The triangle is acute since a² + b² < c² ( 2916 + 961 < 4761.
Is the triangle is right, acute, or obtuse?To determine whether the triangle is right, acute, or obtuse, we can use the Pythagorean Theorem, which states that in a right triangle, the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse.
We can start by finding the longest side of the triangle, which is the hypotenuse.
hypotenuse = 69
Now we can use the Pythagorean Theorem to check whether the triangle is right:
a² + b² = c²
where a and b are the lengths of the other two sides of the triangle.
Plugging in the values we know, we get:
54² + 31² = 69²
Simplifying, we get:
2916 + 961 = 4761
3877 = 4761
Since this equation is not true, we know that the triangle is not a right triangle.
To determine whether the triangle is acute or obtuse, we need to compare the sum of the squares of the lengths of the shorter sides to the square of the length of the longest side:
a² + b² < c² => the triangle is acute
a² + b² > c² => the triangle is obtuse
c² = 69² = 4761
Plugging in the values we know, we get:
54² + 31² = 2916 + 961 = 3877
Since 3877 < 4761, we can conclude that the triangle is acute.
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SHOW WORK
5.
Two mechanics worked on a car. The first mechanic charged $65 per hour, and the second mechanic charged $45 per
hour. The mechanics worked for a combined total of 15 hours, and together they charged a total of $875. How long did
each mechanic work?
The first mechanic wοrked fοr 10 hοurs, and the secοnd mechanic wοrked fοr 15 - 10 = 5 hοurs.
Let x be the number οf hοurs the first mechanic wοrked, then the number οf hοurs the secοnd mechanic wοrked wοuld be (15 - x).
The tοtal cοst οf the first mechanic wοuld be 65x, and the tοtal cοst οf the secοnd mechanic wοuld be 45(15 - x) = 675 - 45x.
Tοgether, their tοtal cοst wοuld be 65x + (675 - 45x) = 20x + 675.
We knοw that their tοtal cοst was $875, sο we can set up the equatiοn:
20x + 675 = 875
Subtracting 675 frοm bοth sides, we get: 20x = 200
Dividing bοth sides by 20, we get: x = 10
Therefοre, the first mechanic wοrked fοr 10 hοurs, and the secοnd mechanic wοrked fοr 15 - 10 = 5 hοurs .
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Which situations describe similar but not congruent triangles?
Triangle TUV is rotated 180° clockwise about the origin and translated 3 units up to create ΔT'U'V'.
Two of the angles of ΔABC have the same measures as two of the angles of ΔDEF, and all of the corresponding side lengths of the two triangles are different.
The three angles of ΔGHI have the same measures as the three angles of ΔQRS, and the side lengths of ΔGHI are twice the corresponding side lengths of ΔQRS.
Triangle PQR is dilated about the origin by a scale factor of and reflected across the y-axis to create ΔP'Q'R'.
The three side lengths of ΔJKL are the same as the three corresponding side lengths of ΔXYZ, and one of the angles of ΔJKL has the same measure as one of the angles of ΔXYZ.
ΔTUV is not congruent to ΔT'U'V', as the transformation involved a rotation and translation, but they have similarities.
ΔABC and ΔDEF have the same angles but different side lengths, so they are similar but not congruent triangles.
What are the similarities?
The situations that describe similar but not congruent triangles are given below:
Two of the angles of ΔABC have the same measures as two of the angles of ΔDEF, and all of the corresponding side lengths of the two triangles are different. This is because similar triangles have the same angle measures but different side lengths, and congruent triangles have both the same angle measures and the same side lengths.The three angles of ΔGHI have the same measures as the three angles of ΔQRS, and the side lengths of ΔGHI are twice the corresponding side lengths of ΔQRS. This is because similar triangles have the same angle measures, but their side lengths are proportional to each other.The three side lengths of ΔJKL are the same as the three corresponding side lengths of ΔXYZ, and one of the angles of ΔJKL has the same measure as one of the angles of ΔXYZ. This is because similar triangles have the same angle measures, and their side lengths are proportional to each other.To know more about triangles, visit:
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8. Select all true statements about the number e. A. e is a rational number. B. e is approximately 2.718. C. e is an irrational number. D. e is between and √2 on the number line. E. e is exactly 2.718.
