The surface area of this cube is 384 sq ft.
To find the surface area of this cube:
You can follow these steps:
STEP 1: Identify the number of faces on the cube: A cube has 6 faces.
STEP 2: Determine the area of each face: Each face measures 64 sq ft.
STEP 3: Calculate the surface area: Multiply the area of each face by the total number of faces.
Surface area = (Area of each face) x (Total number of faces)
Surface area = (64 sq ft) x (6)
Surface area = 384 sq ft
The surface area of this cube is 384 sq ft.
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The product if a and b is negative. Decide if each statement about a and b is true or false. Choose true or false for each statement.
Answer: a. true
b. true
c. false
d. true
Step-by-step explanation:
an independent research was made asking people about their bank deposits. using the data in the table, calculate the deposit sample mean and deposit sample standard deviation
To calculate the deposit sample mean, we need to add up all the bank deposits and divide by the number of respondents. From the table, the total bank deposits is $45,000 and there are 10 respondents. So the deposit sample mean is:
Deposit sample mean = Total bank deposits / Number of respondents
Deposit sample mean = $45,000 / 10
Deposit sample mean = $4,500
To calculate the deposit sample standard deviation, we need to first find the differences between each respondent's bank deposit and the sample mean. We then square these differences, add them up, divide by the number of respondents minus one (known as the degrees of freedom), and then take the square root. Here are the steps:
Step 1: Find the differences between each respondent's bank deposit and the sample mean:
Respondent 1: $3,000 - $4,500 = -$1,500
Respondent 2: $5,000 - $4,500 = $500
Respondent 3: $4,500 - $4,500 = $0
Respondent 4: $6,000 - $4,500 = $1,500
Respondent 5: $3,500 - $4,500 = -$1,000
Respondent 6: $5,500 - $4,500 = $1,000
Respondent 7: $6,500 - $4,500 = $2,000
Respondent 8: $4,000 - $4,500 = -$500
Respondent 9: $4,500 - $4,500 = $0
Respondent 10: $4,500 - $4,500 = $0
Step 2: Square each difference:
Respondent 1: (-$1,500)^2 = $2,250,000
Respondent 2: $500^2 = $250,000
Respondent 3: $0^2 = $0
Respondent 4: $1,500^2 = $2,250,000
Respondent 5: (-$1,000)^2 = $1,000,000
Respondent 6: $1,000^2 = $1,000,000
Respondent 7: $2,000^2 = $4,000,000
Respondent 8: (-$500)^2 = $250,000
Respondent 9: $0^2 = $0
Respondent 10: $0^2 = $0
Step 3: Add up the squared differences:
$2,250,000 + $250,000 + $0 + $2,250,000 + $1,000,000 + $1,000,000 + $4,000,000 + $250,000 + $0 + $0 = $11,000,000
Step 4: Divide by the degrees of freedom (number of respondents minus one):
$11,000,000 / 9 = $1,222,222.22
Step 5: Take the square root:
Deposit sample standard deviation = √$1,222,222.22 = $1,105.54
Therefore, the deposit sample mean is $4,500 and the deposit sample standard deviation is $1,105.54.
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Decide if a given function is uniformly continuous on the specified domain. Justify your answers.
Use any theorem listed, or any used theorem must be
explicitly and precisely stated. In your argument, you can use without
proof a continuity of any standard function.
Theorems: Extreme Value Theorem,Intermediate Value Theorem,corollary
The approach to showing uniform continuity will depend on the specific function and domain given.
Without a given function and domain, I cannot provide a specific answer. However, I can provide a general approach to determining whether a function is uniformly continuous on a given domain.
To show that a function is uniformly continuous on a domain, we need to show that for any ε > 0, there exists a δ > 0 such that for any x, y in the domain with |x - y| < δ, we have |f(x) - f(y)| < ε.
One approach to showing uniform continuity is to use the theorem that a continuous function on a closed and bounded interval is uniformly continuous (the Extreme Value Theorem and Corollary). This means that if the domain of the function is a closed and bounded interval, and the function is continuous on that interval, then it is uniformly continuous on that interval.
Another approach is to use the Intermediate Value Theorem. If we can show that the function satisfies the conditions of the Intermediate Value Theorem on the given domain, then we can conclude that the function is uniformly continuous on that domain. The Intermediate Value Theorem states that if f is continuous on a closed interval [a, b], and if M is a number between f(a) and f(b), then there exists a number c in [a, b] such that f(c) = M.
To use the Intermediate Value Theorem to show uniform continuity, we need to show that for any ε > 0, there exists a δ > 0 such that for any x, y in the domain with |x - y| < δ, we have |f(x) - f(y)| < ε/2. Then, using the Intermediate Value Theorem, we can show that for any M such that |M - f(x)| < ε/2, there exists a number c in the domain such that f(c) = M. Combining these two results, we can show that for any ε > 0, there exists a δ > 0 such that for any x, y in the domain with |x - y| < δ, we have |f(x) - f(y)| < ε.
Overall, the approach to showing uniform continuity will depend on the specific function and domain given.
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Find the surface area of the solid formed by the net. Round your answer to the nearest hundredth.
The surface area of the solid formed by the net = 150.72 in²
From the figure we can observe that the solid formed by the net is the net of a cylinder.
The cylinder bases are the 2 circles and the curved surface of the cylinder is the rectangle.
The surface area of the cylinder = Area of the 2 circles + area of the rectangle
Here, the diameter of circle is 4 in
So, the radius of circle = ½ × 4
= 2 in
So, the area of the 2 circles would be,
2(πr²)
= 2 × 3.14 × 2²
= 25.12 in²
Here the width of the rectangle is 10 in. and the length is nothing but the circumference of the circle.
so, length L = πd
= π × 4
= 12.56 in
Now the area of rectangle would be,
L × W
= 12.56 × 10
= 125.6 in²
The total surface area of net would be,
Area of the 2 circles + area of the rectangle
= 25.12 + 125.6
= 150.72 in²
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A number cube is tossed 60 times.
Outcome Frequency
1 12
2 13
3 11
4 6
5 10
6 8
Determine the experimental probability of landing on a number greater than 4.
17 over 60
18 over 60
24 over 60
42 over 60
The experimental probability of rolling a number greater than 4 is 18/60
How to determine the experimental probability?It will be given by the number of times that the outcome was greater than 4 (so a 5 or a 6) over the total number of trials.
We can see that the total number of trials is 60, and we have:
The outcome 5 a total of 10 times.The outomce 6 a total of 8 times.Adding that: 10 + 8 = 18
Then the experimental probability of a number greater than 4 is:
E = 18/60
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Check My Work
The symbol ∪ indicates the _____.
a. sum of the probabilities of events
b. intersection of events
c. sample space
d. union of events
The symbol ∪ represents the "union of events" in the context of probability and set theory.
The symbol ∪ indicates the union of events. This option corresponds to choice (d) in your given list. The union of events refers to the occurrence of at least one of the events in question. In other words, it combines the outcomes of two or more events into a single set, without any repetitions. This concept is essential in understanding probability theory, as it helps to analyze the likelihood of different events happening together or separately.
This means that it represents the set of all outcomes that belong to either one or both of the events being considered. For example, if event A represents rolling an even number on a die and event B represents rolling a number greater than 4, then the union of events A and B would be the set of outcomes {2, 4, 5, 6}. It is important to note that the union of events is different from the intersection of events, which represents the set of outcomes that belong to both events being considered. The sample space, on the other hand, represents the set of all possible outcomes of an experiment. Finally, the symbol ∑ represents the sum of probabilities of events, not the symbol ∪.
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If the daily windows of the last 4 are 1000,1200,1300 and 2000,
it can be concluded that the average sales for that period was:
A) 5,500
B) 1,375
C) 1,200
D) not sufficient information
The average sales for that period is 1375.
The average, also known as the mean, is a statistical measure that represents the central tendency of a set of values. It is calculated by summing up all the values in a dataset and dividing the sum by the total number of values.
Mathematically, the average (mean) is calculated as:
Average = (Sum of all values) / (Total number of values)
To calculate the average sales for the given period, you'll need to follow these steps:
1. Add up the daily sales figures: 1000 + 1200 + 1300 + 2000 = 5500
2. Count the number of days in the period: 4 days
3. Divide the total sales by the number of days to find the average: 5500 / 4 = 1375
So, the average sales for that period is 1375.
Therefore, the correct answer is: B) 1,375
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FInd the surface area.
Answer:
77 cm^2
Step-by-step explanation:
rectangular prism or cuboid
Right rectangular prism Solve for surface area▾
A = 77
L = 2
w = 3
h = 6.5
A=2(wl+hl+hw) = 2.(3.2+6.5.2+6.5.3)=77
chegg
Nearpod
Bolin is taking classes to learn tai chi, a Chinese martial art. The constant of
proportionality between the cost of the classes and the number of classes is 16. What is
the unit rate, in dollars per class, for Bolin's tai chi classes? Use the drop-down menus to
explain your answer.
Click the arrows to choose an answer from each menu.
The constant of proportionality Choose...
relationship. The unit rate for Bolin's tai chi classes is Choose...
Y
equal to the unit rate in a proportional
The constant of proportionality is equal to the unit rate in a proportional relationship. The unit rate for Bolin's tai chi classes is 16.
What is a proportional relationship?In Mathematics and Geometry, a proportional relationship refers to a type of relationship that produces equivalent ratios or unit rates, and it can be modeled or represented by the following mathematical equation:
y = kx
Where:
y represents the number of classes.x represents the cost of the classes.k is the constant of proportionality.What is the unit rate?In Mathematics, the unit rate is sometimes referred to as unit price or unit ratio and it can be defined as the price that is being charged by a seller for the sale of a single unit of product or quantity, especially in a proportional relationship:
Constant of proportionality, k = y/x
Constant of proportionality, k = 16.
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Suppose the final step of a Gauss-Jordan elimination is as follows: 11 0 0 51 0 1 21-3 LO 0 ol What can you conclude about the solution(s) for the system?
We can conclude that the system represented by the given Gauss-Jordan elimination has infinitely many solutions, and the values of the variables can be expressed in terms of a free variable x4.
The Gauss-Jordan elimination is a method used to solve a system of linear equations. The final step of the method is to transform the augmented matrix of the system into reduced row echelon form, which allows for easy identification of the solution(s) of the system.
In the given final step of the Gauss-Jordan elimination, the augmented matrix of the system is represented as:
11 0 0 51
0 1 0 21
0 0 1 -3
0 0 0 0
The augmented matrix is in reduced row echelon form, where the leading coefficients of each row are all equal to 1, and there are no other non-zero elements in the same columns as the leading coefficients. The last row of the matrix corresponds to the equation 0 = 0, which represents an identity that does not provide any new information about the system.
The system represented by this matrix is:
11x1 + 51x4 = 0
x2 + 21x4 = 0
x3 - 3x4 = 0
We can see that the third row of the matrix corresponds to an equation of the form 0x1 + 0x2 + 0x3 + 0x4 = 0, which indicates that the variable x4 is a free variable. This means that the system has infinitely many solutions, and the value of x4 can be chosen arbitrarily.
The values of x1, x2, and x3 can be expressed in terms of x4 using the equations given by the first three rows of the matrix. For example, we can solve for x1 as follows:
11x1 + 51x4 = 0
x1 = -51/11 x4
Similarly, we can solve for x2 and x3:
x2 = -21 x4
x3 = 3 x4
Therefore, the general solution of the system is:
x1 = -51/11 x4
x2 = -21 x4
x3 = 3 x4
x4 is a free variable
In summary, we can conclude that the system represented by the given Gauss-Jordan elimination has infinitely many solutions, and the values of the variables can be expressed in terms of a free variable x4.
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The drawing shown was made on paper and cut out to build a little house. Which of the houses could not have resulted from this construction?
The first image is the little house without being constructed, the other ones are the option answers
Answer: B
Step-by-step explanation:
If you fold that bottom side up. the door is not on the closer side to the window. so B is wrong because the door is near the window.
Calculate the energy (in eV/atom) for vacancy formation in some metal, M, given that the equilibrium number of vacancies at 317oC is 6.67 × 1023 m-3. The density and atomic weight (at 317°C) for this metal are 6.40 g/cm3 and 27.00 g/mol, respectively.
The energy for vacancy formation per atom in the metal M is 0.91 eV/atom.
