How many proportional relationships are shown in the coordinate plane below? Please answer quick i will give 35 points

Answer:

5.625 inches

Step-by-step explanation:

Given that:

Total Rainfall in inches (P) = 8 inches

The runoff volume (in inches) Q = ???

The curve number CN = 80

Recall that: The runoff volume can be calculated by using the formula:

[tex]Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}[/tex]    for P > 0.2S

Q = 0                     for P < 0.2S

[tex]S = \dfrac{1000}{CN}-10[/tex]

where:

curve number CN = 80

[tex]S = \dfrac{1000}{80}-10[/tex]

S = 2.5 inches

Since the rainfall (P) is greater than 0.25

Then:

[tex]Q = \dfrac{(P-0.2S)^2}{(P+0.8S)}[/tex]  

[tex]Q = \dfrac{(8-0.2(2.5))^2}{(8+0.8(2.5))}[/tex]

[tex]Q = \dfrac{(8-0.5)^2}{(8+2)}[/tex]

[tex]Q = \dfrac{(7.5)^2}{(10)}[/tex]

[tex]Q = \dfrac{(56.25)}{(10)}[/tex]

Q = 5.625 inches

Thus, the runoff volume = 5.625 inches

Answer:

p = -4.33636363636

Step-by-step explanation:

subtract 2.2 from -4.001 which equals -4.001-2.2=-6.201 and divide -6.201 by 1.43p and that equals -4.33636363636 so p = -4.33636363636

Answer:

the last 1

Step-by-step explanation:

Answer:

Given that;

There are three high schools, each having four sections of every 24 students

the 2 types of instructions are Standard curriculum  & computer based curriculum

a)

this study is experimental

this is because the study did not just observe the student's performance but randomly assign the performance to different techniques that have some certain control over the technique of teaching and then observe their performance afterwards

b)

-important  factors are; high schools, instruction type and scores

- Highschool has 2 levels: level one there are three high schools,  level 2 each having four sections of every 24 students

-instruction type: has one level which is  divided into two namely; standard base and computer based

Scores: doesn't have levels

c)

there are 3 schools and 4 sections  so the factor high school has between subjects components

factor instruction type also has between subjects because there are two different types available

there are 24 students in each section which are within subjects

d)

the score on the test  is the dependent measures

e)

“STUDENT” in each section is he basic experiment unit of study

Answer:

C

Step-by-step explanation:

1 back, 3 up.

Answer:

The answer is...

f(x)=(x-3)+(x+3)

I think this is the answer. I haven't done this kind of math in a while so...

The chosen equation, (x +3)(x + 3) = 0, will serve as a representation of the provided graph.

ax²+bx+c=0, with a not, equals 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

given a Graph of a quadratic equation.

Contrarily, parabolas are used to graph quadratic equations. In other words, the data will be displayed as either an "open" or "upside-down" U-shaped curve. The graph is always quadratic if you are drawing a graph from a function and the equation involves x².

in this graph, we can observe that graph has only one root at x = -3

therefore the equation of the Given parabola is

(x + 3)² = 0

or

(x +3)(x + 3) = 0

therefore, the equation choice could represent the graph given will be (x +3)(x + 3) = 0.

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Answer:

12.2 12.3 12.4 12.5

Step-by-step explanation:

Answer:

Angle 9 and Angle 8 they are the same

Step-by-step explanation:

Answer:

1,2,5

Step-by-step explanation:

Answer:

t=8

Step-by-step explanation:

400 divided by 50 hopefully that helps with your question

Step-by-step explanation:

In 1/10 of 1hr = 1/2 mile

10*(1/10) of 1hr = 10(1/2) mile

(10/10) of 1hr = (10/2) mile

1 of 1hr = 5mile

It says, he can run 5 miles in 1 hour

Answer:

b

Step-by-step explanation:

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Step-by-step explanation:

Denote the events as follows:

F = a person with fibromyalgia

R = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

[tex]P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}[/tex]

            [tex]=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183[/tex]

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Answer:

(-3,3)

Step-by-step explanation:

Answer and Step-by-step explanation:

Please find attached

Answer:

Yes blue liquid is toxic

Step-by-step explanation:

H0: p1 = p2

H1: p1>p2

For blue

We calculate proportion as

37/40 = 0.925

For white

9/40 = 0.2250

To get p

(X1 + x2)/(n1 + n2)

= 0.5750

After calculating the z as statistic (please check attachment) I got 6.33

P value = 0.0000

We reject null hypothesis and say in conclusion that enough evidence exists for us to say blu liquid is toxic!

Thank you!

Answer:

Step-by-step explanation:

Inequality: (x-1)(x+2)(2x-7)≤0

If we solve the corresponding equation (x-1)(x+2)(2x-7)²= 0, we get roots

We need to consider the following 4 intervals:

1st interval (−∞; −2)

2nd interval  [−2; 1]

3rd interval (1; 3.5)

4th interval

So, the answer to the inequality is:

Answer:

(f - g)(x) = -x - 6

(f + g)(x) = 3x - 4

(f*g)(4) = -9

Step-by-step explanation:

These are your equations:

f(x) = x - 5

g(x) = 2x + 1

To find (f - g)(x), subtract g(x) from f(x).

(f - g)(x) = x - 5 - (2x + 1)

(f - g)(x) = x - 5 - 2x - 1

(f - g)(x) = -x - 5 - 1

(f - g)(x) = -x - 6

To find (f + g)(x), add f(x) with g(x).

(f + g)(x) = x - 5 + 2x + 1

(f + g)(x) = 3x - 5 + 1

(f + g)(x) = 3x - 4

To find (f*g)(4), you need to first find (f*g)(4).  You can do this by multiplying f(x) wih g(x).

(f*g)(x) = (x - 5)(2x + 1)

(f*g)(x) = 2x² - 9x - 5

Now that you have (f*g)(x), solve with x as 4.

(f*g)(4) = 2(4)² - 9(4) - 5

(f*g)(4) = 2(16) - 9(4) - 5

(f*g)(4) = 32 - 36 - 5

(f*g)(4) = -9

The required expression for (f-g)(x), (f+g)(x) and (fg)(4) are given as 3x - 4, -x - 6 and 11.

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

Here,
f(x)=x-5
g(x) = 2x+1

According to the question,
[f + g ](x) = x - 5 + 2x + 1 = 3x - 4

[f + g ](x) =  3x - 4

[f - g ](x) =  x - 5 - 2x - 1
[f - g ](x) = -x - 6

(f.g)(x) = (x - 5)(2x + 1)
(f.g)(x) = 2x² -4x -5

(f.g)(4) = 2[4]² - 4[4] - 5
         = 32 - 16 - 5
         = 11
(f.g)(4) = 11

Thus, the required expression for (f-g)(x), (f+g)(x) and (fg)(4) are given as 3x - 4, -x - 6 and 11.

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Answer:

163

Step-by-step explanation:

Answer:

3890000000

Step-by-step explanation:

Answer:

=130

Step-by-step explanation:

(2x) (5x+5) = 180

7x + 5 = 180

7x = 175

x = 25

5(25) + 5 = 125 + 5 = 130

Hope this helps (:

Answer:

The probability is   [tex]P(X  >300 ) = 0.97219 [/tex]

Step-by-step explanation:

From the question we are told that

 The capacity of  an Airliner  is  k =  300 passengers

 The sample size n =  320 passengers

  The probability the a randomly selected passenger shows up on to the airport

    [tex]p = 0.96[/tex]

Generally the mean is mathematically represented as

    [tex]\mu  =  n*  p[/tex]

  => [tex]\mu  =  320 *  0.96[/tex]

    => [tex]\mu  = 307.2[/tex]

Generally the standard deviation is  

    [tex]\sigma =  \sqrt{n *  p *  (1 -p ) }[/tex]

=>  [tex]\sigma =  \sqrt{320  *  0.96 *  (1 -0.96 ) }[/tex]

=> [tex]\sigma =3.50 [/tex]

Applying Normal approximation of binomial distribution

Generally the probability that there will not be enough seats to accommodate all passengers is mathematically represented as

  [tex]P(X  > k ) =  P( \frac{ X -\mu }{\sigma }  >  \frac{k - \mu}{\sigma } )[/tex]

Here [tex]\frac{ X -\mu }{\sigma }  =Z (The \ standardized \  value \  of  \ X )[/tex]

=>[tex]P(X  >300 ) =  P(Z >  \frac{300 - 307.2}{3.50} )[/tex]

Now applying  continuity correction we have

    [tex]P(X  >300 ) =  P(Z >  \frac{[300+0.5] - 307.2}{3.50} )[/tex]    

=>    [tex]P(X  >300 ) =  P(Z >  \frac{[300.5] - 307.2}{3.50} )[/tex]

=>    [tex]P(X  >300 ) =  P(Z >  -1.914 )[/tex]

From the z-table  

    [tex]P(Z >  -1.914 ) =  0.97219[/tex]

So

    [tex]P(X  >300 ) = 0.97219 [/tex]

Answer:

I believe c

Step-by-step explanation:

I believe this because if you invest in stock for ten years as on this paragraph the answer is C

Option D is correct. we worth more than $2000 after 10 year period.

percentage, a relative value indicating hundredth parts of any quantity.

