the solution to the given differential equation is: Q(t) = -t^4/25 + t^4/5 ln(t) + C/t
To solve the given differential equation t dQ/dt + Q = t^4 ln(t), we'll first find the integrating factor, solve for Q(t), and then substitute the given terms.
Step 1: Find the integrating factor.
The integrating factor is e^(∫P(t)dt), where P(t) = 1/t in this case. So,
∫(1/t)dt = ln(t)
The integrating factor is e^(ln(t)) = t.
Step 2: Multiply the equation by the integrating factor.
t (t dQ/dt) + t(Q) = t^2 dQ/dt + tQ = t^5 ln(t)
Step 3: Integrate both sides of the equation.
∫(t^2 dQ/dt + tQ)dt = ∫(t^5 ln(t))dt
Using integration by parts on the right side (u = ln(t), dv = t^5 dt):
∫(t^5 ln(t))dt = (t^5 ln(t) / 5) - ∫(t^4 dt) = (t^5 ln(t) / 5) - (t^5 / 25) + C
Step 4: Solve for Q(t).
Since ∫(t^2 dQ/dt + tQ)dt = tQ, we have:
tQ = (t^5 ln(t) / 5) - (t^5 / 25) + C
Q(t) = -t^4/25 + t^4/5 ln(t) + C/t
So, the solution to the given differential equation is:
Q(t) = -t^4/25 + t^4/5 ln(t) + C/t
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An amount is increased by 20% 40% of the new amount is 288 Work out the original amount.
Sophia, Malcolm, and Oren are playing a money game. Their bank
balances are shown in the table. Complete the table by writing the
absolute value of each bank balance to show how much each
player owes. Who owes the greatest amount?
Bank Balance Amount Owed
-$150
- $325
- $275
Answer:
Please mark me the brainliest
Bank Balance | Amount Owed
---------------------|-------------
-$150 | $150
-$325 | $325
-$275 | $275
To find the amount owed, we simply take the absolute value of each bank balance. The player who owes the greatest amount is the one with the largest absolute value bank balance. In this case, that would be Malcolm, who owes $325.
Step-by-step explanation:
help! look at the picture pls math.
Check the picture below.
so if we just get the volume of the whole box, and the volume of the balls, if we subtract the volume of the balls from that of the whole box, what's leftover is the part we didn't subtract, namely the empty space.
[tex]\stackrel{ \textit{\LARGE volumes} }{\stackrel{ whole~box }{(3.5)(3.5)(12.1)}~~ - ~~\stackrel{\textit{three balls} }{3\cdot \cfrac{4\pi (1.65)^3}{3}}} \\\\\\ 148.225~~ - ~~17.9685\pi ~~ \approx ~~ \text{\LARGE 91.8}~cm^3[/tex]
suppose you are interested in using regression analysis to estimate an nba player's salary using the following independent variables: the player was traded in the last 5 years, player's age, player's height, career free throw percentage, average points per game, and the team had greater than 45 wins in the previous season. which of the following independent variables are indicator (dummy) variables? select all that apply.
Based on the information provided, only one of the independent variables can be an indicator (dummy) variable, which is:
- The player was traded in the last 5 years
Based on the information provided, only one of the independent variables can be an indicator (dummy) variable, which is:
- The player was traded in the last 5 years
This variable can take on a value of 0 or 1, where 0 represents that the player was not traded in the last 5 years, and 1 represents that the player was traded in the last 5 years. The other independent variables are continuous variables (e.g., player's age, player's height, career free throw percentage, average points per game) or categorical variables that do not need to be represented as dummy variables (e.g., the team had greater than 45 wins in the previous season).
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x-3y= -9 slope intercept form
Answer:
[tex]\textsf{y=\frac{1}{3}x+3}[/tex][tex]y = \frac{1}{3} x+3[/tex]
Step-by-step explanation
[tex]\textsf{*slope intercept form: y = mx +b}[/tex]
---------------------------------------------
[tex]\textsf{x - 3y = -9}[/tex]
Subtract x from both sides:
[tex]\textsf{-3y = -x - 9}[/tex]
Divide both sides by -3:
-3y/-3 = -x/-3 - 9/-3
[tex]\textsf{y = 1/3x +3}[/tex]
[tex]-jurii[/tex]
Researchers studying osteoporosis (bone loss) suspected that women over the age of 50 in the United
States are diagnosed with the disease more often than women over 50 in Mexico. They took a random
sample of 200 women over the age of 50 from each country. Here are the results:
Diagnosed with osteoporosis? US. Mexico
Yes. 40. 20
No 160 180
Total 200. 200
The researchers want to use these results to test He: pus - PM = 0 versus H₂: Pus-PM > 0.
