The residual for a predicted relative abundance when the rainfall was 3 inches is 1.25. What is the actual relative abundance when the rainfall was 3 inches

Answers

Answer 1

Answer:

The actual relative abundance will be "7.59".

Step-by-step explanation:

The residual on something like a curve anywhere at a point becomes expressed as the maximum at either the position between some of the real y-value as well as the expected y-value. Consequently, the difference regarding true relative abundance as well as expected relative abundance seems to be 1.25 whether we presume that the x-variable represents rainfall, as well as they-variable, represents the relative abundance of locusts.

The predicted relative abundance for 3 inches rainfall will be:

= [tex]6.7 - (0.12\times 3)[/tex]

= [tex]6.34[/tex]

The residual will be:

= [tex]actual - predicted \ relative \ abundance[/tex]

= [tex]1.25[/tex]

Now,

The actual relative abundance will be:

= [tex]1.25 + predicted \ relative \ abundance[/tex]

= [tex]1.25 + 6.34[/tex]

= [tex]7.59[/tex]

Remember that perhaps the residual positive value means that even the calculation underestimates the relative abundance. The real relative abundance, however, is 7.59.


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Step-by-step explanation:

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Answers

Answer:

c

Step-by-step explanation:

edge2020

The solutions to the quadratic equation 4(x + 2)² = 36 is x = -5 and x = 1.

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What is a Quadratic Equation?

Quadratic equation is simply an algebraic expression of the second degree in x. Quadratic equation in its standard form is;

ax² + bx + c = 0

Where x is the unknown

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Given that;

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4( x(x + 2) + 2(x+2) ) = 36

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The solutions to the quadratic equation 4(x + 2)² = 36 is x = -5 and x = 1.

Hence, option c) x = -5 and x = 1 is the correct answer.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:.

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Answer:

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Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

Confidence interval formula is expressed as;

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Answers

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3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10 2 Hours Late 1/20 3 Hours Late 1/20​

Answers

Answer:

The expected value of lateness [tex]\frac{7}{20}[/tex] hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

  Lateness             P (Lateness)

  On Time                     4/5

1 Hour Late                  1/10

2 Hours Late                1/20

3 Hours Late                1/20​

The formula of expected value of a random variable is:

[tex]E(X)=\sum x\cdot P(X=x)[/tex]

Compute the expected value of lateness as follows:

[tex]E(X)=\sum x\cdot P(X=x)[/tex]

         [tex]=(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}[/tex]

Thus, the expected value of lateness [tex]\frac{7}{20}[/tex] hours.

An expected value is the theoretical mean value of a numerical experiment over many repetitions of the experiment.

Expected value of lateness is  [tex]\frac{7}{20}[/tex] hours.

Let us consider, P(x) is represent that probability of lateness and x represent number of hours late.

So, below a table is formed.

         x       0             1            2           3

      P(x)      4/5         1/10      1/20       1/20

From formula of expected value,

        E(x) = ∑ x P(x)

[tex]E(x)=(0*\frac{4}{5} )+(1*\frac{1}{10} )+(2*\frac{1}{20} )+(3*\frac{1}{20} )\\\\E(x)=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20} \\\\E(x)=\frac{7}{20}[/tex]

So, expected value of lateness is 7/20 hours.

Learn more:

https://brainly.com/question/23286309

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