Answer & Explanation:
we need to calculate how much the ball drops due to the effect of gravity over the 60.5 ft distance from the pitcher's mound to home plate. We can use the formula:
d = 1/2 x g x t^2
where:
d is the distance the ball drops (in ft)
g is the acceleration due to gravity (32.2 ft/s^2)
t is the time it takes for the ball to travel 60.5 ft at a horizontal speed of 102.5 mi/h (which we need to convert to ft/s)
Converting the horizontal speed from miles per hour to feet per second:
102.5 mi/h = 102.5 x 5280 ft / 3600 s = 150.7 ft/s
Now we can find the time it takes for the ball to travel 60.5 ft:
t = d / v
t = 60.5 ft / 150.7 ft/s
t = 0.401 seconds
Finally, we can use the time to calculate how far the ball drops vertically:
d = 1/2 x g x t^2
d = 1/2 x 32.2 ft/s^2 x (0.401 s)^2
d = 0.517 ft
Therefore, the ball drops vertically by approximately 0.517 ft (or 6.2 inches) by the time it reaches home plate, assuming it is thrown horizontally at 102.5 mi/h.
If a baseball is thrown horizontally at a speed of 102.5 mph, it would fall approximately 2.605 feet vertically by time it reaches the home plate 60.5 feet away.
The subject of this problem belongs to the area of projectile motion. First, we need to know the time it takes for the ball to reach the home plate. Given that the distance to the home plate is 60.5 feet and the ball is thrown at 102.5 mph (which is approximately 150 feet per second when converted), the time can be calculated using the formula
time = distance/speed. This gives us approximately 0.403 seconds.
Next, we use the equation for displacement in the vertical direction under the influence of gravity, h = 0.5gt^2, where g is the acceleration due to gravity (32.2 ft/s^2), and t is time. Plugging in the known values, we get
h = 0.5 * 32.2 * (0.403^2) = 2.605 feet.
Therefore, if a baseball were thrown horizontally at a speed of 102.5 mph, it would drop approximately 2.605 feet vertically by the time it reached the home plate, 60.5 feet away.
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select a synonym for the word necessity a advertisement b extra c requirement d superior
Answer
explanation
requirments
What are the 3 major categories that the elements are grouped into?
A. Non-metals, metals, metalloids
B. Earth metals, Halogens, Noble gases
C. Alkali metals, acidic metals, neutral metals
D. Metals, metalloids, transition metals
Answer:
Metals, nonmetals, and metalloids are three different categories for the elements. Metals may be hammered into sheets and are malleable, ductile, and excellent conductors of heat and electricity (they can be drawn into wire).
Explanation:
Brainliest pls
Answer:
A. Non-metals, metals, metalloids
Explanation:
metals are Group I, II and III and IV
Non metals are Group VII, VI and VIII
What is the vector sum of a vector T~ given by 40 m, 30 degrees and a vector U~ given by 12
m, 225 degrees?
Hence, R = 28.97 m, 24.5 degrees is the vector sum of T and U.
Is a vector at 30 degrees?A vector's direction is frequently stated as a rotation of the vector's "tail" anticlockwise with respect to due East. In accordance with this practise, a vector having a direction of 30 degrees is a vector that has been anticlockwise rotated 30 degrees with respect to due east.
Let's begin by separating the components of the vector T:
T~ = 40 m, 30 degrees
T_x = 40 cos(30) = 34.64 m
T_y = 40 sin(30) = 20 m
Let's now decompose the vector U into its constituent parts:
U~ = 12 m, 225 degrees
U_x = 12 cos(225) = -8.49 m
U_y = 12 sin(225) = -8.49 m
It is possible to combine elements of the same type (x and y):
R_x = T_x + U_x = 34.64 m - 8.49 m = 26.15 m
R_y = T_y + U_y = 20 m - 8.49 m = 11.51 m
The Pythagorean theorem can be used to determine the size of the resulting vector R:
|R~| = sqrt(R_x² + R_y²) = sqrt((26.15 m)² + (11.51 m)²) = 28.97 m
The inverse tangent function can be used to determine the direction of the resulting vector R:
theta = tan⁻¹(R_y/R_x) = tan⁻¹(11.51 m/26.15 m) = 24.5 degree.
