent (the substance in which a solute dissolve) water

= 102.0 grams

So, the total mass of the solution = 27.0 + 102.0 = 129.0 grams

Then, the percentage by mass = [tex]\frac{27.0}{129.0}[/tex] × 100 = 20.93%

Which is approximate equal to 20.946 at option B.

Therefore, the percentage by mass of solution formed by dissolving 27.0 grams of HCl in 102.0 grams of water is 20.93%.

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