I need to find the missing angle of this triangle or whatever it is

Answer:

If 10 men dig a ditch in 12 days .

Total man-days required to dig the ditch

= 10 men × 12 days

= 120 man-days

how long would 15 men take to dig it?

No of days required to finish the job by 15 men

= 120 men-days / 15 men

= 8 days

Answer: 8 days will be required to finish the job by 15 men

Step-by-step explanation:

Hope this helps u

Crown me as brainliest:)

Answer:

yes it is parallel because the alternate interior angles are equal

Answer: The answer is 11/12 problems

Step-by-step explanation:

You add 2/12 + 9/12 which gives you a result of 11/12

Answer:

Step-by-step explanation:

we need the picture

Answer:

y = -[tex]3^{2}[/tex] + 7x - 2

Step-by-step explanation:

-9-2= -11

y = -11 +7x

+11

y+11 = 7x

/7

1.57142857143= x

Answer:

8.2/10

Step-by-step explanation:

Answer:

42/50

Step-by-step explanation:

Answer:

Tom wants to go to disneyland this weekend with 23 adults including himself and 4 children Ashley 3, Leslie 1, Brit 4, Victor 2. Children under the age of 6 pay "x" amount while anyone older pay "y" amount. What equation can tom use to find out how much the tickets in total will be.

Step-by-step explanation:

Y = Adults pay y amount - There are 23 adults

X =kids under 6 pay x amount - there are 4 children

4x+23y

4 (kids under 6 ticket cost)+ 23 (Adults ticket cost)

Answer:

c on edge

Step-by-step explanation:

fr

Answer:

(B) Stretch z by a factor of 3 and rotate π/6 radians counterclockwise.

Step-by-step explanation:

edge:2022 Happy new year!

Answer:

36 feet.

Step-by-step explanation:

2 goes into 24 12 times, 12 times 3 is 36 therefore the actual house is 36 feet tall.

Answer:

x=-1

Step-by-step explanation:

The first thing we can do is subtract 3x from both sides (it makes solving the equation easier if you get rid of the variable first).

3x+6=4x+7

-3x    -3x

6=x+7

All we need to do now is subtract 7 on both sides.

6=x+7

-7    -7

-1=x  or  x=-1  (they both mean the same thing!)

Hope this helps!! Have a wonderful day c:

Answer: 2,9

(3,3) & (-2,6) midpoints

Answer:

(0.5,4.5)

Step-by-step explanation:

Use the midpoint formula to find the answer: ((x1+x2/2),(y1+y2/2))

((3-2/2),(3+6/2))

((1/2),(9/2))

(0.5,4.5)

Answer:

a. 0.5 g/cc

Step-by-step Explanation:

Given:

Measurement of rectangular prism = 3 cm × 4 cm × 6 cm

Mass of rectangular prism = 36 grams

Required:

Density of rectangular prism

SOLUTION:

[tex] Density = \frac{Mass}{Volume} [/tex]

Mass = 36 g

Volume = 3*4*6 = 72 cm³

[tex] Density = \frac{36}{72} [/tex]

Density = 0.5 g/cc

Answer:it said i was wrong and the correct answer should have been -6 3/10

Step-by-step explanation:

The total change in weight of the sculpture after [tex]3\frac{1}{2}[/tex] hours is, [tex]\bold{-6\frac{3}{10}}[/tex] pounds.

"The rate of change function is the rate at which one quantity is changing with respect to another quantity."

Given: The weight of an ice sculpture changes [tex]-1\frac{4}{5}[/tex] pounds every hour.

We need to find the total change in weight of the sculpture after [tex]3\frac{1}{2}[/tex] hours.

i.e., the rate of change of an ice sculpture per hour is -1 4/5 pound.

Total change in weight of the sculpture after t hours

= change in the weight of the sculpture per hour × t

= [tex](-1\frac{4}{5}) \times (3\frac{1}{2} )[/tex]

= [tex](-\frac{9}{5} ) \times (\frac{7}{2} )[/tex]

= [tex]-\frac{63}{10}[/tex]

= [tex]\bold{-6\frac{3}{10}}[/tex] pounds

Therefore, the total change in weight of the sculpture after 3 1/2 hours is, [tex]\bold{-6\frac{3}{10}}[/tex] pounds.

Learn more about rate of change here:

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Answer:

120 seconds

Step-by-step explanation:

60         20

120        40

180       60

            80

            100

            120

Answer:

C and E

Step-by-step explanation:

the b value of an exponential function needs to be greater than one to be exponential growth

[tex] \sqrt{2} [/tex]

and 1.1 are the only 2 that are greater than one

The possible values for b are those that are greater than 1. The correct answers are square root of  and 1.1, the correct options are C and E.

Consider the function:

[tex]y = a(1\pm r)^m[/tex]

where m is the number of times this growth/decay occurs, a = initial amount, and r = fraction by which this growth/decay occurs.

If there is plus sign, then there is exponential growth happening by r fraction or 100r %

If there is negative sign, then there is exponential decay happening by r fraction or 100r %

We are given that;

f(x)=ab^x

Now,

An exponential growth function is a function that increases as x increases. For the function f(x) = ab^x, this means that the base b must be greater than 1, so that the exponent x makes the function larger.

Therefore, by the exponential growth and decay the answer will be square root of 2 and 1.1

Learn more about exponential growth and decay here:

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Answer:

(x-18)^2+(y+6)^=36

Step-by-step explanation:

circle basic equation is (x-h)^2+(y-k)^2=r^2

center is (18,-6) it is also externally tangent

so

(x-18)^2+(y+6)^2=36 answer

The equation of a circle that is externally tangent to the given circle and has a center at (18, −6) is [tex](x-18)^2+(y+6)^=36[/tex]

A circle can be characterized by its center's location and its radius's length. Let the center of the considered circle be at (h,k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

[tex](x-h)^2 + (y-k)^2 = r^2[/tex]

Given that the circle basic equation is [tex](x-2)^2+(y+6)^2=100[/tex]

The center is (18,-6) it is also externally tangent;

Therefore,

[tex](x-18)^2+(y+6)^2=36[/tex]

Therefore, the equation of a circle that is externally tangent to the circle is; [tex](x-18)^2+(y+6)^2=36[/tex]

Learn more about equation of a circle here:

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Answer:

6(8+x)

Step-by-step explanation:

Notice that the constant and the coefficient have a greatest common factor of 6. Therefore, we can just factor the 6 out to get 6(8+x).

Answer:

Step-by-step explanation:

[tex]48 + 6x\\\\\mathrm{Rewrite\:}48\mathrm{\:as\:}6\times\:8\\\\=6x+6\times\:8\\\\\mathrm{Factor\:out\:common\:term\:}6\\\\=6\left(x+8\right)[/tex]

Answer:

31

Step-by-step explanation:

To solve this problem, we must find the lowest common multiple of 21, 35 and 63

   Find the prime factors of the number;

 Prime factors of 21  = 3 x 7

                            35 = 3 x 5

                            63 = 3 x 3 x 7

  The lcm = 3 x 3 x 5 x 7 = 315

The numbers between  1 and 10, 000 divided by these three numbers;

   First number  = 315

    Last number  = 9765

Now the total number:

      = [tex]\frac{first number - last number }{315} + 1[/tex]

      = [tex]\frac{9765 - 315}{315}[/tex] + 1

     = 30 + 1

     = 31

Answer:

i^15=-i

i^32=1

1^99=-i

i^22=-1

hope this helps :)

im sorry for the late answer, i put all the answers incase some one needs them, have a nice day!

Step-by-step explanation:

Answer: The answer is "1".

Step-by-step explanation:

Correct on edgen.

Answer:

b

Step-by-step explanation:

Answer:

the answer is B

Step-by-step explanation:

Answer:

m<WYZ = 23°

m<ACB = 87°

Step-by-step explanation:

Problem 1: Find WYZ

Given,

m<WVX = (3x - 7)°

m<VYZ = (16x - 3)°

∆WYZ ~ ∆WVX, therefore:

m<WYZ = m<WVX (corresponding angles of similar triangles are congruent)

m<WYZ = (3x - 7)° (substitution)

Create an equation to find the value of x.

m<WYZ + m<VYZ = 180° (linear pair)

(3x -7)° + (16x - 3)° = 180° (substitution)

Solve for x

3x - 7 + 16x - 3 = 180

Add like terms

19x - 10 = 180

Add 10 to both sides

19x - 10 + 10 = 180 + 10

19x = 190

Divide both sides by 19

19x/19 = 190/19

x = 10

m<WYZ = (3x - 7)

Substitute x = 10

m<WYZ = 3(10) - 7 = 30 - 7

m<WYZ = 23°

Problem 2: Find m<ACB

Given,

m<A = 62°

m<AED = (11x - 2)°

m<B = (6x + 13)°

∆ADE ~ ∆ACB, therefore:

m<AED = m<B (corresponding angles of similar ∆s are congruent)

(11x - 2)° = (6x + 13)°

Solve for x

11x - 2 = 6x + 13

Collect like terms

11x - 6x = 2 + 13

5x = 15

Divide both sides by 5

5x/5 = 15/5

x = 3

m<ACB + m<B + m<A = 180° (sum of ∆)

m<ACB + (6x + 13) + 62° = 180° (substitution)

Plug in the value of x and solve

m<ACB + (6(3) + 13) + 62° = 180°

m<ACB + (6(3) + 13) + 62° = 180°

m<ACB + (18 + 13) + 62° = 180°

m<ACB + 31° + 62° = 180°

m<ACB + 93° = 180°

Subtract 93 from both sides

m<ACB = 180° - 93°

m<ACB = 87°

Answer:

MO is 13 units

Step-by-step explanation:

If point lies on a segment, then this point divides the segment into two parts, the sum of their lengths equals the length of the segment

∵ Point N ∈ segment MO

→ That means point N divide segments MO to two parts MN and NO

∴ Point N divides segment MO into two parts MN and NO

→ That mans the length of segment MO equals to the sum of

   lengths of MN and NO

∴ MO = MN + NO

∵ MN = 8 units

∵ NO = 5 units

∴ MO = 8 + 5

∴ MO = 13 units

Answer:

81/100

Step-by-step explanation:

Answer:

81/100

Step-by-step explanation:

Answer:

153.158 ; 177.642

Step-by-step explanation:

Given the following:

Sample mean (m) = 165.40

Sample standard deviation (s) = 21.70

Sample size (n) = 17

α = 98%

Confidence interval = m ± z(SE)

z at 98% = 2.326

SE = s/√n

SE = 21.70/√17 = 5.2630230

Hence,

Confidence interval = 165.40 ± 2.326(5.2630230)

165.40 - 12.241791498 OR 165.40 + 12.241791498

153.158 ; 177.642

First, rewrite

[tex]x^y=e^{\ln x^y}=e^{y\ln x}[/tex]

[tex]5^{x-y}=e^{\ln5^{x-y}} = e^{\ln(5)(x-y)}[/tex]

Now, differentiate both sides using the chain rule:

[tex]\dfrac{\mathrm d\left(e^{y\ln x}\right)}{\mathrm dx}=\dfrac{\mathrm d\left(e^{\ln(5)(x-y)}\right)}{\mathrm dx}[/tex]

[tex]e^{y\ln x}\dfrac{\mathrm d(y\ln x)}{\mathrm dx}=e^{\ln(5)(x-y)}\dfrac{\mathrm d(\ln(5)(x-y))}{\mathrm dx}[/tex]

[tex]x^y\left(\dfrac{\mathrm dy}{\mathrm dx}\ln x+y\dfrac{\mathrm d(\ln x)}{\mathrm dx}\right)=\ln(5)5^{x-y}\left(\dfrac{\mathrm d(x)}{\mathrm dx}-\dfrac{\mathrm dy}{\mathrm dx}\right)[/tex]

[tex]x^y\left(\ln x\dfrac{\mathrm dy}{\mathrm dx}+\dfrac yx\right)=\ln(5)5^{x-y}\left(1-\dfrac{\mathrm dy}{\mathrm dx}\right)[/tex]

[tex]\left(x^y\ln x+\ln(5)5^{x-y}\right)\dfrac{\mathrm dy}{\mathrm dx}=\ln(5)5^{x-y}-yx^{y-1}[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\ln(5)5^{x-y}-yx^{y-1}}{x^y\ln x+\ln(5)5^{x-y}}[/tex]