i need help with the problem below

Answer:

About 3.47kg

Explanation:

Recall that weight is equal to mass times acceleration.

In this case, our acceleration is due to gravity which on earth is about 9.8m/s/s

So we have 34N=9.8 *mass, divide both sides by 9.8 we get mass is equal to about 3.47kg.

Answer:

10 N to the left.

Explanation:

Since the forces are acting in opposite directions, you need to calculate the difference.

20 N - 10 N = 10 N

More force is being exerted to the left. Therefore, the net force is 10 N to the left.

Answer:

Forces can be divided into primarily into two types of forces:

Explanation:

Answer:

Explanation:

Let x be the leaf spring compression distance

F = kx

5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x - 0.500)

5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x) - 1.90 x 10⁵

7.10 x 10⁵ = (9.25 x 10⁵)x

x = 0.76756...

x = 0.768 m

W = ½(5.45 x 10⁵)0.768² +  ½(3.80 x 10⁵)(0.768 - 0.500)²

W = 174,148.648648...

W = 174 KJ

Answer:

when the ball is at its highest point

Explanation:

Provided the ball returns to where it was thrown. The velocity, and therefore kinetic energy, will be momentarily zero at the highest point of the throw.

Answer: they have one path to flow

Explanation: share the same current

The speed of the cannon after firing is 1.2 m/s

This can be solved using the law of conservation of momentum.

From the law of conservation of momentum,

⇒ The momentum of the projectile is equal to the momentum of the cannon.

⇒ Where :

⇒ make V the subject of the equation

From the question,

⇒ Given:

⇒ Substitute these values into equation 2

Hence, The speed of the cannon after firing is 1.2 m/s

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The initial velocity of the 3250 Kg mass is 2.1 m/s. The distance covered by the larger mass in 5s is 4.7 cm.

In this problem, we have to apply the law of conservation of linear momentum. Note that;

Momentum before collision = Momentum after collision

m1u1 + m2u2 = m1v1 + m2v2

(2150 × 10) + (3250u1) = (2150 + 3250)5.22

21500 + 3250u1 = 5400 × 5.22

3250u1  = 28188 - 21500

u1 = 28188 - 21500/3250

u1 = 2.1 m/s

2) Again from the principle of conservation of linear momentum;

(0.40 × 3.5) + (0.60 × 0) = (0.40  × 0.70) + (0.60 × v2)

1.4 = 0.28 + 0.60v2

1.4 - 0.28 =  0.60v2

v2 = 1.87 cm/s

Using;

s = 1/2 ( u + v)t

s = 1/2(0 + 1.87) × 5

s = 4.7 cm

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[tex]\large\huge\green{\sf{Yes}}[/tex]

Answer:

strong nuclear force.

Explanation:

hope this helps you!!

An LED is useful because when a current passes through it, it gives out light.

An LED is useful because when a current passes through it, it gives out Light.

LED, in full light-emitting diode, in electronics, a semiconductor device that emits infrared or visible light when charged with an electric current.

A light-emitting diode (LED) emits light by applying a forward current to the pn junction of a compound semiconductor.

When forward current is passed through the light-emitting diode, carriers (electrons and holes) move. The holes in the p-type region move to the n-type region and the electrons in the n-type region move to the p-type region. The injected carriers recombine, and the energy difference before and after recombination is released as light. The emitted light depends on the energy band gap (Eg) of the compound semiconductor.

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The final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

The given parameters;

The initial momentum of the boy is calculated as follows;

[tex]P_y = m_1 u_1\\\\P_y = 25 \times 5\\\\P_y = 125 \ kgm/s \ \ north[/tex]

The initial momentum of the snowball is calculated as follows;

[tex]P_x = m_2 u_2\\\\P_x = 1 \times 15 \ \\\\P_x = 15 \ kgm/s \ \ west[/tex]

The resultant momentum of the boy and the snowball after collision is calculate as follows;

[tex]P_f = \sqrt{P_y^2 + P_x^2} \\\\P_f = \sqrt{125^2 + 15^2} \\\\P_f = 125 .9 \ kgm/s[/tex]

The final velocity of the system boy-snowball system is calculated as;

[tex]v_f(m_1 + m_2)= P_f\\\\v_f = \frac{P_f}{m_1 + m_2} \\\\v_f = \frac{125.9}{25 + 1} \\\\v_f = 4.84 \ m/s[/tex]

The direction of the boy after the collision is calculated as follows;

[tex]\theta = tan^{-1}(\frac{v_y}{v_x} )\\\\\theta = tan^{-1} (\frac{5}{15} )\\\\\theta = 18.4 \ ^0[/tex]

Thus, the final velocity of the boy after the collision with snowball is 4.84 m/s at 18.4⁰ north-east

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Answer:

good nutrition

Explanation:

I think that one's pretty self explanatory

Answer:

To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.

Compression force can be measured with a force gage or load cell. 

Answer:

When the tides are especially weak, it is called a NEAP tide.

Explanation:

Hope this helps :)

Answer:

Neap

Explanation:

Answered!

Answer:

D) 8

Explanation:

Due to the octet rule the most stable atoms will have 8 valence electrons.

Answer:

Explanation:

Potential energy gets converted to rotational kinetic energy

a)         ½Iω² = mgh

½(mL²/3)ω² = mgL/2

       (L/3)ω² = g

              ω = [tex]\sqrt{3g/L}[/tex]

       v(CG) = (L/2) [tex]\sqrt{3g/L}[/tex]

Not sure if you wanted angular speed or tangential speed of the CG so I gave both.

b) v = Rω =  L [tex]\sqrt{3g/L}[/tex]

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

[tex]f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz[/tex]

The angular frequency of the oscillation is calculated as follows;

[tex]\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s[/tex]

The force constant of the spring is calculated as follows;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m[/tex]

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The mass of block 1 will be 1.99 kg.The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given that,

Mass of block 1=? kg

The coefficient of the kinetic friction,μ=0.200

Now consider the weight component in the uphill direction.The weight is found as;

[tex]\rm W=m_1gsin \theta[/tex]

The force is balanced in the vertical direction as;

[tex]\rm T=F_f-W[/tex]

When the force of friction is;

[tex]\rm F_F=\mu_k N[/tex]

[tex]\rm F_f=(m_1 gcos \theta)[/tex]

Substitute the value in the vertical balanced equation;

[tex]\rm T=m_1gsin(27.5)^0-\mu_kmgcos27.5^0[/tex]

[tex]\rm T-m_2g=0\\\\T=m_2g[/tex]

[tex]\rm (10.1) g=m_1g(0.699-0.2 \times(-0.714) ) \\\\ (10.1) g=m_1g (0.699+0.1428) \\\\\ (10.1) g= m_1 \times 0.8418 \\\\ m_1 =11.99 \ kg[/tex]

Hence the mass of block 1 will be 1.99 kg.

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Answer:

Explanation:

The net work will change the kinetic energy

W = ½mv² = ½m(at)² = ½ma²t²

W = ½(7.7)2.6²(18.5²) = 8907.3985 = 89 kJ

Hi there!

We can use the work-energy theorem to solve.

Recall:

[tex]\large\boxed{E_i = E_f}}[/tex]

Initial energy = final energy

The initial energy is purely potential (she starts from rest), and, if we assign the bottom of the slope as the 0 line, her energy at the bottom is purely kinetic.

PE = mgh

KE = 1/2mv²

We can begin by setting the two equal:

mgh = 1/2mv²

Cancel out the mass and rearrange to solve for velocity:

2gh = v²

v = √2gh

Plug in given values and use g ≈ 10 m/s²:

v = √2(10)(20) = 20 m/s

Answer:

Give me some hint please

Based on the calculations, potential energy of this roller coaster at a height of 75 meters is equal to 588,000 Joules.

Mathematically, potential energy is calculated by using this formula:

P.E = mgh

Where:

Note: Acceleration due to gravity is equal to 9.8 m/s².

At a height of 75 m, we have:

P.E = 800 × 9.8 × 75

P.E = 588,000 Joules.

At a height of 60 m, we have:

P.E = 800 × 9.8 × 60

P.E = 470,400 Joules.

At a height of 45 m, we have:

P.E = 800 × 9.8 × 45

P.E = 352,800 Joules.

At a height of 30 m, we have:

P.E = 800 × 9.8 × 30

P.E = 235,200 Joules.

At a height of 15 m, we have:

P.E = 800 × 9.8 × 15

P.E = 117,600 Joules.

In conclusion, we can deduce that the potential energy of this roller coaster decreases with a decrease in height.

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An object which has more electron than proton is negatively charged, otherwise positively charged. Every statement is false

Atom is the smallest unit of the matter consist of the positive charged nucleus and the electrons which moves around it. The atom can not be divided further.

The atom of a matter is made by three elements-

For the Protons and neutrons, lets check all the statement wheather they are true or false.

Thus, every statement is false as a object which has more electron than proton is negatively charged, otherwise positively charged.

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Answer:true

Explanation:

Answer:

Explanation:

Well which is it ? ρ = 1000 kg/m³ or ρ = 1025 kg/m³?

Obviously the sea is salt water so we can ignore  ρ = 1000 kg/m³

1025 kg/m³(d  m)(9.81 N/kg) = 1 x 10⁵ N/m² = Pa

d = 9.9450535...

d = 10 meters

That's if we only account for the pressure due to the water. On top of that pressure would be atmospheric pressure which is about 101000 Pa

so the robot would be a hair above its pressure limit before it even got in the water.

Answer:

the last one

Explanation: