Answer:
It is the third one
Step-by-step explanation:
Answer:
3 x 26 = 78
Step-by-step explanation:
It's quite simple, when you look at the problem, it states Juan at 26 carrots. Carmen on the other hand ate 3 times as much. For the answer choices, they put Carmen's 3 first and Juan's 26 second.
The cost of 2 bunches of
roses and 5 bunches of
carnations is £45.
The cost of 3 bunches of
roses and 4 bunches of
carnations is £50.
Find the cost of one bunch of each
Answer:
vtdOveractivity of the pituitary gland is called hyperpituitarism. Several disorders related to an overactive pituitary gland can occur.
...
Symptoms may include:
Nervousness.Rapid or irregular heartbeat.Weight loss.Fatigue.Muscular weakness.
Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air:
The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
The given parameters;
distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hoursLet the rate of the jet in still air = R₁
Let the rate of the wind = R₂
The rate of the jet against the wind:
[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]
The rate of the jet with the wind:
[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]
The rate of the jet in still air is calculated as follows;
[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]
The rate of the wind is calculated as follows;
[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]
Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
Learn more about rate here:https://brainly.com/question/11664428
6^3 multiplied by (1/2)^3
Step-by-step explanation:
6³×(½)³
=> 216÷8 = 27.
hope this helps you.
i need help on this math problem
Answer:
Step-by-step explanation:
Slope: 3/1 (positive: line go uphill)
y-intercept: -5
Place your pencil on the vertical line (y) on -5. Go up 3 units and 1 to the right, repeat and trace the line (actually you only need two points to trace a line)
The graph of a linear function has a negative slope. Describe the end behavior of this function.
As the value of x increases, the value of y [ A. decreases , B. increases ].
As the value of x decreases, the value of y [ A. decreases , B. increases ].
Answer:
1. A
2. B
Step-by-step explanation:
It would look like y = -m(x) + b.
For example, m is 1 and b is 0. (You can try any random numbers, but I tried to find the simplest one so it's easy for us to see.) The equation will be y= -x. (you can substitute random numbers in here, too)
If x = 3, y = -3 ; x = 5, y = -5 (x increases, y decreases)
If x = -1, y = 1 ; x = -5, y = 5 (x decreases, y increases)
As you can see from the example,
If the value of x increases, the value of y will decrease and vice versa
For the negative slope equation y = -x as the value of x increases y decreases.
What is a slope?Slope or the gradient is the number or the ratio which determines the direction or the steepness of the line.
Given that the graph of a linear function has a negative slope. Suppose the equation with a negative slope is y = -x.
It would look like y = -m(x) + b.
As an illustration, m is 1 and b is 0. (You can try any random number; however, I looked for the most straightforward one so that we could easily observe it.) It will be written as y=-x. (You can also omit this and use random numbers)
If x = 3, y = -3 ; x = 5, y = -5 (x increases, y decreases)
If x = -1, y = 1 ; x = -5, y = 5 (x decreases, y increases)
Therefore, for the negative slope equation y = -x as the value of x increases y decreases.
To know more about slopes follow
https://brainly.com/question/3493733
#SPJ2
The equilateral triangle with side 12 has altitude
2 - 2x 4x + 12
------- = ---------
4 3
[tex]\tt\frac { 2 - 2 x } { 4 } = \frac { 4 x + 12 } { 3 }[/tex]
[tex]\tt3\left(2-2x\right)=4\left(4x+12\right) [/tex]
[tex]\tt6-6x=16x+48 [/tex]
[tex]\tt6-6x-16x=48 [/tex]
[tex]\tt6-22x=48 [/tex]
[tex]\tt-22x=42 [/tex]
[tex]\tt\:x=\frac{42}{-22} [/tex]
[tex]\boxed{\tt\:x = -\frac{21}{11} = -1\frac{10}{11} \approx -1.90}[/tex]
Method used :-
◇ ✖ Cross multiplication ❌
________
Hope it helps ⚜
Step-by-step explanation:
Given equation is [{(2-2x)/4} = {(4x+12)/3]
On applying cross multiplication then
Since, (a/b) = (c/d)
⇛ab = bc
Where, a = (2-2x), b = (4), c = (4x+12) and d = (3).
Now,
⇛3(2-2x) = 4(4x+12)
Multiply the number outside the bracket with numbers and variables in the bracket.
⇛6 - 6x = 16x + 48
Shift the variable value on LHS and constant on RHS.
⇛-6x - 16x = 48-6
Subtract the values on LHS and RHS.
⇛-22x = 42
Shift the value (-22) from LHS to RHS.
⇛x = 42/-22
Write the obtained answer in lowest form by cancelling method.
⇛x = (42÷2)/(-22÷2)
Therefore, x = 21/-11 = -(21/11)
Answer: Hence the value of x for the given problem is -21/11.
VERIFICATION:
If x = -21/11 then the equation is
[{(2-2x)/4} = {(4x+12)/3]
Substitute the value x = -21/11 in expression, then
⇛[{2-2(-21/11)}/4 = {4(-21/11)+12}/3]
Multiply (-2) from (-21) to get 42 on LHS.
⇛[{2(42/11)}/4 = {4(-21/11)+12}/3]
Again multiply 4 from (-21) to get 81 on RHS.
⇛[{2(42/11)}/4 = {(-81/11) + 12}/3]
Take the LCM of the denominator 1 and 11 is 11 on LHS
⇛[{(2*11 + 42*1)/11}/4 = {(-81*1 + 12*11)/11}/3]
Multiply the numerator on both LHS and RHS.
⇛[{(22+42)/11}/4 = {(-81 + 132)/11}/3]
Add the numerator numbers on both LHS and RHS
⇛[{(64/11)}/4 = [{(48/11)}/3]
Now, conver the division fraction in multiply fraction on both LHS and RHS.
⇛[{(64/11) * 4} = {(48/11) * 3}]
Now, write the numbers in Lower form by cancelling method, on both LHS and RHS.
⇛(16/11) = (16/11)
LHS = RHS
Please let me know if you have any other questions.
2 (3) to the power of 3 + 5
Answer:
13122
Step-by-step explanation:
Our equation is 2(3)⁸
once its solve we get 13122 as our answer
Which of the following could be a helpful first step in solving this equation for q?
p2q+2q=11
Question 5 options:
Combine p2q+2q
Divide the whole equation by 11.
Divide the first term by p2
Factor a q out of p2q+2q
Answer:
D: Factor a q out of p^2 q+ 2q
Step-by-step explanation:
I took the test. Hope it was helpful! :)
The first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the equation is,
p²q+2q=11
Take q common from the L.H.S as
q(p²+2)=11
The value of q is obtained by rearranging the equation as,
q=11/(p²+2)
The value of q obtained after solving the equation p²q+2q=11 will be q=11/(p²+2).
Thus, the first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
Learn more about the equation here,
https://brainly.com/question/10413253
#SPJ2
Which expression is the factored form of−4.5n+3?
−1.5(3n+2)
−3(1.5n+1)
−3(1.5n−1)
−1.5(−3n+2)
Answer:
— 3 (1.5n — 1)
Step-by-step explanation:
[tex] - 4.5n + 3 = - \frac{9}{2} n + 3 = 3( - \frac{3}{2} n + 1) = - 3( \frac{3}{2}n - 1) \\ = - 3(1.5n - 1)[/tex]
one added to the square root of the sum of a number and one is equal to four. find the number
[tex]\stackrel{\textit{one added to the }\sqrt{\qquad }}{1+\sqrt{\quad }}~~,~~ \stackrel{\sqrt{~~}\textit{ of a number and one}}{\sqrt{x+1}}\implies 1+\sqrt{x+1}\stackrel{\textit{equals}}{=}4 \\\\\\ \sqrt{x+1}=3\implies \left( \sqrt{x+1} \right)^2=3^2\implies x+1=9\implies \boxed{x=8}[/tex]
List all the factors pairs in the table 64
(1, 64), (2, 32), (4, 16), (8, 8).
Answer:
1 x 64
2 x 32
4 x 16
8 x 8
Step-by-step explanation:
Factors of 64: 1, 2, 4, 8, 16, 32 and 64.
Pairs:
1 x 64
2 x 32
4 x 16
8 x 8
Hope this helps :)
how to do surface area
Answer:
Step-by-step explanation:
Multiply the length and width, or c and b to find their area. Multiply this measurement by two to account for both sides. Add the three separate measurements together. Because surface area is the total area of all of the faces of an object, the final step is to add all of the individually calculated areas together.
Answer:
Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape. We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.
Step-by-step explanation:
I'm DJ music is my hobbies what about you:)
Answer:
Playing video games or sumthin
Compare the expressions 7+3^2-2⋅5 and (3/4+1/8)÷1/8 using , =, or . Show your work. Answer:
[tex]A=7+3^2 -2 \cdot 5 = 7 + 9 - 10 = 9-3=6\\\\\\B = \left(\dfrac 34 + \dfrac 18\right) \div \dfrac 18 = \dfrac 78 \times 8 =7\\\\\\B>A[/tex]
The expression relation is 7+3²-2⋅5 > (3/4+1/8)÷1/8.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
First, 7+3²-2⋅5
Solving the above expression
= 7 + 9 -2.5
= 16 - 2.5
= 13.5
Second,
(3/4+1/8)÷1/8
= (6/8 + 1/8) ÷ 1/8
= 7/8 ÷ 1/8
= 7/8 x 8/1
= 7
Hence, 7+3²-2⋅5 > (3/4+1/8)÷1/8.
Learn more about Inequality here:
https://brainly.com/question/30231190
#SPJ2
which option is right??
Answer:
its the third choice
Step-by-step explanation:
Side angle side cuz there r 2 sides congruent in the picture shown above.
What is the value of w?
Answer:
w= -2. Solve for w: (w-5) (w+2) = w^2-4. Expand out terms of the left hand side: w^2-3 w-10 = w^2-4. Subtract w^2-4 from both sides
Step-by-step explanation:
What is 100% of 63?
PLEASE ANSWER QUICKLY
Answer:
100 percent of 63 is 63
Step-by-step explanation:
Answer:
63
Step-by-step explanation:
100 x 63 /100 = 63
100 Points
Emily wants to buy turquoise stones on her trip to New Mexico to give to at least 4 of her friends. The gift shop sells small stones for $4 and large stones for $6, and Emily has no more than $30 to spend.
Write and graph a system of Linear Equations and write two possible solutions.
Answer:
Step-by-step explanation:
what is she going to buy? Small stones or big stones? if its small stones then she can buy 7 small stones. If its big stones then she can buy 5 big stones.
find the integral.......
Answer:
1/5(2ln|x|+3*5^1/3)+c
Step-by-step explanation:
-7(8) What is it please help me I need help help help help
what is a degree 3 polynomial with integer coefficients with zeros 3, -4, 5
Y=4x+8 y=-x-7 solve by substitution
Step-by-step explanation:
Alrighty! here you go image.
Answer:x=15
Step-by-step explanation:
Would anyone be able to help with this? on my review and not sure how to do it
90 degrees - 78 degrees = 12 degrees
cofunction of sin is cos
answer : cos12
HELP ME PLEASE!!!!!!!!!!!
Answer:
SAS theorem >This is the correct
Answer:
SSS theoremStep-by-step explanation:
[tex] \huge\colorbox{pink}{hope \: its \: help}[/tex]
7(x+7)≤56 plz help im bad at math
Answer:x[tex]\geq[/tex]1
Step-by-step explanation:
remove the brackets
7x+49≤56
collect like terms
7x≤56-49
7x[tex]\geq[/tex]7
divide both sides by 7
x[tex]\geq[/tex]1
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
Please tell me how much can 6 go into 14 without going over 14
2.
Fit a quadratic function to these three points:
(−2, 8), (0, −4), and (4, 68)
A. y = −2x2 − 2x − 4
B. y = 4x2 + 2x − 4
C. y = −4x2 − 2x − 4
D. y = −2x2 + 2x − 4
Answer:
It's C.
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
just put the x and y values into the equations and see which equation stays true.
for example, point (4, 68) rules out A and C even without detailed calculation, because these 2 expressions can produce for positive x only negative y (and 68 is clearly a positive y).
so, when using this point in B :
68 = 4×4² + 2×4 - 4 = 4×16 + 8 - 4 = 64 + 8 - 4 = 68
correct.
and it is correct also for the other points.
so, B is the right answer.
There are 6 yellow, 9 blue, and 4 orange balls inside an urn. 8 balls are chosen from the urn without replacement. Let X, Y , and W denote the number of yellow, blue, and orange balls selected, respectively.
(a) Find P{X + W = 1}.
(b) Find P{X = 2, Y = W}
Using the probability concept, it is found that:
a) P{X + W = 1} = 0
b) P{X = 2, Y = W} = 0.0667
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, the order in which the balls are chosen is not important, hence, the combination formula is used to find the number of outcomes.
Combination formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In total, 8 balls are chosen from a set of 19, hence:
[tex]T = C_{19,8} = \frac{19!}{8!11!} = 75582[/tex]
Item a:
1 from a set of 15.7 from a set of 4.Not possible, hence:
P{X + W = 1} = 0
Item b:
2 from a set of 6.3 from a set of 9.3 from a set of 4.Hence:
[tex]D = C_{6,2}C_{9,3}C_{4,3} = \frac{6!}{2!4!} \times \frac{9!}{3!6!} \times \frac{4!}{3!1!} = 5040[/tex]
Then, the probability is:
[tex]p = \frac{D}{T} = \frac{5040}{75582} = 0.0667[/tex]
P{X = 2, Y = W} = 0.0667
A similar problem is given at https://brainly.com/question/15536019