Given that  You invest $1,000 in a stock market index fund that earns 8% compounded annually over a 10-year period.

We have to find the  investment be worth after this 10-year period.

A=P(1+r)ⁿ

P is the initial amount

r is rate of interest

n is the time

A=1000(1+0.08)¹⁰

A=1000(1.08)¹⁰

A=1000×2.1589

A=2158.9

Hence, option D is correct. we worth more than $2000 after 10 year period.

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Answer:

6 primos de dos cifras(casos favorables) / 90 numeros de dos cifras(casos posibles) = 1/15

Step-by-step explanation:

Usando el concepto de probabilidad, se encuentra que hay una probabilidad de [tex]\frac{1}{15}[/tex], opcion A, de que al escoger un número positivo de dos cifras, este sea  primo y termine en 3.

------------------------------

Entonces:

[tex]p = \frac{6}{90} = \frac{1}{15}[/tex]

Probabilidad de [tex]\frac{1}{15}[/tex], opcion A, de que al escoger un número positivo de dos cifras, este sea  primo y termine en 3.

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Answer:

11.400 dollars... is the answer

Answer:

$5400

Step-by-step explanation:

9 x 600 = 5400

Answer:

(x-14)^2+(y-3)^2=9

Step-by-step explanation:

equation of a circle is (x-h)^2+(y-h)^2=r^2

so center is (14,3) and is tangent externally means

(x-14)^2+(y-3)2=3^2

(x-14)^2+(y-3)^2=9 answer

The equation of a circle is externally tangent to the given circle and has a center at (14, 3) is [tex](x-14)^2 + (y-3)^2=9[/tex]

The standard formula for finding the equation of a circle is expressed as:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where

(a, b) is the centre

r is the radius

Given the center at (14, 3)

If the equation of a circle is externally tangent to the given circle and has a center at (14, 3), then the radius will be 3

Substitute the radius and the centre into the expression above to have:

[tex](x-14)^2 + (y-3)^2=3^2\\(x-14)^2 + (y-3)^2=9[/tex]

Hence the equation of a circle is externally tangent to the given circle and has a center at (14, 3) is [tex](x-14)^2 + (y-3)^2=9[/tex]

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x^2 = 4 py

where p<0

Step-by-step explanation:

I think this is it but I am not sure

Answer:

I think its B

Step-by-step explanation:

Forgive me if I am wrong, give me brainliest if I am right!

Answer:

a

The confidence interval for the population variance is ​[tex] 5.49 < \sigma^2 < 37.02 [/tex]  

The correct option is  C

b

The confidence interval for the population standard deviation is [tex] 2.34 < \sigma < 6.08 [/tex]

The correct option is  A

Step-by-step explanation:

From the question we are told that

    The sample size is  n =  14

    The standard deviation is  [tex]s = \$3.42[/tex]

Generally the degree of freedom is mathematically represented as

     [tex]df =  14 -1[/tex]

=>   [tex]df =  13 [/tex]    

Given that the confidence level is  98%  then that level of significance is  

     [tex]\alpha = (100 -98) \%[/tex]

=>  [tex]\alpha = 0.02[/tex]

Generally the 98% confidence interval for the variance  is mathematically represented as

     [tex]\frac{(n- 1) s^2}{x^2 _{[\frac{\alpha }{2} , df]}}  < \sigma^2 < \frac{(n- 1) s^2}{x^2 _{[1- \frac{\alpha }{2} , df]}}[/tex]

=> [tex]\frac{(14- 1) (3.42)^2}{x^2 _{[\frac{0.02 }{2} , 13]}}  < \sigma^2 < \frac{(14- 1) (3.42)^2}{x^2 _{[1- \frac{0.02 }{2} , 13]}}[/tex]

From the chi -distribution table  

     [tex]x^2 _{[1- \frac{0.02 }{2} , 13]} = 4.107[/tex]

and

    [tex]x^2 _{[\frac{0.02 }{2} , 13]} = 27.689[/tex]

So

=> [tex]\frac{(14- 1) (3.42)^2}{27.689}  < \sigma^2 < \frac{(14- 1) (3.42)^2}{4.107}[/tex]    

=> [tex] 5.49 < \sigma^2 < 37.02 [/tex]    

Generally the 98% confidence interval for the standard deviation   is mathematically represented as

   [tex]\sqrt{\frac{(n- 1) s^2}{x^2 _{[\frac{\alpha }{2} , df]}}}   < \sigma <\sqrt{ \frac{(n- 1) s^2}{x^2 _{[1- \frac{\alpha }{2} , df]}}}[/tex]

=> [tex]\sqrt{5.49}  < \sigma < \sqrt{37.02 }[/tex]

=> [tex] 2.34 < \sigma < 6.08 [/tex]