How would the photographer use the polarizing filter to find out the direction of polarization of the light coming from the blue sky?

Answer:

F' = 100 F/r²

Explanation:

The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:

F = Gm₁m₂/r²

where,

F = Force between objects

G = Universal Gravitational Constant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects = 10 m

Therefore,

F = Gm₁m₂/10²

Gm₁m₂ = 100F   --------------------- equation (1)

Now, we consider these objects at any distance r apart. So, the force becomes:

F' = Gm₁m₂/r²

using equation (1), we get:

F' = 100 F/r²

So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.

The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,

[tex]P=\frac{GMm}{r^2}[/tex]

M and m are the masses

r is the distance between the masses

If the force between objects that are 10 meters apart, hence;

[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]

To find the force between objects that are any distance apart, we will use the same formula above to have;

[tex]P'=\frac{GMm}{r^2}\\[/tex]

Substitute the result above into the expression to have:

[tex]P'=\frac{100P}{r^2}[/tex]

Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

Learn more on gravitational law here: https://brainly.com/question/11760568

Answer:

A mixture is when two or more substances combine physically together.

However, in water, two hydrogen atoms combine with one oxygen atom chemically, forming a new substance that has properties different from hydrogen alone or oxygen alone.

Explanation:

Answer:

2.51 m/s

Explanation:

Given that,

Angular speed of a fan, [tex]\omega=0.5\ rev/s = 3.14\ rad/s[/tex]

Length of the fan arm, r = 0.8 m

We need to find the speed of a point on the end of the fan arm at this time. Let v is the speed. It is given in terms of angular speed is given by :

[tex]v=r\omega\\\\v=0.8\times 3.14\\\\v=2.51\ m/s[/tex]

So, the required speed is 2.51 m/s.

We are given:

Mass of the Paint bucket (with paint) = 7000 grams

Mass of the paint bucket (without paint) = 500 grams

Volume of Paint in the Bucket = 5000 cm³

Mass of Paint in the Bucket:

To get the mass of the paint in the bucket, we will subtract the mass of the bucket from the mass of the paint bucket (with paint)

Mass of Paint = Mass of Paint bucket (with paint) - Mass of the paint Bucket (without paint)

Mass of Paint = 7000 - 500

Mass of Paint = 6500 grams

Density of the Paint:

We know that density = Mass / Volume

Density of Paint  = Mass of Paint / Volume occupied by Paint

Density of Paint = 6500/5000

Density of Paint = 1.3 grams / cm³

Answer:

Explanation:

v = u + at

v is final velocity , u is initial velocity , a is acceleration and t is time .

here v = 0 , u = 13 m /s , t = 14 s

putting the values

0 = 13 + 14 a

a = 13 / 14 m /s²

= - .9286

= -  0.929 m /s²

Answer:

The same as

Explanation:

First of all, they are in a merry go round, which is a circular one. And thus, we would be dealing with circular motions.

The angular velocity of a merry go round, in this instance, is given by

w = Δ/Δt

The formula has nothing whatsoever to do with distance, and as such, both Rasheed and Sofia would have the same angular velocity.

Transferring this further, the angular acceleration is given as

α = Δw/Δt

Remember I said the velocity has nothing to do with distance, well, so does the acceleration as we can see from the formula stated. And therefore, both Rasheed and Sofia would have the same angular acceleration

Answer:

Vertical velocity = 8.28 m/s

Horizontal velocity = 28.3 m/s

__________________________________________________________

We are Given:

Initial velocity of the ball = 40 m/s

Angle of elevation of the ball = 45°

Time interval = 2 seconds

__________________________________________________________

Vertical and Horizontal Components:

Vertical Component:

The vertical component of the ball can also be written as:

40*Sin(45°)

40*(1/√2)                                                          [since Sin(45°) = 1/√2]

40/√2 m/s

Horizontal Component:

The horizontal component of the ball can also be written as:

40*Cos(45°)

40*(1/√2)                                               [Since Cos(45°) = 1/√2]

