Rena knows a dollar coin has a mass of a little less than 10 grams. She estimates 1 kilogram of coins would be be worth more than a million dollars. Is this reasonable explain.

Answers

Answer 1

Answer: No, it is not reasonable that 1 kilogram of coins would be worth more than a million dollars.

There are a few reasons why this is the case:

1. A kilogram of coins would contain 1000 grams. If each dollar coin weighs less than 10 grams, then a kilogram of dollar coins would contain more than 100 coins. Even if each coin were worth $1000 (which is much more than the face value of a dollar coin), 100 coins would only be worth $100,000.

2. In reality, each dollar coin is worth exactly $1. This means that a kilogram of dollar coins would be worth $1000, which is much less than a million dollars.

3. If Rena's estimate were true, then a single dollar coin would be worth more than $1000, which is clearly not the case.

Therefore, Rena's estimate is not reasonable.

Step-by-step explanation:

Answer 2

This is not reasonable.

What is unit Conversion?

Conversion could appear difficult, but this tip will make it simple for you to convert any unit. The fundamental rule is to multiply when converting from a larger unit to a smaller unit. Divide if you need to go from a smaller to a larger unit.

We have,

A dollar coin has a mass of a little less than 10 grams.

as, 1 Kg = 1000 gm

let a dollar coin mass be x.

So, x < 10 gm

and, 100x < 1000

Now, comparing 1000000 x < 1000000 gm

1000000 x < 1000 Kg

Thus, this is not reasonable.

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Related Questions

whats the answer
x-y=5
3x-2y=12
need to find the x and the y.

Answers

The values of x and y in the system of equations, x - y = 5 and 3x - 2y = 12, are: x = 2  y = -3

How to Solve a System of Equations?

Given the system of equations:

x - y = 5 --> eqn. 1

3x - 2y = 12 --> eqn. 2

Rewrite equation 1:

x = 5 + y --> eqn. 3

Substitute x for 5 + y into equation 2:

3(5 + y) - 2y = 12

15 + 3y - 2y = 12

15 + y = 12

y = 12 - 15 [subtraction property]

y = -3

Substitute y = -3 into equation 3:

x = 5 + (-3)

x = 2

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which of the following situations can use the binomial probability distribution? group of answer choices a sampling of 100 parts to determine whether or not they meet specifications.

Answers

The situation that can use the binomial probability distribution is a sampling of 100 parts to determine whether or not they meet specifications.

The binomial probability distribution is used to model the probability of a certain number of successes in a fixed number of independent trials, where each trial has only two possible outcomes: success or failure. In the given situation, each part in the sample either meets the specifications (success) or does not (failure), which makes it a binomial experiment.

To use the binomial probability distribution, we need to know the probability of success (p) and the number of trials (n). In the given situation, we can determine the probability of a part meet specifications based on the given specifications, and the number of trials is fixed at 100, as we are sampling 100 parts.

Using the binomial probability distribution, we can calculate the probability of a certain number of parts meeting specifications out of the 100 sampled parts. This can be useful in determining whether the sample meets the expected specifications or if there are any issues with the manufacturing process.

In summary, the binomial probability distribution can be used in the given situation of sampling 100 parts to determine whether or not they meet specifications, as it involves a fixed number of independent trials with only two possible outcomes.

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(PLEASE HELP) A student is building a squirrel feeder for a family member. The figure is a model of the feeder.

A rectangular prism with dimensions 4 and one-fourths inches by 18 and one-fourth inches by 3 inches.

How much feed can the container hold?

eighty and one-half in3
one hundred sixteen and one-sixteenth in3
two hundred thirty-two and eleven-sixteenths in3
four hundred sixty-five and three-eighths in3

Answers

The amount of feed the container can hold is 232 11/16 cubic inches. The correct option is the third option - two hundred thirty-two and eleven-sixteenths in3

Calculating how much feed the container can hold

From the question, we are to calculate how much feed the container can hold.

From the given information, the container is a rectangular prism

To calculate how much fed the container can hold, we will determine the volume of the rectangular prism

Volume of a rectangular prism is given by the formula

Volume = Length × Width × Height

Thus,

Volume of the container = 4 1/4 × 18 1/4 × 3

Volume of the container = 232 11/16 cubic inches

Hence,

The quantity of feed it can hold is 232 11/16 cubic inches

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General Chemistry Homework(2) Calculate the following: 1- molecular mass for the compound CgH10N402? Answer M for CgH10N402 (g/mol)= 2-Determine the percent composition for the element C, H, N, O in the compound CgH10N402? Answer %C= %H= %N= %0= 3- The total Percent composition for all the element in the compound CgH10N402? Answer The total Percent= + %

Answers

The total percent composition for all the elements in the compound CgH10N402 is 61.73%.

To calculate the molecular mass of CgH10N402, we need to add up the atomic masses of all the atoms in the compound. The atomic masses can be found on the periodic table.

The molecular formula indicates that the compound contains:

1 carbon atom (C) with atomic mass of 12.01 g/mol

10 hydrogen atoms (H) with atomic mass of 1.01 g/mol

1 nitrogen atom (N) with atomic mass of 14.01 g/mol

4 oxygen atoms (O) with atomic mass of 16.00 g/mol

Molecular mass (M) = (1 x 12.01) + (10 x 1.01) + (1 x 14.01) + (4 x 16.00) = 162.14 g/mol

Therefore, the molecular mass for the compound CgH10N402 is 162.14 g/mol.

To determine the percent composition of each element in the compound, we need to divide the mass contribution of each element by the total molecular mass and multiply by 100%.

Percent composition of C:

Mass contribution of C = 1 x 12.01 g/mol = 12.01 g/mol

% C = (12.01 g/mol / 162.14 g/mol) x 100% = 7.41%

Percent composition of H:

Mass contribution of H = 10 x 1.01 g/mol = 10.10 g/mol

% H = (10.10 g/mol / 162.14 g/mol) x 100% = 6.23%

Percent composition of N:

Mass contribution of N = 1 x 14.01 g/mol = 14.01 g/mol

% N = (14.01 g/mol / 162.14 g/mol) x 100% = 8.63%

Percent composition of O:

Mass contribution of O = 4 x 16.00 g/mol = 64.00 g/mol

% O = (64.00 g/mol / 162.14 g/mol) x 100% = 39.46%

Therefore, the percent composition for the element C, H, N, O in the compound CgH10N402 are:

%C = 7.41%

%H = 6.23%

%N = 8.63%

%O = 39.46%

The total percent composition for all the elements in the compound must add up to 100%.

Total percent composition = %C + %H + %N + %O = 7.41% + 6.23% + 8.63% + 39.46% = 61.73%

Therefore, the total percent composition for all the elements in the compound CgH10N402 is 61.73%.

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If the diameter of a circle is 8.4 in., find the area and the circumference of the circle. Use 3.14 for pi. Round your answers to the nearest hundredth.

Answers

Answer:

Area of the circle = 55.39 in²

Circumference of the circle = 26.38 in

Step-by-step explanation:

Given, the diameter of the circle = 8.4

so the radius is given by the formula

∴ d = 2r

→ 8.4 = 2×r

→r=4.2 in      [i]

Area of the circle = π×r²     [ii]

substituting the value of r in equation [ii]

we get,

area of circle = 3.14×(4.2)²

                      =55.39 in²

                     

circumference of the circle =2πr     [iii]

substituting the value of r in equation [iii]

we get,

circumference of the circle = 2×3.14×4.2

                                             = 26.38 in

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Consider a volleyball net that consists of a mesh with m squares on the horizontal dimension
and n squares on the vertical. What is the maximum number of strings that can be cut before
the net falls apart into two pieces? Solve the problem as a network problem.

Answers

The maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering a mesh with m squares on the horizontal dimension and n squares on the vertical dimension, is min(m+1, n+1).

To determine the maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering the mesh has m squares on the horizontal dimension and n squares on the vertical dimension, we can solve this as a network problem. Here's a step-by-step explanation:

1. Visualize the volleyball net as a graph with nodes representing the intersections of the strings and edges representing the strings themselves.

2. Observe that there are (m+1) nodes horizontally and (n+1) nodes vertically. This is because each square has a node at each corner, so there is an additional node on each side.

3. To separate the net into two pieces, you need to cut all the strings along a specific row or column of the mesh.

4. The maximum number of strings you can cut will be the minimum number of strings needed to cut through the entire mesh either horizontally or vertically.

5. If you choose to cut the strings horizontally, there will be (m+1) strings to cut for each row. Similarly, if you choose to cut the strings vertically, there will be (n+1) strings to cut for each column.

6. Compare the number of strings to cut in both directions, and choose the direction with the minimum number of strings to cut.

7. The maximum number of strings that can be cut before the net falls apart into two pieces is the minimum between (m+1) and (n+1).

