Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass of 0.8 kg. The spring is released and causes the two carts to push off from each other. Which of the following correctly compares the motion and forces acting on the two carts?

A. Cart A experiences a greater force but has the same speed as Cart

B. Cart A experiences a greater force and has a greater speed after the recoil.

C. Both carts experience the same force but Cart A has a greater speed after the recoil.

D. Both carts experience the same force and have the same speed after the recoil.

Answers

Answer 1

Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Mass of the cart A = 0.4 kgMass of the cart B = 0.8 kg

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

[tex]m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s[/tex]

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

[tex]F_A = -F_B[/tex]

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238


Related Questions

please help me !! i’ll give you brainliest if you get the answer right!

Answers

Answer: 25N to the right

Explanation: 35N - 10N = 25N

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the two balls collide, the final momentum of the cue ball is 0.01 kg m/s

Answers

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

Which substances are inorganic? Check all that apply.

C6H12O6
K2CO3
C4H10
C27H46O
Fe3O4

Answers

The major characteristic an organic compound has which an inorganic

compound doesn't  have is the presence of carbon atoms in the molecule.

This helps us to differentiate the compounds into their respective divisions.

Inorganic compounds

K2CO3Fe3O4

Organic compounds

C6H12O6C4H10C27H46O

We can observe that inorganic compounds lack carbon atoms which makes

the answer valid.

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Answer:

B and E because yk thats the asnwer

how to find initial velocity without acceleration

Answers

Answer:

actually you can't find it without acceleration.

you need to use one of these three equations

1- Vf = Vi + at

2- 2ad = Vf^2 - Vi^2

3- d = Vit + 1/2 at^2

Object 1 has a mass of 7.0kg and a initial velocity of 17.0 m/s. Object 2 has a mass of 8.0kg and a initial velocity of -14.0 m/s. What are the final velocitys of each object. Please show work

Answers

[tex]\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3[/tex]

[tex]\\ \sf\longmapsto 7(17)+8(-14)=(7+8)v3[/tex]

[tex]\\ \sf\longmapsto 119-112=15v3[/tex]

[tex]\\ \sf\longmapsto 15v3=7[/tex]

[tex]\\ \sf\longmapsto v3=7/15[/tex]

[tex]\\ \sf\longmapsto v3=2.1m/s[/tex]

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational Force

Explanation:-

The magma flows through the gap between the rocks which are stacked up on top of one another.

The gravity attracts the magma to do that.

Also the rocks are stacked because of the gravitational force between them

Hence Option D is correct

Hope it helps

Answer:

pls mark me as brainliest

Explanation:

last one

whats 10x10 PLEASE I NEED THIS

Answers

10 x 10
= 100

Hope you find this helpful! for solving such a difficult equation :3

Brainliest and a like is much appreciated!

Answer:

100

Explanation:

the only two forces acting on a body have magnitudes of 20 n and 35 n and directions that differ by 80. the resulting acceleration has a magnitude of 20 m/s2. what is the mass of the body?

Answers

Answer:

the mass of the body is 2.75 kg

__________ refers to the distinctive character of a sound, or the quality that allows one to distinguish it from other sounds of similar pitch and loudness.

Answers

timbre

The answer is timbre. Timbre is a feature of
the sound, which is a wave. Other features of
sound are pitch (related with frequency) and
loudness. Timbre is the feature of sound that
permit ear to distinguish sounds with the
same frequency and loudness

A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.

Answers

Hi there!

To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.

Recall:

[tex]\large\boxed{F_D = \mu N}}[/tex]

The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.

[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]

We can plug in the known values to solve for one part of the normal force:

N = (1)(9.8)(cos30)  + F(.5) = 8.49  + .5F

Now, we can plug this into the equation for the dynamic friction force:

Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F

For a block to move with constant speed, the summation of forces must be equivalent to 0 N.

If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:

Fcosθ = 1.697 + .1F

Solve for F:

Fcos(30) - .1F = 1.697

F(cos(30) - .1) = 1.697

F = 2.216 N

A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?

