Answer:
6
Step-by-step explanation:
12
-3
----
9 divided by 1.50= 6
Kenya buy 6 candy bars.
What is Unitary Method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
for example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Give:
Kenya spent a total of $12.00 on soda and candy.
The soda cost $3.00 and each candy bar cost $1.50.
Now, Money left after spending on Candy
= 12- 3
= $9
Now, number of candy bars Kenya buy is
= 9/ 1.50
= $6
Hence, Kenya buy 6 candy bars.
Learn more about Unitary Method here:
https://brainly.com/question/22056199
#SPJ2
Solve: x^2=10
A) x= +5
B) x= +100
C) x= +3.5
D) x= 10 squared
Answer:
D) x=√10
Step-by-step explanation:
√(10)=3.16(approximately )
Help with this one please
Answer:
(3x - 14) (2x - 7)
I hope this helps!
What is the answer for number 12
Th e expert trail is 750 meters longer than the beginner trail. How long is each trail?
do they give the whole amount of both trails together? then someone would be able to answer this so pls add that
Paul and Seth know that one point on the line
Answer:
what
Step-by-step explanation:
he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size required to estimate the mean pulse rate of adult males. Assume that we want 90% confidence that the sample mean is within 3 bpm of the population mean. Complete parts (a) through (c) belo
Answer:
97
Step-by-step explanation:
Given that:
Low = 43bpm
High = 115 bpm
Error = 3
α = 90%
To find the range estimate :
Standard destviation = (high - low) / 4
Standard deviation = (115 - 43) / 4
Standard deviation = 72/4 = 18
The sample size,(n) :
n = [(Zα/2 * sd)/E] ²
2 - tail = (Zα/2) = 1.645
[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²
= 97.41
Sample size = 97
1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following situations:
a) H1:μ>μ0,z=1.88
b) H1:μ<μ0,z=−2.75
c) H1:μ≠μ0,z=2.88
2. Let the test statistics T have t distribution when H0 is true. Find the p-value for each of the following situations (provide an interval if the exact one cannot be found using a table):
a) H1:μ>μ0,n=16,t=3.733
b) H1:μ<μ0,df=23,t=−2.500
c) H1:μ≠μ0,n=7,t=−2.250
Answer:
1 a [tex]p -value = 0.030054[/tex]
1b [tex]p -value = 0.0029798[/tex]
1c [tex]p -value = 0.0039768[/tex]
2a [tex]p-value = 0.00099966[/tex]
2b [tex]p-value = 0.00999706[/tex]
2c [tex]p-value = 0.0654412[/tex]
Step-by-step explanation:
Considering question a
The alternative hypothesis is H1:μ>μ0
The test statistics is z =1.88
Generally from the z-table the probability of z =1.88 for a right tailed test is
[tex]p -value = P(Z > 1.88) = 0.030054[/tex]
Considering question b
The alternative hypothesis is H1:μ<μ0
The test statistics is z=−2.75
Generally from the z-table the probability of z=−2.75 for a left tailed test is
[tex]p -value = P(Z < -2.75) = 0.0029798[/tex]
Considering question c
The alternative hypothesis is H1:μ≠μ0
The test statistics is z=2.88
Generally from the z-table the probability of z=2.88 for a right tailed test is
[tex]p -value = P(Z >2.88) = 0.0019884[/tex]
Generally the p-value for the two-tailed test is
[tex]p -value = 2 * P(Z >2.88) = 2 * 0.0019884[/tex]
=> [tex]p -value = 0.0039768[/tex]
Considering question 2a
The alternative hypothesis is H1:μ>μ0
The sample size is n=16
The test statistic is t = 3.733
Generally the degree of freedom is mathematically represented as
[tex]df = n - 1[/tex]
=> [tex]df = 16 - 1[/tex]
=> [tex]df = 15[/tex]
Generally from the t distribution table the probability of t = 3.733 at a degree of freedom of [tex]df = 15[/tex] for a right tailed test is
[tex]p-value = t_{3.733 , 15} = 0.00099966[/tex]
Considering question 2b
The alternative hypothesis is H1:μ<μ0
The degree of freedom is df=23
The test statistic is ,t= −2.500
Generally from the t distribution table the probability of t= −2.500 at a degree of freedom of df=23 for a left tailed test is
[tex]p-value = t_{-2.500 , 23} = 0.00999706[/tex]
Considering question 2c
The alternative hypothesis is H1:μ≠μ0
The sample size is n= 7
The test statistic is ,t= −2.2500
Generally the degree of freedom is mathematically represented as
[tex]df = n - 1[/tex]
=> [tex]df = 7 - 1[/tex]
=> [tex]df = 6[/tex]