So, the maximum number of strings that can be cut before the volleyball net falls apart into two pieces, considering a mesh with m squares on the horizontal dimension and n squares on the vertical dimension, is min(m+1, n+1).

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y1= sin(x) y2= sin(2x) y3= sin(3x) % 1st plot is to be red and dashed % 2nd plot is to be blue and solid % 3rd plot is to be black and dotted The plot ranges from -6 to 6 in steps of 0.2. Use enough steps so that the plots are smooth. You must include a title ('Multiple Plots'), X-axis label ('x'), y-axis label ('Sine functions') and also a legend ('sin(x)', 'sin(2x)', 'sin(3x)'). In additional, use the grid on and axis equal command.

Answers

To create a plot with three different sine functions, we can use MATLAB code that includes the "plot" function, as well as specific parameters to set the ranges, colors, and styles of each line. First, we need to set up the x-axis range using the "range" function, which takes in the minimum, maximum, and step size values. In this case, we want the range to be from -6 to 6 with steps of 0.2, so we can write:

x = (-6:0.2:6);

Next, we can define each y value using the sine function and the corresponding multiple of x. For example, y1 corresponds to sin(x), so we can write:

y1 = sin(x);

Similarly, we can define y2 and y3 as:

y2 = sin(2*x);
y3 = sin(3*x);

Now, we can use the "plot" function to create a graph with all three sine functions plotted together. We want each function to be plotted with a different color, style, and legend label, so we can specify these parameters in the "plot" function call. Specifically, we want:

- y1 to be plotted in red and dashed
- y2 to be plotted in blue and solid
- y3 to be plotted in black and dotted
- a legend to be added with the labels 'sin(x)', 'sin(2x)', and 'sin(3x)'
- a title to be added with the label 'Multiple Plots'
- an x-axis label to be added with the label 'x'
- a y-axis label to be added with the label 'Sine functions'

Here is the complete code:

x = (-6:0.2:6);
y1 = sin(x);
y2 = sin(2*x);
y3 = sin(3*x);

plot(x, y1, 'r--', 'LineWidth', 1.5, 'DisplayName', 'sin(x)');
hold on;
plot(x, y2, 'b-', 'LineWidth', 1.5, 'DisplayName', 'sin(2x)');
plot(x, y3, 'k:', 'LineWidth', 1.5, 'DisplayName', 'sin(3x)');

title('Multiple Plots');
xlabel('x');
ylabel('Sine functions');
legend('show', 'Location', 'northwest');

grid on;
axis equal;

The "hold on" command ensures that all three plots are shown on the same graph. The "LineWidth" parameter sets the width of each line, and the "DisplayName" parameter sets the label for each line in the legend. Finally, the "grid on" and "axis equal" commands add a grid to the graph and ensure that the x and y axes are scaled equally.

Overall, this code will create a graph with three smooth sine functions plotted together, each with a different color, style, and legend label.

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Jeff's work to find the missing length of the triangle is shown. Explain Jeff's error.

Answers

The missing length of the triangle is given as follows:

x = 35 units.

What is the Pythagorean Theorem?

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.

For the triangle in this problem, we have that:

There is a side of 12 units.The hypotenuse has length of 37 units.

Hence the missing length is obtained as follows:

x² + 12² = 37²

x = sqrt(37² - 12²)

x = 35 units.

Missing Information

The image is blurry, hence the mistake in Jeff's part cannot be explained.

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Please Answer fast Enhancer 1 Find the temperature of the sun if pressure is 1.4x10 atm, density is 1.4 g/cc and average molecular weight of gases present there is 2 (R = 8.4 x 107 erg/mol/K) (a) 3.2 x 10'K (b) 2.4 x 10'K (c)1.2 x 10K (d) 1.8 x 107K

Answers

To find the temperature of the sun, we'll use the ideal gas law equation, which is PV = nRT. We're given pressure (P), density (ρ), average molecular weight (M), and the gas constant (R). First, we'll find the number of moles (n) and then solve for temperature (T). After the calulation the answer is found out to be option b which is approximately 2.4 x 10^7 K.

1. Calculate the number of moles (n) using the formula n = ρ/M.
  n = 1.4 g/cc / 2 g/mol = 0.7 mol/cc
2. Rearrange the ideal gas law equation to solve for temperature (T): T = PV / nR
3. Plug in the values:
  P = 1.4 x 10^10 atm
  V = 1 cc (since we are considering 1 cc of the gas)
  n = 0.7 mol
  R = 8.4 x 10^7 erg/mol/K
  T = (1.4 x 10^10 atm) x (1 cc) / (0.7 mol) x (8.4 x 10^7 erg/mol/K)
4. Perform the calculation:
  T = 1.4 x 10^10 / (0.7 x 8.4 x 10^7) = 2.38 x 10^7 K
The temperature of the sun is approximately 2.4 x 10^7 K (option b).

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The number of people who visited a winter carnival
during the first 7 hours of a day was recorded, as
shown.
79, 83, 50, 69, 86, 77, 88
It was later found that the number of people who
visited during 4th hour was incorrectly recorded. It
should have been 96. Enter a number in each box
to make the statements true.
The range of the incorrectly recorded data is
The actual range of the data is

Answers

Answer: The range of the incorrectly recorded data is:

96 - 50 = 46

The actual range of the data is:

96 - 50 = 46

The range is not affected by the correction of the 4th hour data because the range only depends on the difference between the highest and lowest values, which remains the same.

Step-by-step explanation:

What is the equation of the following line? Be sure to scroll down first to see
all answer options.
O A. y=-¹1-x
OB. y = 2x
OC. y = 4x
O D. y = ¹/x
O E. y = -2x
F. y=x
(-4,8)
-10
10
-10-
(0,0)
10

Answers

The equation of the following line include the following: E. y = -2x .

How to determine an equation of this line?

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical equation (formula):

y - y₁ = m(x - x₁)

Where:

x and y represent the data points.m represent the slope.

First of all, we would determine the slope of this line;

Slope (m) = (y₂ - y₁)/(x₂ - x₁)

Slope (m) = (8 - 0)/(-4 - 0)

Slope (m) = 8/-4

Slope (m) = -2.

At data point (-4, 8) and a slope of -2, a linear equation for this line can be calculated by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 8 = -2(x + 4)  

y - 8 = -2x - 8

y = -2x

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Find the diameter of circle O

Answers

The diameter of the circle is determined as 20.12 units.

What is the radius of the circle?

The radius of the circle is calculated by applying the following formula as shown below;

The let the distance between 9 and center of the circle O = x

The radius of the circle, r = 9 + x --- (1)

Draw a line from circumference from point 10 to center O, this line is the radius = r

Apply Pythagoras theorem;

r² = 10² + x² ------ (2)

From the first equation, recall, r = 9 + x

(9 + x)² = 10² + x²

81 + 18x + x² = 100 + x²

81 + 18x = 100

18x = 100 - 81

18x = 19

x = 19/18

x = 1.06

The radius of the circle = 9 + x

r = 9 + 1.06

r = 10.06

The diameter of the circle = 2r

= 2 x 10.06

= 20.12 units

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draw the graph of polynomial function​

Answers

The graph of the polynomial function​ that passes through the points P(−2,2) and Q(1,0) is added as an attachment

Drawing the graph of polynomial function​

From the question, we have the following parameters that can be used in our computation:

The graph passes through the points P(−2,2) and Q(1,0)

Assuming the graph is a linear function

So, we have

y = mx + c

Where

c = y when x = 0 and m = slope

This gives

-2m + c = 2

m + c = 0

Subtract the equations

So, we have

-3m = 2

m = -2/3

Solving for c, we have

-2/3 + c = 0

Evaluate

c = 2/3

So, the equation is f(x) = -2/3x + 2/3

See attachment for the graph

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Complete question

Draw the graph of polynomial function f(x) containing the points P(−2,2) and Q(1,0)

In a class of 100 students, 55 students have passed in physics and 67 students have passed in Mathematics. Find the number of students passed in Physics only.

Answers

Answer:

Step-by-step by steo

Total number of students = n(P∪M)=100

                   Number of students who passed in physics= n(P)=55

                   Number of students who passed in maths= n(M)=67

                   Number of students who passed both physics and maths=n(P∩M)

                   ⇒n(P∪M)=n(P)+n(M)−n(P∩M)

                   ⇒100=55+67−n(P∩M)

                   ⇒n(P∩M)=122−100

                   ⇒n(P∩M)=22

Step - 2 : Find number of students who passed only in physics

                   Number of students passed in physics = 55

                   Number of students passed in physics and maths both = 22

                   ∴Number of students passed only in physics = 55−22=33

WHAT VALUE OF X WOULD MAKE THE INEQUALITY 55<6X-2 TRUE

Answers

The inequality is x > 9.5 and the numbers greater than 9.5

Given data ,

Let the inequality equation be represented as A

Now , the value of A is

55 < 6x - 2

Adding 2 on both sides , we get

6x > 57

Divide by 6 on both sides , we get

x > 9.5

So , x satisfies all numbers greater than 9.5

Hence , the inequality is x > 9.5

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CARD 4
Zoe opens a savings account that
earns annual compound interest. If she
doesn't make any deposits or
withdrawals after her initial deposit,
the balance in the account after x
years can be represented by the
equation below.
b(x)=675(1.045)*
D
Duncan says the
balance in the
account increases at
a rate of 45% each
year.
Daniella says the
balance in the
account increases at
a rate of 4.5% each
year.
Which answer is right

Answers

The correct answer about the savings account that Zoe opened, represented by the equation b(x)=675(1.045)ˣ is B. Daniella says the balance in the account increases at a rate of 4.5% each year.

What is an equation?

An equation is a mathematical statement that two or more algebraic expressions (the combination of variables with constants and mathematical operands) are equal or equivalent.

This equation is known as the future value equation, formula, or function.

Initial investment = $675

Compound interest rate = 4.5% (0.045 x 100)

Future value factor = 1.045 (100% + 4.5%)

Based on the future value function above, we can conclude that the compound interest rate is 4.5%, which is equivalent to 0.045 as given in the equation.

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Lines b and care parallel. Which pair of angles are alternate exterior angles?
OA. 27 and 28
OB. 21 and 22
OC. 23 and 26
OD. 21 and 28
SUBMIT

Answers

angle 1 and angle 8 are alternate exterior angles.

option D.

What are alternate exterior angles?

Alternate exterior angles are pairs of angles that are located on opposite sides of a transversal line intersecting two parallel lines, and their values are equal.

These angles are positioned in such a way that they are outside of the two parallel lines, but on opposite sides of the transversal.

For the given diagram, the alternate exterior angles are determined as;

angle 1 and angle 8 are alternate exterior angles.

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Find the mean, median, mode, range, and standard deviation of the data set that is obtained after multiplying each value by the given constant. Round to the nearest tenth, if necessary. If there is no mode, write none.
1, 5, 4, 2, 1, 3, 6, 2, 5, 1; x6.5

Answers

Answer:

Step-by-step explanation:

First, organize the numbers; 1,1,1,2,2,3,4,5,5,6. The median is the middle number, in this case, 2 and 3 are in the middle. You'd add 2+3 which equals 5, then divide by 2 to get 2.5. The median is 2.5, to find the mode you need to see how many times one number appears. The mode is 1, the range is the largest number minus the smallest number. The range is 5, to find the mean you add all numbers up, then divide by how many numbers there are. All the numbers added up are 30, now divide that by 10 to get 3. The mean is 3. The standard deviation is 1.7 x 6.5 = 20.8

I'm only an algebra student so I may not be entirely correct.

Use the information given in Exercises 8 - 10 to find the necessary confidence bound for the binomial proportion P. Interpret the interval that you have constructed. 99% upper bound, n = 55, x = 24

Answers

The 99% upper bound for the binomial proportion P is 0.790. To find the necessary confidence bound for the binomial proportion P, we can use the formula: Upper bound = x/n + Zα/2√(x/n(1-x/n))

In this case, we are looking for a 99% upper bound, so Zα/2 = 2.576. Plugging in the given values, we get:
Upper bound = 24/55 + 2.576√(24/55(1-24/55))
          = 0.526 + 2.576(0.100)
          = 0.790
Therefore, the 99% upper bound for the binomial proportion P is 0.790.
Interpreting the interval, we can say that we are 99% confident that the true proportion of whatever we are measuring (which is represented by P) is no higher than 0.790. In other words, we can be fairly certain that the actual proportion falls within the interval from 0 to 0.790.

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A 15-cm × 20-cm printed circuit board whose components are not allowed to come into direct contact with air for reliability reasons is to be cooled by passing cool air through a 20-cm-long channel of rectangular cross section 0. 2 cm × 14 cm drilled into the board. The heat generated by the electronic components is conducted across the thin layer of the board to the channel, where it is removed by air that enters the channel at 15°C. The heat flux at the top surface of the channel can be considered to be uniform, and heat transfer through other surfaces is negligible. The velocity of the air at the inlet of the channel does not exceed 4. 95 m/s and the surface temperature of the channel remains under 50°C. Assume that the flow is fully developed in the channel. 77777 Air 3W 15°C Air channel 0. 2 cm x 14 cm Electronic components the properties of air at a bulk mean temperature at 25C p=1. 184 kg/m k = 0. 02551 W/m°C v=1. 562x10 m/s Cy=1007 J/kg. °C Pr=0. 7296 also Nu=8. 24 Calculate the maximum total power of the electronic components that can safely be mounted on this circuit board?

