The height of women ages 20-29 is normally distributed, with a mean of 63.7 inches. Assume sigma = 2.5 inches. Are you more likely to randomly select 1 woman with a height less than 64.4 inches or are you more likely to select a sample of 21 women with a mean height less than 64.4 inches? Explain.

Answers

Answer 1

Is due to the fact that the standard error of the sample mean decreases with increasing sample size, leading to a more accurate estimation of the population mean.

To determine whether it is more likely to randomly select one woman with a height less than 64.4 inches or a sample of 21 women with a mean height less than 64.4 inches, we need to calculate the probability in each case.

Case 1: Randomly selecting 1 woman with height less than 64.4 inches

Since the height is normally distributed with a mean of 63.7 inches and a standard deviation of 2.5 inches, we can use the z-score formula to calculate the probability of selecting a woman with height less than 64.4 inches:

z = (64.4 - 63.7) / 2.5 = 0.28

From the standard normal distribution table, we can find that the probability of selecting a woman with a z-score of 0.28 or less is approximately 0.6103. Therefore, the probability of randomly selecting one woman with a height less than 64.4 inches is 0.6103.

Case 2: Selecting a sample of 21 women with mean height less than 64.4 inches

Since we are dealing with a sample mean, we need to use the central limit theorem, which tells us that the distribution of sample means will be approximately normal, with a mean of the population mean (63.7 inches) and a standard deviation of the population standard deviation divided by the square root of the sample size (2.5 / sqrt(21) = 0.545).

Using the same formula as before, we can calculate the z-score for a sample mean of less than 64.4 inches:

z = (64.4 - 63.7) / (2.5 / sqrt(21)) = 1.252

From the standard normal distribution table, we can find that the probability of selecting a sample mean with a z-score of 1.252 or less is approximately 0.8944. Therefore, the probability of selecting a sample of 21 women with mean height less than 64.4 inches is 0.8944.

Conclusion:

Based on the calculated probabilities, we can conclude that it is more likely to select a sample of 21 women with mean height less than 64.4 inches, as the probability of this event is higher than the probability of randomly selecting one woman with height less than 64.4 inches. This is due to the fact that the standard error of the sample mean decreases with increasing sample size, leading to a more accurate estimation of the population mean.

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Related Questions

In the figure, ∠1 = (5x)°, ∠2 = (4x + 10)° and, ∠3 = (10x − 5)°. What is ∠3, in degrees?

Answers

Using angle sum property of triangle, the measure of angle ∠3 is 87.1°.

Given that, m∠1 = (5x)°, m∠2 = (4x + 10)° and m∠3 = (10x − 5)°.

Angle sum property of a triangle is m∠1 + m∠2 + m∠3 = 180°

Here, (5x)° + (4x + 10)°  + (10x − 5)° = 180°

(5x + 4x + 10  + 10x − 5) = 180

(19x + 10 − 5) = 180

(19x + 5) = 180

19x = 180 - 5

19x = 175

x = 175/19

x ≈ 9.21

Then, substitute the value of x in (10x − 5)°,

= (10(9.21) − 5)°

= (92.1 − 5)°

= (92.1 − 5)°

= 87.1°

Thus, using angle sum property of triangle, the measure of angle ∠3 is 87.1°.

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QUESTION 2When drawing up a timetable, the following principles must bekept in mind, or taken into consideration:a. Educators should be efficiently deployed, and teaching loadss should be balanced across the timetable.b. The capacity of the building will determine whether thelearners move from classroom to classroom, or whether the educatorsmove or both groups move.c. It should allow for non-teaching timed. Educators should be timetabled to teach the learning areas orsubjects in which they are trainede. Balance: practical subjects or double periods should notfollow too closely upon teach other2.1 Reflect on the school timetable you followed during teachingpractice and elaborate on the above-mentioned points with the aidof one practical example for each.

Answers

Educational psychology provides teachers with research-based principles to guide their teaching.

When teachers go through educational psychology, they are taught on ways to improve their teaching.

These ways will be based on research overtime that have proved efficient in helping students learn from teachers.

Some of these include empowering school social and cultural structures, minimizing bias, implementing an equity pedagogy, the method of knowledge creation, and integrating content (Banks, 1995a).

The main goal of multicultural education is to reduce barriers to educational opportunity and success for students from different cultural backgrounds. The principle that all pupils, regardless of culture, deserve educational equity serves as its cornerstone.

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What value is a discontinuity of x squared plus 7 x plus 1, all over x squared plus 2 x minus 15?
NEED HELP FAST

Answers

At x equals -5 and x equals 3 our function is discontinuous.

We have been given a rational function:

f(x) = [tex]\frac{x^{2}+7x+1 }{x^{2} +2x-15}[/tex]

We are asked to find the points at which our function is discontinuous.

A rational function is discontinuous when the function is undefined or the denominator is zero.

Let us find what values of x will make our denominator zero.

[tex]x^{2} +2x-15=0[/tex]

We will use factoring to find the zeros of x. By splitting the middle term we will get,

[tex]x^{2} + 5x - 3x -15=0\\\\x(x+5)-3(x+5)=0[/tex]

(x +5)(x - 3) = 0

x = -5 and x = 3

Therefore, at x equals -5 and x equals 3 our function is discontinuous.

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out of a group of 100 people what is the probability that there exactly 10 days with exactly 3 birthdays

Answers

The probability of there being exactly 10 days with exactly 3 birthdays out of a group of 100 people is extremely low, approximately 4.63 x [tex]10^{-37}[/tex]

To answer this question, we need to use the concept of probability. The probability of an event happening is the number of desired outcomes divided by the total number of possible outcomes.
In this case, the desired outcome is that there are exactly 10 days with exactly 3 birthdays. To calculate this probability, we need to consider the total number of ways that 100 people can be distributed across 365 days.
There are a total of [tex]365^{100}[/tex] possible ways to distribute birthdays. However, not all of these possibilities are valid because we are looking for exactly 10 days with exactly 3 birthdays.
We can use the formula for combinations to calculate the number of ways that 10 days can be selected out of 365. This is given by:
C(365, 10) = 3.535 x [tex]10^{21}[/tex]
For each of these combinations, we need to calculate the number of ways that exactly 3 people can be assigned to each of the 10 days. This is given by:
[tex]C(100, 3)^{10}[/tex] = 7.917 x [tex]10^{61}[/tex]
The total number of valid outcomes is the product of these two values:
3.535 x [tex]10^{21}[/tex] x 7.917 x [tex]10^{61}[/tex] = 2.798 x [tex]10^{83}[/tex]
The probability of the desired outcome is then:
Desired outcomes / Total outcomes = [tex]2.798 * 10^{83} / 365^{100}[/tex] = 4.63 x[tex]10^{-37}[/tex]

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What is the nth term of 5. 5 7 2008. 5 10 11. 5

Answers

Therefore, the nth term of the sequence is approximately 29.94.

Assuming that the sequence is formed by alternating between adding 1.5 and multiplying by a constant factor, the nth term can be calculated using the following formula:

nth term = [tex]5.5 * c^{((n-1)//2}) + 1.5 * ((n-1) % 2)[/tex]

Here "//" represents integer division, "%" represents the modulo operator, and c is the constant factor that multiplies each term.

Assuming that the constant factor is 1.5 and the sequence starts with the first term being 5.5, the first few terms of the sequence would be:

5.5, 7, 10.5, 16, 24.5, 37, 55.5, 83, 124.5, ...

Using the formula above, we can find the nth term for any given value of n. For example, the 10th term would be:

nth term = 5.5 * [tex]1.5^4[/tex]+ 1.5 * 1

= 5.5 * 5.0625 + 1.5

= 29.9375

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Correct Question:

What is the nth term of 5.5 7  2008.510 11.5.

for each of the following linear operators t on a vector space v and ordered bases {3, compute [t),e, and determine whether f3 is a basis consisting of eigenvectors of t.

Answers

Given a linear operator T on a vector space V and an ordered basis {3}, we need to compute the matrix representation [T] with respect to this basis. Once we have the matrix [T], we can find its eigenvectors and eigenvalues

To address your question, we first need to understand the concepts involved:

1. A linear operator (T) is a function that maps a vector space V to itself, while preserving the structure of the space.
2. An ordered basis is a linearly independent set of vectors that spans the vector space V.
3. [T] is the matrix representation of the linear operator T with respect to the ordered basis.
4. Eigenvectors are non-zero vectors that satisfy the equation T(v) = λv, where λ is a scalar called an eigenvalue.

. If the eigenvectors of T form a basis for the vector space V (i.e., they are linearly independent and span the space), then we can say that F3 is a basis consisting of eigenvectors of T.

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Short Questions: Answer the following questions. Justify your answer mathematically.
a. (6 pnts) Write the negation of the following statement: ∀x ∃y,y > x.
b. (6 pnts) Write the negation of following statement: There exists an integer n such that 2n2 −5n + 2 = 0.
c. (6 pnts) Prove or disprove: ∃x ∀y,(y > x) ⇒ (y > 6).
d. (6 pnts) Prove or disprove: If n is a real number, then either n > 7 or n ≤ 9.
e. (12 pnts) Prove by contraposition: if the product of two integers is odd then both of the integers must be odd.

Answers

A.  The negation of the given statement is "There exists an x such that for all y, y is not greater than x".

B. The negation of the given statement is "For all integers n, 2n² - 5n + 2 is not equal to 0".

E. the statement is true by contraposition.

What are integers?

Integers are a type of number that includes all positive whole numbers (1, 2, 3, ...), zero (0), and negative whole numbers (-1, -2, -3, ...). In mathematical notation, the set of integers is denoted by the symbol Z.

a. The given statement is ∀x ∃y, y > x. Its negation is ¬(∀x ∃y, y > x), which is equivalent to ∃x ¬(∃y, y > x). By De Morgan's law, we can simplify this as ∃x ∀y, ¬(y > x). Therefore, the negation of the given statement is "There exists an x such that for all y, y is not greater than x".

b. The given statement is ∃n ∈ Z, 2n² − 5n + 2 = 0. Its negation is ¬(∃n ∈ Z, 2n² − 5n + 2 = 0), which is equivalent to ∀n ∈ Z, 2n² − 5n + 2 ≠ 0. Therefore, the negation of the given statement is "For all integers n, 2n² - 5n + 2 is not equal to 0".

c. To disprove the statement, we need to find a counterexample where the statement is false. Let x = 10. Then, for any y greater than 10, y is also greater than 6. Therefore, the statement is true for this choice of x, and hence the statement is true.

d. To prove the statement, we can use proof by contradiction. Assume that there exists a real number n such that n ≤ 7 and n > 9. This is a contradiction, and hence our assumption must be false. Therefore, the statement "If n is a real number, then either n > 7 or n ≤ 9" is true.

e. To prove by contraposition, we need to show that if one of the integers is even, then the product of the integers is even. Let's assume that one of the integers is even, say a = 2k. Then, the other integer can be odd or even, but in either case, the product of the integers will be even. Therefore, the statement is true by contraposition.

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When do we use n, p and q? When we are testing a proportion, a
mean (average), or both?
Explain.

Answers

When testing a proportion, we use p and q to represent the proportion of success and failure, respectively.

For example, if we are testing the proportion of students who passed a test, we would use p to represent the proportion who passed and q to represent the proportion who did not pass.

When testing a mean (average), we use n to represent the sample size. For example, if we are testing the average height of a sample of individuals, we would use n to represent the number of individuals in the sample.

In some cases, we may use all three terms when testing both a proportion and a mean. For example, if we are testing the proportion of students who passed a test and the average score of those who passed, we would use p and q to represent the proportion of success and failure, and n to represent the sample size of those who passed. We would also use the mean to represent the average score of those who passed.

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Here are the scores of 13 students on an algebra test.
65, 72, 73, 73, 77, 80, 81, 82, 83, 85, 86, 90, 91
Notice that the scores are ordered from least to greatest.
Give the five-number summary and the interquartile range for the data set.

Answers

Answer:

Q1=65

Range= 65-91= 26

Median= 81

Mode= 73

Median=953 ( if your confused on how to get mode juts add all the scores of the 13 students and then divided by the 13 students so 65,+ 72,+ 73+, 73, +77, +80, +81, +82, +83, +85,+ 86,+ 90,+ 91+÷13=953)

Q2=91

Assume that the situation can be expressed as a linear cost function. find the cost function
fixed cost is $300; 40 items cost $2,300 to produce
The linear cost function is C(x)=????

Answers

C(x) is the linear cost function: C(x) = $50x + $300

Where x denotes the number of things manufactured.

What is function?

A function connects an input with an output. It is analogous to a machine with an input and an output. And the output is somehow related to the input. The standard manner of writing a function is f(x) "f(x) =... "

To find the linear cost function, we need to determine the slope of the cost function and the value of the y-intercept.

Given that 40 items cost $2,300 to produce, we can use this information to find the slope:

Slope = (Change in cost) / (Change in quantity)

Slope = (Total cost for 40 items - Fixed cost) / (40 items - 0 items)

Slope = ($2,300 - $300) / (40 - 0)

Slope = $2,000 / 40

Slope = $50 per item

The fixed cost of $300 represents the y-intercept of the cost function.

Therefore, the linear cost function C(x) is:

C(x) = $50x + $300

Where x represents the number of items produced.

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In a carnival game, players get 5 chances to
throw a basketball through a hoop. The dot
plot shows the number of baskets made by
20 different players.

Answers

Answer:

140

Step-by-step explanation:

7/20 = 0.35 = 35% of the 20 players made all five baskets.

If this trend holds up, then we should expect 35% of the 400 people to make all five baskets.

35% of 400 = 0.35*400 = 140

We expect about 140 people will make all five baskets.

Note how 140/400 = 0.35 = 35%

-------------

Through another alternative method, we can solve like this

7/20 = x/400

7*400 = 20*x ... cross multiply

2800 = 20x

20x = 2800

x = 2800/20 ... dividing both sides by 20

x = 140 which is the same result as before

it's going to be 150 baskets made

The 22 students in Mrs. Aire's class, each purchased balloons to decorate for a party in the gym. Each student paid $3.80. About how much money did the students spend?​

Answers

Answer:

$83.60

Step-by-step explanation:

22 x $3.80 = $83.60

Any process that generates well-defined outcomes is _____.
a. a sample point
b. an event
c. an experiment
d. None of these answers are correct.

Answers

The correct answer is c. an experiment. An experiment is a process or procedure that is carried out to generate outcomes, often to test a hypothesis or answer a research question. These outcomes are usually well-defined and measurable, and can be used to draw conclusions or make predictions.

An experiment is any process that generates well-defined outcomes. In the context of probability and statistics, an experiment is a procedure or action that produces a specific and identifiable result. The term "outcomes" refers to the possible results of an experiment. Each experiment may have one or more possible outcomes, and the collection of these outcomes is known as the sample space. The outcomes of an experiment must be well-defined and measurable to be properly analyzed and to draw meaningful conclusions.

In statistics and probability theory, an experiment is often used to refer to a controlled test or study in which one or more variables are manipulated to observe the effect on the outcome. The results of an experiment can be used to inform decisions, improve processes, or develop new products or services. Therefore, any process that generates well-defined outcomes can be considered an experiment, as long as it involves some form of systematic observation or measurement.
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What’s the answer for the question please?

Answers

The correct expression is the one in option A; [tex]-3^{15}[/tex]

How to simplify the expression?

Here you need to remember two rules for exponents, these are:

[tex]x^n*x^m = x^{n +m}\\\\[/tex]

And:

[tex](x^n)^m = x^{n*m}[/tex]

Now our expression is:

[tex]-(3^2*3^3)^3[/tex]

Using the first rule we will get:

[tex]-(3^2*3^3)^3 = -(3^{2 + 3})^3 = -(3^5)^3[/tex]

Using the second rule:

[tex]-(3^5)^3 = -3^{3*5} = -3^{15}[/tex]

The correct option is a

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HELP ME!!!!!!!! LEAP PRACTICE!!!!!!!! (MATH)!!!!!!!

Answers

Answer:I can't see the question

Step-by-step explanation:

Evaluate 7-\left(-19\right)-18+\left(-19\right)+187−(−19)−18+(−19)+187, minus, left parenthesis, minus, 19, right parenthesis, minus, 18, plus, left parenthesis, minus, 19, right parenthesis, plus, 18

Answers

The value of the numerical expression 7 − (−19) − 18 + (−19) + 18 will be 7.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The expression is given below.

⇒ 7 − (−19) − 18 + (−19) + 18

Simplify the expression, then the value of the expression is given as,

⇒ 7 − (−19) − 18 + (−19) + 18

⇒ 7 + 19 − 18 − 19 + 18

⇒ 7

The worth of the mathematical articulation 7 − (−19) − 18 + (−19) + 18 will be 7.

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Quasilinearization Method
Q10-) Give some examples for the maximal solution and minimal
solution of first order IVP.

Answers

The Quasilinearization Method is a technique used to approximate solutions for nonlinear differential equations by linearizing them iteratively. It is particularly helpful when solving first-order IVPs.

A maximal solution to a first-order IVP is a solution that exists on the largest possible interval, while a minimal solution exists on the smallest possible interval.

Example 1:
Consider the first-order IVP: dy/dt = y^2, y(0) = 1.

Maximal solution: The maximal solution to this IVP is y(t) = 1/(1 - t) on the interval (-∞, 1).

Minimal solution: The minimal solution is the same as the maximal solution for this example, as there are no other solutions that exist on a smaller interval.

Example 2:
Consider the first-order IVP: dy/dx = x + y, y(0) = 0.

Maximal solution: The maximal solution to this IVP is y(x) = -x + e^x - 1 on the interval (-∞, +∞).

Minimal solution: The minimal solution is the same as the maximal solution for this example since there are no other solutions that exist on a smaller interval.



In both examples, the Quasilinearization Method can be applied to linearize the differential equations and approximate the solutions. The maximal and minimal solutions represent the largest and smallest possible intervals where the solutions are valid.

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At the end of each quarter, $4,000 is placed in an annuity that earns 6% interest, compounded quarterly. Find the
future value of the annuity in 10 years
.
$204,567.98
$234,541.92
O $217,071.56.
$247, 893.09

Answers

Answer:

  (c)  $217,071.56

Step-by-step explanation:

You want the value of an ordinary annuity after 10 years when payments of $4000 are made quarterly and the interest is 6%.

Calculator

A suitable financial calculator can tell you the value of 40 quarterly payments that earn an 6% annual rate will be $217,071.58.

Formula

Or, you can use the ordinary annuity formula to find the future value:

  FV = P(n/r)((1 +r/n)^(nt) -1)

  FV = 4000(4/0.06)((1 +0.06/4)^(4·10) -1) = 4000/0.015(1.015^40 -1)

  FV ≈ 217,071.575645 ≈ 217,071.58

The future value of the annuity in 10 years is $217,071.58.

__

Additional comment

The discrepancy in the offered answer choice(s) appears not to be due to rounding of the final value. Perhaps there was some unfortunate rounding of intermediate values when it was calculated.

The radius of a circle is 9 miles. What is the area of a sector bounded by a 180° arc? 180° Give the exact answer in simplest form. JT Submit r=9 mi 00 square miles​

Answers

The area of sector that is bounded by the 180° sector arc, obtained from the formula for the area of circle is 40.5·π square miles

What is the formula for finding the area of a circle?

The area of a circle can be obtained from the product of the pi and the square of the radius of the circle.

Mathematically, the area of a circle = π × (Radius)²

The length of the radius of the circle = 9 miles

The angle bounded by the sector = 180°

The area bounded by the sector is therefore;

Area of the sector = (180/360) × π × 9² = 40.5·π square miles

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if four of the exterior angles of a convex polygon each equal 56 degrees what is the measure of the fifth anngles

Answers

In a convex polygon, the sum of all the exterior angles is always equal to 360 degrees. Given that the four of the exterior angles each measure 56 degrees, we can find the measure of the fifth angle by following these steps:

Here is the step by step explanation

1. Calculate the sum of the four exterior angles that is  4 x 56 = 224 degrees.

2. Subtract the sum of the four angles from the total sum of exterior angles in a convex polygon (360 degrees): 360 - 224 = 136 degrees.

Therefore, the measure of the fifth exterior angle is 136 degrees.

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Construct a confidence interval for assuming that each sample is from a normal population (a) -26,0 = 3, n=15, 90 percentage confidence (Round your answers to 2 decimal places.)

Answers

The 90% confidence interval for the population mean is (-9.05, 15.05).

To construct a confidence interval for a population mean with a known standard deviation when the sample size is less than 30, we use the formula:

CI = x ± z*(σ/√n)

where x is the sample mean, σ is the population standard deviation, n is the sample size, z is the z-score associated with the desired confidence level, and CI is the confidence interval.

Given the information provided, we have:

x = 3

σ = 26

n = 15

The desired confidence level is 90%, which corresponds to a z-score of 1.645 (from the standard normal distribution table)

Substituting these values into the formula, we get:

CI = 3 ± 1.645*(26/√15)

CI = 3 ± 12.05

Therefore, the 90% confidence interval for the population mean is (-9.05, 15.05).

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A Belt working in a supply chain environment has to make a decision to change suppliers of critical raw materials for a new product upgrade.
The purchasing manager is depending on the Belt's effort requiring that the average cost of an internal critical raw material component be less than or equal to $3,600 in order to stay within budget.
Using a sample of 42 first article components, a Mean of the new product upgrade price of $3,200 and a Standard Deviation of $180 was estimated.
Based on the data provided, the Z value for the data assuming a Normal Distribution is?
Response:
5.42
4.30
2.22
1.11

Answers

Based on the data provided and assuming a Normal Distribution, the Z-value is 2.22.

To determine the Z value for the data assuming a Normal Distribution, we will use the following formula:
Z = (X - μ) / σ
Where:
Z = Z value
X = average cost of internal critical raw material component (which should be less than or equal to $3,600)
μ = mean of the new product upgrade price ($3,200)
σ = standard deviation ($180)

First, we need to determine the difference between the desired average cost and the mean:
Difference = $3,600 - $3,200 = $400
Next, we will divide the difference by the standard deviation:
Z = $400÷$180 ≈ 2.22

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To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not lonner than 122 cm. Which inequality can be used to represent the lengths of the glass that will fit in the frame?

Answers

The inequality that can be used to represent the lengths of the glass that will fit in the frame is 12 < x ≤ 122

How to determine the inequality can be used to represent the lengths of the glass that will fit in the frame

We are given that the length, x, of a piece of glass must be longer than 12 cm but not longer than 122 cm in order to fit in an existing frame.

This can be represented mathematically using the inequality 12 < x ≤ 122

Therefore, the inequality that can be used to represent the lengths of the glass that will fit in the frame is 12 < x ≤ 122

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An object in the shape of a rectangular prism has a length of 7 inches, a width of 6 inches, and a height of 4 inches. The object's density is 10.6 grams per cubic centimeter. Find the mass of the object to the nearest gram.

Answers

The mass of the object to the nearest gram is 29223 grams.

We have,

The volume of the rectangular prism.

V = length x width x height

Substituting the given values, we get:

V = 7 x 6 x 4 = 168 cubic inches

We need to convert the volume to cubic centimeters since the density is given in grams per cubic centimeter.

There are 2.54 centimeters in an inch, so:

V = 168 cubic inches x (2.54 cm/in)³

V = 2755.392 cubic centimeters

Now we can find the mass of the object.

mass = density x volume

Substituting the given density and calculated volume, we get:

mass = 10.6 g/cm³ x 2755.392 cm³

mass = 29223.1232 grams

Rounding to the nearest gram, we get:

mass = 29223 grams

Therefore,

The mass of the object to the nearest gram is 29223 grams.

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The following population data of a basic design of a product are given as:
1. Base product:
average length = 90 cm
with a standard deviation of the length = 7 cm
2. A modifications was made to this product and a sample of 12 unit was collected. The sample is shown in the table to the right:
3. Test at a=0.01 whether there is difference between standard deviations (+/-) of this product's length between the base and the modified product?
a) What is/are the critical value(s)?
b) What is/are the test statistic(s)?
c) Was there a difference ? Yes or No

Answers

We conclude that there is a significant difference between the standard deviations of the base and modified product's length.

To test if there is a difference between the standard deviations of the two populations, we can use the F-test.

a) The critical values for the F-distribution with 11 and 11 degrees of freedom at α = 0.01 are 0.250 and 4.025 (found using a statistical table or calculator).

b) The test statistic for the F-test is calculated as:

[tex]F = s1^2 / s2^2[/tex]

where s1 and s2 are the sample standard deviations of the base product and the modified product, respectively.

s1 = 7 cm (given in the problem)

s2 = 3 cm (calculated from the sample data)

Thus, the test statistic is:

F = ([tex]7^2[/tex]) / ([tex]3^2[/tex]) = 16.33

c) To determine if there is a difference between the standard deviations, we compare the test statistic to the critical values. Since our test statistic (16.33) is greater than the critical value of 4.025, we reject the null hypothesis that the standard deviations are equal. Therefore, we conclude that there is a significant difference between the standard deviations of the base and modified product's length.

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. Divide
6x³+x²+7x+9
2x+1

Answers

The polynomial long division of 6x³+x²+7x+9 by 2x+1 gives a quotient of 3x² - x + 4

Dividing using polynomial long division

From the question, we have the following parameters that can be used in our computation:

6x³+x²+7x+9 by 2x+1

Using the polynomial long division setup, we have

2x + 1   |  6x³ + x² + 7x + 9

Evaluating the division, we have

              3x² - x + 4

2x + 1   |  6x³ + x² + 7x + 9

              6x³ + 3x²

             ---------------------------------------

                     -2x² + 7x + 9

                     -2x² - x

             ---------------------------------------

                           8x + 9

                           8x + 4

                        ---------------------------------------

                                  5

                                 

Hence, the quotient is 3x² - x + 4

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Express the numbers on the graph as an inequality, set notation, and interval notation

Answers

The inequality is -2 < x ≤ 1 and the interval notation is ( -2 , 1 ]

Given data ,

Let the inequality be represented as A

Now , the value of A is

-2 < x ≤ 1

And , Interval notation: (-2, 1]

In interval notation, the parentheses "(" and ")" represent open intervals, which means the endpoints are not included, and the square bracket "]" represents a closed interval, which means the endpoint is included.

And , Set-builder notation: {x | -2 < x ≤ 1}

In set-builder notation, the vertical bar "|" is read as "such that," and the inequality -2 < x ≤ 1 describes the set of all values of x that satisfy this condition.

Hence , the inequality is -2 < x ≤ 1

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Two histograms showing the number of hours students in the jazz band practiced in a week are shown. The sample
mean of Group 1's data is 2.57. The sample mean of Group 2's data is 3.337.

Which statement about the two histograms is true?

Graph 1 has a larger sample standard deviation than Graph 2.

Graph 2 has a larger sample standard deviation than Graph 1.

Both graphs have the same sample standard deviation.

The relationship of the sample standard deviations cannot be determined.

Answers

Answer:

The Answer Is B "Graph 2 has a larger sample standard deviation than Graph 1"

Step-by-step explanation:

Because the message in the text said the mean of Group 1's data is 2.57 while the sample mean of Group 2's data is 3.337 and from what I understand. 3.337 is a lot more than 2.57

Answer:

  (b)  Graph 2 has a larger sample standard deviation than Graph 1

Step-by-step explanation:

Given the two histograms of hours practiced, you want to know the relationship between the sample standard deviations of the two data sets.

Standard deviation

The standard deviation is a measure of data variability. It will tend to be larger for less-symmetrical data distributions, and for those that are skewed one way or another.

The data of Graph 2 is less symmetrical than that of Graph 1, so we expect its standard deviation to be higher. A computation of the standard deviation confirms this.

Graph 1 standard deviation: about 1.40

Graph 2 standard deviation: about 1.53

Graph 2 has a larger sample standard deviation than Graph 1, choice B.

__

Additional comment

In the computation, the first list (L1) is the set of data values. The second list, {2, 3, 4, ...} for example, is their relative frequencies—the heights of the bars in the histogram.

The given mean values seem to show that each bar is represented by its midpoint value, 0.5 for the first bar, for example. For the purpose of the standard deviation calculation, we don't need to make that adjustment.

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Write an exponential decay function to the model the situation compare the average rates of change over the given intervals

Initial value:58

Decay factor:0. 9

1

Answers

To write an exponential decay function to the given model and we compare the average rate of changes over the given intervals. Then the average rate of change comes out to be, for situation 1 is-4.065 and situation 2 is -2.667.

It is given that,

Initial value: 50

Decay factor: 0.9

1 ≤ x ≤ 4 and

5 ≤ x ≤ 8

x = 1

f(x) = 50(0.9)¹

f(x) = 45

x = 4

f(x) = 50(0.9)¹

f(x) = 32.805

Now, the average rate of change for situation 1 where x = 1 and x = 4

= (32.805 - 45) / (4 - 1)

= -4.065

average rate of change for situation 2 where x = 5 and x = 8

= (50(0.9)⁵ - 50(0.9)⁸) / (5 - 8)

= 8.0011 / -3

= -2.667

Thus, the average rate of change for situation 1 is-4.065 and situation 2 is -2.667.

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Note that the full question is:

Write an exponential decay function to the model the situation compare the average rates of change over the given intervals

Initial value: 50

Decay factor: 0.9

1 ≤ x ≤ 4 and

5 ≤ x ≤ 8

1. You buy 3 pounds of organic apples for $7.50. The graph shows the price for regular apples.
What is the unit rate for each type of apple?
9 ν ε
1 2 3 4 5 6
1 2 3 4 5 6
pounds
O organic $2.50/pound; regular $3.00/pound
O organic $0.40/pound; regular $0.50/pound
O organic $2.50/pound; regular $2.00/pound
Onone of the above

Answers

The rate of each type of the given apples above would be = organic apple $2.50/pound;regular $2.00/pound. That is option C.

How to calculate the rate of the two types of apple given?

For organic apple;

The quantity of apples sold for $7.50 = 3 pounds.

The amount that is sold for an apple would be = ?.

That is ;

$7.50 = 3 pounds

$x. = 1 pound

make X the subject of formula;

X = 7.50/3

Therefore 1 pound = 7.50/3 = $2.50/pound.

For regular apple;

The rate can be detected from the graph;

1 pound of apple = $2

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