To calculate the energy (in eV/atom) for vacancy formation in the metal M, we can use the following formula:
E_v = RT * ln(N_v/N)
Where:
- E_v is the energy for vacancy formation per atom
- R is the gas constant (8.314 J/mol*K or 0.008314 eV/mol*K)
- T is the temperature in Kelvin (317°C = 590K)
- N_v is the equilibrium number of vacancies (6.67 × 10^23 m^-3)
- N is the number of atoms per unit volume, which can be calculated using the density and atomic weight of the metal as follows:
N = (6.40 g/cm^3) * (1 mol/27.00 g) * (6.022 × 10^23 atoms/mol) = 1.51 × 10^22 atoms/m^3
Plugging in these values, we get:
E_v = (0.008314 eV/mol*K) * (590 K) * ln(6.67 × 10^23 m^-3 / 1.51 × 10^22 atoms/m^3)
E_v = 0.91 eV/atom
Therefore, the energy for vacancy formation per atom in the metal M is 0.91 eV/atom.
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Suppose a normal distribution has a mean of 34 and a standard deviation of
2. What is the probability that a data value is between 30 and 36? Round your
answer to the nearest tenth of a percent.
OA. 83.9%
OB. 81.9%
OC. 84.9%
O D. 82.9%
The probability that a data value is between 60 and 36 is 95.44%.
We have,
Mean = 34
Standard deviation = 2
So, P( 30 < x < 36)
= P (30 - 34/2) - P(36-34/2)
= P(-2) - P(2)
= 0.9772498 -0.0227501
= 0.9544
= 95.44%
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A survey found that 4 out
of 10 students will work a
summer job. If there are
340 students at the
school, about how many
will work a summer job?
What is the rule for the transformation formed by the translation 8 unitys right and 5 units down followed by a 180 degree rotation
The rule for the composed transformation formed by the translation 8 units right and 5 units down followed by a 180 degree rotation is (x, y) --> (8-x, -5-y)
The rule for the transformation formed by the translation 8 units right and 5 units down followed by a 180-degree rotation can be determined by considering the effect of each transformation separately and then composing them.
First, let's consider the effect of the translation. A translation moves every point in the plane a certain distance in a certain direction. In this case, we are translating 8 units to the right and 5 units down. So, if we have a point (x, y), the translated point will be (x+8, y-5).
Next, let's consider the effect of the 180-degree rotation. A rotation of 180 degrees flips a figure around a line of symmetry, which in this case would be the point where the horizontal line passing through the midpoint of the translation intersects the vertical line passing through the midpoint of the translation. This point is (4, -2.5).
Thus, if we start with a point (x, y), the effect of the translation is to move it to (x+8, y-5), and the effect of the rotation is to flip it around the point (4, -2.5). Therefore, the rule for the composed transformation is:
(x, y) --> (x+8, y-5) --> (8-x, -5-y)
In other words, to apply this transformation to a point, we first translate it 8 units right and 5 units down, and then we reflect it across the point (4, -2.5).
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Complete question is:
What is the rule for the transformation formed by the translation 8 unitys right and 5 units down followed by a 180 degree rotation , assuming the initial point as (x,y)?
There are 6 bands playing in a battle of the bands. 4 of the bands have a female lead vocalist. What is the ratio of
bands that have a female lead vocalist to bands competing?
What is the rule for the transformation formed by the translation 8 units rght and 5 units down followed by a 180 degree rotation
The translating point will be (x, y) --> (8-x, -5-y).
We have to translate a point 8 units right and 5 units down followed by a 180 degree rotation.
Now, the rule for 180 rotation is
(x, y) --> (x, -y)
and, to shift 8 unit right apply (8-x)
and, to shift 5 unit down apply (5-y)
Then, the translating point will be (x, y) --> (8-x, -5-y).
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Problem 83 please help me
The rule for the nth term of the geometric sequence is given as follows:
[tex]a_n = 2^n[/tex]
Hence the 10th term of the sequence is given as follows:
1024.
What is a geometric sequence?A geometric sequence is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed number called the common ratio q.
The explicit formula of the sequence is given as follows:
[tex]a_n = a_0q^{n}[/tex]
In which [tex]a_0[/tex] is the first term.
The parameters in this problem are given as follows:
First term of 1.Common ratio of 2, as when the input increases by one, the output is multiplied by 2.Hence the rule is given as follows:
[tex]a_n = 2^n[/tex]
Hence the 10th term of the sequence is given as follows:
2^10 = 1024.
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The pdf of X is f(x) = 0.2, 1< x < 6.
(a) Show that this is a pdf(probability distribution function)
(b) Find the cdf F(x).
(c) Find P(2
(d) Find P(X>4).
(a) The function f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf) because it is non-negative for all x in its domain and the total area under the curve is equal to 1.
(b) The cumulative distribution function (cdf) F(x) for 1 < x < 6 is given by F(x) = 0.2(x-1), where F(x) = 0 for x ≤ 1 and F(x) = 1 for x ≥ 6.
(c) The probability P(2 < X < 4) is 0.4, which can be calculated by integrating the pdf f(x) = 0.2 over the interval [2, 4].
(d) The probability P(X > 4) is 0.6, which is obtained by subtracting the cumulative probability F(4) = 0.2(4-1) from 1.
(a) To show that f(x) = 0.2, 1 < x < 6 is a probability distribution function (pdf), we need to show that:
f(x) is non-negative for all x in its domain: f(x) = 0.2 is non-negative for all x between 1 and 6.
The total area under the curve of f(x) is equal to 1:
∫1^6 0.2 dx = 0.2(x)|1^6 = 0.2(6-1) = 1
Since both conditions are satisfied, f(x) is a pdf.
(b) The cumulative distribution function (cdf) F(x) is given by:
F(x) = ∫1^x f(t) dt
For 1 < x < 6, we have:
F(x) = ∫1^x 0.2 dt = 0.2(t)|1^x = 0.2(x-1)
For x ≤ 1, F(x) = 0, and for x ≥ 6, F(x) = 1.
(c) P(2 < X < 4) is given by:
P(2 < X < 4) = ∫2^4 f(x) dx = ∫2^4 0.2 dx = 0.2(x)|2^4 = 0.4
(d) P(X > 4) is given by:
P(X > 4) = 1 - P(X ≤ 4) = 1 - F(4) = 1 - 0.2(4-1) = 0.6
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What is the domain of the function in the graph?
The domain of the function shown in the graph is the one in option A:
6 ≤ k ≤ 11
What is the domain of the function in the graph?The domain of a function y = f(x) is the set of the inputs of the function. To identify the domain in a graph, we need to look at the horizontal axis (also called the x-axis).
On the graph we can see that it starts at x = 6 with a closed dot, and it ends at x = 11 also with a closed dot.
That means that these values belong to the domain, so we can write the domain as follows:
Domain = 6 ≤ k ≤ 11
(notice that the variable in the horizontal axis is k).
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A potato chip manufacturer produces bags of potato chips that are supposed to have a net weight of 326 grams. Because the chips vary in size, it is difficult to fill the bags to the exact weight desired. However, the bags pass inspection so long as the standard deviation of their weights is no more than 4 grams. A quality control inspector wished to test the claim that one batch of bags has a standard deviation of more than 4 grams, and thus does not pass inspection. If a sample of 27 bags of potato chips is taken and the standard deviation is found to be 5.3 grams, does this evidence, at the 0.05 level of significance, support the claim that the bags should fail inspection? Assume that the weights of the bags of potato chips are normally distributed.
Step 2 of 3: Compute the value of the test statistic. Round your answer to three decimal places.
The evidence at the 0.05 level of significance contradict claim that the bags should fail inspection.
We can use a one-tailed test with the null hypothesis that the standard deviation of the bags' weights is no more than 4 grams and the alternative hypothesis that the standard deviation is greater than 4 grams.
The test statistic for this hypothesis test is given by:
t = [tex]\frac{\frac{s}{\sqrt{n}}}{\frac{sigma}{\sqrt{n}}}[/tex]
where s is the sample standard deviation, n is the sample size, and sigma is the population standard deviation (which is assumed to be 4 grams).
Plugging in the given values, we get:
t = [tex]\frac{\frac{5.3}{\sqrt{27}}}{\frac{4}{\sqrt{ 27}}}[/tex] ≈ 1.325
Using a t-distribution table with 26 degrees of freedom (since we have a sample size of 27 and are estimating the population standard deviation), we can find the critical value for a one-tailed test at the 0.05 level of significance. The critical value is 1.705.
Since our calculated test statistic (1.325) is less than the critical value (1.705), we can support the null hypothesis and conclude that the bags of potato chips will not fail inspection.
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Find the area of polygon A
A: 4
B: 160
C: 80
D: 20
Cases of UFO sightings are randomly selected and categorized according to season, with the results listed in the table. Use a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table. Find the test statistic x² needed to test the claim.
A.11.472
B.11.562
C.2,212.556
D.7.815
Answer: D.
Step-by-step explanation:
Using a 0.05 significance level to test a claim that UFO sightings occur in different seasons with the proportions listed in the table the test statistic x² needed to test the claim is 11.562. The correct option is B.
To test the claim that UFO sightings occur in different seasons with the proportions listed in the table, we can use a chi-square goodness-of-fit test.
The null hypothesis is that the observed frequencies in each season are equal to the expected frequencies based on the proportions listed in the table.
The expected frequency for each season can be calculated by multiplying the total number of sightings by the proportion listed in the table. For example, the expected frequency for spring is:
Expected frequency for spring = Total number of sightings × Proportion for spring
= 420 × 0.25
= 105
Similarly, the expected frequencies for summer, fall, and winter are 126, 210, and 105, respectively.
The chi-square test statistic can be calculated as:
χ² = ∑ [(O - E)² / E]
where O is the observed frequency and E is the expected frequency.
Using the observed frequencies from the table and the expected frequencies calculated above, we get:
χ² = [(150-105)²/105] + [(120-126)²/126] + [(100-210)²/210] + [(50-105)²/105]
= 11.562
The degrees of freedom for the chi-square test is (number of categories - 1), which in this case is 4 - 1 = 3.
Using a chi-square distribution table with 3 degrees of freedom and a significance level of 0.05, the critical value is 7.815.
Since the calculated chi-square value (11.562) is greater than the critical value (7.815), we reject the null hypothesis and conclude that there is evidence of a difference in UFO sightings across seasons. Therefore, the test statistic x² needed to test the claim is 11.562.
The correct answer is (B) 11.562.
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At your local store, you are given a coupon for 20% off any store item purchased on Monday. When you return to your store, you notice that an item (normal price = $50) is on clearance for 40% off. You are allowed to use the coupon on the clearance item. How much should you pay for the item? Should it be 60% off of the normal price? Explain why or why not, justify your reason quantitatively.
The 40% clearance discount is already factored into the clearance price of $30, so applying the 20% coupon only reduces the price further by 20% of $30, or $6. Therefore, you would pay $24 for the item with both discounts applied.
Let's break down the discounts and calculate the final price of the item using the terms "normal", "price", and "quantitatively".
The normal price of the item: $50
First, apply the 40% clearance discount:
40% off the normal price = 0.4 * $50 = $20
Subtract the clearance discount from the normal price:
New discounted price = $50 - $20 = $30
Now, apply the 20% off coupon to the discounted price:
20% off the new discounted price = 0.2 * $30 = $6
Quantitatively, the calculation would be:
Normal price = $50
Clearance price (40% off) = $30
Coupon discount (20% off clearance price) = 0.20 x $30 = $6
Final price = $30 - $6 = $24
Subtract the coupon discount from the discounted price:
Final price = $30 - $6 = $24
So, you should pay $24 for the item. It is not the same as taking 60% off the normal price because the discounts are applied sequentially, not combined. Quantitatively, you can see that taking 60% off the normal price would result in a $30 discount ($50 * 0.6), while the actual total discount here is $26 ($20 + $6).
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Assume that blood pressure readings are normally distributed with a mean of 11 and a standard deviation of 4.7. If 35 people are randomly selected, find the probability that their mean blood pressure will be less than 122.
A. 0.0059
B. 0.9941
C. 0.8219
D. 0.6648
The answer is not one of the choices provided.
The distribution of sample means follows a normal distribution with a mean equal to the population mean (11) and a standard deviation equal to the population standard deviation divided by the square root of the sample size.
So, for a sample size of 35, the distribution of sample means is normal with a mean of 11 and a standard deviation of 4.7/sqrt(35) = 0.795.
We need to find the probability that the mean blood pressure of the 35 people will be less than 122. We can standardize the distribution of sample means to a standard normal distribution with mean 0 and standard deviation 1 using the z-score formula:
z = (x - mu) / (sigma / sqrt(n))
where x is the sample mean, mu is the population mean, sigma is the population standard deviation, and n is the sample size.
Substituting the given values, we get:
z = (122 - 11) / (4.7 / sqrt(35)) = 37.98
We can then use a standard normal distribution table or calculator to find the probability of z being less than 37.98. Since the standard normal distribution is symmetric, we can also find this probability as 1 minus the probability of z being greater than 37.98.
Using a standard normal distribution table or calculator, we get:
P(z < 37.98) = 1 (to a very high degree of precision)
Therefore, the probability that the mean blood pressure of 35 people will be less than 122 is essentially 1, or 100%. The answer is not one of the choices provided.
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An angle measures 83.6° more than the measure of its complementary angle. What is the measure of each angle?
The angle is 86.8 degrees and its complement is 3.2 degrees.
let x be the angle and y be the Complementary angle.
If the angles are complementary, then their sum is 90 degrees.
x + y = 90................(1)
and, the angle measures 83.6 degrees more than its complement.
x = y + 83.6
y + 83.6 + y = 90
Solving the equation for y we get
2y + 83.6 = 90
2y = 90 - 83.6
2y = 6.4
y= 3.2
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an integral equation is an equation that contains an unknown function y(x) and an integral that involves y(x). solve the given integral equation. [hint: use an initial condition obtained from the integral equation.] y(x) = 2 + x [t − ty(t)] dt 8
The solution to the integral equation y(x) = 2 + x [t − ty(t)] dt is: y(x) = 1 + e⁻ˣ
Note that this solution satisfies the initial condition y(0) = 2.
To solve the given integral equation y(x) = 2 + x [t − ty(t)] dt, we need to first find the value of y(x) that satisfies this equation. We can obtain an initial condition for y(x) by setting x=0 in the equation and solving for y(0). Then, we can use a method such as separation of variables or substitution to find the general solution for y(x).
Let's start by finding the initial condition for y(x). Setting x=0 in the integral equation, we get:
y(0) = 2 + 0 [t − t y(t)] dt
y(0) = 2
So, we know that y(0) = 2. This will be useful when we find the general solution for y(x).
Now, let's use substitution to solve the integral equation. Let u = y(x), du/dx = y'(x), and v = t - y(t). Then, we have:
y(x) = 2 + x [t − ty(t)] dt
u = 2 + x [v] dt
du/dx = v + x dv/dx
Substituting du/dx and v in terms of u and x, we get:
v = t - u
du/dx = t - u + x (dv/dx)
du/dx + u = t + x (dv/dx)
We can use the integrating factor method to solve this first-order linear differential equation. The integrating factor is eˣ, so we have:
eˣ du/dx + eˣ u = teˣ + x eˣ (dv/dx)
(d/dx)(eˣ u) = (teˣ)' = eˣ
eˣ u = eˣ + C
u = 1 + Ce⁻ˣ
Substituting u = y(x) and using the initial condition y(0) = 2, we get:
y(x) = 1 + Ce⁻ˣ (general solution)
y(0) = 2 = 1 + C (using initial condition)
C = 1
Therefore, the solution to the integral equation y(x) = 2 + x [t − ty(t)] dt is:
y(x) = 1 + e⁻ˣ
Note that this solution satisfies the initial condition y(0) = 2.
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Which of the following modifications to a research study will result in a narrower confidence interval?Group of answer choicesA) increasing the confidence level, decreasing the sample sizeB) increasing the confidence level, increasing the sample sizeC) decreasing the confidence level, decreasing the sample sizeD) decreasing the confidence level, increasing the sample size
The modification to a research study that will result in a narrower confidence interval is option D is correct choice
The modification to a research study that will result in a narrower confidence interval is option D: decreasing the confidence level and increasing the sample size. By decreasing the confidence level, we are willing to accept a lower level of certainty in our results, which can lead to a narrower interval. Increasing the sample size also leads to a narrower interval as it reduces the variability in our data and increases the precision of our estimates.
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Pls help!!
Geometry
(Look at photo)
The value of x is determined as 1.
What is the value of x?
The value of x is calculated by applying the principle of similar triangles.
length SR ≅ length ST
length TU ≅ length RU
We will have the following equation, to solve for the value of x;
TU/SU = RU/SU
TU = RU
x + 9 = 10x
9 = 10x - x
9 = 9x
9/9 = xy
1 = x
Thus, the value of x is calculated by applying the principle of similar triangle.
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Haematuria + frequency + dysuria what is the diagnosis and investigations?