It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reaction:


2 NaOH + H2CO3 → Na2CO3 + 2 H2O


The concentration of the carbonic acid is _____.

It Takes 60 ML Of 0.20 M Of Sodium Hydroxide (NaOH) To Neutralize 25 ML Of Carbonic Acid (H2CO3) For

Answers

Answer 1

It requires 60 mL of 0.20 M sodium hydroxide [tex](NaOH)[/tex] to neutralize 25 mL of carbonic acid [tex](H_2CO_3)[/tex], hence the carbonate ions concentration is [tex]0.24M[/tex].

Given:

Reaction:

[tex]\to \bold{2NaOH + H_2CO_3 \to Na_2CO_3 + 2H_20 }[/tex]

[tex]NaOH[/tex] volume [tex](V_B) = 60 \ ml[/tex]  

[tex]H_2CO_3[/tex] Volume [tex](V_A) = 25\ ml[/tex]  

[tex]NaOH[/tex] Molarity [tex](C_B) = 0.20\ M[/tex]

[tex]H_2CO_3[/tex] moles [tex](n_A) = 1[/tex]

[tex]NaOH[/tex] moles [tex](n_B) = 2[/tex]

To find:

[tex]H_2CO_3[/tex] Molarity [tex](C_A) =?[/tex]

Solution:

Using the neutralization reaction:  

[tex]\to \frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B} \\\\[/tex]

[tex]\to C_B = 0.2\ M \\\\ \to n_A = 1 \\\\ \to n_B = 2 \\\\ \to V_B = 60\ ml \\\\ \to V_A = 25\ ml[/tex]

Calculating the [tex]C_A[/tex]:

 [tex]\to \frac{C_A \times 25}{0.2 \times 60} =\frac{1}{2} \\\\\to C_A =\frac{1 \times 0.2 \times 60}{2 \times 25} \\\\\to C_A =\frac{1 \times 2 \times 12}{2 \times 5 \times 10} \\\\ \to C_A =\frac{ 12}{ 5 \times 10} \\\\\to C_A = \frac{6}{5 \times 5} \\\\\to C_A = \frac{6}{25} \\\\\to C_A=0.24\ M[/tex]

Therefore, the concentration of carbonic acid is "0.24M".

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Answer 2

The concentration of carbonic acid( H₂CO₃) is 0.24 M.

The given reaction:

2 NaOH + H₂CO₃ → Na₂CO₃ + 2H₂O

Volume of NaOH  = 60mL

Volume of H₂CO₃ = 25 mL

Molarity of NaOH= 0.20M

To find:

Molarity of H₂CO₃=?

2 moles of NaOH and 1 mol of H₂CO₃ reacts to give 1 mol of Na₂CO₃.

Using the neutralization reaction:  

Consider A to be NaOH and B to be  H₂CO₃

[tex]\frac{\text{Number of moles of A}}{\text{Number of moles of B}} =\frac{\text{Molarity of A*Volume of A}}{\text{Molarity of B*Volume of B}}[/tex]

On substituting the values in order to calculate molarity of H₂CO₃:

[tex]\text{Molarity of B}=\frac{1*0.2*60}{2*25} \\\\\text{Molarity of B}=0.24M[/tex]

Therefore, the concentration of H₂CO₃ is 0.24 M.

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what is mass of sodium hydroxide NaOH is present in 0.25 mole of sodium hydroxide
pls be quick​

Answers

Finding molar mass of NaOH

We know that

Molar mass of Sodium (Na) = 23 g/mol

Molar mass of Oxygen (O) = 32 g/mol

Molar mass of Hydrogen (H) = 2 g/mol

So,

Mass of 1 mole of NaOH

=> 1 × 23 + 1 × 16 + 1 × 1

=> 23 + 16 + 1

=> 40 g/mol

Now,

Mass = 40 × 0.25

Mass = 10 g

Here's the question ~

Heat treatment of muscular pain involves radiation of wavelength of about 900 nm (nm = 10-⁹ m). which spectral line of H - atom is suitable for this purpose ?

[ RH = 1 × 10⁵ cm-¹ ]

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[ c = 3 × 10⁸ m/s ]


Thanks for Answering ! ​

Answers

Using the Rydberg formula, the spectral line of H - atom is suitable for this purpose is Paschen, ∞ → 3.

Using the Rydberg formula;

1/λ = RH(1/nf^2 - 1/ni^2)

Given that;

λ = wavelength

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nf = final state

ni = initial state

When final state = 3 and initial state =

Then;

1/λ =  1 × 10^7 m-1 (1/3^2 - 1/ ∞^2)

1/λ =  1 × 10^7 m-1 (1/3^2 )

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True

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Answer:

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Extra info : -

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Hello there!

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Answer:

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[tex]\mathbb{MIREU}[/tex]

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Explanation:

if not then i'm sorry

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A plant without enough space to grow may be impacted by inadequate air as well as light for proper growth.

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Reaction B: Protons are lost by the atom of an element.

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Their identity changes in Reaction B but not in Reaction A.
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Answer:

D is correct

Explanation:

Answer:

A

Explanation:

Electrons are gained by the atoms. There is no change in the nucleus of the atom and the number of protons remains identical.

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Answer: Physical change

Answer:

Change in colour is a chemical change.

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Imagine you have two beakers. Both beakers are filled with the same amount of water. The water in both beakers is the same temperature as well. You add 50 g of Substance A to the first beaker and 50 g of Substance B to the second beaker. After stirring both beakers, there is a small pile of Substance A at the bottom of the first beaker. None of Substance B is visible in the second beaker. Which of the following statements is true?

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B. Substance A is more soluble in water than Substance B


C. Substance A is less soluble in water than Substance B


D. Substance A is not soluble in water

Answers

Substance A is less soluble in water than Substance B.

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Consider the reaction below. H2PO4â€"" H2O Right arrow. H3O HPO42â€"" Which of the following is a baseâ€""conjugate acid pair? H2O and H3O H2O and H2PO4â€"" H2PO4â€"" and HPO42â€"" H2PO4â€"" and H3O.

Answers

Taking into account the Brønsted-Lowry acid-base theory, a base/conjugate acid pair is H₂O/H₃O⁺.

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In other words, a conjugate base is an ion or molecule resulting from the acid that loses the proton, while a conjugate acid is an ion or molecule resulting from the base that gains the proton:

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In this case, you know:

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So, H₃O⁺ is the conjugate acid of the H₂O and HPO₄⁻ is conjugate base of H₂PO₄.

In summary,  a base/conjugate acid pair is H₂O/H₃O⁺.

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100 PIONTSSSS PLZ HELP
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Answer:

Explanation:

how do u draw on here

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Thermal energy typically flows from a warmer material to a cooler material.

Explanation:

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Answer:

D Robert Boyle

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I would say it is A. Aristotle

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he introduced triads of similar chemical properties in periodic table.

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Answer:

Examples of physical change include changes in the size or shape of matter. Changes of state, for example, from solid to liquid or from liquid to gas, are also physical changes. Some of the processes that cause physical changes include cutting, bending, dissolving, freezing, boiling, and melting.

Explanation:

I hope this helps

1. Crushing a can
2. Balling up a piece of paper
3. Boiling water
4. Breaking a glass cup
5. Melting ice
6. Chopping up wood
7. Cutting paper
8. Burning plastic
9. Mixing water and dirt
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