Answers

Answer:it was lifted

Explanation:

by me lifting it because i can life it very high

place any object (textbook, pen, or eraser) on a floor what happens then​

Answers

Answer:

The force of gravity on earth, no matter the object is approximately 9.8 m/ s2 . The reason the crumpled paper hits the ground first is because of air resistance. A crumpled piece of paper has less surface area than an piece of paper that is not crumpled. More surface area means more air resistance.

train travels 1/4of its total distance over half of its time with a constant velocity of 5m/s. calculate the average velocity​

Answers

Let D be the total distance (say in meters) traveled by the train and T the time (say in seconds) it takes to do so. (Assume the train moves in a straight line in only one direction.) Then the average velocity of the train as it covers this distance is

v (ave) = D/T

We're told the train can traverse a distance of D/4 in a matter of T/2 seconds if it moves at a speed of 5 m/s. This means

D/4 = (5 m/s) (T/2)

⇒   5 m/s = 1/2 D/T

⇒   v (ave) = D/T = 10 m/s

The smallest possible particle of complete matter is the atom. True or false?

true

false

Answers

Answer:

TRUE !!

Explanation:

An atom is the smallest particle of an element

A billiard ball with a speed of 5 m/s strikes another stationary billiard ball in a perfectly elastic collision.

After the collision, the first ball has a speed of 4.35 m/s and is traveling at an angle of 30° below its original line of motion.

Find the speed and angle of the second ball, with respect to the initial line of motion, after the collision.

Answers

Assuming both billiard balls have the same mass, conservation of momentum says

[tex]m\vec v_1 + m\vec v_2 = m{\vec v_1}\,' + m{\vec v_2}\,'[/tex]

where m = mass of both billiard balls, and v₁ and v₂ = their initial velocities, and v₁' and v₂' = their final velocities. The masses are the same so the exact value of m is irrelevant. The first ball has initial speed 5 m/s and the second is at rest, so

[tex]\left(5 \dfrac{\rm m}{\rm s}\right) \, \vec\imath = {\vec v_1}\,' + {\vec v_2}\,'[/tex]

After the collision, the first ball has speed 4.35 m/s and is moving at angle of 30° below the original path, so

[tex]{\vec v_1}\,' = \left(4.35\dfrac{\rm m}{\rm s}\right)\left(\cos(30^\circ) \, \vec\imath + \sin(30^\circ) \, \vec\jmath\right) \approx \left(3.77 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(-2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

Then the second ball has final velocity vector

[tex]{\vec v_2}\,' \approx \left(1.23 \dfrac{\rm m}{\rm s}\right) \vec\imath + \left(2.18 \dfrac{\rm m}{\rm s}\right) \vec\jmath[/tex]

so it moves with speed

[tex]\left\|{\vec v_2}\,'\right\| \approx \sqrt{\left(1.23\dfrac{\rm m}{\rm s}\right)^2 + \left(2.18\dfrac{\rm m}{\rm s}\right)^2} \approx \boxed{2.50 \dfrac{\rm m}{\rm s}}[/tex]

at an angle of

[tex]\theta \approx \tan^{-1}\left(\dfrac{2.18}{1.23}\right) \approx \boxed{60.5^\circ}[/tex]

or about 60.5° above the original line of motion.

a q deben los cambios de la materia??

Answers

Answer:

wat

Explanation:

What does the Area under a Speed-time graph represent?
A. acceleration
B. average speed
C. deceleration
D. distance travelled

Answers

Answer:

d. distance travelled

Explanation:

answer

What effect do shiny metals have on radiant energy?

Answers

Answer:

Metals conduct heat and reduce the kinetic energy within the components that need to remain cool

A 50 kg pitcher throws a baseball with a mass of 0. 15 kg. If the ball is thrown with a positive velocity of 35 m/s and there is no net force on the system, what is the velocity of the pitcher? â’0. 1 m/s â’0. 2 m/s â’0. 7 m/s â’1. 4 m/s.

Answers

The velocity of the pitcher at the given mass is 0.1 m/s.

The given parameters:

Mass of the pitcher, m₁ = 50 kgMass of the baseball, m₂ = 0.15 kgVelocity of the ball, u₂ = 35 m/s

Let the velocity of the pitcher = u₁

Apply the principle of conservation of linear momentum to determine the velocity of the pitcher as shown below;

m₁u₁ = m₂u₂

[tex]u_1 = \frac{m_2 u_2}{m_1} \\\\u_1 = \frac{0.15 \times 35}{50} \\\\u_1 = 0.105 \ m/s\\\\u_1 \approx 0.1 \ m/s[/tex]

Thus, the velocity of the pitcher at the given mass is 0.1 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/13589460

A car accelerates at a constant rate of 3 m/s2 for 5 seconds. If it reaches a velocity of 27 m/s, what was its initial velocity?

A
15 m/s

B
42 m/s

C
12 m/s

D
2.1 m/s

Answers

The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

CALCULATE INITIAL VELOCITY:

The initial velocity of the car can be calculated by using one of the equation of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration due to gravity (m/s²)t = time (s)

According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:

u = v - at

u = 27 - 3(5)

u = 27 - 15

u = 12m/s.

Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.

Learn more about motion at: https://brainly.com/question/974124

can somebody explain it to me please?​

Answers

Range be R and height be h

[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]

[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]

u=initial velocity

theta is angle of projection.

g=acceleration due to gravity

ATQ

[tex]\\ \sf\longmapsto R=2h[/tex]

[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]

Cancelling required ones

[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]

sin2O=2sinOcosO

[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]

[tex]\\ \sf\longmapsto tan\theta=2[/tex]

[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]

[tex]\\ \sf\longmapsto \theta=63.4°[/tex]

Done

Option B is correct

What force is responsible for how magma flows and rocks stack up on top of one another?

Question 6 options:

Electroweak and Strong


Nuclear


Electromagnetic


Gravitational

Answers

Gravitational force is responsible for how magma flows and rocks stack up on top of one another.

Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.

The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.

Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.

Learn more about gravitational force: https://brainly.com/question/24783651

how is the rate of evporation of a liquid affected by temperature, the surface area of a liquid exposed to air

Answers

As temperature increases, rate of evaporation also increases. This is due to increasing kinetic energy of the surface molecules which leads them to free and become vapour. c. As surface area increases, rate of evaporation also increases.

when do magnets have the most potential energy

Answers

Answer:

Explanation:

Permanent magnets do have potential energy, stored in their magnetic field. That energy can be compared to the potential energy of some compressed spring. See the picture below, representing the magnetic field lines of a magnetized sphere : These lines are compressed inside the magnet.

Honestly I think it’s the pill

Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o
2. List two realistic criteria for the sub-problem.
o
o
3. Explain why it is important for these criteria to be met in order to solve the problem.
o
4. List two constraints for the sub-problem.
o
o
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
PLEASE HELP ME I DONT UNDERSTAND<333

Answers

Answer:

Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.

Explanation:

I got this from quizlet :)

what is the prmary source of energy inside of the earth

Answers

The correct answer is the energy of the sun
The primary source would be the sun

A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
-10°C. What is the change in volume? *
A. It will increase by 0.18 m
B. It will decrease by 0.18 m'
C.It will increase by 0.05 m
D. It will decrease by 0.05 mº

Answers

T1=40°C=313KT_2=-10°C=263K

Applying Charles law

[tex]\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}[/tex]

[tex]\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}[/tex]

[tex]\\ \sf\Rrightarrow V_2=84.02ml[/tex]

Select the correct answer

1. Instruments that produce sound are called sources of light.

2. Music has no ability to heal the mental stress.

3. A medium is necessary for sound travel.

4. We hear sounds of frequencies below 20 Hz. O First answer O Second answer O Third answer O Forth answer​

Answers

Answer:

C or 3

Explanation:

A: no they are called sources of sound. A is incorrect.

B: It does. Many people attest to this. But this is not a property of physics.

C: A media is required is the correct answer.

D: Dogs might. In general we don't.

I would pick C

How many kilojoules are in 1,967,256J? Round your answer to the nearest whole number.

Answers

Answer:

1,967 kilojoules.

Explanation:

1 kilo = a thousand.

There are 1.967 kilojoules in 1,967,256 joules.

What is law of energy conservation?Energy can neither be created nor destroyed.It is only get transfered from one form to another form.

What is the SI unit of energy?Joule is a SI unit of energy.There are 1000 joules in 1 kilojoules .

learn more about unit of energy here - https://brainly.com/question/3012083

#SPJ2

A 5kg ball is on top of the school building at a height of 40m above the ground.
A. calculate the potential energy of the ball at that height.


B. How much power would it take to get the ball from the ground to that height in 1 minute.


C. If it is dropped what type of energy will the ball have as it approaches the ground.


D. What speed will the ball hit the ground

Answers

Answer:

A-Caclcuate the potential energy of the ball at that height

Explanation:

(a). Mass of the Body = 10 kg.

Height = 10 m.

Acceleration due to gravity = 9.8 m/s².

Using the Formula,Potential Energy = mgh

= 10 × 9.8 × 10 = 980 J.

(b). Now, By the law of the conservation of the Energy, Total amount of the energy of the system remains constant.

∴ Kinetic Energy before the body reaches the ground is equal to the Potential Energy at the height of 10 m.

∴ Kinetic Energy = 980 J.

(c). Kinetic Energy = 980 J.

Mass of the ball = 10 kg.

∵ K.E. = 1/2 × mv²

∴ 980 = 1/2 × 10 × v²

∴ v² = 980/5

⇒ v² = 196

∴ v = 14 m/s.

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