cut the square and make it a triangle
compared to spiral galaxies, elliptical galaxies are:
flat disk like shape
________________
o0o0o0o0o0o0o0o0
A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what are the X AND Y components of the NORMAL FORCE?
Answer:
y-component = 45.75N
x-component = 0N
Explanation:
A rocket burns fuel at a rate of 239 kg/s
and exhausts the gas at a relative speed of
6 km/s.
Find the thrust of the rocket.
Answer in units of MN.
The Thrust on the rocket is 1.434 MN.
To calculate the thrust of a rocket, we use the formula below
Thrust: This is the force that moves an aircraft through the air.
⇒Formula
T = M'×v.................... Equation 1⇒ Where:
T = Thrust of the rocketM' = Fuel ejection ratev = gas exhaust velocityFrom the question,
⇒ Given:
M' = 239 kg/sv = 60 km/s = 6000 m/s⇒ Substitute these values into equation 1
T = 239(6000)T = 1434000 NT = 1.434 MNHence, the Thrust on the rocket is 1.434 MN.
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Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms as levers. Which statement describes this as a class three lever?
Question 13 options:
The wood in your hands was the fulcrum, the load your elbow, and the effort (input force) was supplied by your arm muscles.
The wood was the load in your hands, the fulcrum was your elbow and the effort (input force was supplied by your arm muscles.
The fulcrum was the muscles in your arms, the load was the wood in your hands and the effort (input force) was the elbow.
Answer: The correct answer is the weight of the wood.
Explanation:
Hope this helps
1) A plane takes off from an O'Hare runway heading due west with a speed of 210.1 m/s. Once in the air, it encounters a north wind (blowing south) with a speed of 55.0 m/s. What is the magnitude of its velocity relative to the ground?
2) What is the direction of the resulting velocity (relative to its initial direction)?
Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-
A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.
A car accelerates from 10m/s to 22m/s in 10 seconds. What is the car’s acceleration?
A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s.
Explain please.
Answer:
See attachment and below
Explanation:
A car accelerates from 10m/s to 22m/s in 10 seconds.
a = (22m/s - 10m/s)/10sec
a = 12m/s/10s
a = 1.2 m/s^2
A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s
a = 98m/s - 0m/s)/10sec
a = 9.8 m/s^2
9.8 meters/sec^2 is the acceleration due to gravity.
Where is iron made?
need help
Answer:
Explanation:
Do you mean "made" as in the element itself, or "made" as it is extracted from the Earth and refined.
====
The elements originate in the stars. The fusion reactions in Earth's sun fuse hydrogen and helium atoms to make elements, up to iron. Larger stars and powerful explosions such as supernova create the larger elements. Humans, with the use of particle accelerators make even larger elements, nearly all of which are unstable and decay rapidly into smaller elements. But their creation does offer the perk of naming rights if you can prove it was created, and don't pick a clearly untenable name.
The Fe in stardust from the sun collects in clumps via gravitational forces and, via meteorites, is carried to Earth. This is the major source for pure iron on the Earth.
Iron has chemical properties that lead to it reacting with other substances (e.g., oxygen) and then becoming concentrated in deposits as a variety of salts in the Earth's crust, as a result of natural processes. These deposits are mined and the rock is heated to separate and purify the iron metal.
A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.
The force of impact of the softball at the given conditions is 8 N.
The given parameters:
Horizontal velocity of the ball, v = 32 m/sChange in time of motion of the ball, Δt = 0.8 sMass of the ball, m = 0.2 kgThe force of impact of the softball is calculated by applying Newton's second law of motion as follows;
[tex]F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N[/tex]
Thus, the force of impact of the softball at the given conditions is 8 N.
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What is the weight of sugar if 5% of sugar from 6g of sugar
A box slides across a rough surface, eventually coming to rest.
Part A
a. Use the work-energy principle (Khan Academy:Work and the work-Energy Principle and the definition of work to explain why the box comes to rest.
b. Explain how the motion of the box is consistent with the Law of Conservation of Energy.
Answer:
he was a random act like you to be the first time I see is a great day and night to get a very happy to see you soon I hope that the world is not the same thing to say about this
a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.
b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.
What is work-Energy Principle?According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.
It can simply be written as:
Work done = initial kinetic energy - final kinetic energy
The work energy theorem equation is the one presented above.
Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus Law of Conservation of Energy followed.
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Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.
Answer:
Sound waves bend around the corners of various obstacles.
Explanation:
I took the test
Starting from rest an object accelerates on a straight line at rate of 2ms‐² for 10 seconds. what is the speed of the object at the end of the 10 seconds
Answer:
20 meters/sec
Explanation:
See attachment.
2m/s^2 = (v - 0)/10s
v = 20 m/s
A balance of forces is demonstrated by an object which is slowing to a stop true or false
Answer:
its true since i already did this last year, if i am wrong i apologize
Explanation:
ork is done if a boat has a force 60N and travels 600 meters
I really need the Formula, substitute, answer
Answer:
This is the answer.
Explanation:
is this right?
When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two words complete this sentence?
Answer:
When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.
Hope that helps.
When an object is balanced about a pivot, the total clockwise moment must be equal to the total anticlockwise moment.
What is balancing?
Clockwise involves turning to the right while going in the direction of a clock's hands. The moment is referred to as a clockwise moment if the force acting on a body rotates the body clockwise with regard to the axis of rotation.
On the other hand, the moment is referred to as an anti-clockwise moment if the force rotates the body in the opposite direction. The clock face rule can be used to determine this magnet's polarity.
The face of the loop will display the North Pole if the current is flowing counterclockwise. On the other hand, if the current is moving counterclockwise, the South Pole is visible on the loop's face.
Therefore, the total clockwise and total counterclockwise moments must match when an object is balanced about a pivot.
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Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x Distance 0 J 15 J 30 J 60 J.
Answer:
15 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 30 × 0.5 = 15
We have the final answer as
15 JHope this helps you
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
WORK DONE:The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
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What is the monthly cost of using a 750 W refrigerator that runs for 8 hours every day, if the cost per kWh is $0.23?
Answer:
Assuming there are 28 days in each month,
750W = 0.75kW
Cost of electric bill = 0.75 × 8 × 28 × $0.23
= $38.64
can someone explain with steps please
Answer:
The speed of other projectile is [tex]3.1m/s[/tex]
Explanation:
Range of projectile is given by the equation
[tex]\mathrm{R}=\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}[/tex]
Here we have same range
Hence
[tex]\frac{\mathrm{2.5}^{2} \cdot \sin (2 \times 65)}{\mathrm{g}}=\frac{\mathrm{u}^{2} \cdot \sin (2 \times 15)}{\mathrm{g}}\\\\u^2=\frac{2.5^2\sin130}{\sin30} \\\\u=3.10m/s[/tex]
Here
initial velocity=u
u1=2.5m/su2=?[tex]\theta_1=65°[/tex][tex]\theta_2=15°[/tex]Now
[tex]\\ \sf\longmapsto R_1=R_2[/tex]
[tex]\\ \sf\longmapsto \dfrac{u_1^2sin2\theta_1}{g}=\dfrac{u_2^2sin2\theta_2}{g}[/tex]
[tex]\\ \sf\longmapsto \dfrac{(2.5)^2.sin2(65)}{g}=\dfrac{u_2^2sin2(15)}{g}[/tex]
Cancel g[tex]\\ \sf\longmapsto 6.25sin130=u_2^2sin30[/tex]
[tex]\\ \sf\longmapsto 6.25(0.76)=u_2^2(0.5)[/tex]
[tex]\\ \sf\longmapsto 5.13=0.5u_2^2[/tex]
[tex]\\ \sf\longmapsto u_2^2\approx 10[/tex]
[tex]\\ \sf\longmapsto u_2\approx 3.1m/s[/tex]
Option B is correct
Three forces acting on an object are given by F1 = (−2.00 i + 2.00 j) N,F2 = (5.00 i − 3.00 j) N, and F3 = (−45.0 i) N. The object experiences an acceleration of magnitude 3.75 m/s2.
i. What is the direction of the acceleration?
ii. What is the mass of the object?
iii. If the object is initially at rest, what is its speed after 10.0 s?
iv. What are the velocity components of the object after 10.0 s?
From summation and resultant of forces, the four answers are:
i. ∅ = 34 degrees
ii. M = 0.48 kg
iii. V = 37.5 m/s
iv. V = 37.5i + 0j + 0k
Given that Three forces acting on an object are
F1 = (−2.00 i + 2.00 j) N
F2 = (5.00 i − 3.00 j) N
F3 = (−45.0 i) N.
If the object experiences an acceleration of magnitude 3.75 m/s2.
i. The direction of the force will be the direction of the acceleration.
Sum of the forces = (-2 + 5 - 4.5)i + (2 - 3 + 0)j
Sum of the forces = -1.5i -j
The acceleration direction will be
tan∅ = [tex]\frac{y}{x}[/tex]
tan∅ = [tex]\frac{1}{1.5}[/tex]
∅ = [tex]tan^{-1}[/tex] (0.67)
∅ = 34 degrees (approximately)
ii. The mass of the object can be calculated from Newton's law.
Resultant force = mass x acceleration.
Resultant force = [tex]\sqrt{1.5^{2} + 1^{2} }[/tex]
Resultant force = [tex]\sqrt{3.25}[/tex]
Resultant force = 1.8N
Then,
1.8 = 3.75M
M = 1.8 / 3.75
M = 0.48 kg
iii. If the object is initially at rest, the speed of the object after 10.0 will be calculated by using first equation of motion.
V = U + at
Where U = 0
V = 0 + 3.75 x 10
V = 37.5 m/s
Therefore, the speed of the object after 10.0 is 37.5 m/s
iv. The velocity components of the object after 10.0 are
V = 37.5i + 0j + 0k
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A student claims that the total momentum of a system of objects is conserved when there is no net force on the system.
To test the claim, the student uses a cue ball (white) and rolls it into an eight ball (black). When the balls collide, the cue
ball comes to a complete stop and the eight ball begins to move. The mass of the cue ball is 0.17 kg, and the mass of
the eight ball is 0.16 kg. A radar is used to measure the speed of the cue ball immediately before it comes in contact
with the eight ball, and another radar is used to measure the speed of the eight-ball immediately after the point of
contact. The cue ball approaches the eight ball at a speed of 4.00 m/s. After contact, the eight ball moves away from the
cue ball at a speed of 4.25 m/s. The scenario is shown in the picture.
The total momentum of the system is conserved and the momentum did not change.
The given parameters:
Mass of the white ball, m₁ = 0.17 kgMass of the black ball, m₂ = 0.16 kgInitial velocity of the white ball, u₁ = 4 m/sFinal velocity of the black ball, v₂ = 4.25 m/sThe initial momentum of the system is calculated as follows;
[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 0.17 \times 4 \ + \ 0.16(0)\\\\P_i = 0.68 \ kg m/s[/tex]
The final momentum of the system is calculated as follows;
[tex]P_f = m_1 v_1 + m_2 v_2 \\\\P_f = 0.17 (0) \ + 0.16(4.25)\\\\P_f = 0.68 \ kg m/s[/tex]
Thus, the total momentum of the system is conserved and the momentum did not change.
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( the answer only for points will be reported ) A crane lifts a load of 36000N to a height of 50 metre in 1 minute . What is the power of the crane ?
Answer:
- 30 kW
Explanation:
IDEA:
Power of an object that does work(source) is given by:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
where work done is mostly shown as the Force applied on an object to Displace it through some distance in the same direction as the Force.
[tex] \boxed{ \mathsf{ work = force \times displacement}}[/tex]
___________________
INFORMATION:
In the question,
The source of power is the crane, while the object is a load of 36000N.
Note, what's given is the force, not the mass. Since, the SI unit of mass is kg and that of Force is Newton(N).
[The weight of the load is represented in Newton, since weight of an object is the amount of Force with which the Earth attracts that object]
I) work done
So,
Force = 36000NDisplacement = 50 m=> Work = 36000 × 50
= 1,800,000 J
(The SI unit of work is Joules(J)).
___________________
II) power
After getting the amount of work done, now we have to place it in the formula for power.
That is:
[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]
Note, During calculations, all quantities must be in their SI units.
SI unit for time is Seconds (s)
But the time we have is in minutes.
___________________
Converting time from minutes to Seconds:
1 minute = 60 Seconds.
Hence,
time = 60 s[tex] \implies \mathsf{power = \frac{1800000}{60} } \: [/tex]
=> power = 30,000 W
(SI unit of power is Watts(W))
To write four zeroes with a 3 and W is a lot of effort. So, we can look for simple expressions like kilowatts(kW) that can express bigger quantities in lesser terms.
1000 W = 1 kW
•°• 30,000 W = 30 kW.___________________
Direction and sign:
The crane displaces the load in an upward direction (from the term "lifts")
But, the Force is acting downwards, as the weight of the body is always towards the Earth.
Since, the directions of Force and displacement are opposite, a minus takes its place in front of both Work and power.
___________________
Therefore, the final answer will be:
Power of the crane = - 30 kWA 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.
Part A
How much work is done during this part of its motion by the cable that lowering the elevator? Neglect any friction or air resistance.
Answer:
11115 J
Hope you could get an idea from here.
Doubt clarification - use comment section.
A construction crew is paving a road. The crew has already paved 1,000 square feet and can pave at a rate of 300 square feet of road per hour. The function f(x) = 300x 1,000 represents this situation. What is f(3), and what does it represent?.
f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount.
Mathematical models are representations of real situations. Models often serve the purpose of prediction and can help to explain and simplify certain mathematical problems.
The model; f(x) = 300x + 1,000 represents the number of additional square feet that can be paved in an hour after 1,000 square feet has already been paved.
From the above we can see that the correct answer is; "900 square feet; f(3) represents the number of additional square feet the construction crew has paved after 3 hours, not including the initial paved amount."
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how is one kg mass defined in SI system
Answer:
It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.
Why is kinetic energy lost in an inelastic collision?
Answer:
This is because some kinetic energy had been transferred to something else.
Explanation:
An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.
How much work can a 22 kW (22000W) car engine do in 60 s if it is 100% efficient?
The amount of work done by the car engine if it is 100% efficient is 366.67 Joules.
Given the following data:
Time = 60 secondsPower = 22,000 WattTo determine the amount of work done by the car engine if it is 100% efficient:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = \frac{Power}{time}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = \frac{22000}{60}[/tex]
Work done = 366.67 Joules.
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Which of the balls will exert the smallest force on object A?Why
What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________
The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
EQUATION OF MOTION:
The final velocity of a moving object can be calculated by using one of the equations of motion as follows:
V = u + at
Where;
V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)According to this question,
t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?v = 0 + 4.3(5)
v = 21.5m/s.
Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
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Can someone please help me with number 10
Answer:
A
Explanation:
increase
Answer:
B???
Explanation:
The rate of it going up is lower than L
It might be D too.