[tex] \huge \bf༆ Answer ༄[/tex]
The given terms in the question are : -
I = Electric current = 2 AmperesQ = Charge = 400 CoulombsWe have been given the task to find out time (t)
The formula that can be used to find time is : -
[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]
Rearrange the formula,
[tex] \sf \: t = \dfrac { Q}{I }[/tex]
Solve for time (t)
[tex] \sf t = \dfrac{400}{2} [/tex][tex] \sf t = 200 \: \: sec[/tex][tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]
An 8kg mass is placed on a 30 degrees frictionless inclines plane and is attached to a pulley to a hanging mass of 5kg
Calculate which direction will the system flow
B)what is the acceleration
C)the tension in the rope
Hi there!
We can begin by doing a summation of forces. Let the acceleration be positive in the direction of the DOWNWARD movement of the hanging block.
(A)
The system will flow in the direction of the hanging block's movement downwards.
(B)
Summation of forces of block on incline:
∑F = -M₁gsinФ + T
Summation of forces of hanging block:
∑F = M₂g - T
Sum both summations:
∑F = -M₁gsinФ + T + M₂g - T
∑F = M₂g -M₁gsinФ
According to Newton's Second Law:
∑F = ma
Thus:
(M₁ + M₂)a = M₂g -M₁gsinФ
[tex]a = \frac{M_2g -M_1gsin\theta}{M_1 + M_2}[/tex]
Plug in the values:
[tex]a = \frac{(5 * 9.8) -(8 * 9.8 * sin30)}{8 + 5} = \large\boxed{0.754 m/s^2}[/tex]
(C)
Calculate the rope's tension using one of the above equations:
∑F₂ = M₂g - T
Rearrange for T:
T = M₂g - m₂a
Plug in values:
T = 5(9.8) - 5(0.754) = 45.23 N
A car takes 9 m to stop after the driver applies the brakes.
The brakes exert a force of 2000 N.
Calculate how much work is done by this force.
Depends upon how soon you want to stop. You know the mass of the car, you know the initial velocity of 8.9 m/s. You know the final velocity which is zero. You can now calculate the deceleration of the car if you know how soon you want to stop.
Let's say you want to stop in one second.
a = (vf - vi) / t = - 8.9 m/s^2 (negative sign indicates deceleration).
F = ma = 800 x 8.9 = 7120 Newtons (kg*m/s^2)
Balanced forces are forces that have equal amount of ________. (word choices: force, repel, attract, motion)
Answer:
a
Explanation:
if forces on an object are balanced a moving object continues to move at the same speed and in the same direction
A 29000-kg open railroad car, initially coasting at 0.825 m/s with negligible friction, passes under a hopper that dumps 117500 kg of scrap metal into it.
a)What is the final speed, in meters per second, of the loaded freight car?
b)How much kinetic energy is lost, in joules, when the freight car receives this scrap metal? Ignore the free-fall kinetic energy of the scrap metal.
Answer:
a) Answer: 0.16331 m/s
b) Answer: 8522.66 joules
Explanation:
The final speed is 0.1633 m/s.
When the freight car receives this scrap metal, 7915.72 Joule kinetic energy is lost.
What is momentum?A body has momentum while it is moving, according to our understanding. It is said that a body's momentum is equal to the sum of its mass and speed. A body's direction is important when discussing momentum. Its direction belongs to the body's direction of motion.
(a) Given parameter:
Mass of the railroad car, M = 2900 Kg.
Mass of the scrap metal, m= 11750 Kg.
Initial speed of the car, u = 0.0825 m/s.
Initial speed of the scrap metal = 0 m/s.
Final speed of the system, v = ?
Then, initial momentum of the system = initial momentum of the car + initial momentum of the scrap metal .
= (29000×0.825 + 117500×0) kg.m/s.
= 23925 kg.m/s.
Final momentum of the system = total mass of the system× final speed
= (29000 + 117500)× v kg.m/s
= 146500v kg.m/s.
Hence, from principle of conservation of momentum,
initial momentum of the system = Final momentum of the system
⇒ 23925 = 146500v
⇒ v = 0.1633 m/s.
The final speed of the loaded freight car is 0.1633 m/s.
(b) Lost in kinetic energy = initial kinetic energy of the car - final kinetic energy of the loaded car.
= 1/2*29000*0.825² -1/2*(29000 + 117500)* 0.1633² Joule.
= 7915.72 Joule.
Hence, 7915.72 Joule kinetic energy is lost in this process.
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A wrecking ball has a mass of 650 kg. It swings from a cable that is 21 m long. The centripetal force on the ball is 56 N. What is the tangential speed of the wrecking ball? 1. 3 m/s 1. 8 m/s 46 m/s 870 m/s.
Hi there!
For an object moving in a circle:
Centripetal force = ∑F = mv²/r
Thus:
56 = mv²/r
Rearrange to solve for velocity:
√(56r/m) = v
√(56 × 21)/650 = 1.345 m/s
Answer:
AExplanation:
have a good day
help with this question
Answer:
D and B.
Explanation:
The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.
How would the gravity between two objects change if one object got bigger?
The correct answer is the 3rd answer, gravity would increase its pull on the small object
hope this helps! :)
A balloon with a volume of 2. 0 L at 25°C is placed in a hot room at 35°C. The pressure on the balloon is constant at 1. 0 atm. How does the volume of the balloon change after moving it to the hot room?.
Answer:
25A°C=2L
35A°C=? More
=35/25×2L
=7/5×2L
=14L/5
=2.8L
A ball is released freely from the top of a building 80m high. Find its speed.
At the top of the building, the speed of the ball is zero.
The speed increases steadily as the ball falls.
When it hits the street, its speed is 39.6 m/s.
We are able to walk toward because…
a) we push on the air
b) we push on the ground
c) the air pushes on us
d) the ground pushes on us
We are able to walk toward because b) we push on the ground.
_
_
_
[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]
PLEASE HELP! I NEED TO ANSWER THIS QUICKLY!
1. What are the uses of microwaves in society today? Give examples
2. What advantages and/or disadvantages have microwaves as a technology had for humans
a) health b) economy and c) human living conditions?
Answer:
I'm not a genius ok?
Explanation:
1. Radar communication, Analysis of the molecular and atomic structure, telephone communication
2. c
change 176°F to the Celsius and Kelvin scales. pura batana kese hua fir answer dena plzz
Formulas change from F to degree C : C = (F – 32) / 1.8
so we have (176-32) /1.8= 80 oC
Formulas change from F to degree K : K = 5 / 9 x (F – 32) + 273.15
so we have 5/9 x (176-32) + 273.15 = 353 oK
ok done. Thank to me :>
What is the velocity of a ball swung around on a rope with a
radius of 0.25 meters and period of 0.40 seconds?
A ball swung around on a rope of a radius of 0.25 meters in a time of 0.40 seconds, then the velocity of the ball will be equal to 3.925 m/s.
What is velocity?
Velocity is the rate of change of a traveling object's direction, as measured by a certain unit of time and as seen from a specific vantage point. Speed is a basic concept in kinematics, the branch of special relativity that studies how bodies move.
A scientific vector quantity called velocity must have both a magnitude and direction to be described.
As per the data provided in the question,
Radius, r = 0.25
Time, t = 0.40 seconds
Circumference of the circle, d = 2πr
d = 2π(0.25)
d = 1.570 m
Velocity, v = d / t
v = 1.570 / 0.40
v = 3.925 m/s.
Therefore, the velocity of the ball will be 3.925 m/s.
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helppp
A crane accelerates a 175 kg load is upward. The tension in the cable is 2000 N. Find the magnitude and direction of the elevator's acceleration.
Hi there!
We can begin by summing forces acting on the load:
∑F = T - Mg (where g ≈10 m/s²)
ma = T - Mg
We can plug in the given values to solve:
ma = 2000 - 175(10)
175a = 250
a = 250/175 = 1.43 m/s² UPWARDS
Answer:
a = 1.63 m/s^2
Explanation:
m = 176kg
Ft = 2000N
2000 = 175 (9.8) +175(a)
2000 = 1715 +175a
-1715 -1715
285 = 175a
175 175
a = 1.63m/s^2
Which country is considered to have one of the best ski teams in the world?
Answer:
France
Explanation:
France is the undisputed champion in the world of skiing.
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
Part B
Based on the information in the article, how could plants be used in the future to help counteract some human
emissions?
Answer:
Having more plants performing photosynthesis could help reduce the amount of carbon dioxide in the atmosphere.
Explanation:
sample answer
The plants can be used in the future to help counteract some human
emissions they absorb carbon dioxide from the air and release oxygen.
What is photosynthesis?It is a process carried out by photosynthetic autotrophic organisms, such as plants, algae and some prokaryotes. These organisms capture sunlight, convert it into chemical energy, which will be used to produce organic compounds, based on water and carbon dioxide.
Trees, like other plants, in the process called photosynthesis, absorb carbon dioxide from the air and release oxygen. They also make the air wetter and cooler. In this way, plants contribute to the good quality of the air we breathe.
See more about phtosynthesis at brainly.com/question/1388366
A plane flying above the ground has 60,000 joules of kinetic energy and 6,000 joules off gravitational potential energy. How much mechanical energy does the plane have?
