The price of 40L petrol is £24, find the price of each litre.

Answer:

Exact Form: 309/25

Mixed Form: 12 and 9/25

Step-by-step explanation:

Answer:

14.5

Step-by-step explanation:

AB is halfway between MN and PO. this means it would be the distance halfway between 9 units (length of MN) and 20 units (length of PO). to find this, find the average of 20 and 9. 20+9= 29. 29/2= 14.5

Answer:

0.000000001

Step-by-step explanation:

Let's convert this :

0.000000001

  tHT      M    B

t=tenths

H=Hundredths

T=Thousandths

M=millionths

B=Billionths

Answer:

i think probably x∉∅

Step-by-step explanation:

3x-7 = 3x+9

-7 = 9

so x∉∅

Answer:

0 = 16 or No Solution

Step-by-step explanation:

1) Add  7   to both sides of the equation

3x - 7 + 7 = 3x + 9 + 7

2) Simplify

A. Add the numbers

3x = 3x + 9 + 7

B. Add the numbers

3x = 3x + 16

3) Subtract 3x  from both sides of the equation

3x - 3x = 3x + 16 - 3x

4) Simplify

A. Combine like terms

0 = 3x + 16 - 3x

B. Combine like terms

0 = 16

Answer:

Marcus has 24 pens while Bryan has 12 pens.

Step-by-step explanation:

Let u rep 1 unit.

Marcus = 2u

Bryan = u

2u+u=36

   3u=36

     u=36÷3

       =12

No. of pens Marcus has

= 2u

= 2×12

= 24

No. of pens Bryan has

= u

= 12

Answer:

1. If you live in Manila(hypothesis) then you live in the Philippines ( conclusion)

2. If a triangle is a right triangle (hypothesis), then one of its interior angle is a 90-degree angle ( conclusion)

3. A square is not a triangle (conclusion)

4. An even number is divisible by 2. (conclusion)

5. The measure of an acute angle is less than 90. (conclusion)

Answer:

8s+8

Step-by-step explanation:

Put it into groups: (4s+4s)+(10-2)=8s+8

Brainliest is appreciated

Answer:

(4s+4s)+(10-2)= 8s/8 =1   so s=1

Step-by-step explanation:

Answer:

ok

Step-by-step explanation:

Answer: 8250

Step-by-step explanation:

Answer:

8548

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

Negative numbers are smaller than positive numbers.

Answer:

Your correct 6.55 is a positive number while -6.5 is negitive and positive numbers are always larger then negitive ones

Hope This Helps!!!

y = x+9 because the y-intercept of the function represented by the table is 5.

============================================================

Explanation:

Let's focus on the first two rows of the table. Plug those coordinates into the slope formula below.

m = (y2-y1)/(x2-x1)

m = (13-9)/(4-2)

m = 4/2

m = 2

The slope is 2.

Then we'll use something like (x,y) = (2,9) along with the slope we found to determine the y intercept b

y = mx+b

y = 2x+b

9 = 2*2+b

9 = 4+b

9-4 = b

5 = b

b = 5

The equation for the table is y = 2x+5

We can check this by seeing that x = 6 leads to y = 2*x+5 = 2*6+5 = 17. I'll let you check the other x values of the table.

Because y = 2x+5 has a y intercept of 5, we're going to aim for answer choice B. The y intercept of y = x+9 is 9 which is larger than what we just found.

Answer:

l*b*h is the answer of this question

Answer:

he didnt subtract each equations on both sides

5y-6=4y+1

-4       -4

y  -6=1

  +6=+6

y=7

Step-by-step explanation:

hope that wrk

If the given equations are indeed

[tex]\begin{cases}x-\frac4{5y} = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

we can solve by substitution. Solve the second equation for x :

[tex]-14x - 4y = -46[/tex]

[tex]\implies 7x + 2y = 23[/tex]

[tex]\implies7x = 23 - 2y[/tex]

[tex]\implies x = (23 - 2y)/7[/tex]

Substitute this into the first equation and solve for y :

[tex]\dfrac{23-2y}7 - \dfrac4{5y} = 9\dfrac45[/tex]

On the right side, write the mixed number as an improper fraction:

[tex]9 + \dfrac45 = \dfrac{45}5 + \dfrac45 = \dfrac{45+4}5 = \dfrac{49}5[/tex]

[tex]\implies \dfrac{23-2y}7 - \dfrac4{5y} = \dfrac{49}5[/tex]

Multiply both sides of this equation by 35y (the LCM of the denominator of all three fractions)

[tex]35y \times \dfrac{23-2y}7 - 35y \times \dfrac4{5y} = 35y \times \dfrac{49}5[/tex]

[tex]5y\times(23-2y) - 7\times4 = 7y \times 49[/tex]

[tex]115y - 10y^2 - 28 = 343y[/tex]

[tex]10y^2 + 228y + 28 = 0[/tex]

[tex]5y^2 + 114y + 14 = 0[/tex]

To solve the quadratic, I'll complete the square :

[tex]5\left(y^2 + \dfrac{114}5y\right) + 14 = 0[/tex]

[tex]5\left(\left(y + \dfrac{57}5\right)^2 - \left(\dfrac{57}5\right)^2 \right) + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 - \dfrac{57^2}5 + 14 = 0[/tex]

[tex]5\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}5[/tex]

This system has no real solutions since the square of any real number must be positive.

If we allow complex numbers, we can continue solving to end up with two complex solutions for y,

[tex]\left(y + \dfrac{57}5\right)^2 = -\dfrac{3179}{25}[/tex]

[tex]y + \dfrac{57}5 = \pm i \sqrt{\dfrac{3179}{25}}[/tex]

[tex]y = -\dfrac{57}5 \pm i\dfrac{17\sqrt{11}}5[/tex]

and we can go on to solve for x.

Hence my comment; I suspect you meant to write the system

[tex]\begin{cases}x-\frac45 y = 9\frac45 \\ -14x - 4y = -46\end{cases}[/tex]

because its solution is far simpler. Multiplying through the first equation by 5 gives

[tex]5\times x - 5 \times \dfrac45 y = 5 \times 9\dfrac45[/tex]

[tex]\implies 5x - 4y = 49[/tex]

(since we know 9 + 4/5 = 49/5)

Meanwhile, multiplying through the second equation by -1 gives

[tex]-1 \times (-14x) + (-1) \times (-4y) = -1 \times (-46)[/tex]

[tex]\implies 14x + 4y = 46[/tex]

So if we combine the two equations, we can eliminate y and solve for x :

[tex](5x - 4y) + (14x + 4y) = 49 + 46[/tex]

[tex]\implies 19x = 95[/tex]

[tex]\implies \boxed{x = 5}[/tex]

and solving for y gives

[tex]14x + 4y = 46[/tex]

[tex]\implies 70 + 4y = 46[/tex]

[tex]\implies 4y = -24[/tex]

[tex]\implies \boxed{y = -6}[/tex]

Answer:

static electricty

Step-by-step explanation:

it is preserved charge

Answer:

its electroboom not boy

Step-by-step explanation:

lol its static

Answer:

290

Step-by-step explanation:

145 withdrawal free + 145 in cash = 290.

Answer:

UV=5, VW=5[tex]\sqrt{3}[/tex], and m∠U=60

Step-by-step explanation:

sin 30=UV/10=>0.5=UV/10=>UV=5

VW=√(10²-5²)=√75=5√3

m∠U=180-90-30=60

Answer:

17.08

Step-by-step explanation:

When it reaches its maximum, suppose that y = 0

Therefore you will need to factorise and solve

-16x^2 + 267 x + 107 = 0

Here you can use the quadratic equation[tex]\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex]

Where you will get x = -0.39 seconds or 17.08 seconds (rounded to 2 decimal places according to the question

Because -0.39 is negative, this answer can be deleted

Leacing x = 17.08 seconds

Answer:

42

Step-by-step explanation:

(10x3) + (2x6)

= 30 + 12

= 42

10x + 2 y = (10.3) +(2.6) = 30+12=42

Our answer is 42

Answer:

blah blah

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

65% more than 140 is  231

Answer:

Step-by-step explanation:

Answer:

x=-38

Step-by-step explanation:

-19*2=-38

Hope this helps! Pls give brainliest! Also sub to kgir633 on yt.

Answer:

< 18, - 29 >

Step-by-step explanation:

a = 5b - 6c

   = 5 < 6, 5 > - 6 < 2, 9 > { multiply each element by the scalar ]            

   = < 30, 25 > - < 12, 54 > [ subtract corresponding elements ]

   = < 30 - 12, 25 - 54 >

    = < 18, - 29 >

Answer:

a=(18,-29)

Step-by-step explanation:

You plug (6,5) in for 5b and you plug (2,9) in for -6c so now you get a=5(6,5)-6(2,9) then you cross multiply the 5 and the -6 therefore you get a=(30,25)+(-12,-54) then you add them together getting the answer a=(18,-29).

Answer:

8.0029 x[tex]10^{1}[/tex]

Step-by-step explanation:

8 x 10=80

2 x [tex]\frac{1}{100}[/tex]=0.02

9x[tex]\frac{1}{1,000}[/tex]= 0.009

add all ur answers together and u get 80.029

then in standard form that nwould be 8.0029 x[tex]10^{1}[/tex]

Hoped that helped:P

Answer:

-78.85

Step-by-step explanation:

Using Order of Operations (PEDMAS):

23.15 – [ 115 + ( 12 - 25)]

= 23.15 – [ 115 + (-13)]

= 23.15 – [ 115 - 13]

= 23.15 -  102

= -78.85

Answer:

238 kg

Step-by-step explanation:

If 4 bushels weight 112, then divide 112 by 4 and you get that each bushel weighs 28 kg. Now multiply that by 8.5.

Answer in fraction form is:    y ≤ (1/2)x - 5  or  [tex]y \le \frac{1}{2}x-5[/tex]

Answer in decimal form is:  y ≤ 0.5x - 5

You only need to pick one answer format.

========================================================

Explanation:

The drawing is below.

Let's label the four given points as A,B,C,D

For now, let's focus on the boundary points A(-2, -6) and B(4, -3). A straight line in the form y = mx+b passes through these points. Compute the slope.

m = (y2-y1)/(x2-x1)

m = (-3 - (-6))/(4 - (-2))

m = (-3 + 6)/(4 + 2)

m = 3/6

m = 1/2

m = 0.5

Now let's use one of those (x,y) points along with that m value to find the y intercept b. I'll use the coordinates from point A.

y = mx+b

-6 = 0.5*(-2)+b

-6 = -1 + b

-6+1 = b

-5 = b

b = -5

The equation of the boundary line is y = 0.5x-5 which is the same as saying y = (1/2)x - 5 or [tex]y = \frac{1}{2}x-5[/tex]. We can refer to this as line AB.

-------------------------------

If you were to plot all four points (A,B,C,D) on the same xy grid, then you'd find that point D is on line AB. We're told that point D is a solution to the inequality, which must mean we are going to involve "or equal to" as part of the inequality sign. This will allow points on the boundary to be part of the solution set.

Notice how point C is below line AB. Since point C is also a solution, this means we go for "less than" to shade below the boundary. Overall, the sign we go for is "less than or equal to" or in short ≤

Therefore, the inequality is y ≤ 0.5x - 5

which is the same as writing y ≤ (1/2)x - 5  or [tex]y \le \frac{1}{2}x-5[/tex]

Explanation:

We're given that

Note that P(A)*P(B) = 0.53*0.17 = 0.0901 which is somewhat similar to 0.901 but not entirely the same. We have an extra zero between the decimal point and the nine. So this indicates that [tex]P(A)*P(B) \ne P(\text{A and B})[/tex]. Therefore, events A and B are not independent. We consider them dependent.

Answer:

53/12

Step-by-step explanation:

Conversion a mixed number 4 3/

4

to a improper fraction: 4 3/4 = 4 3/

4

= 4 · 4 + 3/4

= 16 + 3/

= 19/

4

To find a new numerator:

a) Multiply the whole number 4 by the denominator 4. Whole number 4 equally 4 * 4/

4

= 16/4

b) Add the answer from previous step 16 to the numerator 3. New numerator is 16 + 3 = 19

c) Write a previous answer (new numerator 19) over the denominator 4.

Four and three quarters is nineteen quarters

Subtract: 19/

4

- 1/

3

= 19 · 3/

4 · 3

- 1 · 4/

3 · 4

= 57/12

- 4/12

= 57 - 4/12

= 53/12

Answer:

  a) x = {-2 2/3, -2}

  b) x = {-8, 3}

  c) x = {-1, 23}

Step-by-step explanation:

If all you want are solutions, a graphing calculator can give them to you easily. The attachment shows the solutions as x-intercepts when the equation is rearranged to the form f(x) = 0.

__

In general, it can be convenient to write the equation in standard form with integer coefficients. Common factors among the coefficients should be removed.

  3(x+4)^2 = 10x +32 . . . . . given

  3(x^2 +8x +16) -10x -32 = 0

  3x^2 +14x +16 = 0

To factor this, we're looking for factors of 3·16 that total 14.

  48 = 1·48 = 2·24 = 3·16 = 4·12 = 6·8

The last pair of factors has a total of 14, so we can rewrite the equation as ...

  (3x +6)(3x +8)/3 = 0

  (x +2)(3x +8) = 0

The solutions are the values of x that make the factors zero:

  x = -2, x = -8/3

__

  (x +4)^2 = 3x +40 . . . . . . . . given

  x^2 +8x +16 -3x -40 = 0 . . . . subtract the right side

  x^2 +5x -24 = 0 . . . . . . . . simplify

  (x +8)(x -3) = 0 . . . . . . factor

The solutions are the values of x that make the factors zero:

  x = -8, x = 3

__

  (x^2 -1)/2 -11x = 11 . . . . . given

  x^2 -1 -22x -22 = 0 . . . . . . multiply by 2, subtract the right side

  x^2 -22x -23 = 0 . . . . . . simplify

  (x -23)(x +1) = 0 . . . . . . factor

  x = 23, x = -1

_____

Additional comment

Factoring often gets to the solution with the least fuss when the solutions are rational. There are several ways factoring can be done when the leading coefficient is not 1. One of them is illustrated in (a) above. We will show two other methods that give the same result.

factoring by pairs

We have identified the factors of 3·16 = 48 that have a total of 14. We can use those factors to rewrite the 14x term in the equation.

  3x^2 +6x +8x +16 = 0

Now, we can group the terms in pairs, and factor each pair. It does not matter which of the factors (6 or 8) you write first. You will end with the same result.

  (3x^2 +6x) +(8x +16) = 0

  3x(x +2) +8(x +2) = 0

  (3x +8)(x +2) = 0   ⇒   x = -8/3, x = -2

__

factoring using the X method

This method is usually shown using a large graphic X. In the top quadrant is written the product of the leading coefficient and the constant: 3·16 = 48.

In the bottom quadrant is written the coefficient of the x-term: 14.

If one or the other, or both, of these top/bottom values is negative, be sure to keep the sign.

The side quadrants are then filled with values that have a product equal to the top number, and a sum equal to the bottom number. (Pay attention to the signs.) Further, in each of those quadrants, the number written is divided by the leading coefficient, and the fraction reduced to lowest terms.

Here, we would have 6/3 = 2 on one side, and 8/3 on the other side. Now the factors are written as (bx+a), where the reduced fraction on either side is a/b. In our example, the factors are (x+2) and (3x+8)

__

alternate X method

This starts off in the same way the X method does, as described above. However, the factors on either side of the X are not divided by the leading coefficient (a). If those side values are 'p' and 'q', the quadratic is written in factored form as ...

  (ax +p)(ax +q)/a = 0

You will notice we used this form above: (3x +6)(3x +8)/3 = 0.

Now, the divisor 'a' can be used to reduce either or both of the numerator factors. Here, the entire factor of 3 can be removed from (3x+6) to make the factorization be ...

  (x +2)(3x +8) = 0

__

Sometimes, one factor of the divisor will be removed from one term, and the other factor of it will be removed from the other term. An example of this might be ...

  [tex]\dfrac{(6x+3)(6x+2)}{6}=\dfrac{6x+3}{3}\cdot\dfrac{6x+2}{2}=(2x+1)(3x+1)[/tex]