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Sergio saw an angle that measures greater than 0° and less than 90°.What type of angle did he see
Two friends are rock climbing on a cliff face. They are 18 m above the
ground. The two friends have a combined mass of 150 kg. Use
9 = 9.8 m/s².
Calculate the gravitational potential energy of the two climbers.
Round your answer to the nearest thousand.
J
The gravitational potential energy of the two climbers would be 26,460 J.
Gravitational potential energy calculationThe gravitational potential energy (PE) of an object is given by the formula:
PE = mgh
where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object above some reference point.
In this case, the combined mass of the two climbers is 150 kg, and they are 18 m above the ground. Using g = 9.8 m/s², we can calculate their gravitational potential energy as:
PE = (150 kg) x (9.8 m/s²) x (18 m) = 26,460 J
Rounded to the nearest thousand, the gravitational potential energy of the two climbers is 26,000 J.
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Two long parallel wires X and Y carry currents 3A and 5A respectively. if the force experienced per unit length by X is 5 *10^-5 N, the force per unit length of Y is _
The force per unit length of Y would be 1.25 * [tex]10^{-3[/tex] N/m.
Force per unit lengthThe force per unit length between two parallel wires carrying currents can be calculated using the equation:
F = μ0 * I1 * I2 * L / (2 * π * d)
where:
F = force per unit lengthμ0 = permeability of free space = 4π * 10^-7 T·m/AI1 and I2 = currents in wires X and Y, respectivelyL = length of wires X and Yd = distance between the wiresSubstituting the given values, we get:
F_X = μ0 * 3A * 5A * L / (2 * π * d) = 5 * 10^-5 N
Solving for F_Y, we get:
F_Y = 2 * F_X * π * d / (μ0 * 5A * L)
= 2 * (5 * 10^-5 N) * π * d / (4π * 10^-7 T·m/A * 5A * L)
= 1.25 * [tex]10^{-3[/tex] N/m
Therefore, the force per unit length experienced by wire Y is 1.25 * 10^-3 N/m.
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You are in charge of designing a study that determines how far the average fire ant travels from its colony to collect resources.
Plan an investigation to provide evidence of the distance traveled by fire ants.
Also describe the process you will use to accurately measure the distance traveled including the tools you will use and the data you will collect.
To accurately measure the distance traveled by the fire ants, we could use a measuring tape or a GPS device. For short distances, a measuring tape would suffice, while for longer distances, a GPS device would provide more accurate measurements.
How to investigate the distance traveled by fire ants to collect resources?
To investigate the distance traveled by fire ants to collect resources, we could follow the following plan:
Select a suitable study site: We need to select a study site where fire ants are present and are actively collecting resources. It should also be a site where we can easily track and observe the movement of the ants.Mark the location of the colony: Once we have identified a study site, we should locate the fire ant colony and mark its location.Place resources at varying distances: We should then place resources, such as food or sugar water, at varying distances from the colony, starting from the immediate vicinity of the colony and extending outwards in increasing increments.Observe and track ants: We should observe and track the ants as they leave the colony to collect resources. We can mark the ants with a non-toxic paint to identify and track their movement.Measure the distance traveled: We can use a measuring tape or a GPS device to accurately measure the distance traveled by the marked ants from the colony to the resource site.Record the data: We should record the distance traveled by each marked ant in a spreadsheet or database.Analyze the data: Once we have collected the data, we can use statistical analysis to determine the average distance traveled by fire ants to collect resources.To learn more about GPS device, visit: https://brainly.com/question/14996387
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A book sitting on a shelf have 740 J of potential energy, at a height of 1.8
m. What is the mass of the book?
13053.6 J
13053.6 m
41.950 kg
41.950 J
1 point
You have learned that the pressure from a fluid at a certain depth is given by the equation P = ρgh + Patm. You have also learned that the buoyant force is due to the difference in pressure between the top and bottom of an object. Derive the equation for the buoyant force from these two ideas. (Hint: In your derivation, use a simple submerged object, such as a perfect cube with sides of length s.) (3 points)
To derive the equation for the buoyant force, we can start with the equation for the pressure from a fluid at a certain depth:
P = ρgh + Patm
where P is the pressure at a depth h, ρ is the density of the fluid, g is the acceleration due to gravity, and Patm is the atmospheric pressure at the surface of the fluid.
Now, let's consider a simple submerged object, such as a perfect cube with sides of length s, as the hint suggests. The object is fully submerged in the fluid, so it experiences a pressure difference between the top and bottom surfaces. The pressure at the top surface of the object is Ptop = ρghtop + Patm, where htop is the depth of the top surface below the surface of the fluid. The pressure at the bottom surface of the object is Pbottom = ρghbottom + Patm, where hbottom is the depth of the bottom surface below the surface of the fluid. Since the object is at rest in the fluid, the net force acting on the object must be zero. Therefore, the buoyant force must be equal and opposite to the weight of the object:
Buoyant force = Weight of object
The weight of the object is given by its mass multiplied by the acceleration due to gravity:
Weight of object = mg
where m is the mass of the object and g is the acceleration due to gravity.
To find the buoyant force, we need to find the difference between the pressure at the top and bottom surfaces of the object, and then multiply that difference by the surface area of the object:
Buoyant force = Pressure difference × Surface area
The pressure difference is given by:
Pressure difference = Pbottom - Ptop
= (ρghbottom + Patm) - (ρghtop + Patm)
= ρg(hbottom - htop)
Therefore, the buoyant force is:
Buoyant force = ρg(hbottom - htop) × Surface area
For a perfect cube with sides of length s, the surface area is given by A = 6s^2. Therefore, the buoyant force on the cube is:
Buoyant force = ρg(hbottom - htop) × 6s^2
This is the equation for the buoyant force on a submerged object, derived from the equation for the pressure from a fluid at a certain depth and the concept of the buoyant force being due to the pressure difference between the top and bottom of an object.
A Camot engine works between the se and the sink with efficiency 40% How much perature of the sink be lowered keeping the source parature constant so that its efficiency increases by 10%?
Answer:
if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.
Explanation:
The efficiency of a Carnot engine is given by the equation:
η = 1 - T_sink / T_source
where η is the efficiency, T_sink is the temperature of the sink, and T_source is the temperature of the source.
In this case, we are given that the efficiency of the engine is 40%. Therefore, we can write:
0.4 = 1 - T_sink / T_source
Rearranging this equation, we get:
T_sink / T_source = 1 - 0.4
T_sink / T_source = 0.6
Next, we are asked to find the temperature of the sink needed to increase the efficiency of the engine by 10%. Let's call this new efficiency η_new. Since the efficiency of a Carnot engine is given by the same equation as before, we can write:
η_new = 1 - T_sink_new / T_source
where η_new is the new efficiency, and T_sink_new is the new temperature of the sink.
We know that the new efficiency is 10% higher than the original efficiency, so we can write:
η_new = η + 0.1η = 0.4 + 0.1(0.4) = 0.44
Substituting this into the equation above, we get:
0.44 = 1 - T_sink_new / T_source
Rearranging this equation, we get:
T_sink_new / T_source = 1 - 0.44
T_sink_new / T_source = 0.56
Now we can set up an equation to find the new temperature of the sink:
0.56 = T_sink_new / T_source
T_sink_new = 0.56T_source
To find the temperature difference between the old and new sink temperatures, we can subtract the two equations we have derived:
T_sink_new - T_sink = 0.6T_source - 0.56T_source
T_sink_new - T_sink = 0.04T_source
Finally, we can substitute the given efficiency of 40% to find the source temperature:
0.4 = 1 - T_sink / T_source
T_source = T_sink / (1 - 0.4)
T_source = T_sink / 0.6
Substituting this expression for T_source into the equation for the temperature difference, we get:
T_sink_new - T_sink = 0.04(T_sink / 0.6)
Simplifying, we get:
T_sink_new - T_sink = 0.067T_sink
Multiplying both sides by 100, we get:
(T_sink_new - T_sink) * 100 = 6.7T_sink
Therefore, if the temperature of the sink is lowered by 6.7%, the efficiency of the Carnot engine will increase by 10%.
Calculate the focal lengths while submerged in water (n = 1.33) for the two convex lenses used in this experiment assuming the radii and index of refraction as given in question #2 for each lens.
While submerged in water (n = 1.33) for two convex lenses, the focal lengths of Lens 1 is 19.67 cm and Lens 2 is 18.9 cm.
What is Lens ?Lens is a transparent device that is used to focus or redirect light, allowing it to be magnified, focused, or projected onto a surface. It is made of a curved, transparent material like glass, plastic, or crystal. Lenses are commonly used in eyeglasses, cameras, microscopes, and other optical devices. They can be used to magnify, reduce, or otherwise change the direction of light in order to produce a desired effect. They are also used in other applications such as laser cutting and welding, as well as medical imaging and laser treatments.
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A rocket at rest on the ground with initial mass 20,000 kg, 80% of which is fuel, burns 200kg/s as it flies
directly upwards. The exhaust gas exits the rocket at a relative speed of 1.80 km/s. Find (a) the thrust of
the rocket, (b) how long it takes to exhaust its fuel, and (c) the rocket’s speed at the end of its engine burn.
Assume g is constant and neglect air resistance.
Answer:
(a) The thrust of the rocket can be found using the formula:
Thrust = (mass flow rate) x (exhaust velocity)
The mass flow rate is the rate at which mass is expelled from the rocket, which is equal to the burn rate times the mass fraction of fuel:
mass flow rate = burn rate x (mass of rocket) x (mass fraction of fuel)
mass flow rate = 200 kg/s x 20,000 kg x 0.8
mass flow rate = 32,000 kg/s
The exhaust velocity is given as 1.80 km/s. Therefore, the thrust of the rocket is:
Thrust = 32,000 kg/s x 1.80 km/s
Thrust = 57,600 kN
(b) The time it takes to exhaust the fuel can be found using the formula:
time = (mass of fuel) / (burn rate)
The mass of fuel is 80% of the initial mass of the rocket:
mass of fuel = 0.8 x 20,000 kg
mass of fuel = 16,000 kg
Therefore, the time it takes to exhaust the fuel is:
time = 16,000 kg / 200 kg/s
time = 80 seconds
(c) The rocket's speed at the end of its engine burn can be found using the rocket equation:
Δv = (exhaust velocity) x ln[(initial mass) / (final mass)]
The final mass is the mass of the rocket after it has burned all of its fuel, which is:
final mass = (mass of rocket) - (mass of fuel)
final mass = 20,000 kg - 16,000 kg
final mass = 4,000 kg
The initial mass is 20,000 kg. Therefore, the change in velocity is:
Δv = 1.80 km/s x ln[(20,000 kg) / (4,000 kg)]
Δv = 1.80 km/s x ln(5)
Δv = 3.89 km/s
Since the rocket was initially at rest, its final speed is equal to the change in velocity:
final speed = 3.89 km/s
Therefore, the rocket's speed at the end of its engine burn is 3.89 km/s.
Some roads have signs that specify a maximum load for the vehicles that travel on them. Why might this be?
Answer: Applying a weight limit to a road is often done in an attempt to protect a roadway's appearance in particular. It also aims to protect the character and environment of rural areas, villages, and residential estates. Restricting overweight freights may just prevent damages like pot holes and cracks in the road.
Explanation:
I HOPE THIS HELPED GOOD LUCK AND I AM OPEN FOR FREE ANSWERS!
Hypnosis can be used to force people to do things against their will.
True
False
Answer: false
Explanation:
Use nodal analysis to find V1 and V2 in the circuit shown in Fig. 6.
Kirchhoff's current law is applied in nodal analysis. There will be 'n-1' simultaneous equations to solve when there are 'n' nodes in a given electrical circuit. 'n-1' must be solved in order to retrieve all of the node voltages.
Hence, we can solve for V1 and V2:
V1=Vi(R2+R3−k)k(1−nR3)−R2−R3.
V2=Vi(k−R2−R3(1+nR2))k(nR3−1)+R2+R3.
What is the significance of nodal analysis?Nodal analysis is a fundamental approach used to investigate voltage and current distribution in a circuit and is one of the simulations included in SPICE simulators. This method successfully integrates Kirchhoff's and Ohm's laws into a single matrix equation.
The distinction between mesh and nodal analysis is that nodal analysis uses Kirchhoff's current law to calculate the voltages at each node in an equation. Mesh analysis, on the other hand, is an application of Kirchhoff's voltage law, which is used to calculate current.
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Now write the magnitude of the normal force again, this time in terms of the gravitational force Fg, g, θ, the radius of the track r, and the velocity that the car is traveling v. Please use proper number of parentheses in your denominator (Expert TA)
The magnitude of the normal force of the car is given by Fn = Fg cotθ.
What is the normal force of the car?The normal force is the force exerted by the racetrack perpendicular to the car's motion. Let's now derive the expression for the magnitude of the normal force of the car:
The perpendicular component of the normal force is given by:
Fn⊥ = Fg cosθ
The parallel component of the normal force provides the centripetal force required for circular motion.
The centripetal force (Fc) is given by:
Fc = mv²/r
where;
m is the mass of the car, v is the velocity of the car, and r is the radius of the circular path.The centripetal force can also be expressed in terms of the parallel component of the normal force:
Fc = Fn∥ = Fn sinθ
Equating the two expressions for Fc, we get:
Fn sinθ = mv²/r
Solving for Fn, we get:
Fn = mv²/(r sinθ)
Substituting the expression for Fg cosθ, we get:
Fn = Fg cosθ / sinθ
or
Fn = Fg cotθ
where;
Fg is the gravitational force, g is the acceleration due to gravity, θ is the angle of banking of the track, and r and v are the radius and velocity of the car respectively.Learn more about normal force here: https://brainly.com/question/14486416
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The complete question is below:
Circular turns of radius r in a racetrack are often banked at an angle θ to allow the cars to achieve higher speeds around the turns. Assume friction is not present.
Now write the magnitude of the normal force of the car, in terms of the gravitational force Fg, g, θ, the radius of the track r, and the velocity that the car is traveling v.
B) Show that the equation for pressure p=F/ A' is dimensionally correct.
P = [M1 L1 T-2] × [L2]-1 = M1 L-1 T -2. Therefore, the pressure is dimensionally represented as M1 L-1 T -2.
The energy (E) of photon depends upon its wavelngth 'λ' , Planck's constant ' h ' and velocity
' c'. Derive the formula for energy using dimensional analysis.
Planck's frequency (h) and indeed the light's velocity (c) are used to connect a photon's energy (E) to its wavelength (), frequency (v), and wavelength. E = hν = hc/λ.
What is energy, exactly?We frequently use the word "energy" in our everyday speech. Energy has an unique physical meaning even if the term is frequently used figuratively. Energy is defined in physics as something's capacity to perform work. Many types of energy are possible. All energy is kinetic in some way.
The energy is lacking.Energy is present everywhere and comes in a variety of shapes and sizes. Objects at rest have potential energy that, if released, will cause them to move. All moving things contain kinetic energy.
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Write a 16 line poem that describes centripal force utilizing all key concepts and terms.
A typical 16-line poem that described centripetal force can be found below.
Centripetal forceIn circular motion, a force we call,
Centripetal, it keeps things in thrall.
Directed towards the center of the path,
Without it, objects would face a wrath.
Angular velocity is key,
The rate of change of the angle we see.
And the radius of the circle too,
Both play a role in what we must do.
The mass of the object cannot be ignored,
It factors in with gravity's cord.
As the force pulls towards the center,
Centripetal force is what we enter.
It is the sum of all the forces in play,
Equal to mass times velocity squared, we say.
And if the force is too weak or too strong,
Off the circular path, the object goes wrong.
Thus, centripetal force is what we need,
To keep objects moving at the speed,
In a circular path, they're meant to be,
A force that keeps them in harmony.
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(05.04 HC)
Larry finds a lens and shows it to his friends, Mirez and Sherly. All three look through it. Larry looks at the window across the room with the lens and says the window looks upside down. Mirez said that he must be using it incorrectly, because when he looks at his thumb through the lens, it is definitely not upside down. Sherly says that she thinks it is broken, because when she looks through it, everything just looks blurry.
Using your understanding about image formation, explain each of their observations.
The explanation of each of their observations can be found below.
Explanation of observationsLarry observed the window appearing upside down when viewed through the lens. This is because the lens creates an inverted image of the object being viewed. The light rays from the object are refracted by the lens and converge at a point behind the lens to form an inverted real image.Mirez observed that his thumb appeared normal when viewed through the lens. This is because the lens he used is a convex lens and it can create both real and virtual images, depending on the position of the object relative to the lens. For objects placed closer than the focal length of the lens, convex lenses produce virtual images that are upright, magnified, and on the same side of the lens as the object.Sherly observed that everything appeared blurry when viewed through the lens. This might be because the lens is either scratched or dirty, which can cause aberrations in the image formation. Also, the lens might not be properly focused or the object is placed too far or too close to the lens, causing the image to be out of focus.More on observations can be found here: https://brainly.com/question/28041973
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Which pair of cities is moving apart as a result of plate motion
The pair of cities moving apart because of plate motion is London and Boston.
Why are London and Boston moving apart ?London and Boston are moving apart due to the motion of tectonic plates. The Earth's lithosphere is divided into several large plates that are in constant motion due to the underlying mantle convection. The movement of these plates is driven by the forces generated by the mantle convection, which causes the plates to move away from each other, move towards each other, or move sideways past each other.
London and Boston are located on separate tectonic plates that are moving away from each other. London is located on the Eurasian Plate, while Boston is located on the North American Plate.
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Maria is taking an emotional intelligence as that involves looking at abstract image and describing it she describes a couple relaxing on the beach at sunset which personality test is Maria taken
Maria is taking the Rorschach inkblot test.
What personality test involves looking at abstract image and describing it ?The test is designed to assess an individual's personality traits and psychological functioning based on their responses to the images.
The Rorschach inkblot test, which uses a set of inkblot images and asks participants to describe what they see. The Rorschach test is a projective test that is often used to assess an individual's personality, emotional functioning, and thought processes.
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A train with cross-sectional area S, is moving with speed vt inside a long tunnel of cross- sectional area So (So = 4St). Assume that almost all the air (density p) in front of the train flows back between its sides and the walls of the tunnel. Also, the air flow with respect to the train is steady and laminar. Take the ambient pressure and that inside the train to be po. If the pressure in the region between the sides of the train and the tunnel walls is p, then Po-P=2 pu. The value of is 2N
Answer:
The force acting on the train due to the air resistance is given by the formula:
F = (1/2) * p * A * v^2 * Cd
where p is the density of air, A is the cross-sectional area of the train, v is the speed of the train, and Cd is the drag coefficient.
We can assume that the drag coefficient is constant for a given shape of the train, and we can take it to be 0.5 for a train moving through air.
The pressure difference between the front and back of the train is given by:
P = (1/2) * p * v^2
The pressure difference between the sides of the train and the tunnel walls is given by:
2 * P = 2 * (1/2) * p * v^2 = p * v^2
The force acting on the train due to this pressure difference is given by:
F' = 2 * P * S = 2 * p * v^2 * S
The net force acting on the train is given by:
Fnet = F - F' = (1/2) * p * A * v^2 * Cd - 2 * p * v^2 * S
We can simplify this expression by factoring out p * v^2:
Fnet = p * v^2 * [(1/2) * A * Cd - 2 * S]
We are given that So = 4St, so we can substitute A = St and S = St/4:
Fnet = p * v^2 * [(1/2) * St * Cd - 1/2 * St * Cd] = 0
Therefore, the net force acting on the train is zero. This means that the force due to air resistance is exactly balanced by the force due to the pressure difference between the sides of the train and the tunnel walls.
We are given that Po - P = 2 * Pu, so we can substitute P = (1/2) * Po - Pu:
F' = 2 * P * S = 2 * [(1/2) * Po - Pu] * S = (Po - Pu) * 4 * St
We can equate this expression for F' to the expression for air resistance force:
F' = p * v^2 * [(1/2) * St * Cd - 2 * St/4] = p * v^2 * [(1/2) * St * Cd - St/2]
Equating these two expressions, we get:
(Po - Pu) * 4 * St = p * v^2 * [(1/2) * St * Cd - St/2]
Simplifying and solving for Pu, we get:
Pu = Po - (p * v^2 * Cd) / 8
We are given that Cd = 2N, so we can substitute this value:
Pu = Po - (p * v^2 * 2N) / 8
Pu = Po - (p * v^2 * N) / 4
Therefore, the pressure inside the train is Po - (p * v^2 * N) / 4.