Answer:
66,000J
Explanation:
Mechanical energy = Gravitational energy + Kinetic Energy
ME = 6,000 + 60,000 = 66000 J
How long does it take a plane, traveling at a constant speed of 200 m/s, to fly once around a circle whose radius is 2750 m
Answer:
2000 and 156300
jade it jawaban nya
A 3.00 kg toy falls from a height of 10.0 m. Just before hitting the ground, what will its kinetic energy be? (Disregard air resistance; g = 9.81 m/s2.)
The kinetic energy of the toy before hitting the ground is 294.3 J
From the question given above, the following data were obtained:
Mass (m) = 3 Kg
Height (h) = 10 m
Acceleration due to gravity (g) = 9.81 m/s²
Kinetic energy (KE) =?Before the toy will hit the ground, the potential and kinetic energy of the toy will be the same.
KE = PE = mgh
KE = 3 × 9.81 × 10
KE = 294.3 JTherefore, the kinetic energy of the toy is 294.3 J
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Who is the author "talking” to in the third stanza of Flanders field
Answer:
One of Canada's best-known poems, “In Flanders Fields” was written on May 2, 1915, when Canadian serviceman John McCrae was stationed at an army hospital in Flanders, Belgium, during World War I.
Explanation:
a helicopter cruises at a constant velocity when the total thrust of the engines is 5,000 N. How much air resistance acts on the jet ??
Hi there!
[tex]\large\boxed{F_{A} = -5000N}}[/tex]
For an object to be moving at constant velocity:
∑F = 0 (The sum of the forces acting on the object MUST be 0 N)
We can do a summation of forces for this helicopter in the HORIZONTAL direction:
∑Fₓ = Ft (Force of Thrust) + Fa (Force of air resistance) = 0
Thus, if we substitute in the given value for Ft:
Ft = -Fa
5000N = -Fa
Fa = -5000N
The ______________ is all the surroundings of a living organism.
genetics
environment
temperature
heredity
Which element is in the 3rd period and group 16?
Answer:Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.
Answer:
Explanation:
Answer: Thus for n=1 number of electrons is 2 and for n=2 the number of electrons is 8. Hence the electronic configuration of the element X is 2,8,6 and its atomic number is 16. In the Modern Periodic Table, the element Sulphur has atomic number 16. So, the solution is that the element X is Sulphur and it is non metallic.
What is the only force that can overcome the repulsion between two positively charged nuclei to bind them into an atomic nucleus
Answer:
Nuclear Fusion
Explanation:
At large distances, two nuclei repel one another because of the repulsive electrostatic force between their positively charged protons. If two nuclei can be brought close enough together, however, the electrostatic repulsion can be overcome by the attractive nuclear force, which is stronger at close distances.
1. A rocket is launched from a 300 cm rail. The upper Launch Lug is placed 1 point 150 cm from the bottom of the rocket. What is the effective distance of the Launch Rail? 300 cm 150 cm 3 m 300 m O 1m O 1.5 m
Answer:
i think its going to be 150 because its half of 300
Explanation:
How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?
Answer: F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N
Answer:
F = 1080 N
Explanation:
60W light bulb is left on for 5mins. How much energy does it use in KWH
Answer:
Energy = Power × Time
time must be hoursPower must be in kilowatts[tex]{ \tt{E = ( \frac{60}{1000} ) \times ( \frac{5}{60}) }} \\ \\ { \tt{E = 0.005 \: kwh {}^{ } }}[/tex]
Please help, and give an explanation on what you did. Thanks a lot :]
Answer:
3.0 m
Explanation:
The height of the wave is just 1.5 m + 1.5 m which equals 3.0 m
5. SEP Construct Explanations If the line on
a distance-versus-time graph and the line on
a speed-versus-time graph are both straight
lines going through the origin, can the two
graphs be displaying the motion of the same
object? Explain.
Answer:
If and only if the object has 0 speed. Any other case is a no.
Explanation:
In increasing math complexity:
If the graph of a distance/time is a straight line with a non-zero slope it means that the velocity-time graph is an horizontal line where every point has the same second coordinate, equal to the value of the slope of the first line (ie, if the first line has equation [tex]y=2t[/tex] the second line will have equation [tex]y=2[/tex] - I'm using y to denote either the distance or the speed, read it as "the non-time variable")
If the graph of a speed/time is a straight line, the graph of the distance/time is the area of the region of space beneath the straight line in the first graph, ie a triangle. And as you increase the sides of that triangle keeping the angles fixed, you get a parabolic curve.
Bonus case: if [tex]v(t)= 0; d(t) = 0[/tex], they are both straight lines, they both pass through the origin, and they are the exact same line.
With calculus (or: math becomes fun after you add the alphabet to it)
You are asking if the answer of the IVP
[tex]\left \{ {{x'=x} \atop {x(0)=0}} \right.[/tex]
is a linear function. The answer is: besides the obvious [tex]x(t)'=x(t)=0 \ \forall t[/tex] there are no other solutions, linear or otherwise.