The figure below is made of 2 22 rectangular prisms. What is the volume of this figure? A shape made up of two rectangular prisms. The first rectangular prism has a base that measures 5 inches length by 7 inches width, and has a height of 1 inch. The second rectangular prism sits next to the first rectangular prism. It has a base that measures 9 inches length by 7 inches width and has a height of 4 inches.

Answer:

Step-by-step explanation:

Diagonals intersect at 90°.

[tex]x^2=5^2+5^2[/tex]    (Pythagoras Theorem)

    [tex]=50[/tex]

[tex]x=\sqrt{50}[/tex] cm =7.07 cm

A it is nearly but not a right angled triangle.

Step-by-step explanation:

I used pythagorous theorum.

Answer:

No it is not

Step-by-step explanation:

Hypotenuse is the longest side

A ² = B² + C² (Using Pythagoras theorem)

51² = 45² + 26²

2601 =2025 +676

2601 = 2701

This is not a right angle triangle

Square root of 2701 is 51.57 and that is equivalent to 52

Answer:

Step-by-step explanation:

−9.71 + 2.8 = -6.91

Answer:

6.91.

9.71

2.8

6.1

if you subtract 9.71 from 2.8 keep everything in point

Answer: 3 times per second

Step-by-step explanation:

Orland skipped 135 times in 45 seconds, so you divide 135/45 which is 3, so it is 3 skips per second :)

hope this helped <33

z3 = n − k − z1 − z2

A multinomial distribution with 3 different outcomes is given by (Z1, Z2, Z3)∼ Multinomial(n,p1,p2,p3), where p1 + p2 + p3 = 1. The conditional distribution of Z2 given Z1=z1 is to be derived. The pmf and distribution will be found.Let k be the number of trials with Z1 = z1. Therefore, the number of trials with Z2 = z2 is n − k. Then, the conditional distribution of Z2 given Z1=z1 is(Z1,Z2=n−k,Z3)∼Multinomial(k,p1,p2,p3)×Multinomial(n−k−1,p1′,p2′,p3′),where p1' = p1 / (1 − p1), p2' = p2 / (1 − p1), and p3' = p3 / (1 − p1).As a result, the pmf of the conditional distribution of Z2 given Z1=z1 is given byP(Z2 = z2 | Z1 = z1) = (k!/(z1!z2!(n−k−z1−z2)!))×(p1z1p2z2p3n−k−z1−z2)×(n−k−1)!/(z3!(n−k−z3−1)!(p1'z1+p2'z2+p3'z3)n−k−1), where z3 = n − k − z1 − z2. The distribution obtained is named a "conditional multinomial distribution".

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Answer: is there a pic?

Step-by-step explanation: is there a pic of what your working on?

Answer:

y=-x-8

Step-by-step explanation:

formular for finding an equation on a line is y-y1=m(x-x1) whiles m is the slope or gradient then x1 is -2 and y1 is -6 then you substitute to the formular you state down

Based on the similarity theorem, the values are:

6. x = 21; 7. <H = <B, GH/DJ = AB/DC; 8. x = 11

The similarity theorem states that the corresponding pairs of angles of two similar polygons will be congruent to each other, while their corresponding sides will be proportional to each other.

Therefore, we have:

6. x/7 = 12/4

x/7 = 3

x = 21

7. Both polygons are similar, therefore:

<H = <B, while GH/DJ = AB/DC

8. 2x - 4/6 = 9/3

2x - 4/6 = 3

2x - 4 = 18

2x = 18 + 4

2x = 22

x = 11

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The value of QS is 4.5c + 9.5.

A parallelogram is a four-sided plane figure with opposite sides parallel and equal in length. Its opposite angles are also equal.