Answers

The maximum total power of the electronic components that can safely be mounted on this circuit board is 4.2 W.

The maximum total power of the electronic components that can safely be mounted on the circuit board is determined by the amount of heat that can be removed from the channel by the air flow without exceeding the maximum allowable temperature of 50°C on the channel surface.

To calculate the maximum total power of the electronic components, we need to determine the heat transfer rate from the channel to the air flow

where Q is the heat transfer rate, h is the convective heat transfer coefficient, A is the surface area of the channel, and ΔT is the temperature difference between the channel surface and the air.

The convective heat transfer coefficient can be calculated using the Nusselt number correlation for flow inside a rectangular channel:

Nu =  8.24

h =  8.240.02551 /0.2 = 1.048 W/m

where L is the channel's hydraulic diameter, equal to [tex]2*(0.2*14)/(0.2+14)[/tex]  = 0.278 cm = 0.00278 m.

The surface area of the channel is A = 20.220 + 20.214 + 14[tex]*20[/tex] = 120.8 cm[tex]^2[/tex] = 0.01208 [tex]m^2.[/tex]

The temperature difference between the channel surface and the air is ΔT = 50°C - 15°C = 35°C.

Therefore, the maximum heat transfer rate from the channel to the air flow is:

Q = hAΔT = 1.0480.0120835 = 0.0042 kW

This means that the maximum total power of the electronic components that can be safely mounted on the circuit board is:

P = Q = 0.0042 kW = 4.2 W

Therefore, the maximum total power of the electronic components that can safely be mounted on this circuit board is 4.2 W.

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Find the mean, median, interquartile range and mean absolute deviation of the set of numbers. Round to the nearest tenth, if necessary. 1, 1, 4, 8, 9, 3, 8 please help ​

Answers

Answer:

mean- 4.9

median- 4

interquartile range- 7

Step-by-step explanation:

Hope this helps! :)

How do i solve for x?

Answers

Answer:

78° + 95° + (2x + 115)° + 72° = 360°

(2x + 360)° = 360°, so x = 0.

Nachelle earned a score of 725 on Exam A that had a mean of 700 and a standard deviation of 50. She is about to take Exam B that has a mean of 100 and a standard deviation of 20. How well must Nachelle score on Exam B in order to do equivalently well as she did on Exam A? Assume that scores on each exam are normally distributed.

Answers

Nachelle needs to score 110 on Exam B in order to do equivalently well as she did on Exam A.

Given data: Nachelle earned a score of 725 on Exam A that had a mean of 700 and a standard deviation of 50.

She is about to take Exam B that has a mean of 100 and a standard deviation of 20.Let x be the score on Exam B that Nachelle needs to do equivalently well as she did on Exam A.

According to the Z-score formula, Z = (x - μ) / σ where Z is the standard score, x is the value of the element, μ is the population mean, and σ is the standard deviation.

Let's calculate the Z-scores for Nachelle's scores on Exams A and B.

Z-score for Nachelle's score on Exam AZ1 = (725 - 700) / 50 = 0.5

Z-score for Nachelle's score on Exam BZ2 = (x - 100) / 20 = (x - 100) / 20

Now, if Nachelle has to do equivalently well on Exam B as she did on Exam A, then the Z-scores for both exams should be equal.

Hence,0.5 = (x - 100) / 20Solving for x,x - 100 = 0.5 × 20 = 10x = 100 + 10 = 110.

Therefore, Nachelle needs to score 110 on Exam B in order to do equivalently well as she did on Exam A.

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The circle centered at Q is a scaled copy of the circle centered at R.
a. Find the scale factor.
ingrese su respuesta.....
840

Answers

The scale factor of the dilation of the circles is 5

What is the scale factor of the dilation?

From the question, we have the following parameters that can be used in our computation:

The circles

From the circles, we have the following parameters

Diameter of big circle Q = 20

Diameter of the small circle R = 4

Using the above as a guide, we have the following:

Scale factor of the dilation = Radius of big circle/Radius o the small circle

So, we have

Scale factor of the dilation = 20/4

Evaluate

Scale factor of the dilation = 5

Hence, the scale factor of the dilation is 5

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7. Use the following figure to answer questions a-d.
a. Find the perimeter of the figure if the following is true:
a = x + 7
b = 2x + 2
C = 8x
d = x + 10

b. What is the perimeter of the figure in part
(a) if x = 4

c. What is the perimeter of the figure in part (b)
if x = 2 ?

d. Find the perimeter of the figure if the following
is true:
a = x2
b = 4x + 8
c = 2x²
d = x​

Answers

a)  The perimeter of the figure [tex]p = 12x + 19[/tex]

b) The perimeter of the figure when [tex]x = 4[/tex] is 67 units.

c)  The perimeter of the figure when[tex]x = 2[/tex] is 43 units

d)  The perimeter of the figure is [tex]3x^2 + 5x + 8[/tex] units.

a) The perimeter P of the figure is the sum of the lengths of its sides:

[tex]P = a + b + c + d[/tex]

Substituting the given expressions for a, b, c, and d in terms of x, we get:

[tex]P = (x + 7) + (2x + 2) + (8x) + (x + 10)[/tex]

[tex]= 12x + 19[/tex]

b) Substituting x = 4, we get:

[tex]P = 12x + 19[/tex]

[tex]= 12(4) + 19[/tex]

[tex]= 67[/tex]

Therefore, the perimeter of the figure when [tex]x = 4[/tex] is 67 units.

c) Substituting [tex]x = 2,[/tex] we get:

[tex]P = 12x + 19[/tex]

[tex]= 12(2) + 19[/tex]

[tex]= 43[/tex]

Therefore, the perimeter of the figure when[tex]x = 2[/tex] is 43 units.

d) Substituting the given expressions for a, b, c, and d in terms of x, we get:

[tex]P = x^2 + (4x + 8) + 2x^2 + x[/tex]

[tex]= 3x^2 + 5x + 8[/tex]

Therefore, the perimeter of the figure when[tex]a = x^2, b = 4x + 8, c = 2x^2,[/tex] and [tex]d = x[/tex] is [tex]3x^2 + 5x + 8[/tex] units.

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An orange cone has a volume of 376.8 cubin cm and a radius of 6 cm. What is the height?

Answers

Answer:

3.29 cm.

Step-by-step explanation:

The formula for the volume of a cone is V = (1/3)πr^2h, where V is the volume, r is the radius, and h is the height.

Substituting the given values, we get:

376.8 = (1/3)π(6^2)h

Simplifying:

376.8 = 36πh

h = 376.8 / (36π)

h ≈ 3.29 cm

Therefore, the height of the orange cone is approximately 3.29 cm.

Howto prove for root test convergence for complex number.

Answers

To prove convergence for the root test with complex numbers, we use the same approach as with real numbers.
Let's consider a series ∑an with complex terms. We can apply the root test by taking the nth root of the absolute value of each term, which gives us:
lim (n→∞) ∛|an|
If this limit is less than 1, then the series converges absolutely. If it is greater than 1, then the series diverges.
To prove convergence for the root test, we need to show that this limit is less than 1. We can do this by expressing the complex number an in polar form, such that an = rn*e^(iθn), where rn is the magnitude of an and θn is its argument.
Then, taking the nth root of the absolute value of an, we get:
|an|^1/n = (rn)^(1/n)
We can express rn as |an|*cos(θn) + i*|an|*sin(θn), and take the nth root of each term separately:
|an|^1/n = [(|an|*cos(θn))^2 + (|an|*sin(θn))^2]^(1/2n)
= |an|^(1/n) * [(cos(θn))^2 + (sin(θn))^2]^(1/2n)

= |an|^(1/n)
Since the limit of |an|^(1/n) is the nth root of the magnitude of the series, we can rewrite the root test as:
lim (n→∞) ∛|an| = lim (n→∞) |an|^(1/n)
If we can show that this limit is less than 1, then we have proven convergence for the root test with complex numbers.

One way to do this is to use the fact that |an|^(1/n) ≤ r, where r is the radius of convergence of the series. This inequality follows from Cauchy's root test, which applies to both real and complex numbers.
Therefore, if the radius of convergence of the series is less than 1, then the limit of |an|^(1/n) is also less than 1, and the series converges absolutely.
In summary, to prove convergence for the root test with complex numbers, we express each term in polar form and take the nth root of its magnitude. We then show that the limit of these roots is less than 1 by using Cauchy's root test and the radius of convergence of the series.