40/√2 m/s

__________________________________________________________

Speed of the Ball after 2 seconds:

Horizontal Velocity:

Since the horizontal velocity is not affected by any force during the flight, the horizontal velocity after 2 seconds will also be 40/√2 m/s

Since √2 = 1.41:

Horizontal velocity = 28.3 m/s

Vertical Velocity:

v = u + at                            [First equation of motion]

v = 40/√2 + (-10)(2)          

[g is negative because it is acting against the direction of motion]

v = 40/√2 - 20

v = [tex]\frac{40-20\sqrt{2} }{\sqrt{2} }[/tex]                          [taking the LCM]

v = 8.28 m/s                    [√2 = 1.41]

Answer:

B. soft tissue injuries

Explanation:

i took the test on edge and its really the only one that would make sense if you payed attention to the lesson  :)

Answer:

the war of currents is

Explanation:

The war of currents was a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s.

Answer:

a series of events surrounding the introduction of competing electric power transmission systems in the late 1880s and early 1890s

Explanation:

Answer:

3.) 0.3 m

Explanation:

Given parameters:

Torque  = 40Nm

Force = 133N

Unknown:

Distance from the nut that the mechanic must apply the force  = ?

Solution:

Torque is the force that causes an object to rotate on its axis;

  Torque  = force x distance

   Distance  = [tex]\frac{40}{133}[/tex]  = 0.3m

Answer: C

Explanation:

The characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helps to answer is:

           D) Are there more galaxies beyond the milky way

Telescopes are instruments that can perceive very small amounts of light and have very large magnifications, in general to be able to see objects increasingly weak in intensity, telescopes become larger and the observation times of the object increase.

When we increase the observation times, the problem is that atmospheric movement changes the observation conditions and makes it difficult to obtain good images. One way to solve the problem was with telescopes in near space, the environmental disturbance is eliminated.

When the Hubble telescope was placed in space, there were already many answers but they continue to wonder what the limit of the universe is, this telescope allowed us to observe a body much farther away than ground-based telescopes, which is why it answered the question how many and to where there are galaxies out of the milky way.

Let's review the statements given to see the correct ones;

A) False. Copernicus clarified that the Sun is the center of the solar system

B) False. The center of the universe is not known, but the sun is a star in one of the arms of the milky way that is not the center of the universe either.

C) False. It has been known for a century what the movement of the planets in the solar system

D) True. The telescope in space allowed us to expand the limit of vision of the universe and respond to where there are galaxies outside the Milky Way.

In conclusion with the characteristics and problems of telescopes we can find the correct answer to the question that the Hubble telescope helped to answer is:

      D) Are there more galaxies beyond the milky way

Learn more here:  brainly.com/question/16319804

Answer:

A

Explanation:

The image formed by the concave mirror is always virtual. An enlarged image is caused when the concave mirror is positioned too near to the object.

When a hollow spherical is divided into pieces and the exterior surface of each cut portion is painted, it forms a mirror, with the inner surface reflecting the light.

A concave mirror is a name for this sort of mirror. An enlarged and fake image is caused when the concave mirror is positioned too near to the object.

When the distance between the item and the mirror is increased, however, the size of the image decreases, and a true picture is generated.

The picture created by the concave mirror may be manipulated. The image formed by the concave mirror is always virtual.

Hence, option A is correct.

To learn more about the concave mirror, refer to the link;

https://brainly.com/question/25937699

#SPJ2

Answer:

The answer is "[tex]5.06 \times 10^{-6} \ kg \ m^2[/tex]"

Explanation:

[tex]\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh= mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}[/tex]

       [tex]= 5.06 \times 10^{-6} \ kg \ m^2[/tex]

The measurement of length and time is calculated the average speed with the expression

         [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]

Average velocity is defined as the change in displacement between the interval time

      [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]

where [tex]v_{avg}[/tex] is the average velocity, Δx is the displacement in the interval, and Δt the time.

To carry out this measurement, it must be taken into account that the velocity is a vector, for which we define a reference system, it can be a vertical axis with the upward direction as positive, therefore the downward displacement is negative.

A tape measure is placed and the interval during which the scalar distance measurement is performed is defined, the most as is to use time as an independent variable (controlled by the researcher) that is measured with a stopwatch.

The displacement is measured for each given time interval and these two quantities are divided. The sign of the velocity is negative because it goes down

Using the measurements of length and time, the average velocity is calculated with the expression

         [tex]v_{avg} = \frac{\Delta x}{\Delta t}[/tex]t

learn more about average speed here:  brainly.com/question/17277454

Answer:

f= ma

Explanation:

v-u/ t

30-0/10

3m/s

maas 1500

1500*3

4500

Answer:

a. Please see the attached graph and drawing combined created with Microsoft Excel

b. Approximately 3.2217 m/s

c. Approximately 14.0 m/s  

d. Approximately 11.05 meters

Explanation:

a. The given parameters are;

The height of the wall, h = 10.0 m

The distance from the base of the wall the car lands = 4.60 m

The time, t, it takes the car to land is given by the equation for free fall as follows;

h = 1/2·g·t²

Where;

g = The acceleration due to gravity = 9.81 m/s²

From the equation for free fall, we have;

h/(1/2·g) = t²

∴ t = √(h/(1/2·g) ) = √(10/(1/2·9.81) ) ≈ 1.4278

The time it takes the car to land, t ≈ 1.4278 seconds

b. The horizontal speed of the car = Horizontal distance/(Time) = 4.6/1.4278 ≈ 3.2217 m/s

The horizontal speed of the car before it drives off the wall  ≈ 3.2217 m/s

c. The car's vertical speed just before impact is given by the following equation;

v = u + gt

Where;

u = The initial vertical speed = 0

t = The time it takes before impact ≈ 1.4278 seconds

∴ v = 9.81 × 1.4278 ≈ 14.0 m/s  

The car's vertical speed just before impact, v ≈ 14.0 m/s  

d. Whereby the car is subject to the gravitational field of the moon, we have;

Gravitational force per kilogram = 1.7 N/kg

∴ Gravitational acceleration = 1.7 m/s².

The time it takes the car to land whilst subject to the gravitational field of the moon is therefore;

[tex]t_{Moon}[/tex] = √(h/(1/2·g)) = √(10/(1/2 × 1.7)) ≈ 3.43

[tex]t_{Moon}[/tex] ≈ 3.43 seconds

The horizontal distance covered, at the car's horizontal speed in the time of free fall ≈ 3.2217 m/s ×  3.43 seconds ≈ 11.05 meters

The horizontal distance covered, at the car's horizontal speed in the time of free fall  = The distance the car will land from the base of the wall ≈ 11.05 meters

The distance the car will land from the base of the wall ≈ 11.05 meters.

Answer:

Non-zero digits

Explanation:

umm (ꏿ﹏ꏿ;)

Answer:

There's three rules on determining how many important quantities are in a number: Non-zero digits are always predominant. Any zeros between two significant digits are always major. The final zero or dangling zeros in the decimal segment are really only important.

I hope this answered your question, have a nice day!

Answer:

T = 12732 [N]

Explanation:

To solve this problem we must use newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

By means of the attached free body diagram, we can better understand the solution to this problem.

As we see in the diagram the tension Force T lifts the car upwards so the movement is upwards. Therefore we have two forces one upward (positive) of the force T and the other negative downward due to the weight of the vehicle.

As the movement is up the acceleration is also up (with a positive sign).

ΣF = m*a

where:

F = forces [N] (units of Newtons)

m = mass = 1200 [kg]

a = acceleration = 0.8 [m/s²]

T - 1200*9.81 = 1200*(0.8)

T = 12732 [N]

Answer:

12,720

Explanation:

Answer:

iron nail rusting

Explanation:

AnswerAmontons's law. If the temperature is increased, the average speed and kinetic energy of the gas molecules increase. ... If the gas volume is decreased, the container wall area decreases and the molecule-wall collision frequency increases, both of which increase the pressure exerted by the gas (Figure 1).:

Explanation:

Answer:

The answer is the 4th one

Explanation:

Good luck man

Answer:

Following are the solution to this question

Explanation:

please find the complete question in the attached file.

In point a:

The answer is "bottom".

In point b:

Using formula:

[tex]T= mg + \frac{m V^2}{2}[/tex]

[tex]\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}[/tex]

[tex]\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to 100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to 98.038= \frac{0.2 + V^2}{0.5}\\\\\to 49.019=0.2+V^2\\\\\to 48.819=V^2\\\\ \to 6.987 \ \frac{m}{s}[/tex]

Explanation:

hope this answer was helpful

Answer:

The combined force of the catapult and engines is 44545.455 newtons.

Explanation:

Let suppose that platform of the aircraft carrier is horizontal, such that changes in gravitational potential energy can be neglected. In addition, effects of non-conservative forces are neglected. By using Principle of Energy Conservation and Work-Energy Theorem we find that steam catapult-jet aircraft is represented by:

[tex]K_{1}+W_{1\rightarrow 2} = K_{2}[/tex] (1)

Where:

[tex]K_{1}[/tex], [tex]K_{2}[/tex] - Initial and final translational kinetic energies of the jet fighter, measured in joules.

[tex]W_{1\rightarrow 2}[/tex] - Work done on the jet fighter due to the combined force of the catapult and engines, measured in joules.

By applying definitions of translational kinetic energy and work, we expand and simplify the equation above as follows:

[tex]F\cdot \Delta s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex]

[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot \Delta s}[/tex] (2)

Where:

[tex]F[/tex] - Combined force of the catapult and engines, measured in newtons.

[tex]m[/tex] - Mass of the jet fighter, measured in kilograms.

[tex]\Delta s[/tex] - Length of the catapult, measured in meters.

[tex]v_{1}[/tex], [tex]v_{2}[/tex] - Initial and final speeds of the jet aircraft, measured in meters per second.

If we know that [tex]m = 4000\,kg[/tex], [tex]v_{1} = 0\,\frac{m}{s}[/tex], [tex]v_{2} = 70\,\frac{m}{s}[/tex] and [tex]\Delta s = 220\,m[/tex], then the combined force of the catapult and engines is:

[tex]F = \frac{(4000\,kg)\cdot \left[\left(70\,\frac{m}{s} \right)^{2}-\left(0\,\frac{m}{s} \right)^{2}\right]}{2\cdot (220\,m)}[/tex]

[tex]F = 44545.455\,N[/tex]

The combined force of the catapult and engines is 44545.455 newtons.

The combined force of the catapult and engines is 44,545.5 N.

The given parameters;

The combined force of the catapult and engines is determined by applying work energy theorem as shown below;

[tex]W = \Delta E\\\\Fd = \frac{1}{2}m(v^2 -u^2) \\\\220F = \frac{1}{2}(4000)(70^2 - 0^2) \ \\\\220 F = 9,800,000\\\\F = \frac{9,800,000}{220} \\\\F = 44,545.5 \ N[/tex]

Thus, the combined force of the catapult and engines is 44,545.5 N.

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Answer:

Explanation:

The difference between the water level in the eudiometer tube and the water level in the beaker must be measured because we have to put into consideration, the pressure of the gases in the eudiometer tube. This said pressure of gas in the eudiometer must equal the atmospheric pressure. If or by chance, the water levels happens not to be at the same height, then this is not the case. And then, as a result, in order to account for the difference between both, while also being able to get accurate results, you have to find the difference or subtract the water levels and then go ahead in converting them to mmHg.

Answer: Multiply the time by the acceleration due to gravity to find the velocity when the object hits the ground. If it takes 9.9 seconds for the object to hit the ground, its velocity is (1.01 s)*(9.8 m/s^2), or 9.9 m/s.

Explanation:

Answer:

I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.

Explanation:

pls vote brainliest