Please help me if you know physics

Answer:

When a heavy football player and a light one run into each other, does the lighter player really exert as much force on the heavy player s the heavy player exerts on the light one. Yes. The interaction between the two players, the force each exerts on the other have equal strength.

Explanation:

Answer:

Sodium and calcium

Explanation:

Answer:

Ionic bond is the name given to one of the three ways in which atoms can interact with each other. The other forms of interaction between atoms are the covalent bond, which occurs between atoms of ametals, hydrogens, or ametal and hydrogen, and the metallic bond, which occurs only between atoms of the same metal.

Explanation

:The atoms of the chemical elements that participate in the ionic bond must present, necessarily, the nature of gaining or losing electrons, thus, the ionic bond can occur between:

a metal and an ametal;

a metal and hydrogen.

Sodium: metallic element, as it has the characteristic of losing electron; belonging to the IA family, atomic number 11, with an electron in the valence shell.

Chlorine: ametalic element, as it has the characteristic of gaining electrons; belonging to the VIIA family, with atomic number 17.

Answer:

1.77 m/s^2

Explanation:

since it is unbalanced there must be net force(resultant force)

[tex]net \: force \: = accleration \: \times mass[/tex]

net force = 23N

mass = 13kg

a = x

x = 23/13

= 1.769...

approximately = 1.77 m/s^2

Answer:

The best and most correct answer among the choices provided by the question is the third choice. What he observed on the waves is the constructive interference. I hope my answer has come to your help. God bless and have a nice day ahead!

Explanation:

Answer:

Pierce conducts an experiment in which waves collide in a way that the energy increases. What has occurred?

refraction

reflection

constructive interference <<<---CORRECT

destructive interference

Explanation:

2021 EDGE

Answer:

two carbon atoms bonded to each other

a chain of one hundred carbon atoms bonded to one another

a carbon atom bonded to an oxygen atom

two carbon atoms bonded to each other a carbon atom, a chain of one hundred carbon atoms bonded to one another, a carbon atom bonded to an oxygen atom all these are examples of molecules, therefore all the given options are the correct answer

The smallest component of a substance that still has its content and characteristics is called a molecule. It is constructed of two or more atoms connected by chemical bonds. Moles are the foundation of chemistry. Molecules are designated by their elemental symbol and a subscript indicating their atom count.

Atoms are the fundamental unit of an element. They consist of a nucleus and surrounding electrons. When an atom has an incomplete electron shell, it is said to have valence electrons. When two or more atoms come together to share outer shell valence electrons, a covalent bond is formed,

Since molecules include two carbon atoms bonded to each other, one carbon atom, a chain of hundred carbon atoms bonded to one another, and a carbon atom bonded to an oxygen atom, all of the suggested answers are correct.

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Answer:

Four metals other than iron that can be made to exhibit magnetic properties are nickel, cobalt, manganese, and chromium.

two

neutral region

north

magnetic

Explanation:

PennFoster

The four metals other than iron that can be made to exhibit magnetic properties are:

Furthermore, the words which can be used to accurately complete the sentences below are:

The magnet has two unlike poles and in the neutral region, there is the South and North poles.

The North and South poles repel each other and a magnet can attract any material which contains iron materials.

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Answer:

2.5m/s^2

Explanation:

Note that the boat is reducing its speed. It is having negative acceleration or deceleration.

V^2 = u^2 -2as ( minus sign is used because of speed is reduced)

Given that,

s = 12 m

v = 5.5 m/s

u = 9.5 m/s

a = (v^2 - u^2) ÷ (-2s)

a= ( 5.5^2 - 9.5^2) ÷ ( -2× 12)

a = 2.5 m/s^2

The acceleration of the boat is -2.5 m/s²

The given paramters;

distance traveled by the boat, d = 12 m

initial velocity of the boat, u = 9.5 m/s

final velocity of the boat, v = 5.5 m/s

The acceleration of the boat is calculated as;

[tex]v^2 = u^2 + 2as\\\\2as = v^2 - u^2\\\\a = \frac{v^2 - u^2}{2s} \\\\a = \frac{(5.5)^2 -(9.5)^2 }{2(12)} \\\\a = -2.5 \ m/s^2[/tex]

Thus, the deceleration of the boat is 2.5 m/s²

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Answer:

an atom

Explanation: atom then matter

Answer:

the basic building blocks that make up matter are called atoms.

Answer:

The answer is c

Explanation:

Answer: a constant? im not sure that just sounds like itd be right.

Explanation:

Answer:

b

Explanation:

because he isn't moving

Answer:

24

Explanation:

you multiply 2.0x12

Answer:

18 m/s west

Explanation:

The correct option is C. 23 m/s east

Conservation of momentum states that For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

using conservation of momentum

m1v1 + m2v2 = m1 v1' + m2 v2'

Given

m1 = 3154 kg

v1= 6m/s

m2 = 8296 kg

v2 = 23 m/s

v1' = 7m/s

v2' = ?

3154 * 6 + 8296 * 23 = 3154 * 7 + 8296 v2'

209732 - 22078 = 8296 v2'

187654 = 8296 v2'

v2' = 22.62 ≈ 23 m/s east

correct option is C. 23 m/s east

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Answer:

should be d because friction allows things to go faster or slower

Answer:

What are the choices?

Explanation:

1. The speed of the roller coaster car at point B and C: are 19.8 m/s and 0 m/s respectively.

2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on  the mass of an object.

Given the following data:

1. To find the speed of the roller coaster car at point B and C:

First of all, we would determine the potential energy of the roller coaster car by using the formula:

[tex]P.E = mgh[/tex]

Where:

From the diagram, height at point B = [tex]\frac{h}{2} = \frac{40}{2} = 20[/tex] meters

[tex]P.E = 750(9.8)(20)[/tex]

P.E = 147000 Joules.

Next, we would determine the speed by applying the law of conservation of energy.

[tex]Kinetic\;energy = Potential\;energy\\\\\frac{1}{2} mv^2 = mgh[/tex]

Substituting the values, we have;

[tex]147000 = \frac{1}{2} (750)v^2\\\\147000 = 375v^2\\\\v^2 = \frac{147000}{375} \\\\v^2 = 392\\\\v = \sqrt{392}[/tex]

Speed, v = 19.8 m/s

From the diagram, at point C, the speed is equal to zero (0) meters per seconds.

2. If mass (m) of the roller coaster car were doubled, the speed at B would increase because energy is dependent on  the mass of an object.

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Answer:

20.83rad/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 and m2 are the mass of the disc and Brick respectively

u1 and u2 are the linear velocities respectively

v is their final velocity of the block-disc system

Given

m1 = 100kg

m2 = 20kg

u1 = wr =25×1.6

u1 = 40m/s

u2 = 0m/s (brick is stationary)

Substitute and the final linear velocity v

100(40)+20(0) = (100+20)v

4000 = 120v

v = 4000/120

v = 33.3m/s

From the formula;

v = wr

w = v/r

w= 33.3/1.6

w = 20.83rad/s.

Hence the final angular speed of the disc-brick system is 20.83rad/s

Answer: 2 hours 17 minutes

Explanation: 80/35h = 16/7 = 2hrs 17 minutes

Complete Question

A 6.00-µc charge is moving with a speed of 7.50x10^4 m/s parallel to a very long, straight wire. the wire is 5.20 cm from the charge and carries a current of 68.5 A in a direction opposite to that of the moving charge. Calculate the magnitude of the force on the charge.

Answer:

The value is [tex]F =1.20 *10^{-4} \ N[/tex]

Explanation:

From the question we are told that

     The magnitude of the charge is  [tex]Q = 6.00\muC = 6.00 *10^{-6} \ C[/tex]

      The speed is  [tex]v = 7.50 *10^{4} \ m/s[/tex]

      The distance of the wire from the charge is  [tex]d = 5.20 \ cm = 0.0520 \ m[/tex]

       The current flowing through the wire in the opposite direction to the charge  is  [tex]I _2 = 68.5 \ A[/tex]

  Gnerally the magnitude of force on that charge is mathematically represented as

      [tex]F = qvB[/tex]

Here B is magnetic field which is mathematically represented as

              [tex]B = \frac{\mu_o * I}{2\pi d}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value  [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

 So

       [tex]F = qv[\frac{\mu_o * I}{2\pi d}][/tex]

=>     [tex]F = 6.0*10^{-6} * (7.50 *10^{4})[\frac{4\pi * 10^{-7} * 68.5 }{2* 3.142 * 0.0520 }][/tex]      

=>    [tex]F =1.20 *10^{-4} \ N[/tex]

Answer:

4 s

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Total time (T) =.?

Next, we shall determine the time take by the rock to get to the maximum height. This can be obtained as follow:

NOTE: At maximum height, the final velocity is zero.

Initial velocity (u) = 19.4 m/s.

Acceleration due to gravity (g) = –9.81 m/s²

Final velocity (v) = 0 m/s

Time taken to reach the maximum height (t) =.?

v = u + gt

0 = 19.4 + (–9.81 × t)

0 = 19.4 – 9.81t

Collect like terms

0 – 19.4 = –9.81t

–19.4 = –9.81t

Divide both side by –9.81

t = –19.4 / –9.81

t ≈ 2 s

Thus, it took approximately 2 s for the rock to reach its maximum height.

Finally, we shall determine the total time spent by the rock in the air as follow:

Time taken to reach the maximum height (t) = 2 s

Total time spent in air (T) =?

The total time (T) spent by the rock in the air will be two times the time taken (t) to reach the maximum height i.e

T = 2t

t = 2 s

T = 2 × 2

T = 4 s

Therefore, the rock spent approximately 4 s in the air.

the answer is 198.23

Force(f) = 18344 N

Acceleration(a) = 92.54 m/s²

we know that m=f/a

m=18344/92.54</p><p>

ma 198.23 kg

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nope. opposite charges attract. like charges repel.

Answer:

a. (18,8)

b. (3, 6)

c. (10, 10, 10)

d. (a+d, b+e, c+f)

Give me brainliest for this... Thanks

Answer:

[tex]a=1.33\ m/s^2[/tex]

Explanation:

Given that,

Initialy, the jet is at rest, u = 0

Final velocity of the jet, v = 75 m/s

Distance, d = 2100 m

We need to find the acceleration of the jet. It is based on the concept of equation of kinematics. Using third equation of motion, w get :

[tex]v^2-u^2=2ad[/tex]

a is acceleration

[tex]75^2=2a\times 2100\\\\a=\dfrac{75^2}{2\times 2100}\\\\a=1.33\ m/s^2[/tex]

So, the acceleration of the jet is [tex]1.33\ m/s^2[/tex].

Answer:

3/4 0r 0.75

Explanation:

Let E represent the extra cash.

Let R represent the amount raised.

From the question given above, we can say that:

The extra cash (E) is directly proportional to the amount raised (R) i.e

Extra cash (E) ∝ Amount raised (R)

E ∝ R

E = KR

NOTE: K is the constant of proportionality.

With the above formula, we can obtain the value of K as follow:

Extra cash (E) = $ 75

Amount raised (R) = $ 100

Constant of proportionality (K) =?

E = KR

75 = K × 100

Divide both side by 100

K = 75/100

K = 3/4 0r 0.75

Thus, the constant of proportionality is 3/4 0r 0.75

Answer:

Approximately 17.21 seconds

Explanation:

With subtraction, we have the gazelle 18.3 km/h slower than the cheetah, which is about 5.08333 m/s. As the gazelle is 87.5 meters ahead of the cheetah, 87.5 divided by 5.083333333 is about 17.21 seconds.

Answer:

B. It is B because without this much space for oxygen and blood to flow and go through, we would not survive.

Explanation:

Answer:

Height ball A will deflect the target is 2.65 m

Height ball A will deflectthe target is 2.2 m

Ball A, will deflect the target to greater height, thus i will throw ball A

Explanation:

Given;

mass of the target, m₁ = 5.00 kg

mass of the ball, m₂ = 1.5 kg

initial velocity of each throw, u = 12 m/s

Throwing ball A; apply the principle of conservation linear momentum for elastic collision;

m₁u₁ + m₂u₂ = v₁m₁ + v₂m₂

The initial velocity of the target, u₁ = 0

The ball bounced back at the same speed, v₂ = -12 m/s

the velocity of the target after collision, = v₁

0 + 1.5 x 12 = v₁(5) + (-12 x 1.5)

18 = 5v₁ - 18

18 + 18 = 5v₁

36 = 5v₁

v₁ = 36/5

v₁ = 7.2 m/s

The vertical height reached by the target is given by;

v₁² = u₁² + 2gh

v₁² = 0 + 2gh

v₁² = 2gh

h = v₁² / 2g

h = (7.2)² / (2 x 9.8)

h = 2.65 m

Throwing ball B; apply the principle of conservation energy for the inelastic collision;

the kinetic energy of the ball will be converted to the potential energy of the target.

¹/₂m₁u₂² = mgh

¹/₂(1.5)(12)² = (5 x 9.8)h

108 = 49h

h = 108 / 49

h = 2.2 m

Ball A will deflect  the target to greater height, thus i will throw ball A.

Answer:

figure d

Explanation:

Given parameters:

Initial velocity  = 0m/s

Acceleration  = 2.857m/s²

Time  = 15.5s

Unknown:

Final speed of the car = ?

Solution:

 We use one of the motion equations to solve this problem;

     V = U + at

  Where V is the final velocity

               U is the initial velocity

               a is the acceleration

                t is the time taken

    V = 0 + 2.857 x 15.5  = 44.28m/s