I need help with this pre calculus question , i understand how to find the period i just don’t understand this graph

Answer:

1/60

Step-by-step explanation:

For each cake, there is a 1/20 chance to find the gold ring since it is in one of the 20 slices. The probability for each cake is independent of each other, so we multiply

1/20 x 1/20 x 1/20

=1/60

a) The base area of the cylinder is given as follows: 78.54 ft².

b) The height of the cylinder is given as follows: 2 ft.

The volume of a cylinder of radius r and height h is given by the equation presented as follows:

V = πr²h.

The base area is given as follows:

Ab = πr².

Considering the radius of 5 ft, the base area is of:

Ab = 3.1416 x 5²

Ab = 78.54 ft².

Considering the volume of 157.08 ft³, the height of the cylinder is obtained as follows:

78.54h = 157.08

h = 157.08/78.54

h = 2 ft.

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Answer: 70 pages

Step-by-step explanation: If she read 1/7 pages on monday and the book is 490 pages, divide. 490 ÷ 1/7 = 70. 70 × 7 is 490. So use these operations in future problems. Just make sure to read carefully!

The points of the polygon are:

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

Option D is the correct answer.

We have,

From the coordinate plane,

There are 4 points that form the polygon,

The points are all in ordered pairs.

So,

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

Thus,

The points of the polygon are:

(1.5, 2)

(-4, 2)

(-4, -4.5)

(1.5, -4.5)

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The dimension is gioven as 69.26 feet

xy = 1836

This is the area

The cost of fence = 2x + 2y

cost of interior fencing

2x + 4y

C = 20.40(C1) + 12.00(C2)

We have to put the vakues in the formula above

C = 20.40(2x + 2y) + 12.00(2x + 4y)

= 40.80x + 40.80y + 24.00x + 48.00y

= 64.80x + 88.80y

from xy = 1836

y = 1836 / x

We have to put the value in C

C = 64.80x + 88.80(1836/x)

= 64.80x + 164236.80/x

Take the deriveative with respect to x

64.80 - 164236.80/x^2 = 0

x = √(164236.80/64.80)

=  69.26 feet

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The number of childs plate are 201 and  adult's plate are 203.

Let's use C to represent the number of child plates and A to represent the number of adult plates.

We know that a child's plate costs $2.80 and an adult's plate costs $6.90.

Therefore, we can write two equations based on the information given:

The total number of plates served is 404

C + A = 404 ...(1)

C=404-A

The total amount collected is $1,963.50

2.8C + 6.9A = 1963.5 ..(2)

2.8(404-A)+6.9A= 1963.5

1131.2 - 2.8A +6.9A=1963.5

4.1 A =1963.5 -1131.2

4.1A=832.3

Divide both sides by 4.1

A=832.3/4.1

A=203

Now put A in equation (1)

C+203=404

C=404-203

C=201

Hence, the number of childs plate are 201 and  adult's plate are 203.

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Answer: 1040

Step-by-step explanation: y=ab

The exponential equation is: y = 1040(1.3^x)

Calculate the value of y, which stands for the albums sold, and x represents the months passed from their release. For an exponential equation structured as y = a(b^x), identify the base b to solve it mathematically.

By analyzing the last month after launch, known as March, 1040 copies were made available for public consumption. One month further down the line, in April, the gross profit jumped up to 1352 units sold.

When we divide the copies traded throughout April by those resold in March, the value identifies the base:

b=1352/1040 ≈ 1.3

Thus, applying the coefficient a for the initial sales registered during March - totaling 1,040 copies - leads us to define the following form for our equations:

y = 1040(1.3^x)

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Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

y=-2x+2

Based on the information, the correct information regarding the graph is that C. Quantity demanded decreases as price increase.

The graph shows that for every increase of 100 units of the goods demanded, price reduces by 1 unit.

When 500 units was demanded, the price was at 1. Therefore, if 550 units are demanded, the price will reduce by half, which means the price would drop to 0.5.

The price would drop to 0.5. In this case, the the correct information regarding the graph is that Quantity demanded decreases as price increase.

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The measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is:

Range, because Flower Town is symmetric

A histogram is a visual representation of statistical data that makes use of rectangles to illustrate the frequency of data points over a range of successive numerical intervals of equal width. The independent variable and dependent variable are plotted along the horizontal axis and the vertical axis, respectively, in the most typical type of histogram.

Now, from the given histograms, we can see that Desert landing is skewed while Flower town is symmetrical entirely.

Thus, The measure of variability that should be used for both sets of data to determine the location with the most consistent temperature is:

Range, because Flower Town is symmetric

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The numeric ratio of the segment ratio are:

To find the numeric ratios of the given segment ratios, to calculate the distances between the given points.

CD: DB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between D(4,3) and B(-4,7) is:

DB = √[(4 + 4)² + (3 - 7)²] = 10

Therefore, the numeric ratio of CD:DB is:

CD:DB = √5:10

CE: CA

The distance between C(6,2) and E(4,2) is:

CE = √[(6 - 4)² + (2 - 2)²] = 2

The distance between A(-4,2) and C(6,2) is:

CA = √[(-4 - 6)² + (2 - 2)²] = 10

Therefore, the numeric ratio of CE:CA is:

CE:CA = 2:10

DE: BA

The distance between D(4,3) and E(4,2) is:

DE = √[(4 - 4)² + (3 - 2)²] = 1

The distance between B(-4,7) and A(-4,2) is:

BA = √[(-4 + 4)² + (7 - 2)²] = 5

Therefore, the numeric ratio of DE:BA is:

DE:BA = 1:5

CD: CB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between C(6,2) and B(-4,7) is:

CB = √[(6 + 4)² + (2 - 7)²] = √181

Therefore, the numeric ratio of CD:CB is:

CD:CB = √5:√181

Based on the numeric ratios, determine the type of ratio for each segment ratio:

CD: DB is a part:part ratio

CE: CA is a part:whole ratio

DE: BA is a part:part ratio

CD: CB is a part:whole ratio

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Answer:  the answer is 13 and one-half

Step-by-step explanation:

C

Step-by-step explanation:

In this problem, we have that the graph in fact represents a function, as there are no vertically aligned points, that is, each input is mapped to a single output.

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A graph of f(x) is shown in the image below.

A graph of f(x) is shown in the image below.

The vertex form equation for g(x) is g(x) = -x²

In Mathematics and Geometry, the translation a geometric figure or graph to the right simply means adding a digit to the value on the x-coordinate of the pre-image while the translation a geometric figure or graph upward simply means adding a digit to the value on the y-coordinate (y-axis) of the pre-image.

Since the parent function is f(x)= (x + 3)² - 2, g(x) would be created by translating f(x) three units to the right, two units up, and reflected vertically over the x-axis as follows;

f(x) = (x + 3)² - 2

g(x) = -[(x + 3 - 3)² - 2 + 2]

g(x) = -x²

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The value of row total of the column total's is 165.

The value of row total of field is 91

Column total of maple can be found by:

(46.32 /100) * y =44

Or y = (44 *100)/46.32

Or y = 94.991 =95 (approx)

Now we get value of field under maple by

Value of field under maple = (column total - value of pond under maple) = (95 - 44) = 51

Value of row total of the column total's = (column total of oak + column total of maple = (70 + 95) = 165 (total data)

Value of row total of field = ( value of field under oak + value of field under maple) = (40 + 51) = 91

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The position function is s(t) = -5t³ + 3t² + 8t + 2.

We have,

To find s(t), we need to integrate the velocity function v(t) since velocity is the rate of change of position with respect to time.

To do this, we need to first find the velocity function v(t) by integrating the acceleration function a(t):

a(t) = -30t + 6

Integrating with respect to t, we get:

v(t) = -15t² + 6t + C1

We are given that v(0) = 8, so we can use this to solve for the constant C1:

v(0) = -15(0)² + 6(0) + C1 = C1

C1 = 8

Now we have the velocity function:

v(t) = -15t² + 6t + 8

To find s(t), we need to integrate v(t) with respect to t:

s(t) = -5t³ + 3t² + 8t + C2

We are given that s(0) = 2, so we can use this to solve for the constant C2:

s(0) = -5(0)³ + 3(0)² + 8(0) + C2 = C2

C2 = 2

Now we have the position function:

s(t) = -5t³ + 3t² + 8t + 2

Therefore,

The position function is s(t) = -5t³ + 3t² + 8t + 2.

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There is no association between the number of fat grams and the number of calories because there are no outliers or clusters.

To make this clear, when we claim that there is no correlation between two variables, it indicates a lack of comprehensible patterns or connections. Put another way, adjustments in one factor do not seem to impact the other.

In relation to the inquiry at hand, if fat grams and calorie figures have no notable outliers or groupings, there might be an inference that these two variables are not related.

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Answer:

Given system of linear equations are

2x+3y+3z=5

x−2y+z=−4

3x−y−2z=3.

Represent it in matrix form

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

which is in the form of AX=B

A=

⎣

⎢

⎢

⎡

2

1

3

3

−2

−1

3

1

−2

⎦

⎥

⎥

⎤

∣A∣=10+15+15=40



=0

∴ A

−1

exists

To find adjoint of A

A

11

=5,A

12

=5,A

13

=5

A

21

=3,A

22

=−13,A

23

=11

A

31

=9,A

32

=1,A

33

=−7

Adj(A)=co-factor

⎣

⎢

⎢

⎡

5

3

9

5

−13

1

5

11

−7

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

A

−1

=

∣A∣

1

Adj(A)

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

X=A

−1

B

=

40

1

⎣

⎢

⎢

⎡

5

5

5

3

−13

11

9

1

−7

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

5

−4

3

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

25−12+27

25+52+3

25−44−21

⎦

⎥

⎥

⎤

X=

40

1

⎣

⎢

⎢

⎡

40

80

−40

⎦

⎥

⎥

⎤

⎣

⎢

⎢

⎡

x

y

z

⎦

⎥

⎥

⎤

=

⎣

⎢

⎢

⎡

1

2

−1

⎦

⎥

⎥

⎤

Hence, x=1,y=2 and z=−1

The solution to the system of equations is

x = 3

y = 2

z = 2

To solve for x, y, and z, we can use the elimination method or substitution method. Here, we will use the elimination method.

First, we will eliminate y from the equations by multiplying the first equation by 3 and the second equation by 1, and then adding them:

(3) (2x – y + 3z = 10)

6x – 3y + 9z = 30

(1) (x + 3y – 2z = 5)

x + 3y – 2z = 5

Adding the two equations gives:

7x + 7z = 35

Simplifying, we get

x + z = 5 (Equation 1)

Next, we will eliminate y again by multiplying the second equation by 2 and the third equation by 3, and then adding them:

(2) (x + 3y – 2z = 5)

2x + 6y – 4z = 10

(3) (3x – 2y + 4z = 12)

9x – 6y + 12z = 36

Adding the two equations gives:

11x + 8z = 46

Substituting x + z = 5 from Equation 1 into the above equation, we get:

11(x + z) + 8z = 46

11x + 19z = 46

Solving for z, we get:

z = 2

Substituting z = 2 into x + z = 5 from Equation 1, we get:

x + 2 = 5

x = 3

Finally, substituting x = 3 and z = 2 into any of the original equations, we can solve for y:

2x – y + 3z = 10

2(3) – y + 3(2) = 10

6 – y + 6 = 10

y = 2

Therefore, the solution to the system of equations is:

x = 3

y = 2

z = 2

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Answer:

  (b)  10; 150°

Step-by-step explanation:

You want the polar coordinate equivalent of (-5√3, -5).

The polar form of (a, b) is ...

  (a, b) = (r; θ)

where ...

  r = √(a² +b²)

  θ = arctan(b/a) . . . . . with attention paid to quadrant

For the given values, the polar form is ...

  r = √((-5√3)² +5²) = √(75 +25) = 10

  θ = arctan(5/(-5√3)) = arctan(-1/√3) = 150°

The angle is a quadrant II angle with a reference angle of 30°.

The polar form is (10; 150°).

__

Additional comment

Some calculators will do the coordinate conversion based on a vector or ordered pair. Others require the coordinates of the point to be expressed as a complex number, as in the attachment. (Note the calculator mode is set to DEGrees.)

Answer:

Step-by-step explanation:

Based on these factors, the polynomial that graph crosses the x-axis at only one point is A. f ⁡ ( x ) = x ³ − 7 ⁢x² + 3 ⁢x − 21

A polynomial in mathematics is a mathematical statement made up of variables (also known as indeterminates) and coefficients that only include the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

Polynomials are a fundamental algebra topic that is used in many areas of mathematics. A polynomial's degree is the largest exponent of the variable x in the expression. The correct option is A.

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For the function h(x) the values of h(x) when x=0,1,2,3,4,5 are 5, 9, 13,17,21,25 respectively

The given function is h(x) 4x+5

h of x equal to four times of x plus five

We have to find the values of h(x) for different values of x

x=0, h(x) = 5

x=1, h(x)=9

x=2, h(x)=13

x=3, h(x)=17

x=4, h(x)=21

x=5, h(x)=25

Hence, for the function h(x) the values of h(x) when x=0,1,2,3,4,5 are 5, 9, 13,17,21,25 respectively

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Sample Response/ Explanation: The data sets could be the same, but not necessarily. It is possible for data sets to differ in their spread but still have the same measures of center. The measures of spread could be different.

The data sets could be the same, but not really. It is possible for the data sets to differ in their spread but still have the same measures of center. The measures of spread could be different though.

I am not able to create visual content such as an ERD diagram, but I can guide you through the process of creating an ERD for Happy Motor's purchasing department based on the functional description provided.

First, let's identify the entities in the description:

Department (with attributes: department code, name, email)

Vehicle Type (which is produced by each department)

Component (with attributes: component code, name, price)

Vendor (with attributes: vendor code, name, email)

Order (with attributes: order number, date, total amount)

Next, let's identify the relationships between the entities:

Each department produces one or more types of vehicles

Each vehicle type requires at least one or more different specific components

Each department makes orders to buy components from vendors

Each vendor provides one or more types of components

Each order contains several different components, but all components should be from the same vendor

Each component is provided by a specified vendor

An inventory is maintained to keep track of the quantity on hand (QOH) for each component

Based on these relationships, we can create an ERD with the following entities and relationships:

Department (department code, name, email) with a one-to-many relationship with Vehicle Type

Vehicle Type (vehicle type code, name) with a many-to-many relationship with Component

Component (component code, name, price) with a many-to-one relationship with Vendor

Vendor (vendor code, name, email) with a one-to-many relationship with Component and Order

Order (order number, date, total amount) with a many-to-many relationship with Component

To show the inventory relationship, we can add an attribute to the Component entity for QOH.

Note that this is just a general outline of the ERD, and there may be additional details that need to be considered based on the specific requirements of Happy Motor's purchasing department.

To represent the inventory maintained for each component, the Component entity would have an attribute for quantity on hand (QOH).The ERD for Happy Motor® purchasing department would have the following entities and relationships:

Entities:
1. Department - with attributes: department code (PK), name, email
2. Vehicle Type - with attributes: type code (PK), name
3. Component - with attributes: component code (PK), name, price
4. Vendor - with attributes: vendor code (PK), name, email
5. Order - with attributes: order number (PK), date, total amount
Relationships:
1. Department orders Component - one-to-many (1:N) relationship between Department and Component
2. Component belongs to Vehicle Type - many-to-one (N:1) relationship between Component and Vehicle Type
3. Component is provided by Vendor - many-to-one (N:1) relationship between Component and Vendor
4. Order contains Component - many-to-many (M:N) relationship between Order and Component
5. Order is placed by Department - many-to-one (N:1) relationship between Order and Department
6. Order is placed with Vendor - many-to-one (N:1) relationship between Order and Vendor
Additionally, to represent the inventory maintained for each component, the Component entity would have an attribute for quantity on hand (QOH).

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Answer:

  (d)  180° clockwise rotation

Step-by-step explanation:

Given points A(-2, -7), B(3, -2), C(2, -10) and A'(2, 7), B'(-3, 2), C'(-2, 10), you want to know the angle and direction that rotates ∆ABC to ∆A'B'C'.

We notice the signs of each of the coordinates of ABC have been reversed for the coordinates A'B'C'. For example, A(-2, -7) became A'(2, 7).

A line joining these points is a straight line through the origin. The measure of its angle at the origin is 180°. This is the angle of rotation of A'B'C' with respect to ABC.

The image is created by 180° clockwise rotation, choice D.

__

Additional comment

When rotation is 180°, the direction is immaterial. A clockwise rotation gets you to the same place as a counterclockwise rotation.

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Answer:

7

Step-by-step explanation:

a= a+b/2*h