Generally from the t distribution table the probability of t= −2.2500 at a degree of freedom of [tex]df = 6[/tex] for a left tailed test is
[tex]t_{-2.2500 , 6} = 0.03272060[/tex]
Generally the p-value for t= −2.2500 for a two tailed test is
[tex]p-value = 2 * 0.03272060 = 0.0654412[/tex]
Please help with this easy fraction problem <3
18 + 7/9
14 + 7/8
First, rewrite each fraction in terms of a common denominator. 8 and 9 don't share a common multiple until 8 * 9 = 72, so we have
7/9 = (7/9) • (8/8) = (7 • 8)/(9 • 8) = 56/72
7/8 = (7/8) • (9/9) = (7 • 9)/(8 • 9) = 63/72
Next, write each whole number in terms of fractions with the same denominator. We have
18 • 72 = 1296 ==> 18 = 1296/72
14 • 72 = 1008 ==> 14 = 1008/72
Write each mixed number as an improper fraction:
18 + 7/9 = 1296/72 + 56/72 = (1296 + 56)/72 = 1352/72
14 + 7/8 = 1008/72 + 63/72 = (1008 + 63)/72 = 1071/72
If the backpack and book together weigh 18 + 7/9 pounds, and the backpack without the book weighs 14 + 7/8 pounds, then the book alone weighs the difference, call it b :
b = (18 + 7/9) - (14 + 7/8)
b = 1352/72 - 1071/72
b = (1352 - 1071)/72
b = 281/72
Convert this to a mixed number. 72 • 4 = 288, so 72 • 4 - 7 = 281:
b = (72 • 4 - 7)/72
b = (72 • 4)/72 - 7/72
b = 4 - 7/72
b = (3 + 1) - 7/72
b = 3 + (1 - 7/72)
b = 3 + 65/72
Manuel can walk 5 miles In one hour. At this rate, how many miles can he walk in 8 minutes? Round to the nearest tenth
Answer:0.6666664
Step-by-step explanation:
You take 5 and divide by 60. Then multiply by 8.
2/3 of a mile.
If he can walk 5 MILES a hour, lets use 5/60.
Multiply 5/60 by 8 since each minute he travels 5/60 of a MILE.
You get 0.66(repeating) OR 2/3
What is the opposite of the opposite of -1.4?
Answer:
-1.4
Step-by-step explanation:
opposite of -1.4 = 1.4
opposite of the opposite of -1.4 = the opposite of 1.4 = -1.4
Caleb and Emily are standing 100 yards from each other. Caleb looks up at a 45° angle to see a hot air balloon. Emily looks up at a 60° angle to see the same hot air balloon. Approximately how far is the hot air balloon off the ground?
a) 44.3 yd.
b) 63.4 yd.
c) 73.2 yd.
d) 89.7 yd.
Answer:
B. 63.4 yards.
Step-by-step explanation:
A journalist interviews 123 people after they leave a restaurant and asks them how confident they are that the food is safe.
Answer:
what do I need to do to answer
Step-by-step explanation:
At a school, there are 120 athletes. The ratio of boy athletes to giri athletes is 3:5. How many of the athletes are girls?
А
75
B
45
с
24
D 5
Answer:
a
Step-by-step explanation:
because there are over half girls and half of 120 is 60 and 75 is over half
15 tens 7 ones what is the answer?
Answer:
157
Step-by-step explanation:
Answer: 15 tens and 7 ones in standard form would be 157. If you have 15 tens this means that you are adding 10, 15 times or multiplying 10 by 15, which gives you 150.
Step-by-step explanation: Hopefully this helped!
The set A = {1, 3, 5}. What is a larger set this might be a subset of?
Answer:
Step-by-step explanation:
A larger set that a particular set can be a subset of is a Universal set. A universal set is parent where all other sets are derived from.
For example, given a universal set U = {1,2,3,4,5}, a set A = {1, 3, 5} is said to be a subset of the set U because the elements of set B are contained in the Universal set U.
Also, sets like {1, 4,5} and {3,4,5} can also be regarded as the subset of U since all the elements of the sets can be found in the Universal set U. Hence the correct name of the set is a UNIVERSAL SET
So, the number of maximum subsets we can create from the given set is 8.
Subsets:The subsets of any set consists of all possible sets including its elements and the null set. Let us understand with the help of an example.
Example: Find all the subsets of set A = {1,2,3,4}
Solution: Given, A = {1,2,3,4}
Subsets =
The subsets of any set consisting of all possible sets including its elements and the null set. Let us understand with the help of an example.
Example: Find all the subsets of set A = {1,2,3,4}
{}
{1}, {2}, {3}, {4},
{1,2}, {1,3}, {1,4}, {2,3},{2,4}, {3,4},
{1,2,3}, {2,3,4}, {1,3,4}, {1,2,4}
{1,2,3,4}
So, the formula is [tex]2^n[/tex].
