There are 640 acres in 1 square mile. The area of a forest is increasing at a rate of 1 acre per decade. The rate at which the area of the forest is increasing, in square kilometers per decade is C) 0.0025 square kilometers per decade.
The area of the forest is increasing at a rate of 1 acre per decade. To find the rate in square kilometers per decade, we first need to convert acres to square miles, and then square miles to square kilometers.
1 acre = 1/640 square miles (since there are 640 acres in 1 square mile)
Now, we'll convert square miles to square kilometers using the given conversion factor (1 kilometer = 0.62 mile):
1/640 square miles * (1 km / 0.62 mile)^2 = 1/640 * (1 / 0.3844) square kilometers ≈ 0.00256 square kilometers
So, the closest answer to the rate at which the area of the forest is increasing is:
C) 0.0025 square kilometers per decade
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Find the area of polygon A
A: 4
B: 160
C: 80
D: 20
A potato chip manufacturer produces bags of potato chips that are supposed to have a net weight of 326 grams. Because the chips vary in size, it is difficult to fill the bags to the exact weight desired. However, the bags pass inspection so long as the standard deviation of their weights is no more than 4 grams. A quality control inspector wished to test the claim that one batch of bags has a standard deviation of more than 4 grams, and thus does not pass inspection. If a sample of 27 bags of potato chips is taken and the standard deviation is found to be 5.3 grams, does this evidence, at the 0.05 level of significance, support the claim that the bags should fail inspection? Assume that the weights of the bags of potato chips are normally distributed.
Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
The evidence at the 0.05 level of significance contradict claim that the bags should fail inspection.
We can use a one-tailed test with the null hypothesis that the standard deviation of the bags' weights is no more than 4 grams and the alternative hypothesis that the standard deviation is greater than 4 grams.
The test statistic for this hypothesis test is given by:
t = [tex]\frac{\frac{s}{\sqrt{n}}}{\frac{sigma}{\sqrt{n}}}[/tex]
where s is the sample standard deviation, n is the sample size, and sigma is the population standard deviation (which is assumed to be 4 grams).
Plugging in the given values, we get:
t = [tex]\frac{\frac{5.3}{\sqrt{27}}}{\frac{4}{\sqrt{ 27}}}[/tex] ≈ 1.325
Using a t-distribution table with 26 degrees of freedom (since we have a sample size of 27 and are estimating the population standard deviation), we can find the critical value for a one-tailed test at the 0.05 level of significance. The critical value is 1.705.
Since our calculated test statistic (1.325) is less than the critical value (1.705), we can support the null hypothesis and conclude that the bags of potato chips will not fail inspection.
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Pls help!!
Geometry
(Look at photo)
The value of x is determined as 1.
What is the value of x?
The value of x is calculated by applying the principle of similar triangles.
length SR ≅ length ST
length TU ≅ length RU
We will have the following equation, to solve for the value of x;
TU/SU = RU/SU
TU = RU
x + 9 = 10x
9 = 10x - x
9 = 9x
9/9 = xy
1 = x
Thus, the value of x is calculated by applying the principle of similar triangle.
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A survey found that 4 out
of 10 students will work a
summer job. If there are
340 students at the
school, about how many
will work a summer job?
The pdf of X is f(x) = 0.2, 1< x < 6.
(a) Show that this is a pdf(probability distribution function)
(b) Find the cdf F(x).
(c) Find P(2
(d) Find P(X>4).
(a) The function f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf) because it is non-negative for all x in its domain and the total area under the curve is equal to 1.
(b) The cumulative distribution function (cdf) F(x) for 1 < x < 6 is given by F(x) = 0.2(x-1), where F(x) = 0 for x ≤ 1 and F(x) = 1 for x ≥ 6.
(c) The probability P(2 < X < 4) is 0.4, which can be calculated by integrating the pdf f(x) = 0.2 over the interval [2, 4].
(d) The probability P(X > 4) is 0.6, which is obtained by subtracting the cumulative probability F(4) = 0.2(4-1) from 1.
(a) To show that f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf), we need to show that:
f(x) is non-negative for all x in its domain: f(x) = 0.2 is non-negative for all x between 1 and 6.
The total area under the curve of f(x) is equal to 1:
∫1^6 0.2 dx = 0.2(x)|1^6 = 0.2(6-1) = 1
Since both conditions are satisfied, f(x) is a pdf.
(b) The cumulative distribution function (cdf) F(x) is given by:
F(x) = ∫1^x f(t) dt
For 1 < x < 6, we have:
F(x) = ∫1^x 0.2 dt = 0.2(t)|1^x = 0.2(x-1)
For x ≤ 1, F(x) = 0, and for x ≥ 6, F(x) = 1.
(c) P(2 < X < 4) is given by:
P(2 < X < 4) = ∫2^4 f(x) dx = ∫2^4 0.2 dx = 0.2(x)|2^4 = 0.4
(d) P(X > 4) is given by:
P(X > 4) = 1 - P(X ≤ 4) = 1 - F(4) = 1 - 0.2(4-1) = 0.6
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Find the surface area of the solid formed by the net. Round your answer to the nearest hundredth.
The surface area of the solid formed by the net = 150.72 in²
From the figure we can observe that the solid formed by the net is the net of a cylinder.
The cylinder bases are the 2 circles and the curved surface of the cylinder is the rectangle.
The surface area of the cylinder = Area of the 2 circles + area of the rectangle
Here, the diameter of circle is 4 in
So, the radius of circle = ½ × 4
= 2 in
So, the area of the 2 circles would be,
2(πr²)
= 2 × 3.14 × 2²
= 25.12 in²
Here the width of the rectangle is 10 in. and the length is nothing but the circumference of the circle.
so, length L = πd
= π × 4
= 12.56 in
Now the area of rectangle would be,
L × W
= 12.56 × 10
= 125.6 in²
The total surface area of net would be,
Area of the 2 circles + area of the rectangle
= 25.12 + 125.6
= 150.72 in²
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Haematuria + frequency + dysuria what is the diagnosis and investigations?
What is the domain of the function in the graph?
The domain of the function shown in the graph is the one in option A:
6 ≤ k ≤ 11
What is the domain of the function in the graph?The domain of a function y = f(x) is the set of the inputs of the function. To identify the domain in a graph, we need to look at the horizontal axis (also called the x-axis).
On the graph we can see that it starts at x = 6 with a closed dot, and it ends at x = 11 also with a closed dot.
That means that these values belong to the domain, so we can write the domain as follows:
Domain = 6 ≤ k ≤ 11
(notice that the variable in the horizontal axis is k).
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While on vacation at the beach, Eleanor drew the figure shown.
In Eleanor's drawing, the measure of
∠
F
M
D
is 15°, and the measure of
∠
B
M
C
is 30°.
What is the measure of
∠
C
M
D
?
The measure of the angle ∠CMD is 45.
We have,
From the figure,
∠FMD = 15
∠BMC = 30
Now,
∠BMF = 90
This can be written as,
∠BMC + ∠CMD + ∠FMD = 90
30 + ∠CMD + 15 = 90
∠CMD = 90 - 45
∠CMD = 45
Thus,
The measure of the angle ∠CMD is 45.
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Cases of UFO sightings are randomly selected and categorized according to season, with the results listed in the table. Use a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table. Find the test statistic x² needed to test the claim.
A.11.472
B.11.562
C.2,212.556
D.7.815
Answer: D.
Step-by-step explanation:
Using a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table the test statistic x² needed to test the claim is 11.562. The correct option is B.
To test the claim that UFO sightings occur in different seasons with the proportions listed in the table, we can use a chi-square goodness-of-fit test.
The null hypothesis is that the observed frequencies in each season are equal to the expected frequencies based on the proportions listed in the table.
The expected frequency for each season can be calculated by multiplying the total number of sightings by the proportion listed in the table. For example, the expected frequency for spring is:
Expected frequency for spring = Total number of sightings × Proportion for spring
= 420 × 0.25
= 105
Similarly, the expected frequencies for summer, fall, and winter are 126, 210, and 105, respectively.
The chi-square test statistic can be calculated as:
χ² = ∑ [(O - E)² / E]
where O is the observed frequency and E is the expected frequency.
Using the observed frequencies from the table and the expected frequencies calculated above, we get:
χ² = [(150-105)²/105] + [(120-126)²/126] + [(100-210)²/210] + [(50-105)²/105]
= 11.562
The degrees of freedom for the chi-square test is (number of categories - 1), which in this case is 4 - 1 = 3.
Using a chi-square distribution table with 3 degrees of freedom and a significance level of 0.05, the critical value is 7.815.
Since the calculated chi-square value (11.562) is greater than the critical value (7.815), we reject the null hypothesis and conclude that there is evidence of a difference in UFO sightings across seasons. Therefore, the test statistic x² needed to test the claim is 11.562.
The correct answer is (B) 11.562.
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an integral equation is an equation that contains an unknown function y(x) and an integral that involves y(x). solve the given integral equation. [hint: use an initial condition obtained from the integral equation.] y(x) = 2 + x [t − ty(t)] dt 8
The solution to the integral equation y(x) = 2 + x [t − ty(t)] dt is: y(x) = 1 + e⁻ˣ
Note that this solution satisfies the initial condition y(0) = 2.
To solve the given integral equation y(x) = 2 + x [t − ty(t)] dt, we need to first find the value of y(x) that satisfies this equation. We can obtain an initial condition for y(x) by setting x=0 in the equation and solving for y(0). Then, we can use a method such as separation of variables or substitution to find the general solution for y(x).
Let's start by finding the initial condition for y(x). Setting x=0 in the integral equation, we get:
y(0) = 2 + 0 [t − t y(t)] dt
y(0) = 2
So, we know that y(0) = 2. This will be useful when we find the general solution for y(x).
Now, let's use substitution to solve the integral equation. Let u = y(x), du/dx = y'(x), and v = t - y(t). Then, we have:
y(x) = 2 + x [t − ty(t)] dt
u = 2 + x [v] dt
du/dx = v + x dv/dx
Substituting du/dx and v in terms of u and x, we get:
v = t - u
du/dx = t - u + x (dv/dx)
du/dx + u = t + x (dv/dx)
We can use the integrating factor method to solve this first-order linear differential equation. The integrating factor is eˣ, so we have:
eˣ du/dx + eˣ u = teˣ + x eˣ (dv/dx)
(d/dx)(eˣ u) = (teˣ)' = eˣ
eˣ u = eˣ + C
u = 1 + Ce⁻ˣ
Substituting u = y(x) and using the initial condition y(0) = 2, we get:
y(x) = 1 + Ce⁻ˣ (general solution)
y(0) = 2 = 1 + C (using initial condition)
C = 1
Therefore, the solution to the integral equation y(x) = 2 + x [t − ty(t)] dt is:
y(x) = 1 + e⁻ˣ
Note that this solution satisfies the initial condition y(0) = 2.
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Which equality statement is FALSE?
Responses
A −1 = −(−1)−1 = −(−1)
B 7 = −[−(7)]7 = −[−(7)]
C 1 = −[−(1)]1 = −[−(1)]
D −(−14) = 14
The equality statement is False (b) 7= -(-(7)).
The expression on the right side of the equation simplifies to -(-7), which is equal to 7, making the statement untrue. Therefore, 7=-(-7) should be used as the right equality declaration.
In other words, 7 is equal to the opposite of -(-7)
The area of mathematics known as algebra aids in the representation of circumstances or problems as mathematical expressions. Mathematical operations like addition, subtraction, multiplication, and division are combined with variables like x, y, and z to produce a meaningful mathematical expression.
The associative, commutative, and distributive laws are the three fundamental principles of algebra. They facilitate the simplification or solution of problems and aid in illustrating the connection between different number operations.
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Nearpod
Bolin is taking classes to learn tai chi, a Chinese martial art. The constant of
proportionality between the cost of the classes and the number of classes is 16. What is
the unit rate, in dollars per class, for Bolin's tai chi classes? Use the drop-down menus to
explain your answer.
Click the arrows to choose an answer from each menu.
The constant of proportionality Choose...
relationship. The unit rate for Bolin's tai chi classes is Choose...
Y
equal to the unit rate in a proportional
The constant of proportionality is equal to the unit rate in a proportional relationship. The unit rate for Bolin's tai chi classes is 16.
What is a proportional relationship?In Mathematics and Geometry, a proportional relationship refers to a type of relationship that produces equivalent ratios or unit rates, and it can be modeled or represented by the following mathematical equation:
y = kx
Where:
y represents the number of classes.x represents the cost of the classes.k is the constant of proportionality.What is the unit rate?In Mathematics, the unit rate is sometimes referred to as unit price or unit ratio and it can be defined as the price that is being charged by a seller for the sale of a single unit of product or quantity, especially in a proportional relationship:
Constant of proportionality, k = y/x
Constant of proportionality, k = 16.
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A number cube is tossed 60 times.
Outcome Frequency
1 12
2 13
3 11
4 6
5 10
6 8
Determine the experimental probability of landing on a number greater than 4.
17 over 60
18 over 60
24 over 60
42 over 60
The experimental probability of rolling a number greater than 4 is 18/60
How to determine the experimental probability?It will be given by the number of times that the outcome was greater than 4 (so a 5 or a 6) over the total number of trials.
We can see that the total number of trials is 60, and we have:
The outcome 5 a total of 10 times.The outomce 6 a total of 8 times.Adding that: 10 + 8 = 18
Then the experimental probability of a number greater than 4 is:
E = 18/60
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Suppose the scores on a Algebra 2 quiz are normally distributed with a mean of 79 and a standard deviation of 3. Which group describes 16% of the population of Algebra 2 quiz scores?
The group described by 16% of the population is 73.
What is the group describes 16% of the population?
For a normal distribution curve, the population are often divided into 2% below the mean, 14 % below the mean, 34% below the mean, the mean, 34% above the mean, 16% above the mean and 2 % above the mean.
for 34% below the mean, the population = M - 1std
for 16% below the mean, the population = M - 2std
So the population represented by 16% is calculated as follows;
= M - 2std
where;
M is the meanstd is standard deviation= 79 - 2 (3)
= 79 - 6
= 73
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Rewrite each of the following expressions without using absolute value.
|x−y| , if x
If an expression for x that does not use an absolute value is y, rewrite |x-y| as x - y.
It is the same as rearranging one expression to plug it into another expression when rewriting algebraic expressions using structure. Solving for one of the variables and then plugging the resulting expression for that variable into the other expression is the initial step to take in these kinds of issues.
Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.
Here given :
|x−y| , if x then :
y, x - y is rewritten for |x−y|
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Correct Question:
Rewrite each of the following expressions without using absolute value.
1. |x−y| , if x
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 317oC is 6.67 × 1023 m-3. The density and atomic weight (at 317°C) for this metal are 6.40 g/cm3 and 27.00 g/mol, respectively.
The energy for vacancy formation per atom in the metal M is 0.91 eV/atom.
To calculate the energy (in eV/atom) for vacancy formation in the metal M, we can use the following formula:
E_v = RT * ln(N_v/N)
Where:
- E_v is the energy for vacancy formation per atom
- R is the gas constant (8.314 J/mol*K or 0.008314 eV/mol*K)
- T is the temperature in Kelvin (317°C = 590K)
- N_v is the equilibrium number of vacancies (6.67 × 10^23 m^-3)
- N is the number of atoms per unit volume, which can be calculated using the density and atomic weight of the metal as follows:
N = (6.40 g/cm^3) * (1 mol/27.00 g) * (6.022 × 10^23 atoms/mol) = 1.51 × 10^22 atoms/m^3
Plugging in these values, we get:
E_v = (0.008314 eV/mol*K) * (590 K) * ln(6.67 × 10^23 m^-3 / 1.51 × 10^22 atoms/m^3)
E_v = 0.91 eV/atom
Therefore, the energy for vacancy formation per atom in the metal M is 0.91 eV/atom.
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Suppose the final step of a Gauss-Jordan elimination is as follows: 11 0 0 51 0 1 21-3 LO 0 ol What can you conclude about the solution(s) for the system?
We can conclude that the system represented by the given Gauss-Jordan elimination has infinitely many solutions, and the values of the variables can be expressed in terms of a free variable x4.
The Gauss-Jordan elimination is a method used to solve a system of linear equations. The final step of the method is to transform the augmented matrix of the system into reduced row echelon form, which allows for easy identification of the solution(s) of the system.
In the given final step of the Gauss-Jordan elimination, the augmented matrix of the system is represented as:
11 0 0 51
0 1 0 21
0 0 1 -3
0 0 0 0
The augmented matrix is in reduced row echelon form, where the leading coefficients of each row are all equal to 1, and there are no other non-zero elements in the same columns as the leading coefficients. The last row of the matrix corresponds to the equation 0 = 0, which represents an identity that does not provide any new information about the system.
The system represented by this matrix is:
11x1 + 51x4 = 0
x2 + 21x4 = 0
x3 - 3x4 = 0
We can see that the third row of the matrix corresponds to an equation of the form 0x1 + 0x2 + 0x3 + 0x4 = 0, which indicates that the variable x4 is a free variable. This means that the system has infinitely many solutions, and the value of x4 can be chosen arbitrarily.
The values of x1, x2, and x3 can be expressed in terms of x4 using the equations given by the first three rows of the matrix. For example, we can solve for x1 as follows:
11x1 + 51x4 = 0
x1 = -51/11 x4
Similarly, we can solve for x2 and x3:
x2 = -21 x4
x3 = 3 x4
Therefore, the general solution of the system is:
x1 = -51/11 x4
x2 = -21 x4
x3 = 3 x4
x4 is a free variable
In summary, we can conclude that the system represented by the given Gauss-Jordan elimination has infinitely many solutions, and the values of the variables can be expressed in terms of a free variable x4.
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Which of the following modifications to a research study will result in a narrower confidence interval?Group of answer choicesA) increasing the confidence level, decreasing the sample sizeB) increasing the confidence level, increasing the sample sizeC) decreasing the confidence level, decreasing the sample sizeD) decreasing the confidence level, increasing the sample size
The modification to a research study that will result in a narrower confidence interval is option D is correct choice
The modification to a research study that will result in a narrower confidence interval is option D: decreasing the confidence level and increasing the sample size. By decreasing the confidence level, we are willing to accept a lower level of certainty in our results, which can lead to a narrower interval. Increasing the sample size also leads to a narrower interval as it reduces the variability in our data and increases the precision of our estimates.
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Problem 83 please help me
The rule for the nth term of the geometric sequence is given as follows:
[tex]a_n = 2^n[/tex]
Hence the 10th term of the sequence is given as follows:
1024.
What is a geometric sequence?A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.
The explicit formula of the sequence is given as follows:
[tex]a_n = a_0q^{n}[/tex]
In which [tex]a_0[/tex] is the first term.
The parameters in this problem are given as follows:
First term of 1.Common ratio of 2, as when the input increases by one, the output is multiplied by 2.Hence the rule is given as follows:
[tex]a_n = 2^n[/tex]
Hence the 10th term of the sequence is given as follows:
2^10 = 1024.
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The drawing shown was made on paper and cut out to build a little house. Which of the houses could not have resulted from this construction?
The first image is the little house without being constructed, the other ones are the option answers
Answer: B
Step-by-step explanation:
If you fold that bottom side up. the door is not on the closer side to the window. so B is wrong because the door is near the window.
FInd the surface area.
Answer:
77 cm^2
Step-by-step explanation:
rectangular prism or cuboid
Right rectangular prism Solve for surface area▾
A = 77
L = 2
w = 3
h = 6.5
A=2(wl+hl+hw) = 2.(3.2+6.5.2+6.5.3)=77
chegg
What is the rule for the transformation formed by the translation 8 units rght and 5 units down followed by a 180 degree rotation
The translating point will be (x, y) --> (8-x, -5-y).
We have to translate a point 8 units right and 5 units down followed by a 180 degree rotation.
Now, the rule for 180 rotation is
(x, y) --> (x, -y)
and, to shift 8 unit right apply (8-x)
and, to shift 5 unit down apply (5-y)
Then, the translating point will be (x, y) --> (8-x, -5-y).
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If the daily windows of the last 4 are 1000,1200,1300 and 2000,
it can be concluded that the average sales for that period was:
A) 5,500
B) 1,375
C) 1,200
D) not sufficient information
The average sales for that period is 1375.
The average, also known as the mean, is a statistical measure that represents the central tendency of a set of values. It is calculated by summing up all the values in a dataset and dividing the sum by the total number of values.
Mathematically, the average (mean) is calculated as:
Average = (Sum of all values) / (Total number of values)
To calculate the average sales for the given period, you'll need to follow these steps:
1. Add up the daily sales figures: 1000 + 1200 + 1300 + 2000 = 5500
2. Count the number of days in the period: 4 days
3. Divide the total sales by the number of days to find the average: 5500 / 4 = 1375
So, the average sales for that period is 1375.
Therefore, the correct answer is: B) 1,375
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Check My Work
The symbol ∪ indicates the _____.
a. sum of the probabilities of events
b. intersection of events
c. sample space
d. union of events
The symbol ∪ represents the "union of events" in the context of probability and set theory.
The symbol ∪ indicates the union of events. This option corresponds to choice (d) in your given list. The union of events refers to the occurrence of at least one of the events in question. In other words, it combines the outcomes of two or more events into a single set, without any repetitions. This concept is essential in understanding probability theory, as it helps to analyze the likelihood of different events happening together or separately.
This means that it represents the set of all outcomes that belong to either one or both of the events being considered. For example, if event A represents rolling an even number on a die and event B represents rolling a number greater than 4, then the union of events A and B would be the set of outcomes {2, 4, 5, 6}. It is important to note that the union of events is different from the intersection of events, which represents the set of outcomes that belong to both events being considered. The sample space, on the other hand, represents the set of all possible outcomes of an experiment. Finally, the symbol ∑ represents the sum of probabilities of events, not the symbol ∪.
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An angle measures 83.6° more than the measure of its complementary angle. What is the measure of each angle?
The angle is 86.8 degrees and its complement is 3.2 degrees.
let x be the angle and y be the Complementary angle.
If the angles are complementary, then their sum is 90 degrees.
x + y = 90................(1)
and, the angle measures 83.6 degrees more than its complement.
x = y + 83.6
y + 83.6 + y = 90
Solving the equation for y we get
2y + 83.6 = 90
2y = 90 - 83.6
2y = 6.4
y= 3.2
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Let A ∈ R^nxn and let C ∈ R^nxm. Prove the following: (1) Assume A is positive semidefinite. Show that tr A=0 if and only if A = 0. (2) When m
Let A ∈ R^(nxn) and let C ∈ R^(nxm). We will prove the following:
(1) Assume A is positive semidefinite. We need to show that tr(A) = 0 if and only if A = 0.
Proof:
(i) If A = 0, then tr(A) = 0 since the trace of the zero matrix is 0.
(ii) Assume tr(A) = 0. Recall that A is positive semidefinite, which means that its eigenvalues are non-negative. Since the trace of a matrix is the sum of its eigenvalues, having tr(A) = 0 implies that all eigenvalues of A must be zero. Consequently, A is a diagonal matrix with all diagonal elements equal to 0. Therefore, A = 0.
Thus, we have shown that tr(A) = 0 if and only if A = 0.
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At your local store, you are given a coupon for 20% off any store item purchased on Monday. When you return to your store, you notice that an item (normal price = $50) is on clearance for 40% off. You are allowed to use the coupon on the clearance item. How much should you pay for the item? Should it be 60% off of the normal price? Explain why or why not, justify your reason quantitatively.
The 40% clearance discount is already factored into the clearance price of $30, so applying the 20% coupon only reduces the price further by 20% of $30, or $6. Therefore, you would pay $24 for the item with both discounts applied.
Let's break down the discounts and calculate the final price of the item using the terms "normal", "price", and "quantitatively".
The normal price of the item: $50
First, apply the 40% clearance discount:
40% off the normal price = 0.4 * $50 = $20
Subtract the clearance discount from the normal price:
New discounted price = $50 - $20 = $30
Now, apply the 20% off coupon to the discounted price:
20% off the new discounted price = 0.2 * $30 = $6
Quantitatively, the calculation would be:
Normal price = $50
Clearance price (40% off) = $30
Coupon discount (20% off clearance price) = 0.20 x $30 = $6
Final price = $30 - $6 = $24
Subtract the coupon discount from the discounted price:
Final price = $30 - $6 = $24
So, you should pay $24 for the item. It is not the same as taking 60% off the normal price because the discounts are applied sequentially, not combined. Quantitatively, you can see that taking 60% off the normal price would result in a $30 discount ($50 * 0.6), while the actual total discount here is $26 ($20 + $6).
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HELPPPPP!:
WHICH OF THE FOLLOWINGS ARE POLYNOMIAL EXPRESSION!:::-
A. 2x+3 B. 3y² - 2y + 4
C. a + 1/a D. root over 5x + 1
E. x²/2 - 3x + 7 F. root over x+2 - 3
NO NEED FOR EXPLANATION!!!
Answer:
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If x=2 and x=3 are roots of the equation 3x
2
−2kx+2m=0 then (k,m)=
Medium
Solution
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Correct option is A)
Since x=2 and x=3 are roots of the equation 3x
2
−2kx+2m=0
⇒12−4k+2m=0⇒2k−m=6 ...(i)
and ⇒27−6k+2m=0⇒6k−2m=27 ...(ii)
On multiplying (i) by 3 and subtracting (ii) from it, we get
6k−3m=18
−
6
k
+
−
2m=
−
2
7
−m=−9
∴m=9
On putting m=9 in (i), we get
2k=15⇒k=
2
15
∴(k,m)=(
2
15
,9)
Hence, Option A is correct.
Answer:
A. 2x+3 and B. 3y² - 2y + 4 and E. x²/2 - 3x + 7 are polynomial expressions.