THE GIVER Chapter 17
What does Gabe symbolize?
Gabe or Gabriel is a new child in the novel, "The Giver" and was described as a symbol of hope and new beginnings.
As a new child, Gabe is not yet fully indoctrinated into the rules and customs of the community, making him more open to the memories transmitted by Jonas.
This presentation of Gabe's character aligns with the novel's recurring motif of babies symbolizing hope and regeneration in literature.
What is the novel "The Giver" about?The novel "The Giver" was authored by Lois Lowry. It is set in a futuristic society that has eliminated all pain, fear, war, and hatred and appears to be utopian at first glance.
The story is written from the point of view of Jonas, an eleven-year-old boy, selected to be the new Receiver of Memory.
Through training, Jonas learns about the joys and pains of life and becomes increasingly disillusioned with the society he lives in.
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Mrs. Burke's physics class has 122 students, classified by academic year and major, as illustrated in the table. Mrs. Burke randomly chooses one student to collect yesterday's work. Mrs. Burke's Physics Class Academic Year Physics Majors Non-Physics Majors Freshmen 15 19 Sophomores 10 19 Juniors 19 17 Seniors 11 12 Step 2 of 2: What is the probability that she selects a freshman, given that she chooses a non-physics major? Enter a fraction or round your answer to 4 decimal places, if necessary.
Given that individual is a non-physics major, the probability of choosing a freshman is around [tex]0.2342[/tex].
What are examples and probability?It is predicated on the likelihood that something will occur. The justification for probability serves as the basic foundation for theoretical probability. For instance, the theoretical chance of receiving a head while tossing a coin is 12.
How would you describe elementary probability?Calculating a result or the likelihood that an event would ever occur is known as simple probability. Probability statistics are used by insurance firms to calculate the likelihood of having to pay out using a claim. By dividing one possible outcome by all other possible possibilities, one may determine a basic probability.
P(Non-Physics Major) [tex]= (19+19+17+12) / 122 = 0.7049[/tex]
P(Freshman) [tex]= (15+19) / 122 = 0.2951[/tex]
P(Non-Physics Major / Freshman) [tex]= 19 / (15+19) = 0.5588[/tex]
All of these values may now be entered into Bayes' theorem:
P(Freshman / Non-Physics Major)[tex]= 0.5588 * 0.2951 / 0.7049 ≈ 0.2342[/tex]
Therefore, the probability of selecting a freshman given that the student is a non-physics major is approximately [tex]0.2342[/tex].
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a. A circular park of radius 14 m has a road of 7 m width all around on its outside. Find the area of the road.
A circular park of radius 14 m has a road of 7 m width all around on its outside then the area of the road is approximately 153.943 square meters.
The circular park has a radius of 14 m. This means that the diameter of the park is 2 x 14 = 28 m. The road around the park has a width of 7 m. This means that the total width of the park and the road is 28 + 7 + 7 = 42 m. The area of the circular park can be found using the formula for the area of a circle: Area of park =[tex]π x r^2 = π x 14^2 = 615.752 m^2[/tex] (rounded to 3 decimal places)
The area of the park and the road can be found by calculating the area of the larger circle and subtracting the area of the park: Area of park and road =[tex]π x (r+7)^2 - π x r^2 = π x (14+7)^2 - π x 14^2 = π x 21^2 - π x 14^2 = π x (441 - 196) = π x 245 = 769.695 m^2[/tex] (rounded to 3 decimal places)
To find the area of just the road, we need to subtract the area of the park from the area of the park and road: Area of road = Area of park and road - Area of park = 769.695 - 615.752 =[tex]153.943 m^2[/tex] (rounded to 3 decimal places)
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I cant figure it out I need help
For the given figure, the area of the shaded region is obtained as 100 m².
What is area?
An object's area is how much space it takes up in two dimensions. It is the measurement of the quantity of unit squares that completely cover the surface of a closed figure.
The area of shaded region can be obtained as -
Area of shaded region = Area of rectangular concrete path - Area of rectangular lawn
The formula for area of rectangle is -
Area of rectangle = Length × width
The area of rectangular concrete path is -
Length = (30+2) m = 32 m
width = (18+2) m = 20 m
Area of rectangular concrete path = 32 × 20
Area of rectangular concrete path = 640 m²------(1)
The area of rectangular lawn is -
Length = 30 m and width = 18 m
Area of rectangular lawn = 30 × 10
Area of rectangular lawn = 540 m²------(2)
To find the are of shaded region subtract equation (2) from (1) =
Area of shaded region = (1) - (2)
Area of shaded region = (640 – 540) m²
Area of shaded region = 100 m²
Therefore, the total area of concrete is 100 m².
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A rectangular lawn 18 m by 30 m is surrounded by a concrete path 1 m wide. Draw a diagram of the situation and find the total area of concrete.
I NEED HELP!!! RN ASAP!
Write each decrease as a percent.
Illustrate each answer with a
number line.
a) The price of a book decreased from
$15.00 to $12.00.
b) The number of students who take
the bus to school decreased from 200 to 150
We can calculate the percentages according to the amounts provided in the prompt, and then make a number line to illustrate each percentage as follows:
a) The price of the book decreased by 20%.
$15.00 $12.00
|-----------------|------->
100% 80%
b) The percentage decrease in the number of students who take the bus to school is 25%.
200 150
|-----------------|------->
100% 75%
How to calculate percentagesCalculating percentages involves finding a portion of a whole expressed as a fraction of 100. To calculate a percentage, divide the part by the whole and then multiply the result by 100.
For example, if 20 out of 100 students are absent, the percentage of absent students is:
(20/100) x 100 = 20%.
With that in mind, we can conclude that we have correctly answered this question.
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shapes of obtuse triangles occur in real life objects such as kites and architectural designs. note: matlab onramp and the textbook are cited for reference. suppress the output of each calculation by adding a semicolon at the end of each command. the code has syntax that will display your results. reference 1: matlab onramp, entering commands, task 5. https://matlabacademy.mathworks/r2022b/portal.html?course
By using the "acosd" function in MATLAB, you can easily calculate the angles of obtuse triangles in real-life objects.
The shapes of obtuse triangles occur in real-life objects such as kites and architectural designs. An obtuse triangle is a type of triangle that has one obtuse angle, which means that one of its angles is greater than 90 degrees.
These types of triangles can be seen in many real-life objects, such as kites, which often have an obtuse angle at the top where the two sides of the kite meet. Similarly, architectural designs often include obtuse angles in order to create unique and interesting shapes.
In terms of using MATLAB to calculate the angles of an obtuse triangle, you can use the "acosd" function to calculate the angle in degrees. For example, if you have a triangle with sides of length 3, 4, and 5, you can use the following code to calculate the angle between the sides of length 3 and 4:
angle = acosd((3^2 + 4^2 - 5^2)/(2*3*4));
This will give you an angle of 90 degrees, which is a right angle. However, if you change the lengths of the sides to create an obtuse triangle, such as a triangle with sides of length 3, 4, and 6, you can use the same code to calculate the obtuse angle:
angle = acosd((3^2 + 4^2 - 6^2)/(2*3*4));
This will give you an angle of approximately 98.13 degrees, which is an obtuse angle. By using the "acosd" function in MATLAB, you can easily calculate the angles of obtuse triangles in real-life objects.
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unit 6 homework 3
help please
Part 1: Triangles are similar by Side-Side-Side similarity.
Part 2: Triangles are similar angle-Angle (AA) similarity.
Explain about the similarity of the triangles?The 3 triangle similarity theorems, Side-Angle-Side (SAS), Angle-Angle (AA), and Side-Side-Side (SSS), can also be used to compare two triangles.Triangles are similar if they have two that share a single angle type, or AA (Angle-Angle). Triangles are identical if they have two sets of proportional sides with equal included angles, or SAS (Side-Angle-Side).Part 1: Ratios must be equal for triangle similarity.
Taking the ratios of the sides:
17/37.4 = 20/44 = 25/55
On solving
0.4545 = 0.4545 = 0.4545
As the ratios are equal, triangles are similar.by Side-Side-Side similarity.
Part 2:
∠F = ∠H (given)
∠EGF = ∠JGH (vertically opposite)
By Angle-Angle (AA) similarity.
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The correct question is 1 and 2.
An acorn falls from the branch of a tree to the ground 25 feet below. The distance, S, that the acorn is from the
ground as it falls is represented by the equation S(t) = -16t² + 25, where t is the number of seconds. For which
interval of time is the acorn moving through the air?
0
0
○ 0
O
A
54
Step-by-step explanation:
the acorn falls from the height of 25 feet above the ground, it means the initial time when it falls is t = 0. The time when it lands on the ground is t = 1.25
So the acorn was in the air for 1.25 seconds
a certain type of flashlight requires two type-d batteries, and the flashlight will work only if both its batteries have acceptable voltages. suppose that 90% of all batteries from a certain supplier have acceptable voltages. among ten randomly selected flashlights, what is the probability that at least nine will work? (round your answer to three decimal places.)
The probability that at least nine flashlights will work is 0.3874 or 0.387 to three decimal places.
Given: A certain type of flashlight requires two type-D batteries, and the flashlight will work only if both its batteries have acceptable voltages.
Suppose that 90% of all batteries from a certain supplier have acceptable voltages. Among ten randomly selected flashlights,
what is the probability that at least nine will work?Let p be the probability that any single battery has an acceptable voltage.
Let X be the number of flashlights out of 10 that work.
Then X has a binomial distribution with n=10 and p=0.9.
The probability that at least nine of the ten flashlights work is P(X≥9).
We have
[tex]P(X=9)= 10C_9 \times 0.9⁹ \times 0.1 = 0.3874
P(X=10)= 10C_10 \times 0.9¹⁰ \times 0 = 0[/tex]
P(X≥9) = P(X=9) + P(X=10)
= 0.3874 + 0
= 0.3874
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Find the volume of the sphere. Either answer in terms of π or use 3.14 for π and round your final answer to the nearest hundredth.
Answer:
V = (4/3)π(4^3) = 256π/3 cubic units
if you can help, please do
The equation that represents the variation is given by F = 42m/p
What is an equation?An equation is an expression that shows the relationship between numbers and variables using mathematical operators such as addition, subtraction, exponent, multiplication and division.
F varies directly as m and inversely with p, hence:
F ∝ m/p
Let k represent the constant of proportion. Therefore:
F= k*m/p
F = 36 when m = 6 and p = 7. Hence:
36 = k*6 / 7
k = 36 * 7 / 6
k = 42
The equation is F = 42m/p
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Write the expanded form of the expression. − 2 5(y−x)
The expression −25(y-x) can be expanded by multiplying -25 to each term inside the parentheses:
-25(y - x) = -25y + 25x
Therefore, the expanded form of the expression is -25y + 25x.
\( \ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right]= \)
The value of [tex]\( \ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right] \)[/tex] is:
[tex]\ln \sqrt{x^{3}} - \ln \left(2 \cdot \sqrt[3]{(4 x+1)^{7}}\right)\][/tex]
To find the value of \[tex]( \ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right] \)[/tex], we can use the following steps:
1. Factor out [tex]\( \left(x^{3}-2\right)^5 \)[/tex]:
[tex]\[ \ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right][/tex] = [tex]ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \frac{\sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}}{1}\right]\][/tex]
2. Use the product rule for logs:
[tex]\[ \ln \left[\frac{\left(x^{3}-2\right)^{5} \cdot \frac{\sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}}{1}\right] = \ln \left(x^{3}-2\right)^5 + \ln \left(\frac{\sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right)\][/tex]
3. Evaluate each logarithm separately:
[tex]\[ \ln \left(x^{3}-2\right)^5 = 5\ln \left(x^{3}-2\right) \]\[ \ln \left(\frac{\sqrt{x^{3}}}{2 \cdot \sqrt[3]{(4 x+1)^{7}}}\right)[/tex] = [tex]\ln \sqrt{x^{3}} - \ln \left(2 \cdot \sqrt[3]{(4 x+1)^{7}}\right)\][/tex]
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Please follow the directions
Based on the information in the table, the graph shows a diagonal going down from left to right.
How to graph on a cartesian plane?To graph in a Cartesian plane we must be clear that it is a tool to graph the coordinates. The first number of the coordinate corresponds to the x-axis (horizontal) and the second number corresponds to the y-coordinate (vertical). According to the above, we can infer the graph would look like this (image attached). This graph corresponds to a function because it is a constant, in this case it is a diagonal line that descends from left to right.
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Which expression(s) have the same value as 100?
Expression A: 202-3(102)
Expression B: 8(42) + 24
Expression C: 152-53
which equation represents this ellipse? (x-6)^2 /49 + (y-2)^2 / 9 = 1
The equatiοn that represents the given ellipse is[tex](x-6)^2 /49 + (y-2)^2 / 9 = 1[/tex].
This is because the equatiοn οf an ellipse with centre (h, k), hοrizοntal axis length 2a, and vertical axis length 2b are given by:
[tex](x-h)^2 / a^2 + (y-k)^2 / b^2 = 1[/tex]
In this case, the centre οf the ellipse is (6, 2), the hοrizοntal axis length is 2 * 7 = 14, and the vertical axis length is 2 * 3 = 6. Therefοre, we have:
a = 7, b = 3, h = 6, k = 2
Substituting these values intο the general equatiοn οf an ellipse, we get:
[tex](x-6)^2 / 7^2 + (y-2)^2 / 3^2 = 1[/tex]
Simplifying this equatiοn, we get:
[tex](x-6)^2 /49 + (y-2)^2 / 9 = 1[/tex]
Therefοre, the equatiοn that represents the given ellipse is[tex](x-6)^2 /49 + (y-2)^2 / 9 = 1.[/tex]
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Answer:
The answer is A on edge :)
Step-by-step explanation:
goodluck <3
what is the solution pls help
Answer:
n=15.1
Step-by-step explanation:
14.8=n-0.3
14.8+0.3=n
15.1=n
Find the value of x and y from the given figure.
Answer:
x=120 and y=60
Step-by-step explanation:
As we know, a straight line is 180 degrees.
To find x, you would do 180= 60 + x to get 120.
I forget how but I know y= 60 because its the same angle as 60 degrees.
Find the slope of the line that passes through the points (−6,5) and (2,5).
m= y2-y1/x2-x1
m= 5-5/2+6= 0
Answer: The slope is equal to zero
Step-by-step explanation:
Find the slope of (-6,5) and (2,5)
First subtract the x coordinates 2 and -6
which equals 8
Next subtract the y coordinates 5 and 5
which equals o
Then you get 8/0 and when you simplify you get 0, so the slope is zero.
Hence , write down the equation with y as the subject ( in terms of x ). The value of m and q must be indicated
The equation with y as the subject is y = x^m / (4x^n - 2)
To solve for y as the subject of the equation, we need to isolate y on one side of the equation. Here's how we can do it,
First, we can rearrange the equation to get all the y terms on one side:
4x^n y - 2y = x^m
Next, we can factor out y from the left-hand side,
y(4x^n - 2) = x^m
Finally, we can divide both sides by (4x^n - 2) to isolate y,
y = x^m / (4x^n - 2)
Therefore, the equation with y as the subject is:
y = x^m / (4x^n - 2)
where m and n are the constants given in the original equation.
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The given question is incomplete, the complete question is:
Hence , write down the equation with y as the subject ( in terms of x ). The value of m and q must be indicated. equation 4x^ny -2y - x^m = 0, m and n are constant
Which of the following are valid conclusions given parallelogram ABCD with diagonals AC and BD? You may select more than one answer
The answer is d. While it is possible for a parallelogram to be a square, it is not a valid conclusion given only the information that ABCD is a parallelogram and has diagonals AB and BD.
What is parallelogram?A parallelogram is a four-sided plane figure with two pairs of parallel and equal sides. Opposite sides of a parallelogram are of equal length and the opposite angles are of equal measure. The area of a parallelogram is determined by multiplying the length of one side with the height of the parallelogram. Parallelograms are quadrilaterals, which means they have four sides, and are classified by their angles and sides.
To determine if the parallelogram is also a square, additional information such as the length of the sides or angles of the parallelogram would need to be known.
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Complete questions as follows-
Which of the following is not a valid conclusion given parallelogram ABCD with diagonals AB and BD?
a
AB=CD
b
AC=BD
c
d
m
The diameter of the mirror with the frame is 17
inches. To the nearest hundredth, what is the area of only the frame? Use 3.14
for π
The area οf οnly the frame is apprοximately 50.27 square inches.
What is the area οf a circle?The area οf a circle is the amοunt οf surface inside the bοundary οf a circle. It is a measure οf hοw much space the circle takes up in twο-dimensiοnal space. The fοrmula tο calculate the area οf a circle is:
[tex]A = \pi r^2[/tex]
where A is the area οf the circle and r is the radius οf the circle.
The diameter οf the mirrοr with the frame is 17 inches, and the diameter οf οnly the mirrοr (withοut the frame) is 15 inches.
Therefοre, the width οf the frame is:
17 inches (diameter οf mirrοr with frame) - 15 inches (diameter οf οnly mirrοr) = 2 inches
Sο the radius οf the mirrοr withοut the frame is:
r₁= (15 inches / 2) = 7.5 inches
The area οf the mirrοr withοut the frame is:
A₁= π(7.5)² square inches ≈ 176.71 square inches
The radius οf the mirrοr with the frame is:
r₂= (17 inches / 2) = 8.5 inches
The area οf the mirrοr with the frame is:
A₂= π(8.5)² square inches ≈ 226.98 square inches
The area οf οnly the frame is the difference between these twο areas:
=A₂-A₁
=π(8.5)²- π(7.5)² square inches
≈ 50.27 square inches
Therefοre, the area οf οnly the frame is apprοximately 50.27 square inches.
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Question 4 [14 marks]
Part a) (6 marks)
Find the following probabilities by checking the z table i) P(-1.5
ii) P((1.15
Z0.35
Part b) (8 marks)
Battery manufacturers compete on the basis of the amount of time their products last in cameras and toys. A manufacturer of alkaline batteries has observed that its batteries last for an average 26 hours when used in a toy racing car. The amount of time is normally distributed with a standard division of 2.5 hours.
What is the probability that the battery lasts between 25 and 29 hours?
What is the probability that the battery lasts longer than 29 hours
What is the probability that the battery lasts less than 25 hours.
The probability that the battery lasts less than 25 hours is 0.3446.
The probability of P(Z > -1.5) is 0.9332. The value of -1.5 has to be positive for this computation because the normal distribution curve is symmetrical about the z = 0 line. The probability of being at z = -1.5 is the same as being at z = +1.5. Thus, the probability is found by referencing the z-table for the area under the curve to the right of the mean: 0.9332.
The probability of P(Z < 1.15) is 0.8749. The area below z = 1.15 is needed for this calculation. The probability that the standard normal random variable is less than 1.15 is 0.8749.iii) The probability of P(Z > 0.35) is 0.3632. The area under the curve to the right of the mean is needed. The probability that the standard normal random variable is greater than 0.35 is 0.3632.
Given that, the amount of time the battery lasts in a toy racing car is normally distributed with a mean of 26 hours and a standard deviation of 2.5 hours. Let X denote the time a battery lasts, which is a normally distributed random variable. Find the following probabilities:a) P(25 < X < 29)To calculate the probability,
we first standardize the values of 25 and 29 using the formula below:
z1 = (25 - 26) / 2.5 = -0.4 and z2 = (29 - 26) / 2.5 = 1.2 Now, we find the probability as shown:P(-0.4 < Z < 1.2) = P(Z < 1.2) - P(Z < -0.4) = 0.8849 - 0.3446 = 0.5403 Thus, the probability that the battery lasts between 25 and 29 hours is 0.5403.b) P(X > 29)
To find the probability, we first standardize the value of 29 using the formula below:z = (29 - 26) / 2.5 = 1.2 Now, we find the probability as shown:P(Z > 1.2) = 1 - P(Z < 1.2) = 1 - 0.8849 = 0.1151 Thus, the probability that the battery lasts longer than 29 hours is 0.1151.c) P(X < 25)To find the probability, we first standardize the value of 25 using the formula below:z = (25 - 26) / 2.5 = -0.4 Now, we find the probability as shown:P(Z < -0.4) = 0.3446
Thus, the probability that the battery lasts less than 25 hours is 0.3446.
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Reggie ran for 180 yards during the last football game, which is 40 more yards than his previous personal best. Monte ran 50 more yards than Adrian during the same game. If Monte ran the same amount of yards Reggie ran in one game for his previous personal best, how many yards did Adrian run? Define your variables
We want to find the number of yards Adrian ran during the last game, which is represented by the variable a. Adrian ran 90 yards during the last football game.
Let's define the variables we will use in this problem:
r: the number of yards Reggie ran during his previous personal best.
m: the number of yards Monte ran during the last game.
a: the number of yards Adrian ran during the last game.
From the problem statement, we know that:
Reggie ran for 180 yards during the last game, which is 40 more yards than his previous personal best: r + 40 = 180.
Monte ran 50 more yards than Adrian during the same game: m = a + 50.
Monte ran the same amount of yards Reggie ran in one game for his previous personal best: m = r.
We want to find the number of yards Adrian ran during the last game, which is represented by the variable a. To solve for a, we need to use the information we have to create an equation that relates a to the other variables.
From the equation r + 40 = 180, we can solve for r by subtracting 40 from both sides: r = 180 - 40 = 140.
Substituting m = r into the equation m = a + 50, we get: r = a + 50.
Now we can substitute the value of r we found earlier into this equation: 140 = a + 50.
Solving for a, we subtract 50 from both sides: a = 90.
Therefore, Adrian ran 90 yards during the last football game.
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Drag each tile to the correct box. Arrange the functions in decreasing order of their periods. Y=-3cos(x+2pi) y=2/3cot(pi/4)+6 y=1/2tan(5pi/6 + pi)
y=5csc(3x)+6 y=-10sin(pi/5 - 2pi)
Step-by-step explanation:
The correct order of the functions in decreasing order of their periods is:
y = -10sin(pi/5 - 2pi)
y = 2/3cot(pi/4)+6
y = 5csc(3x)+6
y = 1/2tan(5pi/6 + pi)
y = -3cos(x+2pi)
Note: The periods of trigonometric functions are determined by the coefficient of the independent variable (x in this case). The period of y = asin(bx + c) or y = acos(bx + c) is 2pi/b, and the period of y = atan(bx + c) or y = acot(bx + c) is pi/b. The period of y = acsc(bx + c) or y = asec(bx + c) is 2pi/|b|.
What is 2/3 x 3/8
show your work
Answer:
Decimal: 0.25
Fraction: 1/4
Step-by-step explanation:
2 / 3 * 3/8
2/3 X* 3/8
=
2 × 3
3 × 8
=
6/ 24
=
6 ÷ 6
24 ÷ 6
=
1/4
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Question 1 (1 point ) If y varies directly as x and y=15 when x=12 find y when x=32 a 40 b ,5 c ,-5 d -40
a is correct
Question 1 (1 point )If y varies directly as x and y = 15 when x = 12, find y when x = 32. The value of y when x = 32 is 40.How to solve direct variation problems?A direct variation is a function that can be expressed in the form y = kx, where k is a nonzero constant. Two quantities x and y are said to be in direct variation if they satisfy this relationship. To solve direct variation problems, you can use the following formula: y = kx, where k is the constant of variation.The solution to the problem is given below:Given:y varies directly as xx = 12, y = 15To find:y when x = 32Formula:Since y varies directly as x, we have:y = kxLet's substitute x and y values in the above equation:15 = k × 1215/12 = kk = 5/4Thus, the equation of the direct variation is: y = (5/4) xTo find the value of y when x = 32, substitute 32 for x:y = (5/4) × 32y = 40Therefore, y = 40 when x = 32. Hence, the option (a) is correct.
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