Answer:
C₁₀ = 6.3 KN
Explanation:
The catalog rating of a bearing can be found by using the following formula:
C₁₀ = F [Ln/L₀n₀]^1/3
where,
C₁₀ = Catalog Rating = ?
F = Design Load = 2.75 KN
L = Design Life = 1800 rev/min
n = No. of Hours Desired = 10000 h
L₀ = Rating Life = 500 rev/min
n₀ = No. of Hours Rated = 3000 h
Therefore,
C₁₀ = [2.75 KN][(1800 rev/min)(10000 h)/(500 rev/min)(3000 h)]^1/3
C₁₀ = (2.75 KN)(2.289)
C₁₀ = 6.3 KN
in a vehicle you're servicing the fuel pressure drops rapidly when the engine is says that one or more turned off. Technician a says that one or more could be leaking technician b says that a defective check valve in the fuel pump could be the cause who is correct
Answer:
Both Technicians A and B are correct
Explanation:
If the fluid pressure will decrease quickly in a car when the ignition says that one or more has been switched off. One or two could be leaking or the source could be a faulty check mechanism in the catalytic converter.
6. You are an electrician working in an industrial plant. You are building a motor control cabinet that contains six motor starters and six pilot lamps. All control components operate on 120 volts AC. Two of the motor starters have coil currents of 0.1 amperes each and four have coil currents of 0.18 amperes each. The six pilot lamps are rated at 5 watts each. The supply room has control transformers with the following rating (in volt-amperes):
75, 100, 150, 250, 300, and 500.
Which of the available control transformers should you choose to supply the power for all the control components in the cabinet?
Answer:
It's indeed safer to suggest a 150 VA transformer. Following table however is the clarification given.
Explanation:
For 2 motors with 0.1 A, the Power will be:
P = [tex]2\times 120\times 0.1[/tex]
= [tex]24 \ W[/tex]
For 4 motors with 0.18 A, the Power will be:
P = [tex]4\times 120\times 0.18[/tex]
= [tex]86.4 \ W[/tex]
As we know, for 6 pilot lamps, the power is "5 W".
So,
The total power will be:
⇒ P = [tex]24+86.4+5[/tex]
= [tex]115.4 \ W[/tex]
Now,
Consider the power factor to be "0.95"
VA of transformer is:
= [tex]PF\times Power[/tex]
= [tex]115.4\times 0.9[/tex]
= [tex]109.63 \ VA[/tex]
Common car loan duration
Answer:
In 2019, the average term length was 69 months for new cars and 65 months for used vehicles. Most car loans are available in 12 month increments, lasting between two and eight years. The most common loan terms are 24, 36, 48, 60, 72, and 84 months, according to Autotrader
Explanation:
Help please all of the numbers b4 the equal sign are wrong
Answer:
3/5" = 12'1 3/4" = 35'1 1/4" = 25'9/10" = 18'2 13/20" = 53'Explanation:
One number is wrong; they all lack units.
The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.
3/5" = 12'1 3/4" = 35'1 1/4" = 25'9/10" = 18'2 13/20" = 53'Perhaps you want decimal inches:
0.60" = 12'1.75" = 35'1.25" = 25'0.90" = 18'2.65" = 53'
Help!!
Which of the following describes the first and foremost guideline in dimensioning?
A. Legibility
B. Measurement
C. Accuracy
D. Sketching
Answer:
it should be accuracy
Explanation:
Answer:
option C
Explanation:
g At this party, is the fact that a person is from South America independent of that person being majoring in biomedical engineering?
Answer:
Yes, this is completely independent.
Explanation:
Yes, this is completely independent. Even though there are no South American individuals that are majoring in biomedical engineering in this party it is still a completely independent factor. The origin of birth of an individual does not tie them to a specific degree or field of expertise, therefore a South American individual can study anything they want including mechanical engineering, electrical engineering, or biomedical engineering.
What are the differences between separately and shunt DC motor?
An engineer is trying to build a new measurement tool. Which step should the engineer complete first? A. Design a model of the tool to be tested. B. Precisely define the problem that is to be solved. Selected:c. Write a list of the criteria and constraints for the tool.This answer is incorrect. D. Conduct research on how similar problems were solved in the past.
Answer:
B. Precisely define the problem that is to be solved.
Explanation:
Engineering can be defined as the scientific and technological principles that is used for the design, development, operation and control of tools, machines or equipments, structures and systems. These machines, tools, systems and structures are typically designed and developed for the purpose of solving peculiar problems relating to human life. Simply stated, engineering is focused on proffering solutions to real life problems through a design process.