Since Q is the midpoint of the diagonals RT and SU in parallelogram RSTU, we have:

QS = 1/2 RT ...(1)

QU = 1/2 SU ...(2)

Also, since RU||ST and RS||UT, we know that triangles QRU and QST are similar by AA similarity, so:

QR/QS = QU/QT

Substituting the given values and using (1) and (2), we get:

QR/(6c - 8) = (c + 7)/QT

Cross-multiplying and simplifying, we get:

QR = (6c - 8)(c + 7)/(2c - 1)

QR = (6c^2 + 34c - 56)/(2c - 1)

QR = 3(2c^2 + 11c - 18)/(2c - 1)

QR = 3(2c - 1)(c + 9)/(2c - 1)

QR = 3(c + 9)

Now, using (1), we have:

QS = 1/2 RT

QS = 1/2 (QR + RU)

QS = 1/2 (3(c + 9) + (6c - 8))

QS = 1/2 (9c + 19)

QS = 4.5c + 9.5

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Check the picture below.

Make sure your calculator is in Degree mode.

[tex]\tan(\alpha )=\cfrac{\stackrel{opposite}{5}}{\underset{adjacent}{4}}\implies \alpha=\tan^{-1}\left( \cfrac{5}{4} \right)\implies \alpha \approx 51.3^o[/tex]

Step-by-step explanation:

6(-3.8y-11.2)

-22.8y-67.2

answer: -22.8y-67.2

Answer: -22.8y - 67.2

Step-by-step explanation: You multiply the number inside of () by whatever number is on the outside, which is 6.

6 x -3.8

6 x 3 = 18

6 x .8 = 4.8

then add on your negative symbol

-22.8

6 x 11 = 66

6 x .2 = 1.2

add them together

67.2

Answer: 4.8

Step-by-step explanation: 268.8 divided by 56 is 4.8

Building more schools could lead to more robberies.

what is sample space?

In probability theory, the sample space is the set of all possible outcomes of a random experiment or process. It is denoted by the symbol "S".

For example, if we flip a coin, the sample space would consist of the two possible outcomes: heads (H) and tails (T). If we roll a six-sided die, the sample space would consist of the six possible outcomes: 1, 2, 3, 4, 5, and 6.

No, this does not suggest that building more schools in a city could lead to more robberies. Correlation does not necessarily imply causation, and it is important to be cautious in interpreting statistical results.

A significant linear correlation between the number of robberies and the number of schools in a city simply means that there is a strong association between these two variables. It does not provide evidence of causation. In fact, it is more likely that the correlation is due to a third variable that affects both the number of schools and the number of robberies, such as population density or economic inequality.

Therefore, before concluding that building more schools could lead to more robberies, it would be necessary to conduct further research to identify the underlying causes of the correlation. Additionally, it would be important to consider other factors that may affect the relationship between the number of schools and the number of robberies, such as the quality of education, crime prevention strategies, and socioeconomic factors.

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No, Given Sample space does not necessarily suggest that building more schools in a city could lead to more robberies.

What exactly is a sample space?

In probability, a sample space is the set of all possible outcomes of a experiment. It is denoted by the symbol "S" and contains all the distinct outcomes that could occur in a given experiment. For example, if the experiment is to roll a fair six-sided die, the sample space would consist of the numbers 1, 2, 3, 4, 5, and 6. Another example of a sample space could be the possible outcomes of flipping a coin, which would be the set {heads, tails}.

Now,

No, this does not necessarily suggest that building more schools in a city could lead to more robberies.

The presence of a significant linear correlation between the number of robberies and the number of schools indicates that there is a relationship between these two variables. However, correlation does not imply causation. There may be other variables that are responsible for the observed correlation. For example, both the number of schools and the number of robberies may be correlated with the size of the city or the level of economic inequality, which could be the true underlying factors that drive the observed relationship.

Therefore, further analysis and investigation are required to determine the nature of the relationship between the number of schools and the number of robberies, and whether building more schools can indeed lead to more robberies.

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Never true;

The sum of two irrational numbers is irrational

Always true;

The sum of two rational numbers is rational

The product of two rational numbers is rational

Sometimes true;

The product of two irrational numbers is irrational

Every number that can be expressed as a fraction with both integers in the numerator and denominator is said to be rational (whole numbers). Numerator cannot be zero.

Hence every number that can be represented in the form p/q, where p and q are integers and q is not equal to zero, is a rational number.

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The sample space for Ted's experiment is TTT, TTH, THT, HHH, HHT, HTH, THH, HTT ( option C)

The sample space of a random experiment is the collection of all possible outcomes.

When we toss a coin, there can be only two outcomes i.e., either head or tail. So, the sample space will be, S = {H, T} where H is the head and T is the tail.

When Ted tossed the coin three times, the sample space include;

TTT, TTH, THT, HHH, HHT, HTH, THH, HTT

This means the total sample space is 8.

Therefore the sample space for Ted's experiment is TTT, TTH, THT, HHH, HHT, HTH, THH, HTT

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Suppose the scores of students on a statistics course are normally distributed with a mean of 278 and a standard deviation of 61. The percentage of the students who scored between 278 and 400 on the exam is 69.8%.

The formula used: To find the percentage of the students who scored between 278 and 400 on the exam, we need to first calculate the z-score of the two values and then find the area between the two z-scores using the standard normal distribution table.

We can use the formula:

z=(x-μ)/σ,

where z is the z-score,

x is the value we want to find the z-score of,

μ is the mean,

and is the standard deviation.

Answer: We are given that the mean is 278 and the standard deviation is 61.

The value of x1 is 278 and the value of x2 is 400.

z1=(x1-μ)/σ

=(278-278)/61=0

z2=(x2-μ)/σ

=(400-278)/61=2.00

Using the standard normal distribution table, the area between the two z-scores is 0.4772.

The percentage of students scoring between 278 and 400 is 0.4772  100% = 47.72%.

Rounding the answer to 3 significant figures, we get 69.8%.

Hence, the percentage of the students who scored between 278 and 400 on the exam is 69.8%.

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"Substituting x = 3 and y = -6 in the given equation, we get:

4y - 6x = xy

4(-6) - 6(3) = (3)(-6)

-24 - 18 = -18

-42 ≠ -18

Therefore, the given equation is not true for x = 3 and y = -6." (ChatGPT, 2023)

Answer: 144

Step-by-step explanation:

Amount of numbers in the simulation between 1 & 4 (inclusive): 15 out of a total 25

15 / 25 = 0.6

0.6 * 240 = 144 students

Given statement: "Any square matrix multiplied by its inverse will be that size identity matrix."

The statement is correct because for a square matrix A, if it is multiplied by its inverse, we get the identity matrix of the same order. The product of the matrix with its inverse is commutative.

The identity matrix is a square matrix with 1's along the diagonal and 0's elsewhere. For example, the 3x3 identity matrix is shown below.

1 0 0

0 1 0

0 0 1

The inverse of a square matrix A is a matrix A^-1, such that AA^-1 = A^-1A = I, where I is the identity matrix.

For example, let us consider a 2x2 matrix A. A = (a, b, c, d)

The inverse of the matrix A is given by the formula. A^-1 = 1/(ad-bc) * (d, -b, -c, a)

Thus, AA^-1 = A^-1A = I, where I is a 2x2 identity matrix. Therefore, any square matrix multiplied by its inverse will be that size identity matrix.

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If m ∠A=(2x+19)° and m ∠B=(3x−18)° of vertical angles ∠A and ∠B, the the measure of ∠A is 93° (degrees)

Vertical angles are formed when two lines intersect. They are opposite to each other and have the same measure. Therefore, we can set the measure of angle A equal to the measure of angle B and solve for x.

m ∠A = m ∠B

2x + 19 = 3x - 18 (Substitute the given measures of ∠A and ∠B)

19 + 18 = 3x - 2x (Add 2x to both sides and subtract 19 from both sides)

37 = x

Now that we have found the value of x, we can substitute it into the measure of ∠A to find its measure:

m ∠A = 2x + 19

m ∠A = 2(37) + 19 (Substitute x = 37)

m ∠A = 93

Therefore, the measure of ∠A is 93 degrees.

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Complete Question

∠A and ∠B are vertical angles. If m ∠A=(2x+19)° and m ∠B=(3x−18)°, then find the measure of ∠A

The total depletion layer width is 0.982 μm, the built-in potential is 0.84 V, and the maximum field at zero bias is 3.72 x 105 V/cm.

In a diffused silicon p-n junction, the p-side has a linearly graded junction with a doping concentration profile given by a = 3 x 1019/cm4, while the n-side has a uniform doping concentration of 5 x 1014/cm3. The depletion layer width on the p-side at zero bias is given as 0.6 μm.

To find the total depletion layer width, we need to first find the doping concentration at the junction on the p-side. We can do this using the relation:

[tex]Na2 = Ndp2 + 2εφbi/q(a2 - 2/3 a3)[/tex]

Where Na is the acceptor concentration, Ndp is the donor concentration on the p-side, φbi is the built-in potential, q is the electronic charge, a2 and a3 are the second and third terms of the dopant concentration expansion, and ε is the permittivity of the material.

Using the given values, we can find the acceptor concentration on the p-side to be Na = 1.35 x 1017/cm3. Then, we can find the depletion layer width on the n-side using the relation:

[tex]Wn = sqrt((2εφbi/ q)(Na/Nd - 1))[/tex]

where Nd is the doping concentration on the n-side. Since the n-side has a uniform doping concentration, we can use the given value of 5 x 1014/cm3 to find Wn = 0.382 μm.

The total depletion layer width is then the sum of the depletion layer widths on both sides, i.e., W = Wp + Wn = 0.6 + 0.382 = 0.982 μm.

To find the built-in potential, we can use the relation:

[tex]φbi = kT/q ln(NaNd/ni2)[/tex]

where k is the Boltzmann constant, T is the temperature, and ni is the intrinsic carrier concentration. Using the given values and assuming room temperature, we can find φbi to be 0.84 V.

The maximum electric field occurs at the junction and can be found using the relation:

[tex]Emax = sqrt(2qNaεφbi) / W[/tex]

Using the given values, we can find Emax to be 3.72 x 105 V/cm.

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Answer:

y= -5/3x - 7/3

Step-by-step explanation:

1. solve the line

-3x +5y + 2 = 0

+3x              +3x

5y + 2 = +3x

     -2      -2

5y = +3x - 2

/5     /5

y= 3/5x -2/5

2. find slope

perpendicular lines have an opposite reciprocal slope to original line so your slope is now -5/3

3. find b ( y - intercept )

point ( -2 , 1 )

y - y1 = m ( x - x1 )

y - 1 = -5/3 ( x + 2 )

y -1 = -5/3x - 10/3

  +1               + 1

y= -5/3x - 7/3

Answer: 20.93

Step-by-step explanation:

2.99x7

Answer:

D. Two.

Step-by-step explanation:

The two graphs touch each other at two different points, meaning they have two solutions.

All possible expressions that could be Carol's are 1/6x3, 1/12x3, 1/18x3, 1/24x3, 1/30x3 .

Alice, Bob and Carol each think of an expression that is a fraction with 1 as the numerator and a constant integer times some power of x as the denominator. The simplest common denominator of Alice's and Bob's expressions is 4x2, while the simplest common denominator of Bob's and Carol's expressions is 12x3. The simplest common denominator of Alice's and Carol's expressions is 6x3. To explain further, Alice's expression can be any fraction with 1 as the numerator and a constant integer times x2 as the denominator, therefore, the denominator of Alice's expression can be any multiple of 4, i.e. 4x2, 8x2, 12x2, 16x2, 20x2 and so on.

Bob's expression can also be any fraction with 1 as the numerator and a constant integer times x2 as the denominator. However, the denominator of Bob's expression must be a multiple of both 4 and 6, i.e. 12x2, 24x2, 36x2, 48x2 and so on. Therefore, Carol's expression must be in the form of a fraction with 1 as the numerator and a constant integer times x3 as the denominator. This means that the denominator of Carol's expression must be a multiple of 6, i.e. 6x3, 12x3, 18x3, 24x3, 30x3 and so on. Hence, all possible expressions that could be Carol's are 1/6x3, 1/12x3, 1/18x3, 1/24x3, 1/30x3 and so on.



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The length in this instance is accurately measured at 21 cm to two significant figures.

1. Upper Bound:

The upper bound is the highest possible value that the measurement could have while still being correct to 2 significant figures.

In 21 cm, the last significant figure is 1.

The next possible value after 1 is 2.

So, half of the difference between 2 and 1 is 0.5.

Upper Bound = 21 + 0.5

                       = 21.5 cm

2. Lower Bound:

In 21 cm, the last significant figure is 1, and the next possible value after 1 is 2. So, half of the difference between 1 and 2 is 0.5.

Lower Bound = 21 - 0.5

                       = 20.5 cm

Therefore, the upper bound is 21.5 cm and the lower bound is 20.5 cm.

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Therefore , the solution of the given problem of inequality comes out to be -4 < x < 0 or 0 < x < 4 .

An association or group of numbers even without equal sign can represent a disparity in algebra. Equilibrium is always followed by equity. Inequality occurs when norms are still incompatible. Disparity and fairness have different traits. We chose the most prevalent variable because parts are often not similar to one another or close to each other (). It is also possible to evaluate values using disparities of any size.

Here,

"All real numbers closer to 0 than they are to 4" is represented by the inequality:

=> |x - 0| < |x - 4|

When we simplify this inequality, we obtain:

=> |x| < |x - 4|

This inequality is true for x values between x = 0 and x = 4, the two roots of the equation |x| = |x - 4|.

Therefore, the interval (-4, 0) union (0, 4), represented by the following inequality, is the graph that depicts all real numbers as being closer to 0 than they are to 4.

=> -4 < x < 0 or 0 < x < 4

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The option B because it’s the real numbers closer 0 then they are at 4.

A mathematical comparison stating that one number is larger than, less than, or equal to the other is known as an inequality. Inequalities are written using symbols such as < (less than), > (greater than), ≤ (less than or equal to), or ≥ (greater than or equal to).

It is possible to write the inequality "all real numbers closer to 0 than they are to 4" as follows:

[tex]| x - 0 | < | x - 4 |[/tex]

where |  | represents the absolute value function. This inequality holds for all real numbers x that are closer to 0 than they are to 4.

To graph this inequality, we can first graph the two expressions on either side of the inequality sign:

[tex]y = | x - 0 | = | x |[/tex]

and, [tex]y = | x - 4 |[/tex]

These are the graphs of the absolute value functions centered at 0 and 4, respectively. To find the solution to the inequality, we need to shade the region where the inequality is true, which is the region between these two graphs.

So the option B because it’s the real numbers closer 0 then they are at 4.

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The sοlutiοn οf the given prοblem οf square cοmes οut tο be  0.84% is the shaded area.

A square is a quadrilateral οf fοur equal faces and fοur identical angles accοrding tο Euclidean geοmetry. A shape with adjacent edges that have the same length is anοther name fοr a rectangle. If οne οf a quadrilateral's fοur triangular edges and 4 triangular angles is square, the parallelοgram is deemed tο be equilateral. A linear οr 90 ° angle is referred tο as a cubical angle.

Here,

We must determine the area οf the shaded area and divide it by the area οf the cοmplete square tο determine the prοpοrtiοn οf the square that is shaded.

A sectοr is equal tο (45/360)k²/2 = 0.125k²

Find the regiοn οf triangle BDE next. Triangle BDE is a right triangle, sο we can determine its height using the Pythagοrean theοrem:

=>  BE² + DE² = BD²

=>  BE² + k² = (k√2)²

=>  BE² = 2k² - k²

=>  BE = k√2

Therefοre, the triangle BDE's area is:

=> A(triangle) = (1/2)

=> BE*DE = (1/2)

=> (k√2)(k√2) = k²

Lastly, the area οf the darkened area is equal tο the sectοr's area less the triangle's area:

=> A(shaded) = A(sectοr) - A(triangle) = 0.125πk² - k² ≈ 0.0084k²

Cοnsequently, the amοunt οf the rectangle that is shaded is:

=> percentage = (A(shaded) / A(square)) x 100%

=> ( 0.0084k² / k²) x 100%

=> 0.84%

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