How does a pulley make work easier when it is used to lift an object? (1 point)
It increases the amount of work produced to lift the object.
It reduces the weight of the object being lifted.
It decreases the distance over which the force must be applied to lift the object.
It changes the direction of the lifting force to work with gravity.
Answer:
last choice
Explanation:
With a single fixed pulley, you pull down (working with the force of gravity) to lift the load up.
a 2.5 Mass ball thrown vertically upward with 10 m/s calculate a the potential energy after the 0.2second
Answer:
35J
Explanation:
The mass of the ball=2.5kg
The initial speed=10m/s
we have to calculate the height= h
s=ut+1/2at^2
h=10*0.2 -1/2*10*0.04
h=2-0.2
h= 1.8m
the potential energy= mgh
= 2.5kg*10*1.8
= 25*1.8
= 35J
Some help me with this pls
37. Segment B of the graph corresponds to the only solid state. ,38. Segment E of the graph corresponds to the melting point. and all answer given below:
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39. The melting point (temperature) is 300°C.
40. Segment F of the graph corresponds to the only liquid state.
41. Segment A of the graph corresponds to the only gas state.
42. Segment D of the graph corresponds to the boiling point.
43. No, the temperature decreases during freezing.
44. Segment C of the graph corresponds to the freezing point.
45. The boiling point (temperature) is 450°C.
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A power transistor is a solid-state electronic device. Assume that energy entering the device at the rate of 1.00 W by electrical transmission causes the internal energy of the device to increase. The surface area of the transistor is so small that it tends to overheat. To prevent overheating, the transistor is attached to a larger metal heat sink with fins. The temperature of the heat sink remains constant at 35.0°C under steady-state conditions. The transistor is electrically insulated from the heat sink by a rectangular sheet of mica measuring 8.25 mm by 6.25 mm, and 0.0852 mm thick. The thermal conductivity of mica is equal to 0.0753 W/m·°C. What is the operating temperature of the transistor?
Answer:
Explanation:
The rate of heat transfer from the transistor to the heat sink through the mica sheet can be calculated using Fourier’s Law of heat conduction. The formula for this law is Q = kA(T1 - T2)/d where Q is the rate of heat transfer, k is the thermal conductivity of the material, A is the cross-sectional area through which heat is transferred, T1 and T2 are the temperatures at either end of the material and d is its thickness.
In this case, we know that Q = 1.00 W (the rate at which energy enters the device), k = 0.0753 W/m·°C (the thermal conductivity of mica), A = 8.25 mm * 6.25 mm = 5.15625e-5 m² (the cross-sectional area of the mica sheet), T2 = 35°C (the temperature of the heat sink) and d = 0.0852 mm = 8.52e-5 m (the thickness of the mica sheet).
Substituting these values into Fourier’s Law gives us:
1.00 W = (0.0753 W/m·°C)(5.15625e-5 m²)(T1 - 35°C)/(8.52e-5 m)
Solving for T1 gives us:
T1 ≈ 35 + (1 / ((0.0753 * 5.15625e-5) / 8.52e-5)) ≈ 35 + 22 ≈ 57°C
So under steady-state conditions with an energy input rate of 1 W and a heat sink temperature of 35°C, we can expect that the operating temperature of this power transistor would be approximately 57°C.
A car tire is 64.0 cm in diameter. The car is traveling at a speed of 24.0 m/s.
a) What is the tire's rotation frequency, in rpm?
b) What is the speed of a point at the top edge of the tire?
c) What is the speed of a point at the bottom edge of the tire?
The tire rotates at a rate of 223.7 rpm, while the frequency layer of a tire is moving at a rate of 24.0 m/s plus 7.50 m/s, or 31.5 m/s. 24.0 m/s - 7.50 m/s = 16.5 m/s is the speed of a spot on the tire's bottom edge.
Why does frequency matter?Frequency refers to the quantity of waves passing a defined location in a predetermined period of time. As a result, the rate is 2 per second if a wave passes through in 1/2 of a second. In this case, the rate is 100 times per hour if it takes 1/10 of an hour.
Why not offer an example of frequency?The quantity of observations that take place during a specific predetermined timeframe is the frequency of such a class interval. So, the frequency for such 5–9 age range is 20 if, for instance, 20 individuals between the ages of 5 and 9 exist in the study's data.
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Tamara is playing a game of billiards. The white cue ball has a mass of 0.17 kg and all the other balls have a mass of 0.16 kg. The cue ball is moving at a velocity of 6 m/s when it collides with the number seven ball. If the cue ball comes to a complete stop after the collision, then what will the resulting velocity be on the number seven ball?
Answer: (0.17 * 6) + ( 0.16 * 0 ) = (0.17 * 0) + ( 0.16 * v2)
v2 = 6.375 m/s
Explanation:
The answer is v2 = 6.375 m/s
(I did the equation and everything but just in case, check with someone else so you don't get the wrong answer)
The displacement vectors
A
and
B
shown in the figure below both have magnitudes of 1.95 m. The direction of vector
A
is
= 29.0°.
A graph shows two displacement vectors A and B plotted on an x y plane. Vector A is a straight diagonal line that starts from the zero point and extends into the first quadrant at an angle with the horizontal. Vector B starts from the zero point and extends up along the y-axis.
(a) Find
A + B
graphically.
magnitude
m
direction
° counterclockwise from the +x axis
(b) Find
A − B
graphically.
magnitude
m
direction
° counterclockwise from the +x axis
(c) Find
B − A
graphically.
magnitude
m
direction
° counterclockwise from the +x axis
(d) Find
A − 2B
graphically.
magnitude
m
direction
° counterclockwise from the +x axis
The magnitude οf A + B is 1.95 m and its directiοn is 31.3° clοckwise frοm the pοsitive x-axis when the displacement vectοrs A and B is shοwn in the figure belοw bοth have magnitudes οf 1.95 m. The directiοn οf vectοr A is = 29.0°.
Hοw tο determine the magnitude and directiοn οf A + B?Tο determine the magnitude and directiοn οf A + B, we can measure the length οf the resulting vectοr and the angle it makes with the pοsitive x-axis, respectively.
Alternatively, we can use trigοnοmetry tο find the cοmpοnents οf vectοrs A and B and then add them up tο find the cοmpοnents οf A + B. Then, we can use inverse trigοnοmetric functiοns tο find the magnitude and directiοn οf the resulting vectοr.
Let's use the secοnd methοd tο sοlve this prοblem.
We are given that the magnitudes οf vectοrs A and B are 1.95 m each. The directiοn οf vectοr A is 29.0° cοunterclοckwise frοm the pοsitive x-axis. Let's call the angle between vectοr B and the pοsitive x-axis θ.
Using trigοnοmetry, we can find the x and y cοmpοnents οf vectοrs A and B as fοllοws:
Ax = 1.95 cοs 29.0° = 1.695 m
Ay = 1.95 sin 29.0° = 0.939 m
Bx = 1.95 cοs θ
By = 1.95 sin θ
Tο find θ, we need tο use the fact that the magnitude οf vectοr A + B is alsο 1.95 m. This means that:
[tex](Ax + Bx)^2 + (Ay + By)^2 = (1.95)^2[/tex]
Substituting the values of Ax and Ay, we get:
(1.695 + 1.95 cos θ)² + (0.939 + 1.95 sin θ)² = (1.95)²
Simplifying and solving for cos θ and sin θ, we get:
cos θ = -0.359
sin θ = -1.695
Since sin θ is negative, we know that vector B is pointing downwards.
Now, we can use inverse trigonometric functions to find the magnitude and direction of vector A + B:
[tex]|A + B| = sqrt((Ax + Bx)^2 + (Ay + By)^2) = 1.95 m[/tex]
θ = atan2(Ay + By, Ax + Bx) = atan2(-0.756, 1.336) = -31.3°
Therefore, the magnitude of A + B is 1.95 m and its direction is 31.3° clockwise from the positive x-axis.
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