Generally, the design process comprises of series of steps used for the development of various tools, machines, structures and systems. In a chronological order, the basic steps of a design process are;
1. Define the problem: to proffer a solution to any problem, you have to precisely define the problem that is to be solved. Therefore, this is the first step of the design process.
2. Conduct a research: the engineer should collect or gather data (informations) relating to the project.
3. Brainstorming and analysis of data: this is the stage where the engineer conceptualize his or her ideas.
4. Create a prototype or simulated model of the product.
5. Product analytics and test: this is where the product is being used and tested for any flaw, error or defects. Thus, troubleshooting is also required at this stage.
Hence, if an engineer is trying to build a new measurement tool; the first step the engineer should complete is to precisely define the problem that is to be solved so as to have a good clear-cut understanding of the problem.
Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. Ex = 6 − 5x, (0, 1) The equation ex = 6 − 5x is equivalent to the equation f(x) = ex − 6 + 5x = 0. F(x) is continuous on the interval [0
Answer:
some part of your question is incomplete
attached below is the complete question
Answer :
F(0) = -5 < 0
F(1) = e - 1 > 0
since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )
Hence there is a root in the given equation : [tex]e^x = 6 - 5x[/tex]
Explanation:
using Intermediate value Theorem
If F(x) is continuous and f(a) and f(b) have opposite signs then there will be a'c'E (a,b) whereby F(c) = 0
given equation : [tex]e^x = 6 - 5x[/tex] on (0,1)
and F(x) = [tex]e^x - 6 + 5x = 0[/tex]
This shows that the F(x) is continuous on (0,1)
F(0) = [tex]e^0 - 6 + 5(0)[/tex] = -5 which is < 0
F(1) = [tex]e^1 -6 + 5(1)[/tex] = e -1 > 0 and e = 2.7182
since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )
Hence there is a root in the given equation : [tex]e^x = 6 - 5x[/tex]
5-81 The shaft is made of A-36 steel and is fixed at end D, while end A is allowed to rotate 0.005 rad when the torque is applied. Determine the torsional reactions at these supports.
Answer:
The answer is "7.73 kip-ft".
Explanation:
Using this equation, calculate the polar moment of shaft inertia:
[tex]J= \frac{\pi }{32} d^4\\\\[/tex]
[tex]= \frac{\pi}{ 32} \times 6^4\\\\= 127.234 \ \ in^4[/tex]
Equate the number of moments in x:
[tex]\sum M_x =0[/tex]
[tex]\to T_A-T_B +T_C+T_D =0\\\\\to T_A-40 +20+T_D =0[/tex]
Calculate the torsional response at A using the superposition method:
[tex]\to \phi_A =(\phi_A)_{T} - (\phi_A)_{T_A}\\\\[/tex]
[tex]= \frac{T_B L_{BC}}{JG}+ \frac{T_C L_{CD}}{JG} - \frac{T_A L_{AD}}{JG}\\\\[/tex]
[tex]0.05= \frac{40 \times 12 \times 2 \times 12}{127.234 \times 11 \times 10^3}+ \frac{20 \times 12 \times 1.5 \times 12 }{127.234 \times 11 \times 10^3} - \frac{T_A \times 12 \times 5 \times 12}{127.234 \times 11 \times 10^3}[/tex]
[tex]0.05= (8.22 \times 10^{-3})+ (3.086 \times 10^{-3})- (5.14 \times 10^{-4} \ T_A)\\\\[/tex]
[tex]\to T_A =12.27 kip \ ft \\\\[/tex]
The torsional answer in help A is 12.27 kip- ft. It replace the necessary equation values:
[tex]\to T_A-40 +20+T_D =0 \\\\\to 12.27-40+20+T_D=0\\\\T_D=7.73 kip \ ft[/tex]
The torsional reactions at the given supports are;
T_a = 12.3 Kip.ft and T_d = 7.7 Kip.ft
What are Torsional Reactions from Torque?From the image of the shaft attached, if we take a free body diagram and torsion about x, we will have;
∑Mₓ = 0;
T_a + T_d + 20 - 40 = 0 -----(1)
Using the method of superposition, we have;
Φ_a = (Φ_a)_T - (Φ_a)_T_a
Formula for rotation Φ is;
Φ = TL/(JG)
Thus;
0.005 = [tex][\frac{40 * 12 * 2 * 12}{(\pi/2) *3^{4} * 11 * 10^{3}} + \frac{20 * 12 * 1.5 * 12}{(\pi/2) *3^{4} * 11 * 10^{3}}] - \frac{T_{A} * 12 * 5 * 12}{(\pi/2) *3^{4} * 11 * 10^{3}}[/tex]
Solving for T_a in this gives;
T_a = 12.3 Kip.ft
Thus, from eq 1;
12.3 + T_d + 20 - 40 = 0
T_d = 20 - 12.3
T_d = 7.7 Kip.ft
Read more about Torsional reactions from torque at; https://brainly.com/question/20691242
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
This question is incomplete, the complete question is;
Determine the greatest pressure drop allowed over the 10-m-long pipe caused by viscous friction, so the flow remains laminar.
The 125-mm-diameter smooth pipe is transporting SAE 10W-30 oil with ρ=920 kg/m3 and µ=0.2 N.s/m2 .
Answer: the greatest pressure drop allowed is 14247 Pascals
Explanation:
LAMINAR FLOW INF PIPE
greatest pressure drop
(P1 - P2) = pressure drop
(P1 - P2) = 32uvl / D²
so (P1 - P2) ∝ V
greatest pressure drop is only at very high velocity
now Re (Reynold Number = svd / u
Re ∝ V
so velocity is high when Re is high
Re = 2000 ( Highest for LAMINAR)
Re = 2000 = svd / u
now in the question we were given that
s = 920 kg/m³, u = 0.2 NS/m², d = 125mm = 0.125m, l = 10m
so we substitute;
2000 = (920 × v × 0.125) / 0.2
v = 3.48 m/s
now pressure drop = (P1 - P2) = 32UVL / d²
we substitute
(P1 - P2) = (32(0.2) (3.48)(10)) / (0.125)²
(P1 - P2) = 14247 Pascals
therefore the greatest pressure drop allowed is 14247 Pascals
Read the following paragraph as quickly as you can, and see if you encounter any diculties.
Aoccdrnig to rscheearch at an Elingsh uinervtisy, it deosn't mttaer in waht oredr the ltteers in a wrod are, the olny iprmoetnt tihng is taht the frist and lsat ltteer is at the rghit pclae. The rset can be a toatl mses and you can sitll raed it wouthit a porbelm. Tihs is bcuseae we do not raed ervey lteter by itslef but the wrod as a wlohe.
This has been presented as an example of a principle of human reading compre-hension. If you keep the rst letter and the last letter of a word in their correct positions, then scramble the letters in between, the word is still quite readable in the context of an accompanying paragraph. However, it seems that this is a bit of a myth and not truly based on solid research.1 In short, for longer words the task is much more dicult. Nonetheless, we are going to imitate the process on some English text.
The task will be to read in a paragraph from a le, scramble the internal letters of each word, and then write the result to a le. Handling punctuation is tricky. You are required to deal with punctuation that comes at the end of a word (period, question mark, exclamation, etc.)|that is, punctuation is left untouched and does not count as the nal unscrambled letter. Optionally, one can deal with the more dicult task of handling all punctuation, such as apostrophes for possessives or hyphenated words. Truly randomizing the order of letters is a task for later in the text, but we can do some reasonable approximations now. Attacking this problem in a divide-and-conquer way should begin by writing code to scramble the letters in a word.
Create a dierent solution by dening scrambling functions for each of the following approaches: (Each approach counts as a dierent problem)
(a) For each letter choose a random number and rotate that letter by the random amount. Import random and use the random.randint(a,b) function where `a' and `b' dene the range of random numbers returned.
(b) Implement a dierent method to scrambling the letters. You must clearly describe in the comments the process to scramble the letters in place.It must be dierent than the process from part a.
Answer:
a
Explanation:
just took the quiz
Don't break or crush mercury-containing lamps because mercury powder may be released.
A) TrueB) False
Which color of white light bends the most when it is refracted by a prism? red green yellow orange
The color of white light bends the most when it is refracted by a prism is green after the violet.
Why green bents towards the light?The shorter the wavelength of the mild, the greater its miles refracted. As a result, crimson mild is refracted the least, and violet mild is refracted the most - inflicting the colored mild to unfold out to shape a spectrum.
The hues of white mild withinside the order of lowering wavelength are crimson orange-yellow inexperienced blue indigo violet. Fro the listing we are given withinside the alternatives inexperienced has the shortest wavelength than others. Therefore inexperienced will bend the most.
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What are the two most important things to remember when at the end of your interview?
1. When the interviewer asked if you have any questions at the end of the interview don't say no. You should always say yes your interviewer is expecting you to ask a few good questions before ending the interview.
2. Always thank the interviewer for their time and effort to interview you. This would look very good for you and its a nice way to help wrap up the interview.
A closed system of mass 20 kg undergoes a process in which there is a heat transfer of 1000 Q6: ki from the system to the surroundings. The work done on the system is 200 kl. If the initial 5 specific internal energy of the system is (250+R:) kl/kg, what is the final specific internal energy, in kj/kg? Neglect changes in kinetic and potential energy:
The final specific internal energy : 190 kJ/kg
Further explanationThe laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created
The equation is:
[tex]\tt E_{in}-E_{out}=\Delta E~system\\\\\Delta E=\Delta U+\Delta KE+\Delta PE\\\\\Delta U=m(U_2-U_1)\\\\Q-W=\Delta U+\Delta KE+\Delta PE[/tex]
Energy owned by the system is expressed as internal energy (U)
This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)
The sign rules for heat and work are set as follows:
• The system receives heat, Q +
• The system releases heat, Q -
• The system does work, W -
• the system accepts work, W +
A closed system of mass 20 kg⇒m=20 kg
Heat transfer of 1000 kJ from the system to the surroundings⇒Q=-1000 kJ
The work done on the system is 200 kJ⇒W=+200 kJ
The initial specific internal energy of the system is 250 kJ /kg⇒U₁ = 250 kj/kg
Neglect changes in kinetic and potential energy⇒ΔKE+ΔPE=0, so
Q-W = ΔU
Input in equation
[tex]\tt -1000-200=20(U_2-250)\\\\-1200=20U_2-5000\\\\3800=20U_2\\\\U_2=190~kJ/kg[/tex]
What motivated software engineers to move from the waterfall model to the incremental or spiral model
Answer:
1. They needed to develop multiple components in software programs.
2. The ability to overlap the development to be more evolutionary in nature.
3. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.
Explanation:
Software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.
In SDLC, a waterfall model can be defined as a process which involves sequentially breaking the software development into linear phases. Thus, the development phase takes a downward flow like a waterfall and as such each phase must be completed before starting another without any overlap in the process.
An incremental model refers to the process in which the requirements or criteria of the software development is divided into many standalone modules until the program is completed.
Also, a spiral model can be defined as an evolutionary SDLC that is risk-driven in nature and typically comprises of both an iterative and a waterfall model. Spiral model of SDLC consist of these phases; planning, risk analysis, engineering and evaluation.
What motivated software engineers to move from the waterfall model to the incremental or spiral model is actually due to the following fact;
They needed to develop multiple components in software programs. The ability to overlap the development to be more evolutionary in nature. The need to be more risk-averse or the unwillingness to take risks led to the use of a spiral model.What is technology and what are the four features of technology?
Answer: Technology is the application of scientific knowledge for practical purposes, especially in industry.
Mechanical.
Electronic.
Industrial and manufacturing.
Medical.
Communications.
Explanation:
Answer:
Technology is something like a phone or like a tablet or like an electrace car
Explanation:
In the feature i belive that there is going to be more and higher andanved technology or like people say flying cars a robots. But i feel more advanced stuff like phones and computers or labtops or like tablets.
First Order Logic
Translate into First Order Logic (FOL) the following statements. Then write the negations of the FOL propositions found.
1. All tigers are fast. Domain: animals.
2. Some tigers are fierce and dangerous. Domain: animals.
3. Every prime number is odd. Domain: positive integers.
4. All prime numbers except two are odd. Domain: positive integers.
5. All fruits are either yellow or red. Domain: produce.
6. For every integer number, there exist a bigger integer. Domain: integers.
Answer:
1) ∀x [ Tiger(x) → Fast(x) ]
2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) ∀x [ Prime(x) → Odd(x) ]
4) ∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) ∀xэy [ I(x) → greater (y, x) ]
Explanation:
Translating the statements into first Order Logic and their negations
1) All tigers are fast. Domain: animals.
∀x [ Tiger(x) → Fast(x) ]
2) Some tigers are fierce and dangerous. Domain: animals
эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) Every prime number is odd. Domain: positive integers
∀x [ Prime(x) → Odd(x) ]
4) All prime numbers except two are odd. Domain: positive integers
∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) All fruits are either yellow or red. Domain: produce.
∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) For every integer number, there exist a bigger integer. Domain: integers.
∀xэy [ I(x) → greater (y, x) ]
Answer:
Answer:
1) ∀x [ Tiger(x) → Fast(x) ]
2) эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) ∀x [ Prime(x) → Odd(x) ]
4) ∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) ∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) ∀xэy [ I(x) → greater (y, x) ]
Explanation:
Translating the statements into first Order Logic and their negations
1) All tigers are fast. Domain: animals.
∀x [ Tiger(x) → Fast(x) ]
2) Some tigers are fierce and dangerous. Domain: animals
эx [ Tiger (x) ∧ Fierce (x) ∧ Dangerous(x) ]
3) Every prime number is odd. Domain: positive integers
∀x [ Prime(x) → Odd(x) ]
4) All prime numbers except two are odd. Domain: positive integers
∀x [ prime (x) ∧ ~Two(x) → Odd (x) ]
5) All fruits are either yellow or red. Domain: produce.
∀x [ Fruits(x) → ( yellow(x) ∨ Red(x) ]
6) For every integer number, there exist a bigger integer. Domain: integers.
∀xэy [ I(x) → greater (y, x) ]
Explanation:
Stack memory is implemented as a stack data structure. Provide the sequence of push and pop operations on stack memory when the collatz method (provided below) is called with n = 5. Note that an enqueue and dequeue is associated with a method call. For example, the first and last operations in the sequence should be push(collatz(4)) and pop(collatz(4)) respectively. public void collatz(int n) { if (n == 1) return; else if (n % 2 == 0) collatz(n / 2); else collatz(3*n + 1); }
Answer:
attached below is the solution
Explanation:
hello attached below is the sequence of push and pop operations on stack memory
For The collatz method below
public void collatz(int n) {
if (n == 1) return;
else if (n % 2 == 0)
collatz(n / 2);
else collatz(3*n + 1); }
Experimental Design Application Production engineers wish to find the optimal process for etching circuit boards quickly. They create a single replicate 24experiment to test the effect of the following factors on time to etch a circuit board: (A) Concentration of nitric acid in the etchant, (B) temperature of the etchant, (C) stirring rate in the etching tank, (D) surface area of the board. Running this experiment, they obtain the data in HW_EDA_137.csv.Preview the document Which factors effects and interaction effects are significant?
Answer:
Hello your question is incomplete attached below is the missing part and answer
options :
Effect A
Effect B
Effect C
Effect D
Effect AB
Effect AC
Effect AD
Effect BC
Effect BD
Effect CD
Answer :
A = significant
B = significant
C = Non-significant
D = Non-significant
AB = Non-significant
AC = significant
AD = Non-significant
BC = Non-significant
BD = Non-significant
CD = Non-significant
Explanation:
The dependent variable here is Time
Effect of A = significant
Effect of B = significant
Effect of C = Non-significant
Effect of D = Non-significant
Effect of AB = Non-significant
Effect of AC = significant
Effect of AD = Non-significant
Effect of BC = Non-significant
Effect of BD = Non-significant
Effect of CD = Non-significant
(a) At a simple interest rate of 12% per year, determine how long it will take $5000 to increase to twice as much. (b) Compare the time it will take to double if the rate is 20% per year simple interest.
Explanation:
10000=5000(1.12^x)
2=1.12^x
(log_1.12)(2)=x
x= about 6.1163
10000=5000(1.2^x)
2=1.2^x
(log_1.2)(2)=x
x= about 3.8019
compare them by saying like 20% will be 6.12/3.8 times faster
Seth wants to build a wall of bricks. Which equipment will help him in the process?
OA masonry pump
OB. hacksaw
OC. mortar mixer
OD. pressurized cleaning equipment
Answer:
it's B I think
Explanation:
hopefully that helps you
Answer: C
Explanation: A mortar mixer is the equipment that would help Seth in the process of building a wall of bricks. A mortar mixer is used to mix the mortar, which is the binding material used to hold the bricks together. It ensures the mortar is properly mixed to the right consistency for laying the bricks.
Which of the following tasks might a civil engineer perform during a project’s construction phase in a design-build approach? (Select all that apply.)
Work with construction management to solve specific problems as they arise.
Draw up the contracts for construction management.
Ensure compliance with safety standards.
Provide information on design changes.
Answer:
Draw up the contract for construction management.
Answer:
Work with construction management to solve specific problems as they arise.
Ensure compliance with safety standards.
Explanation: