Someone help please

Answer:

42 rats.

Step-by-step explanation:

since the ratio of mice to gerbils is 7:4, given that there are 32 gerbils, that means 32/4=8 gerbils; in other words, 56mice:32gerbils. Then, to find the # of rats, the ratio is 4:3, so you take the previous value of the # of mice and divide it by 4 to get 14(3)= 42

To understand this question, we need to know what it's asking and what's important and what is not important. Many people skip this step, but it is very important.

It is asking us to Find how many Rats there are.

This problem is defiantly reduced to the simplistic ratio

The next step is to Find clues

The clues are 32 Gerbils, 7:4 and 4:3

Now i like to make a chart but you may skip this step if you want

Gerbils=32

Mice=??

Rats=??

First, we have to find the numbers of Mice.

(Reducing Ratios divide them by a number like 2:4=1:2)

If you have 32 Gerbils and you reduced it to 4, what did you dived?

32/4=8

So, you multiply 7x8=56

There is 56 Mice.

Our table looks like this

Gerbils=32

Mice=56

Rats=??

Now we use the ratio 4:3 to find the numbers of Rats

If there are 56 mice, and it is reduced to 4, we have to do 56/4 to find out what we have to multiply 3 by to get the total numbers of rats (Inverse Operation) by. We get 14.

So now we do 3x14 in which we get 42.

Our chart now looks like this

Gerbils=32

Mice=56

Rats=42

I Hope this helped if you have any questions just tell me

Answer:

A AND B IS TRUE  C IS FALSE

Step-by-step explanation:

Answer:

The answer is 2

Step-by-step explanation:

The range of class A is 5-0 = 5

The range of class B is 3-0 = 3

the difference between 3 and 5 is 2.

Answer:

mx x 2 x1dadqd

Step-by-step explanation:

Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

[tex]\%Percentage = \frac{450}{500}[/tex]

Divide 450 by 500

[tex]\%Percentage = 0.9[/tex]

Express as percentage

[tex]\%Percentage = 90\%[/tex]

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

https://brainly.com/question/2776232

Answer:

It's C! y = 7

Step-by-step explanation:

Answer:

[tex]3(x-2)=2x+10\\3x-6=2x+10 | +6\\3x=2x+16 | -2x\\x = 16[/tex]

30.

a) [tex]180^{0} - 134^0-22^0=24^0[/tex]

[tex]r=24^0[/tex]

b)

[tex]90^0=2x^0+3x^0\\90^0=5x^0 |:5\\x^0=18^0[/tex]

[tex]2x^0= 2* 18^0=36^0[/tex]

[tex]3x^0=3*18^0=54^0[/tex]

Take care!

Answer:

there will be 180 gallons of water in the pool after 24 hours

Step-by-step explanation:

[tex]\frac{15}{2} *\frac{12}{12}= \frac{180}{24}[/tex]

Answer:

180 gallons

Step-by-step explanation:

Ok so,

2 hours = 15 gallons.

if we multiply both sides by 12 we can find out how many gallons of water will be in the pool in 24 hours

2 x 12 = 24

15 x 12 = 180

There will be 180 gallons of water in the pool after 24 hours.

Answer:

it looks like y int is about 2550

Step-by-step explanation:

Check the picture below.

Using the formulas to find its length =

P= 2 ( l + w )

d= w² + l²

There are 2 solutions for,

l = P / 4 + 1 / 4 √8d² - p²

= 39.2 / 4 + 1 / 4 × √8 × 14² - 39²

= 11. 2 km answer.

Using the formula to find its width =

w = p / 2 - l

= 39.2 / 2 - 11.2

= 8.4 km answer.

≈ the length of a rectangle is 11.2 km and the width is 8.4 km

Let's simplify step-by-step.

[tex]12a^2*b^4-36a^2*b+44abc=[/tex]

There are no like terms.

Answer:

[tex]12a^2*b^4-36a^2*b+44abc=[/tex]

Answer:

[tex]\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}[/tex]

Step-by-step explanation:

Step 1: Solve the system of equations

[tex]\begin{bmatrix}-x+y>2\\ x+2y>2\end{bmatrix}[/tex]

Isolate [tex]y[/tex] for [tex]-x+y>2[/tex]

[tex]\mathrm{Add\:}x\mathrm{\:to\:both\:sides}[/tex]

[tex]-x+y+x>2+x[/tex]

[tex]y>2+x[/tex]

Isolate [tex]y[/tex] for [tex]x+2y>2[/tex]

[tex]\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}[/tex]

[tex]2y>2-x[/tex]

[tex]\mathrm{Divide\:both\:sides\:by\:}2[/tex]

[tex]\frac{2y}{2}>\frac{2}{2}-\frac{x}{2}[/tex]

[tex]y>\frac{2-x}{2}[/tex]

[tex]\bold{=\begin{bmatrix}y>2+x\\ y>\frac{2-x}{2}\end{bmatrix}}[/tex]

Step 2: Graph

Instructions for graphing:

[tex]\mathrm{1.\:Graph\:each\:inequality\:separately.}[/tex]

[tex]\mathrm{2.\:Choose\:a\:test\:point\:to\:determine\:which\:side\:of\:the\:line\:needs\:to\:be\:shaded.}[/tex]

[tex]3. \mathrm{The\:solution\:to\:the\:system\:will\:be\:the\:area\:where\:the\:shadings\:}\\\mathrm{from\:each\:inequality\:overlap\:one\:another.}[/tex]

When done, it should look like this:

Answer:

B) [tex]-1+cos\theta[/tex]

Step-by-step explanation:

[tex](tan(\frac{\theta}{2}))(-sin\theta)[/tex]

[tex](\frac{1-cos\theta}{sin\theta})(-sin\theta)[/tex]

[tex](\frac{-sin\theta+sin\theta cos\theta}{sin\theta})[/tex]

[tex]-1+cos\theta[/tex]

Therefore, option B is correct

Helpful Tips:

Half-Angle Formula: [tex]tan(\frac{\theta}{2})= \frac{1-cos\theta}{sin\theta}=\frac{sin\theta}{1+cos\theta}=\pm\sqrt{\frac{1+cos\theta}{2}}[/tex]

Answer:

É 5x3=15

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

32 / 4  = 8

56 / 7 = 8

64 / 8 = 8

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0   or   1 - cos(θ) = 0

cos(θ) = 0   or   cos(θ) = 1

[θ = arccos(0) + 2nπ   or   θ = -arccos(0) + 2nπ]

…   or   [θ = arccos(1) + 2nπ   or   θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ   or   θ = -π/2 + 2nπ]   or   [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0   ⇒   θ = π/2

• second solution set with n = 1   ⇒   θ = 3π/2

• third solution set with n = 0   ⇒   θ = 0

So, the first choice is correct.

Answer:

130

ratio of woman to man is : 5/8

5/8×208=130

Answer:

130 women

Step-by-step explanation:

3 men to 5 women:

We can add the variable x:

3x + 5x = 208

8x = 208

x = 26

3 * 26 = 78 men,

5 * 26 = 130 women.

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

Answer:

1.25(-xsquare - 8x + 16)

Step-by-step explanation:

pls give me brainliest

I'm not sure but I think so

Answer:

i think that it would be 0

Answer:

C

Step-by-step explanation:

A function and its inverse are obtained by reflecting in the line y = x

Under a reflection in the line y = x

a point (x, y ) → (y, x )

In graph C

the red line has a point (0, 2 )

the blue line has a point (2, 0 )

Then graph C shows a function and its inverse

Answer:

This a vector addition problem and you need to know the law of cosines and law of sines to solve this problem.

Two vector forces of 80lbs and 70 lbs act on an object at 40 degree angle between them.

The magnitude of the resultant force can be found by applying the law of cosines:

c2 = a2 + b2 - 2abcos140°

where a = 80, b = 70 and c is the resultant force vector you are asked to find

Once you find the magnitude of the resultant force, then you can find the angle it makes wrt the 70lb force using the law of sines:

sinα/a = sin140°/c

where α is the angle opposite side a, or the angle between the resultant and the 70lb vector that you are asked to find. so it would be 140lbs

Step-by-step explanation

Answer:

  a.  39 ft²

  c. 2x² +11x +12

  e. 35 yd²

Step-by-step explanation:

The missing vertical dimension is 5-3 = 2'. The missing horizontal dimension is 11-8 = 3'. Then the figure can be decomposed into a rectangle 11'×3' and one that is 3'×2'. The sum of those areas is ...

  total area = (11 ft)(3 ft) +(3 ft)(2 f) = (3 ft)(11 +2 ft) = (3 ft)(13 ft) = 39 ft²

__

We don't know what to make of the rectangles in each corner, so we'll assume they are distorted right-angle indicators. The area is the product of the dimensions shown:

  A = LW

  A = (2x +3)(x +4) = 2x² +11x +12 . . . area of figure

__

The shaded area is half the area of the rectangle. That is the same area you get if you use the triangle formula for the area of the shaded triangle.

  A = 1/2(14 yd)(5 yd) = 35 yd²

The stocks are worth $ 1396.29 nine months later.

Using the continuous compounding formula,

[tex]A = Pe^{rt}[/tex] where

Substituting the values of the variables into the equation, we have

[tex]A = Pe^{rt}[/tex]

[tex]A = 1200e^{0.202 X 0.75}\\A = 1200e^{0.1515}\\A = 1200(1.1636)\\A = 1396.29[/tex]

So, the stocks are worth $ 1396.29 nine months later.

Learn more about continuous compounding here:

https://brainly.com/question/24722580

Answer:

Today, Carmen out surfing for 8 hours

Step-by-step explanation:

160/100 × 5 = 8

Answer:

A.  52 green beads; 39 yellow beads

Step-by-step explanation:

See the attachment.  If we take the ratios of 4, 2 , and 3, they add to 9.  The

Green (G), Blue (B), and Yellow (Y) will have 4/9, 2/9 and 3/9 each of the total beads, 117.

G:  52 Beads

B:  26 Beads

Y:  39  Beads

Answer:

The price of 1 adult ticket is 12 dollars, and the price of a ticket for one student is 7 dollars

Step-by-step explanation:

Make a system of equations for the two days that the play was shown.

Let x = the price of an adult ticket

Let y = the price of a student ticket

For the first day:

For the second day:

Now, we can solve using the elimination method. Multiply the first equation by 2 and the second equation by 9. Then swap the order of the equations.

Answer: And I don’t know math

Step-by-step explanation:

Answer:

[tex]Fourth \: option: y^2=9^2+19^2-2(9)(19) cos(41°)[/tex]

[tex]The \: law \: of \: cosines \: to \: solve \: for \: one \: side  \: is:[/tex]

[tex]c^2=a^2+b^2-2ab \: cos \: C[/tex]

We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:

[tex]y^2=9^2+19^2-2(9)(19) \: cos \: (41°)[/tex]