The given set is,
[tex]A = \{1, 3, 5\}[/tex]
Here the number of an element is 3.
So, the maximum number of subsets we can create is,
[tex]2^n=2^3=8[/tex]
Learn more about the topic Subsets:
https://brainly.com/question/17514113
Hannah wants to buy a $460 camera. She can save $35 each week from her paycheck. However, before Hannah can buy the camera, she must give her brother $65 that she owes him. For how many weeks will Hannah need to save before she can pay back her and buy the camera?
Answer:
460+65=525/35=15 15 weeks
Julie earned $130 one week and $125.50 the next week. After depositing these amounts in her account, she had a total of $335.
How much was already in her account before she deposited the $130 and $125.50?
Answer:
she had more than me
Step-by-step explanation:
Answer: $79.50
Step-by-step explanation:
Add together $130 and $125.50 to find out how much she deposited.
$130+125.50=$255.50
Now subtract the amount that was deposited from the total amount in her account.
$335−$255.50=$79.50
Statistical significance at the 0.01 level is __________ than significance at the 0.05 level .
a. less informative
b. more difficult to achieve
c. easier to achieve
d. less costly
Answer:
d. less costly
Step-by-step explanation:
Statistical significance level is the probability of rejecting the null hypothesis. Statistical significance at the 0.05 level is the standard level for rejecting the null hypothesis.
A significance of 0.01 shows that there is strong evidence to conclude that the null hypothesis is not true. A 0.05 significance is the most used level while 0.01 is used when multiple tests are conducted or when the researcher is not so sure if the null hypothesis should be rejected. It increases the amount of evidence required to prove the null hypothesis and it also reduces the possibility of obtaining a false positive.
What kind of lines are shown?
Answer:
vertical and horizontal
Can you please simplify c5 x c
Answer:
5c^2
Step-by-step explanation:
i think c is a variable so,
5xcxc = 5c^2
What value of a will make the following equation true?
Answer:
a=16
Step-by-step explanation:
Answer:
A=4
Step-by-step explanation:
Question Help When purchasing bulk orders of batteries, a toy manufacturer uses this acceptance sampling plan: Randomly select and test 36 batteries and determine whether each is within specifications. The entire shipment is accepted if at most 2 batteries do not meet specifications. A shipment contains 3000 batteries, and 3% of them do not meet specifications. What is the probability that this whole shipment will be accepted? Will almost all such shipments be accepted, or will many be rejected?
Answer:
The probability is [tex]P(X \le 2 ) = 0.9072[/tex]
The company will accept 90.72% of the shipment and will reject [tex](100 -90.72) = 9.2\%[/tex] of the shipment , so many of the shipment are rejected
Step-by-step explanation:
From the question we are told that
The sample size is n = 36
The proportion that did not meet the requirement is [tex]p = 0.03[/tex]
Generally the probability that the whole shipment is accepted is equivalent to the probability that there is at most 2 batteries that do not meet the requirement , this is mathematically represented as
[tex]P(X \le 2 ) = [ P(X = 0 ) + P(X = 1 ) + P(X = 0)][/tex]
=> [tex]P(X \le 2 ) = [ [^{n}C_0 * (p)^{0} *(1-p)^{n-0} ] + [^{n}C_1 * (p)^{1} *(1-p)^{n-1} ] + [^{n}C_2 * (p)^{2} *(1-p)^{n-2} ]][/tex]
Here C stands for Combination (so we will be making the combination function in our calculators )
So
=> [tex]P(X \le 2 ) = [ [^{36}C_0 * (0.03)^{0} *(1-0.03)^{36-0} ] + [^{36}C_1 * (0.03)^{1} *(1-0.03)^{36-1} ] + [^{36}C_2 * (0.03)^{2} *(1-0.03)^{36-2} ]][/tex]
=> [tex]P(X \le 2 ) = [ [1 * 1 * 0.3340 ] + [36* 0.03 *0.3444 ] + [630 * 0.0009 *(0.355 ]][/tex]
=>[tex]P(X \le 2 ) = 0.9072[/tex]
The company will accept 90.72% of the shipment and will reject [tex](100 -90.72) = 9.2\%[/tex] of the shipment , so many of the shipment are rejected
Will give brainliest if correct what is the discriminant of the quadratic equation: (multiple choice)
I need help with a math problem comment if u want i really need help with this
Gwendolyn was physically present in the United States for 96 days in 2019, 198 days in 2018, and 66 days in 2017. Under the substantial presence test formula, how many days is Gwendolyn deemed physically present in the United States in 2019 g
Answer:
173 days
Step-by-step explanation:
The formula for substantial presence test is;
SBT = (Total of number of days present in the current tax year) + (1/3)(number of days in the year that was before the tax year) + (1/6)(number of days in the year that was two years before the tax year)
From the question, present tax year is 2019 and number of days is 96 days.