Assume that all conditions have been met.
What is the P-value associated with these sample results?
a. P-value is greater than or equal to
0.20
b. 0.05 is less than or equal to the P-
value < 0.10
c. 0.10 is less than or equal to the P-
value < 0.20
d. P-value < 0.01
e. 0.01 is less than or equal to the P-
value < 0.05
Answer:
A P-value < 0.01
Step-by-step explanation:
and include it in the show your work file attached to question Given the homogeneous system of linear equations, work items a, b, cand type the final answers in the answer box, Write legibly to show all the steps to the final answers x-2y+32-0 -3x+6y-92=0 a (7.5 pts.) Find a basis for its solution space (nullspace of the coefficient matrix) b- (5 pts) What is the dimension of the solution space? (nullity of the coefficient matrix) c-(7.5 pts.) Find a basis for row space of the coefficient matrix
a) A basis for the solution space is the vector (3/4, 1, -1/4).
b) The dimension of the solution space is 1.
c) Basis for the row space is the vector (1, -2, 3, 2).
a) To find a basis for the solution space (nullspace) of the coefficient matrix, we can solve for the variables in terms of the free variable.
Starting with the augmented matrix [A|0]:
| 1 -2 3 2 |
| -3 6 -9 2 |
We can perform row operations to simplify the matrix:
R2 = R2 + 3R1
| 1 -2 3 2 |
| 0 0 0 8 |
Now, we can solve for the variables in terms of the free variable:
x - 2y + 3z = -2z
z = -1/4t
y = t
x = 3/4t
So the solution space can be written as:
t * (3/4, 1, -1/4)
Thus, a basis for the solution space is the vector (3/4, 1, -1/4).
b) The dimension of the solution space (nullity) is the number of free variables, which in this case is 1.
So the dimension of the solution space is 1.
c) To find a basis for the row space of the coefficient matrix, we can row reduce the matrix and take the non-zero rows as a basis.
Starting with the augmented matrix [A|0]:
| 1 -2 3 2 |
| -3 6 -9 2 |
We can perform row operations to simplify the matrix:
R2 = R2 + 3R1
| 1 -2 3 2 |
| 0 0 0 8 |
The row space is spanned by the non-zero rows of the row reduced matrix:
(1, -2, 3, 2)
So a basis for the row space is the vector (1, -2, 3, 2).
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Please help, Find Sin, Where zero the angle shown, give an exact value, not a decimal approximation.
The value of θ from the given right triangle is 50 degree.
The legs of given right angle triangle are 6 units and 5 units.
Here, opposite side = 6 units and adjacent side = 5 units
We know that, tanθ= Opposite/Adjacent
tanθ= 6/5
tanθ= 1.2
θ=50.19
θ≈50°
Therefore, the value of θ from the given right triangle is 50 degree.
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- (d) When a=0.02 and n=24, X2-left =____
X2-right =_____
When a=0.02 and n=24, [tex]X_{left}^{2}[/tex] = 9.260 and [tex]X_{right}^{2}[/tex]= 41.638. In order to calculate [tex]X_{left}^{2}[/tex] and [tex]X_{right}^{2}[/tex] when a=0.02 and n=24, we need to use the chi-squared distribution table. This table provides us with the critical values for a given level of significance (alpha) and degrees of freedom (df).
To answer your question, when a=0.02 and n=24, we will find the [tex]X_{left}^{2}[/tex] and [tex]X_{right}^{2}[/tex] values using the Chi-square distribution table.
Step 1: Determine the degrees of freedom. In this case, the degrees of freedom (df) are equal to n-1, so df = 24 - 1 = 23.
Step 2: Determine the significance level (alpha) and divide it by 2. Since a = 0.02, the significance level is [tex]\frac{\alpha}{2} =0.01[/tex] for each tail (left and right) of the distribution.
Step 3: Use the Chi-square distribution table to find the critical values. Look for the values corresponding to the degrees of freedom (23) and significance level (0.01) in each tail.
According to the Chi-square distribution table:
[tex]X_{left}^{2}[/tex]= 9.260
[tex]X_{right}^{2}[/tex]= 41.638
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The variable b varies directly as the square root of c. If b = 100 when c = 4, which equation can be used to find other combinations of b and c?
a: b = 200c
b: b = 50√c
c: b = 25c
d: b√c = 50
Therefore, the proportionality equation and variable varies that can be used to find other combinations of b and c is: b = 50√c and Option (b) is correct: b = 50√c
We frequently use the phrase "a is proportional to b" when a directly fluctuates as b. When such is the case, a and b have the following algebraic relationship: a = kb. The proportionality constant is referred to as k. A relationship between a set of values for one variable and a set of values for other variables is known as a variation. direct change.
The function y = mx (commonly written y = kx), which is referred to as a direct variation, may be obtained from the equation y = mx + b if m is a nonzero constant and b = 0. Here b varies directly as the square root of c, we can write the equation as:
b = k√c
Here k is the constant of proportionality. To find the value of k, we can use the given values:
b = 100 when c = 4
100 = k√4
100 = 2k
k = 50
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Find the surface area of the regular hexagonal prism to the nearest tenth.
The Surface Area of the regular hexagonal prism is 92.784 square unit.
We have,
a = 2 unit
h= 6 unit
So, surface area of Prism
= 6 ah + 3√3 a²
= 6(2)(6) + 3√3 (2)²
= 72 + 12√3
= 92.784 square unit.
Thus, the Surface Area is 92.784 square unit.
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Which data table indicates a positive linear association between the hours worked and the daily wages of waiters in a restaurant?
Answer:
Step-by-step explanation:
To determine if there is a positive linear association between the hours worked and the daily wages of waiters in a restaurant, you can create a scatter plot of the data and look for a pattern.
Once you have the data, you can use a statistical software or a spreadsheet program to create a scatter plot. You can then visually inspect the scatter plot to see if there is a clear pattern of a positive linear association between the two variables.
If there is a positive linear association, the data points on the scatter plot will form a roughly straight line that slopes upwards from left to right. The closer the data points are to the line, the stronger the association.
So, the data table that indicates a positive linear association between the hours worked and the daily wages of waiters in a restaurant is the one where the scatter plot shows a clear upward trend.
4. Use slope and/or the distance formula to
determine the most precise name for the
figure: A(-5, -6), B(2, 0), C(11, 9), D(4, 3).
[A] parallelogram
[B] kite
[C] rhombus
[D] trapezoid
5. Use slope and/or the distance formula to
determine the most precise name for the
figure: A(-9,-4), B(-7, 1), C(1, 5), D(-1,0).
[B] rhombus
[D] quadrilateral
[A] parallelogram
[C] rectangle
Result:
1. Based on the properties, the most precise name for figure is A. parallelogram
2. From the properties, the most precise name for the figure is B. rhombus.
How to determine the precise name of the figure?We can determine the precise name of the figure calculating the slopes of AB, BC, CD, and DA using the slope formula and/or the distance formula:
1. Using the slope formula:
AB = (0 - (-6))/(2 - (-5)) = 2
BC = (9 - 0)/(11 - 2) = 9/9 = 1
CD = (3 - 9)/(4 - 11) = -6/-7 = 6/7
DA = (-6 - (-5))/( -5 -(-5)) = 0
Calculate the lengths of the sides using distance formula:
AB = [tex]\sqrt((2 - (-5))^2 + (0 - (-6))^2)[/tex] = [tex]\sqrt(7^2 + 6^2)[/tex] = [tex]\sqrt{85}[/tex]
f BC = [tex]\sqrt((11 - 2)^2 + (9 - 0)^2)[/tex] = [tex]\sqrt(9^2 + 9^2)[/tex] = 9√2)
CD = [tex]\sqrt((4 - 11)^2 + (3 - 9)^2)[/tex] = sqrt[tex]\sqrt(7^2 + 6^2)[/tex] = √85
DA = [tex]\sqrt((-5 - 4)^2 + (-6 - (-9))^2)[/tex] = [tex]\sqrt(9^2 + 3^2)[/tex] = 3√10
The slopes of AB and CD are equal (2 and 6/7, respectively), and the slopes of BC and DA are equal (1 and 0, respectively).
Therefore, opposite sides are parallel that is a parallelogram.
2. First, we can calculate the slopes of AB, BC, CD, and DA using the slope formula:
AB = (1 - (-4))/(-7 - (-9)) = 5/2
BC = (5 - 1)/(1 - (-7)) = 4/4 = 1
CD = (0 - 5)/(-1 - 1) = -5/-2 = 5/2
DA = (-4 - 0)/(-9 - (-1)) = 4/8 = 1/2
Next, using the distance formula, we calculate the lengths of the sides:
AB = [tex]\sqrt((-7 - (-9))^2 + (1 - (-4))^2)[/tex] = [tex]\sqrt(2^2 + 5^2)[/tex] = [tex]\sqrt29[/tex]
BC = [tex]\sqrt{(1 - (-7))^2 + (5 - 1)^2}[/tex] = [tex]\sqrt(8^2 + 4^2)[/tex] = 4[tex]\sqrt17[/tex]
CD = [tex]\sqrt((-1 - 1)^2 + (0 - 5)^2)[/tex] = [tex]\sqrt(2^2 + 5^2)[/tex] = [tex]\sqrt29[/tex]
DA = [tex]\sqrt((-9 - (-1))^2 + (-4 - 0)^2)[/tex] = [tex]\sqrt(8^2 + 4^2)[/tex] = [tex]\sqrt80[/tex])
The slopes of AB and CD are equal (5/2 and 5/2, respectively), and the slopes of BC and DA are equal (1 and 1/2, respectively). meaning the opposite sides are parallel.
AB and CD have the same length ([tex]\sqrt(29)[/tex]), and BC and DA have the same (4[tex]\sqrt(17}[/tex]), which means it's a rhombus.
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You have a combination lock that has the numbers 1-40 on the dial. You
forgot the combination, but you remember that the combination is three
numbers, the last digit of all three numbers is 6, and none of the numbers
are between 1 and 10. You make a random guess with what you know.
What is the probability that you will get the combination?
Answer:
1/870 ≈ 0.0011494 or about 0.115% (rounded to 6 decimal places)
Step-by-step explanation:
The first digit can be any of the numbers between 10 and 40, except for those that end in 6 (since the last digit of all three numbers is 6). This leaves us with 30 numbers to choose from for the first digit. Similarly, the second digit can be any of the numbers between 10 and 40, except for those that end in 6 and the one chosen for the first digit. This leaves us with 29 numbers to choose from for the second digit.
For the third digit, we have only one option since we know it ends in 6.
So the total number of possible combinations is:
30 * 29 * 1 = 870
Out of these, only one combination is the correct one. Therefore, the probability of guessing the combination correctly on the first try is:
1/870 ≈ 0.0011494 or about 0.115% (rounded to 6 decimal places)
Now suppose a new highway reduces shipping costs from Plant 3 to the North region by 25%. How will this change affect the appliance company?
a. This change in shipping costs will not affect the shipping plan, but will reduce the company's shipping costs.
b. This change in shipping costs may or may not affect the company. We need additional information to determine the exact effect.
c. Due to this cost reduction, the company's shipping plan will change and they will use the shipping route from Plant 3 to the North region.
d. This change in shipping costs will not affect the company since they are not using this shipping route.
This change in shipping costs may or may not affect the company.
We need additional information to determine the exact effect.
Option B is the correct answer.
We have,
While the reduction in shipping costs from Plant 3 to the North region is significant, we need more information about the company's current shipping plan, routes, and costs associated with other plants to determine if this change will impact their overall shipping strategy.
Thus,
This change in shipping costs may or may not affect the company.
We need additional information to determine the exact effect.
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Calculate the surface area.
25 square inches
120 square inches
126 square inches
132 square inches
The surface area of the figure is 132 square units.
Option D is the correct answer.
We have,
The figure has two types of shapes.
- 3 rectangles
- 2 triangles
Now,
Area of the 3 rectangles.
= 5 x 10 + 4 x 10 + 3 x 10
= 50 + 40 + 30
= 120 square units
Area of 2 triangles.
= 1/2 x 4 x 3 + 1/2 x 4 x 3
= 1/2 x 12 + 1/2 x 12
= 6 + 6
= 12 square units
Now,
Total surface area.
= 120 + 12
= 132 square units.
Thus,
The surface area of the figure is 132 square units.
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What is the coefficient of x^3 term in the power series expansion (or Taylor's expansion) of f(x) = e^(x) sin(x)
The coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x) is 1/15.
To find the coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x), we need to write the Taylor series for [tex]e^x[/tex] and sin(x) and then multiply them to get the Taylor series for f(x). The Taylor series for e^x is:
[tex]e^x[/tex] = 1 + x + (x²/2!) + (x³/3!) + ...
The Taylor series for sin(x) is:
sin(x) = x - (x³/3!) + (x⁵/5!) - ...
Multiplying these two series, we get:
f(x) = [tex]e^x[/tex] sin(x) = (1 + x + (x²/2!) + (x³/3!) + ...) × (x - (x³/3!) + (x⁵/5!) - ...)
Expanding this out and collecting the terms with x³, we get:
f(x) = x - (x³/3!) + (7x³/5!) + ...
Therefore, the coefficient of x³ term in the power series expansion of f(x) = [tex]e^x[/tex] sin(x) is -1/6 + 7/120 = 1/15.
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what is the value of the expression
2/-3 x -1/5
Key Question #20 1. For f(x)= x, determine the average rate of change of f(x) with respect to x over each interval. a. 1
The average rate of change of f(x) = x with respect to x over the interval a = 1 is 1.
To determine the average rate of change of f(x) = x with respect to x over the interval a, we'll use the formula:
Average Rate of Change = (f(b) - f(a)) / (b - a)
In this case, the interval a is 1, so let's choose an interval b. We can use any value for b, but let's choose b = 2 for simplicity.
Step 1: Find f(a) and f(b)
f(x) = x, so:
f(1) = 1
f(2) = 2
Step 2: Plug the values into the formula
Average Rate of Change = (f(2) - f(1)) / (2 - 1)
Average Rate of Change = (2 - 1) / (2 - 1)
Step 3: Calculate the result
Average Rate of Change = (1) / (1)
The average rate of change of f(x) = x with respect to x over the interval a = 1 is 1.
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Please help me with this my quiz. Thank you :)
Due tomorrow
Answer:
dark blue
Step-by-step explanation:
Show work and please explain how to solve it!
The density of the ball in the air is given as follows:
d = 4 x 10^5 ounces/ft³.
How to calculate the density?The density is calculated as the division of the mass by the volume of an object, as follows:
d = m/v.
The ball in this problem is spherical with a diameter of 0.05 feet = radius of 0.025 feet, hence the volume is given as follows:
V = 4 x 3.1416 x 0.025³/3
V = 6.545 x 10^-5 ft³.
The ball in the air is inflated, hence the mass is given as follows:
m = 22.93 ounces.
Thus the density of the ball is given as follows:
d = 22.93/(6.545 x 10^-5)
d = 4 x 10^5 ounces/ft³.
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Question 1 Solve the following differential equations leaving your answer in the form x a. dx/dy = 5x/y ii) = dx/dy= x^4
For the first differential equation, dx/dy = 5x/y, we can separate the variables and integrate:
dy/dx = y/5x
(1/y)dy = (1/5x)dx
Integrating both sides, we get:
ln|y| = (1/5)ln|x| + C
where C is the constant of integration.
To solve for y, we can exponentiate both sides:
|y| = e^(ln|x|/5 + C)
|y| = Ce^(ln|x|/5)
where C is a constant of integration.
Since we don't know whether x and y are positive or negative, we can write the general solution as:
y = ± Cx^(1/5)
For the second differential equation, dx/dy = x^4, we can again separate the variables and integrate:
dy/dx = 1/x^4
x^4dy = dx
Integrating both sides, we get:
(1/3)x^3y = x + C
where C is the constant of integration.
To solve for y, we can multiply both sides by (3/x^3):
y = (3/x^3)(x + C)
y = 3/x^2 + 3Cx^(-3)
So the general solution to the differential equation dx/dy = x^4 is:
y = 3/x^2 + 3Cx^(-3), where C is a constant of integration.
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Which set of angle measures would determine a triangle?
OA 75°, 15°, 10°
OB. 150°, 20°, 50°
O c. 50°,50°, 100°
OD. 75°,5°, 100°
OE. 70°, 60°, 40°
Answer:
OD
Step-by-step explanation:
Angles in a triangle add to 180 degrees. The only set of angles which total to 180 is the values in OD
Estimate the perimeter and the area of the shaded figure.
The perimeter and area of the given polygon are:
Perimeter = 22.325 units
Area = 25 square units
How to find the area and perimeter?Using Pythagoras theorem, we can find the length of the sides of the polygon as:
a = √(1² + 3²)
a = √10
b = √(3² + 3²)
b = 2√9
c = √(3² + 3²)
c = 2√9
d = √(1² + 3²)
d = √10
e = 4
Thus:
Perimeter = 2√10 + 4√9 + 4
Perimeter = 22.325 units
Area = 2(¹/₂ * 1 * 3) + 2(¹/₂ * 3 * 3) + (4 * 3)
= 25 square units
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Express in the form of a rational number: 0.1212….
Answer:
[tex]0.1212...=\dfrac{4}{33}[/tex]
Step-by-step explanation:
A repeating decimal is a decimal number with a digit (or group of digits) that repeats forever.
There are three ways to show a repeating decimal:
Several duplicates of the repeating digit or block of digits, followed by an ellipsis, e.g. 0.3333... or 0.123123...A dot or a line above a repeated digit, e.g. [tex]\sf 0.\.{3}[/tex] or [tex]\sf 0.\overline{3}[/tex]A line above a repeating block of multiple digits, e.g. [tex]\sf 0.\overline{123}[/tex]0.1212... is a repeating decimal as there are two duplicates of the repeating block of digits "12" followed by an ellipsis.
To express a repeating decimal as a rational number, begin by assigning the decimal to a variable:
[tex]x=0.1212...=0.\overline{12}[/tex]
Multiply both sides by 100:
[tex]\implies x \cdot 100=0.\overline{12}\cdot 100[/tex]
[tex]\implies 100x=12.\overline{12}[/tex]
Subtract the first equation from the second to eliminate the part after the decimal:
[tex]\begin{array}{crcr}& 100x & = & 12.\overline{12}\\- & x & = & 0.\overline{12}\\\cline{2-4} & 99x & = & 12\phantom{.12}\\\end{array}[/tex]
Divide both sides of the equation by 99:
[tex]\implies \dfrac{99x}{99}=\dfrac{12}{99}[/tex]
[tex]\implies x=\dfrac{12}{99}[/tex]
Reduce the fraction to is simplest form by dividing the numerator and denominator by 3:
[tex]\implies x=\dfrac{12 \div 3}{99 \div 3}=\dfrac{4}{33}[/tex]
[tex]\textsf{Therefore, $0.1212...$ expressed in the form of a rational number is\;$\dfrac{4}{33}$}.[/tex]
On reversing the digits of a two digit number, the number obtained is 9 less than three times the original number. If the difference of these two numbers is 45, find the original number. A 35
B 27
C 28
D 30
There is no solution to this problem. None of the answer choices (A, B, C, D) are correct.
Let's start by representing the original two-digit number as 10x + y, where x represents the tens digit and y represents the ones digit.
When we reverse the digits, we get the number 10y + x. According to the problem, this number is 9 less than three times the original number:
10y + x = 3(10x + y) - 9
Simplifying this equation, we get:
10y + x = 30x + 3y - 9
7y - 29x = -9
We also know that the difference between these two numbers is 45:
(10x + y) - (10y + x) = 45
9x - 9y = 45
x - y = 5
Now we have two equations with two variables, which we can solve using substitution or elimination. I'll use elimination:
7y - 29x = -9
-7y + 7x = 35 (multiplying the second equation by -7)
Adding these two equations, we get:
-22x = 26
x = -13/11
This doesn't make sense, since x should be a digit between 1 and 9.
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prove if sum of second moments is finite then series converges almost surely math.stackexchange
The second Borel-Cantelli lemma, we have P(lim sup Sn < ∞) = 0, which implies that Sn converges almost surely.
Let {Xn} be a sequence of random variables, and let Sn = X1 + X2 + ... + Xn be the corresponding sequence of partial sums. We want to show that if E(Xn²) is finite for all n, then Sn converges almost surely.
Let Yn = Xn^2. Then E(Yn) = E(Xn²) < ∞ for all n, since we are given that the second moments are finite. By the second Borel-Cantelli lemma, it suffices to show that the series ∑ P(Yn > ε) converges for every ε > 0.
Since Yn = Xn² ≥ 0, we have P(Yn > ε) ≤ P(|Xn| > √ε). Using Markov's inequality, we have:
P(|Xn| > √ε) ≤ E(|Xn|²)/ε = E(Yn)/ε.
Therefore, we have:
∑ P(Yn > ε) ≤ ∑ E(Yn)/ε = (1/ε) ∑ E(Yn) = (1/ε) ∑ E(Xn²) < ∞.
The last inequality follows from the fact that the second moments are assumed to be finite.
Thus, by the second Borel-Cantelli lemma, we have P(lim sup Sn < ∞) = 0, which implies that Sn converges almost surely.
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frankie has a new cell phone plan. he will pay a one-time activation fee of 30$, and 45$ each month. which equation can be used to determine the total amount, t, Frankie will have spent after m months on his cell phone plan
The equation which can be used to determine the total amount, t, Frankie will have spent after m months on his cell phone plan is t = 30 + 45m.
Given that,
Frankie has a new cell phone plan.
He will pay a one-time activation fee of 30$, and 45$ each month.
One time activation fee = $30
Amount each month = $45
Amount for m months = 45m
Total amount for the plan = 30 + 45m
If t represents the total amount for the cell phone activation plan, the required equation can be written as,
t = 30 + 45m
Hence the required equation for the cell phone plan is t = 30 + 45m.
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Which of the following is NOT an assumption of the Binomial distribution?a. All trials must be identical.b. All trials must be independent.c. Each trial must be classified as a success or a failure.d. The probability of success is equal to 0.5 in all trials.
Option e. "The number of trials is not fixed" would be the correct answer.
The assumption of the Binomial distribution that is NOT included in the options provided is that the number of trials must be fixed in advance. This means that the Binomial distribution applies only to situations where there is a fixed number of independent trials, each with the same probability of success, and the interest is in the number of successes that occur in these trials. Therefore, option e. "The number of trials is not fixed" would be the correct answer.
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Annabel is comparing the distances that two electric cars can travelafter the battery is fully charged
After the battery is fully charged, Car B can go further than Car A. Car B, as compared to Car A, had lower variability measurements. After the battery is completely charged, Car B can go further than Car A since Car A has a lower mean and median. Option D is Correct.
The median splits the data in half. A lower median indicates that Car A has less mileage than Car B.
Two measurements exist.
The measure of centre reveals how closely or widely the data are dispersed around the centre.
The measurements of centre are mean, median, and mode.
Car A travelled less since it had a lower mean and median.
We can find out how data changes with a single value using the measure of variability. The data is denser at the mean when the MAD is less. The MAD in Car B is lower. Data that is closer to the centre of the data set has a smaller IQR.
IQR is lower in Car B.
Consequently, automobile B travelled steadily since its IQR and MAD were lower. Option D is Correct.
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Correct Question:
Annabel is comparing the distances that two electric cars can travel after the battery is fully charged. Car A (miles) Car B (miles) Mean 145 200 Median 142 196 IQR 8 4 MAD 6 2 Part A Use the measures of center to make an inference about the data. Use the drop-down menus to complete your answer. Car A can travel further than Car B after the battery is fully charged. Part B Based on the data, which car performs most consistently? Explain. A. Car A because the measures of center are smaller for Car A than for Car B. B. Car B because the measures of center are smaller for Car B than for Car A. C. Car A because the measures of variability are smaller for Car A than for Car B. D. Car B because the measures of variability are smaller for Car B than for Car A.