HELPPPPP please its worth 50

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Answer:

a ratio of 3 or also 3/1 is a fraction is wanted

Answer:

Whenever you are given two points, start by naming the points.  (2, 9) becomes (x1, y1); then (-1, 3) becomes (x2, y2).  When you know which numbers you are putting into which formulas, it makes it much easier.

Start with finding your slope.  m = y2 - y1/ x2 -x1

Step-by-step explanation:

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Answer:

1 2/3

Step-by-step explanation:

1 and 2/3

Answer:

1/4

Step-by-step explanation:

Answer:

m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}

m = slope

(x_1, y_1) = coordinates of first point in the line

(x_2, y_2) = coordinates of second point in the line

Answer:

6mx^4-7x^4

Step-by-step explanation:

Answer:

3+2i, 3-2i

Step-by-step explanation:

no rational solutions

if you use quadratic formula you get (6±[tex]\sqrt{-4}[/tex])÷2

Answer:

3

Step-by-step explanation:

Positive 5 minus 2 positive its just simple subtraction.

Answer: the area of the base will be multiplied by 4, since it will be changed from LW to

(2L)(2W) = 4LW

So, apply that to finding the new volume.

If the rectangular prism has a volume of 960 cubic units. Then the height of the prism will be 12 units.

Let the prism with a length of L, a width of W, and a height of H. Then the volume of the prism is given as

V = L x W x H

A rectangular crystal has a volume of 960 cubic units. The region of the base is 80 square units.

The height of the prism will be given as,

960 = 80 x H

H = 960 / 80

H = 12 units

If the rectangular prism has a volume of 960 cubic units. Then the height of the prism will be 12 units.

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Answer:

Vertical asymptote is at [tex]x=-3[/tex]

Step-by-step explanation:

Let us plot the function

Here

[tex]\frac{x-5}{x^{2}-2x-15}=\frac{x-5}{(x-5)(x+3)}\\\\=\frac{1}{x+3}[/tex]

Function does not exits at [tex]x=-3[/tex]

Vertical asymptote is at [tex]x=-3[/tex]

Answer:

slope:

-b/a

y-intercept:

1

Answer:

0,12,13,21,25

Step-by-step explanation:

jennifer-0, kamal-12, felipe -13, ellma-21, riley 25

basically least to greatest order

Answer:

It grows at a rate  

4/9 ft/second

Step-by-step explanation:

Answer:

slope is -3

y intercept is 6

Step-by-step explanation:

The y intercept is where it crosses the y axis

It crosses the y axis at 6

We need two points to find the slope (0,6) and (2,0)

m = ( y2-y1)/(x2-x1)

   = (0-6)/(2-0)

   = -6/2

   = -3

The slope is -3

Answer:

1.15 inches

Step-by-step explanation:

Answer: 1 in 51

Step-by-step explanation:

Answer:

23/26

Step-by-step explanation:

A standard deck of cards has 52 cards.

The cards are divided into 13 cards of each of 4 suits.

2 suits are black and 2 suits are red.

Each suit has 3 face cards. Since there are 2 black suits, there are 6 black face cards.

The total number of cards in a deck is 52.

52 - 6 = 46

There are 46 cards that are not black suit cards out of 52 total cards.

p(not black face card) = 46/52 = 23/26

Answer:

i thinks its

the unot rate for the 1st company is 2,86

Step-by-step explanation:

Answer:

✓ C. f(x)= sqrt 1/x

Step-by-step explanation:

i hoep this answer your question

Answer:

how do I give the coordinates of the image

Step-by-step explanation:

Answer:

No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3

3 ÷ 2/3

= 3 × 3/2

= 9/2

= 4 1/2

Therefore, 3 divided by 2/3 is 4 1/2

Andre's reasoning is wrong.

Step-by-step explanation:

It is incorrect

Let's divide and compare the sum

3 : 2/3 = 3*3/2 = 9/2 = 4 1/2

and

There are four 2/3 fractions and one 1/3 fraction

The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2

Answer:

Please give me Brainliest!

Step-by-step explanation:

President Kennedy's position on the expense of the space program was that  it would be well worth the high cost.

Explanation:

The general sentiment of the 1960s was extremely in favor of the space race and the Us was heavily invested in the exploration of the space even as the costs for doing so were soaring exorbitantly high.

The President understood this and so did not want to tinker with the hopes and aspirations of the common people who had come to love these efforts.

These efforts were also a matter of great national pride and thus seen well worth the cost they incurred on the people and the tax-paying part of the country.

========================================================

Explanation:

Start with the f(x) function. Then plug in g(x) like so

[tex]f(x) = 4x+3\\\\f(g(x)) = 4(g(x))+3\\\\f(g(x)) = 4\left(\frac{1}{4}x-\frac{3}{4}\right)+3\\\\f(g(x)) = 4\left(\frac{1}{4}x\right)+4\left(-\frac{3}{4}\right)+3\\\\f(g(x)) = x-3+3\\\\f(g(x)) = x\\\\[/tex]

----------------------------

Now we'll start with the g(x) function and then plug in f(x)

[tex]g(x) = \frac{1}{4}x-\frac{3}{4}\\\\g(f(x)) = \frac{1}{4}(f(x))-\frac{3}{4}\\\\g(f(x)) = \frac{1}{4}(4x+3)-\frac{3}{4}\\\\g(f(x)) = \frac{1}{4}(4x)+\frac{1}{4}(3)-\frac{3}{4}\\\\g(f(x)) = x+\frac{3}{4}-\frac{3}{4}\\\\g(f(x)) = x\\\\[/tex]

----------------------------

We've shown that the two equations are true

Therefore, f and g are inverses of each other.

The angle fact that is necessary to prove that m∠1 + m∠2 = m∠2 + m∠3 is: linear pair are supplementary.

Thus,

∠1 and ∠2 are on a straight line, therefore,

m∠1 + m∠2 = 180°

∠2 and ∠3 are on a straight line, therefore,

m∠2 + m∠3 = 180°

Thus:

m∠1 + m∠2 = m∠2 + m∠3

Therefore, the angle fact that is necessary to prove that m∠1 + m∠2 = m∠2 + m∠3 is: linear pair are supplementary.

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[tex]A=\pi ab\qquad \qquad \begin{array}{llll} a+b=20\\ b=20-a \end{array}\qquad \qquad \stackrel{\textit{substituting}}{A=\pi a(20-a)}\implies A=\pi (20a-a^2)[/tex]

The area of the ellipse is given by the function A(a) = 20πa - πa², where a is a parameter representing one of the semi-major axes of the ellipse.

To write the area of the ellipse as a function of a using the given constraint a + b = 20, we first need to solve for b in terms of a and then substitute the expression for b into the formula for the area of the ellipse.

Given the equation for the ellipse:

x²/a² + y²/b² = 1

We have the constraint: a + b = 20

Now, let's solve for b in terms of a:

b = 20 - a

Now, we'll substitute this expression for b into the formula for the area of the ellipse:

Area (A) = πab

Area (A) = πa(20 - a)

Area (A) = 20πa - πa²

So, the area of the ellipse is given by the function A(a) = 20πa - πa², where a is a parameter representing one of the semi-major axes of the ellipse.

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Answer:

Step-by-step explanation:

A = 8(14) - 5(14 - 5 - 2) = 77 m²

Answer:

77m (squared)

Step-by-step explanation:

Answer:

-2(x + 5)

Step-by-step explanation:

Step-by-step explanation:

I hope this helps out bye.

Answer:

x=5[tex]\frac{16}{3}[/tex]/(4-[tex]\frac{16}{3}[/tex])

Step-by-step explanation:

Hi, these are not my strong point, Sorry if its incorrect.

6-[tex]\frac{2}{3}[/tex](x+5)=4x

I first did 6-[tex]\frac{2}{3}[/tex]

6/1 -2/3,  18/3-2/3 =16/3

[tex]\frac{16}{3}[/tex](x+5)=4x

I then expanded the bracket to get [tex]\frac{16}{3}[/tex]x+5[tex]\frac{16}{3}[/tex]

[tex]\frac{16}{3}[/tex]x+5[tex]\frac{16}{3}[/tex]=4x

Then I took away [tex]\frac{16}{3}[/tex]x from both sides to get.

5[tex]\frac{16}{3}[/tex]=4x-[tex]\frac{16}{3}[/tex]x

I then factorised x out

5[tex]\frac{16}{3}[/tex]=x(4-[tex]\frac{16}{3}[/tex])

I then divided by the bracket to get:

x=5[tex]\frac{16}{3}[/tex]/(4-[tex]\frac{16}{3}[/tex])

Answer:

4/7

Step-by-step explanation:

[tex]6 - \frac{2}{3} (x + 5) = 4x[/tex]

U take -2/3 into the brackets

[tex]6 - \frac{2}{3} x - \frac{10}{3} = 4x[/tex]

Put all values with x on one side

[tex]6 - \frac{10}{3} = 4x + \frac{2}{3} x[/tex]

Ensure that they all have the same denominator so that u can add and subtract

[tex] \frac{18}{3} - \frac{10}{3} = \frac{12}{3} x + \frac{2}{3} x[/tex]

[tex] \frac{8}{3} = \frac{14}{3} x[/tex]

Drop the denominator since they both have the same denominator

[tex]8 = 14x[/tex]

divide both sides by 14

[tex] \frac{8}{14} = \frac{14}{14} x[/tex]

[tex]x = \frac{4}{7} [/tex]

[tex]\\(a)\\2^3 \times 2^6 \div 2^9 = 2^{3+6} \times \dfrac{1}{2^9} = 2^9 \times 2^{-9} = 2^{9-9} = 2^0 = 1\\\\ \\(b)\\\\(-5)^8 \div (-5)^4 \times (-5)^3\\ \\= (-5)^8 \times \dfrac 1{(-5)^4 \times (-5)^3} \\\\= (-5)^8 \times \dfrac{1}{(-5)^{4+3}} \\\\= (-5)^8 \times \dfrac{1}{(-5)^7} \\\\= (-5)^{8 - 7} \\\\=(-5)^1 \\\\ =-5\\\\\\(c)\\\\\\\dfrac{6^3 \times 6^5}{6^2 \times 6^4}= \dfrac{6^{3+5}}{6^{2+4}}= \dfrac{6^8}{6^6}=6^{8-6}=6^2 =36[/tex]