Year before tax year is 2018 and number of days is 198 days
2 years before tax year is 2017 and number of days is 66 days.
Thus;
SBT = 96 + ((1/3)198) + ((1/6)66)
SBT = 173 days
PLEASE HELP
For spirit week at a local high school, students were encouraged to wear their school colors of green and white. 1,200 students wore their school colors while 300 students did not wear green and white. What percent of the school population did NOT wear their school colors?
Here are the answer choices
A.
15%
B.
20%
C.
25%
D.
33%
Answer:
C. 25% The correct answer is C. 300 divided by 1200 equals 25%.
Step-by-step explanation:
Answer:
B.) 20%
Step-by-step explanation:
First, add 1,200 and 300. That gives you 1,500. You want to find how much percent of 1,500 equals 300, and that is 20%.
The temperature at 6 a.m. was −12°F. At 11 a.m. the temperature was 0°F. Which of the following shows the temperature change from 6 a.m. to 11 am?
Answer:
+12 degrees
Step-by-step explanation:
You never showed a picture, but im pretty sure this is correct
I hope this helped, please mark Brainliest, thank you!
Why do we study?give me reason
Answer:
Simple to help us improve our lives
Answer:
To do good in school
Step-by-step explanation:
the thing is teachers want us to study so we remember whatever is on the test for an example and that is good but not alt of people always study.
The mean and standard deviation of a random sample of n measurements are equal to and , respectively. a. Find a % confidence interval for if n. b. Find a % confidence interval for if n. c. Find the widths of the confidence intervals found in parts a and b. What is the effect on the width of a confidence interval of quadrupling the sample size while holding the confidence coefficient fixed?
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]33.55 < \mu < 35.5[/tex]
b
[tex]34.03 < \mu < 34.969 [/tex]
c
Generally the width at n = 49 is mathematically represented as
[tex]w = 2 * E[/tex]
[tex]w = 2 * 0.952 [/tex]
[tex]w = 1.904 [/tex]
Generally the width at n = 196 is mathematically represented as
[tex]w = 2 * E[/tex]
[tex]w = 2 * 0.4687 [/tex]
[tex]w = 0.9374 [/tex]
d
The correct option is E
Step-by-step explanation:
From the question we are told that
The sample mean is [tex]\= x = 34.5[/tex]
The standard deviation is [tex]s = 3.4[/tex]
Generally given that the confidence level is 95% then the level of significance is
[tex]\alpha = (100 - 95)\%[/tex]
=> [tex]\alpha = 0.05 [/tex]
Generally from the normal distribution table the critical value of [tex]\frac{\alpha }{2}[/tex] is
[tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]
Considering question a
From the question n = 49
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{s }{\sqrt{n} }[/tex]
=> [tex]E = 1.96* \frac{ 3.4 }{\sqrt{49} }[/tex]
=> [tex]E = 0.952 [/tex]
Generally 95% confidence interval is mathematically represented as
[tex]\= x -E < p < \=x +E[/tex]
[tex]34.5 -0.952 < p < 34.5 + 0.952[/tex]
=> [tex]33.55 < \mu < 35.5[/tex]
Considering question b
From the question n = 196
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{s }{\sqrt{n} }[/tex]
=> [tex]E = 1.96* \frac{ 3.4 }{\sqrt{196} }[/tex]
=> [tex]E = 0.4687 [/tex]
Generally 95% confidence interval is mathematically represented as
[tex]\= x -E < p < \=x +E[/tex]
[tex]34.5 -0.4687 < p < 34.5 +0.4687[/tex]
=> [tex]34.03 < \mu < 34.969 [/tex]
Considering question c
Generally the width at n = 49 is mathematically represented as
[tex]w = 2 * E[/tex]
[tex]w = 2 * 0.952 [/tex]
[tex]w = 1.904 [/tex]
Generally the width at n = 196 is mathematically represented as
[tex]w = 2 * E[/tex]
[tex]w = 2 * 0.4687 [/tex]
[tex]w = 0.9374 [/tex]
Now when the sample size is quadrupled i.e from n = 49 to n = 196
The width of the confidence interval decrease by 2 from 1.904 to 0.9374
7 days left until launch of products with $668 left in budget. Need to spend $85 on last day. How many dollars do we spend on remaining days?
Answer:
In total, you have $668.00.
To reserve enough for the last day, you need to subtract the last day's budget:
This means that, for the remaining 6 days in the week, you have $583.00.
Assuming an equal amount is being spent each day, you can calculate the daily budget by dividing the remaining total by the number of days left.
To avoid going over budget, you can spend $97.16 per day for the other six days.
Hope this helps!
Step-by-step explanation: