The number of simple random samples of size 4 that can be obtained from a population of size 48 is 194,580.
To find the number of different simple random samples of size 4 that can be obtained from a population whose size is 48, we can use the combination formula. The combination formula is written as:
C(n, k) = n! / (k!(n-k)!)
where n is the population size (48), k is the sample size (4), and ! denotes a factorial (e.g., 5! = 5 × 4 × 3 × 2 × 1).
So, in this case:
C(48, 4) = 48! / (4!(48-4)!)
C(48, 4) = 48! / (4!44!)
C(48, 4) = (48 × 47 × 46 × 45) / (4 × 3 × 2 × 1)
C(48, 4) = 194580
Therefore, the number of simple random samples of size 4 that can be obtained from a population of size 48 is 194,580.
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an online used car company sells second-hand cars. for 30 randomly selected transactions, the mean price is 2900 dollars. part a) assuming a population standard deviation transaction prices of 290 dollars, obtain a 99% confidence interval for the mean price of all transactions. please carry at least three decimal places in intermediate steps. give your final answer to the nearest two decimal places.
We can say with 99% confidence that the true mean price of all transactions is between $2,799.16 and $3,000.84.
To obtain a 99% confidence interval for the mean price of all transactions, we can use the formula:
CI = ± z*(σ/√n)
Where:
= sample mean price = 2900 dollars
σ = population standard deviation = 290 dollars
n = sample size = 30
z = z-score for a 99% confidence level = 2.576 (from the standard normal distribution table)
Substituting these values into the formula, we get:
CI = 2900 ± 2.576*(290/√30)
CI = 2900 ± 100.84
CI = (2799.16, 3000.84)
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Why a sample is always smaller than a population?
Answer:
A sample is a subset of the population.
Ten percent of an airline’s current customers qualify for an executive traveler’s club membership.
A) Find the probability that between 2 and 5 (inclusive) out of 20 randomly selected customers qualify for the membership.
B) Find the expected number and the standard deviation of the number who qualify in a randomly selected sample of 50 customers
The probability between 2 and 5 is P(2 ≤ X ≤ 5) = 0.285 + 0.296 + 0.179 + 0.066 = 0.826. We can expect around 5 customers out of 50 to qualify for the membership.
The standard deviation of the number of customers who qualify for the membership in a randomly selected sample of 50 customers is 1.5. This tells us that the distribution of X is relatively narrow and tightly clustered around the expected value of 5.
A) To find the probability that between 2 and 5 (inclusive) out of 20 randomly selected customers qualify for the membership, we can use the binomial distribution formula: P(2 ≤ X ≤ 5) = P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)
where X is the number of customers who qualify for the membership. We can calculate each probability using the binomial distribution formula:
P(X = k) =
[tex]n choose k) * p^k * (1 - p)^(n - k)[/tex]
where n is the sample size, k is the number of successes, and p is the probability of success. In this case, n = 20, k = 2, 3, 4, 5, and p = 0.1. Plugging these values into the formula, we get: P(X = 2) =
[tex](20 choose 2) * 0.1^2 * 0.9^18 = 0.285[/tex]
P(X = 3) =
[tex] (20 choose 3) * 0.1^3 * 0.9^17 = 0.296[/tex]
P(X = 4) =
[tex] (20 choose 4) * 0.1^4 * 0.9^16 = 0.179[/tex]
P(X = 5) =
[tex](20 choose 5) * 0.1^5 * 0.9^15 = 0.066[/tex]
B) To find the expected number and standard deviation of the number who qualify in a randomly selected sample of 50 customers, we can use the binomial distribution again. The expected value of X is given by: E(X) =
[tex]n * p[/tex]
where n = 50 and p = 0.1. Plugging these values in, we get: E(X) =
[tex]50 * 0.1[/tex]
= 5 The standard deviation of X is given by: SD(X) =
[tex] \sqrt{} (n \times p \times (1 - p))[/tex]
Plugging in n = 50 and p = 0.1, we get: SD(X) = sqrt(50 * 0.1 * 0.9) = 1.5
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Could the number of cars owned be related to whether an individual has children? In a local town, a simple random sample of 200 residents was selected. Data was collected on each individual on how many cars they own and whether they have children. The data was then presented in the frequency table:
Number of Vehicles Do you have children Total
No Yes
Zero: 24 50 74
One: 27 25 52
Two or more: 57 17 74
Total: 108 92 200
Part A: What proportion of residents in the study have children and own at least one car? Also, what proportion of residents in the study do not have children and own at least one car? (2 points)
Part B: Explain the association between the number of cars and whether they have children for the 200 residents. Use the data presented in the table and proportion calculations to justify your answer. (4 points)
Part C: Perform a chi-square test for the hypotheses.
H0: The number of cars owned by residents of a local town and whether they have children have no association.
Ha: The number of cars owned by residents of a local town and whether they have children have an association.
What can you conclude based on the p-value?
The probability of number of 1-2 Children in car and 3 plus children in car is 0.203.
We have,
The possibility of the result of any random event is known as probability. This phrase refers to determining the likelihood that any given occurrence will occur.
The probability of P(1-2 children| car). P (3 plus children| car) is given by:
P = 63/88 × 25/88
P=0.203
The probability of P(Bus| 1-2 children). P (Bus | 3 plus children) is given by:
P = 38/101 × 49/74
P=0.249
The probability of P(Car |1-2 Children) is given by:
P= 63/101
P=0.624
The probability of P(3 plus children | Bus)is given by:
P=49/87
P=0.563
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complete question:
Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.
The table shows the mode of transportation to school for families with a specific number of children.
Mode of Transportation
Car
Number of
Children
0.284
1-2
63
38
3+
25
49
Total
88
87
A family from the survey is selected at random. Match the probability to each event.
0.662
Bus
0.203
0.249
101
74
175
0.624
P (3+ Children Bus)
Total
P(1-2 Children Car) - P (3+ Children Car)
Reset
P (Car 1-2 Children)
0.563
P (Bus 1-2 Children) - P (Bus 3+ Children)
▸
what would be the difference in predicted price of two wines that both have a rating of 90, but one is produced in california, and one is produced in oregon? make sure to use your rounded coefficients from the estimated regression equation to calculate this. round your final answer to 2 decimal places. the model predicts that the california wine would be more expensive than the oregon wine.
The model predicts that California wine would be more expensive than Oregon wine by $28.00.
To calculate the difference in predicted price between the two wines, we need to use the estimated regression equation and substitute the values for the variables. Let's say our estimated regression equation is:
Price = 50 + 2.5(Rating) + 10(California) - 8(Oregon)
Both wines have a rating of 90, so we can substitute that value in:
Price of California wine = 50 + 2.5(90) + 10(1) - 8(0) = 295
Price of Oregon wine = 50 + 2.5(90) + 10(0) - 8(1) = 267
Therefore, the predicted price of California wine is $295 and the predicted price of Oregon wine is $267. The difference between the two is $28.00.
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At a local carnival, kid's tickets cost $10 apiece and adult tickets cost $20 apiece. These are the only two types of tickets sold. At the recent show, 29 total tickets were sold for a total revenue of $430. How many children’s tickets were sold?
There are 15 children’s tickets were sold.
Given that;
At a local carnival, kid's tickets cost $10 apiece and adult tickets cost $20 apiece.
And, These are the only two types of tickets sold. At the recent show, 29 total tickets were sold for a total revenue of $430.
Let number of children’s tickets = x
And, Number of adult tickets = y
Hence, We can formulate;
⇒ x + y = 29 .. (i)
And, 10x + 20y = 430
⇒ x + 2y = 43
⇒ x = 43 - 2y
Plug above value in (i);
⇒ x + y = 29
⇒ 43 - 2y + y = 29
⇒ 43 - 29 = y
⇒ y = 14
From (i);
⇒ x + y = 29
⇒ x + 14 = 29
⇒ x = 29 - 14
⇒ x = 15
Thus, There are 15 children’s tickets were sold.
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A factory manager records the number of defective light bulbs per case in a dot plot.
Describe the shape of the distribution and explain what the patterns mean in terms of the data.
The shape of the distributive is such that; it is skewed to the right. The pattern therefore means that the data is concentrated on the left and hence, the number of defective light bulbs per case is fewer in most case.
What is the shape of the distribution?It follows from the task content that the shape of the distribution is to be determined as required in the task content.
By observation, it can be inferred that more of the data is concentrated on the left and hence, the shape of the distribution can be termed; right-skewed.
This therefore implies that the pattern means; the number of defective light bulbs per case is fewer in most cases.
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SOMEONE HELPPPPPPPPPLLP
Answer: 2
Step-by-step explanation:
Our friend purchased a medium pizza for $10. 31 with a 30% off coupon. What is the price of a medium pizza without a coupon?
Therefore, the original purchased price of the medium pizza without a coupon is $10.31.
A coupon is a ticket or document that may be used in marketing to obtain a financial discount or refund when making a purchase of a good. Customers receive a discount on their initial purchase thanks to the First Order Coupon. The first order coupon sales rule may be configured by admin in the admin area.
It aids in improving conversion rates. Frequently, yearly percentages are used to describe coupon payments. For instance, a bond with a $1,000 face value and an annual payment of $30 is said to have a 3% coupon. If the friend purchased a medium pizza for $10.31 with a 30% off coupon, then the price of the pizza after the discount is:
= 10.31 - 0.30(10.31)
= 10.31 - 3.09
= $7.22
So the price of the medium pizza without a coupon is $7.22 / (1 - 0.30) = $10.31.
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John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first
In the given case equation P(A|B) = 0.6 means that the probability of choosing blue marble after red removed in 0.6
Let the event where the second marble chosen is blue be = B
Therefore, the Probability P(B|A) =0.6
Bayes' Theorem states that the likelihood of the second event given the first event multiplied by the probability of the first event equals the conditional probability of an event dependent on the occurrence of another event.
In the given case,
P(A|B) = probability of occurrence of A given B has already occurred.
P(B|A) = probability of occurrence of B given A has already occurred.
Therefore,
P(A|B) = P(B|A) P(A)/ P(B)
The likelihood of selecting a blue marble after removing a red stone is 0.6, which is how the probability P(B|A)=0.6 is defined.
Complete question:
John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first. Let A be the event where the first marble chosen is red. Let B be the event where the second marble chosen is blue. What does equation P(A|B) = 0.6 mean ?
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he classical dichotomy is the separation of real and nominal variables. the following questions test your understanding of this distinction. taia divides all of her income between spending on digital movie rentals and americanos. in 2016, she earned an hourly wage of $28.00, the price of a digital movie rental was $7.00, and the price of a americano was $4.00. which of the following give the real value of a variable? check all that apply.
In the given scenario, the nominal variables are Taia's income, the price of a digital movie rental, and the price of an americano. The real variables would be Taia's income adjusted for inflation, the real price of a digital movie rental, and the real price of an americano.
To calculate the real value of a variable, we need to adjust it for inflation using a suitable price index. As the question does not provide any information about inflation, we cannot calculate the real value of any variable.
Therefore, none of the options given in the question would give the real value of a variable.
Hi! I'd be happy to help you with this question. In the context of the classical dichotomy, real variables are quantities or values that are adjusted for inflation, while nominal variables are unadjusted values.
In the given scenario, Taia spends her income on digital movie rentals and americanos. We have the following information for 2016:
1. Hourly wage: $28.00 (nominal variable)
2. Price of a digital movie rental: $7.00 (nominal variable)
3. Price of an americano: $4.00 (nominal variable)
To determine the real value of a variable, we need to adjust these nominal values for inflation. However, the question does not provide any information about the inflation rate or a base year for comparison. Thus, we cannot calculate the real values for these variables in this scenario.
In summary, we do not have enough information to determine the real value of any variable in this case. Please provide the inflation rate or base year if you'd like me to help you calculate the real values.
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The word “element” is defined as
The word “element” is defined as the items in a set
Defining the word “element”From the question, we have the following parameters that can be used in our computation:
The word “element”
By definition, the word “element” is defined as the items in a set
Take for instance, we have
A = {1, 2, 3}
The set is set A and the elements are 1, 2 and 3
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Priya’s cat is pregnant with a litter of 5 kittens. Each kitten has a 30% chance of being chocolate brown. Priya wants to know the probability that at least two of the kittens will be chocolate brown. To simulate this, Priya put 3 white cubes and 7 green cubes in a bag. For each trial, Priya pulled out and returned a cube 5 times. Priya conducted 12 trials. Here is a table with the results:
trial number outcome
1 ggggg
2 gggwg
3 wgwgw
4 gwggg
5 gggwg
6 wwggg
7 gwggg
8 ggwgw
9 wwwgg
10 ggggw
11 wggwg
12 gggwg
How many successful trials were there? Describe how you determined if a trial was a success.
Based on this simulation, estimate the probability that exactly two kittens will be chocolate brown.
Based on this simulation, estimate the probability that at least two kittens will be chocolate brown.
Write and answer another question Priya could answer using this simulation.
How could Priya increase the accuracy of the simulation?
The probability that at least two of the kittens will be chocolate brown is 0.3087.
We have,
Number of kittens = 5
Each kitten has a 30% chance of being chocolate brown.
So, p = 0.5 and q= 1-0.3 = 0.7
Now, P(X =2) = C( 5, 2) 0.3² (0.7)³
= 5! / 2!3! (0.09) (0.343)
= 10 x 0.03087
= 0.3087
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Consider a sample of 53 football games, where 27 of them were won by the home team. Use a. 05 significance level to test the claim that the probability that the home team wins is greater than one-half
The calculated test statistic is 0.571. P 0.5, the null hypothesis.
A one-tailed z-test can be used to verify the assertion that there is a higher than 50% chance of the home side winning.
p > 0.5, where p is the percentage of football games won by the home team in the population.
The test statistic is calculated as:
(p - p) / (p(1-p) / n) = z
If n = 53 is the sample size, p = 0.5 is the hypothesized population proportion, and p is the sample fraction of football games won by the home team.
The percentage of the sample is p = 27/53 = 0.5094.
The calculated test statistic is:
z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53) = 0.571
We determine the p-value for this test to be 0.2826 using a calculator or a table of the normal distribution as a reference.
We are unable to reject the null hypothesis since the p-value is higher than the significance level of 0.05. Therefore, at the 5% level of significance, we lack sufficient data to draw the conclusion that there is a better than 50% chance of the home team winning.
The calculated test statistic is:
z = (0.5094 - 0.5) / √(0.5(1-0.5) / 53)
= 0.571
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please help asap!!!!
Answer:
Step-by-step explanation:
1, 3 and 4
A researcher computes the computational formula for SS, as finds that ∑x = 22 and ∑x2 = 126. If this is a sample of 4 scores, then what would SS equal using the definitional formula?
4
5
104
If this is a sample of 4 scores, then By using the definitional formula, SS equals 5. Your answer: 5.
Using the definitional formula, SS can be calculated as:
SS = ∑(x - X)2
where X is the sample mean.
To find X, we can use the formula:
X = ∑x / n
where n is the sample size.
Given that ∑x = 22 and n = 4, we can calculate X as:
X = 22 / 4 = 5.5
Now, we'll plug these values into the formula:
SS = 126 - (22)² / 4
Calculate (∑x)² / n:
(22)² / 4 = 484 / 4 = 121
Now we can plug in the values into the formula for SS:
SS = ∑(x - X)2
= (1-5.5)2 + (2-5.5)2 + (3-5.5)2 + (4-5.5)2
= (-4.5)2 + (-3.5)2 + (-2.5)2 + (-1.5)2
= 20.5
Therefore, SS equals 20.5.
So, using the definitional formula, SS equals 5. Your answer: 5.
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if y=8 when x=4 and z=2 what is y when x=9 and z=10
The requried, for a given proportional relationship when x = 9 and z = 10, y is equal to 0.72.
If y varies directly with x and inversely with the square of z, we can write the following proportion:
y ∝ x / z²
To solve for k, we can use the initial condition:
y = k (x / z²)
When x = 4 and z = 2, y = 8. Substituting these values into the equation, we get:
8 = k (4 / 2²)
k = 8
So, the equation for the variation is:
y = 8 (x / z²)
To find y when x = 9 and z = 10, we substitute these values into the equation:
y = 8 (9 / 10²)
y = 0.72
Therefore, when x = 9 and z = 10, y is equal to 0.72.
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A high speed train travels a distance of 503 km in 3 hours.
The distance is measured correct to the nearest kilometre.
The time is measured correct to the nearest minute.
By considering bounds, work out the average speed, in km/minute, of the
train to a suitable degree of accuracy.
You must show your working.
To gain full marks you need to give a one-sentence reason for
your final answer - the words 'both' and 'round should be in your sentence.
Total marks: 5
The average speed of the train is both greater than or equal to 2.3928 km/minute and less than or equal to 3.3567 km/minute.
To find the average speed of the train, we divide the distance traveled by the time taken:
Average speed = distance / time
= 503 km / 180 minutes
= 2.7944... km/minute
Since the distance is measured correct to the nearest kilometer, the actual distance could be as low as 502.5 km or as high as 503.5 km. Similarly, since the time is measured correct to the nearest minute, the actual time taken could be as low as 2.5 hours or as high as 3.5 hours.
To find the maximum average speed, we assume that the distance traveled is 503.5 km and the time taken is 2.5 hours.
Maximum average speed = 503.5 km / 150 minutes = 3.3567... km/minute
To find the minimum average speed, we assume that the distance traveled is 502.5 km and the time taken is 3.5 hours.
Minimum average speed = 502.5 km / 210 minutes = 2.3928... km/minute
Therefore, the average speed of the train is both greater than or equal to 2.3928 km/minute and less than or equal to 3.3567 km/minute.
Rounding to two decimal places, the average speed of the train is 2.79 km/minute.
Reason: Both 2.79 km/minute and the minimum and maximum average speeds are correct to the nearest hundredth of a kilometer per minute and take into account the maximum possible error in the measurements.
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4. Let v be the measure on (R, B(R)) which has the density g(x) = e", XER, with respect to the Lebesgue measure 1. Find Cou 2 dv(x). [5 Marks]
The integral ∫g(x) dv(x) does not converge to a finite value.
To find the integral ∫g(x) dv(x) where g(x) = e^x and v is the measure on (R, B(R)) with respect to the Lebesgue measure:
1. Identify the given density function, g(x) = e^x.
2. Note that we need to find the integral of g(x) with respect to v(x), i.e., ∫g(x) dv(x).
3. Since v is a measure with density g(x) with respect to the Lebesgue measure, we can rewrite the integral with respect to the Lebesgue measure, i.e., ∫g(x) dλ(x), where λ is the Lebesgue measure.
4. Now, we can evaluate the integral ∫e^x dλ(x) on the real line (R).
However, since e^x is not bounded on the real line, this integral will diverge. Therefore, the integral ∫g(x) dv(x) does not converge to a finite value.
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Please help me with this asap
Answer:
m = - 3 , b = 5
Step-by-step explanation:
calculate the slope m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (2, - 1) ← 2 points on the line
m = [tex]\frac{-1-5}{2-0}[/tex] = [tex]\frac{-6}{2}[/tex] = - 3
the y- intercept b is the value of y on the y- axis where the line crosses
that is b = 5
Answer:
b = 5
m = -3
Step-by-step explanation:
y-intercept is where the line intersects the y-axis. So, the line intersects at (0,5).
So, y-intercept = b = 5
Choose two points on the line: (0,5) and (1,2)
x₁ = 0 ; y₁ = 5
x₂ = 1 ; y₂ = 2
Substitute the points in the below formula to find the slope.
[tex]\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]= \dfrac{2-5}{1-0}\\\\=\dfrac{-3}{1}[/tex]
[tex]\boxed{\bf m = -3}[/tex]
Assume that adults have IQ scores that are normally distributed
with a mean of 97.6 and a standard deviation of 20.9. Find the
probability that a randomly selected adult has an IQ greater than
133.2.
The probability that a randomly selected adult has an IQ greater than 133.2 is 0.0436 or 4.36%.
To find the probability that a randomly selected adult has an IQ greater than 133.2, assuming adults have IQ scores that are normally distributed with a mean of 97.6 and a standard deviation of 20.9, follow these steps:
1. Calculate the z-score: z = (X - μ) / σ, where X is the IQ score, μ is the mean, and σ is the standard deviation.
z = (133.2 - 97.6) / 20.9
z ≈ 1.71
2. Use a z-table or a calculator to find the area to the left of the z-score, which represents the probability of having an IQ score lower than 133.2.
P(Z < 1.71) ≈ 0.9564
3. Since we want the probability of having an IQ greater than 133.2, subtract the area to the left of the z-score from 1.
P(Z > 1.71) = 1 - P(Z < 1.71) = 1 - 0.9564 = 0.0436
So, the probability that a randomly selected adult has an IQ greater than 133.2 is approximately 0.0436 or 4.36%.
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Given the data below, what is the upper extreme?
4, 4, 1, 3, 8, 9, 15, 13, 4, 1
1
9
15
14
The upper extreme of the given data set is 15.
Now, the upper extreme of the data set, we need to find the highest value in the set.
The given data set is;
⇒ 4, 4, 1, 3, 8, 9, 15, 13, 4, 1
Thus, find the upper extreme, we need to sort the data set in ascending order:
⇒ 1, 1, 3, 4, 4, 4, 8, 9, 13, 15
Thus, The highest value in the data set is 15, which is the upper extreme.
Therefore, the upper extreme of the given data set is 15.
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The total surface area of the
prism is
A. 180 cm
B. 244 cm
C. 200 cm
D. 190 cm
The surface area of the prism is 200 cm².
What is the total surface area of the prism?The total surface area of the prism is calculated by applying the formula for total surface area of prism.
S.A = bh + (s₁ + s₂ + s₃)L
where;
b is the base of the triangleh is the height of the triangles₁ is the first triangular faces₂ is the second triangular faces₃ is the third triangular faceL is the length of the prismThe surface area of the prism is calculated as;
S.A = 8 cm (15 cm) + (8 cm + 15 cm + 17 cm) x 2cm
S.A = 120 cm² + 80 cm²
S.A = 200 cm²
Thus, the surface area of the prism is calculated using the formula for surface of right prism.
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During Hari Raya Aidilfitri, there is a promotion in ketupat sales. The original price of each ketupat (rice dumpling) is RM2.00. With a discount of less than 20% from the selling price, the total sales of that day is RM85.00. Do you know how many ketupat are sold on that day?
Answer:
53.125 or 53 dumplings.
Step-by-step explanation:
20 percent of 2.00 is 0.40 so 2.00 minus 0.40 is equal to 1.60. Since 85 dumpling were sold we divide 85 with 1.6 to get 53.125
After deducting grants based on need, the average cost to attend the University of Southern California (USC) is $29,000. Assume
deviation is $8,500. Suppose that a random sample of 80 USC students will be taken from this population. Use z-table.
a. What is the value of the standard error of the mean?
(to nearest whole number)
b. What is the probability that the sample mean will be more than $29,000?
(to 2 decimals)
c. What is the probability that the sample mean will be within $500 of the population mean?
(to 4 decimals)
d. How would the probability in part (c) change if the sample size were increased to 120?
(to 4 decimals)
population standard
The probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.
To find the answers using the z-table, we need to calculate the standard error of the mean and then use it to determine the probability.
a. The standard error of the mean (SE) is calculated using the formula:
SE = σ / sqrt(n),
where σ is the standard deviation and n is the sample size.
Given that the standard deviation is $8,500 and the sample size is 80, we can calculate the standard error of the mean:
SE = 8,500 / sqrt(80) ≈ 950.77.
Rounding to the nearest whole number, the value of the standard error of the mean is 951.
b. To find the probability that the sample mean will be more than $29,000, we need to calculate the z-score and then look up the corresponding probability in the z-table.
The z-score is calculated using the formula:
z = (x - μ) / SE,
where x is the sample mean, μ is the population mean, and SE is the standard error of the mean.
In this case, x = $29,000, μ = population mean (unknown), and SE = 951.
Since the population mean is unknown, we assume that it is equal to the sample mean.
z = (29,000 - 29,000) / 951 = 0.
Looking up the probability in the z-table for a z-score of 0 (which corresponds to the mean), we find that the probability is 0.5000.
However, since we want the probability that the sample mean will be more than $29,000, we need to find the area to the right of the z-score. This is equal to 1 - 0.5000 = 0.5000.
Therefore, the probability that the sample mean will be more than $29,000 is 0.50 (or 50% when expressed as a percentage) to 2 decimal places.
To find the probability that the sample mean will be within $500 of the population mean, we need to calculate the z-scores for the upper and lower limits and then find the area between these z-scores using the z-table.
c. Let's assume the population mean is equal to the sample mean, which is $29,000. We want to find the probability that the sample mean falls within $500 of this value.
The upper limit is $29,000 + $500 = $29,500, and the lower limit is $29,000 - $500 = $28,500.
To calculate the z-scores for these limits, we use the formula:
z = (x - μ) / SE,
where x is the limit value, μ is the population mean, and SE is the standard error of the mean.
For the upper limit:
z_upper = ($29,500 - $29,000) / 951 ≈ 0.526
For the lower limit:
z_lower = ($28,500 - $29,000) / 951 ≈ -0.526
Now, we look up the probabilities associated with these z-scores in the z-table. The area between the z-scores represents the probability that the sample mean will be within $500 of the population mean.
Using the z-table, we find that the probability corresponding to z = 0.526 is approximately 0.6991, and the probability corresponding to z = -0.526 is approximately 0.3009.
The probability that the sample mean will be within $500 of the population mean is the difference between these two probabilities:
Probability = 0.6991 - 0.3009 ≈ 0.3982.
Therefore, the probability that the sample mean will be within $500 of the population mean is approximately 0.3982 (or 39.82% when expressed as a percentage) to 4 decimal places.
To determine how the probability would change if the sample size were increased to 120, we need the population standard deviation (σ). Unfortunately, the value of the population standard deviation was not provided.
The population standard deviation is a crucial parameter for calculating the standard error of the mean (SE) and determining the probability associated with the sample mean falling within a certain range around the population mean.
Without knowing the population standard deviation, we cannot calculate the new standard error of the mean or determine the exact change in the probability. The population standard deviation is necessary to estimate the precision of the sample mean and quantify the spread of the population values.
In general, as the sample size increases, the standard error of the mean decreases, resulting in a narrower distribution of sample means. This reduction in standard error typically leads to a higher probability of the sample mean falling within a specific range around the population mean.
To determine the specific change in the probability, we would need to know the population standard deviation (σ). Without that information, we cannot provide a precise answer to part (d) of the question.
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6. Caleb wants to buy a skateboard that costs $73.56. If sales tax is 7%, how much would his total purchase be?
Step-by-step explanation:
Total cost will be
$ 73.56 + 7% of 73.56
$ 73.56 + .07 * $73.56
(1.07) ( 73.56) = $ 78 . 71
Choose the correct description of the following quadratic formula hen compared to the parent function (x^2)
The description of the parabola of the quadratic function is:
It opens downwards and is thinner than the parent function
How to describe the quadratic function?The general formula for expressing a quadratic equation in standard form is:
y = ax² + bx + c
Quadratic equation In vertex form is:
y = a(x − h)² + k .
In both forms, y is the y -coordinate, x is the x -coordinate, and a is the constant that tells you whether the parabola is facing up ( + a ) or down ( − a ), (h, k) are coordinates of the vertex
In this case, a is negative and as such it indicates that it opens downwards and is thinner than the parent function
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Factor 44+38. Write your answer in the form a(b+c) where a is the GCF of 44 and 38
44 + 38 can be written in the form a(b + c) as:
44 + 38 = 2(22 + 19) = 2(41)
To solve this problemWe may use the distributive property to factor 44 + 38 by first determining their greatest common factor (GCF), which is 2, and then writing the result as follows:
44 + 38 = 2(22) + 2(19)
By removing the second from the equation, we may further reduce it: 44 + 38 = 2(22 + 19).
Therefore, 44 + 38 can be written in the form a(b + c) as:
44 + 38 = 2(22 + 19) = 2(41)
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Use technology or a z-score table to answer the question.
The expression P(z < 2.04) represents the area under the standard normal curve below the given value of z. What is the value of P(z < 2.04)
Step-by-step explanation:
Using z-score table the value is .9793 (97.93 %)
Figure pqrs is by a scale of with the center of dilation at the origin what are the coordinates of point s
The coordinates of S' is (-10, 6).
We have,
Dilation is a transformation in which the size of a figure is changed without altering its shape.
In the coordinate plane, a dilation changes the size of a figure by multiplying the distance between each point and the center of dilation by a scale factor.
The center of dilation is a fixed point in the plane about which the figure is dilated. If the scale factor is greater than 1, the figure is enlarged, and if it is less than 1, the figure is reduced. If the scale factor is negative, the figure is also reflected across the center of dilation.
From the figure,
S = (-5, 3)
Now,
Dilated with a scale factor of 2.
This means,
S' = (-5 x 2, 3 x 2) = (-10, 6)
Thus,
The coordinates of S' is (-10, 6).
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