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Find the necessary and sufficient conditions for the spiral if α
(t)=(at,bt^2,t^3)
is a cylindrical helix.
decide on the axis at this time.

Answers

In this case, since the curve is not a cylindrical helix, there is no well-defined axis.

A cylindrical helix is a curve in 3D space that follows the path of a cylinder as it is unwrapped along a line. The curve is parameterized by a vector function α(t) = (x(t), y(t), z(t)), where x(t) = r cos(t), y(t) = r sin(t), and z(t) = ht, with r and h being the radius and height of the cylinder, respectively.

In this case, the parameterization of the curve is given by α(t) = (at, bt^2, t^3). To determine if it is a cylindrical helix, we need to check if it follows the path of a cylinder as it is unwrapped along a line.

First, let's look at the z-coordinate, which corresponds to the height of the curve. We see that it is a cubic function of t, which means that the curve is not a horizontal line and it does not lie in a plane. This suggests that the curve may be a helix.

Next, let's look at the x and y-coordinates. The x-coordinate is a linear function of t, which means that it varies uniformly along the curve. The y-coordinate, on the other hand, is a quadratic function of t, which means that it changes faster than the x-coordinate.

This indicates that the curve may be a spiral, which is a type of helix that has an additional circular motion in the x-y plane as it moves along the z-axis. To confirm that the curve is a spiral, we need to check that the radius of the circle traced out by the curve in the x-y plane is constant.

To find the radius, we can take the derivative of the x and y-coordinates with respect to t:

dx/dt = a

dy/dt = 2bt

The radius of the circle is given by:

r = sqrt(x^2 + y^2) = sqrt(a^2 + 4b^2t^2)

We can take the derivative of r with respect to t to see if it is constant:

dr/dt = 4bt/sqrt(a^2 + 4b^2t^2)

We see that dr/dt is not constant, which means that the radius of the circle traced out by the curve is changing as it moves along the z-axis. Therefore, the curve is not a spiral.

In summary, the necessary and sufficient conditions for the curve to be a cylindrical helix are:

The z-coordinate of the curve is a linear function of t, i.e., z(t) = ht.

The radius of the circle traced out by the curve in the x-y plane is constant.

In this case, the curve does not satisfy condition 2, which means that it is not a cylindrical helix.

The axis of the curve is the line along which the cylinder is unwrapped. In this case, since the curve is not a cylindrical helix, there is no well-defined axis.

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QUESTION 10 During oxygen consumption measurement the participants VO2 was 1004 L/min and VCO2 was 0.932 min. What was the participants RER at that point in time? Give your answer to 4 decimal places

Answers

The participant's RER at that point in time was approximately 0.0009 (rounded to 4 decimal places).

To calculate the participant's Respiratory Exchange Ratio (RER) at that point in time, you will use the formula:

RER = VCO2 / VO2

Given the participant's VO2 was 1004 L/min and VCO2 was 0.932 L/min, plug these values into the formula:

RER = 0.932 / 1004

Now, divide 0.932 by 1004:

RER ≈ 0.0009

So, the participant's RER at that point in time was approximately 0.0009 (rounded to 4 decimal places).

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the melting point of each of 16 samples of a certain brand of hydrogenated vegetable oil was determined, resulting in a sample mean of 94.32. assume the distribution of melting point is normal with a population standard deviation of 1.20. does the true mean melting point differ from 95? use a significance level of 0.01

Answers

We do not have enough evidence to conclude that the true mean melting point differs from 95 at a significance level of 0.01.

To determine if the true mean melting point differs from 95, we can use a one-sample t-test with a significance level of 0.01.

The null hypothesis is that the true mean melting point is equal to 95, and the alternative hypothesis is that the true mean melting point is different from 95.

We can calculate the t-statistic using the formula:

t = (sample mean - hypothesized mean) / (sample standard deviation / sqrt(sample size))

where sample size is 16, sample mean is 94.32, hypothesized mean is 95, and sample standard deviation is the same as the population standard deviation of 1.20.

Plugging in these values, we get:

[tex]t = (94.32 - 95) / (1.20 / \sqrt{(16)} ) = -2.6667[/tex]

Using a t-distribution table with 15 degrees of freedom (n-1=16-1), and a two-tailed test at a significance level of 0.01, the critical t-value is ±2.947.

Since our calculated t-value of -2.6667 falls within the acceptance region (-2.947 < -2.6667 < 2.947), we fail to reject the null hypothesis.

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